Arranging the real number in ascending order -8,2,0,9,-10

8V+3=105

clt

8v=105-3

=102

divide both sides by 8v

8v=102/8v

V=12.75

Answer:

The formula y = mx + b is said to be a linear function

Step-by-step explanation:

Answer:

D. is a linear function

Step-by-step explanation:

A. rational function

B. quadratic function

C. cube root function

Answer:

$76.

Step-by-step explanation:

Answer:

∠5  is supplementary.

It forms a straight angle with ∠1.

Answer:

there are 6 boys

Step-by-step explanation:

Answer:

x=16/15

Step-by-step explanation:

Answer:

104 bracelets

Step-by-step explanation:

182 ÷ 1.75 = 104

Answer:

y + 1 = -5(x - 4)

General Formulas and Concepts:

Algebra I

Point-Slope Form: y - y₁ = m(x - x₁)

Step-by-step explanation:

Step 1: Define

Identify variables.

Point (4, -1) → x₁ = 4, y₁ = -1

Slope m = -5

Step 2: Find Equation

Answer:

To make things easier if you were to find the angle of any exterior angle on a triangle, you can always add up the two remote interior angles in order to get the exterior angle on a triangle. So in this case 76 and 52 added up is 128

m<1= 128

For the first one (i think)

Well the triangles do give away the fact that 66 and 84 are in one of the shape. We know a triangle has 3 angle measures and if added up it would equal to 180.

66+84+x=180

You’d get x=30

Now we have 30 as angle 1.

angle 3 and 84 degrees are supplementary so we can just do

84+y=180 which in this case is 96 so angle 3 is 96

Now we need to find 2, we know that 3 is 96 and we have a 43 degrees already given. It’s a triangle so same thing

96+43+n=180

in this case n is angle 2 and the measure of angle 2 is 41 degrees.

Final answers:

m<1=30

m<2= 41

m<3= 96

Answer:

Step-by-step explanation:

1 = 76+52=128

=180-128

     =30

    2.    96+43=139    180-139=

    =41

     3.180-84

    =96

Answer:

0

Step-by-step explanation:

1×2÷√(3)×√(3)÷2 - √(3)×1÷√(3)

1-1

0

for more refer to the image

Answer:

18:28

Step-by-step explanation:

[tex]\\ \sf\longmapsto 3x-9y> 27[/tex]

[tex]\\ \sf\longmapsto x-3y>9---(1)[/tex]

And

[tex]\\ \sf\longmapsto y-3\leqslant -4/3(x+7)[/tex]

[tex]\\ \sf\longmapsto 3y-9\leqslant -4x+28[/tex]

[tex]\\ \sf\longmapsto 3y+4x\leqslant 37--(2)[/tex]

Graph attached

Answer:

1. 3 × Equation [A2] --> Equation [B2]

2. 4 × Equation [B1] + Equation [B2] --> Equation [C2]

Step-by-step explanation:

1. 3 × Equation [A2] --> Equation [B2]

Technically 1 x equation [A1] --> equation [B2] works, but I doubt you're meant to do that lol

Instead, this works:

4x × 3 = 12x

-7y × 3 = -21y

8 × 3 = 24

2. 4 × Equation [B1] + Equation [B2] --> Equation [C2]

(-3x × 4) + 12x = -12x + 12x = 0x

(2y × 4) + -21y = 8y - 21y = -13y

(7 × 4) + 28 = 28 + 24 = 52

=========================

I'll try to explain my process a little this time.

From A to B, you can see that equation 2 changed. Looking at the first term, 4x changed to 12x. Thats a multiplier of 3, and you can check that on the rest. In this case, that works.

Then from B to C, equation 2 changed again. This time, I noticed that x was canceled out. That means -12x had to have been added to 12x. In equation 1, theres a -3x. 4 times that is -12, and adding -12x to equation 2 works. Check that with the rest, and they all work.

Answer:

Step-by-step explanation:

25 pound bag contains:

Number of pies:

Answer:

D

Step-by-step explanation:

[tex](x_{1},y_{1}) = (2 , 2)\\\\ (x_{2},y_{2}) = (3 , 5)\\\\\\Midpoint=\left(\dfrac{x_{1}+y_{1}}{2},\dfrac{x_{2}+y_{2}}{2} \right)\\\\\\=\left(\dfrac{3+2}{2},\dfrac{5+2}{2} \right)\\\\\\= \left(\dfrac{5}{2},\dfrac{7}{2} \right)[/tex]

Answer:

Step-by-step explanation:

Needs a picture to be solved, please put one.

Answer:

i know

Step-by-step explanation:

I know have a amazing day

Answer:

huuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuh

9514 1404 393

Answer:

  5x^2 +10x = -5

Step-by-step explanation:

The equation will have one solution when the discriminant is zero.

In standard form, the equation is ...

  ax^2 +10x -c = 0

The discriminant of the equation ax^2+bx+c=0 is  ...

  b^2 -4ac

so the discriminant of your equation is ...

  10^2 -4a(-c) = 100 +4ac

We want that to be zero, so we require ...

  100 +4ac = 0

  25 +ac = 0

  ac = -25

Any pair of values of 'a' and 'c' that have a product of -25 will satisfy the requirement. As you state, one possible pair is a = 5 and c = -5. Putting these values into the given equation makes it ...

  5x^2 +10x = -5 . . . . . the equation with a=5, c=-5

_____

Additional comment

Your problem statement does not require that 'a' be non-zero. If a=0, then the equation will have one real solution for any value of c.

If you restrict the solutions to integers, then possibilities include ...

  (a, c) = (1, -25), (5, -5), (25, -1), (-25, 1), (-5, 5), (-1, 25)

Answer:

The equation is 5x+10x=-5

Step-by-step explanation:

19, 15.5

20, 25

21, 1/16

22, 4

23, 11

24, 8

25, 19.5

26, 30

27, 4

28, 56

29, 6.5

30, 4

31, 21

32, 112

33, 3,200

here are they

Answer:

I don't know i just need the points

Answer:

linear

Step-by-step explanation:

Answer:

The answer is 2

Step-by-step explanation:

-2, -1, 0, 1, 2, 3, 4, 5, 6

If you remove the first 4 and the last 4 numbers you are left with 2 which is also the median / middle value. Therefore, the temperature is 2.

Answer:

D 104

Step-by-step explanation:

A and b are too small to have $71 left. C is also not enough if he had $71 left.

Answer: yes math is so good

Step-by-step explanation:

Step-by-step explanation:

the rules of logarithm.

log(a×b) = log(a) + log(b)

log(a^b) = b×log(a)

2×log(x) = log(16) + log(4)

now, using the above knowledge :

log(x²) = log(16×4)

=>

x² = 16×4 = 64

x = ±8

and since a logarithm of a negative number is undefined the only plausible solution is

x = 8

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