B) Express the answer to this multistep calculation using the appropriate number of significant figures: 87. 95 feet x 0. 277 feet +5. 02 feet - 1. 348 feet + 10. 0 feet.
​

Converting mass to moles ccc requires knowing the molar mass of the substance and using it to divide the given mass to find the number of moles

Moles ccc is a unit used to measure the amount of substance, particularly in chemistry. It is defined as the number of atoms, molecules, or ions in 12 grams of pure carbon-12. One mole of any substance contains Avogadro's number of particles, which is approximately 6.022 x 10^23.

To convert mass to moles on the ccc scale, you need to know the molar mass of the substance. Molar mass is the mass of one mole of a substance, expressed in grams per mole. To find the number of moles of a substance, you divide the given mass by its molar mass.

For example, the table given shows how many moles are in 6 grams of four elements: oxygen, sulfur, sodium, and iron. To find the number of moles of oxygen, you divide 6 grams by its molar mass, which is 16 grams per mole. This gives you 0.375 moles of oxygen.

The equation given shows how to use carbon molar mass to find the moles of carbon. The molar mass of carbon is 12 grams per mole. Therefore, if you have a sample of carbon with a mass of 24 grams, you can find the number of moles by dividing 24 grams by 12 grams per mole, which equals 2 moles of carbon.

In summary, converting mass to moles ccc requires knowing the molar mass of the substance and using it to divide the given mass to find the number of moles. The moles ccc scale is a useful unit for measuring the amount of substance in chemistry.

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The total quantity of heat evolved when 10.0 g of steam at 200°C is condensed, cooled, and frozen to ice at 50°C is 410.56 kJ.

To calculate the total quantity of heat evolved, we need to break down the process into different steps:

Step 1: Condensation of 10.0 g of steam at 200°C

The heat evolved during condensation can be calculated using the formula:

q = m × ΔHvap

where q is the heat evolved, m is the mass of steam, and ΔHvap is the molar heat of vaporization of water, which is 40.7 kJ/mol.

First, we need to calculate the moles of steam:

n = m/M

where M is the molar mass of water, which is 18.02 g/mol.

n = 10.0 g / 18.02 g/mol = 0.555 mol

Now we can calculate the heat evolved during condensation:

q1 = n × ΔHvap = 0.555 mol × 40.7 kJ/mol = 22.5 kJ

Step 2: Cooling of liquid water from 100°C to 0°C

The heat evolved during cooling can be calculated using the formula:

q = m × c × ΔT

where q is the heat evolved, m is the mass of water, c is the specific heat capacity of water, and ΔT is the change in temperature.

We need to calculate the mass of water formed from the condensation of 10.0 g of steam. Since the density of water is 1 g/mL, we know that:

m_water = m_ice = V × ρ = 10.0 g/mL × 0.92 g/mL = 9.2 g

Now we can calculate the heat evolved during cooling:

q2 = 9.2 g × 4.18 J/g°C × (100 - 0)°C = 385 kJ

Step 3: Freezing of liquid water from 0°C to -50°C

The heat evolved during freezing can be calculated using the formula:

q = m × ΔHfus

where q is the heat evolved, m is the mass of water, and ΔHfus is the molar heat of fusion of water, which is 6.01 kJ/mol.

We need to calculate the moles of water:

n = m/M = 9.2 g / 18.02 g/mol = 0.510 mol

Now we can calculate the heat evolved during freezing:

q3 = n × ΔHfus = 0.510 mol × 6.01 kJ/mol = 3.06 kJ

Total heat evolved = q1 + q2 + q3 = 22.5 kJ + 385 kJ + 3.06 kJ = 410.56 kJ

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Fossil fuels are the largest contributor of the  greenhouse  gas carbon dioxide,this causes health and environmental issues.

This causes health and environmental issues as it contributes to global warming and climate change. The burning of fossil fuels such as coal, oil and gas releases carbon dioxide into the atmosphere, which traps heat and leads to the Earth's temperature rising.

This can cause extreme weather events, rising sea levels, and harm to ecosystems and wildlife. Additionally, carbon dioxide can contribute to respiratory and cardiovascular health issues in humans and animals.

Therefore, it is important to transition to renewable energy sources in order to reduce our reliance on fossil fuels and mitigate the impacts of climate change.

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The correct answer is: The dianion can form a resonance-stabilized conjugated ring, which tends to absorb visible light.

The correct answer is: The dianion can form a resonance-stabilized conjugated ring, which tends to absorb visible light.

In the first part of the experiment, the reagents used are benzidine and hydrogen peroxide, which react to form a compound called a dianion. This dianion is initially colorless, but when sodium hydroxide is added, it causes the dianion to undergo a rearrangement that forms a resonance-stabilized conjugated ring. This conjugated ring absorbs visible light in the blue-green range, which causes the solution to appear red. This color change is used as an indicator for the presence of blood in forensic and medical labs because benzidine and its derivatives are known to react with the heme group found in blood to form a similar colored proproductduct.
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A heating curve is a graphical representation of how a substance's temperature changes as it absorbs heat energy.

The x-axis represents the amount of heat energy added, while the y-axis represents the temperature of the substance. The heating curve can be divided into three portions, each representing different changes in the substance's physical state and energy.

At the beginning of the heating curve, particles of the substance have the most kinetic energy when the substance is in its solid state. In this portion, the temperature remains constant as the added heat energy is used to break down the intermolecular forces holding the particles together.

This part of the curve is labeled the "melting point" or "fusion" section.

The next portion of the curve represents the transition from the solid to the liquid state. During this section, the temperature again remains constant as the added heat energy is used to overcome the intermolecular forces and convert the substance to a liquid state. This part of the curve is labeled the "boiling point" or "vaporization" section.

Finally, the last portion of the curve represents the liquid state. In this section, the temperature of the substance begins to increase as the added heat energy is used to increase the kinetic energy of the particles. This portion of the curve is labeled the "condensation" or "freezing" section, depending on whether the substance is being cooled or heated.

Overall, a heating curve is a useful tool for understanding how a substance's energy changes during heating, and how this affects its physical state.

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Using the combined gas law, the temperature of a gas at 101.3 kPa is calculated to be 39.5°C, given its initial pressure and temperature of 801.3 kPa and 40.0°C, respectively.

To solve this problem, we can use the combined gas law which states that:

(P1V1/T1) = (P2V2/T2)

where P1 and T1 are the initial pressure and temperature, and P2 and T2 are the final pressure and temperature.

We are given P1 = 801.3 kPa and T1 = 40.0°C, and we want to find T2 at P2 = 101.3 kPa.

Let's assume that the volume (V1) of the gas is constant. Therefore, we can write:

(P1/T1) = (P2/T2)

Solving for T2, we get:

T2 = (P2 x T1)/P1

Substituting the given values, we get:

T2 = (101.3 kPa x 313.15 K)/801.3 kPa

T2 = 39.5°C (rounded to one decimal place)

Therefore, the temperature of the gas at 101.3 kPa is 39.5°C.

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The rate at which NH3 reacts in the given reaction is 4.00 mol L-1 s-1. This is determined by using the stoichiometry of the reaction and the given rate of formation of N2.

The given chemical reaction shows the stoichiometric relationship between the reactants and products, which is important in determining the rate of the reaction. The rate of formation of N2 is given as 2.00 mol L-1 s-1. This means that for every second, the concentration of N2 increases by 2.00 mol L-1.

To find the rate at which NH3 reacts, we need to look at the stoichiometry of the reaction. From the balanced equation, we can see that for every 4 moles of NH3 that react, 2 moles of N2 are formed. Therefore, the ratio of the rate of formation of N2 to the rate of consumption of NH3 is 2:4, or 1:2.

Using this ratio, we can calculate the rate at which NH3 reacts. If the rate of formation of N2 is 2.00 mol L-1 s-1, then the rate of consumption of NH3 is twice as much, or 4.00 mol L-1 s-1.

In summary, the rate at which NH3 reacts in the given reaction is 4.00 mol L-1 s-1. This is determined by using the stoichiometry of the reaction and the given rate of formation of N2.

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He can do this either by changing the temperature to 150 kelvins or by changing the pressure to 200 kilopascals.

The ideal gas law is a fundamental principle in thermodynamics and describes the behavior of ideal gases under various conditions. It is mathematically represented by the equation:

PV = nRT

where:

P is the pressure of the gas,

V is the volume of the gas,

n is the number of moles of the gas,

R is the ideal gas constant, and

T is the absolute temperature of the gas.

The ideal gas law relates the pressure, volume, temperature, and amount of gas (number of moles) in a system. It assumes that the gas molecules do not interact with each other and occupy negligible volume compared to the total volume of the container. The ideal gas law allows for the calculation of any one of the variables (pressure, volume, temperature, or number of moles) if the other three are known.

Based on the Ideal Gas Equation,

V ∝ T

V ∝ 1/P

Using T :

V₁/T₁ = V₂/T₂

200/300 = 100/T₂

T₂ = 100/200 x 300

T₂ = 0.5 x 300

T₂ = 150 K

Using P :

P₁V₁ = P₂V₂

100 x 200 = P₂ x 100

P₂ = 200 kPa

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The molar heat capacity of ethanol is 103 J/(mol⋅K).

First, we need to calculate the amount of heat energy absorbed by 1 mole of ethanol:

The molar mass of ethanol, C2H6O, is 46.07 g/mol

The amount of ethanol used is: 40.1 g / 46.07 g/mol = 0.870 mol

The heat energy absorbed by 0.870 mol of ethanol is: 1367 J / 0.870 mol = 1570 J/mol

Now, we can calculate the molar heat capacity of ethanol:

The temperature increase is 13.9 °C = 13.9 K

The formula for heat capacity is: q = nCΔT, where q is the heat energy absorbed, n is the number of moles, C is the molar heat capacity, and ΔT is the temperature change.

Rearranging the formula, we get: C = q/(nΔT) = 1570 J/mol / (0.870 mol x 13.9 K) = 103 J/(mol⋅K)

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The concentration of a saturated calcium carbonate solution is 5.9 x 10⁻⁵ M.

To find the concentration, first write the balanced chemical equation for the dissolution of calcium carbonate:

CaCO₃(s) ⇌ Ca²⁺(aq) + CO₃²⁻(aq)

The Ksp expression for this reaction is:

Ksp = [Ca²⁺][CO₃²⁻]

Given the Ksp of calcium carbonate is 4.5 x 10⁻⁹, let the concentration of Ca²⁺ and CO₃²⁻ both be "x". So, Ksp = x². Now, solve for x:

4.5 x 10⁻⁹ = x²
x = √(4.5 x 10⁻⁹)
x = 5.9 x 10⁻⁵ M

Thus, the concentration of a saturated calcium carbonate solution is 5.9 x 10⁻⁵ M.

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An atom becomes negatively charged when it gains electrons. The number of electrons an atom needs to gain to become negatively charged depends on the number of protons in its nucleus, which determines its atomic number and the number of electrons it normally has in its neutral state.

In general, if an atom gains n electrons, it will have a negative charge of -n. For example, if an oxygen atom (atomic number 8) gains two electrons, it will have a negative charge of -2.

Therefore, the least number of electrons an atom must have in order to have a negative charge would be one more than the number of protons in its nucleus, since adding one electron will give it a charge of -1. For example, if the atom has 6 protons, it would need 7 electrons to have a negative charge of -1.

This corresponds to the element carbon, which has atomic number 6 and normally has 6 electrons in its neutral state. Adding one electron to a carbon atom would give it a negative charge of -1.

468.5 mL of 10% Na2CO3 solution is required to neutralize 100 mL of HCl solution containing 3.63 g of HCl.

Calculating the amount of HCl in moles is the first step.

mol = 3.63 g / 36.46 g/mol

moles = 0.0995

mol mass HCl = mass HCl / molar mass HCl

The chemical equation for the neutralization of HCl and Na2CO3 is as follows:

2HCl + Na2CO3 → 2NaCl + CO2 + H2O

The equation states that 2 moles of HCl and 1 mole of Na2CO3 react. As a result, the amount of Na2CO3 needed to neutralize the HCl, in moles, is:

moles Na2CO3 = moles HCl / 2

moles Na2CO3 = 0.0995 mol / 2

moles Na2CO3 = 0.0498 mol

The volume of 10% Na2CO3 solution needed to produce 0.0498 mol of Na2CO3 may now be calculated using the definition of molarity:

moles Na2CO3 = (Na2CO3 concentration) x (Na2CO3 volume).

0.1 g/mL x (volume Na2CO3 / 1000 mL) x (105.99 g/mol) = 0.0498 mol

Na2CO3's volume =  (0.0498 mol x 1000 mL) / (0.1 g/mL x 105.99 g/mol).

Na2CO3 = 468.5 mL of volume

Therefore, 468.5 mL of 10% Na2CO3 solution is required to neutralize 100 mL of HCl solution containing 3.63 g of HCl.

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Specific Heat of Glass is: 0.2 J/g°C.

To calculate the specific heat of the glass, you can use the formula:

Q = mcΔT

where Q represents the heat absorbed (32 J), m is the mass of the glass (4.0 g), c is the specific heat we need to find, and ΔT is the change in temperature (45°C - 5°C).

Rearranging the formula to find the specific heat (c):

c = Q / (mΔT)

First, calculate the change in temperature (ΔT):

ΔT = 45°C - 5°C = 40°C

Now, plug the values into the formula:

c = 32 J / (4.0 g × 40°C)

c = 32 J / 160 g°C

c = 0.2 J/g°C

So, the specific heat of the glass is 0.2 J/g°C.

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The heat that is released by 4.5 moles of methane gas is 4005 kJ.

The chemical reaction of combustion involves the breaking of chemical bonds in the fuel molecules, followed by the recombination of atoms with oxygen to form new molecules such as carbon dioxide, water vapor, and other combustion products.

We know that the balanced reaction equation have been shown in the image that is attached here.

As such we have that;

1 mole of methane gas produces 890 kJ of heat

4.5 moles of methane gas would produce 4.5 * 890/1

= 4005 kJ

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In an oxoacid such as [tex]H2SO4[/tex], ionizable hydrogen atoms are those bonded to oxygen atoms.

In [tex]H2SO4[/tex], the two hydrogen atoms bonded to the oxygen atoms are ionizable, meaning they can dissociate from the molecule in water to form [tex]H+[/tex] ions. This makes[tex]H2SO4[/tex] a strong acid, as it can readily donate protons in solution.

The sulfur atom in [tex]H2SO4[/tex] is also bonded to four oxygen atoms, giving it a tetrahedral shape. The electronegativity difference between the sulfur and oxygen atoms in the molecule creates a polar covalent bond, which leads to the acidity of the molecule.

In general, oxoacids have ionizable hydrogen atoms bonded to oxygen atoms, and the number of ionizable hydrogen atoms is determined by the oxidation state of the central atom and the number of oxygen atoms bonded to it.

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The total entropy change of the steam during this process is 24.885 kJ/K.

During this process, the system undergoes a phase change from a saturated liquid-vapor mixture to a saturated vapor. The initial state can be determined using a steam table, which shows that at 225 kPa, the saturation temperature of water is 120.23°C. Therefore, the initial state is a mixture of liquid water and steam at 120.23°C with 80% of the mass in the liquid phase.

When the electric resistance heater vaporizes all of the liquid, the system transitions to a state of saturated vapor at the same pressure of 225 kPa and temperature of 120.23°C. The total entropy change of the steam during this process can be calculated using the formula:

ΔS = m * s_final - m * s_initial

where ΔS is the total entropy change, m is the mass of the steam, s_final is the specific entropy of the final state, and s_initial is the specific entropy of the initial state.

At the initial state, using the steam table, the specific entropy of the saturated liquid-vapor mixture can be found to be 1.5875 kJ/kg-K. At the final state, the specific entropy of the saturated vapor can also be found to be 7.2925 kJ/kg-K.

Therefore, the total entropy change of the steam is:

ΔS = 4.2 kg * (7.2925 kJ/kg-K - 1.5875 kJ/kg-K)
ΔS = 24.885 kJ/K

Therefore, the total entropy change of the steam during this process is 24.885 kJ/K.

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The alpha of the investment is - 0.8%.

The alpha of an investment is a measure of its risk-adjusted performance. It indicates the excess return earned by the investment compared to the return predicted by the market based on its beta.

The formula to calculate alpha is:

alpha = actual return - expected return

where the expected return is the risk-free rate plus the product of the market return and the investment's beta.

Here, we are given:

actual return = 10%

market return = 10%

risk-free rate = 2%

beta = 1.1

Expected return = risk-free rate + beta * (market return - risk-free rate)

Expected return = 2% + 1.1 * (10% - 2%)

Expected return = 10.8%

Therefore, the alpha of the investment is:

alpha = actual return - expected return

alpha = 10% - 10.8%

alpha = -0.8%

The negative value of alpha indicates that the investment underperformed compared to what was expected based on its beta and the market return.

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Complete Question

Polar bonds do not always result in polar molecules; for example, carbon dioxide has polar bonds but is a nonpolar molecule because its bond polarities cancel out due to its linear geometry.

The statement that all molecules with polar bonds are polar molecules is not entirely correct. While it is true that polar bonds occur between atoms with different electronegativities, giving rise to partial positive and negative charges within the molecule, a molecule can still be nonpolar if the polar bonds cancel out each other's effects.

For example, carbon dioxide has two polar bonds between the carbon atom and each oxygen atom, but the molecule is nonpolar because the arrangement of the atoms is linear, with the polar bonds facing in opposite directions and canceling each other's effect. Similarly, tetrachloromethane has four polar bonds between the carbon atom and each chlorine atom, but the molecule is nonpolar due to its tetrahedral geometry, which results in the polar bonds being arranged symmetrically around the carbon atom.

Therefore, it is essential to consider both the electronegativity difference and the geometry of the molecule to determine whether a molecule is polar or nonpolar.

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You need 0.25 grams of magnesium phosphate to make 250 mL of a 0.10% (m/v) solution.

To calculate the grams of solute required to make 250 mL of 0.10% magnesium phosphate (m/v), you'll first need to determine the mass of the solute in the solution.

1. Convert the percentage to a decimal: 0.10% = 0.0010.
2. Multiply the decimal by the volume of the solution: 0.0010 x 250 mL = 0.25 grams.
3. The result, 0.25 grams, is the mass of magnesium phosphate needed to make 250 mL of a 0.10% (m/v) solution.

In summary, to make a 250 mL solution with a 0.10% (m/v) concentration of magnesium phosphate, you will need to dissolve 0.25 grams of the solute in the solvent.

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Answer:

The chemical equation for the conversion of glucose to ethanol during fermentation is:

C6H12O6 → 2C2H5OH + 2CO2

From the equation, we can see that for every mole of glucose (C6H12O6) that reacts, two moles of ethanol (C2H5OH) are produced. The molar mass of glucose is 180.16 g/mol, while the molar mass of ethanol is 46.07 g/mol.

Therefore, to calculate the mass of ethanol produced from 500.0 grams of glucose, we need to convert the mass of glucose to moles, then use the mole ratio from the balanced chemical equation to calculate the moles of ethanol produced, and finally convert the moles of ethanol to mass.

Step 1: Convert the mass of glucose to moles

Number of moles of glucose = mass of glucose ÷ molar mass of glucose

Number of moles of glucose = 500.0 g ÷ 180.16 g/mol

Number of moles of glucose = 2.776 mol

Step 2: Use the mole ratio to calculate the moles of ethanol produced

From the balanced equation, 1 mol of glucose produces 2 mol of ethanol

Therefore, 2.776 mol of glucose will produce:

2.776 mol glucose × (2 mol ethanol / 1 mol glucose) = 5.552 mol ethanol

Step 3: Convert moles of ethanol to mass

Mass of ethanol = number of moles of ethanol × molar mass of ethanol

Mass of ethanol = 5.552 mol × 46.07 g/mol

Mass of ethanol = 255.2 g

Therefore, 500.0 grams of glucose will produce 255.2 grams of ethanol during fermentation.

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Answer:

One of two or more versions of a genetic sequence at a particular region of a chromosome.

The equilibrium constant, Kp, for this reaction at 581 K is 0.107.

The first step in solving this problem is to write the balanced chemical equation for the reaction and the corresponding equilibrium expression in terms of partial pressures:

[tex]COCl_2[/tex](g) ⇌ [tex]CO(g) +[/tex] [tex]Cl_2(g)[/tex]

Kp = (P_CO × P_[tex]Cl_2[/tex]) / [tex]P\ COCl_2[/tex]

Next, we can use the given equilibrium partial pressures of [tex]COCl_2[/tex] and Cl2 to find the equilibrium partial pressure of CO using the ideal gas law:

[tex]P\ {CO} = (P\ COCl_2 - P\ Cl_2) / 2[/tex]

Substituting the values given in the problem, we get:

P_CO = (0.872 atm - 0.390 atm) / 2 = 0.241 atm

Now we can plug in these values into the equilibrium expression and solve for Kp:

[tex]Kp = (0.241\ atm * 0.390\ atm) / 0.872\ atm = 0.107[/tex]

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a. To plot the k emission intensity vs. the concentration of k, we can use the given data for the standard solutions of NaCl.

The concentration of K can be expressed in parts per million (ppm) and the corresponding intensity values can be plotted on a graph. Using regression analysis, we can determine the linearity of the data. The resulting graph should show a linear relationship between concentration and intensity.

b. To plot the ratio of the k intensity to the li intensity vs. the concentration of k, we can divide the intensity of K by the intensity of Li for each standard solution and the unknown.

The resulting values can be plotted against the concentration of K. The linearity of this graph can also be determined using regression analysis. The internal standard improves linearity because it helps to correct for any variations in sample handling and instrument response, resulting in more accurate and precise measurements.

c. To calculate the concentration of K in the unknown, we can use the ratio of the intensity of K to Li and the calibration curve obtained from the standard solutions.

From the graph in part (b), we can determine the concentration of K in the unknown by finding its corresponding value on the x-axis. Alternatively, we can use the regression equation obtained from part (a) to calculate the concentration of K in the unknown based on its measured intensity.

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Answer:

[tex]H _{2} SO _{4}+NaOH→NaSO _{4} +H _{2} O[/tex]

hope it helps:)

The law that applies to this problem is Charles's Law.

The equation for Charles's Law is [tex]\frac{V_{1} }{T_{1} }[/tex] = [tex]\frac{V_{2} }{T_{2} }[/tex]

The original temperature of sulfur dioxide was 185.12 K.

The law that applies to this problem is Charles's Law, which states that at constant pressure, the volume of a fixed amount of gas is directly proportional to its temperature in kelvin.

The equation for Charles's Law is [tex]\frac{V_{1} }{T_{1} }[/tex] = [tex]\frac{V_{2} }{T_{2} }[/tex], where [tex]V_{1}[/tex] is the initial volume, [tex]T_{1}[/tex] is the initial temperature, [tex]V_{2}[/tex] is the final volume, and [tex]T_{2}[/tex] is the final temperature.

Using the given values, we can plug them into the equation and solve for the initial temperature:

[tex]\frac{V_{1} }{T_{1} }[/tex] = [tex]\frac{V_{2} }{T_{2} }[/tex]
20.923/[tex]T_{1}[/tex] = 29.508/260.93

Multiplying both sides by [tex]T_{1}[/tex] and dividing by 29.508, we get:

[tex]T_{1}[/tex] = (20.923/29.508) x 260.93 = 185.02 K

Therefore, the original temperature of sulfur dioxide was 185.12 K.

The answer with correct units is 185.12 K.

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The electron-transfer method is a way to balance chemical reactions by assigning oxidation numbers to each element and then transferring electrons between the two sides of the equation until the number of electrons is equal on both sides.

In this case, the reactants are solid copper and dilute nitric acid, which will produce copper(II) nitrate, water, and nitrogen monoxide gas (NO).

The first step is to assign oxidation numbers to the elements. For copper, the oxidation number is 0, for nitrogen it is +3, for oxygen it is -2, and for hydrogen it is +1.

The next step is to transfer electrons between the two sides of the equation so that the number of electrons on each side is equal. In this case, we can transfer two electrons from the reactant side to the product side. This will result in the equation being balanced, with the copper being reduced to 0 and the nitrogen being oxidized to +5.

The balanced equation would look like this:

Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO

The electron-transfer method is a simple, effective way to balance chemical equations.

By assigning oxidation numbers and transferring electrons between the reactants and products, we can ensure that the equation is balanced and all atoms are conserved.

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The thermodynamic equation for the reaction is:

[tex]HNO_3(g) + 4H_2(g)[/tex] → [tex]NH_3(g) + 3H_2O(g) \Delta H = -637 kJ[/tex]

This means that the reaction releases 637 kJ energy per mole ammonia produced. The amount of energy released when one mole of hydrogen gas reacts is 159.25 kJ,

However,  the amount of energy released when one mole of hydrogen gas reacts. From the balanced equation, we can see that one mole of ammonia is produced for every 4 moles of hydrogen gas that react. Therefore, the amount of energy released :

ΔH/4 = -637 kJ / 4 = -159.25 kJ

So, the amount of energy released when one mole hydrogen gas reacts is 159.25 kJ, and we consider this to be a positive value because the reaction is exothermic.

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Answer:

you equate the question 800×7.2 divide the answer by 735.And you'll get 7.84litre then covert to 0.0m³ if the question says so to get 0.00784

The expression that describes the heat evolved in a chemical reaction when carried out at constant pressure is ΔH = ΔE - w. Here, ΔH represents the enthalpy change, ΔE represents the internal energy change (also symbolized as ΔU), and w represents the work done.

Enthalpy is the sum of the internal energy of a system and the product of its pressure and volume. At constant pressure, the change in enthalpy is equal to the heat evolved or absorbed in the reaction. This is because any work done during the reaction is accounted for in the change in volume term of enthalpy, and at constant pressure, this term is constant. Therefore, the heat evolved or absorbed in the reaction is solely responsible for the change in enthalpy.

When a chemical reaction is carried out at constant pressure, the heat evolved in the reaction can be described using the symbol q, which represents heat. This is because, at constant pressure, the change in internal energy (symbolized by ΔE or ΔU) is equal to the heat absorbed or released in the reaction (represented by q) minus any work done (represented by w). Therefore, to explain the heat evolved in a chemical reaction at constant pressure, we would use the symbol q.

Learn more about internal energy at https://brainly.com/question/25737117

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