The area in square yards of the athletic field at IDEA Brentwood would be 170. 24 yards ²
How to find the area ?The shape of the athletic field at IDEA Brentwood is shown to be a rectangle with two semi - circles attached.
The area of the athletic field at IDEA Brentwood is the sum of the areas of these shapes.
Area of rectangle :
= 15 x 8
= 120 yards ²
The area of the two semi - circles would be:
= π x radius x radius
= π x ( 8 / 2 ) x ( 8 / 2 )
= 50. 24 yards ²
The area of the athletic field at IDEA Brentwood is :
= 50. 24 + 120
= 170. 24 yards ²
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Can someone help me with this please
The measure of x is 36.
We have,
The angle opposite to equal sides is equal.
And,
The sum of the triangle.
27 + 90 + (x + 27)= 180
27 + 90 + x + 27 = 180
x = 180 - 144
x = 36
Thus,
The measure of x is 36.
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PLEASE HELP I have 30 minutes! What is the end behavior of this equation and how did you get it?
The limit of the function will be:
lim f(x) = ∞ as x → ∞
lim f(x) = 0 as x → -∞
How to explain the functionThe limit of f(x) as x goes towards infinity is infinite while the limit of f(x) approaches 0 when x tends to a negative value. Mathematically speaking,
lim f(x) = ∞ as x → ∞
lim f(x) = 0 as x → -∞
We can comprehend such behavior because the function's base is greater than 1 which explains how its growth accelerates as x increases and diminishes quickly as x declines towards zero.
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In tetrahedron $ABCO,$ $\angle AOB = \angle AOC = \angle BOC = 90^\circ.$ A cube is inscribed in the tetrahedron so that one of its vertices is at $O,$ and the opposite vertex lies on face $ABC.$ Let $a = OA,$ $b = OB,$ and $c = OC.$ Show that the side length of the cube is
\[\frac{abc}{ab + ac + bc}.\]
[asy]
import three;
size(180);
currentprojection = orthographic(6,3,2);
real a, b, c, s;
triple A, B, C, O;
a = 6;
b = 3;
c = 2;
s = a*b*c/(a*b + a*c + b*c);
A = (a,0,0);
B = (0,b,0);
C = (0,0,c);
O = (0,0,0);
draw(O--A,dashed);
draw(O--B,dashed);
draw(O--C,dashed);
draw(A--B--C--cycle);
draw((0,0,s)--(s,0,s)--(s,0,0)--(s,s,0)--(0,s,0)--(0,s,s)--cycle,dashed);
draw((s,s,0)--(s,s,s),dashed);
draw((s,0,s)--(s,s,s),dashed);
draw((0,s,s)--(s,s,s),dashed);
label("$A$", A, SW);
label("$B$", B, E);
label("$C$", C, N);
dot("$O$", O, NW);
dot((s,s,s));
[/asy]
pls help me
Answer:
Step-by-step explanation:To solve this problem, we can use similar triangles. Let the side length of the cube be s, and let the midpoints of AB, AC, and BC be P, Q, and R, respectively. Then OP, OQ, and OR are the diagonals of the faces of the cube, and so they are equal to .Consider triangle AOB. By the Pythagorean theorem, we have , so . Since angle AOB is 90 degrees, we can use similarity to see that triangle OAP is similar to triangle OAB, so . Solving, we find that .Using similar triangles, we can find that . Since the sum of the squares of the lengths of the diagonals of a cube is equal to three times the square of the side length, we have
$$(0P2 + 0Q? + OR?) = 35388 Substituting the values we found for $OP$, $OQ$, and $OR$, we haveSimplifying and solving for , we find that . Thus, the side length of the cube inscribed in the tetrahedron is .
Emilio puts $4,000.00 into an account to use for school expenses. The account earns 15% interest, compounded annually. How much will be in the account after 6 years?
Round your answer to the nearest cent.
Answer:
$10,359.73.
Step-by-step explanation:
We can use the formula for compound interest:
A = P(1 + r/n)^(nt)
where:
A = the amount of money after the specified time
P = the principal amount (the initial amount of money)
r = the annual interest rate (as a decimal)
n = the number of times the interest is compounded per year
t = the time (in years)
In this case, we have:
P = $4,000.00
r = 15% = 0.15
n = 1 (compounded annually)
t = 6 years
Substituting into the formula, we get:
A = 4000(1 + 0.15/1)^(1*6)
A = 4000(1.15)^6
A ≈ $10,359.73
Therefore, the amount in the account after 6 years, rounded to the nearest cent, is $10,359.73.
Can someone help me with my accounting assignment please?
The State Cash Flow Statement using the direct method.
OP INV FIN
Personnel emolument 2,000,000
CRF charges 1,000,000
Statutory revenue allocation 20,000,000
Proceeds from sale of fixed assets 100,000
Purchase of marketable securities 50,000
Purchase & construction of fixed assets 500,000
Share of VAT 200,000
Share of excess crude oil 100,000
Internally generated revenue 10,000,000
Gratuities and pension 15,000,000
Miscellaneous income 50,000
Overhead expenses 36,000
Recurrent grant made 20,000
Miscellaneous expenses 10,000
Servicing & repayment of public debts 100,000
Grants & subventions from NGO 200,000
Proceeds from loan & other borrowings 300,000
Dividends received 100,000
12,234,000 -450,000 500,000
Net Cash Flow for the year ended 31 December 2006: 12,284,000
How was the cash Flow Statement using the direct method solved?To prepare the State Cash Flow Statement using the direct method, we'll classify cash flows into three categories: Operating Activities (OP), Investing Activities (INV), and Financing Activities (FIN). Then, we'll calculate the net cash flow for each category and add them together to find the net cash flow for the year.
Operating Activities:
(-2,000,000 - 1,000,000 + 20,000,000 + 200,000 + 100,000 + 10,000,000 - 15,000,000 + 50,000 - 36,000 - 20,000 - 10,000) = 12,234,000
Investing Activities:
(100,000 - 50,000 - 500,000) = -450,000
Financing Activities:
(-100,000 + 200,000 + 300,000 + 100,000) = 500,000
Net Cash Flow for the year ended 31 December 2006:
12,234,000 (Operating Activities) - 450,000 (Investing Activities) + 500,000 (Financing Activities) = 12,284,000
The above answer is in response to the question below;
The following information has been extracted from the records of WELFARE STATE of Nigeria for the year ended 31 December 2006:
Personnel emolument 2,000,000
CRF charges 1,000,000
Statutory revenue allocation 20,000,000
Proceeds from sale of fixed assets 100,000
Purchase of marketable securities 50,000
Purchase & construction of fixed assets 500,000
Share of VAT 200,000
Share of excess crude oil 100,000
Internally generated revenue 10,000,000
Gratuities and pension 15,000,000
Miscellaneous income 50,000
Overhead expenses 36,000
Recurrent grant made 20,000
Miscellaneous expenses 10,000
Servicing & repayment of public debts 100,000
Grants & subventions from NGO 200,000
Proceeds from loan & other borrowings 300,000
Dividends received 100,000
You are required to:
Prepare the State Cash Flow Statements for the year ended 31 December 2006 using the direct method approach (ICAN May 2008)
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Please help me with this
a)There is higher variability of Y with larger values of X.
b) There is non linear relation between X and Y.
a) Based on the given figure, we can make the following observations:
The scatterplot shows an upward trend, indicating a positive relationship between X and Y.The points appear to be spread out in a fan-like shape, suggesting increasing variability of Y with larger values of X. This means that as X increases, the values of Y become more spread out.The scatterplot does not provide clear information about the variability of X with larger values of Y.Therefore, the correct statement is There is higher variability of Y with larger values of X.
b) Based on the features, it is likely that a linear model may not be suitable for these data, and a non-linear model or other regression techniques may be more appropriate to capture the relationship between X and Y accurately.
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Calculate, to the nearest cent, the Present Value of an investment that will be worth $1,000 at the stated interest rate after the stated amount of time.
3 years, at 1.3% per year, compounded weekly (52 times per year).
PV=?
[tex]~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill & \$ 1000\\ P=\textit{original amount deposited}\\ r=rate\to 1.3\%\to \frac{1.3}{100}\dotfill &0.013\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{weekly, thus fifty two} \end{array}\dotfill &52\\ t=years\dotfill &3 \end{cases}[/tex]
[tex]1000 = P\left(1+\frac{0.013}{52}\right)^{52\cdot 3} \implies 1000=P(1.00025)^{156} \\\\\\ \cfrac{1000}{(1.00025)^{156}}=P\implies 961.76\approx P[/tex]
How do I help my student understand this?
Cell 1 is in the "7th grade" row and "Pets" column. Have your student circle these labels or highlight them. Then it should be clear why choice E is the final answer.
Another way to rephrase it: the 35 people in cell 1 represent the number of 7th graders with pets.
What is the probability that a random sample of 20 second grade students from the city results in a mean reading rate of more than 96 words per minute?
Answer:
Step-by-step explanation:
We can calculate the t-statistic and the p-value as follows:
If we assume that the null hypothesis is true, then the t-statistic will follow a t-distribution with 19 degrees of freedom. We can compare the calculated t-statistic with the critical t-value at the 0.05 level of significance using a t-distribution table or statistical software.
If the calculated t-statistic is greater than the critical t-value, then we can reject the null hypothesis and conclude that there is sufficient evidence to support the alternative hypothesis that the population mean reading rate is greater than 96 words per minute.
The p-value is the probability of obtaining a t-statistic as extreme or more extreme than the calculated t-statistic, assuming the null hypothesis is true. We can use the t-distribution table or statistical software to find the corresponding p-value.
If the p-value is less than the significance level of 0.05, then we can reject the null hypothesis at the 0.05 level of significance and conclude that the probability of obtaining a random sample of 20 second grade students with a mean reading rate of more than 96 words per minute is statistically significant.
Math question sb please do ts giving branliest
Answer:
All lines are parallel
Step-by-step explanation:
Get each equation in Slope-Intercept form:
1. Divide both sides by 3: [tex]y=-\frac{4}{3}x+\frac{7}{3}[/tex]
2. No change
3. Subtract 8x and divide by 6 on both sides: [tex]y=-\frac{4}{3}x-\frac{2}{3}[/tex]
Notice:
a. All slopes are -4/3, AND
b. All y-intercepts are different
A man drove 14 miles directly east from his home, made a left turn at an intersection, and then traveled 7 miles north to his place of work. If a road was made directly from his home to his place of work, what would its distance be to the nearest tenth of a mile?
Your friend has a bag of yellow and purple candy. He wants to use them to play a game with you.
Purple is worth 2 points and yellow is worth three points. Pick 9 candies from the bag
Create a system of equations where the combination of the candies gives you a total of 22 points. Make sure you label and define your variables.
The system of equations where the combination of the candies gives you a total of 22 points are:
x + y = 9
2x + 3y = 22
How can we create system of equations?To create the equations, we shall first define the variables:
x = the number of purple candies
y = the number of yellow candies
Next, we shall use the given information that purple candies are worth 2 points and yellow candies are worth 3 points.
Then, we would make sure that the total number of candies selected is 9.
The first equation represents the total number of candies selected:
x + y = 9
The second equation represents the total number of points obtained:
2x + 3y = 22
Therefore, the system of equations is:
x + y = 9
2x + 3y = 22
This is a system of linear equations.
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-3k - 7 ≤ 17 help!!!!!!!!!!!!!!!
<
Javier and Naida are discussing the elevation of Lima, Peru.
200
150 Lima
100
50+
0+Sea level
-50-
-100+
-150
-200
The elevation of Lima, Peru is 154 meters.
Javier: Lima is 154] meters from sea level.
Naida: Lima is 154 meters above sea level.
Whose statement is true?
Choose 1 answer:
Answer:
Naida's statement is true
Step-by-step explanation:
Since the elevation of Lima, Peru is a positive number, you can automatically tell that it is above sea level since sea level is zero
Describe how the following functions are transformed from the parent function
f(x)=|x|-3
f(x)= - |x - 4|
f(x)= 1/3 |x|
f(x)= -2 |x-1|
Answer:
Each of these functions is a transformation of the parent function f(x) = |x|. The transformations include shifting the graph up or down, stretching or compressing the graph vertically, reflecting the graph across the x-axis, and shifting the graph left or right. The vertex of each graph is located at a different point.
Step-by-step explanation:
- The function f(x) = |x| - 3 is a transformation of the parent function f(x) = |x|. The "-3" at the end of the function shifts the graph 3 units down. This means that the vertex, or lowest point, of the graph is at (0, -3) instead of (0, 0).
- The function f(x) = -|x - 4| is also a transformation of the parent function f(x) = |x|. The negative sign in front of the absolute value function reflects the graph across the x-axis. The "-4" inside the absolute value function shifts the graph 4 units to the right. This means that the vertex of the graph is at (4, 0) instead of (0, 0).
- The function f(x) = (1/3)|x| is a transformation of the parent function f(x) = |x|. The "1/3" in front of the absolute value function stretches the graph vertically by a factor of 1/3. This means that the graph is narrower and closer to the x-axis than the parent function. However, because the absolute value function is symmetrical, the graph is still centered at (0, 0).
- The function f(x) = -2|x - 1| is also a transformation of the parent function f(x) = |x|. The negative sign in front of the absolute value function reflects the graph across the x-axis. The "-1" inside the absolute value function shifts the graph 1 unit to the right. The "2" in front of the absolute value function stretches the graph vertically by a factor of 2. This means that the graph is narrower and closer to the x-axis than the parent function, and it is also reflected across the x-axis. The vertex of the graph is at (1, 0).
What is -2 - 1 3\7 please help
Answer:
Step-by-step explanation:
To solve this expression, we need to first combine the integer part of -2 and -1, which gives us -3. Then, we need to combine the fractional parts of -1 and 3/7.
To do this, we find a common denominator, which is 7, and convert -1 to an equivalent fraction with denominator 7 by multiplying both the numerator and denominator by 7, which gives us -7/7.
Now we can add -7/7 and 3/7 to get -4/7.
Therefore, -2 - 1 3/7 = -3 - 4/7, which can also be written as -3 4/7 or -23/7 in improper fraction form
A sixth-grade class collected data on the number of letters in the first names (name lengths) of all the students in class. Here is the dot plot of the data they collected:
How many students are in the class?
Based on the data displayed in the dot plot, it can be concluded there are 25 students in this class.
How to know the number of students based on the dot plot?Dot plots represent data and trends but using dots. In these types of graphs, each individual is represented with a dot. For example, in the number 3, we can see there are 3 dots, which means three students have a first name made of three letters.
Therefore, you can get the total of students by counting all the dots. Based on this, there are 25 students in this class.
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A company produces two products, A and B. At
least 30 units of product A and at least 10 units of
product B must be produced. The maximum
number of units that can be produced per day is
80. Product A yields a profit of $15 and product B
yields a profit of $8. Let a = the number of units of
product A and b = the number of units of product
B.
What objective function can be used to maximize
the profit?
P=
DONE✔
a+
b
The objective function that can be used to maximize the profit is Profit = 15a + 8b
Let a is the number of units of product A and b is the number of units of product B.
Profit = 15a + 8b
This function represents the total profit earned by producing a units of product A and b units of product B
Given that the profit per unit of product A is $15 and the profit per unit of product B is $8.
To maximize the profit, we would need to find the values of a and b that satisfy the constraints given in the problem and maximize the value of the objective function
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What’s the correct answer for problem 16???
The values of x and y of the given transverse lines are:
x = 44.25° and y = 7.25°
How to find the missing angle on the line?We know that there are different classification of angles such as:
Corresponding angles
Alternate angles
Opposite angles
Supplementary angles
Complementary angles
Now, we also know that sum of angles on a straight line is 180 degrees. Thus:
5x - 9y - 16 = 140
5x - 9y = 156 -----(1)
We also know that alternate angles are defined as two angles, that are formed when a line crosses two other lines, that lie on opposite sides of the transversal line and on the opposite relative sides of the other lines. If the two lines crossed are parallel, then the alternate angles are equal.
Thus:
3x + y = 5x - 9y - 16
2x - 10y - 16 = 0
2x - 10y = 16 ----(2)
Solving simultaneously gives us:
x = 44.25° and y = 7.25°
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What is 15% of 100
Please help
Answer:
Step-by-step explanation:15
Express 1:0.2:0.75 in their simple form
Answer:
20 : 4 : 15
Step-by-step explanation:
1 : 0.2 : 0.75
1 : 2/10 : 75/100
1 : 20/100 : 75/100
(×100)
100 : 20 : 75
(÷5)
20 : 4 : 15
How to write Two times the sum of y and 5 is 24
Then solve
Answer:
Step-by-step explanation:
2(y+5)=24
A leading magazine (like Barron's) reported at one time that the average number of weeks an individual is unemployed is 32 weeks. Assume that for the population of all unemployed individuals is normally distributed and the population mean length of unemployment is 32 weeks and that the population standard deviation is 3.9 weeks. Suppose you would like to select a random sample of 66 unemployed individuals for a follow-up study.
Answer the following, rounding all answers to three decimal places.
Find the probability that a single randomly selected value is greater than 31.9.
P(X > 31.9) = ???
Find the probability that a sample of size
is randomly selected with a mean greater than 31.9.
P(M > 31.9) = ???
The probability that a single randomly selected value is greater than 31.9 is 0.511.
The probability that a sample of size 66 is randomly selected with a mean greater than 31.9 is 0.641.
How to calculate the probabilityProbability that a single randomly selected value is greater than 31.9:
z = (31.9 - 32) / 3.9 = -0.026
We can find the probability:
P(X > 31.9) = P(Z > -0.026) = 0.511
Also, μ = 32, σ = 3.9, n = 66
z = (31.9 - 32) / (3.9 / √66) = -0.363
Using a standard normal distribution table or calculator, we can find the probability:
P(M > 31.9) = P(Z > -0.363) = 0.641
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Prove the following this : Let H be a subgroup of a group G . The left cosets of H constitute a partition of G ; the right cosets of H constitute a partition of G ?
To prove that the left cosets of H constitute a partition of G, we need to show that they satisfy two conditions:
1) Each element of G belongs to some left coset of H.
2) Any two distinct left cosets of H are disjoint.
Let g be any element of G. Then, by definition of a left coset, there exists an element h of H such that g = h·x for some x in G. Therefore, g belongs to the left coset H·x. Since this holds for any element g of G, we have shown that the left cosets of H cover all of G, satisfying the first condition.
Now, let H·x and H·y be two distinct left cosets of H. Suppose there exists an element z in both H·x and H·y.
Then, z = [tex]h_{1}[/tex]·x = [tex]h_{2}[/tex]·y for some [tex]h_{1}[/tex], [tex]h_{2}[/tex] in H.
Solving for x,
x = [tex]h_{1}^{-1}[/tex]· [tex]h_{2}[/tex] · y.
Since H is a subgroup, [tex]h_{1}^{-1}[/tex]· [tex]h_{2}[/tex] is also in H, and therefore x belongs to H·y.
Thus, H·x is contained entirely in H·y, and the two cosets cannot intersect.
This satisfies the second condition, and hence the left cosets of H constitute a partition of G.
A similar argument can be used to show that the right cosets of H also constitute a partition of G. This completes the proof.
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(1/2 + 1/3) + [1/4 + (2/3)] ÷ 2/5 -4 x 5/6 ÷ 3/7
Answer:
Step-by-step explanation:
first, take 1/2+1/3 + 1/4+2/3
1/2+1/3=5/6 , 1/4+2/3=11/12
5/6+11/12=22/12
2/5-4=-18/5
-18/5*5/6=-3
22/12/3=22*3/12
=11/2
11/2/3/7=11/2*7/3
=77/6=12.8
A straw is placed inside a rectangular box that is g inches by 6 inches by 7 inches, as shown. If the straw fits exactly into the box diagonally from the bottom left corner to the top right back corner, how long is the straw? Leave your answer in simplest radical form.
Answer:
The length of the straw will be 5.91607 inches long in radical form.
What is Length of diagonal in cuboid?
If a cuboid has length = l units, breadth = b units, and height = h units, then we can evaluate the length of the diagonal of a cuboid using the formula
As per the question the length of the straw is equal to length of the diagonal of Rectangular box.
l= 3 inch , b= 5 inch , h= 1 inch
Let us consider the length of the straw be 'x'.
As, Diagonal of Cuboid is,
X= 5.91607 (in radical form)
Step-by-step explanation:
Hence, the length of the straw will be 5.91607 inches.
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What’s the answer? Will give brainliest if correct
Explain reasoning
The statement that is not true is: C. The translation of a line is a pair of parallel lines.
What is transformation?In geometry, a transformation is a procedure that modifies a figure's position, size, or shape. Translation, rotation, reflection, and dilation are the four main categories of transformations.
Every point in a figure is translated by the same amount and in the same direction. A rotation revolves a figure around the centre of rotation, a fixed point. A figure is reversed over a line known as the line of reflection in a reflection.
In relation to a fixed point known as the centre of dilation, a dilation expands or contracts a figure by a specific scale factor.
The statement that is not true is: C. The translation of a line is a pair of parallel lines as translation is a transformation that moves every point of a figure the same distance in the same direction.
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Please help will give a lot of points
Answer:
how many points will you give?
Step-by-step explanation:
Out of 600 people sampled, 42 had kids. Based on this, construct a 95% confidence interval for the true population proportion of people with kids.
Use GeoGebra to calculate! Give your answers as decimals, to three places
Answer:
So we can be 95% confident that the true proportion of people with kids in the population is between 0.044 and 0.096.
Step-by-step explanation:
To construct a confidence interval, we need to use the formula:
CI = p ± zsqrt((p(1-p))/n)
Where:
CI = confidence interval
p = sample proportion (in this case, 42/600 = 0.07)
z = the z-score corresponding to the desired level of confidence (in this case, 1.96 for a 95% confidence interval)
n = sample size (in this case, 600)
Plugging in the numbers, we get:
CI = 0.07 ± 1.96sqrt((0.07(1-0.07))/600)
Simplifying this, we get:
CI = 0.07 ± 0.026
Therefore, the 95% confidence interval for the true population proportion of people with kids is:
0.044 ≤ p ≤ 0.096
Find the value of x.
The value of x in the chord is 3 units.
How to find line segment when chord intersect?The chord intersection theorem states that the products of the lengths of the line segments on each chord are equal.
Therefore,
6(x + 5) = 4(2x + 6)
Open the brackets
6x + 30 = 8x + 24
subtract 8x from both sides of the equation
6x - 8x + 30 = 24
-2x + 30 = 24
subtract 30 from both sides of the equation'
-2x + 30 - 30 = 24 - 30
-2x = -6
divide both sides by -2
x = -6 / 2
x = 3
Therefore,
x = 3
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