Help me balance ittt

A) The amount of geothermal energy that reaches Earth's surface in one day is : 43.2 * 10¹⁷ joules

B) Humanity's current consumption of energy is; 71.4 GJ per individual.

C) Ratiois ; 60.5 * 10⁶ Joules

Given data :

Amount of energy flow = 50 terawatt =  50*10¹² joule/sec.

Since the geothermal energy reaches the earth in a single day

Energy = power * time

Time = 24 hours ( 1 day ) = 86400 secs.

Energy = 50*10¹² joule/sec * 86400 secs

            = 43.2 * 10¹⁷ joules

Humanity's current consumption of energy in one day is estimated to be 71.4 GJ per individual.

Geothermal energy / human current annual consumption

= 43.2 * 10¹⁷ Joules / 71.4 * 10⁹ Jolues

= 60.5 * 10⁶ Joules

Hence we can conclude that A) The amount of geothermal energy that reaches Earth's surface in one day is : 43.2 * 10¹⁷ joules

B) Humanity's current consumption of energy is; 71.4 GJ per individual.

C) Ratiois ; 60.5 * 10⁶ Joules

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Answer:

B

Explanation:

Answer:

It is refracted.

Explanation:

Answer:

It is refracted

Explanation:

The light changes direction when it enters and exits the prism. When white light is shone through a triangular prism, a rainbow of light is seen on the opposite side of the prism.

Answer:

Explanation:

C looks good,  b/c antinodes are where the waves is at a max displament.

The wave has exactly three antinodes is option C.

As in all status wave styles, each node is separated through an antinode. This sample with 3 nodes and two antinodes is known as the second one harmonic and is depicted within the animation.

The other of a node is an anti-node, a factor where the amplitude of the status wave is at most. those occur midway among the nodes. In a full wavelength of a status wave, there are two loops. So, there should be  nodes midway of every of the two loops.

Wave, propagation of disturbances from location to vicinity in a ordinary and prepared manner. maximum acquainted are floor waves that journey on water, however sound, mild, and the movement of subatomic particles all exhibit wavelike residences.

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Answer:

the answer is B

Explanation:

its b

hope this answer helps...!!!

The frictional torque exerted on the platform by the axle as the platform rotates will be;

[tex]\rm T_f \theta =\frac{1}{2} I [\omega^2-\omega_0^2][/tex]

Torque is the force's twisting action about the axis of rotation. Torque is the term used to describe the instant of force. It is the rotational equivalent of force. Torque is a force that acts in a turn or twist.

The amount of torque is equal to force multiplied by the perpendicular distance between the point of application of force and the axis of rotation.

Work done by the frictional torque = Change in the rotational kinetic energy of the wheel

[tex]\rm T_f \theta =\frac{1}{2} I [\omega^2-\omega_0^2][/tex]

Where,

[tex]\rm T_f[/tex] is the frictional torque

[tex]\rm \omega[/tex] is the final angular velocity

[tex]\rm \omega_0[/tex] is the initial angular velocity

[tex]\rm \theta[/tex] is the angular displacement

Hence, the frictional torque exerted on the platform by the axle as the platform rotates will be;

[tex]\rm T_f \theta =\frac{1}{2} I [\omega^2-\omega_0^2][/tex]

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Answer:

Condensation point is when the temperature at which a vapor condenses into a liquid without a change in the temperature of the substance.

Answer:

[tex]\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}[/tex]

The formula of Density for a random unit cell is as follows -

[tex]Density = \frac{ Z _{effective} \times M }{N _{a} \times a {}^{3} } \\ [/tex]

where ,

★ [tex]Z _{effective}[/tex] = number of atoms in a unit cell

★ M = molar mass

★ [tex] N _{a} = Avogadro's \: Number = 6 × 10^{23}[/tex]

★ a = edge length

now ,

In a tetragonal unit cell ,

the atoms are present over the corners as well as the at the body centre.

Therefore ,

[tex]Z _{effective} = contribution \: by \: the \: 8 \: corners \: + contribution \: by \: the \: body \: centre[/tex]

[tex]\implies \: (\frac{1}{8} \times 8) \: + \: 1 \\ \\ \implies \: 1 + 1 \\ \\ \implies2[/tex]

And ,

[tex]N _{a} = 6 \times 10 {}^{23} [/tex]

Substituting the values of the following in the formula of Density , we get

[tex]\bold\purple{Density = \frac{2 \times M}{6 \times 10 {}^{23} \times a {}^{3} }} \\[/tex]

hope helpful :D

For two runners  running in a 500 meter dash and runner, the speeds of both runners  is mathematically given as

v1=25m/s

v2=20m/s

and the first runner is faster

Generally, the equation for the speed  is mathematically given as

v=d/t

Therefore, for first runner

v=500/20

v1=25m/s

For 2nd runner

v=500/25

v2=20m/s

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Answer: current is 3 A.

Explanation:

V = 6V

R = 2Ω

I = ?

∴ V = IR

I = V/R

I = 6V/2Ω

I = 6/2

I = 3 A ...answer...

hope that helps...

Answer:

3 amps

Explanation:

V = IR

V/R = I

6/2 = 3  amps

Electric field refers to the region in space where the influence of a charge is felt, the height of the building is 447 m.

The term electric field refers to the region in space where the influence of a charge is felt.

Since we know that;

E = F/q =  4.48 x 104N/1C = 4.48 x 10^4 N/C

E = Kq/r^2

4.48 x 10^4 = 9 * 10^9 * 1/r^2

r = √9 * 10^9/4.48 x 10^4

r = √2 * 10^5

r = 447 m

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The value of the coefficient of kinetic friction between the wagon and inclined surface is 0.78.

The value of coefficient of kinetic friction is calculated as follows;

F - Ff = ma

F - μmgcosθ = ma

where;

182 - μ(20 x 9.8 x cos30) = 20(2.5)

182 - 169.74μ = 50

182 - 50 = 169.74μ

132 = 169.74μ

μ = 132/169.74

μ = 0.78

Thus, the value of the coefficient of kinetic friction between the wagon and inclined surface is 0.78.

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Hi there!

(a)

Recall that:
[tex]W = F \cdot d = Fdcos\theta[/tex]

W = Work (J)
F = Force (N)
d = Displacement (m)

Since this is a dot product, we only use the component of force that is IN the direction of the displacement. We can use the horizontal component of the given force to solve for the work.

[tex]W =248(56)cos(30) = 12027.36 J[/tex]

To the nearest multiple of ten:
[tex]W_A = \boxed{12030 J}[/tex]

(b)
The object is not being displaced vertically. Since the displacement (horizontal) is perpendicular to the force of gravity (vertical), cos(90°) = 0, and there is NO work done by gravity.

Thus:
[tex]\boxed{W_g = 0 J}[/tex]

(c)
Similarly, the normal force is perpendicular to the displacement, so:
[tex]\boxed{W_N = 0 J}[/tex]

(d)

[tex]F_{f} =\mu_k N[/tex]

In this instance, the normal force is equivalent to the downward force of gravity and the vertical component of the applied force.

[tex]N = F_g + F_A sin(30)\\\\N = mg + F_A sin(30)\\\\N = 56(9.8) + 248sin(30) = 672.8 N[/tex]

Since the force of friction resists the applied force (assigned the positive direction), the work due to friction is NEGATIVE because energy is being LOST. Thus:
[tex]W_f = -\mu_k Nd\\W_f = - (0.1)(672.8)(56) = -3767.68J[/tex]

In multiples of ten:
[tex]\boxed{W_f = -3770 J}[/tex]

(e)
Simply add up the above values of work to find the net work.

[tex]W_{net} = W_A + W_f \\\\W_{net} = 12027.36 + (-3767.68) = 8259.68 J[/tex]

Nearest multiple of ten:
[tex]\boxed{W_{net} = 8260 J}}[/tex]

(f)
Similarly, we can use a summation of forces in the HORIZONTAL direction. (cosine of the applied force)
[tex]F_{net} = F_{Ax} - F_f[/tex]

[tex]W = F_{net} \cdot d = (F_{Ax} - F_f)[/tex]

[tex]W = (F_Acos(30) - \mu_k N)d\\W = (248cos(30) - 0.1(672.8)) * 56 \\\\W = 8259.68 J[/tex]

Nearest multiple of ten:
[tex]\boxed{W_{net} = 8260 J}[/tex]

Answer:When trying to simplify and find the equivalent resistance you

should first simplify resistors in PARALLEL before

simplifying those in SERIES

Explanation: hope this helps:)

Answer:

the wave length is 7.6 inches

Explanation:

Answer: Kingdom Monera

Answer:

The answer is A.

Explanation:

The friction generated heat to release chemical energy because the same same thing happens with fluorescent and sodium vapor lamps; heat causes the (low-pressure) mercury/sodium vapor gas lamp to cause a lot of heat energy resulting in the same thing happening when you strike a match.

(a) The work done by the gas during the isothermal expansion is -25.6 J.

(b) The heat added to the gas during this process is 25.6 J.

The net work done by the ideal gas in the isothermal expansion is calculated as follows;

W(net) = ΔP x ΔV

W(net) = ( 1 kPa - 5 kPa) x (8L - 1.6 L)

W(net) = -25.6 kPa.L

W(net) = -25.6 J

The heat added to the gas is calculated as follows;

W = -Q

-25.6 J = -Q

Q = 25.6 J

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Answer: It is brighter

Explanation: We are getting closer to the light because the earth is expanding.

the answer is it is brighter cause the light from the object is known as blueshift

Answer:

Above is correct

Answer:

sawing a board in half

dissolving sugar in water

a block of ice subliming

Explanation:

Answer: Dissolving sugar in water, burning a match, and sawing a board in half

Explanation: Dissolving sugar in water is an example of a physical change. Here's why: A chemical change produces new chemical products. In order for sugar in water to be a chemical change, something new would need to result. A chemical reaction would have to occur.

When a match burns, it undergoes a chemical change. Matches use sulfur, phosphate and a friction agent held together by a binding agent. With a match, heat ignites the phosphorous on the head of the match

cutting of wood is a physical change because only physical property of wood is changed and no new substance is formed. the properties of wood remains the same. burning of wood is a chemical change as new substances are formed that is smokes and CO2. it is different from wood.

I hope this is the correct answer im pretty sure because I've finished that quiz or test already

Answer:

W=F⋅l=F⋅vt=900(N)⋅19.44(m/s)⋅900(s)=15.75⋅10

6 (J)

Explanation:

Answer:

because of the oxygen in our bodies.

Answer:

v = 48

Explanation:

follow the formula v = i x r add up all the resistors an multiply it by the current

Hi there!

a)

We know that the resistance of the wire is equivalent to:
[tex]R = \frac{\rho L}{A}[/tex]

R = Resistance (Ω)
ρ = Resistivity (Ωm)

L = Length (m)

A = Cross-sectional area (m²)

We can relate the voltage to an electric field by:
[tex]V = Ed \\\\V = El[/tex]

V = Potential Difference (V)
E = Electric Field (V/m)

l = Length of wire (m)

And Ohm's Law:
[tex]V =iR[/tex]

i = Current (A)

V = Potential Difference (V)

R = Resistance (Ω)

We do not know the length, so we can solve using the above relationships.

[tex]V = iR\\\\V = i\frac{\rho L}{A}\\\\\frac{V}{L} = E = i\frac{\rho}{A}\\\\i = \frac{EA}{\rho} = \frac{.55 \times \pi (0.00044^2)}{(2.44 \times 10^{-8})}} = \boxed{13.71 A}[/tex]

b)

We know that V = Ed (Electric field × distance), so:

[tex]V = 0.55 \times 6.3 = \boxed{3.465 V}[/tex]

c)

Calculate the resistance using the above equation.

[tex]R = \frac{\rho L}{A}\\\\R = \frac{(2.44\times 10^{-8})(6.3)}{\pi(0.044^2)} = \boxed{2.527 \times 10^{-5} \Omega}[/tex]

Objective assessment is the type which is based on repeatable, measurable data.

This involves the use of unbiased and balanced observation based on verified facts.

This is verified by the use of  repeatable and measurable data so as to ensure the accuracy is high in this scenario.

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The speed of cart b is 6m/s while the total momentum of the systmen is 4200 kg m/s

Given Data

Mass of cart two M2  = 150kg

Velocity U2 = 6m/s

Applying the principle of conservation of linear momentum we have

M1U1+M2U2 = M1V1+ M2V2

a. what is the speed of cart b after collision

substituting our given data we have

150*8+ 150*6 = 150*5+150*V2

1200 + 900 = 1200+ 150V2

2100 - 1200 = 150V2

900 = 150V2

Divide both sides by 150

V2 = 900/150

V2 = 6m/s

b. what is the total momentum of the system before and after collision

Total Momentum in the system is

Total momentum = Momentum before Impact+ Momentum after Impact

Total momentum = M1U1+M2U2 + M1V1+ M2V2

Total momentum = 1200 + 900 + 1200+ 900

Total momentum = 4200 kg m/s

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