The force exerted by air on a disk of radius 1.00m at the water's surface is approximately 318.3 N.
To calculate the force exerted by air on a disk of radius 1.00m at the water's surface, we need to know the air pressure and the surface area of the disk.
Assuming standard atmospheric pressure at sea level of 101.325 kPa and neglecting any effects due to wind, we can calculate the force exerted by air on the disk as follows:
Determine the surface area of the disk:
A = [tex]πr^2[/tex]
where r = 1.00m
A = [tex]π(1.00m)^2 = 3.14 m^2[/tex]
Calculate the force exerted by air on the disk using the formula:
F = PA
where P is the air pressure and A is the surface area of the disk.
F = [tex](101.325 kPa)(3.14 m^2)[/tex] = 318.3 N
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the function f(x) = -x^2 - 9x+36 shows the relationship between the vertical distance of a diver from a pool's surface f(x), in feet, and the horizontal distance x, in feet, of a diver from the diving board. What is a zero of f(x), and what does it represent?
The zeros of the function f(x) are x = 3 and x = -12.
To find the zeros of a function, we need to solve the equation f(x) = 0. In this case, we have:
f(x) = -x^2 - 9x + 36
Setting f(x) = 0, we get:
-x^2 - 9x + 36 = 0
We can solve this quadratic equation by factoring or by using the quadratic formula. Factoring, we get:
-(x - 3)(x + 12) = 0
Setting each factor equal to zero, we get:
x - 3 = 0 or x + 12 = 0
Solving for x, we get:
x = 3 or x = -12
These zeros represent the horizontal distances from the diving board where the vertical distance of the diver from the pool's surface is zero. In other words, they represent the points where the diver enters the water. The zero x = 3 represents the point where the diver enters the water at a distance of 3 feet from the diving board, while the zero x = -12 represents the point where the diver enters the water at a distance of 12 feet behind the diving board. However, the negative solution x = -12 is not meaningful in this context since it represents a point that is behind the diving board, so we discard it. Therefore, the zero x = 3 is the meaningful solution, which represents the point where the diver enters the water at a distance of 3 feet from the diving board.
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(a) Find the frequency ratio between the two frequencies fi = 256 Hz and f2=320 Hz.
(b) Add the interval of a fifth to f2 to obtain fs, and find the frequency ratio falfi.
(c) Find the frequency of fs.
The frequency ratio between fi = 256 Hz and f2 = 320 Hz is 4:5.Adding the interval of a fifth to f2 (320 Hz) results in fs (400 Hz). The frequency ratio falfi is 5:8.The frequency of fs is 400 Hz.
What is the interval of a fifth in music theory?The interval of a fifth in music theory is the distance between two notes that are five notes apart in a diatonic scale. For example, the distance between C and G is a fifth.
How are frequency and pitch related in music?Frequency and pitch are related in music because the pitch of a note is determined by its frequency. Lower frequencies result in lower pitches, whereas higher frequencies result in higher pitches.
The relationship between frequency and pitch is logarithmic, meaning that a doubling of frequency results in an increase of one octave (a doubling of pitch).
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As the frequency of a wave is increased, it's: (PICK TWO) A. Wavelength remains the same b. Velocity remains the same c. Velocity decreases d. Velocity increases e. Wavelength decreases f. Wavelength increases
As the frequency of a wave is increased, its wavelength decreases and its velocity remains the same.
What connection exists between a wave's wavelength and frequency?Wavelength and frequency are inversely proportional in a wave. This implies that a wave's wavelength reduces as its frequency rises and vice versa.
What is the significance of the velocity of a wave?The velocity of a wave represents how fast the disturbance is traveling through the medium. It is determined by the properties of the medium, such as its density and elasticity, and is independent of the wave's frequency and wavelength.
The velocity of a wave can be used to calculate other wave properties, such as its period and amplitude.
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In which connection the Vi=V=V2=...? And why?
The sum of the separate voltages in a series circuit, or V = V1+V2, determines the total voltage. Its total resistance (aka load) of a circuit is, as you might assume, equal to the sum individual resistors, R = R1 + R2.
How much voltage is present in a parallel connection?There are two or even more pathways for current to travel through in a parallel circuit. Each element of the parallel connection has the same voltage applied to it. The total flow of current from the source is equivalent to the total of a currents across each path.
What does resistor series connection mean?If the identical amount of current passes through each resistor at the same time, two or even more resistors are considered to be linked in series. That voltage over each resistor in such circuits varies. If any resistor in a linked to the concepts breaks or has a problem, the circuit as a whole is shut off.
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What is the impulse that Earth exerts on it during the first 0.50m of its fall? The next 0.50 m ?
The impulse exerted by Earth on the apple during the first 0.50 m of its fall is 0.74 Ns, and during the next 0.50 m, it is 0.37 Ns.
Using the equation for impulse, which is impulse = force x time, we can calculate the impulse that Earth exerts on the apple during the first 0.50 m and the next 0.50 m of its fall.
First, we need to calculate the force of gravity acting on the apple, which is given by the equation F = mg, where m is the mass of the apple and g is the acceleration due to gravity (approximately 9.81 m/s^2).
The mass of the apple is 150 g, which is 0.15 kg. Therefore, the force of gravity acting on the apple is:
F = mg = (0.15 kg)(9.81 m/s^2) = 1.47 N
Now, we can calculate the impulse exerted by Earth on the apple during the first 0.50 m of its fall. Since the force of gravity is constant, we can use the equation impulse = force x distance, where distance is the distance over which the force is applied.
Impulse during first 0.50 m = force x distance = (1.47 N)(0.50 m) = 0.74 Ns
For the next 0.50 m of the apple's fall, we need to consider that the velocity of the apple is increasing, so the force of gravity is no longer constant. However, we can approximate the average force over this distance as half the force at the start of the fall, or 0.5(1.47 N) = 0.74 N.
Using the same equation impulse = force x distance, we can calculate the impulse exerted by Earth on the apple during the next 0.50 m of its fall:
Impulse during next 0.50 m = force x distance = (0.74 N)(0.50 m) = 0.37 Ns.
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What is Newton's law of cooling
Answer:
Q = h . A . (T (t) - T env)
the rate of loss of heat from a body is directly proportional to the difference in the temperature of the body and its surroundings.
Explanation:
Q = rate of heat transfered out of the body
h = heat transfers coefficient
A = heat transfer to surface area
T = temperature of the objects surface
T env = temperature of the environment
T (t) = time dependent temperature
Below are some properties of candle wax (paraffin wax). Candle wax Melting point (mp)=68°C Specific heat capacity (c)=29j/g°C Specific latent heat of fusion (L) = 220j/g .Calculate the energy gained when changing the temperature of 100g of solid candle wax at 20°C to liquid at 68°C.
To calculate the energy gained when changing the temperature of 100g of solid candle wax at 20°C to liquid at 68°C, we need to consider two processes:
(1) raising the temperature of the wax from 20°C to 68°C
(2) melting the wax at its melting point of 68°C.
The first process requires an energy input of Q1 = mcΔT, where m is the mass of the wax (100 g), c is the specific heat capacity of the wax (29 J/g°C), and ΔT is the change in temperature (68°C - 20°C = 48°C). Thus, Q1 = (100 g)(29 J/g°C)(48°C) = 139,200 J.
The second process requires an energy input of Q2 = mL, where L is the specific latent heat of fusion of the wax (220 J/g). Thus, Q2 = (100 g)(220 J/g) = 22,000 J.
Therefore, the total energy gained when changing the temperature of 100g of solid candle wax at 20°C to liquid at 68°C is Q = Q1 + Q2 = 139,200 J + 22,000 J = 161,200 J.
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when is the angular momentum of asystem constant
The angular momentum of a system is conserved when there is no external torque acting on the system.
This is known as the law of conservation of angular momentum. Mathematically, it can be expressed as:
L = Iω
where L is the angular momentum of the system, I is the moment of inertia, and ω is the angular velocity. If the net external torque acting on the system is zero, then the angular momentum of the system remains constant.
This law has many applications in physics, including in rotational motion, celestial mechanics, and quantum mechanics. For example, the conservation of angular momentum explains why a spinning ice skater speeds up when they bring their arms inwards, and why the Earth's rotation remains constant over long periods of time.
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The two formulas above give the Schwarzschild radius, R, of a black hole in terms of its mass, M. From Equation 1, verify Equation 2, which gives R in meters and M in kilograms, using c = 3x108 m/s for the speed of light, and G = 6.67x10-11 Newtons m2/kg2 for the gravitational constant.
Problem 2: Calculate the Schwarzschild radius, in meters, for Earth where M = 5.7 x 1024 kilograms.
Problem 3: Calculate the Schwarzschild radius, in kilometers, for the sun, where M = 1.9 x 1030 kilograms.
Problem 4: Calculate the Schwarzschild radius, in kilometers, for the entire Milky Way, with a mass of 250 billion suns.
Problem 5: Calculate the Schwarzschild radius, in meters, for a black hole with the mass of an average human being with M = 60 kilograms.
Using the formula given, the Schwarzschild radius are calculated below;
What is the Schwarzschild radius?Problem 1:
Given: R = 2GM/c² and R = 1.48 × 10⁻²⁷M
Using c = 3x10^8 m/s and G = 6.67x10^-11 Nm^2/kg^2
G = gravitational constant, c = speed of light
Substituting the values, we get:
1.48 × 10⁻²⁷M = 2GM/c²
R = 2GM/c² = (2 x 6.67x10^-11 x M)/(9x10^16)
R = 1.48 x 10^-27 M
The radius is 1.48 * 10^-27M
Problem 2:
To calculate the Schwarzschild radius, we simply need to substitute the values into the equation
Given: M = 5.7 x 10^24 kg
Using R = 2GM/c² = (2 x 6.67x10^-11 x M)/(9x10^16)
R = 8.45 * 10^-3m
Problem 3:
Given: M = 1.9 x 10^30 kg
Using R = 2GM/c² = (2 x 6.67x10^-11 x M)/(9x10^16)
R = 2816.2 kilometers
Problem 4:
Given: M = 250 billion suns = 250 x 10^9 x 1.9 x 10^30 kg
Using R = 2GM/c² = (2 x 6.67x10^-11 x 2.5 x 10^11 x 1.9 x 10^30)/(9x10^16)
R = 7.04 x 10^14 kilometers
Problem 5:
Given: M = 60 kg
Using R = 2GM/c² = (2 x 6.67x10^-11 x 60)/(9x10^16)
R = 8.9 x 10^-26 meters
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a block of mass 300kg is sliding down a ramp of 4 m from a height of 3 m .calculate the coefficient of kinetic friction,mechanical advantage ,va
the coefficient of kinetic friction is approximately 0.689, the mechanical advantage is 4/3, and the velocity ratio is 1.22.
the coefficient of kinetic friction, mechanical advantage, and velocity at the bottom of the ramp, we need to use the conservation of energy principle. At the top of the ramp, the block has potential energy given by mgh, where m is the mass of the block, g is the acceleration due to gravity, and h is the height of the ramp. At the bottom of the ramp, the block has kinetic energy given by (1/2)m[tex]v^2[/tex], where v is its velocity. Assuming there is no energy loss due to friction, we can equate the potential energy at the top of the ramp to the kinetic energy at the bottom of the ramp.
1-Ep = Ek + Wf
mgh = 1/2 * m[tex]v^2[/tex]+ μk * mg * d
Solving for the coefficient of kinetic friction, we get:
μk = (mgh - 1/2 * m[tex]v^2[/tex]) / (mgd)
μk = (2gh - [tex]v^2[/tex]) / (2gd)
μk = (2 * 9.81 m/[tex]s^2[/tex] * 3 m - [tex]v^2[/tex]) / (2 * 4 m)
μk = 0.689
2-The mechanical advantage of the ramp is given by the ratio of the length of the ramp to the height from which the block falls:
MA = d / h = 4 m / 3 m = 4/3
3-VR = v / sqrt(2gh)
Ep = Ek + Wf
mgh = 1/2 * m[tex]v^2[/tex] + μk * mg * d
Solving for v, we get:
v = sqrt(2gh - 2μkgd) = 5.77 m/s
So the velocity ratio is:
VR = 5.77 m/s / sqrt(2 * 9.81 m/[tex]s^2[/tex] * 3 m) = 1.22
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A proton traveling due east in a region that contains only a magnetic field experiences a vertically upward force (away from the surface of the earth). What is the direction of the magnetic field with respect to your screen? Question 4 options: a) into your screen b) to the right c) out of your screen d) to the left
The direction of the magnetic field with respect to your screen is d) to the left.
The upward force experienced by the proton indicates that the magnetic field is acting perpendicular to both the motion of the proton (due east) and the force it experiences. According to the right-hand rule for magnetic forces, if you point your thumb in the direction of the velocity of the charged particle (due east in this case) and your fingers in the direction of the force (vertically upward), then the direction your palm faces represents the direction of the magnetic field.
In this scenario, if you extend your left hand and point your thumb to the right (due east) and your fingers vertically upward, your palm will face to the left, indicating that the magnetic field is directed to the left. Therefore, option d) to the left is the correct answer. The magnetic field is perpendicular to the plane of the screen and points into the screen.
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A 10,000 kg railroad car is rolling at 4.00 m/s when a 4000 kg load of gravel is suddenly dropped in.
What is the car's speed just after the gravel is loaded?
The speed of the car just after the gravel is loaded is 2.8m/s.
An isolated system experiences a change in momentum to zero when the starting and final velocities are equal. The reactions between the particles are separated from the surroundings. Momentum is conserved, so we use the rule of conservation of momentum, which is expressed by the equation
[tex]P_{f}[/tex]=[tex]P_{i}[/tex](1)
Railway is frictionless due to isolated mechanism. The thing travels at a momentum p-based speed while having mass. m
An object's bulk and velocity v are combined to form a vector.Equation of the form gives the velocity.
[tex]p=mv[/tex]
Using expression p into equation (1)
[tex]m_{f}v_{f}[/tex]=[tex]m_{i}v_{i}[/tex](2)
The final mass of a car is its original mass plus the mass of the gravel added. A car has an initial mass of.10000Kg preliminary pace is
[tex]m_{f}[/tex]=10000Kg+4000Kg=14000Kg
initial speed 4m/s
the final speed should be found after solving the equation(2) for [tex]v_{f}[/tex]
[tex]v_{f}[/tex]=[tex]\frac{m_{i}v_{i} }{m_f} }[/tex]=[tex]\frac{10000Kg(4m/s)}{1400Kg}[/tex]=2.8m/s
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Write an essay on the meaning of life.
35 points cuz it's kinda hard
Answer:
The meaning of life is one of the most profound and enduring questions that has plagued humanity for centuries. Philosophers, scientists, and theologians have all attempted to answer this question in their own ways, yet it remains an enigma that has yet to be fully understood. At its core, the meaning of life is a subjective concept that is shaped by individual beliefs, experiences, and values. However, there are several common themes and ideas that have emerged from various attempts to answer this question. One of the most prominent views on the meaning of life is that it is to find purpose and fulfillment. This view suggests that we should strive to find something that gives our lives meaning, whether it be through our work, relationships, or personal pursuits. This idea is often associated with the concept of happiness, as many believe that true happiness can only be achieved by finding purpose and meaning in one's life. Another
Easy physics.
if the ball in the following image continues to accelerate at a rate of 10m/s after it reaches the peak height and begins to move back down, what velocity should the ball 3 seconds after reaching the peak height.
The velocity of the ball 3 seconds after reaching the peak height is 30 m/s. And the right option is D. 30 m/s
What is velocity?Velocity is the rate of change of displacement.
To calculate the velocity the ball will travel after reaching the peak height, we use the formula below
Formula:
v = u+at...................... Equation 1Where:
v = velocity at which the ball travels after reaching the peak heightu = Initial velocitya = Accelerationt = TimeFrom the question,
Given:
a = 10 m/s²u = 0 m/s (At the peak height)t = 3 secondsSubstitute these values into equation 1
v = 0+(3×10)v = 30 m/sHence, the velocity is 30 m/s.
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As a beam of light enters a swimming pool, it will_____
1. bend
2.remain on a straight path
3. be absorbed
because light waves____when they pass from one medium to a different medium.
1. reflect
2.refract
3.diffract
Answer:
bend
refract
................
which patterns do you notice about the intensities of the reflected and the refracted rays? What can you conclude from this pattern?
The angle on incidence and the characteristics of the objects involved determine how intense the reflected & refracted rays are. But generally speaking, there are some trends that may be seen.
Where is the ray being reflected?The incident & surface normal planes specify the plane in which light that Reflects always falls. The rules of reflection applies to images created by both curved and planar mirrors.
What do reflection and refracted light mean?Reflection is the act of light simply returning when it strikes a material on a plane. Refraction is the process by which light passes through a medium and undergoes a change that causes it to bend. The medium returns the light that it received.
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The food calorie is equivalent to 4190 J . How many food calories does the cyclist burn if he rides over level ground at 7.3 m/s for 1.5 h ?
Answer:
To solve this problem, we need to use the formula: calories burned = (power expended in watts x time in seconds) / 4.184 First, we need to find the power expended in watts. We can use the formula: power = force x velocity Assuming the cyclist weighs 75 kg, the force required to maintain a speed of 7.3 m/s on level ground is: force = mass x acceleration force = 75 kg x 0 m/s^2 (since the cyclist is not accelerating) force = 0 N Therefore, the power expended by the cyclist is: power = force x velocity power = 0 N x 7.3 m/s power = 0 W Now we can plug in the values into the calories burned formula: calories burned = (power expended in watts x time in seconds) /
EARTH AND SPACE SCIENCE!
Scientist that made several important observations that seemed to counter the current beliefs of the time held by the church in Rome. Sunspots and rough features on the moon countered the idea of perfect "heavens" while the phases of Venus and the moons of Jupiter orbited other bodies than the Earth.
a.) Johannes Kepler
b.) Galileo Galilei
c.) Tycho Brahe
d.) Sir Isaac Newton
b) Galileo Galilei. Galileo was an Italian scientist and astronomer who made several important observations that seemed to contradict the current beliefs of the Roman Catholic Church.
His observations included sunspots, rough features on the moon, the phases of Venus, and the moons of Jupiter orbiting other bodies than the Earth. These observations were instrumental in helping to demonstrate that the Earth was not the center of the Universe, as the Church had previously believed. He is often referred to as the "father of modern observational astronomy" and the "father of modern science.". Additionally, he made detailed studies of sunspots, which contradicted the idea of a perfect and unchanging heavens.
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**DUE TOMORROW NEED ANSWER ASAP**
If the entire mass of the Milky Way was due to gas and stars, how would you expect the rotational speed of a star near the edge of the galaxy to compare to the rotational speed of a star near the center?
Observations of a Milky Way have brought out that stars close to the galaxy's edge rotate rather quickly, which implies that there is more solar masses that we are unable to perceive.
What is a star of mass 1 solar?The Sun-like star is known as a 1-solar mass star. At the rightmost to the bottom left in the stars, the primary structure region is where this type of star begins. Nearing the end its main-sequence existence, the star transforms into a red giant as it keeps burning its fuel.
The eight solar masses are known as.As far as I'm aware, "massive stars" are defined as having masses equal or greater than to eight solar masses.
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In your design, how would you change the mass of Car A to minimize (make less) the change in motion of Car A due to the collision? Explain your idea using Newton's Third Law and support it with evidence from the system model in this activity
to minimize the change in motion of Car A due to the collision, we should decrease the mass of Car A relative to the mass of Car B.
Newton's Third Law states that for every action, there is an equal and opposite reaction. This means that in a collision between two objects, the force that Car A exerts on Car B is equal and opposite to the force that Car B exerts on Car A.
To minimize the change in motion of Car A due to the collision, we need to minimize the force that Car B exerts on Car A. This can be achieved by decreasing the mass of Car A relative to the mass of Car B.
We can see evidence of this from the system model in the activity. When Car A and Car B have equal masses, they experience equal and opposite forces during the collision, and their velocities are both affected to the same degree. However, when Car A has less mass than Car B, Car B experiences a greater force during the collision, but Car A experiences a smaller force. As a result, Car A experiences less of a change in velocity than it would if the masses were equal.
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A sound wave has a frequency of 668 Hz in air
and a wavelength of 0.5 m.
What is the temperature of the air?
Relate the speed of sound in air to temper-
ature in units of Kelvin, but answer in units
of Celsius.
Assume the velocity of sound at 0°C is
334 m/s.
Answer in units of degC.
The temperature of the air would be 6.3 °C.
Sound wave and air temperatureThe speed of sound in air depends on the temperature of the air according to the equation:
v = 331.5 m/s * sqrt(T/273.15 K)
where v is the speed of sound, T is the temperature of the air in Kelvin, and 273.15 K is the temperature at which the speed of sound is 331.5 m/s.
We know the frequency and wavelength of the sound wave, which are:
f = 668 Hz
λ = 0.5 m
The speed of sound can be calculated from the formula:
v = fλv = (668 Hz) * (0.5 m) = 334 m/sSubstituting this value for v and the given value for the speed of sound at 0°C into the equation above and solving for T gives:
v = 331.5 m/s * sqrt(T/273.15 K)(T/273.15 K) = (v/331.5 m/s)^2(T/273.15 K) = (334 m/s / 331.5 m/s)^2(T/273.15 K) = 1.022T = 1.022 * 273.15 KT = 279.4 KThe temperature of the air is 279.4 K, which is equivalent to 6.3 °C, rounded to 1 decimal place.
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Evaluate the formula x² =
(n-1)s²
0²
when o = 2.94, n=39, and s=3.15.
x² = (Round to three decimal places as needed.)
Answer:
x² = ((n-1)s²)/o²
x² = (39 - 1) * (3.15)² / (2.94)²
x² = 38 * 9.9225 / 8.6436
x² = 43.7598
Rounding to three decimal places, x² = 43.760. Therefore, the value of x² is 43.760 when o = 2.94, n = 39, and s = 3.15.
Explanation:
Math
EARTH AND SPACE SCIENCE!
Scientist who ushered out old astronomy by constructing a model of the solar system with the Sun at its center and the planets moving around the Sun.
a.) Galileo Galilei
b.) Nicolaus Copernicus
c.) Tycho Brahe
d.) Sir Isaac Newton
The scientist name is b) Nicolaus Copernicus.
Nicolaus Copernicus was a Polish astronomer who is credited with ushering out old astronomy by constructing a model of the solar system with the Sun at its center and the planets moving around the Sun. He published his model, known as the heliocentric model, in 1543. This model eventually replaced the geocentric model, which placed the Earth at the center of the universe. Copernicus is also credited with making significant contributions in other areas of astronomy, including the motion of the moon and the motion of comets.This model replaced the Ptolemaic model, which had held that the Earth was the center of the universe, and ushered in a new era of astronomy.
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4. An ice skater is spinning on the ice at 4.00 rev/s. If the skater’s nose is 0.120 m from the axis of rotation, what is the centripetal acceleration of his nose?
The centripetal acceleration of the ice skater spinning on the ice at 4.00 rev/s whose nose is 0.120 m from the axis of rotation is [tex]75.78m/s^2[/tex]
Given the rate of revolutions of a skater = 4rev/s
The distance of nose from skater = 0.120m
Let the centripetal acceleration of his nose = ac
The centripetal acceleration of an object moving in a circular path can be calculated using the equation:
[tex]ac = (v^2)/r[/tex]
where v is the velocity of the object, and r is the radius of the circle.
In this case, the angular velocity of the skater is 4.00 rev/s.
Since 1 revolution is = 2π radians,
the skater's angular velocity can be expressed as:
v = rω such that
[tex]\omega = (4.00 rev/s) * (2\pi radians/1rev) = 8\pi rad/s = 25.13rad/s[/tex]
Using the equation above, the centripetal acceleration of the skater's nose can be calculated as:
[tex]ac = \omega^2r^2/r = \omega^2r[/tex]
[tex]ac = (25.13 radians/s)^2*0.120 m[/tex]
[tex]ac = 75.78m/s^2[/tex]
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Because iron is more reactive than copper;it takes its place in a reaction with copper sulphate.What is the word equation?
Answer:
The word equation for the reaction between iron and copper sulfate can be written as:
Iron + Copper sulfate -> Iron sulfate + CopperThis is a displacement reaction, where the more reactive iron displaces the less reactive copper from the copper sulfate solution, forming iron sulfate and copper as products.
Explanation:
The balanced chemical equation for the reaction between iron and copper sulfate is:
Fe + CuSO4 → FeSO4 + CuThis equation shows that one atom of iron (Fe) reacts with one molecule of copper sulfate (CuSO4) to produce one molecule of iron sulfate (FeSO4) and one atom of copper (Cu). The equation is balanced, meaning that the same number of atoms of each element are present on both sides of the equation.
help please!!!
1 . A particle moves in a straight line with constant acceleration. The particle starts moving from rest. It takes the particle 2 seconds to travel 800 meters. Find the acceleration?
2. A golf ball accelerates off a tee at 15m/s2, changing its velocity from 10 m/s to 80m/s down the fairway. How long did it take the golf ball to accelerate?
3. A roller coasters accelerates from an initial velocity of of 40 m/s to a final velocity of 4.0 m/s over 4 seconds. What's the acceleration?
4. If the average speed of a car is 110 km/h, how long will it take the car to travel 715 km?
If a particle travels in a straight line while accelerating continuously. Starting at rest, the particle begins to move. The particle accelerates to a speed of 200 m/s² and travels 800 meters in 2 seconds.
The speed of a golf ball increases from 10 m/s to 80 m/s down the fairway as it accelerates off the tee at 15 m/s2. How much time did the golf ball need to accelerate?We can apply the formula: Initial velocity + acceleration over time equals velocity.
Here, initial velocity is equal to 10 m/s, final velocity is equal to 80 m/s, acceleration is equal to 15 m/s2, and we must determine the time.
Thus, 80 = 10 + 15 x time.
By solving for time, we obtain:
time = (80 - 10)/15, or 4 seconds.
A roller coaster accelerates throughout the course of 4 seconds from an initial speed of 40 m/s to a top speed of 4 m/s. How fast is it going?We can apply the formula: (Final velocity - Initial velocity) / Time = acceleration
Here, the initial speed is 40 m/s, the final speed is 4 m/s, and the time is 4 s.
Acceleration is therefore (4 - 40) / 4 = -9.0 m/s2. Remember that the roller coaster is decelerating, hence the acceleration is negative.
How long will it take a car travelling at an average speed of 110 km/h to cover 715 km?Time can be calculated using the formula: distance x speed.
Speed in this case is 110 km/h, and distance is 715 km.
Time therefore = 715 / (110/3600) = 28.7 hours.
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Astronauts collected a lunar rock with a mass of 73 grams. What was the
rock's weight when they brought it back to Earth? (1 point)
1. 0.715 N
2. 715 N
3. 0.118 N
4. 0.007 N
Answer: 0.715
Explanation: from grams to newtons
If sound waves travel along a guitar string at 220 m/s (based on the medium it is made of), what would be the wavelength of the ‘C’ note from Problem 2 in this guitar string?
To calculate the wavelength of the 'C' note from Problem 2 in this guitar string, we also need to know its frequency. Assuming you're referring to the 'C' note with a frequency of 261.63 Hz (C4), we need to use the formula,
Using the formula, wavelength = speed / frequency, we can calculate the wavelength as follows:
Wavelength = Speed of Sound / Frequency
wavelength = 220 m/s / 261.63 Hz
wavelength = 0.8415 meters.
wavelength = 84.15 cm.
Therefore, the wavelength of the 'C' note on this guitar string is approximately 0.8415 meters or 84.15 cm.
therefore the correct answer is : his guitar string is approximately 0.8415 meters or 84.15 cm.
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Tobias has set a goal to reduce the number of errors on his timed typing tests by three each week. How can he track his progress on this goal?
Question 3 options:
plot the change in his WPM on a chart
purchase a fee-based typing program
track the hours he practices each week
edit each test document and write down the number of errors
Answer: D, Edit each test document and write down the number of errors
Explanation: I did the test and got 5/5 gl! :D
If a transverse wave passes from a flexible spring into a heavier stiffer spring where the wave has a greater speed, what will happen to the
reflected wave in the flexible spring?
When a transverse wave passes from a flexible spring into a heavier stiffer spring, the wave will have a greater speed in the stiffer spring due to the increased stiffness of the material. As a result, when the wave reaches the end of the stiffer spring, some of the energy from the wave will be reflected back towards the flexible spring.
The reflected wave in the flexible spring will be inverted, meaning that it will be flipped upside down. Additionally, the amplitude of the reflected wave will depend on the amount of energy that was transmitted into the stiffer spring.
If a large amount of energy was transmitted, then the reflected wave will have a higher amplitude. Conversely, if only a small amount of energy was transmitted, then the reflected wave will have a lower amplitude.
Overall, the reflected wave in the flexible spring will experience a change in both its orientation and amplitude due to the transmission and reflection of the initial wave in the stiffer spring.
When a transverse wave passes from a flexible spring into a heavier, stiffer spring where the wave has a greater speed, the reflected wave in the flexible spring will have a reduced amplitude and undergo a phase change of 180 degrees, resulting in an inverted waveform.
This occurs due to the impedance mismatch between the two springs, causing part of the wave energy to be reflected and part to be transmitted.
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