Calculate the relative molecular of calcium carbonate

* as following method*

Answer:

A

Explanation:

Convergence is pushing them together so C is out of the question.

B and D are wrong because it is an oceanic plate. B and D are for continental plates.

The models of the universe allow finding the result for how serious the universe in the distant future is:

The Big Bang model shows that the universe was created at a certain point and time where from which all matter is separating at a speed from these objects.

Based on these models and the measurements that the galaxies are moving away, in the distant future the galaxies must be very far from each other so that the universe would be composed of isolated entities without the possibility of interaction between them.

Within each galaxy the bodies are not separated because in each one there is a black body whose gravity holds the stars within its galaxy together.

In conclusion of the models of the universe we can find the result for how serious the universe in the distant future is:

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Hi there!

[tex]\large\boxed{g = 1.904 m/s^2}[/tex]

Acceleration of gravity is unaffected by an object's mass.

In the absence of air resistance, we can use the following kinematic equation:

d = vit + 1/2at²

The object falls from rest, so:

d = 1/2at²

The acceleration in this instance is gravity, our unknown. We can rearrange the equation to solve for 'g':

2d/t² = g

2(28.8)/(5.5²) = 1.904 m/s²

Answer:

come into conflict or opposition.

"in his work, politics and metaphysics collide

The extension of the spring when the ball is allowed to hang straight down, motionless is 0.0032 m.

The given parameters;

The radius of the circular path when spring is stretched is calculated as;

R = l₁ + x

R = 0.201 + 0.0176

R = 0.2186 m

The spring constant is calculated as follows;

[tex]F = ma\\\\Kx = \frac{mv^2}{R} \\\\K = \frac{mv^2}{Rx} \\\\K = \frac{(3.41)^2 m}{0.2186 \times 0.0176} \\\\K = 3,022.4 m \ N/m[/tex]

The extension of the spring when the ball is allowed to hang straight down, motionless;

[tex]F = mg\\\\Kx=mg\\\\x = \frac{mg}{K} \\\\x = \frac{9.8 m}{3022.4 m} \\\\x = 0.0032 \ m[/tex]

Thus, the extension of the spring when the ball is allowed to hang straight down, motionless is 0.0032 m.

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Answer:

Less than one percent of the total energy that reaches Earth is used by plants for photosynthesis

39°C=1.28L

8°C=? Less

=8°C/39°C×1.28L

=8/39×1.28L

=10.24/39

=512/195

=2.6L

Answer:

v=30m/s

Explanation:

m = 1500kg

v = 30m/s

t = 25s

The velocity time graph is parallel to the time axis,

that means The Velocity is constant. ('constant' means remains same).

Therefore, after 25s, v=30m/s

Answer:

The fundamental function of snowshoes is to offer float, allowing you to avoid sinking into snow. Hikers who do not have snowshoes may find themselves knee- or waist-deep in unconsolidated snow if they attempt to traverse it without snowshoes, a practice known as post-holing.

Explanation:

Answer:

Explanation:

I live in a cold country and I own snow shoes. I have to confess I've never thought about this question before.

If the snow is fresh, it is also very loosely packed. If you wear ordinary shoes, the first thing that will happen is that you will sink. How far depends on how deep the snow is. I can see you up to your waist in snow, if the snowfall is heavy enough.

So to prevent that, my snowshoes are 3 feet long and about 1 foot wide, Except for a small hole near the middle, the entire area is covered. I weigh about 140 pounds.

A very small calculation should tell you that if I wear house shoes (mine are 8" long by about 3 inches wide). The pressure is going to be 140 pounds / (2/3 * 1/4) = 140 // 2/12 = 140 / 1/6 = 140 *  6 = 840 pounds / square foot. Trust me, that is a lot of pressure.

What do the snowshoes accomplish?

140 / (3*1) = 46.7 pounds per square foot. You might sink a little, but you are not going down as far as you would with street clothes shoes.

The units are not the normal units you would use, but the ratio is going to be roughly the same. 840 / 46.

All of this is very approximate. That's what physics is all about. Approximations lead you to understanding.

Answer:

here is your answer

1+1=2

2+2=4

4+4=8

Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

Answer:

260 Newtons

Explanation:

Okay, so what you have to do is know what the question is asking. It wants to know the force perpendicular to the ground. We know perpendicular makes a right angle, so we use the diagram to make it into a right triangle with a degree of 60, and hypotunese of 300 newtons. Now, we use basic trigonometry, we place x on the horizontal side since it perpendicular to the ground. We know it´s sin because x is opposite to 300 which is the hyp.

Sin= opp/hyp

x/300

sin(60)= x/300

300*sin(60)= 259.8, which rounds to

260 Newtons

There is your answer :D. Happy to help.

The component of the force which is perpendicular to the ground is → F [y] = 261 a[y].

A vector V making an angle θ with the x - axis, can be resolved into two two components along the x and y - axes respectively as →

V = Vcosθ a[x] + Vsinθ a[y]

where -

a[x] is the unit vector along the +x axis

a[y] is the unit vector along the +y axis.

Given is a force of magnitude 300 N acting on the handle that makes an angle of 60° with the horizontal ground.

The component normal to the ground will be the component along the  y - axis. The component along the y - axis is the sine component. Suppose that vector F represents the force of magnitude (|F|) 300 N. The component perpendicular to the ground will be -

F [y] =  |F| sinθ a[y]

F [y] = 300 x sin(60°)  a[y]

F [y] = 300 x 0.87

F [y] = 261 a[y]

Therefore, the component of the force which is perpendicular to the ground is → F [y] = 261 a[y].

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Answer:

One of Canada's best-known poems, “In Flanders Fields” was written on May 2, 1915, when Canadian serviceman John McCrae was stationed at an army hospital in Flanders, Belgium, during World War I.

Explanation:

The magnitude of the acceleration of the block is 3.5 [tex]\bold{m/s^2.}[/tex]

The correct option is (C) 3.5 [tex]\bold{m/s^2.}[/tex]

Acceleration is the rate of change of velocity with time.

By Newton’s Second law

This law establishes the relationship between the net applied force on an object with the resultant acceleration. For a constant magnitude of force, the more is the mass of the object, the lesser will be its acceleration.

Given,

The mass of the block is 2.0 kg.

The force in the horizontal direction on the block is [tex]\bold{4.0 N + 4.0 N \cos 40{}^\circ.}[/tex]

a is the acceleration in the horizontal direction.

The acceleration for the block can be determined using Newton’s Second law,

[tex]\begin{aligned} \Sigma F&=ma \\ F+F\cos 40{}^\circ &=ma \\ a&=\frac{F\left( 1+\cos 40{}^\circ \right)}{m} \\ &=\frac{4.0\text{ N}\left( 1.766 \right)}{2.0\text{ kg}} \\ &=3.5\text{ m/}{{\text{s}}^{2}} \end{aligned}[/tex]

Thus, the acceleration is 3.5 [tex]\bold{m/s^2.}[/tex]

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Answer:

mass, weight

Explanation:

mass is constant, and weight is dependant on your location

Answer:

I think d

Explanation:

because distance j

has to be the last one that's the only one with distance

Answer:

20 ohms

Explanation:

Resistance=Potential difference÷Electric current

X=260÷13

X=20

Answer:

A

Explanation:if the things have the same charge they will repel makeing the ball move away form its positively charged guy = that the coil gun works.

Answer:

Explanation:

Let v be the velocity of object ,

Given that mass of object , m=100 g=  

1000

100

​

kg=0.1 kg

& kinetic energy of object =20 J

K.E  =  

2

1

​

 mv  

2

20=  

2

1

​

×0.1v  

2

⟹v  

2

=400

⟹v=20 m/s

Answer:

179.1 kg

Explanation:

Answer:

Should be 179.1 kg

Explanation:

Answer:

Theta = 26.93°

R = 0.38m

Explanation:

Theta = cos^-1(0.74m/0.83m)

Theta = 26.93°

R = sqrt(0.83²-0.74²)

R = 0.38m

Answer:

8×10^-3÷10×10^-6=8×10^2=800 kg/m^3

Answer:

2.4/3

Explanation:

first we make 8g/10cm then 0.8 so the only number that can fit for /3 is 2.4

hope helped!

Answer:

between car tires and a road

Explanation:

Using the Hubble law v = H₀d where v = recessional speed = 70,000 km per second H₀ = hubble constant = 70 km/s/Mpc and d = distance of galaxy.

Making d subject of the formula, we have

d = v/H₀

Substituting the values of the variables into the equation, we have

d = v/H₀

d = 70000 km/s/70 km/s/Mpc

d = 1000 Mpc

So, the galaxy is 1000 Mpc away from us.

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Answer:

what is the average speed of the toy car during the two trials to the nearest tenth of m/s

wait nvm the answer is B

Explanation:

CARRY ON LEARNING

Answer:

Fetus

Explanation:

the outsiders I got nuggets out of the elder and I get to make it in and I got I got

Answer:

57.97m/s

12.1s

Explanation:

Use one of the key equations of accelerated motion and sub in the values

vf^2=vi^2+2aΔd

vf^2=(20)^2+(2*9.8)(150)

vf^2 = 3340

vf = 57.79m/s (square rooted both sides)

now use another equation

Δd = (vi+vf/2)Δt

and rearrange for Δt

Δt = (2Δd-vf)/vi

sub in values

Δt = (2*150-57.79)/20

Δt = 12.1s

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Answer:

i think its going to be 150 because its half of 300

Explanation:

Answer:

I think 32.00

Explanation:

Because the equation is mass times velocity so is you mutiply 32 by 25 and 28 times 25 sample A would be greater.

The sample with the greatest average kinetic energy is sample A

The average kinetic energy of a sample can be estimated by the formula one-half of the mass sample multiplied by the speed (RMS) squared.

Mathematically, we have:

[tex]\mathbf{K.E_{avg} = \dfrac{1}{2}mv_{rms}^2}[/tex]

Provided that the speed (RMS) is constant, the average kinetic energy of sample A will be greater than the average kinetic energy of sample B because sample A has a greater mass than sample B.

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Answer:

Space junk, or space debris, is any piece of machinery or debris left by humans in space. It can refer to big objects such as dead satellites that have failed or been left in orbit at the end of their mission. It can also refer to smaller things, like bits of debris or paint flecks that have fallen off a rocket.

Answer:

In addition to derelict man-made objects left in orbit, other examples of space debris include fragments from their disintegration, erosion and collisions or even paint flecks, solidified liquids expelled from spacecraft, and unburned particles from solid rocket motors. Space debris represents a risk to spacecraft.

Explanation: