Cami cut 17 1\2
inches off a rope that was 50 inches long. How is the length of the remaining rope in inches written in decimal form?

The translation of ABC by (Rx + Ry) is UVW and the rigid composition of XYZ to X'Y'Z' cannot be determined

The rule (Rx + Ry) represents a translation image of a shape, where R is a vector representing the direction and distance of the translation, and (x, y) are the coordinates of the original shape.

To apply this rule to a shape, we simply add the vector R to each point of the shape, which moves the shape in the direction and distance specified by R.

Using the above as a guide, we have the following the translation of ABC by (Rx + Ry) to be UVW

The triangle X'Y'Z' is not given in the figure

So, the rigid composition of XYZ to X'Y'Z' cannot be determined

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Answer: 16-4√x/16-x is the answer.

Step-by-step explanation:

=> 4/4+√x*4-√x/4-√x

=> 4(4-√x)/(4)²-(√x)²  {using identity - (a+b) (a-b)=a² - b²}

=> 16-4√x/16-x

Answer:

Step-by-step explanation:

The polygons that can be formed by the intersection of a plane and a cylinder either parallel or perpendicular to the base include :

If a plane intersects three distinct vertices of the cube while bypassing any other vertices, a triangle is produced. To visualize this, suppose a corner of the cube were removed with a knife; picture that cut surface as a triangle.

On the other hand, if a plane coincides with four points on the cube and outlines a square shape, it creates what's called a "square cross-section." This transpires when said plane parallels one side of the cube while intersecting only the midpoints of its opposite face's edges.

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Full question is:

Select all the polygons that can be formed by the intersection of a plane and a cylinder either parallel or perpendicular to the base

A triangle

B square

C. rectangle

D pentagon

E circle

If you double the length and the width, you are quadrupling the area.

This is because 2 × 2 = 4.

Perimeter of new rectangle=   2 × perimeter of initial rectangle.

The perimeter will be double of if we double the length and breadth of rectangle

→ When doubling the dimensions of a rectangle, why the area is quadruple:

We know that :

Area of rectangle = l × b

where, l is length and b is breadth

A = L × W

This means area equals length times width.

if you double the length and you double the width, the formula becomes:

A = 2 × L × 2 × W

A = 2 × 2 × L × W

A = 4 × L × W

if you double the length and the width, you are quadrupling the area.

This is because 2 × 2 = 4.

→When doubling the dimensions of a rectangle, why the perimeter is doubles?

Let length be equal to ′l′

And breadth be equal to ′b′

Perimeter of rectangle = 2 (l + b) ____(equation i )

The perimeter if the length and breadth of the rectangle will increase by two, or will it double? So new parameters of rectangle when its length and breadth will get double on initial one.

Double length of rectangle of initial one= 2 × l=2l

Double breadth of rectangle of initial one = 2×b=2b

So the perimeter of new rectangle whose length and breadth are double of initial one are:

As we know that:

Perimeter of rectangle = 2 (l + b)

So,

Perimeter of new rectangle= 2(2l+2b),  (by taking 2 common)

Perimeter of new rectangle = 2×2(l + b) ____  equation (ii)

As from equation (i) perimeter of initial rectangle is = 2(l + b)

So from equation (i) and (ii)

Perimeter of new rectangle= 2 × 2(l + b)

Perimeter of new rectangle=   2 × perimeter of initial rectangle.

Hence, the perimeter will be double of if we double the length and breadth of rectangle.

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The outlier does not affect the mode

The outlier will increase the mean.

The outlier will not affect the median.

The outlier will increase the mean because  it will significantly increase the sum of the values.

The presence of an outlier will not affect the median, as it only changes the position of the middle value.

The mode is the value that occurs most frequently in a data set. In this case, the mode will not be affected because the outlier is not the most frequent in the data set and only appears once.

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The formula of the nth term of the sequence is f(n) = 8 *0.7r^(n - 1)

From the question, we have the following parameters that can be used in our computation:

a=_1=8, r=0.7

Express properly

So, we have

First term, a = 8

Common ratio, r = 0.7

The above definition is of a geometric sequence that has a first term of 8 and a common ratio of 0.7

Using the above as a guide, we have the following:

f(n) = a * r^(n - 1)

substitute the known values in the above equation, so, we have the following representation

f(n) = 8 *0.7r^(n - 1)

Hence, the nth term of the sequence is f(n) = 8 *0.7r^(n - 1)

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Note that the five number summary and range for the data are given as follows:

The five-number summary and range were calculated using the given stem and leaf plot. The minimum value is 102, the first quartile (Q1) is 226, the median (Q2) is 340, the third quartile (Q3) is 492, and the maximum value is 670. The range is the difference between the maximum and minimum values, which is 568.

The range is calculated by subtracting the minimum value from the maximum value:

Range: 607 - 102 = 505

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Answer:

[tex]\dfrac{\boxed{2}}{\boxed{3}} \times \dfrac{\boxed{1}}{\boxed{2}} = \dfrac{\boxed{1}}{\boxed{3}}[/tex]

Step-by-step explanation:

The square is 1 unit long and 1 unit wide
There are 3 smaller rectangles in the horizontal direction

Length of each rectangle is therefore 1/3 unit

There are 6 rectangles along the vertical direction

The height of each rectangle is therefore 1/6 unit

The shaded area is 2 rectangles wide and 3 rectangles in height

Width of shaded area = 2 x 1/3 = 2/3

Height of shaded region = 3 x 1/6 = 1/2

Area of shaded rectangle is

[tex]\dfrac{\boxed{2}}{\boxed{3}} \times \dfrac{\boxed{1}}{\boxed{2}} = \dfrac{\boxed{1}}{\boxed{3}}[/tex]

The scale drawing of the classroom have the dimensions of 10 centimeters by 4.6 centimeters

From the question, we have the following parameters that can be used in our computation:

Dimension of classroom = 10 meters by 4.6 meters

The scale of the drawing is given as

1 cm : 1 m

Using the above as a guide, we have the following:

Scale factor = 1 cm/1 m

So, we have

Scale factor = 1 cm per m

So, we have

Scale dimension of classroom = (10 meters by 4.6 meters) * 1 cm per m

Evaluate

Scale dimension of classroom = 10 centimeters by 4.6 centimeters

Hence, the scale drawing of the classroom have the dimensions of 10 centimeters by 4.6 centimeters

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Complete question

A rectangular classroom is 10 m long and 4.6 m wide. Make a scale drawing of the classroom using the following scales. 1 cm : 1 m

Step-by-step explanation:

How do you have two equal to signs omg?

Anyway,

x+6+2x=2x+6+4x+6+2x=2x+6+4

3x+6=8x+12=2x+10

0=5x+6=2x+10

0=3x-4=0

3x-4=0

3x=4

x = 4/3 = 1 ⅓

Answer:

A

Step-by-step explanation:

according triangle inequality,

the sum of any two sides of a triangle is larger than the remaining side.

so a + b > c is correct

Answer: D

Step-by-step explanation:

The answer is D. The cost of gasoline is higher in the U.S. than anywhere else in the world.

According to the U.S. Energy Information Administration, the average price of a gallon of regular unleaded gasoline in the United States was $3.53 on March 8, 2023. This is higher than the average price of gasoline in many other countries, including Canada ($1.56), Mexico ($1.97), and the United Kingdom ($1.73). However, the cost of gasoline in the United States is lower than the average price in some countries, such as Norway ($6.62), Sweden ($5.62), and Denmark ($5.51).

Here are the facts about the other statements:

A. Most Americans commute to work in a personally owned vehicle. According to the U.S. Census Bureau, in 2019, 77.4% of workers commuted to work by driving alone.

B. Most Americans who commute to work in car's drive alone. According to the U.S. Census Bureau, in 2019, 77.4% of workers who commuted to work by driving did so alone.

C. Americans spend more income on transportation than anything else except housing. According to the U.S. Bureau of Labor Statistics, in 2020, Americans spent an average of $10,564 on transportation, more than any other category except housing ($16,916).

The value of P(x=1) from the given discrete data is 0.5.

From the given data

Let P(x=2)=x

p+p+x=1

x=1-2p

E(x²)=∑PiXi²=P(0)²+p(1)²+(1-2p)(2)²

= 0+p+(1-2p)4

= 4-7p

E(x)=∑PiXi=P(0)+P(1)(1-2p)(2)

= 0+p+2-4p

= 2-3p

Given that, E(x²)=E(x)

4-7p=2-3p

4p=2

p=0.5

Therefore, the value of P(x=1) from the given discrete data is 0.5.

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first off, let's find out how much he's making on the 2nd year, so since he's getting slashed by 20%, that means his new commission is 100% - 20% = 80%, so 80% of 60000, how much is that?

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{\textit{\LARGE a}\% of \textit{\LARGE b}}\\ \cline{1-1} \\ \left( \cfrac{\textit{\LARGE a}}{100} \right)\cdot \textit{\LARGE b} \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{80\% of 60000}}{\left( \cfrac{80}{100} \right)60000}\implies 48000[/tex]

now, if we want to go up to 57600, that means we need to increase his commission by 57600 - 48000 = 9600.

So, if we take 48000(origin amount) to be the 100%, what's 9600 off of it in percentage?

[tex]\begin{array}{ccll} Amount&\%\\ \cline{1-2} 48000 & 100\\ 9600& x \end{array} \implies \cfrac{48000}{9600}~~=~~\cfrac{100}{x} \\\\\\ 5 ~~=~~ \cfrac{ 100 }{ x }\implies 5x=100\implies x=\cfrac{100}{5}\implies \boxed{x=20}[/tex]

Answer:

Both sides are equal, and are equvalent to 5 square root of 2

Step-by-step explanation:

This is a special right angled triangle known as the 45-45-90 triangle

The hypotenuse of a 45-45-90 triangle is x square root 2, with x being both sides of the triangle

10=x square root of 2 (Divide both sides by square root of 2)

10/square root of 2=x (Rationalize)

x=5 square root of 2

Θ(x) = tan⁻¹(5x / (4(x - 13))), and Θ is maximized when the distance the cow must stand from the billboard x₀ = 26.

To find Θ, use similar triangles. Let the distance from the cow to the top of the billboard be h. Then, using similar triangles:

h / x = 5 / (x - 13)

Solving for h:

h = 5x / (x - 13)

The vertical angle subtended by the billboard at the cow's eye is equal to the angle whose tangent is given by:

tan(Θ) = h / 4

Substituting for h:

tan(Θ) = 5x / (4(x - 13))

To maximize Θ, find the value of x that maximizes tan(Θ). Taking the derivative of tan(Θ) with respect to x and setting it equal to zero:

d/dx (tan(Θ)) = 5(52 - 26x) / (4(x - 13))² = 0

Solving for x:

x₀ = 26

Substituting x₀ into the expression for Θ:

Θ(x₀) = tan⁻¹(5(26) / 4(13)) = tan⁻¹(5/2)

Therefore, Θ(x) = tan⁻¹(5x / (4(x - 13))), and Θ is maximized when x₀ = 26.

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Answer: Cut 3 inch per person

Step-by-step explanation:

there is a 4 foot sub you take the quadrilatiral and divide it by 10 and you get 3 inches per person remember to multiply the reciprocal by 12 as there are 12 inches in a foot and you have 4 foot so the product of that reciprocal will be equal to 4 divided by your sum from adding the recriptorcal into the quadrilateral remember a quadrilateral not a duolateral or a triolatiral as there is 4 feet in the sub. >:)

Answer:

7 Cuts

Step-by-step explanation:

This is because if you do 48 inches / 6 inches = 8 sections Since each cut will create two sections, you need to make 7 cuts (one fewer than the number of sections) to get 8 equal portions.

The x intercepts are (-2, 0), (2, 0) and (3, 0) and it has vertical asymptotes at x = 4 and x = -4

The x intercepts are the points where the graph intersect with x-axis

In this case, the points are (-2, 0), (2, 0) and (3, 0)

So, the x intercepts are (-2, 0), (2, 0) and (3, 0)

The graph has no horizontal asymptotes

However, it has vertical asymptotes at x = 4 and x = -4

From the graph, the local maxima or minima are

Minima (3, -1) and Maxima (-1, 12)

This is the points where the graph changes it concave-ness

From the graph, we have the point to be (1, 13/2)

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The dimensions that minimizes the perimeter are undefined and DNE

From the question, we have the following parameters that can be used in our computation:

Base = w

Heights = h and T

Where

T = 1.6w

The area of the window is calculated as

A = 1/2Tw + hw

So, we have

A = 1/2 * 1.6w * w + hw

A = 0.8w² + hw

Differentiate with respect to w

A' = 1.6w + h

Set to 0

1.6w + h = 0

Solve for h

h = -1.6w

The above means that the perimeter cannot be minimized

This is because h and w cannot be negative

Hence, h = undefined and w = undefined

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The equation of the circle is determined as (x + 3)²  + (y - 9)² = 25.

The equation of the circle is calculated as follows;

For the equation;

y = 3/4x+5

Slope = 3/4,  the slope of the line perpendicular to the line = -4/3.

it is pass through the (0, 5).

The equation of the line: y - 5 = -4x/3

For the equation;

3x + 4y = 38

4y = -3x + 38

y = -3x/4 + 38

slope = -3/4, the slope of the line perpendicular to the line = 4/3

it is pass through the (6, 5)

The equation of the line: y - 5 = 4/3(x - 6)

Solve the two equations together to find the point of intersection;

(-4/3)x + 5 = (4/3)(x - 6) + 5

-4x/3 = 4x/3 - 8

8x/3 = -8

8x = -24

x = -3

y - 5 = -4x/3

y - 5 = -4(-3)/3

y - 5 = 4

y = 9

The center of the circle = (-3, 9)

The radius of the circle is calculated as;

r = √ (-3 -0)² + (9 - 5)²

r = √(9 + 16)

r = 5

The equation of the circle becomes;

(x - a )² + (y - b)² = r²

(x + 3)²  + (y - 9)² = 5²

(x + 3)²  + (y - 9)² = 25

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The quadratic equation is solved and the solution is x = 1 and x = 4

Given data ,

Let's expand the left-hand side of the equation:

(2x+1)² + (4x-4)²

= (2x)² + 2(2x)(1) + 1² + (4x)² - 2(4x)(4) + 4² (using the formula for the square of a binomial)

= 4x² + 4x + 1 + 16x² - 32x + 16

= 20x² - 28x + 17

Now let's expand the right-hand side of the equation:

(4x-1)²

= (4x)² - 2(4x)(1) + 1²

= 16x² - 8x + 1

Now we can set the left-hand side equal to the right-hand side and simplify:

20x² - 28x + 17 = 16x² - 8x + 1

4x² - 20x + 16 = 0

x² - 5x + 4 = 0

(x - 1)(x - 4) = 0

Hence , the solution is x = 1 and x = 4

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Answer:(a) The rate of decay is 14.4% per day, which can be written as a decimal by dividing by 100: r = 0.144.

(b) The formula for continuous decay is given by:

A = A₀ * e^(-rt)

where A is the remaining amount of the substance after time t, A₀ is the initial amount, r is the rate of decay, and e is the mathematical constant approximately equal to 2.71828.

Plugging in the given values, we get:

A = 140 * e^(-0.144*15)

A = 140 * e^(-2.16)

A ≈ 47.23

Therefore, after 15 days, approximately 47.23 mg of the radioactive substance will be left, rounded to two decimal places.

Step-by-step explanation:

The Slope of x = -3 is undefined; 6x-3y=18 is 2; (4,-2) and (1,7) is -3; and (7,5) and (8,5) is 0.

Slope of a line (m) = rise/run = change in y / change in x

Note that the slope of vertical lines are always undefined.

Therefore, we have the following:

x = -3 represents the equation of a vertical line, therefore, the slope is undefined.

6x - 3y = 18 is rewritten as y = 2x - 6 in slope-intercept form. The slope is 2.

For (4,-2) and (1,7):

Slope (m) = (7 -(-2))/(1 - 4) = 9/-3 = -3

For (7,5) and (8,5):

Slope (m) = 5 - 5/8 - 7 = 0/1 = 0

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The number of games that the team did play in the last season is 23.

The frequency is the number of times an event happens. Therefore, frequency is the number of repetitions of a digit or an event.

The given frequency table represents the frequency of different runs scored by the team in the entire season.

The frequency is written in tally form, which means that each of the vertical lines represents the count of 1, while a group of fours lines such that the four lines are vertical while the fifth line cuts the other four represents a count of 5 as shown in the second column of the second row.

Therefore, the frequency table can be made as:

Number of runs     Frequency

            0                         8

            1                          5

            2                         3

            3                         6

            4                         1

Total:                              23

Hence, the team played 23 games.

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The value of the "trigonometric-expressions' are :

(a) tan(5π/2) is undefined,

(b) sec(315°) is √2.

Part(a) : The expression "tan(5π/2)" is undefined because the tangent function is undefined at odd multiples of π/2, which includes 5π/2.

Part(b) : To find the value of sec(315°), we use the identity: sec(θ) = 1/cos(θ),

First, we convert 315° to radians:

Which is : 315° = (7π/4) radians;

Next, we find the value of cos(7π/4):

⇒ cos(7π/4) = cos(π/4) = (√2)/2;

Finally, we substitute in the identity for sec(θ);

So, Sec(7π/4) = 1/cos(7π/4) = 1/[(√2)/2] = √2.

Therefore, value of sec(315°) is √2.

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The given question is incomplete, the complete question is

Find the value of the trigonometric expressions :

(a) tan(5π/2)

(b) sec(315°)

the approximate difference in the mean circumferences of the Earth and the Moon is about 29153.88 kilometers.

A circle is a particular type of ellipse in mathematics or geometry where the eccentricity is zero and the two foci are congruent.

A circle is also known as the location of points that are evenly spaced apart from the centre. The radius of a circle is measured from the centre to the edge. T

he line that splits a circle into two identical halves is its diameter, which is also twice as wide as its radius.

A circle is a fundamental 2D form whose radius is quantified. The interior and exterior parts of the aircraft are separated by the circles.

The formula for the circumference of a circle is:

C = 2πr

where C is the circumference, π (pi) is a constant approximately equal to 3.14, and r is the radius.

The difference in the mean circumferences of the Earth and the Moon can be found by subtracting the circumference of the Moon from the circumference of the Earth.

The circumference of the Earth is:

C earth = 2π * 6371.0 km = 40075.04 km (rounded to two decimal places)

The circumference of the Moon is:

C moon = 2π * 1737.5 km = 10921.16 km (rounded to two decimal places)

The difference in the mean circumferences of the Earth and the Moon is:

C earth - C moon = 40075.04 km - 10921.16 km ≈ 29153.88 km

Therefore, the approximate difference in the mean circumferences of the Earth and the Moon is about 29153.88 kilometers.

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