can someone please help my solve for x?

The expression is [tex]\frac{(x^{19}y^{21})^{4} }{(x^{2} y^{6})^{2} }[/tex].  The simplified expression as [tex]{x^{72}y^{72} }[/tex]. Option B is correct.

Given that,

The expression is [tex]\frac{(x^{19}y^{21})^{4} }{(x^{2} y^{6})^{2} }[/tex]

We have to simplify the expression.

Simplify the expression means solving a math problem is the same thing as simplifying an expression. You basically attempt to write an expression as simply as you can when you simplify it. There shouldn't be any more multiplication, dividing, adding, or deleting to be done when the process is finished.

Take the expression

=[tex]\frac{(x^{19}y^{21})^{4} }{(x^{2} y^{6})^{2} }[/tex]

Multiply the powers

=[tex]\frac{x^{76}y^{84} }{x^{4} y^{12} }[/tex]

Divide the x and y terms

=[tex]{x^{72}y^{72} }[/tex]

Therefore, We got the simplified expression as [tex]{x^{72}y^{72} }[/tex]. Option B is correct.

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Using linear function concepts, it is found that graph A is the one that best represents the relationship.

A linear function is modeled by:

y = mx + b

In which:

In this problem, there is a fixed fee of $10, plus a fee of $2 per movie, hence m = 2, b = 10, and the function is given by:

y = 2x + 10.

Due to the y-intercept of y = 10, that is, when x = 0, y = 10, graph A is the one that best represents the relationship.

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Answer:

algebros....

Step-by-step explanation:

Answer:

  2 3/4 miles

Step-by-step explanation:

Remaining miles are found by subtracting miles already traveled from the number that need to be traveled.

__

12 1/2 - 2 1/4 - 7 1/2

= (12 1/2 -7 1/2) -2 1/4

= 5 -2 1/4 = 2 3/4

The letter traveled 2 3/4 miles on Wednesday to reach its destination.

The population density is the ratio of the number of geese to the area. Then the greatest population density in pond C is 128.

The population density is defined as the number of objects present in the unit area.

The formula is given as

[tex]\rm Population\ density = \dfrac{number\ of \ object}{total \ area}[/tex]

The table shows the number of resident geese living in four different ponds. a 3-column table has 4 rows.

Then the greatest population density of the geese will be

[tex]\rm Population\ density = \dfrac{192}{1.5} = 128[/tex]

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Answer:

pond B

Step-by-step explanation:

edg 2022

Answer:

the photo has the anwer

and it up to you if this is right it should be can I be marked as brainliest

Answer:

i dont the answer

Step-by-step explanation:

hey u, you're a loser

Answer:

10

Step-by-step explanation:

Let (2, 7) = [tex](x_{1} ,y_{1} )[/tex]    and (8, -1) = [tex](x_{2} ,y_{2} )[/tex]

 = [tex]\sqrt{(8-2)^{2} + (-1 -7)^2}[/tex]

= [tex]\sqrt{6^2 +(-8^2)}[/tex]

= [tex]\sqrt{36 + 64}[/tex]

= [tex]\sqrt{100}[/tex]

= 10

The length of the segment with endpoints at (2, 7) and (8, -1) using distance formula is 10 units.

Distance formula is the the formula for calculating the length of a line segment given the coordinates of the endpoints. The formula is given as :

Given the endpoints [tex](x_1,y_1), (x_2, y_2)[/tex]

d = [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Given in the question,

[tex](x_1,y_1) = (2,7)\\(x_2, y_2)=(8,-1)[/tex]

[tex]d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\d= \sqrt{(8-2)^2+(-1-7)^2}\\\\d= \sqrt{(6)^2+(-8)^2}\\\\d = \sqrt{36+64} = \sqrt{100} = 10[/tex]

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The required table of values for equation y=5-2x is;

x | y

0   5

1    3

2    1

3   -1

Tables of values are values used to represent functions.

Given the linear function expressed as y = 5 - 2x, we are to form a tables of values for the function.

Using the values of x = 0, 1, 2, and 3

If x = 0

y = 5 - 2(0)

y = 5

If x = 1

y = 5 - 2(1)

y = 3

If x = 2

y = 5 - 2(2)

y = 1

If x = 3

y = 5 - 2(3)

y = -1

Hence the required table of values for equation y=5-2x is;

x | y

0   5

1    3

2    1

3   -1

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Answer:

360 in²

Step-by-step explanation:

Total SA = 2 triangles + 3 squares

Triangles:

A = bh/2

A = (9 · 10)/2

A = 90/2

45 in²

Squares:

A = bh

A = (9)(10)

90 in²

Total SA: 2(45) + 3(90)

Total SA: 360 in²

I hope this helps!

Answer:

Step-by-step explanation:

4x − 1 = 19

solving for x, x = 5

2x − 4 = 10

x=7

2x + 2y = 48

x=24-7

y=24-x

5x + 2y = 90

x=18-2y/5

y=45-5x/2

all the situations I could find hope this helps for each equation.

Answer:

B. 314.9 m2

Step-by-step explanation:

Answer:

Your answer is 180

Step-by-step explanation:

180 x 5 = 900

Answer:

9.165

Step-by-step explanation:

Pythagorean Theorem implies a^2 + b^2 =c^2

AC= hypotenus

AB= 4

CB= ?

10^2=4^2+CB^2

CB= √10^2-4^2

    = 9.165

Answer:

b = 5

Step-by-step explanation:

x = 3
3B = 15
3B/3 = 15/3
B = 5

Both the median and the range changed, the correct option is A.

Median, in statistics, is the middle value of the given list of data, when arranged in an order.

The data set that contains the outlier is given as:

4, 14, 15, 15, 16, 16, 18, 19, 20, 20, 21

The minimum value of the data is: 4

The median or middle quartile i.e. [tex]\rm Q_2[/tex]  is the central tendency of the data and exists in the middle of the data.

The median is: 16

Also, the lower set of data is:

4,14,15,15,16

The lower quartile i.e. [tex]\rm Q_1[/tex]  is the median of the lower set of data.

The  lower quartile i.e. [tex]\rm Q_1[/tex] = 15

Similarly, the upper set of data is:

18, 19, 20, 20, 21

the upper quartile i.e. [tex]\rm Q_3[/tex]  is the median of the upper set of data.

upper quartile i.e. [tex]\rm Q_3[/tex] = 20

Also, the interquartile range is:

[tex]\rm Q_3-Q_1=20-15=5[/tex]

The maximum value of the set is 21.

Range = Maximum value-Minimum value =21 - 4 = 17

As we know that 4 is the outlier of the data as it is the smallest as compared to all the data points.

After removing the outlier the data set is:

14, 15, 15, 16, 16, 18, 19, 20, 20, 21

The minimum value of the set =14

The maximum value of set =21

Range = Maximum value-Minimum value =21-14 = 7

Hence, Both the median and the range changed.

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Based on the information provided in the histogram, the percent of students that type less than 30 words per minute is 30%.

A histogram is used to represent data graphically. The histogram is made up of rectangles whose area is equal to the number of students and whose width is equal to the words per minute.

Percentage of students who type less than 30 words per minute = (number of students that type less than 30 words per minute) / total number of students) x 100

[(10 + 5) / 50] x 100 = 30%

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Answer:√44

Step-by-step explanation:

Answer:

1357.2

Step-by-step explanation:

[tex]V=\pi r^{2} h[/tex]

[tex]=\pi *6^{2} *12[/tex]

[tex]=1357.2[/tex]

Answer:

28 bottles

HOPE THIS HELPS! :)

Answer: The answer is 80

Step-by-step explanation:

Answer:

Gary baked 80 muffins on Sunday

Step-by-step explanation:

I can set up a proportion, knowing that 24/x = 3/10, where x is the total number of muffins baked on Sunday.  By cross multiplying, I get 240 = 3x.  By dividing both sides by 3, I find x = 80.

Answer:

x= 4 and y=7

Step-by-step explanation:

Bellow is the graph of the two systems, you can find the coordinates (4,7) were they intersect.

Because of this the two equations are true

7= 4+3 (True)

Answer:

6x²+9x+1

Step-by-step explanation:

Check out the attached photo

The area of the triangle is the half of the product of base and height then the correct option is A.

Triangle is a polygon that has three sides and three angles. The sum of the angle of the triangle is 180 degrees.

Points A, B, and C are midpoints of the sides of the right triangle DEF.

Then the area of the triangle is given as

Area of the triangle = half of the product of base and height

That can be written as

[tex]\rm Area = \dfrac{1}{2} \times b \times h[/tex]

Thus, the correct option is A.

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Answer:

B,C,D

Step-by-step explanation:

The volume of the prism which is filled with 135 cubes is 5 cubic feet.

What is the Volume of Cube ?

The volume of a cube defines the number of cubic units, occupied by the cube completely. The unit of volume of the cube is in cubic units such as cu. centimeters, cu. meters, cu. inches, cu. feet, etc.

Here Prism is filled with 135 cubes.

Volume of prism = volume of 135 cubes

                            = 135 X side X side X side

                            = 135 X 1/3 X 1/3 X 1/3

                            = 135 / 27

Volume of prism = 5 cu. feet

Thus, The volume of the prism which is filled with 135 cubes is 5 cubic feet.

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I believe she will have 8 rolls of toilet paper left after one year.

She started with 36, then gave away 4, so then she would have 32 left for herself, then she used 2 every month so if you deduct 2 rolls every month for 12 months she would use 24 in one year. So 32-24 is 8.

You didnt put any images

Answer:B 73

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

Correct Question :-

Calculate the circumference of the shape below.

[tex] \\ \\ [/tex]

[tex] \\ \\ [/tex]

[tex] \\ \\ [/tex]

[tex] \\ [/tex]

We know :-

[tex] \bigstar\boxed{ \rm Circumference_{(circle)} = 2\pi r}[/tex]

[tex] \\ [/tex]

Steps :-

[tex] \dashrightarrow\sf Circumference_{(circle)} = 2\pi r[/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow\sf Circumference_{(circle)} = 2\pi \times 12.5 \\ [/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow\sf Circumference_{(circle)} = 2 \times \dfrac{22}{7} \times 12.5 \\ [/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow\sf Circumference_{(circle)} =\dfrac{44}{7} \times 12.5 \\ [/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow\sf Circumference_{(circle)} =\dfrac{44}{7} \times \dfrac{125}{10} \\ [/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow\sf Circumference_{(circle)} =\dfrac{44}{7} \times \dfrac{ \cancel{125} {}^{25} }{ \cancel{10} {}^{2} } \\ [/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow\sf Circumference_{(circle)} =\dfrac{44}{7} \times \dfrac{25}{2} \\ [/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow\sf Circumference_{(circle)} =\dfrac{ \cancel{44}}{7} \times \dfrac{25}{ \cancel2} \\ [/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow\sf Circumference_{(circle)} =\dfrac{22}{7} \times \dfrac{25}{1} \\ [/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow\sf Circumference_{(circle)} =\dfrac{550}{7} \\ [/tex]

[tex] \\[/tex]

[tex] \dashrightarrow\bf Circumference_{(circle)} =78.6 \: m\{approx \} \\ [/tex]

[tex] \\[/tex]

~[tex] \pmb{\cal W\frak{indy}M\frak{int}}[/tex]