can someone pls help me with solving one variable expressions pls show your work too so i can understand thanks

Can Someone Pls Help Me With Solving One Variable Expressions Pls Show Your Work Too So I Can Understand

Answers

Answer 1

Step-by-step explanation:

Basically, let's represent the amount of money earned in

July with x

and

August with x+90

x+(x+90)=350

2x+90=350

2x=350-90

2x=260

x=260÷2

x=130

So, Wanda earned $130 babysitting in July and in July, 130+90=$220.

Hope this helps!


Related Questions

7 times a number plus 3 is 38. find the number​

Answers

Answer:

5

Step-by-step explanation:

7 x 5 =  35

35 + 3 = 38

Raise the fraction to its highest terms by supplying the missing numerator.7/8=?/240

Answers

Do you divide because I can’t see answer

The required simplified value of the given expression is 210

As mentioned in the question,
To raise the fraction to its highest terms by supplying the missing numerator.7/8=x/240.

What is simplification?

The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

Here,
according to the question,
7 / 8 = x / 240
x = 7/8 × 240
x = 7 × 30
x = 210

Thus, the required simplified value of the given expression is 210.

Learn more about simplification here:

https://brainly.com/question/12501526

#SPJ2

Winter fills 2/5 of a water bottle in 1/4

of a minute. How many bottles can

Winter fill in 1 minute?

Answers

Answer:

1.6 (decimal), 1 6/10 (proper), and 8/5 (improper)

Step-by-step explanation:

If it’s 2/5 in 1/4 and to get one while you need four 1/4 you need to multiply to get how much it can fill in that 4/4. To do this multiply 2/5 by 4 which is 1.6 (decimal) and 1 6/10 fractional. Or if you want it improper, 8/5

65% of 51. Please also show me how to do it because I can't.

Answers

Answer:

Step-by-step explanation:

65% of 51 = [tex]\dfrac{65}{100}*51[/tex]

                = 0.65 *51

                = 33.15

If you were to solve the following system of equations by using a matrix,
which of the following would be your coefficient matrix?
4x – 3y=7
x + 5y=13

Answers

Answer:

I believe it is C but it's good to double check

Step-by-step explanation:

Answer:

Step-by-step explanation:

b

helpppppppppppppppp meeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Answers

Answer:

a) = 4.198

b) = 4.146

Step-by-step explanation:

a) 15.444/6+0.232*7

do pemdas

=15.444/6+(0.232*7)

=(15.444/6)+1.624

=2.574+1.624

a) = 4.198

b) (1.709+0.364)*6/3

pemdas again

=(2.073) *6 / 3

=12.438 / 3

b) =4.146

Hope this helps :)

Answer:

A 4.198 and b is 2.073

Step-by-step explanation:

i hope this is right

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Match each linear model to its inverse.

Answers

Answer:

We need the options

Step-by-step explanation:

...

neeeeeeed heeeeeelp pleaseeeeeeeee

Answers

Answer:

D

Step-by-step explanation:

Hope this is correct and helps

Answer:

D

Step-by-step explanation:

I'm not completely sure but A is constant cuz it don't move B is increasing C is same as A and D Is decreased

3 sss, aas, sas, or not enough information

Answers

Answer:

AAS

Step-by-step explanation:

I'm pretty sure its this, but im sorry if im wrong!

(a) 85% of 80 is what number?
(b) 21 is 35% of what?

Answers

Answer:

a) 68

b)60

Step-by-step explanation:

a) 85% = 0.85

0.85 * 80 = 68

b) let x be the unknown number.

35% = 0.35

0.35x = 21

x = 60

Answer:

Step-by-step explanation:

a, 85% of 80

85% of 80

= 85/100*80

=85/100*80

=0.85*80

=68.

b, 21 is 35%

21 is 35%

=21*35/100

=21*0.35

=7.35.

hope this helps you dear and have a nice day

What is the number if 4 is subtracted from sum of 1 fourth of 5 times of 8 and 10

Answers

Answer:

Answer:18.5

Step-by-step explanation:

10+8=18

18*5=90

90/4

22.5-4=18.5

Have a happy day! <3Miss Hawaii

Answer:

16

Step-by-step explanation:

sum of 8 and 10=18

5 times of sum of 8 and

10= 18×5=80

1/4 of 5 times of sum of 8 and

10= 1/4×80=20

and then subtracted 4 from

20 =20-4=16

Hooke’s Law for an elastic spring states that the distance a spring stretches varies directly as the force applied. If a force of 180 newtons stretches a spring 5 cm, how much will a force of 270 newtons stretch the same spring?
Will give Brainliest :)

Answers

Answer:

7.5m

:) hoped this helped!

Step-by-step explanation:

the sum of two numbers is 21 the second number is six times the first one

Answers

Answer:

18+3

Step-by-step explanation:

3x6= 18

and 18+3=21

Find the unit rate for this situation. Please DO NOT use any extra spaces or

symbols. Simply type in the number amount.

Answers

Please GIVE US the problem you want us to answer

major help.......................

Answers

Answer: C. 85°

Step-by-step explanation:

Answer:

I look lik dis almost dreads and then them types of braces and my eye brows look like that and I got a tattoo on my face but my eyes are blue and I have contacts so no more glasses

Please solve... I will mark you brainliest

Answers

Answer:

x = 5

Step-by-step explanation:

[tex]6x - 20 = 2x \\ - 20 = 2x - 6x \\ - 20 = - 4x \\ \frac{ - 20}{ - 4} = x = 5[/tex]

[tex]f(x)=\frac{2x}{x-1}[/tex]

[tex]f(a); f(a+h); \frac{f(a+h)-f(a)}{h}[/tex]

Answers

1st = x=0
2nd I’m not sure I don’t want to provide the wrong answer

 Use trigonometric identities to solve each equation within the given domain

sec(x) cos(3x) = 0 from [- x /2 , x /2]

Answers

Answer:

Either [tex]x = (-\pi / 6)[/tex] or [tex]x = (\pi / 6)[/tex].

Step-by-step explanation:

Angle sum identity for cosine:

[tex]\cos(a + b) = \cos(a)\, \cos(b) - \sin(a) \, \sin(b)[/tex].

Double-angle identity for cosine and sine:

[tex]\begin{aligned}& \cos(2\, a)\\ &= \cos^{2}(a) - \sin^{2} (a) \\ &= (\cos^{2}(a) + \sin^{2}(a) - 2\, \sin^{2}(a) \\ &= 1 - 2\, \sin^{2}(a)\end{aligned}[/tex].

[tex]\sin(2\, a) = 2\, \cos(a) \, \sin(a)[/tex].

The secant of an angle is the inverse reciprocal of the cosine of that angle:

[tex]\displaystyle \text{$\sec(x) = \frac{1}{\cos(x)}$ if $\cos(x) \ne 0$}[/tex].

Apply these identities to rewrite the left-hand side of the equation.

[tex]\begin{aligned} & \sec(x) \, \cos(3\, x) \\ =\; & \frac{1}{\cos(x)} \cdot \cos(3\, x) \\ =\; & \frac{1}{\cos(x)} \cdot (\cos(x)\, \cos(2\, x) - \sin(x)\, \sin(2\, x)) \\ =\; &\cos(2\, x) \\ & - \frac{1}{\cos(x)} \cdot (\sin(x)\, \sin(2\, x)) \\ =\; & \cos(2\, x)\\ & - \frac{1}{\cos(x)} \cdot (\sin(x) \cdot (2\, \sin(x)\, \cos(x))) \\ =\; & \cos(2\, x) - 2\, \sin^{2}(x) \\ =\; & (1 - 2\, \sin^{2}(x)) - 2\, \sin^{2}(x) \\ =\; &1 - 4\, \sin^{2}(x) \end{aligned}[/tex].

Solve the rewritten equation:

[tex]\displaystyle \sin^{2}(x) = \frac{1}{4}[/tex].

Either [tex]\sin(x) = (1/2)[/tex] or [tex]\sin(x) = (-1/2)[/tex].

The question required that [tex](-\pi / 2) \le x \le (\pi / 2)[/tex]. The sine function is one-to-one over this range. In other words, for each [tex]y[/tex] between [tex](-1)[/tex] and [tex]1[/tex], there is exactly one [tex]x[/tex] between [tex](-\pi / 2)[/tex] and [tex](\pi / 2)[/tex] such that [tex]\sin(x) = y[/tex].

If [tex]\sin(x) = (-1/2)[/tex] and [tex](-\pi / 2) \le x \le (\pi / 2)[/tex], then [tex]x = (-\pi / 6)[/tex].

Otherwise, if [tex]\sin(x) = (1/2)[/tex] and [tex](-\pi / 2) \le x \le (\pi / 2)[/tex], then [tex]x = (\pi / 6)[/tex],

Verify that [tex]\cos(x) \ne 0[/tex] for either of the two [tex]x[/tex] values, such that the [tex]\sec(x)[/tex] in the original equation takes a real value.

13. A bakery is having a buy 4, get 1 free sale on cakes. This sale is eguivalent to what percentage off the regular price of all 5 cakes? A. 196 B. 10%% C. 20 D. 25%6 E. 40%​

Answers

Answer: 20

Step-by-step explanation:

Anna challenges Sarah to a game where Sarah flips a fair coin and then randomly chooses a card from a small deck of cards that includes only 111 jack, 111 queen, 111 king, and 111 ace.The only way Sarah can win is by flipping heads and then choosing either the jack or the queen.If XXX is a random variable that represents Sarah's outcome, drag the bars to graph the probability distribution for all possible values of XXX.

Answers

The probability distribution for all possible values of X are given in the discrete probability table ;

X : ____ winning ____ not winning

P(X) : ____ 0.25 ________ 0.75

Fair coin = {H, T}

card = {J, Q, K, A}

Sample space :

__ H ___ TJ | HJ __ TJQ| HQ __TQK| HK __ TKA| HA __ TA

Total possible outcomes = sample space = 8

Winning selection = {HJ, HQ}

Probability of winning ; P(Winning) = 2/8 = 1/4 = 0.25

Probability of not winning ;

1 - P(wininng) = 1 - 1/4 = 3/4 = 0.75

X : ____ winning ____ not winning

P(X) : ____ 0.25 ________ 0.75

Learn more : https://brainly.com/question/25274933

Please Please Help Me. Put the following equation of a line into slope-intercept form, simplifying all fractions.
2y-2x= -14

Answers

Answer:

y = x-7

Step-by-step explanation:

Slope intercept form is

y = mx+b  where m is the slope and b is the y intercept

2y -2x = -14

Add 2x to each side

2y-2x+2x= 2x-14

2y = 2x-14

Divide by 2

2y/2 = 2x/2 -14/2

y = x-7

ddddwfdwfd qdqfqfqqdqdqdqddqdqdq

Answers

I must speak in your language

ddddwfdwfd qdqfqfqqdqdqdqddqdqdq

The formula 1/2 bh finds the area of what shape?

Answers

The formula ½ bh finds the area of a triangle.

Please check the picture.

Answer:

Triangle

Step-by-step explanation:

b -  base of the triangle

h - height or altitude

Solve for a. -16-7a=5

Answers

Answer:

A = -3

Step-by-step explanation:

-16-7(-3)=5

plz help asap
You have used the Distributive Property to transform numerical expressions such as (5)(3) + (2)(3) to (5 + 2)(3). How would you transform 5x + 2x into a single term? Substitute five different values into the expressions 5x + 2x and 7x - 1. What do you notice about the values of the expressions? Is there any value that would make the two expressions equal? Why or why not?

Answers

Answer:

5x + 2x result values are 1 more then 7x - 1 result values

there are no values that will make the 2 expressions equal....

because 5x + 2x = 7x......and the other one is 7x - 1......so the 7x - 1 values will always be 1 number less...because ur subtracting one

Step-by-step explanation:

5x + 2x.....combine like terms..... = 7x

5x + 2x....subbing in 1                               7x - 1....subbing in 1

5(1) + 2(1) = 5 + 2 = 7                               7(1) - 1 = 7 - 1 = 6

5x + 2x...subbing in 2                                 7x - 1...subbing in 2

5(2) + 2(2) = 10 + 4 = 14                            7(2) - 1 = 14 - 1 = 13

5x + 2x...subbing in 3                                 7x - 1...subbing in 3

5(3) + 2(3) = 15 + 6 = 21                            7(3) - 1 = 21 - 1 = 20

5x + 2x...subbing in 4                                 7x - 1....subbing in 4

5(4) + 2(4) = 20 + 8 = 28                            7(4) - 1 = 28 - 1 = 27

5x + 2x...subbing in 5                                 7x - 1...subbing in 5

5(5) + 2(5) = 25 + 10 = 35                          7(5) - 1 = 35 - 1 = 34

Answer:

5x+2x= 7x....

Step-by-step explanation:

There is no value that would make them equal.  If u subsitute x by 1, 2, 3 you get 7, 14, 21. When u substitute for 7x-1, all the values are 1 less than 7, 14, 21.

Simplify the following to standard form
1.(9x+7y+8z)+(2x+ -4y+7z)
2. (5x +10y+ -8z) - (2x+ -2y + -3z)​

Answers

Answer:

1, 11x + 3y + 15z

2, 3x + 12y + -5z

Step-by-step explanation:

all you need to do is combined the like terms and make sure the signs (positive and negative signs) are right

Translate the blue shape to the pink shape...

help me quick please

Answers

Answer:

I can't help you if there's no picture lol

3. What is the function of a Golgi complex? What
is the function of the endoplasmic reticulum?

Answers

Answer:

Step-by-step explanation:

Gogli complexes packages proteins, while endoplasmic reticulums transport proteins made by the gogli complexes around the cell.


[tex]Evaluate: \sqrt{ \frac {1 - sin(x)}{1 + sin(x)​​}} \\ [/tex]


Solve this problem please..​​

Answers

[tex]\large\underline{\sf{Solution-}}[/tex]

We have to evaluate the given expression.

[tex] \rm = \sqrt{ \dfrac{1 - \sin(x) }{1 + \sin(x) } } [/tex]

If we multiple both numerator and denominator by 1 - sin(x), then the value remains same. Let's do that.

[tex] \rm = \sqrt{ \dfrac{[1 - \sin(x)][1 - \sin(x) ]}{[1 + \sin(x)][1 - \sin(x) ]} } [/tex]

[tex] \rm = \sqrt{ \dfrac{[1 - \sin(x)]^{2}}{1- \sin^{2} (x) } } [/tex]

We know that:

[tex] \rm \longmapsto { \sin}^{2}(x) + \cos^{2}(x) = 1[/tex]

[tex] \rm \longmapsto \cos^{2}(x) = 1 - { \sin}^{2}(x)[/tex]

Therefore, the expression becomes:

[tex] \rm = \sqrt{ \dfrac{[1 - \sin(x)]^{2}}{\cos^{2} (x)}} [/tex]

[tex] \rm = \dfrac{1 - \sin(x)}{\cos(x)}[/tex]

[tex] \rm = \dfrac{1}{\cos(x)} - \dfrac{ \sin(x) }{ \cos(x) } [/tex]

[tex] \rm = \sec(x) - \tan(x) [/tex]

[tex] \sqrt{ \frac{ \cos(n) }{1 + \: \sin(n) } } [/tex]

see the attachment!!

hope it helps

#carryolearning

The diagram below a triangle PQR on a Cartesian plane. Given the distance a Q from origin is 6 units

If the gradient of straight line PQ is 4/3 calculate y-intercept​

Answers

⸻➤[tex]{\pink{\tt{Mixedfarming}}}[/tex][tex]\huge{\underline{\mathtt{\red {A}\pink{N}\green{S}\blue{W}\purple {E}\orange{R}}}}[/tex][tex]\huge{\underline{\mathtt{\red {A}\pink{N}\green{S}\blue{W}\purple {E}\orange{R}}}}[/tex][tex]\huge{\underline{\mathtt{\red {A}\pink{N}\green{S}\blue{W}\purple {E}\orange{R}}}}[/tex][tex]\huge{\underline{\mathtt{\red {A}\pink{N}\green{S}\blue{W}\purple {E}\orange{R}}}}[/tex][tex]\huge{\underline{\mathtt{\red {A}\pink{N}\green{S}\blue{W}\purple {E}\orange{R}}}}[/tex][tex]\huge{\underline{\mathtt{\red {A}\pink{N}\green{S}\blue{W}\purple {E}\orange{R}}}}[/tex][tex]\huge{\underline{\mathtt{\red {A}\pink{N}\green{S}\blue{W}\purple {E}\orange{R}}}}[/tex][tex]\huge{\underline{\mathtt{\red {A}\pink{N}\green{S}\blue{W}\purple {E}\orange{R}}}}[/tex][tex]\sf\red{hope\:it\:helps\:you}[/tex][tex]\huge\pink{\mid{\fbox{\tt{your\:QUESTION}}\mid}}[/tex][tex]\huge\pink{\mid{\fbox{\tt{your\:QUESTION}}\mid}}[/tex][tex]\huge\pink{\mid{\fbox{\tt{your\:QUESTION}}\mid}}[/tex][tex]\huge\red{\mid{\underline{\overline{\textbf{Solution\:࿐}}}\mid}}[/tex]

[tex]\huge\red{\mid{\underline{\overline{\textbf{Solution\:࿐}}}\mid}}[/tex]

[tex] \frac{a}{b} [/tex][tex] \frac{a}{b} [/tex][tex] \frac{a}{b} [/tex][tex] \frac{a}{b} [/tex][tex] \frac{a}{b}

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