Chad buys pineapples, watermelons, and a bag of grapes for a fruit salad. He spends a total of $29.68 on the fruit salad. Pineapples
cost $2.15 each, and watermelons cost $3.75 each. The bag of grapes costs $4.48.
Create an equation to model this situation, where p represents the number of pineapples Chad can purchase and w represents the
number of watermelons he can purchase.

The lateral surface area about x-axis is 114.1 square units.

To find the lateral surface area of the cone generated by revolving the line segment y=9/2x, 0≤x≤9 about the x-axis, we first need to find the length of the slant height of the cone.

We can think of the cone as being formed by rotating a right triangle about the x-axis.

The line segment y=9/2x intersects the x-axis at (0,0) and (9,81/2).

This forms a right triangle with base 9 and height √(81/2) = (9/2)√2.

The slant height of the cone is the hypotenuse of this right triangle, which can be found using the Pythagorean theorem:

l = √(9² + (9/2√2)²) = √(81 + 81/8) = (9/√2)√(9/8) = (9/2)√2

The lateral surface area of the cone can then be found using the formula:

L = πrl

where r is the radius of the base of the cone (which is equal to half the base of the right triangle, or 9/2) and

l is the slant height we just found.

Substituting in the values, we get:

L = π(9/2)(9/2)√2 = (81/4)π√2 ≈ 114.1

Therefore, the lateral surface area of the cone generated by revolving the line segment y=9/2x, 0≤x≤9 about the x-axis is approximately 114.1 square units.

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,Based on the information, we need to consider 5 terms in the series for the sum to exceed 1507.

Substituting the given values, we get:

1507 < -3(1 - (-4)^n)/(1 - (-4))

Simplifying this inequality, we get:

-4^n < 502

Taking the logarithm of both sides, we get:

n*log(4) > log(502)

n > log(502)/log(4)

n > 4.29

n = 5

Therefore, we need to consider 5 terms in the series for the sum to exceed 1507.

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The answer would be

A = $8,650

P = $5,000

t = 5 years

To solve this problem, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where:

A = the amount of money after t years

P = the principal (initial deposit)

r = the annual interest rate

n = the number of times the interest is compounded per year

t = the number of years

We know that Allen opened a retirement savings account with an initial deposit of $5,000 and made annual contributions. After 5 years, the account grew to $8,650. We don't know the annual interest rate or how the interest is compounded, so we can use the formula to find out.

Let's assume that Allen made no additional contributions to the account after the initial deposit. Then:

A = $8,650

P = $5,000

t = 5 years

We can rearrange the formula to solve for r:

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The expression of linear inequalities that represents Tami's earnings is as follows: 6x + 12y ≥ 150.

A linear inequality is a mathematical expression that involves a linear function and a relational operator such as <, >, ≤, ≥, or ≠ and it can be used to compare two expressions or values. It defines a range of values that satisfy inequality.

For the scenario painted above, we see that Tani is meant to earn a minimum of $150 Thus, the greater than or equal to symbol  ≥ should be used for the expression. $6 per hour and $12 per hour are also well represented in the equation.

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The solution to the differential equation with the given initial condition is:

[tex]u = -1/2 * ln(-2/9 * e^{(9t)} + 4/9 * e^{(-8)} + 2/9)[/tex]

To solve equation, we can separate the variables and write:

[tex]1/e^{(2u)} du = e^{(9t)} dt[/tex]

Integrating both sides, we get:

[tex]\int 1/e^{(2u)} du = \int e^{(9t)} dt[/tex]

Integrating the left side requires the substitution v = 2u, dv/du = 2, and du = dv/2, which gives:

[tex]\int 1/e^{(2u)} du = \int 1/2 * 1/e^v dv = -1/2 * e^{(-2u)}[/tex]

Integrating the right side gives:

[tex]\int e^{(9t)} dt = 1/9 * e^{(9t)}[/tex]

Substituting these integrals back into the original equation, we get:

[tex]-1/2 * e^{(-2u)} = 1/9 * e^{(9t)} + C[/tex]

where C is the constant of integration.

We can solve for the constant of integration using the initial condition u(0) = 4:

[tex]-1/2 * e^{(-24)} = 1/9 * e^{(90)} + C[/tex]

[tex]-1/2 * e^{(-8)} = 1/9 + C[/tex]

[tex]C = -1/2 * e^{(-8)} - 1/9[/tex]

Therefore, the solution to the differential equation [tex]du/dt = e^{(2u+9t)}[/tex] with initial condition u(0) = 4 is:

[tex]-1/2 * e^{(-2u)} = 1/9 * e^{(9t)} - 1/2 * e^{(-8)} - 1/9[/tex]

Solving for u, we get:

[tex]e^{(-2u)} = -2/9 * e^{(9t)} + 4/9 * e^{(-8)} + 2/9[/tex]

Taking the natural logarithm of both sides, we get:

[tex]-2u = ln(-2/9 * e^{(9t)} + 4/9 * e^{(-8)} + 2/9)[/tex]

Dividing by -2, we get:

[tex]u = -1/2 * ln(-2/9 * e^{(9t)} + 4/9 * e^{(-8)} + 2/9)[/tex]

Therefore, the solution to the differential equation with the given initial condition is:

[tex]u = -1/2 * ln(-2/9 * e^{(9t)} + 4/9 * e^{(-8)} + 2/9)[/tex]

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Step-by-step explanation:

g(x)  is just f(x) shifted UP three units ...so

  g(x) = f(x) +3

Answer:

1 orange

Step-by-step explanation:

you just color 1 circle.

The equation of the attached graph is

The equation is written by the general formula

y = A cos (Bx + C) + D

where:

A = amplitude.

B = 2π/T

where T = period

C = phase shift.

D = vertical shift.

A = amplitude

A = (maximum - minimum) / 2

Using the graph,

maximum = 1

minimum = -1

A = [1 - (-1)] / 2 = 2/2 = 1

B = 2π/T

where T = 2π

B = 2π/(2π) = 1

C = phase shift = 0

D = vertical shift

D = 1 - 1 = 0

substituting results to

y = 1 cos (1x + 0) + 0

this is written as

y = 1 cos (1x) + 0

y = cos (x)

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The number of students who took the test on Monday is found to be 15, hence the correct option is B.

Let us assume that the number of student taking test on Monday is n. The total score for Monday's test is n times the average score of 80.4,

Monday's total score = 80.4n

When the student who missed the test on Monday took the test on Tuesday and scored 90, the total score became,

Total score = 80.4n + 90

The new average score of 81 can be expressed as,

81 = Total score / (n+1)

Substituting the value of the total score, we get,

81 = (80.4n + 90)/(n+1)

Multiplying both sides by n+1, we get,

81(n+1) = 80.4n + 90

Expanding the brackets,

81n + 81 = 80.4n + 90

Simplifying,

0.6n = 9

n = 15, so, the number of students who took the test on Monday is 15.

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The measure of arc DF is given as follows:

mDF = 58º.

We have two secants in this problem, and point E is the intersection of the two secants, hence the angle measure of 52º is half the difference between the angle measure of the largest arc of 162º by the angle measure of the smallest arc.

Then the measure of arc DF is obtained as follows:

52 = 0.5(162 - mDF)

52 = 81 - 0.5mDF

0.5mDF = 29

mDF = 58º.

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The image of P under a 270° counterclockwise rotation about the origin is (2, -8) .

Transformations are changes done in the shapes on a coordinate plane by rotation, reflection or translation.

Translation, rotation, reflection, and dilation are the four common types of transformations.

Rotation simply means turning. If a point P, whose position vector is (x,y), is rotated  270° counterclockwise rotation about the origin, the position of the image P' is (y, -x).

We have: P(8, 2)

Thus, the image of P will be:

P'(2, -8)

Therefore, the image of P under a 270° counterclockwise rotation about the origin is (2, -8).

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According to the 68-95-99.7 rule, approximately 68% of the distribution falls within one standard deviation of the mean, 95% falls within two standard deviations, and 99.7% falls within three standard deviations.

In this case, the mean is 7.06 minutes and the standard deviation is 0.75 minutes. Therefore, the range of times that covers the middle 95% of the distribution would be from the mean minus two standard deviations (7.06 - 2 x 0.75 = 5.56 minutes) to the mean plus two standard deviations (7.06 + 2 x 0.75 = 8.56 minutes).

In other words, 95% of the male college students' mile run times are expected to fall between 5.56 and 8.56 minutes. This means that most of the students' mile run times will be within this range, and only a small percentage will be outside of it.

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As the number of trials gets larger, the experimental probability of an event approaches the theoretical probability of the event.

The Law of Large Numbers, a key idea in probability theory, holds that as trials or experiments are conducted, the experimental probability of an occurrence tends to converge toward the theoretical or predicted probability of that event.

In other words, the experimental results improve in accuracy and reliability as the sample size grows when forecasting the actual course of an event. This is because a bigger sample size reduces the significance of random changes or data errors and increases the likelihood that the experimental results will accurately reflect the true underlying probability of the event.

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The ordered pair that is a reflection over the x-axis for the point shown include the following: A. (6, 4)

In Mathematics and Geometry, a reflection over or across the x-axis is represented by this transformation rule (x, y) → (x, -y).

This ultimately implies that, a reflection over or across the x-axis would maintain the same x-coordinate while the sign of the y-coordinate changes from positive to negative or negative to positive.

Next, we would apply a reflection over or across the x-axis to the point;

(x, y)                →      (x, -y)

(6, -4)                →      (6, -(-4)) = (6, 4)

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The length of the fabric piece is 5 cm.

We are given the width and area of the fabric piece and need to find its length. Here are the steps:

1. The terms involved in this problem are width, length, and area.
2. The formula to calculate the area of a rectangle is Area = Width × Length.
3. We are given the width (6 cm) and area (30 cm²) of the fabric piece.
4. To find the length, we'll rearrange the formula: Length = Area ÷ Width.
5. Plug in the given values: Length = (30 cm²) ÷ (6 cm).
6. Perform the calculation: Length = 5 cm.

So, the length of the fabric piece is 5 cm.

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The z-score for the 90th percentile is approximately 1.28, for the 62nd percentile is approximately 0.31, and for the first quartile (25th percentile) is approximately -0.67.

To calculate the percentiles for this dataset, we need to use the z-score formula. Unfortunately, I cannot directly provide you the responses for the 90th, 62nd, and first quartile percentiles without more information.

However, I can help you understand the process of finding these percentiles:

1. Determine the z-score corresponding to the desired percentile using a z-score table or calculator. For example, the z-score for the 90th percentile is approximately 1.28, for the 62nd percentile is approximately 0.31, and for the first quartile (25th percentile) is approximately -0.67.

2. Use the following formula to find the response corresponding to the z-score:

  Response = Mean + (Z-score × Standard Deviation)

For example, to find the 90th percentile:

  Response = 5.7 + (1.28 × 2.3)

Calculate this for each percentile using their respective z-scores, and you will find the responses you are looking for.

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The function used to add together the last employee's sales for the three months on the Employee Sales Summary sheet is: =SUM('Employee Sales January:Employee Sales March'!E5)

SUM(E16): This function adds up the values in cells E16 from the current sheet. If the last employee's sales for the three months are stored in cells E16, E17, and E18, then this function would correctly calculate the total.

E16+E16+E16: This expression adds up the value in cell E16 three times. If the last employee's sales for the three months are stored in cells E16, E17, and E18, then this expression would not calculate the total correctly.

SUM('Employee Sales October:Employee Sales December'!E16): This function adds up the values in cell E16 from all sheets between Employee Sales October and Employee Sales December (inclusive). If the last employee's sales for the three months are stored in cells E16, E17, and E18 on different sheets, then this function could be used to calculate the total.

SUM('Employee Sales January:Employee Sales March'!E5): This function adds up the values in cell E5 from all sheets between Employee Sales January and Employee Sales March (inclusive).

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Full Question: On the Employee Sales Summary sheet, the function used to add together the last employee's sales for the three months is ___________________.

Group of answer choices

The sample mean difference from these 24 pairs of siblings is 1.79 inches.

To find the sample mean difference from these 24 pairs of siblings, you can use the given 95% confidence interval for the mean difference in heights, which is (-0.76, 4.34).

The sample mean difference is the midpoint of the confidence interval. To calculate this, add the lower bound (-0.76) and the upper bound (4.34) of the confidence interval, and then divide by 2:

(-0.76 + 4.34) / 2 = 3.58 / 2 = 1.79 inches

So, the sample mean difference from these 24 pairs of siblings is 1.79 inches.

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Carla's right rectangular prism could have either a 3x4 or a 2x6 rectangle as the bottom layer, with a height of 2 units, to achieve the given volume of 24 cubic units.

Carla built a right rectangular prism using unit cubes, with a volume of 24 cubic units and a height of 2 units. To determine the possible figure for the bottom layer of the prism, we need to understand the relationship between the volume, height, and the base area.

The volume of a rectangular prism can be calculated using the formula: Volume = Base Area × Height. In Carla's case, the volume is 24 cubic units, and the height is 2 units. By rearranging the formula, we can find the base area: Base Area = Volume ÷ Height. Substituting the given values, Base Area = 24 ÷ 2, which equals 12 square units.

Now, we need to find a possible figure for the bottom layer with an area of 12 square units. Since the bottom layer is made of unit cubes, it must have whole-number dimensions. There are two possible rectangular figures that meet this requirement: 1) a 3x4 rectangle, and 2) a 2x6 rectangle. Both of these figures have an area of 12 square units (3x4 = 12 and 2x6 = 12) and can be formed using unit cubes.

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The rate of return should an investor expect to earn if he or she purchases these bonds is equal to 4.184%.

Annual coupon rate = 6.35%

Maturity time = 20 years

To calculate the rate of return an investor should expect to earn if they purchase the Taussig Corp. S bonds,

Consider the cash flows from the bond and the purchase price.

Determine the cash flows from the bond,

The bond has a 6.35% annual coupon rate,

which means it pays $63.50 per year 6.35% of $1,000 face value.

The bond has a 20-year maturity, so there will be 20 coupon payments of $63.50 each.

If the bond is not called, the investor will receive the face value of $1,000 at maturity.

Calculate the purchase price of the bond,

The bonds are currently selling for $960.

Calculate the yield to maturity (YTM) on the bond,

Assume the yield curve is horizontal, so the yield to maturity will be the same as the coupon rate.

Calculate the rate of return using the following formula,

Rate of Return = [tex](Total Cash Flows / Purchase Price)^{(1 / Holding Period)}[/tex] - 1

Let us calculate the rate of return step by step,

Total Cash Flows,

Coupon payments,

$63.50 × 20 years = $1,270

Face value at maturity = $1,000

Total Cash Flows = $1,270 + $1,000

                            = $2,270

Rate of Return = [tex]($2,270 / $960)^{(1 / 20)}[/tex] - 1

Using a financial calculator , Attached calculation.

solve for the rate of return:

Rate of Return ≈ 4.184%

Therefore, an investor should expect to earn approximately a 4.18% rate of return if they purchase these bonds.

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Answer:

17 DVDs and 23 CDs

Step-by-step explanation:

x is the number of DVDs

y is the number of CDs

7x + 4y = $211

x + y = 40 ----(x4)----> 4x + 4y = 160

3x = 51

x = 17

x + y = 40

17 + y = 40

y = 23

In conclusion, 17 DVDs and 23 CDs were sold.

Answer:

6

Step-by-step explanation:

Here are the base five numerals from 1 to 100

1, 2, 3, 4, 10, 11, 12, 13, 14, 20, 21, 22, 23, 24, 30, 31, 32, 33, 34, 40, 41, 42, 43, 44, 100.

With the base five, every number can only take on the values of 0, 1, 2, 3, or 4.

After the number 4, we carry over to the following place value and start again with 0. So, for instance, the number after 4 in base five is 10, because we've carried over to the next place value and started with 0 again.

In this way, we can count all the way up to 100 in base five, using these 25 unique numerals.

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To compute the direct labor rate and efficiency variances, we will use the given terms: Actual Hours (AH), Standard Hours (SH), Actual Rate (AR), and Standard Rate (SR). Here's a step-by-step explanation:

Step 1: Calculate the Actual Labor Cost
Actual Labor Cost = AH * AR

Step 2: Calculate the Standard Labor Cost
Standard Labor Cost = SH * SR

Step 3: Calculate the Labor Rate Variance
Labor Rate Variance = (AR - SR) * AH

Step 4: Classify the Labor Rate Variance
If the Labor Rate Variance is positive, it is unfavorable. If it is negative, it is favorable. If it is zero, there is no variance.

Step 5: Calculate the Standard Labor Cost for Actual Hours
Standard Labor Cost for Actual Hours = AH * SR

Step 6: Calculate the Labor Efficiency Variance
Labor Efficiency Variance = (AH - SH) * SR

Step 7: Classify the Labor Efficiency Variance
If the Labor Efficiency Variance is positive, it is unfavorable. If it is negative, it is favorable. If it is zero, there is no variance.

By following these steps, you can compute the direct labor rate and efficiency variances for the period and classify each as favorable, unfavorable, or no variance.

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Answer:

8.5y

Step-by-step explanation:

you add what's in the parentheses, 0.5+8, it's 8.5

You then do 8.5*y, and you get

8.5y

Answer: f(t) = 2.4t - 500

Step-by-step explanation:

So first of all, we need how much she actually profits from each taco. She charges $3.25 per taco, but we cannot forget that it is not free to make a taco in the first place. It costs her $0.85 to make a taco. This means we have to subtract the 85 cents from the 3 dollars 25 cents, which means it ends up being $2.40, or as the answer choices have it, 2.4.

So now we know what the number of tacos is being multiplied by: 2.4.

2.4t is now the profit per taco multiplied by the number of tacos.

But we're not quite done yet.

She has a fixed expense of $500 a month, which means this has to be subtracted from her taco profits to find her true profit.

Putting all of this together, we get f(t)=2.4t - 500.

(t)= (profit per taco)(amount of tacos sold) - (fixed expenses)

After 5 years with 8% depreciation, the Audi R8's value will be around $81,249.36.

To determine how much money you must have in your account now, you can use the formula A = Pe^(rt), where A is the final amount, P is the principal (the initial amount invested), e is the constant 2.71828, r is the annual interest rate expressed as a decimal, and t is the time in years. We will calculate using this formula.Plugging in the given values, we get:
A = $23,000
r = 0.068 (6.8% expressed as a decimal)
t = 5 years
So, $23,000 = P*e^(0.068*5)
Solving for P, we get:
P = $16,376.59
Therefore, you must have $16,376.59 in your account now to reach your goal of $23,000 in 5 years with 6.8% continuous compounding interest. To determine how much the Audi R8 will be worth in 5 years, you can use the formula A = P(1 - r)^t, where A is the final amount, P is the initial amount, r is the annual depreciation rate expressed as a decimal, and t is the time in years. Plugging in the given values, we get:
P = $148,700
r = 0.08 (8% expressed as a decimal)
t = 5 years
So, A = $148,700*(1 - 0.08)^5
Simplifying, we get:
A = $81,249.36
Therefore, the Audi R8 will be worth approximately $81,249.36 in 5 years with 8% depreciation.

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