Charged Particles
Charge on Particle Number of Particles
Positive 3
Negative 2

A negatively charged substance is brought near the ion. What will most likely happen?


(A) The negatively charged ion will repel the substance.
(B) The negatively charged ion will attract the substance.
(C) The positively charged ion will repel the substance.
(D) The positively charged ion will attract the substance.

Answers

Answer 1

Answer:

D

Explanation:

cause overall charge is +1 so will attract


Related Questions

9. a) What is an isotope?​

Answers

Answer:

Each of two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei, and hence differ in relative atomic mass but not in chemical properties; in particular, a radioactive form of an element. Hope this helps, have a good day! :)

Answer:

atoms with the same number of protons and electrons but different numbers of neutrons

Explanation:

Please show all of your work, I need to understand all steps:
A student collected time (t) and concentration ([A]) data at
295 K for the reaction 2A→B. These time and concentration data are shown in the table to the right. The student then plotted graphs of [A] versus t (Figure 1) , ln[A] versus t (Figure 2) , and 1/[A] versus t (Figure 3) .
Figure 1:
t (s) (A)(M) ln(A) 1/ (A)
0.00 0.500 −0.693 2.00
20.0 0.389 −0.944 2.57
40.0 0.303 −1.19 3.30
60.0 0.236 −1.44 4.24
80.0 0.184 −1.69 5.43
i.) What is the rate of the reaction?
ii.) What is the value of the rate constant for this reaction?
iii.)
Next, the student ran the same reaction at a different temperature and measured a different reaction rate, with the following results:
T(K) k(s-1)
295 0.0125
325 0.0357
What is the activation energy of this reaction?
Express your answer to three significant figures and include the appropriate units.

Answers

Answer:

a because the x and y value is the same

PLEASE HELP 15 POINTS!! Which equation is needed to solve this problem?

Answers

Answer:

Option 1

Explanation:

The question is asking us what formula is used to obtain the quantity of heat added to a given mass of mercury in order to cause its temperature to change.

This quantity of heat is obtained from;

q = mcspΔT

Where;

q = quantity of heat added

m = mass of the mercury

csp= specific heat capacity of mercury

ΔT = temperature change

Each of the following sets of quantum numbers is supposed to specify an orbital Choose the one set of quantum numbers that does NOT contain an error.
a) n=4, I=4, m/=1
b) n=5, I=3, m/=- 3
c) n=3, I=1, m/= -2
d) n=3, I= 2, m/=+3 ​

Answers

Answer:

C

Explanation:

The correct answer is C because the first quantum numbers containing and encompass in an orbital m contain a definite she'll of 2 and hence

Please help me fill in the blanks

Answers

Answer: ew i hate science but ive done that same thing before i dont remember the answers though

Explanation:

Why does the standard model of the universe need to be change?

Answers

Explanation:

The standard model of particle physics is a relativistic theory of quantum fields developed between 1970 and 1973 [citation needed] based on the ideas of unification and symmetries [1] that describes the fundamental structure of matter and vacuum considering the elementary particles as irreducible entities whose kinematics is governed by the four known fundamental interactions (except for gravity, whose main theory, general relativity, does not fit the mathematical models of the quantum world). The word "model" in the name comes from the 1970s when there was not enough experimental evidence to confirm the model. [1] To date, almost all experimental tests of the three forces described by the standard model are in agreement. with their predictions. However, the standard model falls short of being a complete theory of fundamental interactions due to several unresolved issues.

A sample of 4.0 L of nitrogen, at 1.2 atmospheres, is transferred to a 12 L container.
What will the pressure be in the new container?

Answers

Answer:

The pressure will be 0.4 atm.

Explanation:

The gas laws are a set of chemical and physical laws that allow determining the behavior of gases in a closed system. The parameters evaluated in these laws are pressure, volume, temperature and moles.

As the volume increases, the gas particles (atoms or molecules) take longer to reach the walls of the container and therefore collide with them less times per unit of time. This means that the pressure will be lower because it represents the frequency of collisions of the gas against the walls. In this way pressure and volume are related, determining Boyle's law which says:

"The volume occupied by a certain gaseous mass at constant temperature is inversely proportional to pressure"

Boyle's law is expressed mathematically as:

P*V= k

If you initially have the gas at a volume V1 and press P1, when the conditions change to a volume V2 and pressure P2, the following is satisfied:

P1*V1= P2*V2

In this case:

P1= 1.2 atmV1= 4 LP2= ?V2= 12 L

Replacing:

1.2 atm* 4 L= P2* 12 L

Solving:

[tex]P2=\frac{1.2 atm*4 L}{12 L}[/tex]

P2= 0.4 atm

The pressure will be 0.4 atm.

We learned that Energy can
exist in many forms.
Do you think energy can
converted from one form to
another?

Answers

Yea energy can convert from one form to another

The form of energy carried by moving electrical charges is ____________________ energy.

Answers

Answer:

kinetic

Explanation:

hope this helps

Answer:

Kinetic energy

Explanation:

How to solve this problem in Chemistry? I am stuck

Answers

The buffer can be made using an acid or a base.

What is a buffer?

We have to know that the term buffer is the generic term that can be generally used to describe any solution that is resistant to changes in acidity and the alkalinity of the solution.

We know that we can be able to make a buffer in two ways;

1) By the use of a weak acid and its salt

2) By the use of weak base and its salt.

In each case, the pH of the solution that has been formed would not be easily changed and this is the job of the buffer.

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The Sun is located _____.

in the central core of the Milky Way galaxy
in the bar of the Milky Way
in an arm about 25% of the distance from the center of the Milky Way to its outer edge
in an arm about 75% of the distance from the center of the Milky Way to its outer edge

Answers

Answer:

I believe the answer is going to be A. in the central core of the Milky Way galaxy.

Explanation: lol sorry I put it in the question box instead of answering it, hope this helps!

Which phase change results in atoms with the highest kinetic energy? A. Boiling B. Melting C. Freezing D. Condensing

Answers

Answer: Boiling because it makes the molecules in water bounce around.

Hope it helps.

How many moles of NaCl would you have in 100 mL of this solution?

Answers

Answer:

You didnt give me a molarity so ill show you how to solve it with an equation

Explanation:

Molarity represent by M

M= mols/ Volume (in liters)

so mols = (whatever the molarity was) x (.100L because it is =100ml)

Mols=  M x (.100)

plug in the molarity you have for x and you are done

WILL MARK BRAINLIEST!!
Which situation indicates a beta emission?


The atomic number increases by one, but the mass number does not change.


The atomic number decreases by two, and the mass number decreases by four.


The atomic number decreases by one, and the mass number decreases by one.

The atomic number and the mass number both decrease by two.

Answers

The answer is the first option

Answer:

A: The atomic number increases by one, but the mass number does not change.

what is the energy of a photon of yellow light with a frequency of 5.2 x 10¹⁴ Hz?

Answers

Answer:

3.4x10⁻¹⁹J is the energy of the photon

Explanation:

To find the energy of a photon from its frequency we must use the equation:

E = hf

Where E is the energy of the photon in J, our incognite

h is Planck's constant = 6.6262x10⁻³⁴Js

And f is the frequency = 5.2x10¹⁴Hz = 5.2x10¹⁴s⁻¹

Replacing:

E = 6.6262x10⁻³⁴Js*5.2x10¹⁴s⁻¹

E = 3.4x10⁻¹⁹J is the energy of the photon

If a photon dropping from the n = 7 to the n = 1 level hit the surface of Au, what would be the wavelength of the ejected electron in nanometers?

Answers

Answer:

here's the answer.hope it helps

5. (a-c) In the balanced equation below, how many grams of solid iron can be formed if 50.0g Fe2O3 reacts with 10.0g of CO?
Fe2O3(s) + 3CO(g) → 2Fe(s) +3CO2

a. What mass of the excess reactant remains after the reaction occurred?
b. If you conducted an experiment and 11.5 grams of Fe(s) was formed what would be the percent yield?
c. If the percent yield for the process to obtain 75 kg of CO2 was 80.7%, how many kg of CO is needed?

Answers

The mass of the excess reactant ([tex]Fe_2O_3[/tex] that remains after the reaction would be 30.96 gramsThe percent yield would be 86.28%The amount of CO needed would be 59.14 kg.

Stoichiometric problems

From the balanced equation of the reaction, the mole ratio of the reactants is 1:3.

Mole of 50.0 g [tex]Fe_2O_3[/tex] = 50/160 = 0.3125 mol

Mole of 10.0 g CO = 10/28 = 0.3571 mol

Stoichiometric equivalent of  [tex]Fe_2O_3[/tex] = 0.3571/3 = 0.1190 mol

In other words,  [tex]Fe_2O_3[/tex] is in excess.

Excess mole = 0.3125 - 0.1190 = 0.1935 mol

Mass of 0.1935 mol [tex]Fe_2O_3[/tex] = 0.1935 x 160 = 30.96 grams

Mole ratio of CO to Fe = 3:2

Equivalent mole of Fe that would be formed = 0.3571 x 2/3

                                                                          = 0.2381 mol

Mass of 0.238 mol Fe = 0.238 x 56 = 13.328 grams

Percent yield of Fe = 11.5/13.328 x 100 = 86.28%

Mole of 75 gk CO2 = 75000/44 = 1704.55 mol

Mole ratio of CO2 and Co = 1:1

Equivalent mole of CO = 1704.55 mol

Mass of 1704.55 mol CO = 1704.55 x 28 = 47.73 kg

80.7% = 47.73 kg

100% = 100 x 47.73/80.7

        = 59.14 kg

In other words, 59.14 kg of CO would be needed.

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4. A student poured 50 cm^3
water into a beaker and
measured the water's
temperature. The student added
1.00 g calcium chloride to the
water, stirred the mixture and
then recorded the temperature.
The concentration of a calcium
chloride solution is 12 g/dm^3.
Calculate the volume of this
solution, in cm^3, that contains
9.0 g of calcium chloride.

Answers

Answer:

V = 750 cm³

Explanation:

The volume of the solution can be calculated by the following formula:

[tex]V = \frac{M}{C}[/tex]

where,

V = Volume of solution = ?

M = Mass of Calcium Chloride = 9 g

C = Concentration of Solution = 12 g/dm³

Therefore,

[tex]V = \frac{9\ g}{12\ g/dm^3}\\\\V = (0.75 dm^3)(\frac{1000\ cm^3}{1\ dm^3})[/tex]

V = 750 cm³


Under the right conditions aluminum will react with chlorine to produce aluminum chloride.
2 Al + 3 Cl2 - 2 AICI3
How many grams of aluminum are needed to react completely with 11.727 liters of chlorine?
CORRECT ANSWER IS 9.42, but what are the steps to get that answer ?

Answers

Answer:

9.42 g

Explanation:

Step 1: Write the balanced equation

2 Al + 3 Cl₂ ⇒ 2 AICI₃

Step 2: Calculate the moles corresponding to 11.727 L of Cl₂

Since the conditions are not specified, we will assume Cl₂ is at standard temperature and pressure. At STP, 1 mole of Cl₂ occupies 22.4 L.

11.727 L × 1 mol/22.4 L = 0.524 mol

Step 3: Calculate the moles of Al needed to react with 0.524 moles of Cl₂

The molar ratio of Al to Cl₂ is 2:3. The moles of Al needed are 2/3 × 0.524 mol = 0.349 mol

Step 4: Calculate the mass corresponding to 0.349 moles of Al

The molar mass of Al is 26.98 g/mol.

0.349 mol × 26.98 g/mol = 9.42 g

CaCO3 (s) + 176 KJ à CaO (s) + CO (g)

A. 176 KJ are released in an endothermic reaction.
B. 176 KJ are released in an exothermic reaction
​​​​​​C. 176 KJ are absorbed in an exothermic reaction.
D. 176 KJ are absorbed in an endothermic reaction.

Answers

Answer:

its d

Explanation:

How many molecules of H2O are equivalent to 98.2 g of H2O

Answers

Answer:

Demo Mole Quantities

58.5g NaCl(mol/58.5g)(6.02 x 1023/mol) = 6.02 x 1023 Na

+

Cl21 pre-1982 pennies (after 1982 pennies are mostly zinc with copper coating)

63.5g Cu( mol/ 63.5g)(6.02 x 1023/mol) = 6.02 x 1023 Cu

19.0g Al (mol/27.0g)(6.02 x 1023/mol) = 4.24 x 1023 Al

Explanation:

How many grams of sodium carbonate are produced when 5.3 moles of sodium phosphate reacts with aluminum carbonate?

Answers

Answer: There is 842.54 grams of sodium carbonate are produced when 5.3 moles of sodium phosphate reacts with aluminum carbonate.

Explanation:

Chemical equation depicting reaction between sodium phosphate and aluminum carbonate is as follows.

[tex]Al_{2}(CO_{3})_{3} + 2Na_{3}PO_{4} \rightarrow 2AlPO_{4} + 3Na_{2}CO_{3}[/tex]

As this equation contains same number of atoms on both reactant and product side. So, this equation is a balanced equation.

According to the equation, 2 moles of sodium phosphate is giving 3 moles of sodium carbonate.

Therefore, sodium carbonate formed by 5.3 moles of sodium phosphate is as follows.

[tex]\frac{3}{2} \times 5.3 mol\\= 7.95 mol[/tex]

As number of moles is the mass of substance divided by its molar mass. So, mass of sodium carbonate ( molar mass = 105.98 g/mol) is as follows.

[tex]No. of moles = \frac{mass}{molar mass}\\7.95 mol = \frac{mass}{105.98 g/mol}\\mass = 842.54 g[/tex]

Thus, we can conclude that there is 842.54 grams of sodium carbonate are produced when 5.3 moles of sodium phosphate reacts with aluminum carbonate.

10 points

Scenario: Calculate the new temperature when a 2.0 L of a gas at 220 K is compressed to 1.0 L.

Hint! You should check three boxes: one to describe particle speed, one to describe particle spacing and one to describe number of particle collisions.

Question 5 options:

The particles speed up.


The particles slow down.


The particle speed doesn't change.


The particles get squished (compressed) together.


The particles float farther apart.


The distance between particles doesn't change.


The amount of collisions among particles in the gas sample increase.


The amount of collisions among particles in the gas sample decrease.


The amount of collisions among particles in the gas sample doesn't change.

Answers

Answer:

The 2nd, 4th, and 7th options

Explanation:

Suppose two materials: (1) titanium and (2) a new synthetic polymer are tested by hanging a mass from a test sample made from each material. Both samples have an initial length of and a cross-section area of . The synthetic polymer is know to behave similarly to the Kelvin-Voigt model, and has parameters and . Use MATLAB to plot the deformation in each specimen for the first ten seconds of the test. Neglect the mass of each test specimen, and assume that the hanging mass is instantly applied to each material at time .

Answers

Answer:

ffffffffffffff

Explanation:

vvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv

The density of oxygen gas at a certain temperature and pressure is 1.345 g cm-3. How many oxygen atoms are present in 2.0 L of oxygen gas at this same temperature and pressure?

Answers

The number of oxygen atoms present in 2.0L of oxygen gas at same temperature and pressure is 5.1 × 10²² atoms.

How to calculate number of atoms?

The number of atoms of a substance can be calculated by multiplying the number of moles in the substance by Avogadro's number (6.02 × 10²³).

no of atoms = no of moles × 6.02 × 10²³

According to this question, the density of oxygen gas at a certain temperature and pressure is 1.345 g cm-³. If 2.0 L of oxygen gas is given, the mass of the oxygen gas can be calculated as follows:

mass = 1.345 × 2 = 2.69grams

moles = 2.69g ÷ 32g/mol = 0.084moles

No of atoms = 0.084 mol × 6.02 × 10²³

no of atoms = 5.1 × 10²² atoms

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A 752g sample of an unknown substance has its temperature increase by 8°C after being exposed to 1287.424 j,calculate the specific heat of
the substance. _____J/g*C (3 sig figs)

Answers

Answer:

0.214 J/g.°C

Explanation:

Step 1: Given data

Mass of the sample (m): 752 gTemperature increase (ΔT): 8 °CProvided heat (Q): 1287.424 J

Step 2: Calculate the specific heat of the substance (c)

The specific heat of the substance is an intrinsic property of a substance. We can calculate it using the following expression.

Q = c × m × ΔT

c = Q / m × ΔT

c = 1287.424 J / 752 g × 8 °C = 0.214 J/g.°C

Starting with 2.50 mol of N2 gas (assumed to be ideal) in a cylinder at 1.00 atm and 20.0C, a chemist first heats the gas at constant volume, adding 1.36 * 104 J of heat, then continues heating and allows the gas to expand at constant pressure to twice its original volume. Calculate (a) the final temperature of the gas; (b) the amount of work done by the gas; (c) the amount of heat added to the gas while it was expanding; (d) the change in internal energy of the gas for the whole process.

Answers

Answer:

a)  [tex]T_b=590.775k[/tex]

b)  [tex]W_t=1.08*10^4J[/tex]

d)  [tex]Q=3.778*10^4J[/tex]

d)  [tex]\triangle V=4.058*10^4J[/tex]

Explanation:

From the question we are told that:

Moles of N2 [tex]n=2.50[/tex]

Atmospheric pressure [tex]P=100atm[/tex]

Temperature [tex]t=20 \textdegree C[/tex]

                      [tex]t = 20+273[/tex]

                     [tex]t = 293k[/tex]

Initial heat [tex]Q=1.36 * 10^4 J[/tex]

a)

Generally the equation for change in temperature is mathematically given by

[tex]\triangle T=\frac{Q}{N*C_v}[/tex]

  Where

  [tex]C_v=Heat\ Capacity \approx 20.76 J/mol/K[/tex]

[tex]T_b-T_a=\frac{1.36 * 10^4 J}{2.5*20.76 }[/tex]

[tex]T_b-293k=297.775[/tex]

[tex]T_b=590.775k[/tex]

b)

Generally the equation for ideal gas is mathematically given by

 [tex]PV=nRT[/tex]

For v double

 [tex]T_c=2*590.775k[/tex]

 [tex]T_c=1181.55k[/tex]

Therefore

[tex]PV=Wbc[/tex]

[tex]Wbc=(2.20)(8.314)(1181_590.778)[/tex]

[tex]Wbc=10805.7J[/tex]

Total Work-done [tex]W_t[/tex]

[tex]W_t=Wab+Wbc[/tex]

[tex]W_t=0+1.08*10^4[/tex]

[tex]W_t=1.08*10^4J[/tex]

c)

Generally the equation for amount of heat added is mathematically given by

[tex]Q=nC_p\triangle T[/tex]

[tex]Q=2.20*2907*(1181.55-590.775)\\[/tex]

[tex]Q=3.778*10^4J[/tex]

d)

Generally the equation for change in internal energy of the gas is mathematically given by

[tex]\triangle V=nC_v \triangle T[/tex]

[tex]\triangle V=2.20*20.76*(1181.55-293)k[/tex]

[tex]\triangle V=4.058*10^4J[/tex]

Anyone know this
Please help me

Answers

Answer:

sorry I don't know

Explanation:

have a great time with your family and friends

How many moles of magnesium atoms react with 1 mole of oxygen molecules?

Answers

1 mole of magnesium atoms will react with 2 moles of oxygen molecules. This is because the chemical equation for the reaction between magnesium and oxygen is: Mg + O2 → MgO.

What is chemical equation?

A chemical equation is a symbolic representation of a chemical reaction, showing the reactants (starting materials) on the left side and the products (resulting substances) on the right side. The symbols used to represent the reactants and products are chemical formulas, which use the symbols of the elements in the reaction. The arrow between the reactants and products indicates the type of reaction taking place. The coefficients next to the symbols and formulae of entities indicate the number of moles of each species that are involved in the reaction. The overall reaction is balanced when the number of atoms of each element on the left side of the equation is equal to the number of atoms of that element on the right side of the equation.

This equation shows that for every 1 mole of magnesium atoms, 2 moles of oxygen molecules are required for the reaction to take place. Therefore, 1 mole of magnesium atoms will react with 2 moles of oxygen molecules.

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I need help please in this:(

Answers

Answer:

That would be A sir or Miss

Explanation: Tell me if I am wrong, Also hope this helped you!

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