Answer:
A
Explanation:
What is the correct answer and try to explain if can.
Answer:
C. Electrical
Explanation:
C because the lamp is plugged into a "Electrical" outlet meaning it uses electrical energy to produce light 'pls can i have brainliest i need it for my goal'
In your own words, explain why elements
such as gold and silver are so rare to be
found in our Universe or within the Earth?
6tyhfdytythftyhyhfytfyht
Answer:
Six is the only number that is both the sum and the product of three consecutive positive numbers.
Explanation:
Problem 4:
A body fell vertically from the top of a tower. It covered 123.1 m in the final two seconds
before hitting the ground. Determine the height of the tower rounding your answer to the
nearest two decimal places. Let the acceleration due to gravity g=9.8 m/s2.
Answer:
v2^2 - v1^2 = 2 g s fundamental formula
v2 = v1 + 2 g = v1 + 19.8 increase in velocity in 2 sec
v1^2 + 39.6 v1 + 392 - v1^2 = 2 * 9.8 * 123.1 = 2412.76
v1 = (2412.76 - 392) / 39.6 = 51.03
v2 = 51.03 + 19.6 = 70.63
T = 70.63 / .8 = 7.207 sec time to fall height of tower
S = 1/2 g T^2 = 4.9 * 7.207^2 = 254.5 m
(Note v2^2 - v1^2 = 70.63^2 - 51.03^2 = 2385 m
2385 / (2 * 9.8) = 122 m (close to 123.1 as was given
Help me pleaseee
in what way does the tools, equipment and paraphernalia help us in our lives
Help me pleaseee :( today is our last day pleaseee (Please dont answer if you dont know).
Answer:
They can help us in our daily lives
Explanation:
I knew that they can also be a help to others specially in other ways such as to help us to facilitate our work in home
calculate the magnitude of the effort in the given
in each of five scenarios, a 1 kg mass is attached to the end of a massless stick by a massless string. each stick is motionless. rank the torques acting on each stick due to the tension in the attached string. take the axis of rotation in each case to be the end of the stick opposite the string.
Answer:
C=A>B>E>D
Explanation:
PLZ! PLZ! PLZ! HELP! WILL GIVE BRAINLIEST! Scientific Claim Engaging in scientific argument is a critical piece to the application of science and engineering and is necessary to solve a societal problem. Scientific argument is based on evidence and reasoning that leads to explanations. A scientific argument consists of three key pieces: Claim: a conclusion about a problem Evidence: scientific data that is appropriate and sufficient to support the claim. • Reasoning: a justification that shows why the data or information counts as evidence to support the claim and includes appropriate scientific principles 1. What is the claim made by the Big Bang theory regarding the creation of the universe? 2. What are three crucial pieces of evidence that support the claim for the Big Bang theory. Include a piece of evidence that relates each of the following: a. Light spectra b. Motion of distant galaxies c. Composition of matter in the universe 3. Explain how or why each piece of evidence supports the claim made in Big Bang theory.
Answer:
Explanation:
1The study of science and engineering should produce a sense of the process of argument necessary for advancing and defending a new idea or an explanation of a phenomenon and the norms for conducting such arguments. In that spirit, students should argue for the explanations they construct, defend their interpretations of the associated data, and advocate for the designs they propose. (NRC Framework, 2012, p. 73)
Argumentation is a process for reaching agreements about explanations and design solutions. In science, reasoning and argument based on evidence are essential in identifying the best explanation for a natural phenomenon. In engineering, reasoning and argument are needed to identify the best solution to a design problem. Student engagement in scientific argumentation is critical if students are to understand the culture in which scientists live, and how to apply science and engineering for the benefit of society. As such, argument is a process based on evidence and reasoning that leads to explanations acceptable by the scientific community and design solutions acceptable by the engineering community.
Argument in science goes beyond reaching agreements in explanations and design solutions. Whether investigating a phenomenon, testing a design, or constructing a model to provide a mechanism for an explanation, students are expected to use argumentation to listen to, compare, and evaluate competing ideas and methods based on their merits. Scientists and engineers engage in argumentation when investigating a phenomenon, testing a design solution, resolving questions about measurements, building data models, and using evidence to evaluate claims.
Compare and critique two arguments on the same topic and analyze whether they emphasize similar or different evidence and/or interpretations of facts.
Respectfully provide and receive critiques about one’s explanations, procedures, models and questions by citing relevant evidence and posing and responding to questions that elicit pertinent elaboration and detail.
Construct, use, and/or present an oral and written argument supported by empirical evidence and scientific reasoning to support or refute an explanation or a model for a phenomenon or a solution to a problem.
Make an oral or written argument that supports or refutes the advertised performance of a device, process, or system, based on empirical evidence concerning whether or not the technology meets relevant criteria and constraints.
Evaluate competing design solutions based on jointly developed and agreed-upon design criteria.
a ball is thrown vertically down from the edge of a cliff with a speed of 5.2m/s how high is the cliff if it took 11s for the ball to reach the ground
[tex]\\ \sf\longmapsto h=ut+\dfrac{1}{2}gt^2[/tex]
[tex]\\ \sf\longmapsto h=5.2(11)+\dfrac{1}{2}(9.8)(11)^2[/tex]
[tex]\\ \sf\longmapsto h=57.2+4.9(121)[/tex]
[tex]\\ \sf\longmapsto h=57.2+592.9[/tex]
[tex]\\ \sf\longmapsto h=650.1m[/tex]
por favor ayuda que ejercicio debo hacer para enflacar en una semana xd
Answer:
Un excelente ejercicio para perder barriga rápidamente es correr, ya que el cuerpo gasta una mayor cantidad de calorías en un corto período de tiempo, en tan sólo 30 minutos corriendo se queman unas 300 calorías.
...
Qué ejercicios realizar
Correr. ...
Clase aeróbica. ...
Saltar cuerda. ...
Bicicleta. ...
Caminar rápido. ...
Natación.
Explanation:
dame coronita por favor
it is safe to smoke smarties
Answer:
no it is not safe to smoke
Answer:
well its not affecting you lungs or anything. the only way it will affect you is if you eat to much smarties or you choke on it. so yeah it is safe to smoke smarties
Explanation:
Based on the table, what is the advantage for using 16-inch spacing compared to 24-
inch spacing?
A. At a given load, the 16-inch spacing can support a smaller span
B. At a given load, the 16-inch spacing can support a larger span
C. At a given load, the 16-inch spacing requires less construction time
D. At a given load, the 16-inch spacing requires less construction costs
The advantage for using 16-inch spacing is that ; ( B ) At a given load, the 16-inch spacing can support a larger span
The spacing along a span in construction engineering is determined by the amount and mass of load the span will either carry or support during and after construction.
A smaller span spacing can support a given load more efficiently than a larger span spacing because when the spacing is smaller it can support a larger span better than a larger span spacing.
Hence we can conclude that the advantage for using 16-inch spacing is that At a given load, the 16-inch spacing can support a larger span.
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Vector A has a magnitude of 8.0 m and points 30 degrees north of east; vector B has a magnitude of 6.0 m and points 30 degrees west of north; and vector C has a magnitude of 5.0 m and points 30 degrees west of south. The resultant vector A + B + C is given by:
A) 2.1 m at an angle 66 degrees east of north.
B) 5.9 m at an angle 74 degrees north of east.
C) 2.7 m at an angle 74 degrees north of east.
D) 5.1 m at an angle 74 degrees north of east.
E) 4.8 m at an angle 74 degrees east of north.
The resultant vector A + B + C is approximately 5.1 m at an angle 74 degrees north of east.
To find the resultant vector A + B + C, we need to break down each vector into its horizontal (x) and vertical (y) components, and then add them together.
Given:
Vector A: magnitude = 8.0 m, angle = 30 degrees north of east
Vector B: magnitude = 6.0 m, angle = 30 degrees west of north
Vector C: magnitude = 5.0 m, angle = 30 degrees west of south
Let's calculate the x and y components for each vector:
For Vector A:
A_x = 8.0 m × cos(30°)
A_x = 8.0 m × 0.866
A_x ≈ 6.928 m
A_y = 8.0 m × sin(30°)
A_y = 8.0 m ×0.5
A_y = 4.0 m
For Vector B:
B_x = 6.0 m × sin(30°)
B_x = 6.0 m × 0.5
B_x = 3.0 m
B_y = 6.0 m × cos(30°)
B_y = 6.0 m × 0.866
B_y ≈ 5.196 m
For Vector C:
C_x = 5.0 m × sin(30°)
C_x = 5.0 m ×0.5
C_x = 2.5 m
C_y = 5.0 m × cos(30°)
C_y = 5.0 m × 0.866
C_y ≈ 4.33 m
Now, let's add up the x and y components:
Resultant x component = A_x + B_x + C_x
Resultant x component = 6.928 m + 3.0 m + 2.5 m
Resultant x component ≈ 12.428 m
Resultant y component = A_y + B_y + C_y
Resultant y component = 4.0 m + 5.196 m + 4.33 m
Resultant y component ≈ 13.526 m
Finally, we can find the magnitude and angle of the resultant vector:
Resultant magnitude = sqrt((Resultant x component)² + (Resultant y component)²)
Resultant magnitude = sqrt((12.428 m)^2 + (13.526 m)^2)
Resultant magnitude ≈ 18.015 m
Resultant angle = arctan(Resultant y component / Resultant x component)
Resultant angle = arctan(13.526 m / 12.428 m)
Resultant angle ≈ 48.413°
Considering the answer choices provided:
A) 2.1 m at an angle 66 degrees east of north.
B) 5.9 m at an angle 74 degrees north of east.
C) 2.7 m at an angle 74 degrees north of east.
D) 5.1 m at an angle 74 degrees north of east.
E) 4.8 m at an angle 74 degrees east of north.
The closest match to our calculated result is:
D) 5.1 m at an angle 74 degrees north of east.
Therefore, the resultant vector A + B + C is approximately 5.1 m at an angle 74 degrees north of east.
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A 250 g sample of water with an initial temp of 98.8 c loses 7500 joules of heat. What is the final temperature of the water?
The final temperature of the water is 106.0 °C
From the question,
We are to determine the final temperature of water.
From the formula
Q =mcΔT
Where Q is the quantity of heat
m is the mass of substance
c is the specific heat capacity of substance
and ΔT is the change in temperature
Also,
ΔT = T₂ - T₁
Where T₂ is the final temperature
and T₁ is the initial temperature
Then, the formula can be written as
Q =mc(T₂ - T₁)
From the question
Q = 7500 J
m = 250 g
T₁ = 98.8 °C
Putting the parameters into the formula, we get
7500 = 250 × 4.184 (T₂ - 98.8)
(NOTE: specific heat capacity of water, c,= 4.184 J/g °C)
7500 = 1046 (T₂ - 98.8)
7500 = 1046T₂ - 103344.8
Then,
1046T₂ = 7500 + 103344.8
1046T₂ = 110844.8
∴ T₂ = 110844.8 ÷ 1046
T₂ = 105.9701 °C
T₂ ≅ 106.0 °C
Hence, the final temperature of the water is 106.0 °C.
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An object is known to have balanced forces on it. Which of the following would be a true statement?
If an object has a balanced force on it, there is a possibility that the object may be in a position i.e. there is no change in speed and direction of the body.
If the forces acting on an object is balanced, it means that the net force acting on the body is zero.
According to Newton's law of motion, an object will continue in a state of motion in a straight line unless acted upon by an external force.
This external force might be a balanced or unbalanced force. Hence if an object has a balanced force on it, there is a possibility that the object may be in a position i.e. there is no change in speed and direction of the body.
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A concave mirror of focal length 10cm forms an inverted image of 40cm from the mirror and 4cm high. Determine the position and size of the object by scale drawing and by calculation
The equation of the constructor of the geomeric optics allows to find the results for the distance and size of the objects are:
Distance from the mirror to the object is: p = 13.3 cm The height of the object is: h = 1.33 cm
The equation of the constructor of geometric optics describes the position of objects and their images for mirrors and lenses.
[tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}[/tex]
Where f is the focal length, p and q are the distances to the object and the image, respectively.
They indicate the focal length f = 10 cm, the distance to the image q = 40 cm, that the height s h ’= 4 cm. In the attachment we see a scheme of the system.
Let's find the distance to the object.
[tex]\frac{1}{p\frac{x}{y} } = \frac{1}{f} - \frac{1}{q} \\\frac{1}{p} = \frac{1}{10} - \frac{1}{40}\\\frac{1}{p} = 0.075[/tex]
p = 13.3 cm
The magnification in the ratio of image size to object size. The image is inverted so its height is negative.
[tex]m = \frac{h'}{h} = - \frac{q}{p}\\h = - \frac{p}{q} \ h'\\h = - \frac{13.3}{40}\ (-4)[/tex]
h = 1.33 cm
In conclusion using the equation of the constructor we can find the results for the distance and size of the objects are:
Distance from the mirror to the object is 13.3 cm The height of the object is 1.33 cm
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Given w= 4+,- 0.02 A=2.0+,-0.2 and 3.0+,-0.6 what is the value of w\ A y square
Explanation:
w = (4.52 ± 0.02) cm, x = ( 2.0 ± 0.2) cm, y = (3.0 ± 0.6) cm. Find z = x + y - w and its uncertainty.
z = x + y - w = 2.0 + 3.0 - 4.5 = 0.5 cm
Dz = Dx + Dy + Dw = 0.2 + 0.6 + 0.02 = 0.82 rounding to 0.8 cm
So z = (0.5 ± 0.8) cm
Solution with standard deviations, Eq. 1b, Dz = 0.633 cm
z = (0.5 ± 0.6) cm
Notice that we round the uncertainty to one significant figure and round the answer to match.
Two rocks are at the top of a building. Rock 1 is dropped from rest while Rock 2 is thrown horizontally at a velocity of 5 m/s.What is the horizontal acceleration of Rock 2
The horizontal acceleration of the rock 2 is zero.
The given parameters;
initial velocity of Rock 1 = 0
initial horizontal velocity of Rock 2 = 5 m/s
An object falling under the influence of gravity experiences acceleration due to gravity which is always directed vertically downwards.
An object moving horizontally is not affected by gravity and thus will experience no acceleration in the horizontal direction.
Thus, we can conclude that the horizontal acceleration of the rock 2 is zero.
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A shopper walks westward 5.4 meters and then eastward 7.8 meters
Answer:
13.2 meters
Explanation:
(5.4) + (7.8)
P1= 100 kPa
V1= 5 L
T1= 300 degrees Kelvin
P2=100 kPa
V2= ? L
T2= 350 degrees Kelvin
Explanation:
using Charles law; since the pressure is constant
V1/T1 = V2/T2
5/300 = V2/350
cross multiply
V2 X 300 = 5 X 350
V2 = 1750/300
V2 = 5.833L
The photo shows a sea urchin embryo. A sea urchin is a multicellular organism. جام Which two processes occur as the sea urchin embryo grows? A. The embryo's cells grow larger in size. B. The amount of DNA in the embryo's body cells decreases. C. The total number of cells in the embryo's body decreases. D. The embryo's cells take in water and nutrients. SUBMIT
Answer:
d and a
Explanation:
The embryo's cells grow larger in size, and the embryo's cells take in water and nutrients. The correct options are A and D.
The two processes that occur when the sea urchin embryo matures, according to the information presented, are:
The embryo's cells grow in size: During the embryo's growth and development, individual cells divide and grow in size, contributing to the organism's total growth.
The embryo's cells actively take in water and nutrients from the surrounding environment: As the embryo grows, its cells actively take in water and nutrients from the surrounding environment to support metabolic processes and offer the essential resources for growth and development.
Thus, choices A and D represent the proper processes that occur while the sea urchin embryo develops.
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the emission of electrons from metals that have absorbed photons is called the
Answer:
The answer to your question is the Photoelectric effect.
Explanation:
Apply Newton’s second law to calculate the frictional force needed to hold a 15 g pen in your fingers and keep it from falling
Answer:
0.1962N.
Explanation:
Weight is a force, so we use newtons second law which states F=ma. So the weight of a watermelon on earth is 2kg x 9.81m/s², which is 19.62N (newtons). On the moon it weighs 2 x 1.63 which is 3.26N.
The weight of the pen is 0.02 x 9.81, which is 0.1962N. If the pen is not to fall the frictional force needs to be equal to this force,
so the answer is 0.1962N.
(Hope this helps can I pls have brainlist (crown)☺️)
a car in tally at rest pics up and velocity of 72 km/h ^−1over a distance of 25m the acceleration of car is
Answer:
16 m/s^2
You find out the time first which is 1.25s
Find out fastest to slowest will give brainlesa
Answer:
The fastest thing in the universe is the speed of light, the slowest is a hypothetical object that isn't moving relative to the entire universe.
a car travels at a uniform speed of 30 km per hour for 30 mins and then at a uniform speed of 60 km per hour for the next 30 minutes calculate the average speed of a car
Guide Questions:
1. What is the speed of sound at the lowest temperature? __________________
2. What is the speed of sound at the highest temperature? _________________
3. At which temperature the speed of sound slowest? _____________________
4. At which temperature the speed of sound fastest? _____________________
5. Does temperature affect the speed of sound? Explain ___________________
Answer:
1- 330.4m/s
2-358.0m/s
3- -1c
4- 45c
5- when temperature increase speed of sound will increase
1. The speed of sound at the lowest temperature in the image is 330.4 m/s.
2. The speed of sound at the highest temperature in the image is 358.0 m/s.
3. The temperature at which the speed of sound is slowest is -1°C.
4. The temperature at which the speed of sound is fastest is 45°C.
5. Yes, temperature affects the speed of sound.
The image shows the relationship between temperature and speed of sound in air. The x-axis of the graph shows the temperature in degrees Celsius, and the y-axis shows the speed of sound in meters per second. The line on the graph shows that the speed of sound increases with temperature. For every 1 degree Celsius increase in temperature, the speed of sound increases by about 0.6 m/s.
The speed of sound in air is also affected by other factors, such as humidity and air pressure. However, temperature is the most important factor affecting the speed of sound.
The speed of sound at the lowest temperature in the image is 330.4 m/s, which is at -1°C.
The speed of sound at the highest temperature in the image is 358.0 m/s, which is at 45°C.
The temperature at which the speed of sound is slowest is -1°C.
The temperature at which the speed of sound is fastest is 45°C.
Yes, temperature affects the speed of sound. The speed of sound increases with temperature. This is because the molecules of a medium vibrate faster at higher temperatures, and this allows sound waves to travel more quickly.
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Question 3
Kennedy is planning an investigation into the transformation between Kinetic and potential energy using objects she found around her house
The object that is best used to study the transformation between kinetic and potential energy is the clock because it has a pendulum.
A pendulum can be used to study the conversion of kinetic energy to potential energy. As the pendulum swings from side to side energy is converted from potential energy to kinetic energy and back to potential energy.
The potential energy is minimum and the kinetic energy is maximum at the middle of the pendulum. At both ends of the pendulum, the potential energy of the system is maximum.
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1) how can you show that atmospheric exerts pressure?
2) how do you measure the volume of an irregular solid ? explain an experiment with diagram.
Answer:
1. While boiling replace the cap and allow it to cool. Vapours inside condense and form water creating vacuum above them. Observation - The can crumbles due to air pressure from outside. This proves that air exerts pressure.
2. Measure the volume of the liquid displaced when the object is submerged. Measure the initial volume of water in graduated cylinder. Submerge the irregular object. Measure the final volume of the water.
— The difference between the initial volume and the final volume is the volume of the object.
hope can help ^_^
Why is the oort cloud important for understanding the formation of the solar system?
The Oort cloud is the proximate source of observed nearly parabolic, so-called 'new' comets entering the planetary region, and is also the presumed source of the long-period comet flux and the majority of Halley-type comets (HTCs).
The oort cloud is important for understanding the formation of the solar system.
What is oort cloud?It is believed to be an important source of comets that can provide valuable information about the conditions and processes that were present in the early solar system.
Here,
The Oort Cloud is important for understanding the formation of the solar system because it is believed to be a reservoir of icy bodies that formed early in the solar system's history. These icy bodies, which include comets, are thought to have played a key role in the early evolution of the solar system by delivering water and other volatile materials to the inner solar system, including the early Earth.
By studying the composition and properties of comets from the Oort Cloud, scientists can gain insights into the formation and evolution of the solar system and learn more about the conditions that were present in the early solar system.
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