Circle A is located at (6, 5) and has a radius of 4 units. What is the equation of a line that is tangent to circle A from point C (2, 8)? x = 2 y = −0. 75x + 9. 5 y = 1. 33x + 1. 66 x = 8

The two true statements are:

A "When the time starts, there are 13.5 gallons of water in the pool."

C "The water is draining at a rate of 1.25 gallons per minute."

Here we have the linaer equation y = –1.25x + 13.5 that represents the gallons of water y left in an inflatable pool after x minutes.

And we want to see which of the given statements are true.

We can see that the slope is -1.25, this means that the volume of water is reducing (due to the negative sign) then the statement C is true.

We also can see that the y-intercept is 13.5, that would be the initial volume of water in the pool, then the statement A "When the time starts, there are 13.5 gallons of water in the pool." is also true.

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The word sentence for the given number line represents the X is greater than zero. The inequality is the X is not less than or equal to zero.

In the given number line the values are from negative infinity to positive infinity. Though the number line is having all values, there is some part that is shaded only on certain parts of the number line. The part is from number 1 to positive infinity marking zero as a circle.

The circle represents the value starts counting from the next step. In the given number line circle is shaded at number zero and the value started from the next value which is number 1 onwards to positive infinity.

So, the given number line represents X is greater than zero and X is not less than or equal to zero.

In mathematical words,

X < 0 and X≠0

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Given question is not having enough information to solve, for better understanding attaching the number line image below.

You can drive at most 700 miles within the $180 budget for weekly transportation.

To determine how many miles can be driven with a budget of $180 for weekly transportation, we'll use the given information: $75 per week for car rental and $0.15 per mile driven. First, subtract the weekly rental cost from the total budget:

$180 - $75 = $105

Now, divide the remaining budget by the cost per mile to find the maximum number of miles that can be driven:

$105 ÷ $0.15 ≈ 700 miles

So, you can drive at most 700 miles within the $180 budget for weekly transportation.

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The ratio of the perimeters is 14/5, which simplifies to 70/25, which reduces to 14/5. So the answer is (d) 5/7.

Let's use the fact that the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding side lengths. If we let the corresponding side lengths be a and b, then we have:

(area of first triangle)/(area of second triangle) = (a^2)/(b^2)

We are given that the areas of the two triangles are 50 cm^2 and 98 cm^2, respectively. Let's call the side lengths of the first triangle a1, a2, and a3, and the side lengths of the second triangle b1, b2, and b3. Then we have:

(50)/(98) = (a1a2)/(b1b2)

We don't know the actual values of a1, a2, b1, and b2, but we can find the ratio of their perimeters by adding up the side lengths of each triangle. Let's call the perimeters of the first and second triangles P1 and P2, respectively. Then we have:

P1 = a1 + a2 + a3

P2 = b1 + b2 + b3

Dividing P1 by P2, we get:

P1/P2 = (a1 + a2 + a3)/(b1 + b2 + b3)

We can rewrite the ratios of the side lengths using the equation we found earlier:

P1/P2 = [(a1a2)/(b1b2)]*[(a1 + a2 + a3)/(a1 + a2 + a3)]

P1/P2 = [(a1a2)/(b1b2)]*1

P1/P2 = (a1a2)/(b1b2)

We still don't know the values of a1, a2, b1, and b2, but we can eliminate them by using the equation we found earlier:

(50)/(98) = (a1a2)/(b1b2)

Simplifying this expression, we get:

(a1/a2) = sqrt((98/50)*(b1/b2))

We can use this to substitute for one of the ratios of side lengths in the equation for P1/P2:

P1/P2 = [(a1a2)/(b1b2)]*[(a1 + a2 + a3)/(a1 + a2 + a3)]

P1/P2 = [sqrt((98/50)(b1/b2))][(a1 + a2 + a3)/(a1 + a2 + a3)]

P1/P2 = sqrt((98/50)*(b1/b2))

Now we can substitute the given values to get:

P1/P2 = sqrt((98/50)(b1/b2)) = sqrt((98/50)(2/1)) = sqrt(196/50) = 14/5

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Answer:

It is not true since 9x - 3x = 6x and

3x(3) = 9x.

Answer:

Not true b/c

Step-by-step explanation:

9x-3x=6x

and3x(3)=9x

6x is not equal to 9x

The length of the rectangle is 8 feet given it is 7 feet wide and has an area of 56 square feet.

A rectangle is a geometric figure with four straight sides and four right angles, where the opposite sides are parallel and equal in length. In this case, we are given that the rectangle has a width of 7 feet and an area of 56 square feet. The area of a rectangle is calculated by multiplying its length (L) and width (W), expressed as A = L × W.

We are provided with the width, W = 7 feet, and the area, A = 56 square feet. To find the length of the rectangle, we can rearrange the area formula:

L = A ÷ W

Substituting the given values, we have:

L = 56 ÷ 7

L = 8 feet

Hence, the length of the rectangle is 8 feet. To summarize, a rectangle with a width of 7 feet and an area of 56 square feet has a length of 8 feet. The dimensions of the rectangle are 7 feet by 8 feet.

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Answer:

In this pattern, there are 12 regular pentagons and 20 regular hexagons. Each hexagon shares a vertex with three pentagons and each pentagon shares a vertex with five hexagons.

To find the measure of each gap between the hexagons, we can use the fact that the sum of the angles around any vertex in a regular polygon is always 360 degrees. Let x be the measure of the angle between two adjacent pentagons, and y be the measure of each angle at the center of a hexagon.

At each vertex of the pattern, there are three pentagons and three hexagons meeting. Thus, we have:

3(108) + 3y = 360

Simplifying, we get:

324 + 3y = 360

3y = 36

y = 12

Therefore, each angle at the center of a hexagon measures 12 degrees. Since there are six angles around the center of a hexagon, the total angle around the center of a hexagon is 6(12) = 72 degrees.

To find the measure of each gap between the hexagons, we need to subtract the angle of the hexagon from 180 degrees (since the sum of the angles of a triangle is 180 degrees). Thus, the measure of each gap between the hexagons is:

180 - 72 = 108 degrees

Step-by-step explanation:

The total number of zeros in the mass of the sun when written in standard notation is 30, which is option B.

When we write the number in standard notation, we move the decimal point to the left or right to express the number in terms of powers of 10. In this case, we can write the mass of the sun as:

1.9891 x 10^30

To count the number of zeros in this number, we only need to count the number of digits to the right of the decimal point, which is zero in this case. Then we add the exponent, which tells us the number of places we need to move the decimal point to the right to express the number in standard notation. In this case, the exponent is 30, so we need to move the decimal point 30 places to the right, which means adding 30 zeros.

Therefore, the total number of zeros in the mass of the sun when written in standard notation is 30, which is option B.

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Answer:

4.28

Step-by-step explanation:

To find what the length of AC is, we can use the tangent of angle A, which is 35°.  Here's the equation:

tan(35)=3/x

multiply both sides by x

x·tan(35)=3

divide both sides by the tangent of 35

x=4.28 (rounded to the nearest hundredth)

This means that AC=4.28

Hope this helps! :)

Answer:

Step-by-step explanation:

True

a) The distance the ball rebounds on the fifth bounce is approximately 7.59 ft.

b) The total distance the ball has traveled after the fifth bounce is approximately 52.61 ft.

Let's denote the height of the ball after its nth bounce by h_n. Then we can express the relationship between the height of the ball after each bounce in terms of a recursive formula:

h_0 = 16 (initial height)

h_1 = (3/4) * h_0 (rebound distance after the first fall)

h_2 = (3/4) * h_1 (rebound distance after the second fall)

h_3 = (3/4) * h_2 (rebound distance after the third fall)

h_4 = (3/4) * h_3 (rebound distance after the fourth fall)

h_5 = (3/4) * h_4 (rebound distance after the fifth fall)

a) To find the distance the ball rebounds on the fifth bounce, we need to calculate h_5:

h_5 = (3/4) * h_4

= (3/4) * ((3/4) * ((3/4) * ((3/4) * 16)))

= (3/4)^5 * 16

= 7.59375 ft

Therefore, the ball rebounds approximately 7.59 ft on the fifth bounce.

b) To find the total distance the ball has traveled after the fifth bounce, we need to add up all of the distances traveled during the falls and rebounds:

total distance = distance of first fall + rebound distance after first fall + rebound distance after second fall + rebound distance after third fall + rebound distance after fourth fall + rebound distance after fifth fall

total distance = 16 + (3/4) * 16 + (3/4)^2 * 16 + (3/4)^3 * 16 + (3/4)^4 * 16 + (3/4)^5 * 16

total distance = 16 + 12 + 9 + 6.75 + 5.0625 + 3.7969

total distance = 52.6094 ft

Therefore, the ball travels approximately 52.61 ft after the fifth bounce.

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Full Question:

Although part of your question is missing, you might be referring to this full question:

Be sure to show and explain all work using mathematical formulas and terminology. A bouncy ball is dropped from a height of 16ft and always rebounds ¼ of the distance of the previous fall.

a) What distance does it rebound the 5th time?

b) What is the total distance the ball has travelled after this time?

If the base of the roof is 32 feet long, then the area of the triangular roof is 256 square feet.

In the given scenario, we are provided with information about a triangular roof. It is mentioned that the base of the roof is 32 feet long, and we need to determine the area of the triangular roof.

To calculate the area of a triangle, we need to know the length of the base and the height. In this case, we are given that the height is half the length of the base, which can be expressed as h = (1/2) * b.

Since we are given that the base length, b, is 32 feet, we can substitute this value into the height equation to find the height of the triangle: h = (1/2) * 32 feet = 16 feet.

Now that we have the base length (b = 32 feet) and the height (h = 16 feet), we can use the formula for the area of a triangle: A = (1/2) * b * h.

Substituting the values, we have A = (1/2) * 32 feet * 16 feet = 256 square feet.

Therefore, the area of the triangular roof is determined to be 256 square feet. This represents the amount of surface area covered by the triangular section of the roof.

Let the base of the triangular roof be denoted by b, and its height be denoted by h. We are given that

h = (1/2) * b, and that

b = 32 feet.

We can use this information to find the area A of the roof as follows:

A = (1/2) * b * h

 = (1/2) * 32 feet * (1/2) * 32 feet

 = 256 square feet

Therefore, the area of the triangular roof is 256 square feet.

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The value of the quantity after 51 years, rounded to the nearest hundredth, is 499.92.

Since a decade is a period of 10 years, a decay rate of 5% per decade can be converted to a continuous decay rate as follows:

Continuous decay rate = (1 + decay rate per decade[tex])^{(1/10)[/tex] - 1

In this case, the decay rate per decade is 5%, which can be expressed as 0.05.

Continuous decay rate = (1 + 0.05[tex])^{(1/10)[/tex] - 1

Continuous decay rate ≈ 0.0048767

Now we can use the formula for continuous decay:

A = A0[tex]e^{rt[/tex]

In this case, the initial value A0 is 390, the continuous decay rate r is 0.0048767, and the time elapsed t is 51 years.

Substituting these values into the formula, we have:

A = 390 [tex]e^{(0.0048767)( 51)[/tex]

A ≈ 499.9202826

Therefore, the value of the quantity after 51 years, rounded to the nearest hundredth, is 499.92.

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The final temperature after the next 8 hours (6 hours at -0.8°C per hour, followed by 2 hours at -0.8°C per hour) will be -2.4°C.

The final temperature can be calculated by subtracting the total temperature change from the initial temperature of 4°C.

The total temperature change during the next six hours can be calculated by multiplying the mean rate of -0.8°C per hour by the number of hours, which is 6.

-0.8°C/hour x 6 hours = -4.8°C

Therefore, the temperature after the next six hours will be:

4°C - 4.8°C = -0.8°C

For the next two hours, the temperature changed at a mean rate of -0.8°C per hour. This means the temperature decreased by:

-0.8°C/hour x 2 hours = -1.6°C

So the final temperature will be:

-0.8°C - 1.6°C = -2.4°C.

Therefore, the final temperature after the next 8 hours (6 hours at -0.8°C per hour, followed by 2 hours at -0.8°C per hour) will be -2.4°C.

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If a man bought a diamond for $32 in 1682 and the man had instead put the $32 in the bank at 3% interest compounded continuously, then the value of the diamond in 2003 would be $554,311.

The given problem is related to exponential growth. In this problem, the continuous compounding formula will be used to find the value of $32 in 2003.

The formula for continuous compounding is given by:

A = Pert   Where,

P is the principal amount,

r is the annual interest rate,

e is the Euler's number which is approximately 2.71828, and

t is the time in years.

Using the formula, we get:

A = 32e^(0.03 x 321)

A = 32e^9.63

A = 32 x 17322.23

A = $ 554311.36

Thus, $32 invested at 3% compounded continuously from 1682 to 2003 would be worth $554,311.

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10 stereos must the salesperson sell to make that same amount of money under both plans.

Assume that in order for the salesperson to earn the same amount of money under both schemes, x stereos must be sold.

The salesperson will be paid a salary of $250 + $25 for each stereo sold under the first strategy. So, these are the total earnings:

First plan's total profits are $250 plus $25.

Instead of receiving a salary under the second proposal, the salesperson would be compensated with a $50 commission for each stereo sold. So, these are the total earnings:

Total income under the second plan equals $50x

We can set the two equations for total earnings to be equal in order to determine the value of x:

$250 + $25x = $50x

When we simplify the equation, we obtain:

$250 = $25x

x = 10

The sales person must thus sell 10 stereos in order to.

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Answer:

**Statement | True or False**

---|---

**1. The higher the percentile rank of a score, the greater the percent of scores above that score.** | True

**2. A mark of 75% always has a percentile rank of 75.** | False. A mark of 75% could have a percentile rank of 75 if it is the median score. However, it could also have a percentile rank of 60, 65, 80, or any other percentile rank, depending on the distribution of scores.

**3. A mark of 75% might have a percentile rank of 75.** | True. See above.

**4. It is possible to have a mark of 95% and a percentile rank of 40.** | True. For example, if there are 100 students in a class, and 95 of them get 100% on a test, then the student who gets 95% will have a percentile rank of 40.

**5. The higher the percentile rank, the better that score is compared to other scores.** | True. A higher percentile rank indicates that a score is better than more of the other scores.

**6.A percentile rank of 80, indicates that 80% of the scores are above that score.** | False. A percentile rank of 80 indicates that 80% of the scores are **at or below** that score.

**7. PR50 is the median.** | True. The median is the middle score in a distribution. By definition, half of the scores will be at or below the median, and half of the scores will be at or above the median. Therefore, the percentile rank of the median is 50.

**8. Two equal scores will have the same percentile rank.** | True. Two equal scores will always have the same percentile rank.

Step-by-step explanation:

The expression |y-x| without absolute value is simply: y-x

In mathematics, the absolute value refers to the magnitude or numerical value of a real number without considering its sign. It gives the distance of the number from zero on the number line. The absolute value of a number x is denoted by |x| and is defined as follows:

If x is positive or zero, then |x| = x.

If x is negative, then |x| = -x (the negative sign is removed).

Since y > x, the difference (y-x) will be positive. The absolute value of a positive number is the number itself. Therefore, the expression |y-x| without absolute value is simply: y-x

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The function f(x) = (x + 6)/(2-6) does not have any critical values. A critical value of a function is a value of x where the derivative of the function is either zero or undefined.

However, in this case, the denominator of f(x) is a constant, so the derivative of f(x) is simply the derivative of the numerator divided by the constant denominator.

The derivative of the numerator is 1, so the derivative of f(x) is simply 1/(2-6) = -1/4. Since the derivative is a constant, it is never zero or undefined, and so there are no critical values for this function.Explanation: To find the critical values of a function, we need to find the values of x where the derivative of the function is either zero or undefined. However, in this case, the denominator of f(x) is a constant, so the derivative of f(x) is simply the derivative of the numerator divided by the constant denominator. The derivative of the numerator is 1, so the derivative of f(x) is simply 1/(2-6) = -1/4. Since the derivative is a constant, it is never zero or undefined, and so there are no critical values for this function. Therefore, the answer is None.

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given:  function f(x) = 2sin(x) + 3x + 3 ,Xo=1.5

1. Compute the derivative of the function, f'(x).
2. Use the iterative formula: Xₖ₊₁ = Xₖ - f(Xₖ) / f'(Xₖ)
3. Repeat the process 10 times.

First, let's find the derivative of f(x):
f'(x) = 2cos(x) + 3

Now, use the iterative formula to compute the iterations:

X₁ = X₀ - f(X₀) / f'(X₀)
X₂ = X₁ - f(X₁) / f'(X₁)
...
X₁₀ = X₉ - f(X₉) / f'(X₉)

Remember to not round any values until the final answer, and then round to six decimal places. Since I cannot actually compute the iterations, I encourage you to use a calculator or program to find the values for each Xₖ using the provided formula.

Answer:

there both symmetrical

Answer:

Congruent

Step-by-step explanation:

When visualizing how two angles are related, try squashing the two parallel lines into each other. When you do that with these angles, they go from appearing like =\= to appearing like -\-, with x and y being catty-corner from each other.

Because the parallel lines are straight, x and y are both half of a pair that adds up to 180. However, x and y aren't sharing a straight line, so they cannot add up to 180 with each other. That leaves only one possibility, that x and y have the same angle measure.

Answer: 2

Step-by-step explanation:

Answer:

[tex] \frac{dy}{dx} = \frac{4}{9} [/tex]

Step-by-step explanation:

sol,

2x+3y-6x+6y=0

f(x,y)=2x+3y-6x+6y

f(X,-y)=2x+3y-6y,fx=?

f(x-y)=2x+3y-6y,fy=?

fx=-4

fy=9

[tex] \frac{d}{y} = \frac{ - 4}{9} [/tex]

now,

[tex] \frac{dy}{dx} = \frac{4}{9} [/tex]

Answer:

70 dogs

Step-by-step explanation:

sum the parts of the ratio , 5 + 2 = 7 parts

divide total by 7 to find the value of one part of the ratio

98 ÷ 7 = 14 ← value of 1 part of the ratio , then

5 × 14 = 70 ← number of dogs

If password begin with capital letter followed by lower case letter, and end with symbol , then the number of unique passwords which can be created using letters and symbols are 47525504.

The password must have 6 characters and the first character must be a capital letter, so, we have 26 choices for the first character.

For the second character, we have 26 choices for a lower-case letter.

For the third, fourth, and fifth characters, we can choose from any of the 26 letters (upper or lower case).

For the last character, we have 4 choices for the symbol

So, total number of unique passwords that can be created is:

⇒ 26 × 26 × 26 × 26 × 26 × 4 = 26⁵ × 4 = 47525504.

Therefore, there are 47525504 unique passwords that can be created using these letters and symbols.

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Answer:

Yes, there is evidence at the 10% significance level, but not at the 5% level

Step-by-step explanation:

Look at the p-value in bottom left corner (in the Height row).

It is less than 0.1, but greater than 0.05. Thus, Yes, there is evidence at the 10% significance level, but not at the 5% level. Got it right.

The probability of Jeremy selecting a jelly bean that is not lemon or orange is: 26/48 = 0.54 or 54%.

To find the probability that Jeremy randomly selects a jelly bean that is not lemon or orange, we need to first find the total number of jelly beans that are not lemon or orange.

The number of grape jelly beans is 10, the number of cherry jelly beans is 16, so the total number of jelly beans that are not lemon or orange is:

10 + 16 = 26

The total number of jelly beans in the dish is:

10 + 8 + 14 + 16 = 48

Therefore, the probability of Jeremy selecting a jelly bean that is not lemon or orange is:

26/48 = 0.54 or 54%.

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In the circle, the measure of p is 34 (option 3).

First, we know that angle MBC is an exterior angle to triangle PBC. Therefore, the measure of angle PBC is equal to the sum of angles MBC and MCB, which is 100 + (1/2)(angle MCP) = 100 + (1/2)(angle MQP).

Similarly, angle MCD is an exterior angle to triangle PCD. Therefore, the measure of angle PDC is equal to the sum of angles MCD and MDC, which is 62 + (1/2)(angle MPQ) = 62 + (1/2)(angle MQP).

Since angle PBC and angle PDC are both subtended by the same arc BC, they are equal. Therefore, we can set the expressions for these angles equal to each other and solve for angle MQP:

100 + (1/2)(angle MQP) = 62 + (1/2)(angle MQP)

38 = (1/2)(angle MQP)

angle MQP = 76 degrees

Finally, we can use the fact that angles MPQ and MQP form a linear pair, so they add up to 180 degrees. Therefore, angle MPQ is 180 - 76 = 104 degrees.

Since angle MPQ is an exterior angle to triangle PAB, we can use the exterior angle theorem to find the measure of angle P, as follows:

angle P = angle MPQ + angle PAB = 104 + 100 = 204 degrees

However, angles in a circle cannot be greater than 180 degrees, so we need to subtract 180 from angle P to get the actual measure of angle P:

angle P = 214 - 180 = 34 degrees

Therefore, the answer is option (3).

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The distance along the inside edge of each lane is 170 yards, 180 yards,  190 yards,  200 yards,  210 yards, 220 yards, 230 yards, and 240 yards.

Length of the Beld = 100 yd

Width of the Beld = 50 yd

The radius of the lane = 50/2 = 25 yards

To calculate the length of the overall length of the lane including semicircles is:

100 yards + 2 × 25 yards = 150 yards

The length of the innermost lane is:

150 yards + 2 × 10 yards = 170 yards

To calculate the length of the other lanes is:

170 yards + 10 yards = 180 yards

The length of lane 3 is:

180 yards + 10 yards = 190 yards

The distance between the two lanes is 10 yards. Then the remaining lengths of the lanes will be 200 yards,  210 yards, 220 yards, 230 yards, and 240 yards

Therefore, we can conclude that the distance between the two lanes along the inside edge of each lane is 10 yards.

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The equation of the plane passing through the three points P, Q, and R is -29x + 50y - 23z = 229

To find the equation of the plane passing through the three points P, Q, and R, we need to first find two vectors in the plane. We can do this by subtracting P from Q and R to get:

Q - P = (3-1, 12-7, 12-4) = (2, 5, 8)
R - P = (8-1, 11-7, 7-4) = (7, 4, 3)

Next, we can take the cross product of these two vectors to get a vector that is perpendicular to the plane:

(2, 5, 8) x (7, 4, 3) = (-29, 50, -23)

Now we have the equation of the plane in the form ax + by + cz = d, where (a, b, c) is the normal vector we just found and (x, y, z) is any point on the plane (we can use one of the three given points):

-29x + 50y - 23z = d  (equation of plane)

To find the value of d, we can substitute one of the points, say P:

-29(1) + 50(7) - 23(4) = d
-29 + 350 - 92 = d
d = 229

Therefore, the equation of the plane passing through the three points P, Q, and R is:

-29x + 50y - 23z = 229

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Therefore, the equivalent expression to [tex]9^2[/tex] is 81.

To solve an equation, you need to isolate the variable on one side of the equation, typically the left side, and simplify the other side until you are left with an expression that has only the variable you are trying to solve for.

Here are the general steps to solve an equation:

Start by simplifying both sides of the equation as much as possible. This may involve distributing or combining like terms.

Get all terms with the variable you are solving for on one side of the equation. To do this, you can add or subtract terms from both sides of the equation. For example, if you have the equation 2x + 5 = 9, you can subtract 5 from both sides to get 2x = 4.

Isolate the variable by dividing both sides of the equation by its coefficient. In the above example, you can divide both sides by 2 to get x = 2.

Check your solution by plugging it back into the original equation and verifying that both sides of the equation are equal.

[tex]a^m/a^n = a^{(m-n)}[/tex]

to simplify the expression.

The expression [tex]9^2[/tex] means 9 multiplied by itself 2 times:

[tex]9^2 = 9 * 9[/tex]

Using the laws of exponents, we can rewrite this expression as:

[tex]9^2 = 9^{(1+1)} (since 2 = 1 + 1)[/tex]

Then, using the rule that [tex]a^{(m+n)} = a^m * a^n[/tex], we have:

[tex]9^2 = 9^1 *9^1[/tex]

Finally, using the fact that. [tex]a^1 = a[/tex] for any value of a, we get:

We can use the rule of exponents that states:

[tex]9^2 = 9 * 9 = 81[/tex]

Therefore, the equivalent expression to [tex]9^2[/tex] is 81

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