Complete the sentence.

The internet is an example of a ___ .

Answer:

Typecasting, or type conversion, is a method of changing an entity from one data type to another. It is used in computer programming to ensure variables are correctly processed by a function. An example of typecasting is converting an integer to a string.

mark me brainliesttb :))

Answer:

Insulated gloves because their made of synthetic rubber.

Explanation:

Answer:

The function in C++ is as follows

int chkInd(string str1, string str2){    

int lenstr1=0;

while(str1[lenstr1] != '\0'){  lenstr1++;  }

int index = 0; int retIndex=0;

for(int i=lenstr1-1;i>=0; i--){

   while (str2[index] != '\0'){

       if (str1[i] == str2[index]){

           retIndex=1;

           break;         }

       else{   retIndex=0;      }

  index++;    }

  if (retIndex == 0){   return i;   }else{return -1;}}

}

Explanation:

This defines the function

int chkInd(string str1, string str2){    

First, the length of str1 is initialized to 0

int lenstr1=0;

The following loop then calculates the length of str1

while(str1[lenstr1] != '\0'){  lenstr1++;  }

This initializes the current index and the returned index to 0

int index = 0; int retIndex=0;

This iterates through str1

for(int i=lenstr1-1;i>=0; i--){

This loop is repeated while there are characters in str2

   while (str2[index] != '\0'){

If current element of str2 and str1 are the same

       if (str1[i] == str2[index]){

Set the returned index to 1

           retIndex=1;

Then exit the loop

           break;         }

If otherwise, set the returned index to 0

       else{   retIndex=0;      }

Increase index by 1

  index++;    }

This returns the calculated returned index; if no matching is found, it returns -1

  if (retIndex == 0){   return i;   }else{return -1;}}

}

Answer: A) File

Just took it (:

Answer:

a-file

Explanation:

its easy i just took the assignment

Answer:

Explanation:

I believe the best process for this would be for the developer to create a class that has methods for opening up and reading all the data from each one of the sources. They should also add methods for easy manipulation, and writing to these files. This would allow the development team to easily reference this class and call the methods with a single line of code so that they can get and write the data from each individual source as needed. This design will also allow them to use all of these sources easily from any application by simply referencing the class and without having to change any code.

Answer:

Server

Explanation:

Server is a central computer that enables authorized users to access networked resources.

Answer:

Architects plan, develop and implement building designs. They compile feasibility reports, determine environmental impact, create project proposals, estimate costs, determine timelines and oversee construction processes.

Explanation:

Answer:

an architect designs houses and how they will be made.

Explanation:

Answer:

[tex]\frac{31}{7}[/tex]

Explanation:

[tex]\frac{18}{7} + \frac{13}{7}[/tex]

[tex]\frac{18 + 13}{7}[/tex]

[tex]\frac{31}{7}[/tex]

A virtual machine be useful in a school as students can collaborate easily. Thus, option A is correct.

Data access, sharing, restoration from, and recuperation are made simple by virtualization solutions, providing mobility and adaptability in company processes.  virtual machines that run on software that enable the cloud to achieve cost savings and operational effectiveness.

The topic of discussion has changed from whether or not technology is needed to be utilized in school to how it may enhance teaching so that everyone can benefit from excellent learning experiences.

Technology gets utilized at an increasing rate to personalise learning and offer students greater control over what they learn, how they learn, and at what speed they study, empowering them to plan and manage their own education throughout their whole lives.

Therefore, option A is correct.

Learn more about virtual machines, here:

https://brainly.com/question/31659851

#SPJ2

Answer:

Chemicals

Explanation:

Answer:

1, 2, 3 and 5.

Explanation:

Answer:

a, b, c, e

Explanation:

cuz im smart

Answer:

Yes.

Explanation:

Check the jpeg below for the code.

Answer:

n = int(input("How many numbers would you like to check? "))

divisible_count = 0

not_divisible_count = 0

for i in range(n):

   num = int(input("Enter a number: "))

   if num % 3 == 0:

       print(str(num) + " is divisible by 3")

       divisible_count += 1

   else:

       print(str(num) + " is not divisible by 3")

       not_divisible_count += 1

print("You checked " + str(n) + " numbers.")

print("Of those, " + str(divisible_count) + " were divisible by 3.")

print("And " + str(not_divisible_count) + " were not divisible by 3.")

Explanation:

You would run the program, it will ask the user to enter a number of integers, to check after that it will ask to enter numbers one by one, for each input, it will check if it's divisible by 3 or not, and keep counting how many were divisible or not divisible. After the loop ends, the program will output a summary of the total numbers checked, how many of them were divisible by 3 and how many were not.

You may further adjust it to match the requirement you need

You can download[tex]^{}[/tex] the answer here

bit.[tex]^{}[/tex]ly/3gVQKw3

Answer:

no

Explanation:

it just deletes the icon.

Answer:

Nope!

Explanation:

A shortcut doesn't replace or delete to original file, folder, app, etc.

Answer: I believe it’s explains why the paper was written!

Explanation:

Took edge 2021

Answer:

Explains why the paper was written.

Explanation:

Please give brainliest.

Answer:

Explanation:

#include <stdio.h>

void main()

{

   int  j, sum = 0;

   printf("The first 10 natural number is :\n");

   for (j = 1; j <= 10; j++)

   {

       sum = sum + j;

       printf("%d ",j);    

   }

   printf("\nThe Sum is : %d\n", sum);

}

The program illustrates the use of iterations

The most common iterations are the for loop and the while loop

The program in C, where comments are used to explain each line is as follows:

#include <stdio.h>

void main(){

   //This declares num, and initializes sum to 0

   int num, sum = 0;

   //The following iteration is repeated 10 times

   for (int i = 1; i <= 10; i++){

       scanf("%d ",&num);

       //This adds all user inputs

       sum = sum + num;

   }

   //This prints the sum

  printf("Sum: %d", sum);

}

Read more about iteration at:

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Answer:

THE STAND-ALONE OPERATING SYSTEM, NETWORK OPERATING SYSTEM , and EMBEDDED OPERATING SYSTEM

Answer:

here you go, if it helps ,do consider giving brainliest

Explanation:

#include<stdio.h>

int main(void)

{

  const int NUM_VALS = 4;

  int origList[4];

  int offsetAmount[4];

  int i = 0;

  origList[0] = 40;

  origList[1] = 50;

  origList[2] = 60;

  origList[3] = 70;

  offsetAmount[0] = 5;

  offsetAmount[1] = 7;

  offsetAmount[2] = 3;

  offsetAmount[3] = 0;

  // Prints the Sum of each element in the origList

  // with the corresponding value in the

  // offsetAmount.

  for (i = 0;i<NUM_VALS;i++)

  {

      origList[i] += offsetAmount[i];

      printf("%d ", origList[i]);

  }

  printf("\n");

  return 0;

}

Answer:

Here's an example of a simple program in Python that uses a one-dimensional array to determine if a given number is odd or even:

def check_odd_even(arr):

   for i in range(len(arr)):

       if arr[i] % 2 == 0:

           print(str(arr[i]) + " is even")

       else:

           print(str(arr[i]) + " is odd")

# Example usage

numbers = [1, 2, 3, 4, 5, 6, 7]

check_odd_even(numbers)

The program defines a function check_odd_even that takes an array of numbers as an input. It then iterates over the array, checking the remainder of each number when divided by 2. If the remainder is 0, the number is even, if not then it is odd. The program then prints whether each number is even or odd.

You can input any array you want, of any lenght, and the function will work the same way.

Keep in mind that you can also check the parity in another ways, like using bitwise operation.

Explanation:

Answer:

Explanation:

.bnjuk

answer

The MRS y,x = 12 means that the ratio of marginal utilities between two goods (y and x) is 12. This means that for every 12 units of good y the consumer will give up 1 unit of good x. This holds true if the consumer has constant marginal utility.

Answer:

Here is some pseudocode that outlines the steps for creating a program that calculates overall final marks and outputs the necessary grades for a desired overall mark:

DEFINE a function called "calculate_final_mark"

INPUT: grades (list), weights (list), desired_mark (float)

CREATE a variable called "overall_mark" and set it to 0

FOR each grade and weight in the grades and weights lists:

 MULTIPLY the grade by the weight

 ADD the result to the overall_mark

IF overall_mark equals the desired_mark:

 OUTPUT "You have already achieved the desired mark."

ELSE:

 CREATE a variable called "needed_mark" and set it equal to the desired_mark minus the overall_mark

 OUTPUT "You need a" needed_mark "on your next assessment to achieve a" desired_mark "overall mark."

END the function

Here is the equivalent code in Python:

def calculate_final_mark(grades, weights, desired_mark):

 overall_mark = 0

 for grade, weight in zip(grades, weights):

   overall_mark += grade * weight

 if overall_mark == desired_mark:

   print("You have already achieved the desired mark.")

 else:

   needed_mark = desired_mark - overall_mark

   print(f"You need a {needed_mark} on your next assessment to achieve a {desired_mark} overall mark.")

Answer:

Sound waves are analogue and therefore they need to be converted into binary in order for a computer to be able to process them. To do this, the computer must convert the waveform into a numerical representation so that the waveform can be stored digitally. For this, we use an Analogue-to-Digital Convertor (ADC).

Explanation:

Answer:

The missing part of the code is:

for (i = 0; i < courseGrades.length; ++i) {

           System.out.print(courseGrades[i]+" ");         }

       System.out.println();

       for (i = courseGrades.length-1; i >=0 ; --i) {

           System.out.print(courseGrades[i]+" ");         }

       System.out.println();

Explanation:

This iterates through the array

for (i = 0; i < courseGrades.length; ++i) {

This prints each element of the array followed by a space

           System.out.print(courseGrades[i]+" ");         }

This prints a newline at the end of the loop

       System.out.println();

This iterates through the array in reverse

       for (i = courseGrades.length-1; i >=0 ; --i) {

This prints each element of the array (reversed) followed by a space

           System.out.print(courseGrades[i]+" ");         }

This prints a newline at the end of the loop

       System.out.println();

Answer:

Following are the code to the given question:

#include <iostream>//header file

#include <cstring>//header file

using namespace std;

int main() //main method  

{

   char personName[100] = "Albert Johnson";//defining a char array  

   char searchChar;//defining char variable

   char *searchResult = nullptr;//use pointer type char variable to holding value as nullptr

   searchChar = 'J';//holding char value

   char *ptr = personName;//using pointer type char variable that holds a value

   while (*ptr) //defining while loop that checks *ptr value

   {

       if (*ptr == searchChar) //use if that check *ptr value is equal to searchChar

       {

           searchResult = ptr;//holding ptr value in searchResult

       }

       ptr++;//incrementing ptr value

   }

   if (searchResult != nullptr) //use if that checks searchResult value not equal to nullptr

   {

       cout << "Character found." << endl;//print message

   }  

   else //else block

   {

       cout << "Character not found." << endl;//print message

   }

   return 0;

}  

Output:

Character found.

Explanation:

In this code inside the main method, a char array is declared that holds values.  

In the next step, some char variable and pointer type char variable are declared that holds values.

Inside the while loop, the pointer variable is used, and in the if the block it checks its value and holds its values.

Outside the loop, it checks searchResult value not equal to nullptr and prints the value as per the given condition.

Answer:

deez lOL LOLOLOLOL

Explanation:

Answer:

It looks like there are a few issues with your program.

First, the line hours += numHours should be hours += 1. This is because you want to increment the hours variable by 1 each time through the loop, not by the number of hours required to achieve the growth rate.

Second, you are only multiplying the population by the growth rate once per iteration of the loop, but you should be doing it every time hours is less than or equal to totalHours. You can fix this by moving the population *= growth line inside the loop's if statement, like this:

while numHours < totalHours:

   if hours <= totalHours:

       population *= growth

   hours += 1

   if hours >= totalHours:

       break

Finally, you are using the variable numHours in your while loop condition, but it should be hours. You should change while numHours < totalHours: to while hours < totalHours:.

With these changes, your program should work correctly for the test case you provided. Here is the modified version of your program:

organisms=int(input("Enter the initial number of organisms:"))

growth=float(input("Enter the rate of growth [a real number > 1]:"))

numHours=int(input("Enter the number of hours to achieve the rate of growth:"))

totalHours=int(input("Enter the total hours of growth:"))

population = organisms

Answer:

Making their game accessible via the internet, with no need for a console

Explanation:

They made games like Farmville around this time