Convert.
970 milligrams = centigrams

Option A includes values within the range (6 and 53), so it is suitable. However, it includes decimal values which might not be necessary for this dataset.

What is scatter graph?

A scatter graph, also known as a scatter plot or scatter chart, is a type of graph used to display the relationship between two variables. The graph consists of a set of points that are placed on a coordinate plane, with one variable represented on the horizontal (x) axis and the other variable represented on the vertical (y) axis. Each point on the graph represents a pair of corresponding values for the two variables.

According to the question:

To choose the suitable options for the Length axis, we need to consider the range of values in the dataset. The minimum value for the Length variable is 6, and the maximum value is 53. Therefore, any options that do not include values within this range would not be suitable for the Length axis.

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Answer:

Yes, the geometric distribution is appropriate.

Step-by-step explanation:

Answer:

2 real solutions

Step-by-step explanation:

Currently, this quadratic equation is in standard form, which is:

[tex]ax^2+bx+c=0[/tex]

We can find the number of real solutions using the discriminant from the quadratic equation which is:

[tex]b^2-4ac[/tex]

When b^2 - 4ac > 0, there are 2 real solutions

When b^2 - 4ac = 0, there is 1 real solution

When b^2 - 4ac < 0, there are 0 real solutions

In the example, our a value is 5, our b value is 8 and our c value is -1:

[tex]8^2-4(5)(-1)\\64-20=44[/tex]

44 > 0, so there are 2 real solutions

Answer:

we can see that the second option, 21 oz for $3.50, has the better value because it costs less per ounce compared to the first option.

Step-by-step explanation:

To calculate the unit rate for each option, we divide the price by the amount of ounces:

For 17 oz for $2.98:

Unit Rate = $2.98 ÷ 17 oz

Unit Rate = $0.175 oz^-1 (rounded to three decimal places)

For 21 oz for $3.50:

Unit Rate = $3.50 ÷ 21 oz

Unit Rate = $0.167 oz^-1 (rounded to three decimal places)

Comparing the two unit rates, we can see that the second option, 21 oz for $3.50, has the better value because it costs less per ounce compared to the first option.

Thus, the cost would be $60 + $56 = $116 for a group of two persons and $60 + $52 + $52 = $164 for a party of three for number n.

The pricing structure for the tour company is based on a base price of $60 per person, which is then discounted by $4 for each additional person up to a maximum of 8 people. This means that for a group of 2 people, the price would be $60 + $56 = $116, while for a group of 3 people, the price would be $60 + $52 + $52 = $164.

The pricing structure incentivizes larger groups to go on the tour, as they can benefit from the discounted price per person. However, the discount stops at 8 people, which means that larger groups do not receive any further discounts. This is likely because the tour company may have a limit on the number of people they can accommodate on a single tour.

It is important for customers to be aware of the pricing structure when considering booking a tour with the company. They should also consider the benefits and drawbacks of going with a larger group versus a smaller one, such as the potential for a more personalized experience with a smaller group versus a more social experience with a larger group. Overall, the pricing structure is designed to be fair and encourage group bookings, while also accommodating the needs of the tour company.

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Therefore, it will cost $1.42 to mail a package that weighs 6.8 ounces.

To mail a package that weighs 6.8 ounces, the amount it will cost can be calculated using the given information. The post office charges $0.55 to mail a standard-sized item that weighs an ounce or less, and the charge for each additional ounce (up to 13 ounces), or fraction of an ounce, of weight is $0.15.

Therefore, to mail a package that weighs 6.8 ounces, we can use the following formula:
Cost = $0.55 + (Number of additional ounces) x $0.15

We need to find the cost of mailing a package that weighs 6.8 ounces. We know that the first ounce costs $0.55, and the package weighs 6.8 ounces. Therefore, the number of additional ounces is:
6.8 - 1 = 5.8

We also know that the cost for each additional ounce is $0.15. Therefore, the cost of mailing a package that weighs 6.8 ounces can be calculated as:
Cost = $0.55 + (5.8) x $0.15
Cost = $0.55 + $0.87
Cost = $1.42
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The function of given situation is 30x + 40y = 240. The x and y- intercept of function is  (8, 0), (0, 6).

To represent this situation, we can use the following function:

f(x, y) = 30x + 40y

where x is the number of picks and y is the number of shovels.

Since the function represents the total amount spent by Jack, we can set it equal to the given amount:

30x + 40y = 240

To find the x-intercept, we can set y = 0 and solve for x:

30x + 40(0) = 240

30x = 240

x = 8

Therefore, the x-intercept is (8, 0), which means that if Jack buys 8 picks and no shovels, he will spend $240.

To find the y-intercept, we can set x = 0 and solve for y:

30(0) + 40y = 240

40y = 240

y = 6

Therefore, the y-intercept is (0, 6), which means that if Jack buys 6 shovels and no picks, he will spend $240.

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_____The given question is incomplete, the complete question is given below:

Jack brought x picks costing $30 each and y shovels costing $40 each. In all he spent 240 write the function to represent this situation. what are the x and y intercepts of function

Answer:

Step-by-step explanation:

You want the values of the variables j and k in the parallelogram with the halves of one diagonal labeled (3j) and (5j-9), and the halves of the other diagonal labeled (6k) and (k+10).

The diagonals of a parallelogram bisect each other. That means ...

  5j -9 = 3j   ⇒   2j = 9   ⇒   j = 4.5

  6k = k +10   ⇒   5k = 10   ⇒   k = 2

The values of j and k are 4.5 and 2, respectively.

If a ray QT bisects <RQS, then the measure of one  m ∠TQS = 23.5°

Bisector:

In geometry, bisector is the division of something into two equal or equal parts (of the same shape and size). This usually involves a bisector, also called the midline. The most commonly considered bisectors are the bisector (the line passing through the midpoint of a given line segment) and the angle bisector (the line passing through the vertex of the angle, the bisector equal to the angle ).

According to the Question:

Given :

a ray QT bisects <RQS

∠PQR and ∠RQS is a linear pair . It makes and angle 180 degree

m ∠PQR + m ∠RQS = 180

From the diagram,

m ∠PQR = 3x-5, and m ∠RQS= x+1

Substitute the expression and solve for x

     m ∠PQR + m ∠RQS = 180

⇒ 3x-5 + x+1 = 180

⇒ 4x -4 = 180

⇒ 4x = 184

⇒ x = 46

Now ,  

m ∠RQS = x +1

               = 46 +1

               = 47

Given  QT bisects <RQS. it means QT divides RQS equally

   m ∠TQS = m ∠RQS/2

⇒ m ∠TQS = 47/2

⇒ m ∠TQS = 23.5

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To calculate b, we can plug one of the points into the equation to solve for b. If we plug in (1,2) we get 2 = 1(1) + b, so b = 1. Therefore, the equation of the linear function is y = x + 1.

To find the equation of the linear function represented by the table, we can use the slope-intercept form of a linear equation, which is y = mx + b. To calculate m, we can take two points on the line and calculate the rise (y2 - y1) over the run (x2 - x1). In this case, we can take the points (1,2) and (3,4). The rise is 2 and the run is 2, so m = 1. To calculate b, we can plug one of the points into the equation to solve for b. If we plug in (1,2) we get 2 = 1(1) + b, so b = 1. Therefore, the equation of the linear function is y = x + 1.

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The correct options are:

The equation StartFraction 1 over 8 EndFraction (x + 16) = StartFraction 76 over 8 EndFraction represents the situation, where x is the food bill.

The solution x = 60 represents the total food bill.

What is the equivalent expression?

Equivalent expressions are expressions that work the same even though they look different. If two algebraic expressions are equivalent, then the two expressions have the same value when we plug in the same value for the variable.

Since there are 8 friends and they decided to split the bill and tip evenly among themselves, each friend pays an equal share of the total bill, which is the food bill plus the tip. Let x be the food bill.

Then the total bill is x + 16 (the food bill plus the tip), and each friend's share is StartFraction 1 over 8 EndFraction (x + 16).

So, we have the equation StartFraction 1 over 8 EndFraction (x + 16) = StartFraction 76 over 8 EndFraction, which represents the situation where the total bill is $76 and there are 8 friends. Solving for x, we get:

StartFraction 1 over 8 EndFraction (x + 16) = StartFraction 76 over 8 EndFraction

x + 16 = 76

x = 60

Therefore, the total food bill is $60, which is the solution to the equation.

Each friend's share of the food bill and tip is StartFraction 1 over 8 EndFraction (x + 16) = StartFraction 1 over 8 EndFraction (60 + 16) = $9.

The equation 8(x + 16) = 76 is not correct, as it assumes that the total bill is divided equally among 8 people without taking into account the food bill and the tip separately.

hence, The correct options are:

The equation StartFraction 1 over 8 EndFraction (x + 16) = StartFraction 76 over 8 EndFraction represents the situation, where x is the food bill.

The solution x = 60 represents the total food bill.

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The ratio of the area of the inscribed circle to the area of the square ABFE is π:2.

If AB is divided into four congruent segments, each of which is the diameter of a semicircle, then we can draw four semicircles such that each one has its diameter on AB and they all have the same radius. Let the radius of each semicircle is r.

Let's assume the radius of each semicircle to be "r" and AB to be equal to "4r" because AB is divided into four congruent segments. Let the center of the inscribed circle be "O". Draw radii from the center of the inscribed circle to the tangent points, and let the tangent points on the semicircles be "C" and "D", and the midpoint of AB be "M".

Since CM and DM are radii of semicircles, they each have a length of "2r". So, MC = MD = 2r. Additionally, since CMDO is a square (as opposite sides are parallel and equal in length), we have CM = MD = CO = DO = 2r.

By the Pythagorean theorem, we have MC² = MO² - OC². Substituting the values we have, we get:

(2r)² = MO² - (2r)²

4r² = MO² - 4r²

MO² = 8r²

The area of the inscribed circle can be calculated as πr², so substituting MO² = 8r², we get the area of the inscribed circle as 8πr².

The area of the square ABFE is (4r)² = 16r².

So, the ratio of the area of the inscribed circle to the area of the square ABFE is:

(8πr²) : (16r²) = π : 2

Therefore, the ratio of the area of the inscribed circle to the area of the square ABFE is π : 2.

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The complete question: AB is divided into four congruent segments, each of which is the diameter of a semicircle. If a circle is inscribed in the quadrilateral formed by connecting the endpoints of the semicircles, what is the ratio of the area of the inscribed circle to the area of the square ABFE?

The statement that is true about equations and expressions is that an example of an equation is because it shows that two expressions are equal.

While an example of an expression is because it is a mathematical phrase represented by numbers, a variable, and an operation.

An equation is a mathematical statement where two expressions are equal. It's important to note that an equation has an equals sign, so the left side of the equation is equal to the right side of the equation.

Expressions are combinations of numbers, symbols, and operators that represent a value. A symbol or letter that represents a value is a variable. It's important to note that an expression does not have an equals sign, so the value of the expression is not defined.Why is an example of an equation true?An equation can be written in the form x = y. The equals sign indicates that x and y are equal. This means that two expressions, x and y, are equal. Therefore, an equation shows that two expressions are equal.

An example of an equation is 3x + 4 = 10. This equation is an example of an equation because it shows that two expressions, 3x + 4 and 10, are equal. The left side of the equation (3x + 4) equals the right side of the equation (10). Therefore, this statement is true: "An example of an equation is because it shows that two expressions are equal."

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Changing  from rectangular to spherical coordinates is: (2, π/2,0)

Spherical Coordinates:

In mathematics, a spherical coordinate system is a coordinate system in three-dimensional space in which the position of a point is specified by three numbers: the radial distance of the point from a fixed origin, the polar angle measured at from a fixed zenith direction, and its Azimuth orthogonal projection on a reference plane passing through the origin and normal to the vertex, measured from a fixed reference direction on this plane.

According to the Question:

To change the coordinates from rectangular to spherical we have to use these formulae:

     [tex]A = \sqrt{x^{2} + y^{2} + z^{2} }[/tex]

And, ∅ = arctan (y/x)

θ = [tex]arccos = \frac{z}{\sqrt{x^{2} +y^{2} +z^{2} } }[/tex]

So, the given points is (0,-2,0)

     [tex]A = \sqrt{0^{2} + (-2)^{2} + 0^{2} }[/tex]

Or, A = √4

Or, A = 2

And, ∅ = arctan (2/0)

           =  arctan (∞) = π/2

    θ = [tex]arccos = \frac{0}{\sqrt{0^{2} +(-2)^{2} +0^{2} } }[/tex]

⇒ θ = [tex]arccos = \frac{0}{\sqrt{(-2)^{2} } }[/tex]

⇒ θ = arcos (0)

Therefore,

The point becomes: (2, π/2,0)

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There are 8208 different ways that the children can sit.

There are 8 children in total, so we first need to choose one of them to sit in the middle. This can be done in 8 ways.

Once the child in the middle has been chosen, the remaining 7 children can sit in a circle around them. There are (7-1)! = 6! = 720 ways to arrange 7 children in a circle. However, due to the condition that "two seatings are considered identical if the same child is in the middle in both and each child on the outside has the same child on his or her right in both seatings", we need to divide by 7 to account for the fact that there are 7 equivalent circular arrangements.

Therefore, the total number of different ways that the children can sit is:

8 x (6! / 7) = 8 x 720 / 7 = 8208

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It will take him 2[tex]\frac{1}{4}[/tex] hours to travel the entire distance between the two cities. The solution has been obtained by using the arithmetic operations.

What are arithmetic operations?

All real numbers are thought to be sufficiently described by the four basic operations, sometimes referred to as "arithmetic operations." The mathematical operations quotient, product, sum, and difference follow division, multiplication, addition, and subtraction.

It is given that a man traveled [tex]\frac{1}{3}[/tex] of the distance between 2 cities in [tex]\frac{3}{4}[/tex] of an hour.

So, using the multiplication, if he travels at the same rate, he will cover the entire distance in,

⇒ Time taken = [tex]\frac{3}{4}[/tex] * 3

⇒ Time taken = [tex]\frac{9}{4}[/tex]

⇒ Time taken = 2[tex]\frac{1}{4}[/tex] hours

Hence, it will take him 2[tex]\frac{1}{4}[/tex] hours to travel the entire distance between the two cities.

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Answer: Work out the problem. or input it in for check

The sum between angles a° and c° gives 300°.

Here we want to find the sum of the two angles a° and c°.

First, we can see that a is a plane angle, then:

a° = 180°

We also can see that c° plus the angle at its left which is 60° should be a plane angle, then we can write:

60° + c° = 180°

c° = 180° - 60°

c° = 120°

Now we know the values of c°  and a°, then the sum will give:

a° + c° = 120° + 180° = 300°

That is the answer.

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what is the question asking? independent and dependent?? if so h is independent and m is dependent. Explanation: Independent is the leader and dependent is the follower, in your question the amount of hours you work depend on the amount of money you make because say for example you can get paid $15 per hour and if you work for 2 days  you'll only gain $30 bucks that day. hopefully that makes sense!

If it's not asking for dependent and independent,  please reply to comment i'll be more than happy to help .

The possible rational zeros for [tex]$f(x) = 5x^3 + 7x^2 - 7x + 4$[/tex] are [tex]\pm 1, \pm 2, \pm 4, \pm \frac{1}{5}, \pm \frac{2}{5}, \pm \frac{4}{5}$.[/tex]

What is meant by rational zeros?

In algebra, rational zeros are possible values of the variable in a polynomial equation with rational coefficients, where the numerator and denominator of the value are integers that divide the constant term of the polynomial.

[tex]$f(x) = 5x^3 + 7x^2 - 7x + 4$[/tex]

To find the possible rational zeros, we need to look at the factors of the constant term and the factors of the leading coefficient.

The constant term is 4, so its factors are [tex]\pm 1, \pm 2, \pm 4$.[/tex]

The leading coefficient is 5, so its factors are [tex]\pm 1, \pm 5$.[/tex]

Now we can list all the possible rational zeros by taking all possible ratios of factors of the constant term over factors of the leading coefficient:

[tex]$$\pm 1, \pm 2, \pm 4, \pm \frac{1}{5}, \pm \frac{2}{5}, \pm \frac{4}{5}$$[/tex]

Therefore, the possible rational zeros for [tex]$f(x) = 5x^3 + 7x^2 - 7x + 4$[/tex] are [tex]\pm 1, \pm 2, \pm 4, \pm \frac{1}{5}, \pm \frac{2}{5}, \pm \frac{4}{5}$.[/tex]

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Answer:

2/12

Step-by-step explanation:

There is a 1/6 chance of rolling a 3 once because there are six sides and only one 3, double that ratio if your want the probability of rolling that same number twice in a row.

The flagpοle is apprοximately 5.88 feet tall.

The angle between an item abοve the hοrizοntal line οf sight and that line is knοwn as the angle οf elevatiοn.

This issue can be resοlved using trigοnοmetry. Let's denοte the flagpοle's height "h" Drawing a right triangle with the flagpοle as the vertical leg, the shadοw as the hοrizοntal leg, and the sun as the angle οppοsite the hypοtenuse is pοssible when the angle οf elevatiοn οf the sun is 32 degrees.

We knοw that the length οf the shadοw is 10 feet, sο that we can write:

tan(32 degrees) = h/10

Tο sοlve fοr "h," we can multiply bοth sides by 10 and simplify:

h = 10  tan(32 degrees)

h = 5.88 feet

Therefοre, the flagpοle is apprοximately 5.88 feet tall.

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The mean, median, mode, and range of times for the second week are

Mean: 13.857 hours

Median: 14 hours

Mode: 16 and 10 hours

Range: 8 hours

To find the mean, median, mode, and range for the second week, we first need to calculate the new set of values by adding 6 to each entry in the first week.

New set of values for the second week:

16 14 18 12 11 10 16

Mean

To find the mean, we add up all the values in the set and divide by the total number of values

Mean = (16 + 14 + 18 + 12 + 11 + 10 + 16) / 7

Mean = 97 / 7

Mean = 13.857

Therefore, the mean for the second week is 13.857 hours.

Median

To find the median, we need to arrange the values in ascending order:

10 11 12 14 16 16 18

The median is the middle value in the set. Since there are an odd number of values in the set, the median is the fourth value, which is 14.

Therefore, the median for the second week is 14 hours.

Mode

The mode is the value that appears most frequently in the set. In this case, there are two values that appear twice: 16 and 10. Therefore, the set has two modes.

Therefore, the mode for the second week is 16 and 10 hours.

Range

The range is the difference between the highest and lowest values in the set. In this case, the highest value is 18 and the lowest value is 10.

Therefore, the range for the second week is 18 - 10 = 8 hours.

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The given question is incomplete, the complete question is:

We are given set of entries in that the number of hours taken by a group of teammates spent in their first week of training is:

10            8            12             6             5            4              10

Now in the second week the each of the entry is increased by 6 so the data for the second week is given as:

16             14            18            12              11             10             16  . The table shows the number of hours that a group of teammates spent in their first week of training for the track finals. In the second week, they each add 6 hours to their training times. What are the mean ,median ,mode , and range of times for the second week?

Answer:

-12i - 64j

Step-by-step explanation:

Answer:

100

Step-by-step explanation:

100 unit fractions of 1/10 are in 100.

The number of unit fractions of 1/10 in 100 is 1000.

Fractions are numbers which are of the form a/b where a and b are real numbers. This implies that a parts of a number b.

Here, a is called the numerator and b is called the denominator.

Any number can be expressed as fractions.

We have to find how many 1/10 s are in the number 100.

In order to find it, we have to divide 100 by the fraction 1/10.

Divide 100 by 1/10.

100 / (1/10) = 100 × 10 = 1000

Hence the number of unit fractions in the number 100 is 1000.

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The solutions to the equation [tex]csc2(x) + 6 csc(x) − 7 = 0 are x = π/2, (2n+1)π/2, (2n+1)π + arcsec(-6)[/tex] and [tex](2n+1)π - arcsec(-6).[/tex]

The equation [tex]csc2(x) + 6 csc(x) − 7 = 0[/tex] can be rewritten as [tex]csc(x)(csc(x) + 6) − 7 = 0[/tex]. Factorizing the equation we have

Now, solving for csc(x) = 0, we have csc(x) = 0. This implies that x = π/2 or (2n+1)π/2, where n is an arbitrary integer.

Similarly, solving for[tex]csc(x) + 6 = 0[/tex], we have csc(x) = -6. This implies that [tex]x = (2n+1)π + arcsec(-6) or (2n+1)π - arcsec(-6)[/tex], where n is an arbitrary integer.

Therefore, the solutions to the equation[tex]csc2(x) + 6 csc(x) − 7 = 0 are x = π/2, (2n+1)π/2, (2n+1)π + arcsec(-6) and (2n+1)π - arcsec(-6).[/tex]

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Answer:

C=2πr

Step-by-step explanation: