During the basketball game, you record the number of rebounds from missed shots for each team. (a) describe the likelihood that your team rebounds the next missed shot. (B) how many rebounds should ur team expect to have in 15 missed shots

Based on the options provided, it seems that the question is asking whether the budgeted amount is enough to cover expenses, savings, and emergencies. The answer would be either A, B, C, or D.

A) No, it's short $207.0.
B) No, it's short $227.0.
C) Yes, there's a surplus of $207.0.
D) Yes, there's a surplus of $227.0.

Unfortunately, without more information about the specific budgeted amount and the actual expenses, savings, and emergencies, it is impossible to determine the correct answer. It is important to regularly track expenses and compare them to the budgeted amount to ensure that there is enough money to cover all necessary expenses and unexpected events. If there is a shortfall, it may be necessary to adjust the budget or find ways to increase income or decrease expenses to ensure financial stability.

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Answer: 80 trees

Step-by-step explanation:

YIELD = (NUMBER OF TREES)*(NUMBER OF ORANGES PER TREE)

Let's assume NUMBER OF TREES = 60 + x, where x is the number of additional trees above 60

The NUMBER OF ORANGES PER TREE will = (400-4x).  Hence:

YIELD = (60+x)*(400-4x) = 24000-240x+400x-4x2 = -4x2 + 160x + 24,000

To find the maximum YIELD, take the derivative of YIELD wrt x, set it to zero, and solve for x:

d(YIELD)/dx = -8x + 160

0 = -8x +160

8x = 160

x = 20

The grower should grow 60 + 20 = 80 trees to maximize yield.

Answer: 80 trees

Step-by-step explanation: just bc it is

We need at least 7 terms of the series to be certain that the partial sum Sn is within 1/100 of the sum.

We want to find the smallest value of n such that the absolute value of the difference between the sum of the first n terms and the sum of the entire series is less than 1/100.

The sum of the first n terms of the series is given by:

Sn = ∑_(k=1[tex])^n[/tex] (-1[tex])^(k+1)[/tex]/[tex]2^k[/tex]

We can write the sum of the entire series as:

S = ∑_(k=[tex]1)^∞[/tex] (-1[tex])^(k+1)[/tex]/[tex]2^k[/tex]

The absolute value of the difference between the sum of the first n terms and the sum of the entire series is:

|S - Sn| = |∑_(k=n+1[tex])^∞[/tex] [tex](-1)^(k+1)/2^k|[/tex]

We want to find the smallest value of n such that |S - Sn| < 1/100.

Let's start by evaluating the sum of the series:

S = ∑_(k=1) (-1[tex])^(k+1)[/tex]/[tex]2^k[/tex] = 1/2 - 1/4 + 1/8 - 1/16 + ...

This is a geometric series with first term a = 1/2 and common ratio r = -1/2. The sum of the series is:

S = a/(1-r) = (1/2)/(1+1/2) = 1/3

Now we can write:

|S - Sn| = |∑_(k=n+1[tex])^∞[/tex] (-1[tex])^(k+1)[/tex]/[tex]2^k|[/tex] <= 1/[tex]2^(n+1)[/tex]

The last inequality is true because the terms of the series are decreasing in absolute value, and we are summing an infinite number of terms.

Therefore, we need to find the smallest value of n such that 1/2^(n+1) < 1/100. This gives:

n+1 > log2(100)

n > log2(100) - 1

n > 6.64

The smallest integer value of n that satisfies this inequality is n = 7.

Therefore, we need at least 7 terms of the series to be certain that the partial sum Sn is within 1/100 of the sum.

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The equation that can be used to find the total number of students would be n = 19 + 5.

It is acknowledged that Clara provided 2 bottles per each pupil joining her on the excursion. Denote, by using ‘x’, the quantity of learners present; we can then inscribe the succeeding formula:

2x = 38

By resolving this mathematical principal, the total number of students attending the event is revealed.

x = 38 / 2

x = 19

Currently, 19 individuals are confirmed to embark upon the outing, due to five individuals failing to furnish required consent forms and will be absent. Subsequently, we may deduce the quantity of pupils (designated as ‘n’) in Clara’s class:

n = 19  (students going on the trip ) + 5 ( students not going )

n = 19 + 5

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The height of the triangle is 2 meters.

Para encontrar la altura del triángulo, podemos utilizar la fórmula para calcular el área de un triángulo:

Área = (base x altura) / 2

Sabemos que el área es de 1.5 m² y que la base mide 1.5 m, por lo que podemos despejar la altura de la siguiente manera:

1.5 m² = (1.5 m x altura) / 2

Multiplicando ambos lados por 2:

3 m² = 1.5 m x altura

Despejando la altura:

altura = 3 m² / 1.5 m

altura = 2 m

Por lo tanto, la altura del triángulo que representa al pino en el periódico mural es de 2 metros.

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Each of the three sisters owes $75 to cover the cost of hiring the karaoke deejay for Taylor's graduation party.

To determine how much each sister owes, we need to first calculate the total cost of the party and then divide that cost by three, since there are three sisters splitting the cost.

1. Tent rental: $45
2. Microphone system: $60
3. Deejay cost: $30/hour × 4 hours = $120

Now, we'll add these costs together to find the total cost:
Total cost = $45 (tent) + $60 (microphone) + $120 (deejay) = $225

Finally, we'll divide the total cost by the number of sisters (3) to find out how much each sister owes:
Amount owed per sister = $225 (total cost) ÷ 3 (sisters) = $75

So, each sister owes $75 for the karaoke deejay at Taylor's graduation party.

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Table c represents a proportional relationship because the ratio of y to x is constant at 18.

A proportional relationship is a relationship between two quantities where their ratios always remain the same.

In option (a), the ratio of y to x is not constant. For example, y/x = 40/1 = 40, but y/x = 148/4 = 37. Therefore, this table does not represent a proportional relationship.

In option (b), the ratio of y to x is not constant either. For example, y/x = 48/2 = 24, but y/x = 192/5 = 38.4. Therefore, this table does not represent a proportional relationship.

In option (c), the ratio of y to x is constant. For example, y/x = 18/1 = 18, but y/x = 126/7 = 18. Therefore, this table represent a proportional relationship.

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Which of the following tables represent a proportional relationship?

a. y/x= 40/1 76/2 112/3 148/4

b. y/x= 48/2 96/3 144/4 192/5

c. y/x= 18/1 54/3 90/5 126/7

d. 24/1 21/2 18/3 15/4

The height of a cone with a diameter of 12m whose volume is 226m³ is 6 meters.

The formula for the volume of a cone is

V = (1/3) * π * r^2 * h

where V is the volume, r is the radius, h is the height, and π is approximately equal to 3.14.

We know the diameter of the cone is 12m, which means the radius is 6m.

We also know that the volume of the cone is 226m^3.

Substituting these values into the formula, we get:

226 = (1/3) * π * 6^2 * h

Simplifying:

226 = (1/3) * 3.14 * 36 * h

226 = 37.68h

h = 226/37.68

h ≈ 6

Therefore, the height of the cone is approximately 6 meters.

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Answer:

Step-by-step explanation:To solve the quadratic equation 6x²-11x-35= 0, we can use the quadratic formula:

x = (-b ± sqrt(b² - 4ac)) / 2a

where a, b, and c are the coefficients of the quadratic equation.

In this case, we have:

a = 6

b = -11

c = -35

Substituting these values into the quadratic formula, we get:

x = (-(-11) ± sqrt((-11)² - 4(6)(-35))) / 2(6)

Simplifying this expression:

x = (11 ± sqrt(121 + 840)) / 12

x = (11 ± sqrt(961)) / 12

x = (11 ± 31) / 12

So, we have two solutions:

x = (11 + 31) / 12 = 3

and

x = (11 - 31) / 12 = -5/2

Therefore, the solutions to the equation 6x²-11x-35= 0 are x = 3 and x = -5/2.

The area of a rectangle can be found by multiplying its length and width.

To find the area of rectangles with different perimeters, we need to use the formula:

Area = length x width

Possible dimensions:

Length = 5 cm, Width = 3 cm

Length = 4 cm, Width = 4 cm

Area of the first rectangle = 5 cm x 3 cm = 15 cm²

Area of the second rectangle = 4 cm x 4 cm = 16 cm²

Possible dimensions:

Length = 6 cm, Width = 4 cm

Length = 5 cm, Width = 5 cm

Area of the first rectangle = 6 cm x 4 cm = 24 cm²

Area of the second rectangle = 5 cm x 5 cm = 25 cm²

Possible dimensions:

Length = 4 cm, Width = 3 cm

Area of the rectangle = 4 cm x 3 cm = 12 cm²

Therefore, the areas of the possible rectangles with perimeters 16cm, 20cm, and 14cm are:

For perimeter 16cm: 15 cm² and 16 cm²

For perimeter 20cm: 24 cm² and 25 cm²

For perimeter 14cm: 12 cm²

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Answer: arithmetic. Common difference is -4

Step-by-step explanation:

 constantly subtract four to get to the next

If the fifth and tenth terms of an arithmetic sequence, respectively, are -2 and 53, the seventh term of the arithmetic sequence is 20.

To find the seventh term of the arithmetic sequence, we need to first find the common difference (d) of the sequence. We know that the fifth term is -2 and the tenth term is 53.

The formula for the nth term of an arithmetic sequence is: an = a1 + (n-1)d

Using this formula, we can set up two equations:

-2 = a1 + 4d  (since the fifth term is a1 + 4d)
53 = a1 + 9d  (since the tenth term is a1 + 9d)

We now have two equations with two variables (a1 and d). We can solve for either variable using substitution or elimination. I'll use elimination:

-2 = a1 + 4d
53 = a1 + 9d

Subtracting the first equation from the second equation, we get: 55 = 5d

Therefore, d = 11

Now that we know the common difference is 11, we can use the formula for the nth term again to find the seventh term:

a7 = a1 + (7-1)d
a7 = a1 + 6d

We still don't know a1, but we can solve for it using one of the previous equations:

-2 = a1 + 4d
-2 = a1 + 4(11)
-2 = a1 + 44
a1 = -46

Now we can substitute a1 and d into the formula for the seventh term:

a7 = -46 + 6(11)
a7 = -46 + 66
a7 = 20

Therefore, the seventh term of the arithmetic sequence is 20.

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The statement''El 91 no es un número primo porque tiene más divisores que el 1 y el 91''  is true because  91 is not a prime number.

A prime number is a positive integer that has only two divisors, 1 and itself. To check if 91 is a prime number, we need to find its divisors. We can start by dividing 91 by 2, but we find that 2 is not a divisor of 91. Next, we can try dividing it by 3, and we get 30 with a remainder of 1. This means that 3 is not a divisor of 91 either.

We continue dividing by 4, 5, 6, and so on until we reach 13, which gives us 7 as a quotient and 0 as a remainder. Therefore, the divisors of 91 are 1, 7, 13, and 91, which means that 91 is not a prime number because it has more than two divisors. Hence, the statement is true.

91 ÷ 2 = 45 r 1

91 ÷ 3 = 30 r 1

91 ÷ 4 = 22 r 3

91 ÷ 5 = 18 r 1

91 ÷ 6 = 15 r 1

91 ÷ 7 = 13 r 0

Since 91 has more than two divisors, it is not a prime number.

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Answer: -40

Step-by-step explanation:

Rate of change is calculated as the slope. The formula for Slope is:

S = [tex]\frac{x_{1}-x_{2} }{ y_{1}-y_{2}}[/tex]

The two points we have are when x = 3 and 6.

the points are (3, 120) and (6, 0), as we can see.

plugging into the slope formula:

S = [tex]\frac{120-0 }{ 3-6}[/tex]

S = 120/-3

S = -40

Which hopefully makes sense, because the slope is negative, (the graph is falling).

a. By central limit theorem, P(XB- XA >= 0. 2) is approximately 0.0228 under the condition that μA=μB.

b. Yes, we can conclude that the observed difference in sample means does provide evidence that the two population means for the two machines are different.

a. Using the central limit theorem, we know that the sampling distribution of the difference in means (XB - XA) is approximately normal with mean (μB - μA) and standard deviation (σ/√n), where σ is the population standard deviation (σ=1 ounce) and n is the sample size (n=36 for both machines).

So, P(XB - XA >= 0.2) can be calculated by standardizing the difference in means:

Z = (XB - XA - (μB - μA)) / (σ/√n)
Z = (4.7 - 4.5 - 0) / (1/√36)
Z = 2

Looking up the probability of Z being greater than or equal to 2 in a standard normal distribution table, we find P(Z >= 2) = 0.0228.

Therefore, P(XB - XA >= 0.2) is approximately 0.0228 under the condition that μA=μB.

b. The difference in sample means (XB - XA = 0.2) is relatively small compared to the population standard deviation (σ=1 ounce). However, the calculated probability in part a (0.0228) suggests that the observed difference in sample means is statistically significant at a significance level of 0.05 (since P(XB - XA >= 0.2) < 0.05).

Therefore, we can conclude that the observed difference in sample means does provide evidence that the two population means for the two machines are different. However, further testing or analysis may be necessary to confirm this conclusion.

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The explanation on why △ACF is 30°-60°-90° triangle is given below.

With a regular hexagon, each of its sides and angles are equal in measure. Consider the centre of the encompassing circle, connected to two neighbouring vertices - labeled A and B here. This then creates a radius wherein the length of AB is basically equal to any other side, denoted as 's'. Furthermore, △ABF will be an isosceles triangle (with AB = BF).  

From these facts, we can produce △ACF which is a right angled triangle – with AC being its hypotenuse, A F and FB both equating to s/2, finally concluding that ∠AFB is equivalent to 120°/2 = 60° while establishing that ∠ACF is also a right angle constituent making △ACF essentially a 30°-60°-90° triangle.

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The volume of cement in cubic feet that will be needed is 45 cubic feet.

Volume is the space occuppied by an object.

To calculate the volume of cement in cubic feet that will be needed, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

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To find the equation of the plane that passes through the point (0, 9, 0) and is perpendicular to the vector n = -2i ÷ 4k, we first need to find the normal vector of the plane.

Since the plane is perpendicular to the given vector, the normal vector will be parallel to it. So, we can take the given vector and multiply it by -1 to get a vector in the opposite direction, which will be normal to the plane.

n = -2i ÷ 4k = -1/2i ÷ k

Multiplying by -1 gives us:

n = 1/2i ÷ k

Now we can use the point-normal form of the equation of a plane:

r · n = d

where r is the position vector of any point on the plane, n is the normal vector, and d is the distance of the plane from the origin (since the normal vector is normalized, d will be the signed distance of the plane from the origin).

Substituting the given point (0, 9, 0) and the normal vector n = 1/2i ÷ k into the equation, we get:

(0, 9, 0) · (1/2i ÷ k) = d

0 + 9(1/2) + 0 = d

d = 4.5

So the equation of the plane is:

x/2 + z/2 = 4.5

or, multiplying by 2 to eliminate fractions:

x + z = 9

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a. The equation to solve for x is given as follows: 2x + 8 = 42.

b. The solution for x is given as follows: x = 17.

The value of x is obtained applying the angle bisection theorem, which divides an angle into two angles of equal measure, hence the opposite segments also have equal length.

The segments for this problem, along with their lengths, are given as follows:

Hence the equation is given as follows:

2x + 8 = 42.

The value of x is given as follows:

2x = 34

x = 17.

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Answer:

if the two angles are equal

we use sss therom to solve it

2ft/6ft=24ft/xft

x=(6*24)/2

=72

The solutions for x between 0 and 2π are: x = π/2, (5π)/6, and (11π)/6.

To solve the equation 5 + sin(3x) = 4 for x on the unit circle, where x is between 0 and 2π, follow these steps:

1. Subtract 5 from both sides: sin(3x) = -1
2. Determine the angle for which sin is -1: sin(3x) = sin(3π/2)
3. Since the sine function has a period of 2π, the general solution is: 3x = 3π/2 + 2πk, where k is an integer.
4. Divide both sides by 3: x = π/2 + (2πk)/3

Now, find the values of x between 0 and 2π by trying different integer values of k:

- If k = 0, x = π/2
- If k = 1, x = π/2 + 2π/3 = (5π)/6
- If k = 2, x = π/2 + 4π/3 = (11π)/6

Thus, the solutions for x between 0 and 2π are: x = π/2, (5π)/6, and (11π)/6.

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Answer:

2 inches

Step-by-step explanation:

The area of the metal plate can be calculated by subtracting the area of the hole from the area of the original plate. The area of the original plate is:

8 inches x 4 inches = 32 square inches

The area of the hole is:

8 inches x 4 inches = 32 square inches

So the area of the metal that remains is:

32 square inches - 32 square inches = 0 square inches

According to the equation given, we know that:

(8 + 2x)(4 + 2x) - 32 = 32

Expanding this equation we get:

32 + 16x + 8x + 4x^2 - 32 = 32

Simplifying and rearranging we get:

4x^2 + 24x - 32 = 0

Dividing both sides by 4 we get:

x^2 + 6x - 8 = 0

We can solve this quadratic equation by factoring:

(x + 4)(x - 2) = 0

So x = -4 or x = 2. Since the width of the frame cannot be negative, the only valid solution is x = 2.

Therefore, the frame width is 2 inches.

We know that by solving for t, you can find the amount of time Roger spent answering phone calls

You can use the equation t + 40 = 90, where t represents the amount of time Roger answers phone calls at the information desk.

This equation takes into account that Roger spends 40 minutes delivering flowers and the total time he volunteers at the hospital is 90 minutes.

By solving for t, you can find the amount of time Roger spent answering phone calls.

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Answer:

Step-by-step explanation:

If there are 180 degrees in a triangle total and in this problem we know that one angle is 49 and the other is 39, we can assume that subtracting 39 and 49 from 180 will find x. In this case, x will be 92.

Answer: ⬇️⬇️

Step-by-step explanation:

In the expression 5 x y/7, the value of y that would make a product greater than 5 is 8. 

HOW TO SOLVE ALGEBRAIC EXPRESSIONS?

According to this question, the following algebraic equation was given:

5 x y/7

This equation reveals that the result can only be equal to 5 when y is exactly 7.

This is because if y = 7, y/7 = 1.

 Therefore, the value of y that would make a product greater than 5 is 8.

He must sell the car at R80,625 to make an overall profit of 25%

To find the selling price of the car that gives a 25% profit, we need to use the following steps:

Calculate the total cost of buying and transporting the car to Durban:

Total cost = Cost of car + Cost of transportation

Total cost = R60,000 + R4,500

Total cost = R64,500

Calculate the desired profit:

Profit = 25% of total cost

Profit = 0.25 x R64,500

Profit = R16,125

Calculate the total amount that the car needs to be sold for:

Total amount = Total cost + Profit

Total amount = R64,500 + R16,125

Total amount = R80,625

Therefore, the man needs to sell the car for R80,625 to make an overall profit of 25%.

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Jesus' net bi-weekly pay is $856.69 after paying his taxes and deductions.

To find Jesus' net bi-weekly pay, I followed these steps:

Calculate Jesus' commission: Jesus sold $16,200 of computer equipment, so his commission is 5.5% of $16,200, which is $891.

Calculate Jesus' gross bi-weekly pay: Jesus receives a bi-weekly salary of $300 plus his commission of $891, so his gross bi-weekly pay is $1,191.

Calculate Jesus' deductions: Jesus pays 8% for State Income Tax, 12.3% for Federal Income Tax, 6.3% for Social Security, and 1.45% for Medicare. To calculate the deductions, I multiplied his gross bi-weekly pay by each percentage rate:

State Income Tax: 8% of $1,191 = $95.28

Federal Income Tax: 12.3% of $1,191 = $146.67

Social Security: 6.3% of $1,191 = $75.09

Medicare: 1.45% of $1,191 = $17.27

Subtract the deductions from the gross bi-weekly pay: To find Jesus' net bi-weekly pay, I subtracted the total deductions of $334.31 from his gross bi-weekly pay of $1,191:

Net bi-weekly pay = $1,191 - $334.31 = $856.69

Therefore, Jesus' net bi-weekly pay is $856.69 after paying his taxes and deductions.

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The sum of the polynomials (5x³ + x) + (3x³ + 8) is 8x³ + x + 8

(5x³ + x) + (3x³ + 8) can be simplified by adding the coefficients of the like terms. The like terms are 5x³ and 3x³, which can be combined to give 8x³. The single terms are x and 8, which can be combined to give 8 + x. Therefore, the polynomials add up to

8x³ + x + 8

In standard form (highest exponent to lowest), the answer is:

8x³ + x + 8

Therefore, the sum of the polynomials (5x³ + x) + (3x³ + 8) is 8x³ + x + 8 in standard form (highest exponent to lowest)

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The probability values when calculated are

From the question, we have the following parameters that can be used in our computation:

Cards = {1, 2, 3, 4, 5}

Selecting two cards without replacement

So, we have

P(2 numbers greater than 3) = 2/5 * 1/4

P(2 numbers greater than 3) = 0.1

P(2 even numbers) = 2/5 * 4/4

P(2 even numbers) = 0.4

P(2 cards with same numbers) = 1/5 * 0/4

P(2 cards with same numbers) = 0

P(1 card is 3) = 2 * 1/5 * 3/4

P(1 card is 3) = 0.3

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The equation of the tangent line at (6, f(6)) is y = 6x - 48.

a. The slope of the secant line joining (2, f(2)) and (7, f(7)) is:

slope = (f(7) - f(2)) / (7 - 2)

We can find f(7) and f(2) by plugging in x = 7 and x = 2 into the expression for f(x):

f(7) = 7² - 6(7) = 7

f(2) = 2² - 6(2) = -8

Substituting these values into the slope formula, we get:

slope = (7 - (-8)) / (7 - 2) = 3

Therefore, the slope of the secant line joining (2, f(2)) and (7, f(7)) is 3.

b. The slope of the secant line joining (6, f(6)) and (6 + h, f(6 + h)) is:

slope = (f(6 + h) - f(6)) / ((6 + h) - 6) = (f(6 + h) - f(6)) / h

We can find f(6) and f(6 + h) by plugging in x = 6 and x = 6 + h into the expression for f(x):

f(6) = 6² - 6(6) = -12

f(6 + h) = (6 + h)² - 6(6 + h) = h² - 6h + 36 - 36 - 6h = h² - 12h

Substituting these values into the slope formula, we get:

slope = (h² - 12h - (-12)) / h = h - 12

Therefore, the slope of the secant line joining (6, f(6)) and (6 + h, f(6 + h)) is h - 12.

c. The slope of the tangent line at (6, f(6)) is the derivative of f(x) at x = 6:

f'(x) = 2x - 6

f'(6) = 2(6) - 6 = 6

Therefore, the slope of the tangent line at (6, f(6)) is 6.

d. To find the equation of the tangent line at (6, f(6)), we use the point-slope form of a line:

y - f(6) = f'(6)(x - 6)

Substituting f(6) and f'(6) into this equation, we get:

y - (-12) = 6(x - 6)

Simplifying, we get:

y = 6x - 48

Therefore, the equation of the tangent line at (6, f(6)) is y = 6x - 48.

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