Edgar has a fountain that holds 5 quarts of water. He only wants to fill it 3/4 full. How many​ 1-pint containers does it take to fill the​ fountain? How could he fill it with pint and cup​ containers? Explain.

Supposing the value of x to be an integer, the values of k that donot

satisfy the given equation 3x = k mod 6 are 1,2,4,5.

An integer, which can comprise both positive and negative integers, including zero, is a number without a decimal or fractional portion.

Integers are a set of numbers that include both positive and negative numbers, as well as zero. Whole numbers, on the other hand, only include the set of non-negative numbers starting from 0 (i.e., 0, 1, 2, 3, 4, ...). In other words, whole numbers are a subset of integers.

If 3x = k mod 6 has no solutions in x, then k must not be divisible by 3. The positive integers less than 6 that are not divisible by 3 are 1, 2, 4, and 5. Therefore, k can take on 4 values: 1, 2, 4, and 5.

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The number of points is simply 5 times this random variable, and E(C*Y) = C*E(Y), where C is a constant and Y is a random variable, according to expected value principles. As a result, E(X) = 5*2 = 10.

The field of mathematics concerned with probability is known as probability theory. Although there are various distinct interpretations of probability, probability theory approaches the idea rigorously mathematically by articulating it through a set of axioms. A probability is a number that represents the possibility or chance that a specific event will occur. Probabilities can be stated as proportions ranging from 0 to 1, as well as percentages ranging from 0% to 100%.

Here,

The number of dice that are showing an even number is a binomial random variable with n = 4, and p = 1/2 (because half the faces on the die are even and half are odd).

The expected value of this random variable is n*p = 4*1/2 = 2.

The number of points is simply 5 times this random variable, and by the rules of expected value, E(C*Y) = C*E(Y), where C is a constant and Y is a random variable. Thus E(X) = 5*2 = 10.

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Answer:

5 + 2q = 15

Step-by-step explanation:

The perimeter is 4 + 2 + q + (q - 1) = 15.

Add 4 + 2 then subtract the sum from both sides.

q + (q - 1) = 9

This can be simplified further by adding the "q" variables together.

2q - 1 = 9

Add 1 to both sides.

2q = 10

Divide both sides by 2 to isolate q.

q = 5

Answer:

y[tex]\sqrt{5}[/tex]

Step-by-step explanation:

Like radicals are radicals that have the same radical (the number into the square root) and the same radicand (the number above the root)

Here, only the last expression [tex]\sqrt{5}[/tex] can be chosen.

Answer:

b. 1,2,3,4,5,6

bc a dice has 6 sides

Answer:

A farmer has enough food to feed 20 animals in his cattle for 6 days. How long would the food last if there were 10 more animals in his cattle? Here the number of animals and the number of days are in inverse proportion. Hence the food will last 4 days.

For this we can use an equation of y=mx+b, b will equal what she started with, and m will be how much she saves each week

Using this, we now can use the equation Y=15x+30, y equals the total she has saved, and x equals the weeks.

You should be able to use this equation to solve the rest now!

Answer:

Well everyone does

Step-by-step explanation:

The remainder when 2 is divided by 1000 is 2

Let O be the center of the circle, R be the length of the radius, and let the chord be AB with midpoint M. Let x be the distance from O to M, then the length of the radius OM is R/2 and the length of the chord AB is 2x.

Since the chord is perpendicular to the radius at the midpoint, we know that the radius bisects the chord. Therefore, the two segments MO and MB are congruent and have length x.

The area of the larger region is the area of the sector OMB, which is (1/4) of the area of the circle. The area of the smaller region is the area of the triangle OMA, which is (1/2) of the area of the sector OMA.

The ratio of the larger region to the smaller region is (1/4) : (1/2) = 2 : 1.

So, the area of the larger region is twice the area of the smaller region.

We can see that abcdef = 21111*1 = 2, the remainder when 2 is divided by 1000 is 2. Thus, the answer is \boxed{002}.

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Answer:

No, it is AAS.

Step-by-step explanation:

By vertical angle theorem ∠KLJ≅∠MLN.

And the given congruent sides are not between the two congruent angles, therefore it cannot be ASA.

Triangle KLJ ≅ Triangle MLN

h = 7 is the solution to the equation 1/ (h - 5) + 2/ (h + 5) = 16 / (h² - 25)

The meaning of such an equations in algebra is just a mathematical expression stating the equality between two mathematical terms. For instance, 6x + 5 = 11 is an equation where 6x + 5 and 11 are two expressions separated by the 'equal' sign.

Identity equations and conditional equations are the two types of equations. For just any value of both the variables, an equality remains true. Only such variables have values that make a condition expression true. Two expressions joined by an equals sign ("=") form an equation.

The equation given that,

1/ (h - 5) + 2/ (h + 5) = 16 / (h² - 25)

The least common multiple of the denominators is:

h² - 25 = (h - 5) (h + 5)

We multiply through with the LCM to obtain:

= [(h - 5) × (h + 5)] × [1 / (h - 5)] + [(h - 5) × (h + 5)] × [2 / (h - 5)]

= 16 / (h² - 25) × [(h - 5) × (h + 5)]

We cancel out common factors to obtain:

= 1 (h + 5) + 2 (h - 5)

= 16

We expand the brackets to obtain

= h + 5 +2h - 10

We group like terms to get:

h + 2h = 16 - 5 + 10

This simplifies to:

3h = 21

We now divide through by 3 to obtain:

h = 7

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NP, PM, and MN are all midsegments and bisect each side.

value of x = 5 unit

NP = 12

MP=2x

RQ = 5x-1

SQ=6x

Using Midsegments of a Triangle

A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle

Triangle Midsegment Theorem

Using Midsegments of a Triangle

Theorem 5-1 Triangle Midsegment Theorem

The segment connecting the midpoints of two sides of a triangle is parallel to the 3rd side and is half as long.

Triangle Midsegment Theorem A segment whose endpoints are the

midpoints of two sides of the triangle

Midsegment

Base

Midsegment = ½ of Base

M = ½ b

NP =1/2(RQ)

12 =1/2(5x-1)

12* 2 = 5x-1

24 =5x-1

24+1 =5x

25 =5x

x=25/5

x = 5 unit

NP, PM, and MN are all midsegments and bisect each side.

value of x = 5 unit

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Slope of the line AB is 7/6.

The slope of the line is the ratio of the rise to the run, or rise divided by the run. It describes the steepness of line in the coordinate plane.

The slope intercept form of a line is y=mx+b, where m is slope and b is the y intercept.

The slope of line passing through two points (x₁, y₁) and (x₂, y₂) is

m=y₂-y₁/x₂-x₁

From the given graph the coordinates of A are (4, 3) and B is (-2, -4)

Slope AB=-4-3/-2-4

=-7/-6

Slope=7/6

Hence, slope of the line AB is 7/6.

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Earth's rotation and revolution are both very slow motions, so slow that we don't feel them. The rate of Earth's rotation is about 1,000 miles per hour, and the speed of its revolution is about 67,000 miles per hour, but both of those speeds are so slow that we don't feel any movement or acceleration.

Earth's rotation and revolution are both very slow motions, so slow that we don't feel them. The rate of Earth's rotation is about 1,000 miles per hour and its revolution is about 67,000 miles per hour, but both of these speeds are too slow to be felt.Earth's rotation and revolution are both very slow motions, so slow that we don't feel them. The speed of Earth's rotation is about 1,000 miles per hour, and the speed of its revolution is about 67,000 miles per hour, but both of those speeds are so slow that we don't feel any movement or acceleration.

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Answer:

$2.31

Step-by-step explanation :

$16.17 divided by 7

Using the Pythagoras Theorem the third side c of the right-angled triangle is obtained as 6.5 units.

What is Pythagoras Theorem?

In a right-angled triangle, the square of the hypotenuse side is equal to the sum of the squares of the other two sides, according to Pythagoras's Theorem. These triangle's three sides are known as the Perpendicular, Base, and Hypotenuse. Due to its position opposite the 90° angle, the hypotenuse in this case is the longest side.

The data given is -

Assume a, b and c are sides of right-angled triangle.

Then, two adjacent sides of right-angled triangle are -

a^2=29.25 squared units

b^2=13 squared units

The unknown side c is taken to be x.

Find the length of c using Pythagoras Theorem -

c^2=a^2+b^2

where, c is the hypotenuse, a is the perpendicular and b is the base.

Plugging the values in the equation -

x^2=29.25+13

x=√(29.25+13)

x=√42.25

x=6.5

Therefore, the third side measures x=6.5 units.

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Answer:

4d-20

hope this helps

Step-by-step explanation:

Answer:

71

Step-by-step explanation:

I found the area by spliting the figure into the triangle, square, and rectangle

triangle = .5(14*5)=35

square = 2*2=4

rectangle = 8*4=32

35+4+32=71

hope this is right:)

Answer:

4y-100

2(2y-50)

hope this helps

have a good day :)

Step-by-step explanation:

The equation of the line that passes through the points (−8, −10) and (6, 3)in slope-intercept form is y = (13/14) x - 18/7.

The equation of a line can be expressed in three different forms: standard form, slope-intercept form, and point-slope form.

The slope-intercept form of the equation of a line is given by the formula:

y = mx + b

where m is the slope of the line

b is the y- intercept

Given the two points, (−8, −10) and (6, 3), get the slope of the line using the formula:

m = (y₂ - y₁) / (x₂ - x₁)

m = (3 - -10) / (6 - -8)

m = 13 / 14

Using the slope-intercept form, plug in the value of the slope and one point to determine the y-intercept, b.

y = mx+ b

-10 = (13/14)(-8) + b

b = -18/7

Substitute the value of the slope and y-intercept in the slope-intercept form.

y = mx + b

y = (13/14) x - 18/7

Hence, the equation of the line in slope-intercept form is y = (13/14) x - 18/7.

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Jane should land 1.5 mi down the shoreline and walk the remaining 4.5 mi to the village to minimize her travel time.

Let x = distance travelled along the shore over water.

Then, 6 − x = distance travelled along the shore over land.

Let T = the total time taken to reach the destination.

T = distance/velocity = √(4 + x²)/3 + (6-x)/5 on [0, 6].

Note that T must be non negative and that x = 6 means the destination

is reached solely by rowing and without the benefit of faster land

travel. In actual fact, T is valid over [0, ∞) but [0, 6] is reasonable here.

T' = x/3√(4 + x²) - 1/5 = 5x - 3√(4 + x²) = 0

⇒5x = 3√(4 + x²)

⇒25x² = 9(4 + x²)

⇒16x² = 36

⇒x = ±6/4 = ±1.5

The negative x value is discarded since it does not belong to [0,6].

T(0) = 28/15 = 1.8667

T(1.5) = 1.733

T(6) = 2.1082

Therefore, Jane should land 1.5 mi down the shoreline and walk the

remaining 4.5 mi to the village to minimize her travel time.

Her minimum travel time will be T(1.5) = 1.733 hrs. or 1hr 44 min.

--The given question is incomplete, the correct question is

"Jane is 2 mi, offshore in a boat and wishes to reach a coastal village 6 mi, down a straight shoreline from the point nearest the boat. She can row at 3mph and can walk at 5 mph. Where should she land her boat to reach the village in the least amount of time?"--

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Answer:

domain: (-oo,oo)

range:[2,oo)

Using the provided equations, Applying the addition method in the system of equations, The answer is x=-2 and y =-6.

An equation is a statement of equality between two expressions, usually containing one or more variables. Equations can be used to express mathematical relationships and can be solved to find the value of the variables. Equations can take many forms, such as linear equations, quadratic equations, and differential equations. They can also be represented graphically.

The addition method to solve a system of equations is a way to solve a system of two linear equations by adding them together. The goal is to eliminate one variable by adding or subtracting the equations. We can eliminate one variable by adding the equations together. To do this, we'll add the left-hand side of the first equation to the left-hand side of the second equation and add the right-hand side of the first equation to the right-hand side of the second equation. It is important to note that the addition method works only when the coefficients of the variable you want to eliminate are opposite in sign.

4x-5y=22

3x+2y=-18

multiplying first equation with 3 and second equation with 4 and subtracting them , we eliminate x and solve for y,

y=-6

put y=-6 in first equation , we get x,

x=-2

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if n is a positive integer: 1²+ 2² + 3² + ... +n² = 1/6n(n+1)(2n+1)​ IS 1

P(n) :

1²+ 2² + 3² + … +n² = 1/6n(n+1)(2n+1)​

P(1) :

[tex]1^2=\frac{1(1+1)(2(1)+1)}{6}[/tex]

[tex]1=\frac{6}{6}=1[/tex]

∴ LHS = RHS

Assume P(k) is true

P(k):

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Answer:

22 by 26

Step-by-step explanation:

10+10+14+14=48 (the perimeter)

48×2=96

10+12=22

14+12=26

22+22+26+26=96