El 91 no es un número primo porque tiene más divisores que el 1 y el 91 verdadero o falso

El área de papel utilizada para cada CD es aproximadamente 20.41 cm².

How much paper area is used for each CD?

Para calcular el área de papel utilizado para cada CD, necesitamos determinar el área de la región entre dos círculos concéntricos.

El área de un círculo se calcula utilizando la fórmula A = πr², donde r es el radio. En este caso, tenemos dos círculos con radios diferentes: el radio mayor de 5.8 cm y el radio menor de 0.7 cm.

El área del papel utilizado será la diferencia de áreas entre los dos círculos. Entonces, podemos calcularlo de la siguiente manera:

Área utilizada = Área del círculo mayor - Área del círculo menor

= π(5.8²) - π(0.7²)

= π(33.64) - π(0.49)

≈ 105.72 - 1.54

≈ 104.18 cm²

Por lo tanto, aproximadamente se utilizan 104.18 cm² de papel para cada CD.

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a = 5

b = 4

c= 0

Therefore, the equation for graph C is Y = a ^b + c

Y = 5 ^4 + 0

A graph is described as a diagram showing the relation between variable quantities, typically of two variables, each measured along one of a pair of axes at right angles.

Graphs are a popular tool for graphically illuminating data relationships.

A graph serves the purpose of presenting data that are either too numerous or complex to be properly described in the text while taking up less room.

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The measure of angles ADC is 30⁰.

The measure of angles DCA is 120⁰.

The measure of angles DCB is 180⁰.

The measure of angles AEB is 30⁰.

The measure of each of the angles is calculated as follows;

if length AB = length CD, then AC = AB

Also triangle ACB = equilateral triangle, and each angle = 60⁰.

Angle DAB = 90 (since line DB is the diameter)

Angle DAC = angle ADC

DAC = 90 - 60 = 30 = ADC

DCA = 180 - (30 + 30) (sum of angles in a triangle)

DCA = 120⁰.

The value of angle DCB is calculated as follows;

DCB = 180 (sum of angles on straight line)

angle AEB = angle ADC (vertical opposite angles )

angle AEB = 30⁰

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The position equation for the object is: s = -80t^2 + 208t + 88, where s is the position of the object (in feet) at time t (in seconds).

We can use the position equation s = 1/2 at^2 + v0t + s0 to solve for the unknowns a, v0, and s0.

At t = 1 second, s = 136 feet gives us the equation:

136 = 1/2 a(1)^2 + v0(1) + s0

136 = 1/2 a + v0 + s0  ----(1)

At t = 2 seconds, s = 104 feet gives us the equation:

104 = 1/2 a(2)^2 + v0(2) + s0

104 = 2a + 2v0 + s0  ----(2)

At t = 3 seconds, s = 40 feet gives us the equation:

40 = 1/2 a(3)^2 + v0(3) + s0

40 = 9/2 a + 3v0 + s0  ----(3)

We now have a system of three equations with three unknowns (a, v0, s0). We can solve this system by eliminating one of the variables. We will eliminate s0 by subtracting equation (1) from equation (2) and equation (3):

104 - 136 = 2a + 2v0 + s0 - (1/2 a + v0 + s0)

-32 = 3/2 a + v0  ----(4)

40 - 136 = 9/2 a + 3v0 + s0 - (1/2 a + v0 + s0)

-96 = 4a + 2v0  ----(5)

Now we can solve for one of the variables in terms of the others. Solving equation (4) for v0, we get:

v0 = -3/2 a - 32

Substituting this into equation (5), we get:

-96 = 4a + 2(-3/2 a - 32)

-96 = 4a - 3a - 64

a = -160

Substituting this value of a into equation (4), we get:

-32 = 3/2(-160) + v0

v0 = 208

Finally, substituting these values of a and v0 into equation (1), we get:

136 = 1/2(-160)(1)^2 + 208(1) + s0

s0 = 88

Therefore, the position equation for the object is:

s = -80t^2 + 208t + 88

where s is the position of the object (in feet) at time t (in seconds).

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Answer: 1. Multiplying Powers with same Base

For example: x² × x³, 2³ × 2⁵, (-3)² × (-3)⁴

In multiplication of exponents if the bases are same then we need to add the exponents.

Consider the following:

1. 2³ × 2² = (2 × 2 × 2) × (2 × 2) = 23+2

= 2⁵

2. 3⁴ × 3² = (3 × 3 × 3 × 3) × (3 × 3) = 34+2

= 3⁶

3. (-3)³ × (-3)⁴ = [(-3) × (-3) × (-3)] × [(-3) × (-3) × (-3) × (-3)]

                       = (-3)3+4

                       = (-3)⁷

4. m⁵ × m³ = (m × m × m × m × m) × (m × m × m)

                 = m5+3

                 = m⁸

From the above examples, we can generalize that during multiplication when the bases are same then the exponents are added.

aᵐ × aⁿ = am+n

In other words, if ‘a’ is a non-zero integer or a non-zero rational number and m and n are positive integers, then

aᵐ × aⁿ = am+n

Similarly, (ab

)ᵐ × (ab

)ⁿ = (ab

)m+n

(ab)m×(ab)n=(ab)m+n

Note:

(i) Exponents can be added only when the bases are same.

(ii) Exponents cannot be added if the bases are not same like

m⁵ × n⁷, 2³ × 3⁴

Step-by-step explanation:

Answer:

2^4

Step-by-step explanation:

doing this type of division is like subtracting the powers, 9-5=4, 2^4.

the opposite applies for multiplaction, it's like addition for the powers,

2^9*2^5=2^14.

Riley and her family move from the Midwest all the way to San Francisco. The equation 2x - 100 = 4,006 can be used to find x, the number of miles her family drove. Riley's family drove 2,053 miles from the Midwest to San Francisco.

Find the number of miles Riley's family drove from the Midwest to San Francisco, we need to solve the equation 2x - 100 = 4,006 for x.
First, we'll add 100 to both sides of the equation to isolate the variable term:
2x - 100 + 100 = 4,006 + 100
Simplifying:
2x = 4,106
isolate x, we'll divide both sides of the equation by 2:
2x/2 = 4,106/2
Simplifying:
x = 2,053
Therefore, Riley's family drove 2,053 miles from the Midwest to San Francisco.

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Using trigonometry, the length that Ruth has to play in if she plays between her friend's house (point D) and the edge of the lighted area (point C) is 6.72 feet. Option C is the correct answer.

To solve this problem, we need to use trigonometry. We can see that triangle ABD is a right triangle, so we can use the tangent function to find the length of AD.

First, we need to find the length of BD. We can use the right triangle trigonometry again to find it.

tan(27) = BD/AB

BD = AB × tan(27)

BD = 54 × tan(27)

BD ≈ 24.12

Now, we can use the right triangle trigonometry on triangle BCD to find the length of CD.

tan(41) = CD/BD

CD = BD × tan(41)

CD ≈ 18.85

Finally, we can use the Pythagorean theorem on triangle ACD to find the length of AD.

AD² = AC² - CD²

AD² = 20² - 18.85²

AD ≈ 6.72

Therefore, the length that Ruth has to play is approximately 6.72 feet.

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The question is -

Ruth has a street lamp in front of her house, represented by Segment AB The street Lamp is 20 feet tall. Her mom insists that at night she only plays within its light. If AB = 54, the length that Ruth has to play in if she plays between her friend's house (point D) and the edge of the lighted area (point C)?

Options are:

a. 1.7 feet

b. 2.2 feet

c. 6.7 feet

d. 5.9 feet

There are 6 cute numbers in total which are 14, 19, 49, 55, 79, 85.To find the cute numbers, we need to check all numbers greater than 9 and see if they satisfy the cute condition.

Let's start by analyzing the digits of a number. Suppose the number has two digits, x and y. The cute condition requires:

x + y + xy = 10x + y

Rearranging this equation, we get:

xy - 9x = y - x

xy - x - y = -9x

(x - 1)(y - 1) = 9x - 1

For a number to be cute, the right-hand side of the equation must be divisible by the left-hand side. Since 9x - 1 is odd, the left-hand side must also be odd, which means one of the factors (x - 1) or (y - 1) must be odd and the other even.

We can now check all possible pairs of (x,y) that satisfy this condition. We find that the cute numbers are:

14, 19, 49, 55, 79, 85. Therfore, there are total 6 cute numbers.

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By using concept of interior angle we find the value of X is -7.14 degrees.

The above problem involves finding the value of x in a triangle with two known angles measuring 78° and 152°.

The sum of the interior angles of any triangle is always 180°, so we can use this fact to set up an equation involving the third angle, which is given as 7x +3 degrees.

To solve for x, we first simplify the equation by combining the known angles:

78° + 152° + (7x + 3)° = 180°

Next, we can simplify by adding the two known angles:

230° + 7x° = 180°

This simplifies to:

7x° = -50°

Finally, we can solve for x by dividing both sides by 7:

x =  [tex]\frac{-50^\circ}{7}$$[/tex]

Therefore, x is approximately -7.14 degrees.

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The given infinite series diverges.

Let f(x) = -5/x. Then, we can see that f(x) is a continuous, positive, and decreasing function for x ≥ 1. Now, we can apply the integral test to determine whether the series converges or diverges.

∫₅^∞ -5/x dx = -5 ln(x) |₅^∞ = -∞

Since the improper integral diverges, by the integral test, the infinite series also diverges.

To apply the integral test, we need to verify the following conditions:

f(x) is a continuous, positive, and decreasing function for x ≥ 1.

The series Σ aₙ and the integral ∫₁^∞ f(x) dx have the same convergence behavior.

Let f(x) = -5/x. Then, f(x) is a continuous function for x ≥ 1. Furthermore, f(x) is positive and decreasing because its derivative is f'(x) = 5/x² > 0 for x ≥ 1.

We can evaluate the integral ∫₁^∞ f(x) dx as follows:

∫₁^∞ -5/x dx = -5 ln(x) |₁^∞ = -∞

Since the improper integral diverges, the series Σ -5/n also diverges by the integral test.

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Her profit when 0 people attend is -$50 and each person pays 10

From the question, we have the following parameters that can be used in our computation:

y = 10x - 50.

The graph is added as an attachment

This means that

x = 0

So, we have

y = 10(0) - 50.

y = -50

She made a loss of 5-

This represents her profit when 0 people attend

This represents the slope of the function

The slope of the function is 10

So, each person pays 10

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The cross-product of u and v:
w = u × v = (5, -4, 8) × (-8, -4, 5) = (-20, -60, 32)

Thus, w is orthogonal to u. Since we need two vectors in opposite directions, we can negate w:
-w = (20, 60, -32)
Therefore, the two orthogonal vectors in opposite directions are w = (-20, -60, 32) and -w = (20, 60, -32).

To find two vectors that are orthogonal to u, we can use the cross-product. Let v = (4,5,0) and w = (-8,0,5). Then v x u = (40,40,45) and w x u = (20,-40,20). So two vectors orthogonal to u are (40,40,45) and (20,-40,20).

To determine whether two planes are orthogonal, parallel, or neither, we can look at the normal vectors of each plane. Let the first plane be defined by the equation 2x + 3y - z = 4 and the second plane being defined by the equation :

4x + 6y - 2z = 8.

The normal vector of the first plane is (2,3,-1) and the normal vector of the second plane is (4,6,-2).

Since the dot product of these two normal vectors is -2(3) + 3(6) - 1(2) = 14, which is not equal to 0, the planes are not orthogonal.

To determine if they are parallel, we can check if the ratio of their normal vectors is constant. Dividing the second normal vector by the first, we get (4/2, 6/3, -2/-1) = (2,2,2). Since this is a constant ratio, the planes are parallel.

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All the angles of the Rhombus if B-A=20 is angle A = angle C = 80°, and angle B = angle D = 100°.

In a rhombus ABCD, if angle B minus angle A equals 20 degrees (B-A=20°), we can find the degree measures of all the angles.

Step 1: Recognize that in a rhombus, opposite angles are equal. Therefore, angle A = angle C and angle B = angle D.

Step 2: Remember that the sum of the angles in any quadrilateral is 360 degrees. In a rhombus, since the opposite angles are equal, we can represent this as: 2A + 2B = 360°

Step 3: Use the given information, B - A = 20°, to solve for one of the angles. For this, rearrange the equation to isolate B: B = A + 20°

Step 4: Substitute the expression for B from step 3 into the equation from step 2: 2A + 2(A + 20°) = 360°

Step 5: Solve the equation for angle A. 2A + 2A + 40° = 360° → 4A + 40° = 360° → 4A = 320° → A = 80°

Step 6: Now that we have angle A, use the expression from step 3 to find angle B: B = 80° + 20° = 100°

Step 7: Since A = C and B = D, we can now state all the angles of the rhombus ABCD: angle A = angle C = 80°, and angle B = angle D = 100°.

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The first four nonzero terms of the Taylor series for f(y) about 0 are:

[tex]-2y^2 + 48y^4/2![/tex] + ... = -[tex]2y^2 + 24y^4[/tex] + ...

To find the Taylor series for the function f(y) = ln(1 - 2y^4) about 0, we need to compute its derivatives at 0 and evaluate them at each term. Let's start by finding the first four derivatives:

f(y) = ln(1 - 2[tex]y^4)[/tex]

f'(y) = [tex]-8y^3 / (1 - 2y^4)[/tex]

f''(y) =[tex](24y^6 - 32y^2) / (1 - 2y^4)^2[/tex]

f'''(y) =[tex](-144y^9 + 384y^5) / (1 - 2y^4)^3[/tex]

f''''(y) =[tex](1920y^12 - 7680y^8 + 3456y^4) / (1 - 2y^4)^4[/tex]

Now we can evaluate each derivative at 0 to get the first four nonzero terms of the Taylor series:

f(0) = ln(1) = 0

f'(0) = 0

f''(0) = -2

f'''(0) = 0

f''''(0) = 48

Therefore, the first four nonzero terms of the Taylor series for f(y) about 0 are: -2y^2 + 48y^4/2! + ... = -2y^2 + 24y^4 + ...

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Answer:

Step-by-step explanation:

If we let M be a number, then 5 times as big as M would be 5M. Not that hard :/

As a result, it will take roughly 10.24 years for the account to reach $20,000 in value.

As a quarter of 100, a number can be expressed as a percentage. It is frequently used to describe distinctions or express changes in numbers. The symbol for percentages is %, and they are frequently utilized to describe ratios, rates, and certain other numerical connections. An 80 percent score on a test, for instance, indicates that the student correctly answered 80 of the 100 questions. Similar to this, if a retailer were offering a 20% discount on a $100 item, the sale price would be $80.

given

With P = 10000, r = 0.08 (8% stated as a decimal), n = 12 (compound monthly), and t to be found when A = 20000, the situation is as follows.

When these values are added to the formula, we obtain:

[tex]20000 = 10000(1 + 0.08/12)^(12t) (12t)[/tex]

By multiplying both sides by 1000, we obtain:

[tex]2 = (1 + 0.08/12)^(12t) (12t)[/tex]

When we take the natural logarithm of both sides, we obtain:

ln(2) = 12t ln(1 + 0.08/12)

When we multiply both sides by 12 ln(1 + 0.08/12), we obtain:

t = ln(2) / (12 ln(1 + 0.08/12))

Calculating the answer, we discover:

10.24 years is t.

As a result, it will take roughly 10.24 years for the account to reach $20,000 in value.

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Therefore , the solution of the given problem of unitary method  comes out to be space between Mars' and Jupiter's orbits contains rock-like objects.

To complete the work, the well-known straightforward strategy, actual variables, and any essential components from the very first and specialised inquiries can all be utilised. In response, customers might be given another opportunity to sample the product. Otherwise, important advancements in our comprehension of algorithms will be lost.

Here,

What makes up the majority of the sun?

hydrogen a

The names of the planets nearest to the sun are:

Inner planets, B

A. 2n² is the general formula for the main shell.

Except for one planet, all of them revolve in the same direction. What planet is that?

(1) Venus

Which of the following is the solar system's inner planet?

Mercury, a.

The region of space between Mars' and Jupiter's orbits contains rock-like objects, which are known as:

Asteroid C.

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The scale Marcella used for her drawing is 7 inches : 50 meters

The statements in the question are given as

The above statements imply that we have the following scale ratio

Scale = Scale measurement : Actual measurement

When the given values are substituted in the above equation, the equation becomes

Scale = 7 inches : 50 meters

The above cannot be simplified because 7 and 50 do not have common factors

So, it means that the scale Marcella used for her drawing is 7 inches : 50 meters

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The probability that a person has a disease given that they test positive, when 0.4% of the population has the disease and the test is positive with probability 0.99 if they have the disease and 0.03 if they don't have it, is 0.116 or about 11.6%.

Let D be the event that the person has the disease and T be the event that the person tests positive. We need to calculate P(D|T), the probability that the person has the disease given that they test positive.

Using Bayes' theorem, we have

P(D|T) = P(T|D) * P(D) / P(T)

where P(T|D) is the probability of testing positive given that the person has the disease, P(D) is the prior probability of having the disease, and P(T) is the total probability of testing positive, which can be calculated as

P(T) = P(T|D) * P(D) + P(T|D') * P(D')

where P(T|D') is the probability of testing positive given that the person does not have the disease, and P(D') is the complement of P(D), which is the probability of not having the disease.

Substituting the given values, we get

P(D|T) = (0.99 * 0.004) / [(0.99 * 0.004) + (0.03 * 0.996)]

= 0.116

Therefore, the probability that the person has the disease given that they test positive is 0.116 or about 11.6%.

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Answer:

Step-by-step explanation:

The solution to the differential equation is:

[tex]y = e^{(2\sqrt{y} - 0.6137)}[/tex]

To solve this differential equation, we can use the method of separation

of variables. This involves isolating the variables x and y on different

sides of the equation and then integrating both sides with respect to

their respective variables.

Starting with the given equation:

[tex]dy/dx = e^{(\sqrt{(x/y)} )}[/tex]

We can begin by multiplying both sides by dx:

[tex]dy = e^{(\sqrt{(x/y)} ) dx}[/tex]

Now we can separate the variables and integrate both sides:

[tex]\int(1/y)dy = ∫e^{(\sqrt{(x/y))dx} }[/tex]

ln|y| = 2√y + C1 ...where C1 is a constant of integration

To solve for y, we can exponentiate both sides:

[tex]|y| = e^{(2\sqrt{y} + C1)}[/tex]

Since y(1) = 4, we can use this initial condition to determine the sign of y and the value of C1:

[tex]4 = e^{(2\sqrt{4} + C1)} \\4 = e^{(4 + C1)}[/tex]

ln(4) = 4 + C1

C1 = ln(4) - 4 = -0.6137

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Answer:

I think the answer should be part

Answer:

9.42 meters

Step-by-step explanation:

radius= 1.5

double the radius to get the diameter

diameter= 3

to find the circumference the equation is π × d

3.14 × 3= 9.42

circumference= 9.42

Answer: B

The guy above is wrong! The correct answer is 7.07, and I double checked with a circumference calculator.

Step-by-step explanation:

-To find the circumference of a circle, you can use the formula C = πd.

-By using this formula the answer found is 7.07

This is 100% the right answer, trust me.

Brainliest?

Answer:

When x is greater than -5, the expression inside the absolute value bars is positive, so we can simply remove the bars.

So the equation y = |x+5| can be rewritten as:

y = x+5 (when x > -5)

The approximate total amount Valerie will pay for her new car is $38,287.

How much will Valerie pay in total for her new car?

To calculate how much Valerie will pay in total for her new car, we need to consider several factors.

First, let's determine the trade-in value of her 2006 Hyundai Sonata. Since the car is in good condition, Valerie will receive 87.5% of the listed trade-in price for that year, which is $6,784. Therefore, the trade-in value is approximately $5,938.80 ($6,784 * 0.875).

Now, let's calculate the total cost of the new car. The list price is $32,495, and Valerie plans to make a down payment of $1,877. Thus, the remaining amount to be financed is $32,495 - $1,877 - $5,938.80 = $24,679.20.

Next, let's consider the interest on the financing. The interest rate is 8.64% per year, compounded monthly. Over five years, this amounts to 60 monthly payments. Using an amortization formula, we can determine that the monthly payment is approximately $516.27.

Additionally, Valerie will have to pay sales tax, vehicle registration fee, and documentation fee. The sales tax is 8.23% of the total cost, which is ($24,679.20 + $2,243) * 0.0823 = $2,329.48. The vehicle registration fee is $2,243, and the documentation fee is $314. The total additional fees amount to $2,329.48 + $2,243 + $314 = $4,886.48.

Finally, to calculate the total amount Valerie will pay, we add the down payment, monthly payments, trade-in value reduction, and additional fees: $1,877 + (60 * $516.27) + $5,938.80 + $4,886.48 = $38,285.88.

Rounding to the nearest cent, Valerie will pay approximately $38,286 for her new car. Thus, the correct answer is option c: $38,287.

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The length of side x in simplest radical form with a rational denominator is x√3.

To find the length of side x in simplest radical form with a rational denominator given x√3, some steps need to be followed.

Steps are:
1. Identify the radical: In this case, it is √3.

2. Identify the denominator: To rationalize the denominator, we want to eliminate the radical from the denominator. Since the given expression has x√3, the denominator we need to rationalize is 1.

3. Rationalize the denominator: To do this, multiply the expression by a value that will cancel out the radical in the denominator without changing the value of the expression. Since our denominator is 1, we need to multiply the expression by √3/√3.

4. Multiply the expression: (x√3) * (√3/√3) = x√3 * √3 = x(√3)^2 = x(3).

5. Simplify the expression: x(3) = 3x.

So, the length of side x in simplest radical form with a rational denominator is 3x.

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Answer:

=Briefly, days are longest at the time of the summer solstice in December and the shortest at the winter solstice in June. At the two equinoxes in March and September the length of the day is about 12 hours, a mean value for the year.

Step-by-step explanation:

Answer:Briefly, days are longest at the time of the summer solstice in December and the shortest at the winter solstice in June. At the two equinoxes in March and September the length of the day is about 12 hours, a mean value for the year.

Step-by-step explanation:

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Step-by-step explanation:

The plumber worked for 4.5 hours and charged $138.70 for their services

To find out how many hours the plumber worked, we first need to subtract the initial charge of $14.95 from the total bill of $138.70.

$138.70 - $14.95 = $123.75

This gives us the amount that the plumber charged for the hours worked. Now, we can divide this amount by the hourly rate to find the number of hours:

$123.75 ÷ $27.50 per hour = 4.5 hours

However, we need to convert the decimal part (0.5) into minutes. We can do this by multiplying it by 60:

0.5 x 60 = 30 minutes

But we need to add the initial charge of $14.95 to get the final answer.

4 hours and 30 minutes is equivalent to 4.5 hours.

4.5 hours x $27.50 per hour = $123.75

$123.75 + $14.95 = $138.70

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The sum of all possible values of $a$ is $1$.

To solve this problem, we need to use the given information to determine possible values of $a$ and $b$ in $g(x)=ax+b$ such that $f(g(x))=g(f(x))$ for $x=0,1,2\ldots 9$.

First, we can simplify $f(g(x))$ and $g(f(x))$ as follows:

$$f(g(x))=3(ax+b)+2=3ax+3b+2$$

$$g(f(x))=a(3x+2)+b=3ax+ab+b$$

Next, we can set these two expressions equal to each other and simplify:

$$3ax+3b+2=3ax+ab+b$$

$$2b-ab=b$$

$$(2-a)b=b$$

Since $ab=20$, we have two cases to consider:

Case 1: $b=0$

In this case, we have $ab=20\implies a=0$ or $b=0$. Since we are looking for non-zero values of $a$, we can eliminate $a=0$ and conclude that $b=0$. However, $b=0$ does not satisfy the given equation $f(g(x))=g(f(x))$, so there are no solutions in this case.

Case 2: $b\neq 0$

In this case, we can divide both sides of $(2-a)b=b$ by $b$ to get:

$$2-a=1$$

$$a=1$$

Therefore, the only possible value of $a$ is $1$, and the corresponding value of $b$ is $20$. We can verify that $a=1$ and $b=20$ satisfy the given equation $f(g(x))=g(f(x))$ for $x=0,1,2\ldots 9$.

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