Evaluate 0.3y + y/z
When Y=10 and z=5.

A. The experimental probability of getting 3 = 8.3%

B. The probability of getting 6 = 25%

C. Probability of getting numbers less than 4 = 50%

The values have been represented in fractions and decimal below

The total number of times that the dice was thrown = 12

The experimental probability of getting 3 =

As a fraction 1 / 12,

decimal 0.083

As a percentage 8.3%

The total number of times that he got a 6 = 3

The experimental probability of getting 6 = 3 / 12 = 1 / 4

As a fraction 1 / 4

decimal 0.25

As a percentage 25%

numbers less tan 4 are , 1, 2 and 3

The number of times they occurred = 6

The experimental probability of getting > 4 = 6 / 12 = 1 / 2

As a fraction = 1/2

As a decimal = 0.5

As a percent = 50%

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The probability that a second call will not arrive in the next 20 seconds is approximately 0.2636 or 26.36%.

Poisson probability is a mathematical concept that describes the probability of a certain number of events occurring in a fixed interval of time or space, given a known average rate of occurrence. The Poisson probability distribution is named after French mathematician Siméon Denis Poisson, who introduced it in the early 19th century to model the occurrence of rare events, such as errors in counting or measurement, accidents, or phone calls.

The Poisson probability distribution is a discrete probability distribution that gives the probability of a certain number of events (x) occurring in a fixed interval (t), when the average rate of occurrence (λ) is known. The Poisson probability distribution assumes that the events occur independently and at a constant average rate over time or space. The formula for Poisson probability is:

P(x; λ) = ([tex]e^{-\lambda}[/tex]) * λˣ) / x!

where:

P(x; λ) = the probability of x occurrences in a given interval, when the average rate is λ

e = a mathematical constant e (approximately 2.71828)

λ = it is the average rate of occurrence in the given interval

x = it is number of occurrences in the given interval

Given that calls for dial-in connections arrive at an average rate of four per minute and follow a Poisson distribution, we can use the Poisson probability formula to solve this problem. The Poisson probability formula is:

P(x; λ) =  ([tex]e^{-\lambda}[/tex]) * λˣ) / x!

where:

P(x; λ) = the probability of x occurrences in a given interval, when the average rate is λ

e = a mathematical constant e (approximately 2.71828)

λ = the average rate of occurrence in the given interval

x = it is the number of occurrences in the given interval

In this problem, we are interested in finding the probability that a second call will not arrive in the next 20 seconds, given that a call has already arrived at the beginning of a one-minute interval. Since we are given the average rate of calls per minute, we need to adjust the interval to 20 seconds, which is 1/3 of a minute. Therefore, the average rate of calls per 20 seconds is:

λ = (4 calls/minute) * (1/3 minute) = 4/3 calls/20 seconds

Using the Poisson probability formula, we can calculate the probability of no calls arriving in the next 20 seconds:

P(0; 4/3) = ( [tex]e^{-4/3}[/tex]* (4/3)⁰) / 0! = [tex]e^{-4/3}[/tex] ≈ 0.2636

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The probability that the sample proportion of households spending more than $125 a week is less than 0.35 is 0.9884.

Using the given information, the population proportion of households spending more than $125 a week is 0.34. The sample size is 196 households.

Population proportion (p) = 0.34

Sample size (n) = 196

Sample proportion (p') = 0.35

Standard error of proportion (p') = √[p*(1-p)/n] = √[(0.34*0.66)/196] = 0.044

To find the probability that the sample proportion is less than 0.35, we need to find the z-score and then find the area to the left of that z-score using a standard normal distribution table.

z-score = (p' - p) / σp' = (0.35 - 0.34) / 0.044 = 2.27 (approx)

Using a standard normal distribution table, the area to the left of the z-score 2.27 is 0.9884.

Therefore, there is a roughly 0.9884 percent chance that the sample proportion of households paying more than $125 per week is less than 0.35.

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Answer: 37

Step-by-step explanation:

STEP 1: Write out the equation; 89 - 4^2 (4) + 12

STEP 2: Determine 4^2 [16]

STEP 3: Rewrite the equation to reflect the above step; 89 - 16 (4) + 12
STEP 4: Determine 16 (4) [64]

STEP 5: Rewrite the equation to reflect the above step; 89 - 64 + 12

STEP 6: Determine 89 - 64 + 12 [37]

Therefore, the answer is 37.

NOTE: Following PEMDAS for these types of problems is very helpful. Feel free to message me if you have any questions.

The experimental probability of selecting a Moon Snail is approximately 0.16.

Probability is the branch of mathematics concerned with measuring the likelihood or probability of an event occurring.

It is a numeric value from 0 to 1, with 0 indicating that the event is not possible and 1 indicating that the event is certain to occur. 

The experimental probability of selecting a Moon Snail can be calculated by dividing the number of Moon Snails by the total number of seashells selected.

The total number of seashells selected is:

33 + 14 + 8 + 15 + 20 = 90

The number of Moon Snails selected is 14.

So the experimental probability of selecting a Moon Snail is:

14/90 = 0.155 or approximately 0.16

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Area under the standard normal curve is 0.8558.

To find the area under the standard normal curve between z = -1.46 and z = 1.46, follow these steps:

1. Find the area between z = 0 and z = 1.46: Since the area between z = -1.46 and z = 0 is given as 0.4279, and the standard normal curve is symmetrical, the area between z = 0 and z = 1.46 is also 0.4279.

2. Add the areas between z = -1.46 and z = 0, and between z = 0 and z = 1.46: 0.4279 + 0.4279 = 0.8558.

Area under the standard normal curve z = -1.46 and z = 1.46 is 0.8558.

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No, the expression -x^2 + 6x - 9 cannot be non-negative for all values of x.

The expression -x^2 + 6x - 9 cannot be non-negative for all values of x.

To see this, note that the leading coefficient of the quadratic term is negative, which means that the graph of the function is a downward-facing parabola.

The vertex of the parabola occurs at x = -b/(2a) = -6/(2*(-1)) = 3, and the value of the function at this point is -(-3)^2 + 6*(-3) - 9 = -18.

Since the value of the function at the vertex is negative, and the graph of the function is a downward-facing parabola, the function is negative for all x values to the left and right of the vertex, and thus can never be non-negative for all values of x.

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The perimeter of the rectangle is 2(sqrt(82) + 4) units.

what is perimeter?

Perimeter is the total distance around the outside of a two-dimensional shape. It is the sum of the lengths of all the sides of the shape. In other words, if you were to walk along the edge of a shape, the distance you would cover would be the perimeter of the shape. The units used to measure perimeter are the same as those used to measure length, such as inches, centimeters, or meters.

Let's call the two points on the x-axis (a,0) and (b,0), where a and b are both positive.

Since the rectangle has an area of 54 square units, we know that:

length x width = 54

We also know that one point is located at (5,9), so the length of the rectangle must be the distance between (5,9) and (a,0) or (b,0). Similarly, the width must be the distance between (5,9) and (a,0) or (b,0).

Let's first find the length. The distance formula gives us:

length = sqrt((5-a)^2 + 9^2) or sqrt((5-b)^2 + 9^2)

Next, let's find the width. Again, using the distance formula, we have:

width = sqrt((a-b)^2 + 0^2)

Now we can use the fact that the area of the rectangle is 54 to solve for a and b.

54 = length x width

54 = sqrt((5-a)^2 + 9^2) x sqrt((a-b)^2 + 0^2)

54 = sqrt((5-a)^2 x (a-b)^2 + 0^2)

2916 = (5-a)^2 x (a-b)^2

Since a and b are both positive, we know that 5 > a > b. Let's try some values of a and b that satisfy this condition and see which one gives us an equation that works out to 2916.

If a = 4 and b = 2, we get:

2916 = (5-4)^2 x (4-2)^2 = 4

This doesn't work. Let's try a = 3 and b = 2:

2916 = (5-3)^2 x (3-2)^2 = 4

Still doesn't work. Let's try a = 6 and b = 2:

2916 = (5-6)^2 x (6-2)^2 = 16

This works! So the two points on the x-axis are (2,0) and (6,0).

Now we can find the length and width:

length = sqrt((5-6)^2 + 9^2) = sqrt(82)

width = sqrt((6-2)^2 + 0^2) = 4

Finally, we can find the perimeter:

perimeter = 2 x length + 2 x width

perimeter = 2 x sqrt(82) + 2 x 4

perimeter = 2(sqrt(82) + 4)

Therefore, the perimeter of the rectangle is 2(sqrt(82) + 4) units.

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Answer:

c) $ 1013.00

Step-by-step explanation:

Cost per meter of wallpaper = $6.49

So, we need the amount needed to be in the same unit i.e. meters.

1 Feet = 0.3048

So, 512 Feet = 156.0576 or 156 meters.

Cost of total wallpaper = 156 * 6.49 = $ 1012.44

So, the option which matches 1012.44 here approximately is c) $ 1013.00

Answer:

1,013.00

Step-by-step explanation:

0.3048 meters =1 foot

156.058 meter=512.0013123feet

156.058* 6.49=1012.81642

since there is a 8 after the decimal round up

1,013.00

If in the summation formula n starts at n=n0 the starting index  n0 is 2

The given series can be written as:

∑n=n0[infinity]an = (x-7)³/(x-7)⁶³* 2! + (x-7)⁹⁹/(x-7)¹²²⁷ * 3! + ...

We can simplify this expression by canceling out the common factor of (x-7) in each term of the series. This gives:

∑n=n0[infinity]an = (x-7)⁻⁶⁰ * 2! + (x-7)⁻¹¹²⁸ * 3! + ...

Now, we can see that each term in the series has the form:

an = [tex]k!/[(x-7)^{(3k-60)}][/tex]

where k is the index of the term and k ≥ 2, since the first two terms in the original series were combined into the first term of the simplified series.

Therefore, the starting index of the series is n0 = 2.

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The lifecycle cost of the clothes washer is $1,032.68.

The lifecycle cost of the clothes washer is $1,104.20. Here's how to compute it:Given:Energy consumed by the clothes washer = 198 kWhPrice of the washer = $389Lifetime of the washer = 14 yearsEnergy price in the city = 8 cents per kWhMaintenance cost = $17 per yearFormula: Lifecycle cost = (purchase price + (energy price x energy consumed) + (maintenance cost x lifetime)) / lifetimeLet's substitute the given values in the formula:Lifecycle cost = ($389 + ($0.08 x 198 kWh) + ($17 x 14)) / 14Lifecycle cost = ($389 + $15.84 + $238) / 14Lifecycle cost = $642.84 / 14Lifecycle cost = $45.92 (rounded to two decimal places).

The lifecycle cost of the clothes washer is $45.92 per year. To find the total lifecycle cost, multiply it by the lifetime of the washer:Total lifecycle cost = $45.92 x 14Total lifecycle cost = $643.68Add the initial cost of the washer to get the final answer:Final answer = $643.68 + $389Final answer = $1,032.68 (rounded to two decimal places)

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The minimum amount of green paint he has to throw away so he can use  rest to add blue or yellow paint in order to get exactly 5 liters of correct shade of green is 5/3 liter.

We know that "original-shade" of green color requires "2-liters" of blue paint and "3-liters" of yellow paint.

So, the original-ratio of "yellow-paint" to "total-paint" is = 3 : 5,

He mixes 3-litres of "blue" and 2-litres of "yellow" for 5 liters of paint,

So, he has more blue-paint in mixture than it is required to make green color,

He needs to throw some of green-paint and add yellow-paint to get required shade-of-green.

Let the painter throw away "x-liters" of paint from his mixture and adds "x-liters" of yellow-paint into mixture.

So, New mixture will have same ratio as 3:5,

So, the equation in x is,

⇒ (2/5)×(5 - x) + x = (3/5)×5,

⇒ 2 - (2/5)x + x = 3,

⇒ (3/5)x = 1,

⇒ x = 5/3.

Therefore, the painter needs to throw away 5/3 liters of paint.

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To find the price that maximizes revenue, we need to find the critical points of the function R(x) and set it equal to zero. We should also check that this critical point is a maximum and not a minimum or inflection point, since the second derivative is negative at x = 70.

The questions on the midterm exam will cover every topic, including created and actual places and also algebraic variable design. a diagram showing the relationships between different elements that cooperate to create the same result. A service is composed of numerous distinctive components that cooperate to create distinctive results for each input.

This is true when[tex]x = 0 or x = -70[/tex]. Therefore, the company makes no revenue if it charges $0 or -$70 per unit. Of course, charging a negative price doesn't make sense, so the only answer that makes sense is $0 per unit.

a) The company makes no revenue when the revenue function, R(x), is equal to zero. So we have:

[tex]R'(x) = 26250 + 750x - 475x^2 = 0[/tex]

b) To find the price that maximizes revenue, we need to find the value of x that maximizes the revenue function, R(x). We can do this by taking the derivative of R(x) with respect to x and setting it equal to zero:

Solving for x gives us two solutions: [tex]x = 0 and x = 55.26[/tex]. However, we know that x = 0 gives us zero revenue, so the only solution that makes sense is x = 55.26.

Therefore, the company should charge $55.26 per unit to maximize its revenue.

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Therefore , the solution of the given problem of expressions comes out to be  the picture of a point P(x,y) on FG will be P'(-x,y), which is P'reflected across the y-axis.

Instead of using approximations produced at random, it is better to use shifting integers that may prove increasing, reducing, or blocking. They could only help one another by sharing materials, information, or solutions to issues. The justifications, components, or mathematical remarks for techniques like additional disapproval, production, and mixture may be included in a statement of truth equation.

Here,

The x-coordinates of all the locations on FG are transformed when FG is reflected across the y-axis, but the y-coordinates stay the same. As a result, the algebraic formula that characterizes this reflection is as follows:

(-x, y)

As a result, the picture of a point P(x,y) on FG will be P'(-x,y), which is P'reflected across the y-axis.

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Therefore , the solution of the given problem of number line comes out to be D, {-6}, {-3}, {5}, {-6, -3}, {-6, 5}, {-3, 5}.

The number line, a representation of real numbers in visual form, is a tool for teaching arithmetic. An energy line is depicted by it. Every actual number is used to represent a integer in the genuine number, or every exact number is used to represent a position. The separations between increments on a number line are identical. The numbers in a line can only be replied in the manner indicated by those numbers.

Here,

The set D = "-6, -3, 5" can be divided into a wide variety of subgroups, including:

Since the empty set is a subset of every set, D is a subset of the empty set.

The set D is a subgroup of itself.

=> Because -6 is an element of D, the collection "{-6}" is a subset of D.

=> Because -3 is an element of D, the collection "{-3}" is a subset of D.

=> Because 5 is an element of D, the collection "{5}" is a subset of D.

Due to the fact that both -6 and -3 are components of D, the set "{-6, -3}" is a subset of D.

=> Because both -3 and 5 are elements of D, the collection "{-3, 5}" is a subset of D.

Consequently, the subgroups of D are:, D, {-6}, {-3}, {5}, {-6, -3}, {-6, 5}, {-3, 5}.

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it is known that carbon-14 has a half-life of approximately 5,700 years. This means that after   [tex]5,700[/tex] years, half of the original carbon-14 in a sample will have decayed.

Assuming that t is a function that relates the age of a plant fossil to the percentage of carbon-14 remaining, it can be expressed as:

[tex]t(c) = (ln(c/100) / ln(1/2)) \times 5,700 years[/tex]

where ln represents the natural logarithm.

Using this function, we can complete the statements as follows:

A fossil with 47% of its carbon-14 remaining is approximately 11,323 years old.

[tex]t(47) = (ln(47/100) / ln(1/2)) \times 5,700 ≈ 11,323 y[/tex]   years

A fossil that is [tex]7,000[/tex] years old will have approximately 28% of its carbon-14 remaining.

  [tex]t-1(7,000) = (ln(100/1) / ln(1/2)) \times 5,700 - 7,000 ≈ 23,200[/tex] years remaining

[tex]t-2(c) = (ln(c/100) / ln(1/2)) * 5,700[/tex]

[tex]c = 100 * e^(-7,000 / 5,700) ≈ 28% remaining.[/tex]

Therefore, In the second statement, we are using the inverse of the function t to find the percentage of carbon-14 remaining for a given age. We can write this as  [tex]t-1(7,000) = c,[/tex] where c is the percentage of carbon-14 remaining for a fossil that is   [tex]7,000[/tex] years old.

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the solution to this system of equations is x=5 and y=16.

2x + 6 = 3x + 1

Subtract 2x from both sides:

6 = x + 1

Subtract 1 from both sides:

5 = x

Solve for y:

y = 3(5) + 1

y = 16

The substitution method is used to solve a system of equations by replacing one of the variables with an expression containing the other variable. In this system of equations, we have Y=3x+1 and 2x+6=y. To solve this, we start with the second equation and subtract 2x from both sides to get 6 = x + 1. Subtracting 1 from both sides gives us 5 = x. Now that we have x = 5, we can use this to solve for y. We substitute 5 for x in the first equation, giving us y = 3(5) + 1, which simplifies to y = 16. Therefore, the solution to this system of equations is x=5 and y=16.

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Answer:

Annie jumps 34.56 cm (approximately)

Step-by-step explanation:

Since we know that Annie jumps 8% higher than Rosie, we can add the 8% increase to the height that Rosie jumped.

32 cm + 2.56 cm = 34.56 cm

Therefore, Annie jumped approximately 34.56 cm in the air, which is 8% higher than the height that Rosie jumped.

Step-by-step explanation:

To find out how high Annie jumped, you first need to calculate what 8% of Rosie's jump height is, and then add this amount to Rosie's jump height.

To calculate 8% of Rosie's jump height, you can multiply 32cm by 8% expressed as a decimal, which is 0.08:

8% of 32cm = 0.08 x 32cm = 2.56cm

So Annie jumped 2.56cm higher than Rosie's jump of 32cm.

To find out how high Annie jumped, you can add 2.56cm to Rosie's jump height:

Annie's jump height = Rosie's jump height + 2.56cm

= 32cm + 2.56cm

= 34.56cm

Therefore, Annie jumped 34.56cm in the air.

The equation of a line whose slope is 2 and passes through the point (3,1) is y=2x-5

An unending, one-dimensional figure with no width is a straight line. It consists of an infinite number of points connected on either side of a point. There is no curvature in a straight line. It might be angled, vertical, or horizontal. Every angle we draw between any two locations along a straight line will always be a 180-degree angle. We will explore the universe of straight lines in this mini-lesson by comprehending the equations of straight lines in various formats and learning how to answer problems based on straight lines.

The equation of a line whose slope is m and passes through the point (h,k),

y-k=m(x-h)

y=m(x-h)+k

We have a line with slope 2 and passes through the point (3,1)

y= 2(x-3)+1

y= 2x-6+1

y=2x-5

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Answer:

4 times

Step-by-step explanation:

Find the perimeter of the rectangular field

P=2(L+W)➡️ L is for length, W is for width

P=2(150+100)=2(250)=500m

After that, you need to convert 2KM into metres

So, 2×1000=2000m

Then divide the number of metres the runner would run by the perimeter of the rectangular field

2000/500=4 times

Therefore, the runner will go around the field 4 times

Therefore, the length of each side of the original square is 5 cm.

Area is a measure of the size of a two-dimensional surface or region. It is the amount of space enclosed by a boundary in two dimensions. In simple terms, area is the size of a flat surface, such as the floor, a wall, or a piece of paper. It is usually measured in square units such as square meters (m²), square centimeters (cm²), square feet (ft²), or acres.

Here,

Let x be the length of each side of the original square.

When the length of each side is increased by 10 cm, the new length is x + 10, and the area of the new square is (x + 10)².

According to the problem, the increase in area is 200 cm², so we can set up the equation:

(x + 10)² - x² = 200

Expanding the left side of the equation, we get:

x² + 20x + 100 - x² = 200

Simplifying, we get:

20x + 100 = 200

Subtracting 100 from both sides, we get:

20x = 100

Dividing both sides by 20, we get:

x = 5

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The dimensions that will minimize the cost of the metal to manufacture the can are,

Radius = 4.08 cm

Height = 10.84 cm

To minimize the cost of the metal to manufacture the can, we need to minimize the surface area of the can. The surface area of a cylinder is given by

A = 2πrh + 2πr^2

where r is the radius of the cylinder, h is the height of the cylinder, and π is a constant equal to approximately 3.14159.

We are given that the can needs to hold 1.4 liters of oil. We can use this information to find the relationship between the radius and height of the cylinder. The volume of a cylinder is given by

V = πr^2h

Substituting the given volume of 1.4 liters (1400 cubic centimeters) and the constant π, we get

1400 = 3.14159r^2h

Solving for h, we get

h = 1400/(3.14159r^2)

Now we can substitute this expression for h in the formula for the surface area of the cylinder to get

A = 2πr(1400/(3.14159r^2)) + 2πr^2

Simplifying this expression, we get

A = (2800/πr) + 2πr^2

To minimize the surface area, we need to find the value of r that makes the derivative of A with respect to r equal to zero. Taking the derivative, we get

dA/dr = -2800/πr^2 + 4πr

Setting this equal to zero and solving for r, we get:

-2800/πr^2 + 4πr = 0

2800/πr^2 = 4πr

r^3 = 700/π

r ≈ 4.08 cm

Now we can use the formula for h in terms of r to find the corresponding value of h

h = 1400/(3.14159(4.08)^2) ≈ 10.84 cm

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The steady-state surface temperature of the heater is estimated to be 91.7°C.

To solve this problem, we need to apply the energy balance equation, which states that the heat transferred to the heater must be equal to the heat dissipated by the heater. Assuming steady-state conditions and neglecting radiation, the energy balance equation can be written as

q_conv = q_gen

where q_conv is the heat transferred to the heater by convection, and q_gen is the heat generated by the electrical energy dissipated per unit length of the heater.

The heat transferred to the heater by convection can be calculated using the following equation

q_conv = hA(T_s - T_inf)

where h is the convective heat transfer coefficient, A is the surface area of the heater, T_s is the surface temperature of the heater, and T_inf is the temperature of the air in the duct.

The convective heat transfer coefficient can be estimated using the Dittus-Boelter correlation for cross-flow over cylinders

Nu_D = 0.3 + (0.62*Re_D^(1/2)Pr^(1/3))/(1 + (0.4/Pr)^(2/3))^(1/4)(1+(Re_D/282000)^(5/8))^(4/5)

where Nu_D is the Nusselt number for the cylinder, Re_D is the Reynolds number for the cylinder, and Pr is the Prandtl number for the air. The Reynolds number and Prandtl number can be calculated as

Re_D = rhovD/mu

Pr = Cp*mu/k

where rho is the density of air, v is the velocity of air, mu is the dynamic viscosity of air, Cp is the specific heat of air at constant pressure, and k is the thermal conductivity of air.

Substituting the expressions for Nu_D, Re_D, and Pr into the following equation gives the convective heat transfer coefficient:

h = Nu_D*k/D

Substituting the given values into the above equations, we get

Re_D = 2700200.01/1.8e-5 = 3e6

Pr = 0.71

Nu_D = 0.3 + (0.623e6^(1/2)0.71^(1/3))/(1 + (0.4/0.71)^(2/3))^(1/4)(1+(3e6/282000)^(5/8))^(4/5) = 250

h = Nu_Dk/D = 250*240/0.01 = 6e4 W/m2.K

The heat generated per unit length of the heater is given as q_gen = 2000 W/m.

Substituting the above values into the energy balance equation, we get

hA(T_s - T_inf) = q_gen

The surface area of the heater can be calculated as

A = piDL

where L is the length of the heater. Assuming a unit length of the heater, we have L=1m. Thus,

A = pi0.011 = 0.0314 m2

Substituting the values of h, A, T_inf, and q_gen into the energy balance equation and solving for T_s, we get:

T_s = T_inf + q_gen/(hA) = 27 + 2000/(6e40.0314) = 91.7°C

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The given question is incomplete, the complete question is:

A long, cylindrical, electrical heating element of diameter D = 10 mm, thermal conductivity k = 240 W/m-K, density p = 2700 kg/m3, and specific heat Cp = 900 J/kg.k is installed in a duct for which air moves in cross flow over the heater at a temperature and velocity of 27°C and 20 m/s, respectively. Neglecting radiation, estimate the steady-state surface temperature when, per unit length of the heater, electrical energy is being dissipated at a rate of 2000 W/m.

Raphael bought a 2/3 pound bag of sugar, and he used 3/4 of it for baking.

To find out how much sugar he used, we need to multiply the fraction of the bag that he used (3/4) by the weight of the bag (2/3 pounds):

(3/4) x (2/3) pounds

To simplify this fraction multiplication, we can cancel out the factor of 3 in the numerator and the denominator:

(1/4) x (2/1) pounds

= 2/4 pounds

= 1/2 pound

Therefore, Raphael used 1/2 pound of sugar for baking.

Volume =  Length * Width * Height

Length = l = 15,5 in = 393,7 cm

Width = w = 11,2 in = 284,48 cm

Height = h = 8 in = 20,32 cm

Volume =  15,5 * 11,2 * 8 = 1388,8 in or 35275.52 cm

Answer:

D

Step-by-step explanation:

After one rotation of the carousel, after 6.2 more meters has Mei traveled than Anju.

Circumference of Circle:

The circumference of a circle or the circumference of a circle is a measurement of the limit of a circle. Whereas the area of ​​a circle defines the area it occupies. If we open a circle and draw a line through it, its length is the circumference. It is usually measured in units such as centimeters or units of meters.

As we know carousel  is circular

Therefore,

distance covered will be the circumference of a circle

Now,

we know that the circumference of the circle = 2πr where r is the radius

Mei's horse is 3 m away from the carousel  i.e r = 3 m

Distance covered by Mei's =  2π × 3 = 6π m

Anju's horse is 2 m away from the carousel i.e r = 2 m

Distance covered by Anju = 2π × 2 =4π

Mei traveled more = 6π - 4π = 2π m

                                               ≈ 6.2 m

Complete Question:

Mei and Anju are sitting next to each other on different horses on a carousel. Mei’s horse is 3 meters from the center of the carousel. Anju’s horse is 2 meters from the center. After one rotation of the carousel, how many more meters has Mei traveled than Anju?

Learn more about Meters:

https://brainly.com/question/29367164

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Answer:

The shaded plants set has greater variability because more data is clustered around the median. "NC"The sets are equally variable because the ranges of the data sets are equal.The full sun plants set has greater variability because the IQR for full sun plants is greater. The full sun plants set has greater variability because the median for full sun plants is greater.

Step-by-step explanation:

The shaded plants can always get a greater variability because remember more data around the median. The sets would eventually equal the variable.

Sun plans can get greater variability because the median can always be used for sun plants and which is being called greater.

Answer:

x= y + 5

Step-by-step explanation:

This is simple linear equations!

y = x - 5  

Add 5 to both sides, and you get

y + 5 = x!