Evaluate the expression. −3[−4(3−10)−12] over −2(−1) What is the value of the expression?

Answer:

|5x - 1| < 1

-1 < 5x - 1 < 1

0 < 5x < 2

0 < x < 2/5

The height of the antenna is approximately 5.1 feet.

1. Let's assume the height of the antenna as 'h' feet.

2. We have two angles of elevation: 5 degrees and 10 degrees.

3. When the person is 1 mile closer to the antenna, the change in the angle of elevation is 10 - 5 = 5 degrees.

4. We can use the tangent function to find the height of the antenna. The tangent of an angle is equal to the opposite side divided by the adjacent side.

5. The opposite side is the change in height, which is h feet (since the person moved closer by 1 mile, the change in height is equal to the height of the antenna).

6. The adjacent side is the horizontal distance from the person to the antenna. We can use trigonometry to find this distance.

7. In a right triangle, the tangent of an angle is equal to the ratio of the opposite side to the adjacent side.

  tan(5 degrees) = h / x (where x is the horizontal distance in miles)

8. Similarly, after moving closer, the tangent of the angle becomes:

  tan(10 degrees) = h / (x - 1)

9. We can solve these two equations simultaneously to find the value of h.

10. Rearranging the equations, we get:

  h = x * tan(5 degrees)

  h = (x - 1) * tan(10 degrees)

11. Setting the two expressions for h equal to each other, we have:

  x * tan(5 degrees) = (x - 1) * tan(10 degrees)

12. Solving this equation for x, we find:

  x = tan(10 degrees) / (tan(10 degrees) - tan(5 degrees))

13. Substitute the value of x back into one of the earlier equations to find h:

  h = x * tan(5 degrees)

14. Calculate the value of h using a calculator:

  h ≈ 1 * tan(5 degrees) ≈ 0.0875 miles ≈ 0.0875 * 5280 feet ≈ 461.4 feet

15. Rounded to the nearest tenth of a foot, the height of the antenna is approximately 5.1 feet.

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The graph in this problem is the graph of y = 2sin(x), not y = x, as it has a amplitude of 2.

The standard definition of the sine function is given as follows:

y = Asin(B(x - C)) + D.

For which the parameters are given as follows:

The function in this problem has an amplitude of 2, with no phase shift, no vertical shift and period of 2π, hence it is defined as follows:

y = 2sin(x)

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The number of votes needed in an election can vary depending on various factors such as the type of election, voting rules, and specific requirements.

Without additional context or information about the specific election, it is challenging to provide an exact number of votes needed.The number of votes needed in an election is typically determined by factors such as the majority threshold, minimum vote requirement, or any specific criteria outlined in the election rules.

For example, in some elections, a candidate may need a simple majority (more than half) of the votes cast to win, while in others, a candidate may need a specific number or percentage of votes to secure victory.To determine the number of votes needed, it is essential to refer to the specific guidelines or rules established for that particular election.

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The solution for p=2l+2w, the value of w= 3 units.

To solve the equation p = 2l + 2w for w, we will follow the steps below:

Step 1: Start with the given equation: p = 2l + 2w.

Step 2: To isolate the variable w, we need to get rid of the terms involving l. We can do this by subtracting 2l from both sides of the equation:

p - 2l = 2w.

Step 3: Next, we want to solve for w. To do this, we divide both sides of the equation by 2:

(p - 2l) / 2 = w.

Step 4: Simplify the expression on the right side:

w = (p - 2l) / 2.

Now, let's apply this formula to a specific example. Suppose we have a rectangle with a perimeter of 16 units (p = 16) and a length of 5 units (l = 5). We can find the width (w) using the formula:

w = (16 - 2(5)) / 2

w = (16 - 10) / 2

w = 6 / 2

w = 3.

By following the steps outlined above and substituting the given values of the perimeter (p) and length (l) into the formula w = (p - 2l) / 2, you can determine the value of the width (w) for any given rectangle.

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The system B is gotten from system A by operation (d)

From the question, we have the following parameters that can be used in our computation:

x + y = 8

4x - 6y = 2

Also, we have the solution to be (5, 3)

Recall that

x + y = 8

4x - 6y = 2

Multiply the first equation by 6

So, we have

6x + 6y = 48

4x - 6y = 2

Add the equations

10x = 50

This means that the system B from system A is (d)

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5 whole numbers are written in order. 5,8,x,y,12 The mean and median of the five numbers are the same then the values of x and y are:[tex]$$\boxed{x=8, \ y=3}$$[/tex] OR [tex]$$\boxed{x=12, \ y=53}$$[/tex].

let's first calculate the median of the given numbers.

Median of the given numbers is the middle number of the ordered set.

As there are five numbers in the ordered set, the median will be the third number.

Thus, the median of the numbers = x.

The mean of a set of numbers is the sum of all the numbers in the set divided by the total number of items in the set.

Let the mean of the given set be 'm'.

Then,[tex]$$m = \frac{5+8+x+y+12}{5}$$$$\Rightarrow 5m = 5+8+x+y+12$$$$\Rightarrow 5m = x+y+35$$[/tex]

As per the given statement, the median of the given set is the same as the mean.

Therefore, we have,[tex]$$m = \text{median} = x$$[/tex]

Substituting this value of 'm' in the above equation, we get:[tex]$$x= \frac{x+y+35}{5}$$$$\Rightarrow 5x = x+y+35$$$$\Rightarrow 4x = y+35$$[/tex]

Also, as x is the median of the given numbers, it lies in between 8 and y.

Thus, we have:[tex]$$8 \leq x \leq y$$[/tex]

Substituting x = y - 4x in the above inequality, we get:[tex]$$8 \leq y - 4x \leq y$$[/tex]

Simplifying the above inequality, we get:[tex]$$4x \geq y - 8$$ $$(5/4) y \geq x+35$$[/tex]

As x and y are both whole numbers, the minimum value that y can take is 9.

Substituting this value in the above inequality, we get:[tex]$$11.25 \geq x + 35$$[/tex]

This is not possible.

Therefore, the minimum value that y can take is 10.

Substituting y = 10 in the above inequality, we get:[tex]$$12.5 \geq x+35$$[/tex]

Thus, x can take a value of 22 or less.

As x is the median of the given numbers, it is a whole number.

Therefore, the maximum value of x can be 12.

Thus, the possible values of x are:[tex]$$\boxed{x = 8} \text{ or } \boxed{x = 12}$$[/tex]

Now, we can use the equation 4x = y + 35 to find the value of y.

Putting x = 8, we get:

[tex]$$y = 4x-35$$$$\Rightarrow y = 4 \times 8 - 35$$$$\Rightarrow y = 3$$[/tex]

Therefore, the values of x and y are:[tex]$$\boxed{x=8, \ y=3}$$[/tex]  OR [tex]$$\boxed{x=12, \ y=53}$$[/tex]

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The x-axis represents the values of x, and the y-axis represents the values of y. The first point (0, 11/2) lies on the y-axis, at a height of 11/2. The second point (2, 17/2) lies to the right of the y-axis, at a height of 17/2. The third point (-3, 1) lies to the left of the y-axis, at a height of 1.

To find three points that satisfy the equation -3x + 2y = 11, we can arbitrarily assign values to either x or y and solve for the other variable. Let's choose to assign values to x and solve for y:

Let x = 0:

-3(0) + 2y = 11

2y = 11

y = 11/2

The first point is (0, 11/2).

Let x = 2:

-3(2) + 2y = 11

-6 + 2y = 11

2y = 11 + 6

2y = 17

y = 17/2

The second point is (2, 17/2).

Let x = -3:

-3(-3) + 2y = 11

9 + 2y = 11

2y = 11 - 9

2y = 2

y = 1

The third point is (-3, 1).

Now let's plot these points on a graph:

The x-axis represents the values of x, and the y-axis represents the values of y. The first point (0, 11/2) lies on the y-axis, at a height of 11/2. The second point (2, 17/2) lies to the right of the y-axis, at a height of 17/2. The third point (-3, 1) lies to the left of the y-axis, at a height of 1.

By plotting these three points on the graph, you will have a visual representation of the solutions to the equation -3x + 2y = 11.

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The money raised by Lucas for the fundraiser is $30.

The bars sold on Saturday are 12 bars. Each bar costs $1.50.

So, the amount will be:  12 * 1.50 = 18

The bars sold on Sunday are  8 bars.

So, the amount will be:  8 * 1.50 = 12

Hence, the total amount: is 18+12= 30

The equation of the conic section in conic form is (x - 1) = (y + 6)²/4.

To write the equation of the conic section in conic form, we can complete the square to transform the equation into its standard form. Let's start with the given equation:

y² - 4x + 12y + 32 = 0

Rearranging the terms, we have:

y² + 12y - 4x + 32 = 0

To complete the square for the y-terms, we add and subtract the square of half the coefficient of y (which is 6 in this case):

y² + 12y + 36 - 36 - 4x + 32 = 0

Simplifying this, we get:

(y + 6)² - 4x + 4 = 0

Now, rearranging the terms, we have:

(y + 6)² = 4x - 4

Dividing both sides of the equation by 4, we get:

(y + 6)²/4 = x - 1

Finally, we can write the equation in conic form:

(x - 1) = (y + 6)²/4

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The Probable question may be:
Which type of conic section is defined by the equation y²-4x+12y + 32 = 0?

This is an equation of a parabola

Write the equation of this conic section in conic form:

Answer:

Step-by-step explanation:

1. The system of inequalities that models this scenario can be represented as:

Let x be the number of servings of dry food.

Let y be the number of servings of wet food.

The cost constraint:

1x + 5y ≤ 15

The minimum number of dogs constraint:

x + y ≥ 4

2. The graph of the system of inequalities would be a shaded region in the coordinate plane.

To graph the inequality 1x + 5y ≤ 15, we can first graph the equation 1x + 5y = 15 (the corresponding boundary line) by finding two points on the line and connecting them. For example, when x = 0, y = 3, and when y = 0, x = 15. Plotting these points and drawing a line through them will represent the equation 1x + 5y = 15.

Next, we need to shade the region below the line because the inequality is less than or equal to (≤). This shaded region represents the solutions that satisfy the cost constraint.

To graph the inequality x + y ≥ 4, we can again find two points on the line x + y = 4 (the corresponding boundary line). For example, when x = 0, y = 4, and when y = 0, x = 4. Plotting these points and drawing a line through them will represent the equation x + y = 4.

Lastly, we shade the region above the line x + y = 4 because the inequality is greater than or equal to (≥). This shaded region represents the solutions that satisfy the minimum number of dogs constraint.

The solution set is the overlapping region where the shaded areas of both inequalities intersect. This region represents the combination of servings of dry food and wet food that Michelle can purchase within her budget ($15) to feed at least four dogs at the animal shelter.

The inequalities D + W > 4 and D + 5W ≤ 15 model the problem. The graph represents these inequalities, with the overlap of shaded regions showing possible food serving combinations.

Let's define D as the number of servings of dry food and W as the number of servings of wet food. The system of inequalities that models this scenario is:

The graph will show the solution sets to the inequalities. D and W must both be non-negative, hence the graphed area is in the first quadrant. The first inequality requires shading above a line that connects (0,4) and (4,0). This line is solid since numbers equal to 4 are included. The second inequality requires shading below a line that connects (0,3) and (15,0). This is also a solid line because Michelle can spend exactly $15. The overlapping region of the graph is the solution set, quantifying the combinations of dry and wet food servings that Michelle can buy.

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Answer:

π(2^2 - .75^2) = 55π/16 m² = 10.8 m²

D is the correct answer.

A set S is T-finite if it satisfies Tarski's finite set condition, which states that for every nonempty subset X of P(S), there exists a maximal element u in X such that there is no v in X with u as a proper subset of v and u is distinct from v. If a set does not satisfy this condition, it is considered T-infinite.

In set theory, a set S is said to be T-finite if it satisfies a particular property called Tarski's finite set condition. This condition states that for every nonempty subset X of the power set of S (denoted as P(S)), there exists a maximal element u in X such that there is no element v in X that properly contains u (i.e., u is not a proper subset of v) and u is distinct from v.

To understand this concept, let's break it down further:

T-finite set: A set S is T-finite if, for any nonempty subset X of P(S), there exists an element u in X that is maximal. This means that u is not properly contained in any other element in X.

Maximal element: In the context of Tarski's finite set condition, a maximal element refers to an element u in X that is not a proper subset of any other element in X. In other words, there is no v in X such that u is a proper subset of v.

Distinct elements: This means that u and v are not the same element. In the context of Tarski's finite set condition, u and v cannot be equal to each other.

T-infinite set: A set S is T-infinite if it does not satisfy Tarski's finite set condition. This means that there exists a nonempty subset X of P(S) for which no maximal element u can be found, or there exists an element v in X that properly contains another element u.

In conclusion, a set S is T-finite if it meets Tarski's finite set condition, which asserts that there exists a maximal element u in X such that there is no v in X with v as a proper subset of u and u is different from v. A set is regarded as T-infinite if it does not meet this requirement.

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A suitable delta (δ) for ε = 0.01 is any positive value smaller than √6.

To find a suitable delta (δ) for the given limit, we need to consider the epsilon-delta definition of a limit.

The definition states that for a given epsilon (ε) greater than zero, there exists a delta (δ) greater than zero such that if the distance between x and the limit point (2, in this case) is less than delta (|x - 2| < δ), then the distance between the function (√x + 7) and the limit (3) is less than epsilon (|√x + 7 - 3| < ε).

Let's solve the inequality |√x + 7 - 3| < ε:

|√x + 7 - 3| < ε

|√x + 4| < ε

-ε < √x + 4 < ε

To remove the square root, we square both sides:

(-ε)^2 < (√x + 4)^2 < ε^2

ε^2 > x + 4 > -ε^2

Since we're interested in the interval around x = 2, we substitute x = 2 into the inequality:

ε^2 > 2 + 4 > -ε^2

ε^2 > 6 > -ε^2

Since ε > 0, we can drop the negative term and solve for ε:

ε^2 > 6

ε > √6

Please note that this solution assumes the function √x + 7 approaches the limit 3 as x approaches 2. To verify the solution, you can substitute different values of δ and check if the conditions of the epsilon-delta definition are satisfied.

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Answer:

Number of Females in Class = x Given: Ratio of Males to Females = 2:3 Given: Number of Males in Class = 12 Assume the total number of people in class = y 2/3 of y = x 2x = 3y 12 + x = y y - 12 = x y - 12 = 2x 3y - 36 = 2x 3y = 2x + 36 y = (2x + 36) / 3 y = (2(12) + 36)/3 y = 24 x = y - 12 x = 24 - 12 x = 12 Answer: There are 12 females in the class.

Step-by-step explanation:

After solving by formula the second expression is y =  [tex](x^2 + 1)[/tex].

We know that the product of the HCF and LCM of two numbers is equal to the product of the numbers themselves. In this case, we can apply the same principle to expressions:

HCF * LCM = (x + 1) *  [tex](x^3+ x^2 - x - 1)[/tex]

the first number is [tex]x^{2} -1\\[/tex] and  let the second number is y

Therefore, we can set up the equation:

(x + 1) *  [tex](x^3+ x^2 - x - 1)[/tex] =  [tex]x^{2} -1\\[/tex]  * y

[tex]x^4 + x^3 + x^2 - x^3 - x^2 + x - x - 1 = x^2 - 1 * y[/tex]

Simplifying:

[tex]x^4 - 1 = (x^2 - 1) * y[/tex]

Now, we can divide both sides by [tex](x^2 - 1)[/tex]:

[tex](x^4 - 1) / (x^2 - 1) = y[/tex]

Notice that [tex](x^2 - 1)[/tex]can be factored as (x + 1)(x - 1). Therefore, we can simplify further:

[tex](x^4 - 1) / ((x + 1)(x - 1)) = y[/tex]

The expression [tex](x^4 - 1)[/tex] can be factored using the difference of squares:

[tex](x^4 - 1) = (x^2 + 1)(x^2 - 1)[/tex]

[tex][(x^2 + 1)(x^2 - 1)] / ((x + 1)(x - 1)) = y[/tex]

Now, we can cancel out the common factor  [tex](x^2 - 1)[/tex] from the numerator and denominator:

[tex]y =(x^2 + 1)[/tex]

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Answer:

[tex]\textsf{a)} \quad \textsf{Radius = $\overline{HG}$}[/tex]

[tex]\textsf{b)} \quad \textsf{Chord = $\overline{GF}$}[/tex]

[tex]\textsf{c)} \quad \textsf{Diameter = $\overline{JF}$}[/tex]

[tex]\textsf{d)} \quad \textsf{Secant = $\overleftrightarrow{GF}$}[/tex]

[tex]\textsf{e)} \quad \textsf{Tangent = $\overleftrightarrow{GK}$}[/tex]

[tex]\textsf{f)} \quad \textsf{Point of tangency = $\overset{\bullet}{G}$}[/tex]

[tex]\textsf{g)} \quad \textsf{Circle $H$}[/tex]

Step-by-step explanation:

The radius is the distance from the center of a circle to any point on its circumference. The center of the circle is point H. Therefore, the radius of the given circle is line segment HG.

A chord is a straight line joining two points on the circumference of the circle. There are two chords in the given circle:  line segments GF and JF. Therefore, a chord of the given circle is line segment GF.

The diameter of a circle is a straight line segment passing through the center of a circle, connecting two points on its circumference.

Therefore, the diameter of the given circle is line segment JF.

A secant is a straight line that intersects a circle at two points.

Therefore, the secant of the given circle is line GF.

A tangent is a straight line that touches a circle at only one point.

Therefore, the tangent line of the given circle is line GK.

The point of tangency is the point where the line touches the circle.

Therefore, the point of tangency of the given circle is point G.

A circle is named by its center point. Therefore, as the center point of the circle is point H, the name of the circle is "Circle H".

Answer:

c

Step-by-step explanation:

add 360 to 265 to get the first number and subtract 360 from 265 to get the second number

The solution to the system is (b) (-2, 3, z) where z is any real number

From the question, we have the following parameters that can be used in our computation:

The augmented matrix

Where, we have

[tex]\left[\begin{array}{ccc|c}1&0&0&-2\\0&1&0&3\\0&0&0&3\end{array}\right][/tex]

From the above, we have the first two diagonals to be 1

And other elements to be 0

This means that

x = -2 and y = 3

For z, the value is infinitely many

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a) The mean of the data-set is of 2.

b) The range of the data-set is of 4 units, which is of around 4.3 MADs.

The mean of a data-set is obtained as the sum of all observations in the data-set divided by the number of observations in the data-set, which is also called the cardinality of the data-set.

The dot plot shows how often each observation appears in the data-set, hence the mean of the data-set is obtained as follows:

Mean = (1 x 0 + 5 x 1 + 3 x 2 + 5 x 3 + 1 x 4)/(1 + 5 + 3 + 5 + 1)

Mean = 2.

The range is the difference between the largest observation and the smallest, hence:

4 - 0 = 4.

4/0.93 = 4.3 MADs.

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Answer:

27

Step-by-step explanation:

Answer:

Assuming Miguel rolled up his sleeping bag tightly and neatly, the length and circumference of the sleeping bag can help us estimate the length of string needed to tie it up.

Let's say the length of the sleeping bag is 6 feet and the circumference (distance around) is 3 feet. To tie it up, Miguel would need to wrap the string around it 2-3 times, depending on how long the string is and how tight he ties the knot.

So, we can estimate that he used about 12-18 feet of string (i.e. 2-3 times the circumference). In inches, that would be about 144-216 inches of string (i.e. 12-18 feet * 12 inches/foot).

Keep in mind that this is just an estimate and the actual amount of string used may vary depending on the factors mentioned above.

Step-by-step explanation:

The true options are:

A. If p = a number is negative and q = the additive inverse is positive, the original statement is p → q.

B. If p = a number is negative and q = the additive inverse is positive, the inverse of the original statement is ~p → ~q.

E. If q = a number is negative and p = the additive inverse is positive, the converse of the original statement is q → p.

Option A represents the original statement accurately. It states that if a number is negative (p), then the additive inverse is positive (q). This corresponds to the implication p → q, where the antecedent is p and the consequent is q.

Option B represents the inverse of the original statement. It states that if a number is not negative (~p), then the additive inverse is not positive (~q). This is the negation of the original statement and can be written as ~p → ~q.

Option C represents the converse of the original statement. It states that if the additive inverse is not positive (~q), then the number is not negative (~p). The converse swaps the positions of the antecedent and consequent, resulting in ~q → ~p.

Options D and E are not true. Option D represents the contrapositive of the original statement, which would be if the additive inverse is not positive (~q), then the number is not negative (~p). However, the contrapositive should have the negation of both the antecedent and the consequent, so the correct contrapositive would be ~q → ~p.

Option E incorrectly represents the converse by stating that if the additive inverse is negative (q), then the number is positive (p), which is not an accurate representation of the converse.

In summary, the true options are A, B, and C, as they accurately represent the original statement, its inverse, and its converse, respectively.

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The complete question is :

Given the original statement "If a number is negative, the additive inverse is positive,” which are true? Select three options.

A. If p = a number is negative and q = the additive inverse is positive, the original statement is p → q.

B. If p = a number is negative and q = the additive inverse is positive, the inverse of the original statement is ~p → ~q.

C. If p = a number is negative and q = the additive inverse is positive, the converse of the original statement is ~q → ~p.

D. If q = a number is negative and p = the additive inverse is positive, the contrapositive of the original statement is ~p → ~q.

E. If q = a number is negative and p = the additive inverse is positive, the converse of the original statement is q → p.

Answer:

Step-by-step explanation:

$28 for 1st hr and $20per hr after that:

t = 28 +  20(h-1)

$30 for 1st hr and $20per hr after that:

t = 30 + 20(h-1)

t - 30 - 20(h-1)

Answer:

8

Step-by-step explanation:

i took the test mde 100

The net cash flow from operating activities would be $100,800.

Change in accounts receivable:

= $20,900 - $20,000

= $900

Change in inventory:

= $61,800 - $62,500

= -$700

Change in accounts payable:

= $19,700 - $18,600

= $1,100

Change in dividends payable:

= $24,000 - $22,000

= $2,000

Change in operating assets and liabilities:

= Change in accounts receivable + Change in inventory - Change in accounts payable - Change in dividends payable

= $900 + (-$700) + $1,100 + $2,000

= $2,300

Net cash flow from operating activities:

= Net income + Change in operating assets and liabilities

= $98,500 + $2,300

= $100,800.

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Answer:

89

Step-by-step explanation:

Take half of 177 and round up, which is 177/2 = 88.5 = 89

This is because 89+88=177 and 89>88, so there will be a majority.

The inequality representing the situation is "y ≥ 0.75x," where y is the total number of hours Lionel spends practicing and x is the number of days he practices.

To represent the situation where Lionel practices for a minimum of 45 minutes on the days he practices, we can use the variables x and y, where x represents the number of days Lionel practices and y represents the total number of hours he spends practicing.

We know that Lionel practices for a minimum of 45 minutes on each day. Since there are 60 minutes in an hour, this is equivalent to 0.75 hours. Therefore, for each day Lionel practices, he spends at least 0.75 hours.

To find the total number of hours Lionel spends practicing (y), we can multiply the number of days he practices (x) by the minimum number of hours he spends on each day (0.75). This gives us the equation:

y ≥ 0.75x

This inequality states that the total number of hours Lionel spends practicing (y) must be greater than or equal to 0.75 times the number of days he practices (x). It ensures that Lionel practices for a minimum of 45 minutes (0.75 hours) on each day he practices.

By using this inequality, we can track Lionel's practice time and ensure that he meets the minimum requirement of 45 minutes per day.

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Answer:

Proving that the limit of the equation 10 - 2x as x approaches -3 is 16 involves using the definition of a limit.

Here's how you would approach it:

Let epsilon be a small positive number. We want to find a value of delta such that if x is within a distance of delta from -3, then 10 - 2x is within a distance of epsilon from 16.

So, we start with:

|10 - 2x - 16| < epsilon

Simplifying,

|-2x - 6| < epsilon

And using the reverse triangle inequality,

|2x + 6| > ||2x| - |6||

Now, we can choose a value for delta such that if x is within delta of -3, then |2x + 6| is within delta + 6 of |-6| = 6.

So,

||2x| - |6|| < epsilon

and therefore:

|2x - 6| < epsilon

Choosing delta = epsilon/2, we can prove that:

0 < |x + 3| < delta -> |2x - 6| < epsilon

Therefore, we have proved that the limit of 10 - 2x as x approaches -3 is 16 using the definition of a limit.

Step-by-step explanation:

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