examps of sources of primary pollutants

Answers

Answer 1

Answer:

Primary pollutants can be emitted from many sources including cars, coal-fired power plants, natural gas power plants, biomass burning, natural forest fires, volcanoes, and many more. The effects of primary pollutants are of concern as they can be harmful to humans, animals and plants.Sep 3, 2018

Explanation:

A primary source results from the direct emissions from an air pollution source. In contrast, a secondary source results from the formation of a pollutant in the atmosphere from the chemical reaction of precursors emitted from air pollution sources.


Related Questions

Which property is an intensive, rather than an extensive, property of matter?

A. volume

B. density

C. mass

D. length

Answers

Answer:

Density other dude is incorrect

Explanation:

Density is an intensive, rather than an extensive property of matter.

WHAT ARE INTENSIVE AND EXTENSIVE PROPERTIES?

The property of matter is divided into two categories namely: intensive and extensive properties.

Intensive properties are those properties that are not dependent on the size or amount of the substance. Examples include density, temperature, boiling point, melting point etc.

Extensive properties are those properties that depend on the size or amount of the substance involved. Examples are length, mass, volume weight etc.

Therefore, density is an intensive, rather than an extensive property of matter.

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Given the ion Al+3, what species would you expect to form with each of the following ions? OH- ___________ S2- ___________ PO43- _________

Answers

Ionic substances are formed by exchange of valencies between the ions that make up the substance.

The ion [tex]Al^3+[/tex] has a valency of +3. It exchanges this valency with other ions as it forms ionic substances.

In the case of OH- which has a valency of 1, the compound Al(OH)3 is formed.

In the case of [tex]S^2-[/tex] which has a valency of 2, the compound Al2S3 is formed.

In the case of [tex]PO4^3-[/tex] which has a valency of 3, the compound AlPO4 is formed.

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Axon diameters of cortico-cortical fibres in the human brain range from 0.16 um to 9 um in
length. Convert the length, 0.16 um, into meters using scientific notation. (Use the following
format: a x 10^b using the correct number of significant figures).

Answers

The conversion of units in science is achieved by the use of conversion factors.

A conversion factor is a number used to change a quantity from one unit to another.

The given unit here is the micrometer and we are expected to convert the quantity (mass in this case) from micrometer to meter.

The conversion factor to use is:

1 μm = [tex]1 * 10^-6 m[/tex]

Hence;

0.16 μm = 0.16 μm * 1 * 10^-6 m/ 1 μm

= 1.60 * 10^-7 m

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What is the major organic product obtained from the reaction of ethylbenzene with nitronium ion, followed by benzylic oxidation?
a. 3-ethyl-aniline.
b. 4-nitro-benzoic acid.
c. 3-nitro-toluene.
d. 3-nitrobenzoic acid.

Answers

Answer:

b

Explanation:

If an inverse relationship exist between x and y, and k = 200, which of the following would be points on the graph?

-(200,0.1)
-(100, 0.2)
-(400, 0.5)
-(800, 0.4)

Answers

Answer:

The answer is (400, 0.5)

Which option describes the molecule geometry of a molecule with one bond and three lone pairs?

A. octahedral

B. linear

C. angled

D. tetrahedral

Answers

based one VSEPR

1 bond 3 lone pairs is linear

The option describes the molecule geometry of a molecule with one bond and three lone pairs. Thus, option B is correct.

What is covalent bond?

A covalent bond is defined as  a chemical bond that includes the sharing of electron pair between atoms.The pair of electrons are know as bonding pairs and the stable balance of attractive and repulsive forces between atoms.

The properties of covalent bond are mentioned below:

The covalent compounds have low melting points and boiling points.The covalent compounds do not contain electricity.

The covalent compounds are  having lower enthalpies of vaporization and fusion.The covalent compounds are easily catches fire and are more flammable than ionic compounds.

The covalent compounds are very soft and flexible. The physical properties of covalent compounds are that they have lower melting points and electrical conductivity.

Therefore, The option describes the molecule geometry of a molecule with one bond and three lone pairs. Thus, option B is correct.

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Nobel gases (inert gases) have full set of valence electrons so they DO NOT REACT with other elements. Noble gases are elements.

A. stable
B. unstable

Answers

Answer:

Noble gases are stable as they have fully filled outermost orbital. Hence they do not participate in chemical reactions.

But Xenon reacts in some cases in favourable conditions

22. Which of the following is contained only in a eukaryotic cell? A. cell wall
B. nucleus
C. chromosomes


23.Which of the following terms represent the chemical reactions to break down food into simpler compounds in an organism?
A. anabolism
B. catabolism
C. nitrogen cycle



24.What types of molecules are bonded together to form a nucleotide? A. 2 nitrogen bases + 1 sugar
B. 2 sugars + 1 phosphate group
C. 1 nitrogen base + 1 phosphate group + 1 sugar


25.Glucose and oxygen are the two products of photosynthesis A. true
B. false


26.What is the first step in the refining of petroleum? A. cracking
B. drilling
C. distillation


27.When radium-226 (atomic number 88) decays by emitting an alpha particle, it becomes _________.
A. polonium-222 B. polonium-224 C. radon-222


28.The general name for hydrocarbons with at least one triple covalent bond is _________.
A. alkenes B. alkanes C. alkynes



29.What particle is emitted in alpha radiation? A. electron
B. photon
C. helium nucleus


30.Which type of compound is this? CH3CH2CH2CH2OH
A. alcohol B. aldehyde C. ether


31.Why are the molecules of hydrocarbons nonpolar? A. The intermolecular attractions are strong.
B. All the bonds are single covalent bonds.
C. The electron pair is shared almost equally in all the bonds.



32. An amino group and a carboxyl group are joined by a ___________ bond. A. peptide
B. protein
C. amino


33.What type of radiation is likely to occur when the ratio of protons to neutrons is below the band of stability?
A. alpha decay
B. beta decay
C. neutron emission


34.Covalent bonds are between bases in a DNA base-pair. A. true
B. false



35.What is the name of the functional group in the following compound? R—NH2
A. halogen B. amine C. ether

Answers

Answer:

22 options A cell wall

23 options A anabolism

24 options B 2sugar + 1phosphate group

The density of gold is 19.3 g/cm3, and the density of iron pyrite is 5.02 g/cm3. What substance do you think you found?

Answers

Answer:

Step 1

1 of 2

V = m / D; V (nugget of gold) = 50 g / 5.0 g / cm 3 = 10 cm3; V (nugget of iron pyrite) = 50 g / 19 g / cm3 = 2.63 cm 3

Result

2 of 2

Due to these results you can conclude that nugget of gold which volume is 10 cm3 is bigger than volume of nugget of iron pyrite which is 2.63 cm3.

Explanation:

Which compound is a carbohydrate. Nucleotide or protien or starch or amino acid

Answers

starch is carbohydrate

Name the reaction type & mechanism of the following reactions:

Answers

Answer:

MECHANISM:

1) The lone pair on oxygen attacks the H-Br molecule forming a hydronium ion.

2) Formation of carbocation.

3) Attack of Nucleophile Br  −  .

Explanation:

Answer:

DISPLACEMENT REACTION

COMBINATION REACTION

DOUBLE DISPLACEMENT REACTION

DECOMPOSITION REACTION

In rutherfords gold foil experiment, most alphas particles passed through the gold foil without deflection and were detected on the screen. What caused the particles to pass through without any deflection?

Answers

Answer:

The vast majority of the volume in an atom consists of the electron orbitals with electrons that have too little mass to deflect the alpha particles.  So most pass right through the foil.  Only the ones hitting the nucleus are deflected.

Explanation:

The whole reason Rutherford and his students conducted this experiment was to test the then current hypothesis that an atom consists of a homogeneous blend of atomic particles, known as the "plum pudding" model.  If so, there should be no, or minimal, deflection of particles.  That's not what they found.  Since particles were found to be deflected, the group concluded that atoms must contain a large object, which became known as the nucleus.

what was daltons motivation for proposing his model of the atom

Answers

Answer:

John Dalton based his partial pressures theory on the idea that only like atoms repel one another, Whereas unlike atoms appear to react indifferently. This notion was erroneous, but it helped to explain why each gas in a mixture behaved independently, serving the purpose of showing that atoms of all kinds are not alike.

the electronic configuration of an atom of element X is 2,8,2 what will be the valency of the element x

Answers

The element is Magnesium

It has total 12 electrons

it has electronic configuration

[tex]\\ \sf\longmapsto 2,8,2[/tex]

or

[tex]\\ \sf\longmapsto 1s^22s^22p^63s^2[/tex]

In valence cell it has 2 electrons and therefore its valency is 2

4.25x10 ^ -3 in standered notation

Answers

Answer:

This Scientific notation;

[tex]4.25 \times {10}^{ - 3} [/tex]

This in standered notation ;

[tex]0.00425[/tex]

I hope I helped you^_^

Which isotope of iron from the periodic table is most abundant

Answers

Answer:

Iron has four naturally-occurring stable isotopes, 54Fe, 56Fe, 57Fe and 58Fe. The relative abundances of the Fe isotopes in nature are approximately 54Fe (5.8%), 56Fe (91.7%), 57Fe (2.2%) and 58Fe (0.3%).

calculate the number of each atom in 2.5 gram of caco3 ​

Answers

Answer:

[tex]2.5\; \rm g[/tex] of [tex]\rm CaCO_{3}[/tex] would contain:

Approximately [tex]1.5 \times 10^{22}[/tex] calcium atoms (approximately [tex]0.025\; \rm mol[/tex],)Approximately [tex]1.5 \times 10^{22}[/tex] carbon atoms (approximately [tex]0.025\; \rm mol[/tex],) andApproximately [tex]4.5 \times 10^{22}[/tex] oxygen atoms (approximately [tex]0.075\; \rm mol[/tex].)

Explanation:

Look up the Avogadro constant: [tex]N_{\rm A} \approx 6.022 \times 10^{23}\; \rm mol^{-1}[/tex].

For example, "[tex]1\; \rm mol[/tex] of carbon atoms" would contain [tex]N_{\rm A}[/tex] carbon atoms (approximately [tex]6.022\times 10^{23}[/tex]) by definition.

Look up the relative atomic mass of carbon, calcium, and oxygen on a modern periodic table:

Calcium: [tex]40.078[/tex].Carbon: [tex]12.011[/tex].Oxygen: [tex]15.999[/tex].

In other words, the mass of [tex]1\; \rm mol[/tex] of calcium atoms would be [tex]40.078\; \rm g[/tex]. The mass of [tex]1\; \rm mol\![/tex] of carbon atoms would be [tex]12.011\; \rm g[/tex], and the mass of [tex]1\; \rm mol \!\![/tex] of oxygen atoms would be [tex]15.999\; \rm g[/tex].

As the formula [tex]\rm CaCO_{3}[/tex] suggests, every formula unit of this ionic compound includes one calcium atom, one carbon atom, and three oxygen atoms. The formula mass of [tex]\rm CaCO_{3}\![/tex] would give the mass of every mole of [tex]\rm CaCO_{3}\!\![/tex] formula units.

Calculate the formula mass of [tex]\rm CaCO_{3}[/tex] from the relative atomic mass data:

[tex]\begin{aligned} & M({\rm CaCO_{3}}) \\ =\; & 40.078\; \rm g \cdot mol^{-1} \\ & + 12.011\; \rm g \cdot mol^{-1} \\ & + 3 \times (15.999\; \rm g \cdot mol^{-1}) \\ =\; & 100.086\; \rm g \cdot mol^{-1}\end{aligned}[/tex].

Calculate the number of [tex]\rm CaCO_{3}[/tex] formula units in that [tex]2.5\; \rm g[/tex] of this compound:

[tex]\begin{aligned}& n({\rm CaCO_{3}}) \\ =\; & \frac{m({\rm CaCO_{3}})}{M({\rm CaCO_{3}})} \\ =\; & \frac{2.5\; \rm g}{100.086\; \rm g \cdot mol^{-1}} \\ \approx\; & 0.025\; \rm mol\end{aligned}[/tex].

In other words, [tex]2.5\; \rm g[/tex] of [tex]\rm CaCO_{3}[/tex] would contain approximately [tex]0.025\; \rm mol[/tex] [tex]\rm CaCO_{3}\![/tex] formula units.

Again, there are one calcium atom, one carbon atom, and one oxygen atom in every [tex]\rm CaCO_{3}[/tex] formula unit. That approximately [tex]0.025\; \rm mol[/tex] [tex]\rm CaCO_{3}\![/tex] formula units would thus contain:

Approximately [tex]1 \times 0.025\; \rm mol = 0.025\; \rm mol[/tex] calcium atoms, Approximately [tex]1 \times 0.025\; \rm mol = 0.025\; \rm mol[/tex] carbon atoms, andApproximately [tex]3 \times 0.025\; \rm mol = 0.075\; \rm mol[/tex] oxygen atoms.

Make use of the Avogadro constant to convert the numbers.

For example, the number of calcium atoms in that approximately [tex]0.025\; \rm mol[/tex] of calcium atoms would be:

[tex]\begin{aligned} & N({\text{calcium}) \\ = \; & n({\text{calcium}) \cdot N_{\rm A} \\ \approx \; & 0.025\; \rm mol \times 6.022\times 10^{23} \cdot mol^{-1} \\ \approx \; & 1.5 \times 10^{22} \end{aligned}[/tex].

Likewise, the number of carbon atoms in that approximately [tex]0.025\; \rm mol[/tex] of carbon atoms would be:

[tex]\begin{aligned} & N({\text{carbon}) \\ = \; & n({\text{carbon}) \cdot N_{\rm A} \\ \approx \; & 0.025\; \rm mol \times 6.022\times 10^{23} \cdot mol^{-1} \\ \approx \; & 1.5 \times 10^{22} \end{aligned}[/tex].

The number of oxygen atoms in that approximately [tex]0.075\; \rm mol[/tex] of oxygen atoms would be:

[tex]\begin{aligned} & N({\text{oxygen}) \\ = \; & n({\text{oxygen}) \cdot N_{\rm A} \\ \approx \; & 0.075\; \rm mol \times 6.022\times 10^{23} \cdot mol^{-1} \\ \approx \; & 4.5 \times 10^{22} \end{aligned}[/tex].

You are unable to lift an object. Which property makes the object difficult to lift?(1 point)

mass

density

weight

volume

Answers

Answer:

You are unable to lift an object. Which property makes the object difficult to lift?(1 point)

weight

what is the formula of water​

Answers

Answer:

H2O is the formula of water

Answer:

H²O is formula of water

Explanation:

2 molecule of hydrogen and 1 molecule of oxygen

Choose the correct definition of PRESSURE.
1. force per unit area
2. the rate of work done
3. a push or a pull applied on an object
4. product of force with displacement of object

Answers

Pressure - Force per unit area

Hope it helped :)

Based on properties of elements in the periodic table, which element is the best conductor of thermal energy?
(1 point)
argon (Ar)
O germanium (Ge)
O vanadium (V)
polonium (Po)

Answers

Answer:

Vanadium (V) is the best conductor of thermal energy in this list

How much heat is absorbed by a 112.5 g sample of water when it is heated from 12.5 °C to 92.1 °C? (Specific heat capacity of water is 4.184 J/g °C)

Answers

Answer:

[tex]\boxed {\boxed {\sf37,467.72 \ Joules }}[/tex]

Explanation:

We are asked to find how much heat a sample of water absorbed. Since we are given the mass, temperature, and specific heat, we will use the following formula.

[tex]q=mc \Delta T[/tex]

The mass (m) of the sample is 112.5 grams. The specific heat capacity of water (c) is 4.184 Joules per gram degree Celsius. The difference in temperature (ΔT) is found by subtracting the initial temperature from the final temperature.

ΔT= final temperature - initial temperature

The water was heated from 12.5 degrees Celsius to 92.1 degrees Celsius.

ΔT= 92.1 °C - 12.5 °C= 79.6°C

Now we know three variables and can substitute them into the formula,

m= 112.5 g c= 4.184 J/g °C ΔT= 79.6 °C

[tex]q= (112.5 \ g )(4.184 \ J/g \textdegree C)(79.6 \textdegree C)[/tex]

Multiply the first 2 numbers. Note the units of grams cancel.

[tex]q= (112.5 \ g *4.184 \ J/g \textdegree C)(79.6 \textdegree C)[/tex]

[tex]q= (112.5 *4.184 \ J/ \textdegree C)(79.6 \textdegree C)[/tex]

[tex]q= (470.7 \ J/ \textdegree C)(79.6 \textdegree C)[/tex]

Multiply again. This time the units of degrees Celsius cancel.

[tex]q= (470.7 \ J/ \textdegree C *79.6 \textdegree C)[/tex]

[tex]q= (470.7 \ J *79.6 )[/tex]

[tex]q= 37467.72 \ J[/tex]

37, 467.72 Joules of heat are absorbed by the sample fo water.

A 25.0 mL sample of 0.723 M HClO4 is titrated with a 0.273 M KOH solution. The H3O+ concentration after the addition of 66.2 mL of KOH is __________ M.
a. 0.723
b. 1.00 × 10-7
c. 2.81 × 10-13
d. 0.439
e. 0.273

Answers

B 2048% q100-10000(10)

What's the difference between science and science methods?

Answers

Answer:

Science is related only to sense-experience, and reason based on the former. It is an accumulation of systematic and verifiable knowledge. The scientific method is one and the same in all branches of knowledge. The unity of science, according to him, consists in its method, not in its material alone.

Explanation:

Do you think the video game "Geometry dash" is dead?

Answers

Answer:

HELL NO!

THAT'S MY CHILDHOOD GAME!

I LOVE THAT GAME!

IT SHOULD NOT BE DEAD!

IT SHOULD LIVE ON FOREVER!

#GemoteryDashShouldLiveOnForever!

[tex]AnimeVines[/tex]

honestly yeah game is only good sometimes but there are so many other games now

What volume of 0.32M HCl is required to completely neutralize 50.0m mL of a 0.12M Mg(OH)2 solution?​

Answers

Answer:

37.5 mL of HCl will be required for complete neutralization with magnesium hydroxide

Explanation:

[tex]{ \bf{2HCl _{(aq)} + Mg(OH)_{2(s)}→ MgCl_{2(s)} + 2H _{2} O_{(l)}}}[/tex]

we've to first get moles of magnesium hydroxide in 50.0 ml :

[tex]{ \sf{1 \: l \: of \: hydroxide \: contains \: 0.12 \: moles}} \\ { \sf{0.05 \: l \: of \: hydroxide \: contain \: (0.05 \times 0.12) \: moles}} \\ = { \underline{0.006 \: moles}}[/tex]

for complete neutralization:

[tex]{ \sf{1 \: moles \: of \: hydroxide\: react \: with \: 2 \: moles \: of \: acid}} \\ { \sf{0.006 \: moles \: react \: with \: \{0.006 \times 2 \}} \: moles} \\ = { \underline{0.012 \: moles \: of \: acid}}[/tex]

compare with acid molarity:

[tex]{ \sf{0.32 \: moles \: of \: acid \: occupy \: 1 \: litre}} \\ { \sf{0.012 \: moles \: of \: acid \: occupy \: ( \frac{0.012}{0.32}) \: litres }} \\ { \underline{ = 0.0375 \: litre \: \: = \: \: 37.5 \: ml}}[/tex]

Which property altered during a chemical change is not altered during a physical change?

A. composition of the matter

B. temperature of the matter

C. volume of the matter

D. phase of the matter

Answers

A. composition of the matter

The property altered during a chemical change that is not altered during a physical change is composition of the matter.

A physical change is one in which no new substance is formed and it is easily reversible.

A chemical change is one that is not easily reversible and no new substance is formed. It may be accompanied by absorption or evolution of heat.

The composition of a substance changes during a chemical change  because bonds between atoms break and new bonds are formed. This does not occur during a physical change.

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How many inches are in 1.00 km

Answers

1 kilometer =
39370.079 inches
39370.08 inches in 1 Kilometre hi mom

Al(s) + NaOH(aq) → Al(OH)3(s) + Na+(aq) displacement, or decomposition.

Answers

Answer:

Displacement

Explanation:

OH- in the reactant side of the reaction has switched from Na+ to Al 3+ in the product side. Decomposition is where a compound from the reactant side of the reaction would dissolve into elements in the product side, but that's not the case in this example.

Oceanography does not include the study of which of the following topics?

A.the relationship between the Sun, Moon, and Earth

B.the relationship between the atmosphere, Earth, and the oceans

C.the Earth's oceans

D.the plants and animals that live in the oceans

Answers

A.The relationship between the Sun moon and Earth
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