Answer:
Examples of electromagnetic waves include radio waves, microwaves, infrared, visible light, ultraviolet, x-rays, and gamma rays. ... Microwaves are used to cook your food. Infrared waves are used in remote controls and are emitted from all warm objects, allowing them to be used to create heat-sensitive cameras.
Explanation:
brainliest please
A 5,257 kg rocket blasts off to the moon with an acceleration of 76 m/s ^2 what is the net force on the rocket
Newton's subsequent law expresses that power is corresponding to what exactly is needed for an object of consistent mass to change its speed. This is equivalent to that item's mass increased by its speed increase. We use Newtons, kilograms, and meters each second squared as our default units, albeit any proper units for mass (grams, ounces, and so forth) or speed (miles each hour out of every second, millimeters per second2, and so on) could unquestionably be utilized also - the estimation is the equivalent notwithstanding.
Hence, the appropriate answer will be 399,532.
Net Force = 399532
A 3.89 x 10-8 F capacitor has a
voltage applied, which creates
1.15 x 10-10 C of charge on the
plates. What voltage was applied?
Answer:
0.00296
Explanation: This answer works for Acellus! :)
The voltage applied to the capacitor is approximately 2.964 x 10⁻³ C/F.
Capacitance is a fundamental electrical property that measures the ability of a system to store an electric charge when a potential difference (voltage) is applied across it. It is denoted by the symbol "C" and is measured in farads (F). A capacitor is a device commonly used to create capacitance in an electrical circuit.
In simple terms, capacitance is a measure of how much electric charge can be stored on an object (usually a capacitor) for a given electric potential difference. It is directly proportional to the amount of charge stored and inversely proportional to the applied voltage. Capacitance plays a crucial role in various electronic circuits and systems, including filtering, energy storage, and timing applications.
To calculate the voltage applied to the capacitor, we can use the formula:
Q = C × V
Where:
Q is the charge on the plates of the capacitor
C is the capacitance
V is the voltage applied to the capacitor
Given:
Capacitance (C) = 3.89 x [tex]10^{(-8)[/tex] F
Charge on the plates (Q) = 1.15 x [tex]10^{(-10)[/tex]C
Rearranging the formula, we can solve for V:
V = Q / C
Substituting the given values:
V = (1.15 x [tex]10^{(-10)[/tex] C) / (3.89 x [tex]10^{(-8)[/tex] F)
Dividing the numerator and denominator by [tex]10^{(-8)[/tex]:
V = (1.15 / 3.89) x [tex]10^{(-10 - (-8))[/tex] C/F
V = (1.15 / 3.89) x [tex]10^{(-2)[/tex] C/F
V = 0.2964 x [tex]10^{(-2)[/tex] C/F
Using scientific notation, we can express the voltage as:
V = 2.964 x [tex]10^{(-3)[/tex]C/F
Therefore, the voltage applied to the capacitor is approximately 2.964 x [tex]10^{(-3)[/tex] C/F.
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A gas is placed in a 5.0-mL syringe. It exerts 141 mm Hg of pressure on the inside walls of the syringe. The syringe's plunger is pressed, reducing the volume of the syringe to 2.9 mL. The cap was not removed from the syringe, so none of the gas escapes. Assuming the temperature of the gas does not change, use Boyle's law (below) to determine the pressure of the compressed gas. P_1V_1 = P_2V_2
Answer: [tex]243.10\ mm\ \text{of}\ Hg[/tex]
Explanation:
Given
The initial volume of gas [tex]V_1=5\ ml[/tex]
Initial pressure is [tex]P_1=141\ mm\ \text{of}\ Hg[/tex]
Final volume is [tex]V_2=2.9\ ml[/tex]
As it is given [tex]P_1V_1=P_2V_2[/tex]
insert the values
[tex]141\times 5=P_2\cdot 2.9\\P_2=243.10\ mm\ \text{of}\ Hg[/tex]
(eopt)s. Find the power dissipated in a 25 r heater
connected to a 220V outer.
Answer:
P = 1936 W
Explanation:
Given that,
Voltage, V = 220 V
The resistance of the heater, R = 25 ohms
We need to find the power dissipated in the heater. We know that the power dissipated by the electric appliances is given by :
[tex]P=\dfrac{V^2}{R}\\\\P=\dfrac{(220)^2}{25}\\\\P=1936\ W[/tex]
So, the required power is equal to 1936 W.
A student decides to give his bicycle a tune up. He flips it upside down (so there's no friction with the ground) and applies a force of 34 N over 0.6 seconds to the pedal, which has a length of 16.5 cm. If the back wheel has a radius of 33.0 cm and moment of inertia of 1200 kg cm^2, what is the tangential velocity of the rim of the back wheel in m/s
Answer:
[tex]V=9.2565m/s[/tex]
Explanation:
From the question we are told that:
Force [tex]F = 34 N[/tex]
Time [tex]t = 0.6 s[/tex]
Length of pedal [tex]l_p=16.5cm \approx0.165m[/tex]
Radius of wheel [tex]r = 33 cm = 0.33 m[/tex]
Moment of inertia, [tex]I = 1200 kgcm2 = 0.12 kg.m2[/tex]
Generally the equation for Torque on pedal [tex]\mu[/tex] is mathematically given by
[tex]\mu=F*L\\\mu=34*0.165[/tex]
[tex]\mu=5.61N.m[/tex]
Generally the equation for angular acceleration [tex]\alpha[/tex] is mathematically given by
[tex]\alpha=\frac{\mu}{l}[/tex]
[tex]\alpha=\frac{5.61}{0.12}[/tex]
[tex]\alpha=46.75[/tex]
Therefore Angular speed is \omega
[tex]\omega=\alpha*t[/tex]
[tex]\omega=(46.75)*(0.6)[/tex]
[tex]\omega=28.05rad/s[/tex]
Generally the equation for Tangential velocity V is mathematically given by
[tex]V=r\omega[/tex]
[tex]V=(0.33)(28.05)[/tex]
[tex]V=9.2565m/s[/tex]
a mango fruit drop down from top of its tree which is 5m high. How long does it take to reach the ground
Answer:
What is the mass tho?
You need the mass to answer this question
Answer:
[tex]distance = ut + \frac{1}{2} g {t}^{2} \\since \: the \: fruit \: is \: from \: rest : \: initial \: velocity \: is \: 0 \: (u = 0) \\ 5 = (0 \times t) + ( \frac{1}{2} \times 9.81 \times {t}^{2} ) \\ 5 = 4.905 {t}^{2} \\ t = \sqrt{1.0194} \\ t = 1 \: second[/tex]
4. How many excess electrons does a balloon that was rubbed on a child's hair and
now has a charge of 4.0 x 107 Coulombs?
In velocity time graph of a body, two points are given as A(40,5) and B(20,2). What is the acceleration of the body
Answer:
0.15 m/s²
Explanation:
Acceleration is rate of change of velocity-time function. We can find acceleration by finding the slope. The slope of graph can be found by:
[tex] \displaystyle{a = \dfrac{ \Delta v}{ \Delta t} \: \to \: \dfrac{v_f - v_i}{t_f- t_i}}[/tex]
Substitute in:
[tex] \displaystyle{a = \dfrac{5 - 2}{40 - 20}} \\ \\ \displaystyle{a = \dfrac{3}{20}} \\ \\ \displaystyle{a = 0.15 \: \text{m/s}^{2} }[/tex]
Therefore, the acceleration is 0.15 m/s²
define area and give its SI unit
Answer:
area is the space bounded by certain lines, the SI unit of area is m²
area of rectangle =l×w×h
square=l²
What are the horizontal and vertical components of a cat's displacement when the cat has climbed 5 m
directly up a tree © = 90°? Sin90=1
cos90=0
The horizontal component of the cat's displacement, Dx = 0 m
The vertical component of the cat's displacement, Dy = 12 m
What are the horizontal and vertical components of a vector?The horizontal component of a vector is the value of that vector acting in the horizontal direction.
The horizontal component of a vector is given as Dx.
Dx = Dcosθ
where;
D is the resultant of the vector
θ is the angle of the vector from the horizontal
The horizontal component of the cat's displacement is:
Dx = 12 * 0
Dx = 0 m
The vertical component of a vector is the value of that vector acting in the vertical direction.
The vertical component of a vector is given as Dy.
Dy = Dsinθ
where;
D is the resultant of the vector
θ is the angle of the vector from the horizontal
The vertical component of the cat's displacement is:
Dy = 12 * 1
Dy = 12 m
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A 30-g bullet traveling horizontally at 300 m/s strikes a 1.0-kg block which is attached to a horizontal spring with a force constant of 2000 N/m and rests on a frictionless horizontal surface. The spring is on the far side of the block and aligned with the direction of travel of the bullet. The bullet becomes embedded in the block and, as a result of the impact, and the block slides against the spring. How far is the spring compressed before it reverses its direction of travel
Answer:
Explanation:
Using law of conservation of momentum during collision , velocity after collision can be found .
common velocity V = m v / ( m + M )
= .030 x 300 / ( .030 + 1 )
V= 8.7378 m /s
The kinetic energy of the bullet and block will be stored as elastic energy
1/2 ( M + m ) V² = 1/2 k A² where k is force constant and A is maximum compression in the spring .
( M + m ) V² = k A²
1.030 x 8.7378² = 2000 x A²
A² = .0393
A= .1982 m .
= 19.82 cm
¿Con qué cualidad del sonido está relacionada la Amplitud de onda?
Answer:
Amplitud (dinámica)
Explanation:
La amplitud de una onda de sonido determina su volumen relativo. En música, el volumen de una nota se denomina nivel dinámico.
if a referee tosses a basketball in the air and hits the floor, at what point will the ball have no mechanical kinetic energy (hint: this occurs at more than one point)
the ball have no mechanical kinetic energy:
Just before the ball is set in motion in the air. Just after it hits the floor.What is mechanical kinetic energy?This refers to the energy that an object possessed due to its motion or due to its position. It is calculated by getting the product of the mass of the object and its velocity and dividing it by two. It is measured in joules, J.
if a referee tosses a basketball in the air, the ball will not have mechanical kinetic energy:
Just before the ball is set in motion in the air. ( Potential energy that is energy due to an object's position).Just after it hits the floor. ( Potential energy that is energy due to an object's position).Learn more about kinetic energy on
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what is polarization of light?
Answer:
Polarized light waves are light waves in which the vibrations occur in a single plane. The process of transforming unpolarized light into polarized light is known as polarization. There are a variety of methods of polarizing light.
Explanation:
1. Compare and contrast sensation and perception.
2. Describe an example of sensory adaptation that you have experienced.
3. Why would it be difficult to play a sport such as baseball or basketball without the ability
to perceive depth?
4. Do you think that subliminal messages should be banned from advertising? Why or why
not?
5. What is your opinion about extrasensory perception? Do you think it exists? Explain your
answer.
A frog jumps as is moves. what is the relation between its maximum height and maximum range
The relation between a frog's maximum height and maximum range is that when the frog jumps at an angle of 45°, its maximum height is half of the horizontal range.
What are the maximum height and maximum range?The maximum height refers to the maximum vertical distance that an object can travel.
The maximum range is the maximum horizontal distance that an object can travel.
The maximum height, H that the projectile reaches when the range, R, is at its greatest is H = Rmax /4.
R = 4Hcot is the relationship between the horizontal range and maximum height.
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Two engines create SIL values of 75 dB and 85 dB respectively. What dB reading would you expect when both are run simultaneously?
Answer:
Explanation:
In a quiet forest, you can sometimes hear a single leaf fall to the ground. ... greater its pressure amplitude, the more the air is compressed in the sound it creates. ... Graphs of the gauge pressures in two sound waves of different intensities. ... The sound intensity level β in decibels of a sound having an intensity I in watts per .
A coil of 27 turns is in the shape of an ellipse having a major axis of 12.0 cm and a minor axis of 9.00 cm. The coil rotates at 57rpm in a region in which the Earth's magnetic field is 74.0 microT. What is the maximum voltage induced in the coil if the axis of rotation of the coil is along its major axis and this axis of rotation is aligned perpendicular to the Earth's magnetic field
Answer:
Explanation:
Emf induced e = nBAω sinωt where n is no of turns , B is magnetic field, A is area of the coil ω is angular frequency of rotation .
maximum emf = nBAω
Given n = 27 , B = 74 x 10⁻⁶ T , A = .12 m x .09 m = 108 x 10⁻⁴ m²
ω = 2π x 57/60 = 5.966 rad/s .
Putting the values
maximum emf = 27 x 74 x 10⁻⁶ T x 108 x 10⁻⁴ m² x 5.966 rad/s .
= 1.29 x 10⁻⁴ V .
Describe the image with a object distance of 65cm and a focal length of 20cm
Answer:
Imag distance = 28.9 cm
Explanation:
Given that,
Object distance, u = -65 cm
The focal length of the convex les, f = +20 cm
We need to find the image distance. The lens formula gives the relation between focal length, object distance and image distance is given by :
[tex]\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{20}+\dfrac{1}{-65}\\\\v=28.9\ cm[/tex]
So, the image distance is 28.9 cm
Please need help ASAP, ASAP
If force is doubled, acceleration will also be doubled.
Newton’s second law of motion, unlike the first law of motion, pertains to the behaviour of objects for which all existing forces are unbalanced. The second law of motion is more quantitative and is used extensively to calculate what happens in situations involving a force.It states that: Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration.The acceleration of the body is directly proportional to the net force acting on the body and inversely proportional to the mass of the body. This means that as the force acting upon an object is increased, the acceleration of the object is increased.In this given question, force is doubled. We know that force is directly proportional to acceleration. As we increase the force on an object the acceleration increases proportionally. Therefore, if you double the force you double the acceleration.
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Net work W would accelerate an object from rest to velocity v. What net work is needed to accelerate the object from rest to velocity 2v?
The net work that is needed to accelerate a 2.0 kg mass from rest to velocity 2v is 4.0 m/s.
What is net work done?When a force acts on a body at rest or at uniform motion in a straight line, then it starts to accelerate.
Given that, the velocity is 5.0
Time is 2 sec
The given mass is 2.0 kg
First, we calculate the acceleration
Acceleration = v / t = 10 / 5.0 = 2
From Newton's second law, we know that
force = mass x acceleration
F = ma
F = 2.0 x 2 = 4.0 m/s
Therefore, the net work that is needed to accelerate a 2.0 kg mass from rest to velocity 2v is 4.0 m/s.
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The question is incomplete. Your most probably complete question is given below:
What net force is needed to accelerate a 2.0 kg mass from rest to a velocity of 10 m/s in 5.0 s?
Sound is not so distinct at day due to............
Explanation:
This is because of a phenomenon called refraction which effects the direction of sound.
You push a cart with mass 30 kg forward, giving it an acceleration of 5 m/s2How much force did you apply? O A. 0.17 N O B. 35 N O C. 75 N O D. 150 N
Answer:
150N
Explanation:
To find the force applied remember that force equals to Mass multiply by the Acceleration.
F=Ma
=30*5
=150N
Answer:
150N
Explanation:
F = m*a = 30 * 5 = 150 N
The monster wants to make himself known to the family in the cottage in chapters 9-12 of Frankenstein. He decides he can't do that until he masters something. What skill
must he master?
A. How to dress properly
B. Language
C. The rules of etiquette
D. Music
Answer:
c
Explanation:
Bonjour ,
je n'arrive pas a comprendre cet exercice de physique niveau 5eme.
Ceci concerne le chapitre sur l'éléctricité .
MERCI
Answer:
Bonjour! Mon francais est assez rouillé, mais faire de mon mieux pour traduire la page; voici les principaux points:
1. (Une) Le rôle de la boule de flotteur dans le circuit électrique est qu'il permet à la pompe d'arrêter lorsque l'eau n'est pas le bon niveau en venant en contact avec deux conducteurs et la fermeture du circuit électrique.
2. (Deux) Je veux dire que le matériau qui constitue la balle en isolant, car il maintient l'eau et hors de blocage force active de la machine.
3. (Trois) Le courant électrique continuera aussi longtemps que la pompe est branchée sur une prise électrique, je crois.
Encore une fois, s'il vous plaît pardonnez-moi, je suis mieux à la lecture de français que de l'écrire! J'espère que cela a pu aider. Si vous avez plus de questions, je vais faire de mon mieux pour y répondre!
Salut!
A force F making an angle with the horizontal is acting on an object resting on the table. Which statement is true for the motion of sliding the object on the table? A. It is independent of all the forces acting on the object. B. It depends only on the forces acting along the x-axis. C. It depends only on the forces acting along the y-axis. D. It depends only on the normal force acting on the object. E. It depends only on the frictional force acting on the object.
Answer:
C
Explanation:
it depends only on the forces acting along the y- axis
Answer:
The statement that is true for the motion of sliding the object on the table is : its independent of all forces acting on the object
Explanation:
A wave is traveling at a speed of 12m/s and its wavelength is 3 m calculate the wave frequency
Answer:
f = 4 Hz
Explanation:
Given that,
The speed of a wave, v = 12 m/s
The wavelength of a wave, [tex]\lambda=3\ m[/tex]
We need to find the frequency of the wave. We know that the speed of wave is equal to the product of wavelength and frequency. So,
[tex]v=f\lambda\\\\f=\dfrac{v}{\lambda}\\\\f=\dfrac{12}{3}\\\\f=4\ Hz[/tex]
So, the frequency of the wave is equal to 4 Hz.
The Earth wire only carries a current if there is a _____ in the
circuit. What one word completes the sentence?
Answer:
Fault
Explanation:
it only carries a current if there is a fault.
A particle which is moving in a straight line with a velocity of 15m/s accelerates uniformly for 3.0s, increasing its velocity to 45m/s. What distance does it travel while accelerating
The distance travel while accelerating is 90m
The initial velocity of the particle is 15m/s and the final velocity is 45m/s, so the change in velocity is 45m/s - 15m/s = 30m/s. The particle accelerates uniformly for 3.0s, so the acceleration is 30m/s / 3.0s >>30/3=10 that is 10m/s^2.
The distance traveled during the acceleration is equal to the average velocity times the time elapsed, so the distance traveled is (15m/s + 45m/s)/2 * 3.0s = (15+45)/2*3= 90m .
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What influences speed of an objects fall? (Choose as many as apply)
1. Sunlight
2. Air
3. Altitude
4. Heat
Altitude and Air
but mainly altitude, Air is just depending on the situation.
Air does not always influence an object's fall, but Altitude always influences it.