f(a)=(a+2)^2
g(a)=5a+4
g(f(-2))
Evaluate g(f(-2)) = ???

Step-by-step explanation:

y=x+6.......(1)

y=-3X-6....(2)

from eq (1), we get,

x=y-6....(3)

sub eq (3) in eq (2), we get

y= -3(y-6)-6

y= -3y+18-6

y+3y-12=0

4y=12

y=3

sub value of y in eq (3)

x=3-6

x=-3

Answer: (3, 3)

Step-by-step explanation:

There are three general ways of solving a system of equations:

When solving systems of equations with graphing, look for points that overlap with each other or cross, and that will be the solution for the system. There might be one, two, or more than two solutions.

Please refer to the attachment below for the graph of the two equations.

Hope this helps!! :)

Please let me know if you have any questions

Answer:

[tex] \frac{2 - 3i}{4 + 2i} = \frac{1 - 8i}{10} [/tex]

Step-by-step explanation:

To simplify an expression like this, we multiply top and ottom of the fraction (denominator and numerator) by the complex conjugate of the bottom (numerator). For a complex expression (a+bi), the complex conjugate is (a−bi). When we do the calculation, it will become clear why this works so well.

Note that (a−bi)/(a−bi) is just the same as 1, so when we do this multiplication the result is the same number we started with.

[tex] \frac{2 - 3i}{4 + 2i} = \frac{2 - 3i}{4 + 2i} \times \frac{4 - 2i}{4 - 2i } \\ = \frac{8 - 12i - 4i + 6 {i}^{2} }{16 + 8i - 8i - 4 {i}^{2} } \\ = \frac{8 - 16i + 6 {i}^{2} }{16 - 4 {i}^{2} } [/tex]

But

[tex] i = \sqrt{ - 1} \: so \: {i}^{2} = - 1 [/tex]

Using this and collecting like terms, we have:

[tex]\frac{8 - 16i + (6 \times - 1) }{16 - 4 ( - 1) } = \frac{2 - 16i}{20} = \frac{1 - 8i}{10} [/tex]

Answer:

7, 3, 0, -3, -5, -8, -14

Step-by-step explanation:

I know 7 is the greatest value you add the most because to get to 7 from 0.

I know -14 is the least value because I subtracted the most to get to -14 from 0.

simplify the expression below

(x 1/15) 5

Using the law of indices we multiply the power outside the parenthesis with the power inside the parenthesis.

Therefore,

1/15 x 5 = 5/15 = 1/3

After multiplying the power, we reduce the fraction to it lowest term. By doing so we get the fraction power of 1/3.

our final expression will be like

(xA 1/15) A 5 multiply the power

(xA 5/15) reduce the fraction power to it lowest term

(1/x3)

Answer:

yes

Step-by-step explanation:

since it can be expressed as a fraction, it is rational

Answer:

a)

Step-by-step explanation:

Y=k/x........(1)

Put y and x in (1) to get:

3=k/5

K=15

Now put k=15 in (1):

Y=15/x

b)

Y=k/x as x=45

Y=15/45

Y=1/3

Step-by-step explanation:

4(1-3x)+7x-8

4-12x+7x-8

-12x+7x+4-8

-5x-4

Answer:

According to factor theorem, if f(x) is a polynomial of degree n ≥ 1 and 'a' is any real number, then, (x-a) is a factor of f(x), if f(a)=0. ... Also, we can say, if (x-a) is a factor of polynomial f(x), then f(a) = 0. This proves the converse of the theorem.

The shaded region of a circle formed by one line as shown in the image is called a segment.

Answer: segment

Answer:

500 - 6r = t

Step-by-step explanation:

500 represents the amount of copper wire Lisa started with.

-6r represents how much copper wire (in yards) is used on the robot (9*2 / 3 = 6).

t represents the total wire left after Lisa builds r robots.

Answer:

14th term is 16,384

Step-by-step explanation:

I. When [tex]a_{n} = a_{1}(r^{n-1} )[/tex]

If n = 14, a = 2 and r = 2

         [tex]a_{14} = 2(2^{14-1} )[/tex]

               = 2([tex]2^{13}[/tex])

         [tex]a_{14}[/tex]      = 16,384

Answer:

It's option B. 4x^3 - 33x^2 + 65x - 66

See the attached image for my work:

Answer:

f(1) = 2 f(3) = 8 f(t) = 2^t

Step-by-step explanation:

you just plug in the number in the parenthesis next to f to x in the equation 2^x

Answer:

[tex] = \frac{33}{14} [/tex]

Step-by-step explanation:

[tex] - 10 \frac{2}{7} + ( - 4 \frac{4}{11} )[/tex]

➡️ [tex] - \frac{72}{7} \div - ( \frac{48}{11} )[/tex]

➡️ [tex] \frac{72}{7} \times \frac{11}{48} [/tex]

➡️ [tex] \frac{3}{7} \times \frac{11}{2} [/tex]

➡️ [tex] \frac{33}{14} [/tex] ✅

The metal displaced a volume of

58.85 mL - 31.47 mL = 27.38 mL = 27.38 cm³

of water, which is to say the metal has this volume.

If the metal has a mass of 287.8 g, then its density is its mass per unit volume,

(287.8 g)/(27.38 cm³) ≈ 10.51 g/cm³

Answer:

167

812

Step-by-step explanation:

I think it's correct and helping you get a great day:)

Answer:

C. Y=2x

Step-by-step explanation:

I hope this help you

Answer:

[tex] {x}^{2} + x + xy + y + zx + z \\ = x(x + 1 + y + y + z) + z \\ = x(x + 2y + z + 1) + z[/tex]

Answer:

2 kg

Step-by-step explanation:

5 - 3 = 2

Hey there!

First, read the the problem again and look for any clues. "Have left" is a phrase that would be used for subtraction. So, 5 kg - 3kg = 2 kg.

Patrick has 2 kilograms of sugar left.

Hope this helps!

Have a great day!

Answer:

see explanation

Step-by-step explanation:

The inverse of a matrix A = [tex]\left[\begin{array}{ccc}a&b\\c&d\\\end{array}\right][/tex] is

[tex]A^{-1}[/tex] = [tex]\frac{1}{ad-bc}[/tex] [tex]\left[\begin{array}{ccc}d&-b\\-c&a\\\end{array}\right][/tex]

If ad - bc = 0 then the matrix has no inverse

A = [tex]\left[\begin{array}{ccc}11&-5\\3&-1\\\end{array}\right][/tex]

ad - bc = (11 × - 1) - (- 5 × 3) = - 11 - (- 15) = - 11 + 15 = 4 , then

[tex]A^{-1}[/tex] = [tex]\frac{1}{4}[/tex] [tex]\left[\begin{array}{ccc}-1&3\\-5&11\\\end{array}\right][/tex] = [tex]\left[\begin{array}{ccc}-0.25&0.75\\-1.25&2.75\\\end{array}\right][/tex]

Answer:

Step-by-step explanation:

[tex]A=\begin{bmatrix}11&-5\\3&-1\end{bmatrix}\\det(A)=11*(-1)-3*(-5)=-11+15=4\\minor=\begin{bmatrix}-1&3\\-5&11\end{bmatrix}\\cofactor=\begin{bmatrix}-1&-3\\5&11\end{bmatrix}\\Transposed\ cofactor=\begin{bmatrix}-1&5\\-3&11\end{bmatrix}\\A^{-1}=\dfrac{Transposed\ cofactorx}{det(A)} =\begin{bmatrix}\dfrac{-1}{4} &\dfrac{5}{4} \\\\ \dfrac{-3}{4} &\dfrac{11}{4}\end{bmatrix}\\[/tex]

[tex]Proof:\\A*A^{-1}=\begin{bmatrix}11&-5\\\\3&-1\end{bmatrix}*\begin{bmatrix}\dfrac{-1}{4} &\dfrac{5}{4}\\\\ \dfrac{-3}{4}&\dfrac{11}{4}\end{bmatrix}\\\\\\=\begin{bmatrix}\dfrac{-11+15}{4} &\dfrac{55-55}{4}\\\\ \dfrac{-3+3}{4}&\dfrac{15-11}{4}\end{bmatrix}\\\\\\=\begin{bmatrix}1&0\\\\ 0&1\end{bmatrix}\\[/tex]

Bonus: method of Gauss 's pivot jointed

Answer:

2. ☑ A [tex]\displaystyle f(x) = tan\:\frac{1}{2}x[/tex]

☐ B [tex]\displaystyle f(x) = tan\:2x[/tex]

☐ C x = [tex]\displaystyle 2tan\:x[/tex]

1. ☐ A [tex]\displaystyle \frac{\pi}{2}[/tex]

☐ B [tex]\displaystyle \pi[/tex]

☑ C [tex]\displaystyle 2\pi[/tex]

Explanation:

[tex]\displaystyle \boxed{f(x) = -cot\:(\frac{1}{2}x - \frac{\pi}{2})} \\ \\ y = Acot(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\pi} \hookrightarrow \frac{\frac{\pi}{2}}{\frac{1}{2}} \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \hookrightarrow \boxed{2\pi} \hookrightarrow \frac{\pi}{\frac{1}{2}} \\ Amplitude \hookrightarrow N/A[/tex]

OR

[tex]\displaystyle y = Atan(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \hookrightarrow \boxed{2\pi} \hookrightarrow \frac{\pi}{\frac{1}{2}} \\ Amplitude \hookrightarrow N/A[/tex]

Here is all the information you will need. Now, what you need to know is that ALL tangent, secant, cosecant, and cotangent functions have NO amplitudes. Also, keep in mind that although this IS the tangent graph, if you plan on writing your equation as a function of cotangent, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = cot\:\frac{1}{2}x,[/tex] in which you need to replase "tangent" with "cotangent", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the tangent graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the cotangent graph [photograph on the right] is shifted [tex]\displaystyle \pi\:units[/tex] to the left, which means that in order to match the tangent graph [photograph on the left], we need to shift the graph FORWARD [tex]\displaystyle \pi\:units,[/tex] which means the C-term will be positive, and perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{\pi} = \frac{\frac{\pi}{2}}{\frac{1}{2}},[/tex] but we are NOT YET DONE. Although we shifted the graph back into position, remember, cotangent is graphed in REVERCE, so we need to insert a negative in front of the amplitude term, and with that, the cotangent graph of the tangent graph, accourding to the horisontal shift, is [tex]\displaystyle y = -cot\:(\frac{1}{2}x - \frac{\pi}{2}).[/tex] Now, with all that being said, we can move forward. To find the period in this case, you need to take a look at the distanse between each vertical asymptote. Now, accourding to this graph, the vertical asymptotes are [tex]\displaystyle -\pi = x\:and\:\pi = x.[/tex] From here, you will then find the distanse between these asymptotes by simply perfourming the operation of Deduction, and doing that will give you [tex]\displaystyle \boxed{2\pi} = \pi + \pi.[/tex] So, the period of this function is [tex]\displaystyle 2\pi.[/tex] Now, you will instantly get the jist of the horisontal shift by looking at the above formula. Just keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must pay cloce attention to what is given to you inside those parentheses. Finally, the midline is the centre of your graph, also known as the vertical shift, which in this case is at [tex]\displaystyle y = 0.[/tex]

Well, that just about wraps it up. Now that everything has been explained, you should understand it better. If you still have questions, do not hesitate to comment any you have.

I am delighted to assist you at any time.

Answer:

c

Step-by-step explanation:

it is because in (a) the square root of 112. is 10.58 which is in between 10 and 11

(B) the square root of 180 is 13.42 which is between 13&14

(c) the square root of 12 is 3.46 which is not between 4&5

Answer:

C the square root  of 12 is between 4&5.

Step-by-step explanation:

Answer:

0.72 repeat

Step-by-step explanation:

              __

8 ÷ 11 =0.72

Step-by-step explanation:

steps are in the picture above.

Note:if you need to ask any question please let me know.

Answer:

1

Step-by-step explanation:

The second power and square root cancel each other (second power means squared by the way)

Answer:it depends what was on it but i would say about 500

Step-by-step explanation:

Answer:

x = 8

Step-by-step explanation:

A common pythagorean triplet is 7, 8, 9

Answer:

11.4

Step-by-step explanation:

Pythagorean theorem

[tex]7^{2}[/tex] + [tex]9^{2}[/tex] = [tex]x^{2}[/tex]

49 + 81 = [tex]x^{2}[/tex]

130 = [tex]x^{2}[/tex]

11.4 = x