The basis for the eigenspace corresponding to lambda=5,1,4 are None,[tex]\left[\begin{array}{c}-1 \\\frac{1}{2} \\0\end{array}\right][/tex] and [tex]$\left[\begin{array}{l}2 \\ 1 \\ 1\end{array}\right]$[/tex]
[tex]$$A=\left[\begin{array}{ccc}5 & -12 & 10 \\0 & 7 & -3 \\0 & 6 & -2\end{array}\right]$$[/tex]
Eigenspace corresponding to lambda=5,1,4
The eigenspace E_lambda corresponding to the eigenvalue lambda is the null space of the matrix a [tex]\mathrm{A}-(\lambda) \mathrm{I}"[/tex]
for lambda=5
[tex]$$\mathrm{E}_5=\mathrm{N}(\mathrm{A}-5 \mathrm{I})$$[/tex]
Reducing the matrix A-5I by elementary row operations
[tex]$$\begin{aligned}A-5 I & =\left[\begin{array}{ccc}5-5 & -12 & 10 \\0 & 7-5 & -3 \\0 & 6 & -2-5\end{array}\right] \\& =\left[\begin{array}{ccc}0 & -12 & 10 \\0 & 2 & -3 \\0 & 6 & -7\end{array}\right] \\& \sim\left[\begin{array}{ccc}0 & -12 & 10 \\0 & 1 & -\frac{3}{2} \\0 & 6 & -7\end{array}\right] R_2 \rightarrow \frac{R_2}{2} \\& \sim\left[\begin{array}{ccc}1 & 0 & -8 \\0 & 1 & -\frac{3}{2} \\0 & 6 & -7\end{array}\right] R_1 \rightarrow R_1+2 R_2\end{aligned}$$[/tex]
[tex]\sim\left[\begin{array}{ccc}1 & 0 & -8 \\ 0 & 1 & -\frac{3}{2} \\ 0 & 0 & 2\end{array}\right] R_3 \rightarrow R_3-6 R_2$$\\\sim\left[\begin{array}{ccc}1 & 0 & -8 \\ 0 & 1 & -\frac{3}{2} \\ 0 & 0 & 1\end{array}\right] R_3 \rightarrow \frac{\mathrm{R}_3}{2}$$\\\sim\left[\begin{array}{ccc}1 & 0 & 0 \\ 0 & 1 & -\frac{3}{2} \\ 0 & 0 & 1\end{array}\right] \mathrm{R}_1 \rightarrow \mathrm{R}_1+8 \mathrm{R}_3$[/tex]
[tex]$\sim\left[\begin{array}{lll}1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1\end{array}\right] R_2 \rightarrow R_2+\frac{2 R_3}{2}$[/tex]
The solutions x of A-5I=0 satisfy x_1=x_2=x_3=0 that is, the null space solves the matrix
[tex]$$\left[\begin{array}{lll}1 & 0 & 0 \\0 & 1 & 0 \\0 & 0 & 1\end{array}\right]\left[\begin{array}{l}x_1 \\x_2 \\x_3\end{array}\right]=\left[\begin{array}{l}0 \\0 \\0\end{array}\right]$$[/tex]
Hence The null space is [tex]\left[\begin{array}{l}0 \\ 0 \\ 0\end{array}\right] E_5[/tex] has no basis
[tex]$$\begin{aligned}& \text { case: } 2 \\& \text { for } \lambda=1 \\& \mathrm{E}_5=\mathrm{N}(\mathrm{A}-(1) \mathrm{I})\end{aligned}$$[/tex]
we reduce the matrix A-I by elementary row operations as follows.
[tex]$$\begin{aligned}A-1 & =\left[\begin{array}{ccc}5-1 & -12 & 10 \\0 & 7-1 & -3 \\0 & 6 & -2-1\end{array}\right] \\& =\left[\begin{array}{ccc}1 & -3 & \frac{5}{2} \\0 & 6 & -3 \\0 & 6 & -3\end{array}\right] R_1 \rightarrow \frac{R_1}{4} \\& \sim\left[\begin{array}{ccc}1 & -3 & \frac{5}{2} \\0 & 1 & -\frac{1}{2} \\0 & 6 & -3\end{array}\right] R_2 \rightarrow \frac{R_2}{6}\end{aligned}[/tex]
[tex]$$$\sim\left[\begin{array}{ccc}1 & 0 & 1 \\ 0 & 1 & -\frac{1}{2} \\ 0 & 6 & -3\end{array}\right] R_1 \rightarrow R_1+3 R_2$\\$\sim\left[\begin{array}{ccc}1 & 0 & 1 \\ 0 & 1 & -\frac{1}{2} \\ 0 & 0 & 0\end{array}\right] R_3 \rightarrow R_3-6 R_2$[/tex]
Thus, the solutions x of (A-I) X=0 satisfy
[tex]$\left[\begin{array}{ccc}1 & 0 & 1 \\ 0 & 1 & -\frac{1}{2} \\ 0 & 0 & 0\end{array}\right]\left[\begin{array}{l}x_1 \\ x_2 \\ x_3\end{array}\right]=\left[\begin{array}{l}0 \\ 0 \\ 0\end{array}\right]$[/tex]
x_3=t
[tex]$\Rightarrow \mathrm{x}_1=-\mathrm{t}, \mathrm{x}_2=\frac{\mathrm{t}}{2}$[/tex]
[tex]$\vec{x}=\left[\begin{array}{c}-t \\ \frac{t}{2} \\ t\end{array}\right]=\left[\begin{array}{c}-1 \\ \frac{1}{2} \\ 1\end{array}\right] t$[/tex]
The Basis for the nullspace A-I will be: [tex]$\left.\left(\begin{array}{c}-1 \\ \frac{1}{2} \\ 1\end{array}\right]\right)$[/tex]
case:3
lambda=4
[tex]$$\mathrm{E}_5=\mathrm{N}(\mathrm{A}-(4) \mathrm{I})$$[/tex]
we reduce the matrix A-4I by elementary row operations as follows.
[tex]$\begin{aligned} A-4 \mid & =\left[\begin{array}{ccc}5-4 & -12 & 10 \\ 0 & 7-4 & -3 \\ 0 & 6 & -2-4\end{array}\right] \\ & =\left[\begin{array}{ccc}1 & -12 & 10 \\ 0 & 3 & -3 \\ 0 & 6 & -6\end{array}\right] \\ & \sim\left[\begin{array}{ccc}1 & -12 & 10 \\ 0 & 1 & -1 \\ 0 & 6 & -6\end{array}\right] R_2 \rightarrow \frac{R_2}{3}\end{aligned}$[/tex]
[tex]$\begin{aligned} & \sim\left[\begin{array}{ccc}1 & 0 & -2 \\ 0 & 1 & -1 \\ 0 & 6 & -6\end{array}\right] \mathrm{R}_1 \rightarrow \mathrm{R}_1+12 \mathrm{R}_2 \\ & \sim\left[\begin{array}{ccc}1 & 0 & -2 \\ 0 & 1 & -1 \\ 0 & 0 & 0\end{array}\right] \mathrm{R}_3 \rightarrow \mathrm{R}_3-6 \mathrm{R}_2\end{aligned}$[/tex]
Thus, the solutions x of (A-4IX)=0 satisfy
[tex]$$\left[\begin{array}{ccc}1 & 0 & -2 \\0 & 1 & -1 \\0 & 0 & 0\end{array}\right]\left[\begin{array}{l}x_1 \\x_2 \\x_3\end{array}\right]=\left[\begin{array}{l}0 \\0 \\0\end{array}\right]$$[/tex]
x_3=t
[tex]$\Rightarrow \mathrm{x}_1=2 \mathrm{t}, \mathrm{x}_2=\mathrm{t}$[/tex]
[tex]$$\vec{x}=\left[\begin{array}{c}2 t \\t \\t\end{array}\right]=\left[\begin{array}{l}2 \\1 \\1\end{array}\right] t$$[/tex]
The Basis for the nullspace A-4 I will be [tex]\left(\left[\begin{array}{l}2 \\ 1 \\ 1\end{array}\right]\right)[/tex]
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Write the coordinates of the vertices after a rotation 90 degrees counterclockwise around the origin.
Answer: J' (8, -9); K' (8, -2); L' (3, -2); M' (3, -9)
Step-by-step explanation:
A rotation of 90 degrees counterclockwise is (x, y) -> (-y, x), so
J (-9, -8) -> J' (8, -9)
First, you take negative 8 (y) of J and make it positive 8 for the x of J'. Then, take -9 (y) of J and switch it to x of J'.
You repeat this process for the rest of the points. X switches to Y with the opposite sign and Y switches to X but stays the same.
K (-2, -8) -> K' (8, -2)
L (-2, -3) -> (3, -2)
M (-9, -3) -> (3, -9)
The ratio of chocolate kisses in a party favor bag to people it will serve is 1:5. If Deb wants to provide party favor bags to 80 people, how many bags will Deb use?
Answer:
times 1 by 80 and 5 by 80
Step-by-step explanation:
then you can determine from there
What does -= mean in Python?
In Python an operator -= is subtracts the value on its right to the variable and assigns the result to the variable on its left.
As we know an operator is nothing but a symbol that represents a mathematical or logical process.
We know that in Python the operator -= provides a way to subtract a value to an existing variable and assign the new value back to the same variable.
If m -= n
This means, the variable m the left side is getting added to the value on the right side (n), and the result is then reassigned to the variable on the left.
i.e., m = m - n
-= is an assignment operator.
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PLEASE HELP? The standard form for the function is: P(x)=-5x^+120x-315.
Rewrite the function in vertex form.
Answer:
P(x) = -5(x² - 12)² + 405
Step-by-step explanation:
P(x) = -5x² + 120x - 315
Factor out -5 from the first two terms
P(x) = -5(x² - 24x) - 315
Complete the square
P(x) = -5(x - 12)² - (-5(-12)²) -315
P(x) = -5(x - 12)² + 720 - 315
P(x) = -5(x - 12)² + 405
Find the solution of (x+2)^2 +2=6 by using square roots method
Answer:
(x + 2)² +2 = 6(x + 2)² = 4√(x + 2)² = √4x + 2 = ± 2x = -2 ± 2x = -4, x = 0It takes a ship three hours to cover 72 km with the current and 4 hrs against the current. Find the speed of the ship in still water and the speed of the current.
Answer:
3km/h and the speed of the ship is 21 km/h.
Step-by-step explanation:
Answer:
The current is 3km/h and the speed of the ship is 21 km/h.
Step-by-step explanation:
help help help help help help
The equation point slope is y - y1 = m(x - x1)
we got y - (-16)=3(x-7)
what is meant by point of slope?Point-slope is the general form y-y₁=m(x-x₁) for linear equations. It emphasizes the slope of the line and a point on the line (that is not the y-interceptThe slope intercept formula y = mx + b is used when you know the slope of the line to be examined and the point given is also the y intercept (0, b). In the formula, b represents the y value of the y intercept pointA simple definition of point-slope form is an equation of a line written using one point on the line and the slope of the line. The point form is written as (x,y) and the slope is the rise over run, or the ratio of the change in the y values over the change in the x valuesThe slope of a line is a measure of its steepness. Mathematically, slope is calculated as "rise over run" (change in y divided by change in x).To learn more about point of slope refers to:
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I need help with my final!
Answer:
(-7, 4)
Step-by-step explanation:
How do I solve problem 7?
Answer:
16ᵗʰ Term of the sequence is 1010
Step-by-step explanation:
7.)
Here,
First Term = a₁ = 5
Common Difference = d = 67
Now, For 16ᵗʰ term, n = 16
aₙ = a + (n - 1)d
a₁₆ = 5 + (16 - 1) 67
a₁₆ = 5 + 15 × 67
a₁₆ = 5 + 1005
a₁₆ = 1010
Thus, 16ᵗʰ Term of the sequence is 1010
-TheUnknownScientist
Two children take turns breaking up a rectangular chocolate bar 6 squares wide by 8 squares long. They may break the bar only along the divisions between the squares. If the bar breaks into several pieces, they keep breaking the pieces up until only the individual squares remain. The player who cannot make a break loses the game. Who will win
The player who goes first will win.
This is because the chocolate bar can be broken up into 6*8=48 squares, and the player who goes first can always ensure that the second player is left with one square on their turn (by breaking the bar into two pieces that leave one square for the second player to take). This means that the second player will always be the one who cannot make a break, and thus loses the game.
Therefore, The player who goes first will win.
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PEASE HELP RIGHT AWNSER GETS THE CROWN THING
Answer: i believe that the answer is B :)
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
We can either use the graph or the chart.
For this question it'll be easier to use the graph.
First find the y-intercept (that were your line meet the y-axis)
y = 4
Then find the slope ([tex]\frac{rise}{run} = \frac{2}{1} = 2[/tex])
Slope = 2
Then plug them into the equation: y = mx + b
m = slope = 2
b = y-intercept = 4
y = 2x + 4
Therefore, the answer is A
help please (mhanifa)
For each question order the cards from least to greatest. If the feature is equal to two or more functions, place them next to each other.Maximum value on the interval 2 ≤ x ≤ 6
(sort the cards/letters from least to greatest based on Maximum value on the interval 2 ≤ x ≤ 6)
Answer:
u sus imposter
Step-by-step explanation:
Oof I need help again plz people
Answer:
3/10 m^2
Step-by-step explanation:
To find the area of the rectangle
A = l*w
= 2/5 * 3/4
=6/20
Divide the top and bottom by 2
= 3/10 m^2
Answer:
As a decimal it would be 0.3 but as a faction it would be 3/10
Step-by-step explanation:
2/5 times 3/4 = 0.3 or 3/10
In the figure, m∠AOB = m∠COD. Which property of equality will you use to prove m∠AOC = m∠BOD?
A)
Subtraction
B)
Transitive
C)
Addition
D)
Symmetric
Answer:
transitive
.......gguf
Find the value of xx in the equation below.
11=
11=
\,\,x -6
x−6
Answer:
Find the value of xx in the equation below.
11=
11=
\,\,x -6
x−6
Step-by-step explanation:
Of the 360 members of the kennel club who were
surveyed, 190 said they would try a new dog food.
If the kennel club has 2,100 members, how many
could be expected to try the new dog food?
URGENT! HOMEWORK DUE TOMORROW MORNING!
Miguel has three times as many dimes as he has quarters. He has as many nickels as he has dimes and quarters combined. The total amount of money he has is $3.00. How many of each coin does Miguel have?
After solving the algebraic equation, Miguel has 4 quarters, 12 dimes and 16 nickels.
What is algebra?
One of the earliest areas of mathematics that deals with number theory, geometry, and analysis is algebra. Algebra is also defined as the study of mathematical rules and symbols through the manipulation of those mathematical symbols.
The number of quarters is taken to be x, then the number of dimes will be 3x, and the number of nickels will be 3x + x = 4x
$3.00 when converted to cents is 300 cents.
The value of nickels is 5 x 4x=20x.
The value of dimes is 10 x 3x=30x.
The value of quarters is 25x.
As the total value of money Miguel has is 300 cents, then the algebraic equation will be -
20x + 30x + 25x = 300
Solve to get the value of x -
75x = 300
x = 4
Therefore, the amount of quarters is x = 4 quarters.
The amount of dimes is x = 3x = 3 x 4 = 12 dimes.
The amount of nickels is 4x = 4 x 4 = 16 nickels.
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Cari owns a horse farm and a horse trailer that can transport up to 8000 pounds of livestock and take she travles with 5 horses whose combined weight is 6240
Complete question :
Cari owns a horse farm and a horse trailer that can transport up to 8000 pounds of livestock and take she travles with 5 horses whose combined weight is 6240
Let t represent the average weight of tack per horse, which of the following inequalities could be used to determine the weight of the tack cari can allow for each horse
Answer:
t ≤ 352
Step-by-step explanation:
Maximum allowable weight (tack and horse) = 8000 pounds
Combined weight of 5 horses = 6240
Let average weight of tack per horse = t
Average weight of tack for the 5 horses = 5t
Hence, weight of tack + weight of horse ≤ 8000
5t + 6240 ≤ 8000
5t ≤ 8000 - 6240
5t ≤ 1760
t ≤ 352
NEED HELP ASAP
NO LINKS AND NO JUST SAYING HI, PLEASE ANSWER LEGITIMATELY! THANK YOU!!!! <3
Answer:
85 degrees
Step-by-step explanation:
Hi there!
<x is an exterior of the triangle ABC. An exterior angle of a triangle is equal to the sum of the two opposite interior angles. Therefore, we could say that x is equal to the sum of 60 and 25:
60+25=x
85=x
Therefore, angle x measures 85 degrees.
I hope this helps!
Answer:
85
Step-by-step explanation:
HELPPP. I need help finding this answer
Answer:Don't know
Step-by-step explanation:
Eden is working on an experiment for her science fair project. She is planting a total of 10 herbs for an herb garden. She is going to plant basil and mint. The basil plants cost $.50 per plant and the mint plants cost $.25 per plant. Eden has a total of $3 to spend on plants because she also has to purchase potting soil and a long planter pot. Write a system of equations and solve either using elimination or substitution.
A system of equations for this problem can be written as:
x + y = 10 (1) equation for the total number of herbs planted
0.50x + 0.25y = 3 (2) equation for the total cost of the herbs
Where x is the number of basil plants and y is the number of mint plants.
Using substitution, we can solve the system of equations.
Solving equation (1) for x, we get x = 10 - y
Substituting this into equation (2) we get:
0.50(10 - y) + 0.25y = 3
5 - 0.50y + 0.25y = 3
5 = 0.75y + 3
0.75y = -2
y = -2/0.75 = -8/3
So, Eden planted -8/3 mint plants, which doesn't make sense, as a fraction of plant are not possible. This implies that either the number of plants or the amount spent are incorrect or something is missing in the problem description.
Find the value x that makes the equation true . x + 4 = 12
x = 16
x=8
x=24
x=3
Answer:
x = 8
Step-by-step explanation:
x + 4 = 12
Subtract 4 from both sides
x = 8
Let's check
8 + 4 = 12
12 = 12
So, x = 8 is correct!
If you can, please give me a Brainliest, thank you!
The rectangular floor of a classroom is 30 feet in length and 36 feet in width. A scale drawing of the floor has a length of 5 inches. What is the area, in square inches, of the floor in the scale drawing?
HURRYYYYYYYYYYYYYY
Answer:
30 in.²
Step-by-step explanation:
Real:
length 30 ft
width 36 ft
Scale:
length 5 in.
width ?
30/36 = 5/x
30x = 5 × 36
x = 6
The scale width is 6 inches.
Scale area:
area = length × width
area = 5 in. × 6 in.
area = 30 in.²
The area, of the floor in the scale drawing is 30 in.²
What is the unitary method?The area is the total amount of space that an object's shape or a flat (2-D) surface occupies.
Given that rectangular floor of a classroom is 30 feet in length and 36 feet in width. A scale drawing of the floor has a length of 5 inches.
length 30 ft
width 36 ft
Scale: length 5 in.
Then we have
30/36 = 5/x
30x = 5 × 36
x = 6
The scale width is 6 inches.
Scale area:
The area = length × width
area = 5 in. × 6 in.
area = 30 in.²
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Suppose you know the answer to 4/5*(20*1 7/8). Explain how the Commutative and Associative Properties of Multiplication can make the computation easier. Then find the answer
You can rearrange terms in an expression using the commutative and associative qualities to arrange compatible numbers next to one another and in groups.
What distinguishes an associative property from a commutative property?According to the associative property, numbers can be added to or multiplied while still maintaining the same result. According to the commutative property, even if the numbers are added or multiplied, the solution will remain the same.
Explain:
[tex]\frac{4}{5}[/tex] ×(20×17/8)
20×17/8
340÷8
[tex]\frac{4}{5}[/tex]×[tex]\frac{340}{8}[/tex]
= [tex]\frac{64}{2}[/tex]
= 32
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-x+6=-2(x+2)-5
Solve for x
Answer:
x = -15
Step-by-step explanation:
-x+6=-2(x+2)-5
Solve for x
-x + 6 = -2(x + 2) - 5
-x + 6 = -2x - 4 - 5
x = -15
------------------------
check- (-15) + 6 = -2(-15 + 2) - 5
21 = 21
the answer is goodx = -15
Given this equation in slope y - intercept form y=2x+5, the slope, and the y-intercept are represented as ______.
Answer:
slope is 2 ,, y intercept is 5
Step-by-step explanation:
y=mx+c
m represents slope
c represents y intercept
Use the distributive property to write an equivalent expression to 8(7 + 3y). Explain how you know they are equivalent.
Answer:
56 + 24y
Step-by-step explanation:
8(7 + 3y) = 56 + 24y
Because
8 * 7 = 56
8 * 3y = 24y
If the statement 4 > 3 is true, which of the following are true about the relationship between –4 and –3? Check all that apply.
–4 < –3
The inequality changes from greater than to less than because -4 is less than -3.
–4 > –3
The greater than inequality holds true even when the opposites of 4 and 3 are used.
–4 = –3
Answer: The answer is A and b, the person above me is wrong
Step-by-step explanation: Hope y'all stay safe and healthy! ^^
Benjamin invested $66,000 in an account paying an interest rate of 63%
compounded annually. Christian invested $66,000 in an account paying an interest
rate of 5% compounded continuously. After 19 years, how much more money would
Benjamin have in his account than Christian, to the nearest dollar?
Answer:
$16,755
Step-by-step explanation:
You want the difference in interest earned on $66,000 after 19 years between an account earning 6 3/8% compounded annually, and one earning 5 3/4% compounded continuously.
Interest formulasThe formula for the account value multiplier when interest is compounded annually is ...
k = (1 +r)^t . . . . . . compounded annually at rate r for t years
When interest is compounded continuously, the multiplier is ...
k = e^(rt)
ApplicationThe difference in account values between the two rates is ...
∆value = $66,000·(1 +0.06375)^19 -e^(0.0575·19))
∆value ≈ $16,754.70
Benjamin will have about $16,755 more than Christian after 19 years.
How do i solve this? (by factoring)
x(x+3)=x+8
[tex]\sf x\left(x+3\right)=x+8\\\\\\\\x^2+3x=x+8\\\\\\\\\sf \boxed{\sf\mathrm{Subtract\:}8\mathrm{\:from\:both\:sides}}\\\\\\\\\sf x^2+3x-8=x+8-8\\\\\\\\\sf \boxed{\sf \mathrm{Simplify}}\\\\\\\\\sf x^2+3x-8=x\\\\\\\\\boxed{\sf \mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}}\\\\\\\\\sf x^2+3x-8-x=x-x\\\\\\\\\boxed{\sf \mathrm{Simplify}}\\\\\\\\\sf x^2+2x-8=0\\\\\\\\\boxed{\sf factor~ x^2+2x-8=0}\\\\\\\\\sf \left(x-2\right)\left(x+4\right)=0[/tex]
[tex]\sf \boxed{\sf \mathrm{Using\:the\:Zero\:Factor\:Principle:\quad \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0}\\\\\\\\\sf x-2=0\quad \mathrm{or}\quad \:x+4=0\\\\\\\\\boxed{\sf \{x=2\}}\\\\\boxed{\sf \{x=-4 \} }[/tex]