Find the area of an equilateral triangle with a side length of 14.

Answer:

8

Step-by-step explanation:

Answer:

7

Step-by-step explanation:

We have 42 oranges. we want to split the oranges evenly to 6 people. 42 divided by 6 people equals 7 oranges a person.

42÷6

=7

so each person will have 7 oranges.

Answer:

X = 10.4

Step-by-step explanation:

Since the angle is a 90 degress angle we can assume that

39 + (5x-1) = 90 degrees.

Therefore we can subtract 39 from both sides which will give us

5x-1=51

Add 1 to both sides

5x = 52

Divide both sides by 5

x=52/5

The answer is

X = 10.4

Hope this helps! :)

Answer:

in third quadrant... i thinkso

Answer: 4?

Step-by-step explanation: im prob wrong

Answer:

3.5

Step-by-step explanation:

Answer:

[tex]x > - 14[/tex]

Step-by-step explanation:

Since the dot in the illustration isn't filled in, that means that x can not be a part of -14, which means it is greater than 14

[tex]\dfrac{3}{\sqrt 7- \sqrt 2}\\\\\\=\dfrac{3 \left( \sqrt 7+ \sqrt 2\right)}{\left(\sqrt 7- \sqrt 2 \right)\left( \sqrt 7+\sqrt 2\right)}\\\\\\=\dfrac{3 \left( \sqrt 7+ \sqrt 2\right)}{\left(\sqrt 7 \right)^2 - \left(\sqrt 2 \right)^2 }\\\\\\= \dfrac{3 \left( \sqrt 7+ \sqrt 2\right)}{7-2}\\\\\\=\dfrac{3 \left( \sqrt 7+ \sqrt 2\right)}5[/tex]

Answer:

It's A!

Step-by-step explanation:

A good strategy to pay down the principal of the student loan is making payments in monthly instalments, the correct option is A.

A student loan is the amount borrowed by a student from a bank or any other financial institution for studies.

The borrowed amount is large and it becomes a burden if decided to pay all at once after studies on getting a job, a monthly payment of instalments is the right strategy.

To know more about Student Loan

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4. sector angle = 120°

area of sector = 120/360* π*r^2

= 1/3 π *36 = 12π = 37.69 cm^2

area of isosceles ∆ = .5*36*sin 120 = 15.58cm^2

area of shaded portion = 37.69 - 15.58= 22.11 cm^2

5. sector area = 90/360 * π * 64 = 16π ft^2

area of right ∆ = 1/2*64= 32ft^2

shaded portion area = 16π-32 = 18.26ft^2

6. sector area = 60/360 π 36 = 6π m^2

triangle area = √3/4 * 36 = 9√3 m^2

shaded area = 18.84 - 9√3 = 3.26 m^2

7. sector area = 45/360*π*18^2 = 40.5 π yd^2

8. sector area = 90/360*π*16 = 64π cm^2

9. sector area = 60/360 * π * 169 = 28.16π m^2

10. sector area = 135/360*π*64 = 24π cm^2

1. circle area = π*5.5^2 = 30.25π cm^2

2. circle area = π*0.85*.85 = .7225π ft^2

3. circle area = π * 1/9 in^2

Answer: y=80x

Step-by-step explanation:

It should be 80x ....try that

Answer:

the answer to that question is 5.314

Answer:

600

Step-by-step explanation:

10x60=600

since its 10% you multiply by 10 to get 100%

Your answer is (3,6)

Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form:

(3,6)

Your Answer:

Your answer is (3,6)

Answer:

Step-by-step explanation:

Givens

Circle:      3 grams       Number:  1  right hand side Number LHS: 2

Square:   2 grams        Number:  2 Number LHS: 5

Triangle: x                    Number:  5  Number LHS: 2

Formula

Mass RHS   = Mass LHS

Solution

3*1 + 2*2 + 5x = 3*2 + 5*2 + 2*x        Combine

3 + 2 + 5x = 6 + 10 + 2x

5 + 5x = 16 + 2x                                 Subtract 5 from both sides

5-5+5x = 16-5 + 2x                            Combine

5x = 11 + 2x                                       Subtract 2x from both sides

3x = 11                                               Divide by 3

x = 11/3

As you can see, I'm not getting any of the answers that you have provided. Ask your teacher how it was done. (The method used is correct).

Answer:

b and d i think hope this helps

Step-by-step explanation:

[tex] m \angle B = 22 \degree[/tex]

Explanation:

Given:

[tex]\sf m \angle A = 120 \\ \sf m\angle B =x \\\sf m \angle C = x+16[/tex]

To find:

[tex]\sf m\angle B \: = ?[/tex]

Solution:

We know that,

sum of all the interior angle of triangle equals 180 degrees.

[tex]\sf m \angle A + m\angle B + m \angle C = 180 \degree \\ \sf 120 + x + x + 16 = 180 \degree \\ \: \sf 2x+136= 180\degree \\ \: \sf 2x=180-136 \\ \:\sf 2x=44 \degree \\ \sf \: x= \frac{44}{2} \\ \:\sf x= 22 \degree[/tex]

Measure of angle B is equal to x hence,

[tex] m \angle B = 22 \degree[/tex]

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Step-by-step explanation:

Check out the attached photo

Answer:

3

Step-by-step explanation:

Answer:

a = 6

b = 25

Step-by-step explanation:

As alternative angles in a parallel line are equal to each other,

5a = 3a + 12

So, now we can find the value of a by making "a" the subject.

5a - 3a = 12

2a = 12

Divide both sides by 2.

a = 6°

And now let us find the value of b.

We know that interior angles in a triangle are added up to 180°.

So,

2b + 4b + 3a + 12 = 180

We can replace a with 6 and then we can make "b" the subject to find the value of b.

Let us solve it now.

2b + 4b + 3 × 6 + 12 = 180

6b + 18 + 12 = 180

6b + 30 = 180

6b = 180 - 30

6b = 150

Divide both sides by 6.

b = 25°

Answer:

The exponential function, exp : R → (0,∞), is the inverse of the natural logarithm, that is, exp(x) = y ⇔ x = ln(y). Remark: Since ln(1) = 0, then exp(0) = 1. Since ln(e) = 1, then exp(1) = e.

Step-by-step explanation:The exponential function, exp : R → (0,∞), is the inverse of the natural logarithm, that is, exp(x) = y ⇔ x = ln(y). Remark: Since ln(1) = 0, then exp(0) = 1. Since ln(e) = 1, then exp(1) = e.

The function Q is a linear function  because the function Q has a constant rate

The functions are given as:

A linear function is represented as:

y = mx + b

Where m represents the slope, and b represents the y-intercept

By comparing y = mx + b to the functions, we can see that the function Q is a linear function.

This is so because the function Q has a constant rate, while the function P does not have a constant rate

Read more about linear functions at:

https://brainly.com/question/4025726

Answer:

Each book cost about $6.20 per book, or in more general terms, $6 per book.

Step-by-step explanation:

If you round the $30.85 total of 5 books to $31 and divide that by 5, you get an average cost of $6.20 per book.

If you need a more general answer, you could round the $30.85 total of 5 books to $30 and divide that by 5, you get an average cost of $6 per book.

Answer:

12-2 is 10

Step-by-step explanation:

Answer: 6

Step-by-step explanation:

Answer:

[tex] \frac{ 3 }{100} < \frac{1}{10} < 0.8 < 0.91[/tex]

Step-by-step explanation:

0.8=0.8

1/10=0.1

3/100=0.03

0.91=0.91

Hence required arrangement

0.03,0.1,0.8,0.91

I hope it helped you

Answer:
I'm pretty sure its 0.03,0.1,0.8,0.91

Step-by-step explanation:

i did the assignment too :)

Step-by-step explanation:

For 1st Circle, A1= 36π

For 2nd Circle, A2= 81π/4

A1-A2 = 63π/4

π = 22/7

=49.5unit²

The differences in the areas of circles in square centimeters is 49.455

[tex]A = \pi r^{2}[/tex]

Where,

A is the area of circle

r is the radius of circle

and π = 3.14

Radius of circle is the distance from the center of the circle to any point on it's circumference. It is calculated as :

[tex]Radius = \frac{diameter}{2}[/tex]

According to the given question

Diameter of one circle is 12cm and diameter of another circle 9cm.

Area of circle with diameter 12 cm = [tex]\pi (\frac{12}{2} )^{2}[/tex] = [tex](3.14)(6)^{2}[/tex] = 113.04 square cm

Area of circle with diameter 9 cm = [tex]\pi( \frac{9}{2} )^{2} =(3.14)(4.5)^{2} = 63.585[/tex] square cm

Therefore,

The difference between the areas of two circles = (113.04 -63.585) square centimeter = 49.455 square centimeter.

Learn more about the area of circle here:

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Answer:

13

Step-by-step explanation:

13 is the number in the very middle of the set.

Another way to find this is to add up all numbers and divide by the total in the data set which in this case would be 26

the x-intercepts are simply found by setting y = 0 and then solving for "x", now, this equation doesn't factor in nice integers, so let's plug it in the quadratic formula.

[tex]\stackrel{f(x)}{0}~~ = ~~4x^2+10x-7 \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{quadratic formula} \\\\ 0=\stackrel{\stackrel{a}{\downarrow }}{4}x^2\stackrel{\stackrel{b}{\downarrow }}{+10}x\stackrel{\stackrel{c}{\downarrow }}{-7} \qquad \qquad x= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a} \\\\\\ x= \cfrac{ - (10) \pm \sqrt { (10)^2 -4(4)(-7)}}{2(4)}\implies x=\cfrac{-10\pm\sqrt{100+112}}{8}[/tex]

[tex]x=\cfrac{-10\pm\sqrt{212}}{8}\implies x=\cfrac{-10\pm 2\sqrt{53}}{8}\implies x=\cfrac{-5\pm \sqrt{53}}{4} \\\\\\ x= \begin{cases} \frac{-5 + \sqrt{53}}{4}\\\\ \frac{-5 - \sqrt{53}}{4} \end{cases}\qquad \qquad x\approx \begin{cases} 0.57\\ -3.07 \end{cases}[/tex]

Answer:

[tex] \cos( \alpha ) = \frac{7}{25} \\ \alpha = (73.73979529169) \\ \ \sin(73.73979529169) = \frac{h}{25} \\ h = \sin(73.73979529169) \times 25 \\ h = 24[/tex]