find the areas of the sectors formed by angleDFE. Round your answers to the nearest hundredth

The equation y = -1/2(x-3)² + 5  reduces the graph, which means that the graph decreases as we move away from the vertex (3, 5) in both directions along the x-axis.

In mathematics, a graph is a visual representation of a set of objects (called vertices or nodes) and the connections (called edges) between them.

The equation y = -1/2(x-3)² + 5 is a quadratic function in vertex form. The vertex of this parabola is at the point (3, 5), and the coefficient of the x²  term is negative (-1/2), which tells us that the parabola opens downwards. This means that the graph of this equation reduces.

To see why this is the case, consider the behavior of the y-values as x moves away from the vertex. Since the leading coefficient is negative, the y-values will decrease as x moves to the left or right from the vertex. Additionally, the squared term inside the parentheses means that the graph will be symmetric around the x-coordinate of the vertex, which is 3 in this case.

Thus, as x moves away from the vertex to the left or right, the y-values decrease in a symmetric manner, resulting in a graph that reduces. This can be seen in the shape of the parabola as it curves downwards from the vertex.

Therefore, the equation y = -1/2(x-3)² + 5  reduces the graph, which means that the graph decreases as we move away from the vertex (3, 5) in both directions along the x-axis.

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according the given question the exact value of given expression is [tex]$\cos\frac{x}{2} = -\sqrt{\frac{1}{2(1 - \left(-\frac{160}{81}\right)^2)}} = -\sqrt{\frac{81^2}{2(81^2 - 160^2)}} = \boxed{-\frac{81\sqrt{239}}{319}}$[/tex]

First, we need to find [tex]$\sin x$[/tex] using the identity[tex]$\cos^2x + \sin^2x = 1$:$\sin^2x = 1 - \cos^2x = 1 - \left(-\frac{4}{5}\right)^2 = \frac{9}{25}$[/tex]

Since  [tex]$\frac{\pi}{2} < x < \pi$[/tex], we know that  [tex]$\frac{\pi}{4} < \frac{x}{2} < \frac{\pi}{2}$[/tex]. Therefore, we can use the

identity [tex]$\tan\frac{x}{2} = \frac{\sin x}{1 + \cos x}$[/tex]:

[tex]$\tan\frac{x}{2} = \frac{\sqrt{\frac{9}{25}}}{1 - \frac{4}{5}} = \frac{\frac{3}{5}}{\frac{1}{5}} = \boxed{3}$[/tex]

[tex]If $\tan x = \frac{40}{9}$ and $\pi < x < \frac{3\pi}{2}$, find $\cos\frac{x}{2}$.[/tex]

First, we need to find [tex]$\sin x$[/tex] using the identity [tex]$\tan^2x + 1 = \sec^2x$[/tex]:

[tex]$\sin x = \frac{\tan x}{\sec x} = \frac{\frac{40}{9}}{-\frac{9}{40}} = -\frac{160}{81}$[/tex]

[tex]Since $\pi < x < \frac{3\pi}{2}$, we know that $\frac{\pi}{2} < \frac{x}{2} < \frac{3\pi}{4}$[/tex]. Therefore, we can use the identity [tex]$\cos\frac{x}{2} = \pm\sqrt{\frac{1 + \cos x}{2}}$[/tex]:

[tex]$\cos\frac{x}{2} = -\sqrt{\frac{1 + \cos x}{2}} = -\sqrt{\frac{1 + \frac{\cos^2x}{\sin^2x}}{2}} = -\sqrt{\frac{\sin^2x + \cos^2x}{2\sin^2x}} = -\sqrt{\frac{1}{2(1 - \sin^2x)}}$[/tex]

Plugging in [tex]$\sin x = -\frac{160}{81}$[/tex] , we get:

[tex]$\cos\frac{x}{2} = -\sqrt{\frac{1}{2(1 - \left(-\frac{160}{81}\right)^2)}} = -\sqrt{\frac{81^2}{2(81^2 - 160^2)}} = \boxed{-\frac{81\sqrt{239}}{319}}$[/tex]

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Answer:

450

Step-by-step explanation:

Answer: 64°

Step-by-step explanation:

Had this problem and got it right

Answer:

Step-by-step explanation:

Domain is now called the "source" which means before a change or transformation. In mathematics, the term "source" is often used to refer to the set of all possible inputs or values that can be fed into a function or transformation, before any changes or transformations take place. The set of all possible outputs or resulting values from the function or transformation is called the "range" or "codomain".

Answer: brainliest ?

The correct answer is: The data is dependent, because the hours of video streaming in January and July occurred in the same households.

This is because the data collected is related to the same households and not different people. The same households were monitored during both January and July, which means that any changes in the video streaming hours during those months are likely due to factors within those households, such as changes in habits, routines, or available free time.

If the data were independent, then it would mean that the hours of video streaming in January and July were not related or influenced by any factors from the other month. For example, if the data were collected from two completely different sets of households, then it would be considered independent because there would be no connection or influence between the households in January and July. However, this is not the case in the given scenario, so the correct answer is that the data is dependent.

Step-by-step explanation:

hope its help <:

The unknown side lengths of the given right triangle ∆LJK where LJ 30° and JK 5 are LJ = 6, and JK = 4.

Triangle is a three-sided polygon with three angles. It is one of the basic shapes in geometry. A triangle has three sides and three angles, usually measured in degrees. The angles always add up to 180°. Triangles can be classified according to the lengths of their sides or the sizes of their angles. Types of triangles include right, acute, obtuse, scalene, isosceles, and equilateral. Triangles are also used to form more complex shapes in geometry, such as polygons and circles.

To find the unknown side lengths of a right triangle, we can use the Pythagorean Theorem. The Pythagorean Theorem states that the square of the hypotenuse (the longest side of a triangle) is equal to the sum of the squares of the other two sides. In this case, the hypotenuse is JK and the other two sides are LJ and JK.

We can use the Pythagorean Theorem to find the unknown side length of JK. We know that the angle LJ is 30°, so we can use the sine rule to calculate the length of side LJ. The sine rule states that the ratio of the length of a side of a triangle to the sine of its opposite angle is equal for all three sides. Therefore, we can calculate the length of LJ by dividing the sine of 30° (0.5) by the length of the opposite side (JK).

We can now use the Pythagorean Theorem to calculate the length of side JK. We know that the length of LJ is 6, and the length of JK is 5. We can plug these values into the equation a2 + b2 = c2, where a is the length of LJ (6), b is the length of JK (5), and c is the hypotenuse (JK). This yields the equation 36 + b2 = c2, which simplifies to b2 = c2 - 36. Since we know that c2 = 52, we can solve for b2 by subtracting 36 from 52, which gives us 16. The square root of 16 is 4, so the length of JK is 4.

Therefore, the unknown side lengths of the given right triangle ∆LJK where LJ 30° and JK 5 are LJ = 6, and JK = 4.

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Answer:

x = 0

Step-by-step explanation:

9x - 7 = -7

Add 7 to both sides.

9x - 7 + 7 = -7 + 7

9x = 0

Divide both sides by 9.

9x/9 = 0/9

x = 0

Answer:

x=0

Step-by-step explanation:

In the polygon, using sum of exterior angles the value of x = 37°

A polygon is a shape that has 3 or more sides.

Given the polygon which is a hexagon to find the value of x, we note that the angles are all exterior angles. We know that the sum of the exterior angles of a polygon is 360°.

So, we have the equation as

x + 2x + (x - 1) + 3x + (x + 18) + (x + 10) = 360°

Collecting like terms, we have that

x + 2x + x + 3x + x + x - 1 + 18 + 10 = 360°

9x + 27° = 360°

Subtracting 27° from both sides of the equation, we have that

9x + 27° - 27° = 360° - 27°

9x + 0 = 333°

9x = 333°

Dividing both sides by 9, we have that

x = 333°/9

x = 37°

So, the value of x = 37°

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The distance the plane traveled from point A to point B is approximately 8.15 miles or 43056 feet (rounded to the nearest tenth of a foot).

An angle is a geometric figure formed by two rays, called the sides of the angle, that share a common endpoint, called the vertex of the angle. Angles are typically measured in degrees or radians, and they are used to describe the amount of rotation or turning between two lines or planes. In a two-dimensional plane, angles are usually measured as the amount of rotation required to move one line or plane to coincide with the other line or plane.

Let's first draw a diagram to visualize the problem:

                    /  |

                  /     |

                 /       |P (plane)

                /        |

               /         |

              /          | h = 6900 ft

            /            

           / θ2.        |  

         /                |

       /                  |

   B ___/θ1__  _|___ A

           d

We need to find the distance the plane traveled from point A to point B, which we'll call d. We can use trigonometry to solve for d.

From point A, we have an angle of elevation of 16° to the plane. This means that the angle between the horizontal and the line from point A to the plane is 90° - 16° = 74°. Similarly, from point B, we have an angle of elevation of 27° to the plane, so the angle between the horizontal and the line from point B to the plane is 90° - 27° = 63°.

Let's use the tangent function to solve for d:

x = h / tan(74°) = 19906.5 ft

d - x = h / tan(63°) = 23205.2 ft

So,

d = x + h / tan(63°) ≈ 43111.7 ft ≈ 8.15 miles.

Therefore, the distance the plane travelled from point A to point B is approximately 8.15 miles or 43056 feet (rounded to the nearest tenth of a foot).

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Miles is going to spend less than the hours that were spent last week since 2/3 is a fraction.

A fraction represents a part of a whole, and is therefore always less than the whole. For example, 2/3 represents two out of three equal parts of a whole.

The implication of this is that the time that Miles would have to spend on biking in the coming week would be wo out of three equal parts of a whole time that was spent in the last week and this would be less than the time spent last week.

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Answer: LN = 15

Make a proportional relationship:

[tex]\dfrac{LN}{JL}=\dfrac{LM}{KL}[/tex]

Insert the values:

[tex]\longrightarrow\dfrac{LN}{30} =\dfrac{6}{30-18}[/tex]

cross multiply:

[tex]\longrightarrow LN=\dfrac{30(6)}{12}[/tex]

Simplify:

The calculated sum of the infinite series represented as 72 - 36 + 18 - 9 +... is 48

Given that we have the following infinite series

72 - 36 + 18 - 9 +...

In the above series, we have the following parameters

Initial value, a = 72

Common ratio, r = -36/72

When the above are evaluated, we have

Initial value, a = 72

Common ratio, r = -0.5

The sum of the infinite series is then calculated as

Sum = a/(1 - r)

When values are substituted, we have

Sum = 72/(1 + 0.5)

Evaluate

Sum = 48

Hence, the sum is 48

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Answer:

Step-by-step explanation:

12 to the second power (or 12 squared) is equal to 144.

Mathematically, it can be represented as:

12^2 = 12 x 12 = 144

The expression represents the distributive property from the list of options is (b) a(b + c) = ab + ac

The distributive property is a mathematical property that applies to multiplication and addition or subtraction.

It states that when you multiply a number (or variable) by a  sum or difference inside parentheses, you can distribute the multiplication across the terms inside the parentheses.

This is represented by the following formula:

a(b + c) = ab + ac

This is represented by Option (B)

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Answer: To solve the third-order differential equation y''' + y' = cot(x) by variation of parameters, we first need to find the solution to the associated homogeneous equation, which is:

y''' + y' = 0

The characteristic equation is r^3 + r = 0, which can be factored as r(r^2 + 1) = 0. This gives us the roots r = 0, r = i, and r = -i. Therefore, the general solution to the homogeneous equation is:

y_h = c1 + c2 cos(x) + c3 sin(x)

To find a particular solution to the non-homogeneous equation using variation of parameters, we assume that the solution has the form:

y_p = u1(x) + u2(x) cos(x) + u3(x) sin(x)

where u1, u2, and u3 are functions to be determined.

We can find the derivatives of y_p:

y'_p = u1'(x) + u2'(x) cos(x) - u2(x) sin(x) + u3'(x) sin(x) + u3(x) cos(x)

y''_p = u1''(x) + u2''(x) cos(x) - 2u2'(x) sin(x) - u2(x) cos(x) + u3''(x) sin(x) + 2u3'(x) cos(x) - u3(x) sin(x)

y'''_p = u1'''(x) + u2'''(x) cos(x) - 3u2''(x) sin(x) - 3u2'(x) cos(x) - u2(x) sin(x) + u3'''(x) sin(x) + 3u3''(x) cos(x) - 3u3'(x) sin(x)

Substituting these derivatives into the non-homogeneous equation, we get:

u1'''(x) + u2'''(x) cos(x) - 3u2''(x) sin(x) - 3u2'(x) cos(x) - u2(x) sin(x) + u3'''(x) sin(x) + 3u3''(x) cos(x) - 3u3'(x) sin(x) + u1'(x) + u2'(x) cos(x) - u2(x) sin(x) + u3'(x) sin(x) + u3(x) cos(x) = cot(x)

Grouping the terms with the same functions together, we get:

u1'''(x) + u1'(x) = 0

u2'''(x) cos(x) - 3u2''(x) sin(x) - u2(x) sin(x) + u2'(x) cos(x) + u2'(x) cos(x) = cot(x) cos(x)

u3'''(x) sin(x) + 3u3''(x) cos(x) - 3u3'(x) sin(x) + u3'(x) sin(x) + u3(x) cos(x) = cot(x) sin(x)

The first equation is a first-order differential equation, which can be solved by integrating both sides:

u1'(x) + u1(x) = c1

where c1 is a constant of integration. The solution to this equation is:

u1(x) = c1 + c2 e^(-x)

where c2 is another constant of integration.

Step-by-step explanation:

The lumpsum amount invested in 18 years ago for the given value Future value and interest is = Rs 2763,18.3268

What about lumpsum?

In mathematics, a lump sum refers to a single, fixed amount of money or quantity of something that is paid or received all at once, rather than being paid or received in installments or over a period of time.

The term "lump sum" can be used in various mathematical contexts, such as in finance, where it can refer to a single payment or investment, or in statistics, where it can refer to a single value or data point.

Define future value:

In mathematics, future value (FV) refers to the value of an investment or cash flow at a specified date in the future, assuming a certain rate of return.

The future value of an investment is the amount of money that an investor would expect to have at a specified date in the future if they were to invest a certain amount of money today, and if that investment earns a certain rate of return over time.

⇒ The formula for calculating the future value of an investment is:

[tex]FV = PV x (1 + r)^n[/tex]

According to the given information:

Interest Rate = 5%

Time Period =  18 years

Future Value = Rs 6649,93.

Using the concept of TVM calculation we have that,

Present value = [tex]\frac{Future Value}{(1+r)^{t} }[/tex]

So, the Present Value = [tex]\frac{664993}{(1+0.05)^{18} } = 2763,18.3268[/tex]

Hence, the Lumpsum Amount is Rs 2763,18.3268

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The vector equations of L₂ when expressed as Cartesian equations are

y = 0

x = (z ± √(z² - 4(z-2))) / 2

z = [(4 - ((x-1)/(-z))²) ± √((4 - ((x-1)/(-z))²)² + 64)] / 8

To find the vector equation of the line L₂, we need to find a vector that is perpendicular to L₁ and passes through the point (1,0,2). Let's start by finding the vector equation of L₁.

Let P(x,y,z) be a point on L₁. Then the vector equation of L₁ is given by:

r₁ = P + t * d₁

where d₁ is the direction vector of L₁ and t is a scalar parameter.

Since L₂ is perpendicular to L₁, its direction vector must be perpendicular to d₁. Thus, we can find a vector that is perpendicular to d₁ by taking the cross product of d₁ with any non-zero vector that is not parallel to d₁. Let's choose the vector (0,1,0):

v = d₁ x (0,1,0) = (-z,0,x)

Note that we can choose any non-zero vector that is not parallel to d₁, and we will still get a vector that is perpendicular to d₁.

Now we have a point on L₂ (1,0,2) and a direction vector (v), so we can write the vector equation of L₂:

r₂ = (1,0,2) + s * v

where s is a scalar parameter.

To express the Cartesian equations of L₂, we can write the vector equation as a set of three parametric equations:

x = 1 - sz

y = 0

z = 2 + sx

We can eliminate the parameter s by solving for it in two of the equations and substituting into the third equation:

s = (x - 1) / (-z)

s = (z - 2) / x

Setting these two expressions equal to each other and solving for x, we get:

[tex]x^2 - zx + z - 2 = 0[/tex]

This is a quadratic equation in x, so we can solve for x using the quadratic formula:

[tex]x = (z \± \sqrt{(z^2 - 4(z-2)})) / 2[/tex]

Substituting this expression for x into one of the parametric equations, we get:

y = 0

And substituting the expressions for x and s into the other parametric equation, we get:

[tex]z = 2 + [(z \± \sqrt{(z^2 - 4(z-2)})) / 2] * [(1 - sz) / (-z)][/tex]

Simplifying this equation, we get:

[tex]4z^2 - (4 - s^2)z - 4 = 0[/tex]

Again, this is a quadratic equation in z, so we can solve for z using the quadratic formula:

[tex]z = [(4 - s^2) \± \sqrt((4 - s^2)^2 + 64)] / 8[/tex]

z = [(4 - s²) ± √((4 - s²)² + 64)] / 8

Finally, we can substitute these expressions for x and z into one of the parametric equations to get:

[tex]y = 0\\x = (z \± \sqrt{(z^2 - 4(z-2)})) / 2\\z = [(4 - ((x-1)/(-z))^2) \± \sqrt{((4 - ((x-1)/(-z))^2)^2} + 64)] / 8[/tex]

These are the Cartesian equations of L₂.

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In response to the stated question, we may state that Since [tex]\theta[/tex]is in the trigonometry fourth quadrant, [tex]\theta/2[/tex] is also in the fourth quadrant.

The study of the connection between triangle side lengths and angles is known as trigonometry. The concept first originated in the Hellenistic era, during the third century BC, due to the application of geometry in astronomical investigations. The subject of mathematics known as exact techniques deals with certain trigonometric functions and their possible applications in calculations. There are six commonly used trigonometric functions in trigonometry. Sine, cosine, tangent, cotangent, secant, and cosecant are their separate names and acronyms (csc). The study of triangle characteristics, particularly those of right triangles, is known as trigonometry. As a result, geometry is the study of the properties of all geometric forms.

a) We can use the double angle formula for sine to find sin 2theta:

[tex]sin 2\theta = 2sin \theta cos \theta\\sin^2 \theta + cos^2 \theta = 1\\sin^2 \theta + (3/10)^2 = 1\\sin^2 \theta = 1 - (9/100)\\sin \theta = \sqrt(91)/10 \\sin 2\theta = 2sin \theta cos \theta\\sin 2\theta = 2(\sqrt(91)/10)(3/10)\\sin 2\theta = 3\sqrt(91)/50[/tex]

b) To find the quadrant in which [tex]\theta/2[/tex] is located, we need to find [tex]\theta/2[/tex] first:

[tex]\theta/2 = (3\pi/2 + \theta)/2\\\theta/2 = 3\pi/4 + t\heta/2\\\theta/2 - \theta/2 = 3\pi/4\\\theta/2 = 3\pi/4\\\theta = 3\pi/2[/tex]

Since theta is in the fourth quadrant, [tex]\theta/2[/tex] is also in the fourth quadrant.

c) To find cos theta/2, we can use the half angle formula for cosine:

[tex]cos(theta/2) = \sqrt((1 + cos theta)/2)\\cos(theta/2) = \sqrt((1 + 3/10)/2)\cos(theta/2) = \sqrt(13/20)\\cos(theta/2) = \sqrt(13)/2sqrt(20)\\cos(theta/2) = \sqrt(13)/10[/tex]

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Answer:i don't know the answer

Step-by-step explanation: i don't konw

The volume of the triangular pyramid is 26 2/3 yd³

The formula for calculating the volume of a triangular pyramid is expressed with the equation

A = 1/3bh

Such that the parameters in the equation are;

The base area of the pyramid is;

Area = 1/2 × 4 × 5

Multiply the values

Base area =20/2

Base area = 10 yd

Substitute the value

Volume = 1/3 × 10 × 8

Multiply the values

Volume = 80/3

Divide the values

Volume = 26 2/3 yd³

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The baby born in week 40 weighs relatively less since its z-score -0.26, is smaller than the z-score of -0.16 for the baby born in week 32.

To find the z-score, we use the formula:

z = (x - μ) / σ

where x is the individual value, μ is the mean, and σ is the standard deviation.

For the 32-week gestation period baby (weight = 2575 grams):

For the 40-week gestation period baby (weight = 3075 grams):

Now, we round the z-scores to two decimal places:

Since the z-score for the 40-week baby (-0.26) is smaller than the z-score for the 32-week baby (-0.16), the correct answer is:

C. The baby born in week 40 weighs relatively less since its z-score -0.26, is smaller than the z-score of -0.16 for the baby born in week 32.

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The best linear equation that describe given graph is y=2.5x-35 i.e. C.

What is a linear equation ?

A linear equation is a mathematical equation that, when plotted on a graph, represents a straight line. It is an equation of the following form:

y = mx + b

where y = dependent variable, x = independent variable, m= slope of the line, and b = y-intercept (the point where the line crosses the y-axis).

Now,

Lets take a point on the given graph that is on line (50,90)

then the equation of line should give the same values.

So,

For A,  y=0.4x-35

y=0.4*50-35

y=-15  Hence, It does not follow.

For B, y= y=0.4x-70

y=0.4*50-70

y=-50  Hence, It does not follow.

For C, y= y=2.5x-35

y=2.5*50-35

y=125-35

y=90

 Hence, It does follow the given point.

Therefore, The best linear equation that describe given graph is y=2.5x-35

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The three-dimensional object in the figure has a surface area of 52 square yards.

Surface area is the two-dimensional measure or area of a three-dimensional space's boundary, just as perimeter is the one-dimensional measure or length of a two-dimensional area's boundary.

The object's rectangular base has a length of 4 yards and a width of 3 yards, as seen in the figure. As a result, the base's area is:

Area of base = length x width = 4 x 3 = 12 square yards

Area of a triangular face = (1/2) x base x height = (1/2) x 4 x 5 = 10 square yards

Since the object has four triangular faces, the total area of the four triangular faces is:

Total area of triangular faces = 4 x 10 = 40 square yards

We add the base's area to the sum of the four triangle sides to determine the object's surface area:

Surface area = Area of base + Total area of triangular faces

Surface area = 12 + 40 = 52 square yards

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Answer:

Below

Step-by-step explanation:

3.15 can be read as  3 and 15 hundredths =   3   15/100  = 3  3/20

Answer:  63/20

Step-by-step explanation:

Answer:

48 cookies were in the bag.

Step-by-step explanation:

It said 12 was 25%, so you want to multiply it by 4 to get 100% and 100% of the bag was 48 cookies.

The two statements that are both true are as follows: line

AC is perpendicular to line HB and line AC is parallel to FG. That is option A.

A perpendicular line is defined as the line that forms angle 90° where it meets with another line in a plane.

A line is said to be parallel to each other when they do not intercept as they are both on the same plane.

From the given diagram, line AC is perpendicular to line HB because they form angle 90° at the point of intersection.

Also, line AC is parallel to FG, because they can never intersect till infinity.

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