find the m of arc AB, round to nearest tenth.

Answer:

Pi is a mathematical term we need under the circumstances of solving complex math problems.

Answer:

pi explains everything

Step-by-step explanation:

pi goes on forever, so u could look in pi and find your birthday and even your name (in letter/number code : a=1 z=26 etc...) its pretty cool

Step-by-step explanation:

any quadratic equation has the form

y = ax² + bx + c

so, we can see in our case

a = 1

b = 8

c = 7

the x value of the vertex is indeed camcorders by

x = -b/(2a) = -8/2 = -4

the corresponding y we get then

y = (-4)² + 8×-4 + 7 = 16 - 32 + 7 = -9

the vertex = (-4, -9).

the y- intercept is simply the point with x = 0 (and the corresponding y value).

which is c, because

y = 0² + 8×0 + 7 = 7

the y-intercept = (0, 7)

Answer:

B

Step-by-step explanation:

Hey there!

3.0 * 10^8

= 3.0 * 10 * 10 * 10 * 10 * 10 * 10 * 10 * 10

= 3.0 * 100 * 100 * 100 * 100

= 3.0 * 10,000 * 10,000

= 3.0 * 100,000,000

= 300,000,000

Therefore, your answer is:

300,000,000

Good luck on assignment & enjoy your day!

~Amphitrite1040:)

Answer:

C -- 72

Step-by-step explanation:

Formula B x W x H

B = base

W = with

H = hight

Hope this helps! Please let me know if you need more help or think my answer is incorrect. Brainliest would be MUCH appreciated. Also remember to rate answers to help other students, While leaving thanks to answers that help you. Have a great day!

Answer:

15

Step-by-step explanation:

i belive its 15 i think you should look where the dot is

Answer:

Your answer is correct. It is letter A

Step-by-step explanation:

7/9= 0.778

Hence, A

Answer:

the missing value is 7

Step-by-step explanation:

mode means the highest occuring number and from the figures above, the numbers the occured the most are 3,5and7. they appeared two times and since from the question it's said that 7 is the mode, it means that 7 should occure more than 3 and 5. so the missing value is 7.

Answer:

A and D

Step-by-step explanation:

Plato/Edmentum answer

The graphs have a line that is a line of best fit for the data points are:

scatter plot of options A and D.

A scatterplot is a type of graphical display that is used to represent the relationship between two continuous variables.

In a scatterplot, each point represents the values of the two variables, with one variable being plotted along the x-axis and the other variable being plotted along the y-axis.

The position of each point on the graph represents the values of both variables for that particular observation.

We have,

The line of best fit, also known as the regression line, is a straight line that is drawn through a scatter plot of data points to represent the trend or relationship between two variables.

In a scatter plot, the horizontal axis represents one variable, and the vertical axis represents the other variable.

The line of best fit is drawn in such a way that it minimizes the distance between the line and the data points.

We see that,

The scatter plot of option A and D graphs have a line that is a line of best fit for the data points.

Thus,

The scatter plot of option A and D graphs have a line that is a line of best fit for the data points.

Learn more about scatterplots here:

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As the side of the curved line on the right increases in the x direction (input) the curved lines gets greater t words the left side . This means the output decreases.

answer:

D. As the input increases, the output decreases for all values of x.

Option A

It's a parabola having vertex (-1,-5)

As we can see the graph .

The curve first decreases until it reaches the vertex (-1,-5) then it increases on increase in x

As parabola is opening upwards Vertex is minimum

So option A is correct

Answer:

0.05%

Step-by-step explanation:

Answer:

5x - 60

Explanation:

[tex]\dashrightarrow \sf 5(x - 12)[/tex]

using distributive method :  a(b + c) = a(b) + a(c)

[tex]\dashrightarrow \sf 5(x) +5(- 12)[/tex]

[tex]\dashrightarrow \sf 5x -60[/tex]

Answer:

7/25

Step-by-step explanation:

[tex]cos2θ = 1 - 2 {sin}^{2} θ \\ = 1 - {2(sinθ)}^{2} \\ = 1 - {2 (\frac{3}{5}) }^{2} \\ = \frac{7}{25} [/tex]

Answer:

21

Step-by-step explanation:

10-(3×2²-23) = 21

10- -11

10+11=21

(1+10²)=101

2²×5²=100

101-100=1

²¹/1 = 21

Answer:

a=21° b=70°

Step-by-step explanation:

a=21°(Vertically Opposite Angles)

b+110°=180° (linear pair)

b=180-110

b=70°

[please mark me brainliest]

Answer:

a = 21°

b = 70°

c = 89°

Step-by-step explanation:

angle of measure b and the angle of measure 110 are two supplementary angles

Then b + 110 = 180

Therefore b = 180 - 110 = 70°

angle of measure b and the angle of measure 21 are two opposite angles

Then a = 21

We Know that the sum of the interior angles of a triangle equal to 180

Then a + b + c = 180

Therefore c = 180 - a - b = 180 - 21 - 70 = 159 - 70 = 89°

Answer:

a^1/12

Step-by-step explanation:

a ^1/3 / a^1/4   =   a ^ (1/3 - 1/4) = a^ 1/12

Prime polynomials cannot be factorized in smaller degree polynomials. The prime polynomials out of the considered option are:

Those polynomials with integer coefficients that cannot be factored further, with factors of lower degree and integer coefficients are called prime polynomial.

(it is necessary that no factors exists having their coefficients are still integers and they're of lower degree)

Checking all the options for them being prime or not:

Take [tex](x+a)(x+b) = x^2 + 9[/tex]

Then, expanding it gives:

[tex]x^2 + (a+b)x + ab = x^2 + 9 \implies a+b = 0, ab = 9[/tex]

or we get: [tex]a = -b, ab = -b^2 = 9, b^2 = -9[/tex]

Square of a real number doesn't exist, so this factor doesn't exist. Thus, it is prime polynomial.

We have the identity [tex](a+b)(a-b) = a^2 - b^2[/tex]

and since 9 is square of 3, therefore, we get:

[tex]x^2 -9 = x^2 -3^2 = (x+3)(x-3)[/tex]

So it got factorized. Thus, not a prime polynomial.

Take [tex](x+a)(x+b) = x^2 + 3x + 9[/tex]

Then, expanding it gives:

[tex]x^2 + (a+b)x + ab = x^2 + 3x + 9 \implies a+b = 3, ab = 9[/tex]

That gives:

[tex]a = 3-b\\ab = b(3-b) = 3b - b^2 = 9\\b^2 -3b + 9 = 0[/tex]

Solving this quadratic equation by root formula gives:

[tex]b = \dfrac{-(-3) \pm \sqrt{(-3)^2 -4(1)(9)} }{2}\\\\b = \dfrac{-(-3) \pm \sqrt{-27} }{2}\\[/tex]

this makes 'b' a complex number and it doesn't remain a real number as its expression contains square root of a negative number.

Thus, this polynomial cannot be factorized in terms of smaller degree polynomials. Thus, its a prime polynomial.

Taking -2 common out, we get:

[tex]-2(x^2 - 4) = -2(x^2 - 2^2) = -2(x-2)(x+2)[/tex]

Thus, it got factorized, and therefore not a prime polynomial.

Thus, the prime polynomials out of the considered option are:

Learn more about prime polynomials here:

https://brainly.com/question/10717989

Answer:

A) x2 + 9

C) x2 + 3x + 9

☆
EDGE2022; Good Luck :D!!!

The probability that Juliana will take jazz on Saturday morning based on the decision tree given is 3%.

The probability that jazz is taken is:

= 1 - Probability of ballet

= 1 - 70%

= 30%

The probability that if jazz is taken, it will be taken on Wednesday is:

= Probability that jazz is taken on Wednesday night / Probability that Jazz is taken

= 27% / 30%

= 90%

The probability that Jazz is taken on Saturday morning is therefore:

= Probability that jazz is taken x (1 - Probability of Wednesday night)

= 0.3 x ( 1 - 90%)

= 3%

Find out more on probability at https://brainly.com/question/17930357?referrer=searchResults.

Answer:

X = 5

Step-by-step explanation:

From the given figure,

one length of a square(l)= x

Area of the square(A) = 25cm^2

We know,

Area of square(A)= l^2

or, 25=x^2

or, √25 = x

or, 5cm = x

Step-by-step explanation:

Given, that the area of the square = 25cm^2

area of square = (side)^2

25 = x^2

x = √25

x = 5 cm.

MN goes through

Slope:-

Slope of perpendicular line:-

Passes through k(3,-3)

Equation in point slope form

Check one by one

Yes option B is correct

Answer:

(2, 2)

Step-by-step explanation:

First find the slope of the line MN, using the two given points:

[tex]\sf let\:(x_1,y_1)=(2,3)[/tex]

[tex]\sf let\:(x_2,y_2)=(-3,2)[/tex]

[tex]\implies \sf slope\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{2-3}{-3-2}=\dfrac15[/tex]

If two lines are perpendicular to each other, the product of their slopes will be -1.

Therefore, the slope (m) of the line perpendicular to MN is:

[tex]\implies \dfrac15 \times m=-1[/tex]

[tex]\implies m=-5[/tex]

Using the point-slope form of the linear equation with point K (3, -3), we can construct the linear equation of the line perpendicular to MN:

[tex]\sf y-y_1=m(x-x_1)[/tex]

[tex]\implies \sf y-(-3)=-5(x-3)[/tex]

[tex]\implies \sf y=-5x+12[/tex]

Now we have the equation of the line perpendicular to MN, we can input the x-values of the solution options to see which once is correct:

[tex]x=0\implies \sf y=-5(0)+12=12\implies (0,12)[/tex]

[tex]x=2\implies \sf y=-5(2)+12=2\implies (2,2)[/tex]

[tex]x=4\implies \sf y=-5(4)+12=12\implies (4,-8)[/tex]

[tex]x=5\implies \sf y=-5(5)+12=-13\implies (5,-13)[/tex]

Therefore, the point that is on the line that is perpendicular to MN and passes through point K is (2, 2)

Answer:

W = 13 + 4.5l + 3s

Step-by-step explanation:

We would have to add 13 because it's the natural weight. We don't know how many apples there are, but we know much weight is in each one. We will use the letters as the unknown. Then we will use 4.5 for L, and 3 for s

Answer:

(x-0.5)^2=0

Step-by-step explanation:

x^2-x+0.25=0

(x-0.5)^2=0

Answer:

(2v+3) (v^2+7)

Step-by-step explanation:

2v^3 + 3v^2 + 14v +21

v^2 (2v+3) + 7(2v+3)

= (2v+3) (v^2+7)

I think this is the correct answer from what I remeber, sorry if I may have it wrong.

Answer:

B and E

Step-by-step explanation:

^

The area of the circle that contains the sector is 546.5 in² (rounded to the nearest tenth)

From the question, we are to determine the area of the circle.

The area of a circle can be determined by using the formula,

[tex]A = \pi r^{2}[/tex]

From the given information,

Area of the sector = 167 in²

Arc measure = 110°

Using the formula,

[tex]Area\ of\ sector = \frac{\theta}{360 ^\circ} \times \pi r^{2}[/tex]

Then,

[tex]167= \frac{110 ^\circ}{360 ^\circ} \times \pi r^{2}[/tex]

[tex]167= \frac{11}{36} \times \pi r^{2}[/tex]

[tex]\pi r^{2} =\frac{167 \times 36}{11}[/tex]

[tex]\pi r^{2} = 546.5 \ in^{2}[/tex]

Since area of the circle, A, is given by πr²

Then,

A = 546.5 in²

Hence, the area of the circle that contains the sector is 546.5 in²

Learn more on Calculating the area of a circle here: https://brainly.com/question/15673093

Here is the complete question:

Find the area of the circle that contains sector. Round to the nearest tenth, if necessary. One sector has an area of 167 square inches and an arc measure of 110°.​

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Answer:

Volume of tank = l×b×h

=3ft.×1ft.×2ft.

=6 ft³

Step-by-step explanation:

Hope it helps you. Please Mark me brilliant.

Answer:

c. two-tailed

Step-by-step explanation:

i think its this because i say so now trust :)

Answer:

14a + 6b

Step-by-step explanation:

To expand use distributive property. a*(b +c) =a*b +a *c

Simplifying an expression

2*(3a - 5b + 4*(a+2b) = 2*(3a -5b + 4*a +4*2b)

                                  = 2*(3a - 5b + 4a + 8b)

                                  = 2* (3a + 4a - 5b + 8b)

Combine like terms.  To combine like terms, add or subtract the coefficient of the variables. 3a and 4a   & (-5b) and 8b are like terms  

                                 = 2*( 7a + 3b)  

                                 = 2*7a + 2*3b

                                 = 14a + 6b

Hey there!

2(3a - 5b) + 4(a + 2b)

= 2(3a - 5b) + 4(1a + 2b)

= 2(3a) + 2(-5b) + 4(1a) + 4(2b)

= 6a - 10b + 4a + 8b

= (6a + 4a) - (10b + 8b)

= 6a + 4a - 10b + 8b

= 10a - 2b

Therefore, your answer is: 10a - 2b

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

The nuclear binding energy for thorium -234 is  2.78 × 10-10 j

We have given that,

Kilograms are represented by the mass defect for thorium

-234 = 3.09 × 10-27 kg

To determine the nuclear binding energy for thorium -234.

ΔE = Δmc^2

Where

ΔE = binding energy

Δm = mass defect

c = speed of light

mass defect = 3.09×  10^-27 kg

We know that the speed of light = 3 × 10^8 m /s

[tex]\Delta E \\= 3.09\times 10^{-27} kg (3 \times 10^8 m /s)^2 \\= 2.781 \times 10^{-10} J / Kg[/tex]

Therefore, the nuclear binding energy for thorium -234 is  

2.78 × 10-10 j

To learn more about the energy visit:

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.

Answer:

The nuclear binding energy for thorium -234 is  2.78 × 10-10 j

Step-by-step explanation: