Find the value of y and RT if S is between RT. RT = 7y + 7, RS = 11, and ST = 5y + 6.​

Answer:

Units of Length

10 millimeters (mm) = 1 centimeter (cm)

10 decimeters = 1 meter (m)

10 decimeters = 1000 millimeters

10 meters = 1 dekameter (dam)

Answer:

x+ ( 1– a ) = 0

x= – 1 + a

I hope I helped you^_^

Answer:

Solution given:

-2b(-7)=11

open bracket

-2b*-7=11

+14b=11

divide both side by 14

14b/14=11/14

b=11/14

Answer:

[tex] - 2b ( - 7) = 11 \\ - 2b \times - 7 = 11 \\ 14b = 11 \\ b = \frac{11}{14} \\ thank \: you[/tex]

if 6 litres cost £7.20

then 1/2 of it will cost 'x'(algebraic value)

we form equation

[tex] \frac{ 7.2}{6} \times \frac{1}{2}x[/tex]

which is equal to 0.6

Cost of 1/2 liter is £0.6.

It is a method where we find the value of a single unit from the value of multiple units and the value of multiple units from the value of a single unit.

According to the question

Cost of 6 liters ⇒ £7.20

Cost of 1/2 liter ⇒ X

According to the unitary method

6X = [tex]7.20\times\frac{1}{2}[/tex]

X  = [tex]\frac{7.20}{6}\times\frac{1}{2}[/tex]

X = [tex]\frac{3}{5}[/tex]

X = £0.6

Cost of 1/2 liter is £0.6

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Answer:

33

Step-by-step explanation:

608pages/16h = 33pages/h

Answer:

Here ia your answer

Hope it helps

Answer:

see explanation

Step-by-step explanation:

(a)

[tex]\frac{5}{a}[/tex] + [tex]\frac{3}{b}[/tex] + [tex]\frac{7}{c}[/tex] = 0 ( multiply through by abc to clear the fractions )

5bc + 3ac + 7ab = 0 ( subtract 5bc from both sides )

3ac + 7ab = - 5bc ( factor a out of each term on the left side )

a(3c + 7b) = - 5bc ← divide both sides by (3c + 7b)

a = - [tex]\frac{5bc}{3c+7b}[/tex]

---------------------------------

(b)

p = [tex]\frac{\sqrt{4r(q^2-s)} }{q}[/tex] ( multiply both sides by q )

pq = [tex]\sqrt{4r(q^2-s)}[/tex] ← square both sides

(pq)² = 4r(q² - s) ← distribute

p²q² = 4rq² - 4rs ← subtract 4rq² from both sides

p²q² - 4rq² = - 4rs ( multiply through by - 1 )

4rq² - p²q² = 4rs ← factor out q² from each term on the left side

q²(4r - p²) = 4rs ← divide both sides by (4r - p²)

q² = [tex]\frac{4rs}{4r-p^2}[/tex] ( take the square root of both sides )

q = ± [tex]\sqrt{\frac{4rs}{4r-p^2} }[/tex]

Answer:

BCG

Step-by-step explanation:

This is because it is what you see when you look in the front of the shape.

HOPE THIS HELPED

1. ∠A and ∠B are complementary

2. ∠A + ∠B = 90° and ∠B + ∠C = 90°

3. ∠A = 90° - ∠B

4. ∠C = 90° - ∠B

5. ∠A ≅ ∠C

Answer:

x/35=98/60

x=7/6

The value of x is 7/6

Answer:

5×(2x+3)

Step-by-step explanation:

hope this helps:)

Answer:

(14, 42)

Step-by-step explanation:

(-4, 2, 14, 34, 42) are all elements of b, and (-7. 14, 21, 42) are all elements of c. (14, 42) are the only elements that are in both sets

Answer:

the greatest common factor is 8

Answer:

B,87

STEPS

78+89+83+80+84+95+100+86+84+91

10

870

10

Answer:

9 3/4

Step-by-step explanation:

First you would want to multiply the whole number with their denominators and then add the numerator to that. 2*6+1 and 4*2+1  Then you keep the original denominator at the bottom of the fraction.

2*6+1/6  4*2+1/2 ---> 13/6 x 9/2

You would then simplify the crossing numbers 6 and 9. They both can be divided by three.

13/2 x 3/2 = 39/4

Now you would do long division where you divide 39 by 4

4 goes into 39 nine times subtracting 36 from 39.

You then end up with 1 which becomes you numerator, 4 is the new denominator and 9 is the whole number.

The answer of the given mixed numbers 2 1/6 x 4 1/2 is 9 3/4.

A mixed number is a whole number, and a proper fraction represented together. It generally represents a number between any two whole numbers.

You should first multiply the entire number by the denominators of the other numbers, and then add the numerator to that result. 2*6+1 and 4*2+1 The original denominator is then kept at the bottom of the fraction.

(2*6+1)/6 x ( 4*2+1)/2 —-> 13/6 x 9/2

Next, you would streamline the intersection of numbers 6 and 9. They are both divisible by three.

13/2 x 3/2 = 39/4

You would now perform a long division by dividing 39 by 4.
4 multiplies 39 by 9 and subtracts 36 from 39.

In the end 3 becomes the numerator, 4 becomes the new denominator, and 9 is the total.

Therefore, 2 1/6 x 4 1/2 = 9 3/4.

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Answer:

[tex]{ \underline{ \sf{true}}}[/tex]

Answer:

The perimeter of a rectangle can be calculated by adding both lengths, and both widths

Step-by-step explanation:

Answer:

6

Step-by-step explanation: We observe that if 288 is multiplied by (2 x 3), then its prime factors will exist in triples. Thus, the required smallest number by which 288 be multiplied to make it a perfect cube i: (2 x 3)=6. 1,331 is a perfect cube.

Answer:

f(x)=x–5

f (3x–2) = (3x–2) –5

f (3x–2) = 3x–7

I hope I helped you^_^

Answer:

Step-by-step explanation:

It's D.

A theorem is true by some sort of mathematical logic.

It is not a definition. Not C

It is not in the end true because of inductive reasoning (a theorem may lend itself to inductive reasoning, but it must be proved.) Not A

It certainly not assumed to be true without proof. Not B

Answer:

[tex]\displaystyle \frac{28}{15}\; \text{radians}[/tex], which is approximately [tex]107^{\circ}[/tex].

Step-by-step explanation:

In a given circle, the angle of a sector is proportional to the length of the corresponding arc:

[tex]\displaystyle \frac{\text{angle of sector $1$}}{\text{angle of sector $2$}} = \frac{\text{length of arc of sector $1$}}{\text{length of arc of sector $2$}}[/tex].

For the circle in this question, [tex]r = 15\; \rm cm[/tex], and the circumference would be:

[tex]2\, \pi \, r = 30\, \pi\; \rm cm[/tex].

The full circle itself is like a sector with an angle of [tex]2\, \pi[/tex], with the arc length equal to the circumference of the circle.

[tex]\displaystyle \frac{\text{angle of sector}}{\text{angle of full circle}} = \frac{\text{length of arc of sector}}{\text{circumference of circle}}[/tex].

[tex]\displaystyle \frac{\text{angle of sector}}{2\,\pi\; \rm rad} = \frac{28\; \rm cm}{30\, \pi\; \rm cm}[/tex].

Rearrange the equation to find the angle of the sector:

[tex]\begin{aligned} & \text{angle of sector} \\ =\; & (2\,\pi\; \rm rad) \cdot \frac{28\; \rm cm}{30\, \pi\; \rm cm} \\ =\; & \frac{28}{15}\; \rm rad\end{aligned}[/tex].

In other words, the angle of this sector would be [tex]\displaystyle \frac{28}{15}\; \rm rad[/tex]. Multiply that measure in radians by [tex]\displaystyle \frac{360^{\circ}}{2\,\pi\; \rm rad}[/tex] to find the value of the angle measured in degrees:

[tex]\begin{aligned} & \frac{28}{15}\; \rm rad \times \frac{360^{\circ}}{2\,\pi\; \rm rad} \approx 107^{\circ}\end{aligned}[/tex].

[tex]\\ \rm\Rrightarrow 2x+15=2x-15[/tex]

[tex]\\ \rm\Rrightarrow 2x-2x=-15-15[/tex]

[tex]\\ \rm\Rrightarrow 0=-30[/tex]

Hence

[tex]\\ \rm\Rrightarrow x=\infty[/tex]

Answer:

It is likely that Tom did not expand brackets fully or forgot to subtract and add from both sides.

Step-by-step explanation:

Answer:

Angle ABC = 110 degrees

Step-by-step explanation:

Set angle ABC equal to the two parts and solve for x

17x + 8 = 42 + 12x - 4

17x + 8 = 12x + 38

5x = 30

x = 6

Plug in x to angle ABC and solve

17(6) + 8 = 110

Answer:

I don't know where can you find this question's answer.

Answer:

x = 1/4

Step-by-step explanation:

-6x –(-9 – 4x) = -2(3x – 5)

-6x + 9 + 4x = -6x + 10

-2x + 9 = -6x + 10

-2x + 6x = 10 - 9

4x = 1

x = 1/4

Answer:

x = 6

Step-by-step explanation:

20 = 7x + 2 - 4x

7x + 2 - 4x  = 20    (switch the sides)

7x - 4x + 2 = 20     (group the like terms together)

3x + 2 = 20            (add similar numbers, in this case it's the both x's)

    -2     -2              (subtract 2 on both sides)

------------------

3x = 18

/3     /3                   (divide both sides by 3)

-------------------

x = 6

Answer:

set of even counting number is well-defined

Answer:

4/9 and 30/9

Step-by-step explanation:

9, 18, 27, 36

3, 6, 9, 12,

4/9 already has 9 denominator

10/3 × 3/3= 30/9

so now both numbers have common denominators.

4/9 and 30/9

Step-by-step explanation:

[tex] - \frac{2}{3} + 1 \frac{5}{6} + ( - \frac{3}{2} )[/tex]

[tex] = 1 \frac{5}{6} - \frac{2}{3} - \frac{3}{2} [/tex]

[tex] = \frac{11}{6} - (\frac{2}{3} + \frac{3}{2} )[/tex]

[tex] = \frac{11}{6} - ( \frac{4 + 9}{6} )[/tex]

[tex] = \frac{11}{6} - \frac{13}{6} [/tex]

[tex] = \frac{11 - 13}{6} [/tex]

[tex] = \frac{ - 2}{6} [/tex]

After simplifying,

[tex] = \frac{ - 1}{3} (ans)[/tex]