Find the volume of each composite figure please help

Answer:

24

Step-by-step explanation:

[tex]\sf Given\:fraction:\dfrac{48}{72}[/tex]

Factors of 48: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48

Factors of 72:  1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72

So the greatest common factor (GCF) of 48 and 72 is 24.

Therefore, to simplify the fraction, divide the numerator and denominator by 24:

[tex]\sf \implies \dfrac{48}{72}=\dfrac{48 \div 24}{72 \div 24}=\dfrac{2}{3}[/tex]

Answer:

24

Step-by-step explanation:

Factors of 48 and 72

Solving

Answer:

C

Step-by-step explanation:

H(4) simply means that where there is X, it must be substituted by the value 4

So lets see step by step:

A. h(4)=2 (incorrect)(there is no X to substitute on the right side and it is stated that H is non linear. This 2 would mean that H is a straight line)

B. (4)^3 -4= 60 (incorrect as answer needs to be 2)

C. 2^4 - 14=2 (correct, as answer is 2 and equation is non linear)

D. 1/2 (4) +3 = 5 (incorrect)

Hence your answer is C

Answer:

[tex]\huge\boxed{\sf Volume\ of\ cylinder = 270\ cm^3}[/tex]

Step-by-step explanation:

Volume of cone = 90 cm³

Volume of cylinder = ?

Always remember:

Volume of cylinder = 3 × volume of cone

Volume of cylinder = 3 × 90

Volume of cylinder = 270 cm³

[tex]\rule[225]{225}{2}[/tex]

Answer:

-3, -12

Step-by-step explanation:

Only the y coordinate should change. A translation of -6 units would be -12 meaning it is (-3, -12)

Answer:

45.359237

Step-by-step explanation:

I believe this is the answer because if u convert u get 45.35

Using exponential function concepts, it is found that the range of f(x) is given by:

{y | y > –4}

An exponential function is defined by:

[tex]y = ab^x + k[/tex]

The value of k is the asymptote of the function, hence the range is {y|y>k}.

In this problem, the function is given by:

[tex]f(x) = \left(\frac{3}{4}\right)^x - 4[/tex]

Hence k = -4 and the range is {y | y > –4}.

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Answer:

the answer is A

Step-by-step explanation:

i got it right on edge 2022

Answer:

Ethan sold 1/12 gallon more lemonade

Step-by-step explanation:

1 1/4 = 2/3 + x

x is the amount of lemonade Kayla sold

find least common denominator

1 3/12 = 8/12 + x

subtract 8/12 on both sides

15/12 - 8/12 = x

7/12 = x

7/12 = amount of lemonade Kayla sold

2/3 - 7/12 = how much more Ethan sold

8/12 - 7/12 = 1/12 gallon

Answer:

100

Step-by-step explanation:

10x10=100

Answer:

-7.8 :)

Step-by-step explanation:

first perform 44 minus 90

then add 7 to that

then divide that by 5

Answer:

[tex]39^{\circ} + b= 180^{\circ} (linear \: pair)\\b= 180 - 39\\\boxed{b = 141^{\circ}}[/tex]

Answer:

see explanation

Step-by-step explanation:

the tan , sin , cos ratios are used to find sides and angles in a right triangle.

There is no indication on the diagram that the triangle is right.

then the use of the tan ratio is an error if the triangle is not right.

Answer:

AA postulate the two triangles are similar

Answer:

Step-by-step explanation:

Use the slope formula.

[tex]\underline{\text{SLOPE:}}[/tex]

[tex]\Longrightarrow: \sf{\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{Rise}{Run} }[/tex]

[tex]\sf{y_2=9}\\\\\\\sf{y_1=5}\\\\\\\sf{x_2=3}\\\\\\\sf{x_1=1}[/tex]

[tex]\sf{\dfrac{9-5}{3-1} }[/tex]

Solve.

[tex]\sf{\dfrac{9-5}{3-1}=\dfrac{4}{2}=\boxed{\sf{2}}[/tex]

I hope this helps. Let me know if you have any questions.

Answer:

52.25 MPH

Step-by-step explanation:

Using the formula given D=RT we simply plug in values,

313.5=6R

313.5/6=R

52.25=R

Cone details:

Sphere details:

================

From the endpoints (EO, UO) of the circle to the center of the circle (O), the radius is will be always the same.

Using Pythagoras Theorem

(a)

TO² + TU² = OU²

(h-10)² + r² = 10²                                   [insert values]

r² = 10² - (h-10)²                                     [change sides]

r² = 100 - (h² -20h + 100)                       [expand]

r² = 100 - h² + 20h -100                        [simplify]

r² = 20h - h²                                          [shown]

r = √20h - h²                                       ["r" in terms of "h"]

(b)

volume of cone = 1/3 * π * r² * h

===========================

[tex]\longrightarrow \sf V = \dfrac{1}{3} * \pi * (\sqrt{20h - h^2})^2 \ ( h)[/tex]

[tex]\longrightarrow \sf V = \dfrac{1}{3} * \pi * (20h - h^2) (h)[/tex]

[tex]\longrightarrow \sf V = \dfrac{1}{3} * \pi * (20 - h) (h) ( h)[/tex]

[tex]\longrightarrow \sf V = \dfrac{1}{3} \pi h^2(20-h)[/tex]

To find maximum/minimum, we have to find first derivative.

(c)

First derivative

[tex]\Longrightarrow \sf V' =\dfrac{d}{dx} ( \dfrac{1}{3} \pi h^2(20-h) )[/tex]

apply chain rule

[tex]\sf \Longrightarrow V'=\dfrac{\pi \left(40h-3h^2\right)}{3}[/tex]

Equate the first derivative to zero, that is V'(x) = 0

[tex]\Longrightarrow \sf \dfrac{\pi \left(40h-3h^2\right)}{3}=0[/tex]

[tex]\Longrightarrow \sf 40h-3h^2=0[/tex]

[tex]\Longrightarrow \sf h(40-3h)=0[/tex]

[tex]\Longrightarrow \sf h=0, \ 40-3h=0[/tex]

[tex]\Longrightarrow \sf h=0,\:h=\dfrac{40}{3}[/tex]

maximum volume:                when h = 40/3

[tex]\sf \Longrightarrow max= \dfrac{1}{3} \pi (\dfrac{40}{3} )^2(20-\dfrac{40}{3} )[/tex]

[tex]\sf \Longrightarrow maximum= 1241.123 \ cm^3[/tex]

minimum volume:                 when h = 0

[tex]\sf \Longrightarrow min= \dfrac{1}{3} \pi (0)^2(20-0)[/tex]

[tex]\sf \Longrightarrow minimum=0 \ cm^3[/tex]

Answer:

(a)  see step-by-step

[tex]\textsf{(b)}\quad V=\dfrac{20}{3} \pi h^2-\dfrac13 \pi h^3[/tex]

[tex]\textsf{(c)}\quad h=\dfrac{40}{3}[/tex]

Step-by-step explanation:

A right triangle can be drawn with vertices at the center O, the base angle of the cone and the center of the base of the cone (see annotated image).

Side lengths of the formed right triangle:

Using Pythagoras' Theorem [tex]a^2+b^2=c^2[/tex]
(where a and b are the legs, and c is the hypotenuse, of a right triangle)

[tex]\implies r^2+(h-10)^2=10^2[/tex]

[tex]\implies r^2+h^2-20h+100=100[/tex]

[tex]\implies r^2+h^2-20h=0[/tex]

[tex]\implies r^2=20h-h^2[/tex]

[tex]\textsf{Volume of a cone}=\dfrac13 \pi r^2h[/tex]
(where r is the radius and h is the height)

Substitute the expression for [tex]r^2[/tex] found in part (a) into the equation so that volume (V) is expressed in terms of h:

[tex]\begin{aligned}V & =\dfrac13 \pi r^2h\\\\ \implies V & =\dfrac13 \pi (20h-h^2)h\\\\ & = \dfrac13 \pi (20h^2-h^3)\\\\ & = \dfrac{20}{3} \pi h^2-\dfrac13 \pi h^3 \end{aligned}[/tex]

To find the value of h such that the volume of the cone is a maximum, differentiate V with respect to h:

[tex]\begin{aligned}V & =\dfrac{20}{3} \pi h^2-\dfrac13 \pi h^3\\\\ \implies \dfrac{dV}{dh} & =2 \cdot \dfrac{20}{3} \pi h-3 \cdot \dfrac13 \pi h^2\\\\ & = \dfrac{40}{3} \pi h- \pi h^2\\\\ & = \pi h\left(\dfrac{40}{3}-h\right)\end{aligned}[/tex]

Set it to zero:

[tex]\begin{aligned}\dfrac{dV}{dh} & =0\\\\ \implies \pi h\left(\dfrac{40}{3}-h\right) & = 0\end{aligned}[/tex]

Solve for h:

[tex]\begin{aligned} \pi h & = 0 \implies h=0\\ \dfrac{40}{3}-h & =0\implies h=\dfrac{40}{3}\end{aligned}[/tex]

Substitute the found values of h into the equation for Volume:

[tex]\begin{aligned}\textsf{when}\:h=0:V &=\dfrac{20}{3} \pi (0)^2-\dfrac13 \pi (0)^3\\\\ \implies V & =0\sf \:cm^3\end{aligned}[/tex]

[tex]\begin{aligned}\textsf{when}\:h=\dfrac{40}{3}:V &=\dfrac{20}{3} \pi \left(\dfrac{40}{3}\right)^2-\dfrac13 \pi \left(\dfrac{40}{3}\right)^3\\\\ \implies V & =\dfrac{32000}{27} \pi -\dfrac{64000}{81} \pi\\\\ & = \dfrac{32000}{81} \pi \\\\ & = 1241.123024..\sf \:cm^3\end{aligned}[/tex]

Therefore, the value of h such that the volume of the cone is a maximum is:

[tex]h=\dfrac{40}{3}[/tex]

Answer:

[tex]L[/tex] ≤ [tex]29[/tex]

Step-by-step explanation:

Given

Perimeter = 57 (at most)

Required

Determine the length of each side

The term at most in the values of the perimeter shows that the expression is an inequality and it means that perimeter can't exceed that value;

Let L represents the length of each sides;

Perimeter [tex]=L+L+L[/tex]

So,

[tex]L+L+L[/tex] ≤ [tex]57[/tex]

[tex]3L[/tex] ≤ [tex]57[/tex]

Divide both sides by 3

[tex]3L[/tex] ÷ [tex]3[/tex] ≤ [tex]57[/tex] ÷ [tex]3[/tex]

[tex]L[/tex] ≤ [tex]29[/tex]

From the graph and orientation of the parametric equations: A. the graph is a circle with a radius of 4. The orientation is counterclockwise as t increases.

In geometry, the relationship between the rectangular coordinates (x, y) and polar coordinates (r, t) is given by these polar functions:

x = rcost and y = rsint.

Where:

Mathematically, the standard form of the polar equation of a circle is given by;

x² + y² = r²

Given the following data;

x = 16cost  ⇒ x² = 16cos²t

y = 16sint   ⇒ y² = 16sin²t

Evaluating, we have:

x² + y² = 16

r² = 16

r = √16

Radius, r = 4.

Also, the orientation is counterclockwise as t increases because the angle gets bigger (increases).

x = 3t    .....equation 1.

y = t²     .....equation 2.

Making t the subject of formula in eqn. 1, we have:

t = x/3    .....equation 3.

Substituting eqn. 3 into eqn. 2, we have:

y = (x/3)²

rsinθ = (rcosθ/3)²

rsinθ = r²cos²θ/9

9rsinθ = r²cos²θ

9sinθ = rcos²θ

r = 9sinθ/cos²θ

r = 9 × (sinθ/cosθ) × 1/cosθ

r = 9tanθsecθ.

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Answer:

1571 + 64x < 2187

Step-by-step explanation:

Answer:

d

Step-by-step explanation:

Answer:

The expression represent the total amount of price money is 3x-150.

The expressions let X be the amount of money for first place. This means X-50 would be the amount of second place because each subsequent place after 1st wins $50 less than the previous place. Thirds, would be X-50-50 or X-100.

That is X = first place and each place after that is 50 less so 2nd place would be  x - 50 and third place would be x - 100.

Thus the total amount of money would be all of the values combined which is

x + (x - 50) + (x - 100)

Combinimg the like terms

What is the combinimg the like terms?

To combine like terms, we have to add the coefficients and keep the variables the same. We add like terms to make one term.

x+x-50+x-100

3x-150

3x - 150

Therefore the option b is correct.

So the expression represent the total amount of price money is 3x-150.

Step-by-step explanation:

Answer:

Margo makes 2/3 shots and making 4 shots and missing 2 shots equals 6 so 4/6 reduces to 2/3.

Step-by-step explanation:

4/6 = 2/3

Answer:

B

Step-by-step explanation:

Length of one side= 3a+6b

Perimeter= sum of 4 sides= 4(3a+6b) = 12a+24b

The 42 burgers are sold by Mrs. Garcia's class at $57.12 and 37 salad is sold by Mr. Runner’s class at $61.05.

A system of equation is the set of equation in which the finite set of equation is present for which the common solution is sought.

Mrs. Garcia’s class sold burgers for $1.36 each and Mr. Runner’s class sold salads for $1.65 each. Together, the classes sold 79 items and earned $118.17 for their school.

Let x burgers are sold by Mrs. Garcia's class and s salad is sold by Mr. Runner’s class. Together, the classes sold 79 items for their school. Thus,

[tex]x + s = 79[/tex]            .....1

Mrs. Garcia’s class sold burgers for $1.36 each and Mr. Runner’s class sold salads for $1.65 each. Together, the classes earned $118.17 for their school. Thus,

[tex]1.36(x) + 1.65(s) = 118.17\\1.36x + 1.65s = 118.17[/tex]             ....2

Rewrite the first equation,

[tex]x + s = 79 \\ x = 79-s[/tex]             .....3

Put this value of x in equation 2,

[tex]1.36(79-s) + 1.65s = 118.17\\107.44-1.36s + 1.65s = 118.17\\0.29s=118.17-107.44\\s=\dfrac{10.73}{0.29}\\s=37[/tex]

Put this value in equation 3,

[tex]x=79-37\\x=42[/tex]

42 burgers are sold by Mrs. Garcia's class and 37 salad is sold by Mr. Runner’s class. Thus, Mrs. Garcia's class sold more items.

Money earned by Mrs. Garcia's class by selling 42 burger at $1.36 each is,

[tex]M_x=1.36\times42\\M_x=57.12[/tex]

Money earned by Mr. Runner’s class by selling 37 salad at $1.65 each is,

[tex]M_s=1.65\times37\\M_s=61.05[/tex]

Thus, Mr. Runner’s class earned more money.

Hence, the 42 burgers are sold by Mrs. Garcia's class at $57.12 and 37 salad is sold by Mr. Runner’s class at $61.05.

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Answer:

13$

Step-by-step explanation:

Dan purchased a set of knitting needles for $11 and 6 identical packs of yarn. The total cost was $89.

How muc[tex]rweds[/tex]h did each pack of yarn cost?

The total cost of each pack of yarn is $13.

The total cost of an item is the sum of the cost of all items that are purchased. Total cost for more items can be found by multiplying the number of items and the cost of the individual item.

For the given situation,

There are two items purchased knitting needles and packs of yarn.

Cost of knitting needle = $11

Number of packs of yarn purchased = 6

Total cost = $89

Let the cost of yarn be x.

The cost of the yarn can be find by using the equation,

Total cost = Cost of knitting needle + (number of yarn purchased × x)

⇒ [tex]89=11+6x[/tex]

⇒ [tex]6x=78[/tex]

⇒ [tex]x=13[/tex]

Hence we can conclude that the cost of each pack of yarn is $13.

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Answer:

28c-12 and  it would be 4(7e-3 and i did not copy from googe i did this on my own

Step-by-step explanation:

Answer:

[tex] \: [/tex]

Step-by-step explanation:

So, here we are to factor the polynomial :

[tex] \\ \longrightarrow \sf \qquad28c - 12\\ \\[/tex]

[tex]\longrightarrow \sf \qquad4(7c - 3)\\ \\[/tex]

Some points to know :

Heyo!

RummySokka is here to help!!

Let's do this step-by-step explanation!

: Let's solve for the y.

[tex]x=a-2by^2[/tex]

Step 1: Flip the equation.

[tex]-2by^2+a=x[/tex]

Step 2: Add a- to your both sides.

[tex]-2by^2+a+a-a=x+-a[/tex]

[tex]-2by^2=-a+x[/tex]

Step 3: Divide both sides by -2b.

[tex]\frac{-2by^2}{-2b} =\frac{a+x}{-2b}[/tex]

[tex]y^2=\frac{a-x}{2b}[/tex]

Step 4: Take square root.

[tex]y=\sqrt{\frac{a-x}{2b} }[/tex] [tex]or[/tex] [tex]y-\sqrt{\frac{a-x}{2b} }[/tex]

Answer:

[tex]y=\sqrt{\frac{a-x}{2b} }[/tex] [tex]or[/tex] [tex]y-\sqrt{\frac{a-x}{2b} }[/tex]

Hopefully, this helps you!!

RummySokka~

Permutation helps us to know the number of ways an object can be arranged in a particular manner. The number of ways the remaining player can be arranged is 1,814,400.

Permutation helps us to know the number of ways an object can be arranged in a particular manner. A permutation is denoted by 'P'.

[tex]^nP_r = \dfrac{n!}{(n-r)!}[/tex]

where,

n is the number of choices available,

r is the choices to be made.

Given that the team has 11 players while there are only 9 positions available, therefore, the number of ways the coach can choose 9 people and arrange them is,

[tex]^{11}P_9 = \dfrac{11!}{(11-9)!} = \dfrac{11!}{2!} = 19,958,400[/tex]

Now, since Amy does not want to be a pitcher, therefore, the number of ways the remaining people can be arranged in the place of the pitcher is 10.  Also, the position remaining in the team is 8, while the number of people remaining is 10. Thus, the number of ways the remaining people can be arranged are,

[tex]\text{Number of ways}= ^{10}P_8 =\dfrac{10!}{(10-8)!} = 1,814,400[/tex]

Hence, the number of ways the remaining player can be arranged is 1,814,400.

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Answer:

19,958,400,

10,

8,

1,814,400

Step-by-step explanation:

Considering the hypotheses tested, it is found that the p-value for Nicolas's test is of 0.101.

At the null hypotheses, it is tested if the mean is of 24, that is:

[tex]H_0: \mu = 24[/tex]

At the alternative hypotheses, it is tested if it is different, hence:

[tex]H_1: \mu \neq 24[/tex]

As we are testing if the mean is different of a value, we have a two-tailed test, with t = -1.79 and 12 - 1 = 11 df. Hence, using a t-distribution calculator, the p-value is of 0.101.

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Answer:

an = a(n-1) - 7

Step-by-step explanation:

the second term is smaller than the first term 7.

a20 = a19 - 7

a19 = a18 - 7

=> a20 = (a18 - 7) - 7

Then you can accumalate until a1

-> a20 = a1 - 19*7 = 86 - 19*7 = -47