Given y = a(x - h)^2 + k, p =
A. a
B. 4a
C. 1/4a

Answer:

-6

11

Step-by-step explanation:

-6n-5=31

-6n=36

n=-6

-28=-3n+5

3n=5+28

3n=33

n=11

Answer:

the equation is not completed

Answer:

-20

Step-by-step explanation:

Multiply 4x5 which is 20 but since 5 is negative then it's -20

Answer: The time is 20:15 on a military time clock.

Step-by-step explanation:

Explanation:

If we replaced y with 3 in choice A, then we get

2y-3 = 6

2(3)-3 = 6

6-3 = 6

3 = 6

which is a false statement. So choice A's solution is not y = 3. We can cross choice A off the list. The same applies with choices B and D as well.

Choice C is the answer because,

11y+4 = 37

11(3)+4 = 37

33+4 = 37

37 = 37

which is true. This confirms choice C.

Answer:

your answer is 3/15

Step-by-step explanation:

if im wrong pls let me know

Answer:

turning point: (1, 4)

Roots: (-1, 0), (3, 0)

Step-by-step explanation:

The turning point is the vertex of the parabola, which occurs at point (1, 4).   The roots are the areas where the graph crosses the x-axis, referred to as the x-intercepts. The graph crosses the x-axis at points (-1, 0) and (3, 0).

The equation of a line is written as t = ax + b where a is the slope and b is the y-intercept.

Using the slope and y intercept given the equation is:

Y = 3x + 2

Answer:

B

Step-by-step explanation:

the converse of alternate interior angles theorem states that if two lines are intersected by a transversal forming congruent alternate interior angles then the lines are parallel.

Answer:

29in

pls give brainliest tq

have a great day

Answer:

−p3q2r−p3qr2−p2q3r−p2q2r2−p2qr3+pq3r2+pq2r3

Step-by-step explanation:

(p2qr+pq2r+pqr2)((−p)(q)+qr+−pr)

(p2qr)((−p)(q))+(p2qr)(qr)+(p2qr)(−pr)+(pq2r)((−p)(q))+(pq2r)(qr)+(pq2r)(−pr)+(pqr2)((−p)(q))+(pqr2)(qr)+(pqr2)(−pr)

−p3q2r+p2q2r2−p3qr2−p2q3r+pq3r2−p2q2r2−p2q2r2+pq2r3−p2qr3

−p3q2r−p3qr2−p2q3r−p2q2r2−p2qr3+pq3r2+pq2r3

[tex]\large\underline{\sf{Solution-}}[/tex]

Given that:

[tex]\sf\longmapsto(p^2qr+pq^2r+pqr^2)(-pq+qr-pr)[/tex]

Opening the brackets,

[tex]\sf\longmapsto p^2qr(-pq+qr-pr) + pq^2r(-pq+qr-pr) + pqr^2(-pq+qr-pr)[/tex]

Opening the next brackets,

[tex]\sf\longmapsto p^2qr(-pq)+ p^2qr(qr)- p^2qr(pr) + pq^2r(-pq)+ pq^2r(qr)- pq^2r(pr) + pqr^2(-pq)+ pqr^2(qr)- pqr^2(pr)[/tex]

So,

[tex]\sf\longmapsto -p^3q^2r+ p^2q^2r^2- p^3qr^2 - p^2q^3r+ pq^3r^2- p^2q^2r^2-p^2q^2r^2+ pq^2r^3- p^2qr^3[/tex]

[tex]\sf\longmapsto -p^3q^2r- p^3qr^2 - p^2q^3r+ pq^3r^2+ pq^2r^3- p^2qr^3+ p^2q^2r^2-2p^2q^2r^2 [/tex]

[tex]\sf\longmapsto -p^3q^2r- p^3qr^2 - p^2q^3r+ pq^3r^2+ pq^2r^3- p^2qr^3- p^2q^2r^2 [/tex]

Hence, the product is,

[tex]\longmapsto\bf -p^3q^2r- p^3qr^2 - p^2q^3r- p^2qr^3+ pq^3r^2+ pq^2r^3 - p^2q^2r^2 [/tex]

Answer:

33.176

Step-by-step explanation:

Answer:

Step-by-step explanation:

x ≥ 1

Hope this helps!

close circle = ≥ or ≤

open circle = > or <

positive number = going to the right

negative number = going to the left

Answer:

A. A reflection over the x-axis

Answer:

this is A, a reflection over the x axis

Answer:

the answer is 1.6

Step-by-step explanation:

Answer:

metric po

Step-by-step explanation:

measurements and metric units of measure

Answer: POSSIBLY B

Step-by-step explanation:

Answer:

Coordinates A and B: (1, 0) and (3, 0)

Coordinates of P: (0, 3)

Coordinates of Q: (2, -1)

Step-by-step explanation:

You're pretty much given the x-intercepts from the original equation.

y = (x - 1)(x - 3). So to get the x-intercepts (points A and B), y has to equal 0. So,

0 = (x - 1)(x - 3).

and y = 0 when x equals 1 and 3. Because anything multiplied by 0 equals 0. So substituting 1 for the value of x, for example, we get:

0 = (1 - 1)(1 - 3)

0 = 0 * (-2)

So there are your x-intercepts, points A and B.

Now,

Expand the brackets of the equation.

y = (x - 1)(x - 3) becomes

y = x^2  -  4x  + 3

You get the y-intercept (point P) by substituting 0 for the value of x. Doing so gives:

y = 0^2 - 4*0 + 3

y = 0 - 0 + 3

y = 3

So, we have our y-intercept (0, 3).

Point Q, the x-coordinate of the vertex is calculated with the equation -b/2a

Taking our expanded equation: x^2 - 4x + 3

which is of the form ax^2 + bx + c

So we find the values of a, b and c and input the values into the equation

a = 1

b = -4

c = 3

So, inputting these into the vertex equation, gives:

-(-4) / 2 * 1

4 / 2

2

So we have the x-coordinate of the vertex. Now that we know that, we can just substitute it into the expanded equation to give the y-coordinate:

y = 2^2 - 4*2 + 3

y = 4 - 8 + 3

y = -1

So there's our y-coordinate, and now we have both the x and y coordinate for the vertex, point Q. (2, -1).

Answer:

11x + 5

Step-by-step explanation:

Step-by-step explanation:

Given equations :-

Substitute (2) in (1) :-

Answer:

3. Lotion

2. Suspension

1. Capsule

Answer: January, because negative numbers are positive numbers' opposite; so -11.4 < -10.4

Answer:

Step-by-step explanation:

[tex] {115}^{o} = {(4k + 5)}^{o} + {(6k + 10)}^{o} \\ [/tex]

An exterior angle of a triangle is equal to the sum of its two interior opposite angles.

[tex] {115}^{o} = {(4k + 5)}^{o} + {(6k + 10)}^{o} \\ {115}^{o} = 4k + 5 + 6k + 10 \\ {115}^{o} = 10k + 15 \\ {115}^{o} - 15 = 10k \\ {100}^{o} = 10k \\ \frac{100}{10} = k \\ {10}^{o} = k \\ [/tex]

Answer:

4u³

Step-by-step explanation:

2/3u × 4/2u² = 4/3u³

4/3u³ × 3/1 = 4u³

Answer:

Step-by-step explanation:

Answer:

x=-3, That is the x value of the vertex, and it is a vertical parabola.

Answer:

Step-by-step explanation:

The difference is the filling rate with both lines open:

The pool is 2/3 full and needs filling the remainder, 1/3.

Time required to fill:

Answer:

Orange and apple

Step-by-step explanation:

Mark brainliest, isaac farts all the time u don’t want him to fart on u next

Derivatives can be calculated from graphed functions.

The values of the derivatives are:

The given parameter is:

[tex]\mathbf{h(x) = f(g(x))}[/tex]

Start by calculating the equations of f(x) and g(x)

Graph f(x)

The slopes of f(x) are: 3/2 and -3/2

So, the equations are:

[tex]\mathbf{f(x) = \frac{3}{2}x,\ 0 \le x \le 2}[/tex]

[tex]\mathbf{f(x) = -\frac{3}{2}x,\ x \ge 2}[/tex]

Graph g(x)

The slope of g(x) is: -1/2

So, the equation is:

[tex]\mathbf{g(x) = -\frac 12x}[/tex]

For x = 1 and x = 2, we have:

So, we have:

[tex]\mathbf{h(x) = f(g(x))}[/tex]

Where:

[tex]\mathbf{f(x) = \frac{3}{2}x\ 0 \le x \le 2}[/tex] and [tex]\mathbf{g(x) = -\frac 12x}[/tex]

[tex]\mathbf{h(x) = f(g(x))}[/tex] becomes

[tex]\mathbf{h(x) = \frac{3}{2}(-\frac{1}{2}x)}[/tex]

Open brackets

[tex]\mathbf{h(x) = -\frac{3}{4}x}[/tex]

Differentiate

[tex]\mathbf{h'(x) = -\frac{3}{4}}[/tex]

So:

[tex]\mathbf{h'(1) = -\frac{3}{4}}[/tex]

[tex]\mathbf{h'(2) = -\frac{3}{4}}[/tex]

For x = 3, we have:

[tex]\mathbf{h(x) = f(g(x))}[/tex]

Where:

[tex]\mathbf{f(x) = -\frac{3}{2}x\ x \ge 2}[/tex] and [tex]\mathbf{g(x) = -\frac 12x}[/tex]

[tex]\mathbf{h(x) = f(g(x))}[/tex] becomes

[tex]\mathbf{h(x) = -\frac{3}{2}(-\frac{1}{2}x)}[/tex]

[tex]\mathbf{h(x) = \frac{3}{4}x}[/tex]

Differentiate

[tex]\mathbf{h'(x) = \frac{3}{4}}[/tex]

Substitute 3 for x

[tex]\mathbf{h'(3) = \frac{3}{4}}[/tex]

Hence, the values of the derivatives are:

[tex]\mathbf{h'(1) = -\frac{3}{4}}[/tex], [tex]\mathbf{h'(2) = -\frac{3}{4}}[/tex] and [tex]\mathbf{h'(3) = \frac{3}{4}}[/tex]

Read more about graphed functions at:

https://brainly.com/question/11804653