Help I don’t understand

Answer: The answer is 120

Step-by-step explanation:

5x4x3=60   6x4x5+120 divided by 2= 60

                               60+60= 120

Answer:

300

Step-by-step explanation:

Let y = unknown number

30% of y = 90

⇒ 0.3 × y = 90

⇒ y = 90 ÷ 0.3

⇒ y = 300

Answer:

13

Step-by-step explanation:

The coefficient is the number placed before the given variable.

In this case:

Coefficient: 13

Variable: y

Power: 3

The coefficient is a number in front of the variable( x or y)

The coefficient would be 13

Answer:

-56

Step-by-step explanation:

First lets solve the bottom of the fraction :

1/7 * -1/8 is equal to -1/56 because to multiply two fractions we multiply there numerators and denominators

Now we have to divide 1 by -1/56 which is equal to :

1 *-56= -56 becasue when dividing by a fraction you want to switch its numerator and denominator

At the end you get -56

Answer:

A fully functioning forest has a great capacity to regenerate. But exhaustive hunting of tropical rainforest wildlifecan reduce those species necessary to forest continuance and regeneration. For example, in Central Africa, theloss of species like gorillas, chimps, and elephants undercuts the seed dispersal and slows the recovery.

Step-by-step explanation:

Answer:

3

Step-by-step explanation:

Use the formula:

The slope equation using the equation of line is given as, y = mx + b, here, m is the slope and b is the y-intercept.

choose any 2 rows and plot them into the formula.

(-2)-1/(-2)-(-1) = 3

Answer: 3 or C

Step-by-step explanation:

Answer:

74

Step-by-step explanation:

By average definition:

(74 + 67 +73 +x) / 4 = 72

Multiply by 4

(74 + 67 +73 +x)  = 288

shift the first three terms on the right side

x = 288 -74 -67 -73 =  74

The given equation represents a hyperbola. Its main features are:

A hyperbola can be defined by its center, vertices,  foci and asymptotes. And it is represented algebraically  by the standard equation:  [tex]\frac{\left(y-k\right)^2}{a^2}-\frac{\left(x-h\right)^2}{b^2}=1[/tex], where:

h= x-coordinate of center

k= y-coordinate of center

a and b= semi-axis

First, you need to rewrite the given equation 9y²-x²+2x+54y+62=0 in the standard equation hyperbola:

[tex](-x^2+2x+?)+9(y^2+6y+?)=-62\\(-x^2+2x+?)+9(y^2+6y+9)=-62\\(-x^2+2x-1)+9(y^2+6y+9)=-62\\(-x^2+2x-1)+9(y^2+6y+9)=-62-1+81\\((-x^2+2x-1)+9(y^2+6y+9)=18 ) \div 18\\ \frac{(-x^2+2x-1)}{18} +\frac{9(y^2+6y+9}{18}= \frac{18}{18} \\\frac{-(x-1)^2}{18} +\frac{(y+3^2)}{2}=1\\\frac{-(x-1)^2}{(3\sqrt{2})^2} +\frac{(y+3^2)}{(\sqrt{2})^2 }=1\\\frac{\left(y+3)^2}{\left(\sqrt{2}\right)^2}-\frac{\left(x-1\right)^2}{\left(3\sqrt{2}\right)^2}=1[/tex]

Comparing the previous equation with the standard form ([tex]\frac{\left(y-k\right)^2}{a^2}-\frac{\left(x-h\right)^2}{b^2}=1[/tex]), you have:

h=1,  k=-3,  a=[tex]\sqrt{2}[/tex] and b=[tex]3\sqrt{2}[/tex] . From now, it is possible to find that the question asks:

The coordinates for center is (h,k). Thus, the center is (1,-3).

The vertices (V1 and V2) of hyperbola can be found from the coordinates of center (h,k) and the semi-axis (a).

V1= (h,k+a)= (1,-3+[tex]\sqrt{2}[/tex])

V2= (h,k-a)= (1,-3-[tex]\sqrt{2}[/tex])

The foci or the focus points can be found from the coordinates of center (h,k) and the c ([tex]\sqrt{a^2+b^2}[/tex]) which represents the distance from the center to the focus.

[tex]c=\sqrt{a^2+b^2}\\ c=\sqrt{(3\sqrt{2} )^2+(\sqrt{2} )^2}\\c=\sqrt{18+2} \\c=\sqrt{20}=2\sqrt{5}[/tex]

Thus,

F1= (h,k+c)= (1 , -3+ [tex]2\sqrt{5}[/tex] )

F2= (h,k-c)= (1 , -3 - [tex]2\sqrt{5}[/tex] )

The asymptotes are the lines the hyperbola tends to at ±∞. For hyperbola, the asymptotes are defined as: [tex]y=\pm \frac{a}{b}\left(x-h\right)+k[/tex]. Then, for this question:

[tex]y=\pm \frac{\sqrt{2}}{3\sqrt{2}}\left(x-1\right)-3\\y=\pm \frac{1}{3}\left(x-1\right)-3[/tex]

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Answer:

177 600 000 is the answer

Answer:

7,24,20

Step-by-step explanation:

The perimeter is simply the lengths of the sides, added up
n+4n-4+4n-8=9n-12=51 cm
9n=51+12
9n=63
n=7

plug in 7 for n to get:
7,4*7-4,4*7-8
or
7,24,20

Answer:

I think that it is the one on the bottom left

Step-by-step explanation:

I am so sorry if it is wrong he he

6 x 13^2=1,014

A=1,014 in

The surface area of the cube is 1,014 square in

Answer: B. hours

Step-by-step explanation:

    Let us closely look at the varible t it gives, the one we are looking at units for. "t stands for the amount of time the workers have left to clean the windows"

         "t stands for the amount of time ..."

    The only unit they give that represents time is hours, meaning the answer to your question is:

     B. hours

Answer:

B

Step-by-step explanation:

because the angles 1 and 7 are alternate and equal , we can conclude that p and q are parralel

Answer:

A. (2, 0)

Step-by-step explanation:

The function crosses the x-axis at point (2,0). Therefore, that is the x-intercept.

hope this helps :)

Answer:

[-5, 4) ∪ (4, ∞)

Step-by-step explanation:

Given functions:

[tex]f(x)=\dfrac{1}{x-3}[/tex]

[tex]g(x)=\sqrt{x+5}[/tex]

Composite function:

[tex]\begin{aligned}(f\:o\:g)(x)&=f[g(x)]\\ & =\dfrac{1}{\sqrt{x+5}-3} \end{aligned}[/tex]

Domain: input values (x-values)

For [tex](f\:o\:g)(x)[/tex] to be defined:

[tex]x+5\geq 0 \implies x\geq -5[/tex]

[tex]\sqrt{x+5}\neq 3 \implies x\neq 4[/tex]

Therefore, [tex]-5\leq x < 4[/tex]  and  [tex]x > 4[/tex]

⇒  [-5, 4) ∪ (4, ∞)

a. The least amount as indicated in the box plot is: 10

b. Median amount of snowfall is: 20

c. Data is concentrated at the third quartile

The median of a data in a box plot is the value indicated by the vertical line that divides the box.

a. The least amount is the minimum value which is at the extreme end of the whisker to your left = 10

b. Median amount of snowfall is the value indicated by the vertical line = 20

c. The largest section is the third quarter, so the data is most concentrated within the third quarter.

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Answer:

14

Step-by-step explanation:

g(f(1)) simply means we first get f(1), and that result becomes the input value for g(x). and that is then the end result.

so,

f(1) = 4

and then

g(f(1)) = g(4) = 14

Answer:

x^2 +3x -4 = 0  --> (x +4)(x -1) = 0

Step-by-step explanation:

Let's find A and B such that

A*B = - 4    and  A+B = 3

Numbers are:

A = +4  and  B = -1

The factoring equation is y = (x + A)(x + B)

In this specific case: y = (x +4)(x -1)

Solutions to the quadratic equation require

y = (x +4)(x -1) = 0

and hence

x +4 = 0  --> x = -4

x - 1 = 0 -->  x= +1

The amount of money does Liam need to put in the simple interest account to earn  $750 in interest, is $6250.

Simple interest is the amount charged on the principal amount with a fixed rate of interest for a time period. Simple interest calculated only on the principal amount.

The formula for the simple interest can be given as,

[tex]I=\dfrac{Prt}{100}[/tex]

Here, (I) is the interest amount earned on the principal amount of (P) with the rate of (r) in the time period of (t).

Liam wants to put some money in a simple interest account. He pays R=6% interest annually for t=2 years. Liam would like to earn I=$750 in interest.

Put the values in the formula,

[tex]750=\dfrac{P\times6\times2}{100}\\P=\dfrac{750\times100}{6\times2}\\P=6250[/tex]

Thus, the amount of money does Liam need to put in the simple interest account to earn  $750 in interest, is $6250.

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The amount of money does Liam need to put in the simple interest account to earn  $750 in interest, is $6250.

What is simple interest?

Simple interest is the amount charged on the principal amount with a fixed rate of interest for a time period. Simple interest calculated only on the principal amount.

The formula for the simple interest can be given as,

Answer: $6,250

Step By Step: Here, (I) is the interest amount earned on the principal amount of (P) with the rate of (r) in the time period of (t).

Liam wants to put some money in a simple interest account. He pays R=6% interest annually for t=2 years. Liam would like to earn I=$750 in interest.

Put the values in the formula,

Thus, the amount of money does Liam need to put in the simple interest account to earn  $750 in interest, is $6250.

Answer:

12 miles per hour.

Step-by-step explanation:

1. If you pick 5 hours, then you will noticed that the graph shows you 60 miles.

2. Find the unit rate.

5 hours = 60  miles

1 hour = x miles

x= 60 ÷ 5

x= 12 miles per hour

Answer:

[tex]408cmx^{2}[/tex]

Step-by-step explanation:

A=2(wl+hl+hw)=2·(2·6+24·6+24·2)= 408cm²

length= 6

width= 2

height= 24

the area if the box.

[tex]a = lwh[/tex]

[tex]a = 2(wl + hl + hw)[/tex]

[tex]a = 2 \times (2.6 + 24.6 \times + 24.2)[/tex]

[tex]a = 408 {cm}^{2} [/tex]

therefore, the area of the box is 408 square centimeters.

Answer:

√41

Step-by-step explanation:

Pythagorean Theorem:

a^2+b^2=c^2

4^2+5^2=c^2

16+25=c^2

41=c^2

√41=c

Answer:

7.8 rounding up to 8

Step-by-step explanation:

Answer:

No.

Step-by-step explanation:

The maximum that can be earned is $720, which results from walking 60 dogs at $12 per walk.

Answer:

discount: 30% sale price: $98

Step-by-step explanation:

Simply multiply 140 by 70%(0.7) to get 98

Replace [tex]x\mapsto \tan^{-1}(x)[/tex] :

[tex]\displaystyle \int_0^{\frac\pi2} \sqrt[3]{\tan(x)} \ln(\tan(x)) \, dx = \int_0^\infty \frac{\sqrt[3]{x} \ln(x)}{1+x^2} \, dx[/tex]

Split the integral at x = 1, and consider the latter one over [1, ∞) in which we replace [tex]x\mapsto\frac1x[/tex] :

[tex]\displaystyle \int_1^\infty \frac{\sqrt[3]{x} \ln(x)}{1+x^2} \, dx = \int_0^1 \frac{\ln\left(\frac1x\right)}{\sqrt[3]{x} \left(1+\frac1{x^2}\right)} \frac{dx}{x^2} = - \int_0^1 \frac{\ln(x)}{\sqrt[3]{x} (1+x^2)} \, dx[/tex]

Then the original integral is equivalent to

[tex]\displaystyle \int_0^1 \frac{\ln(x)}{1+x^2} \left(\sqrt[3]{x} - \frac1{\sqrt[3]{x}}\right) \, dx[/tex]

Recall that for |x| < 1,

[tex]\displaystyle \sum_{n=0}^\infty x^n = \frac1{1-x}[/tex]

so that we can expand the integrand, then interchange the sum and integral to get

[tex]\displaystyle \sum_{n=0}^\infty (-1)^n \int_0^1 \left(x^{2n+\frac13} - x^{2n-\frac13}\right) \ln(x) \, dx[/tex]

Integrate by parts, with

[tex]u = \ln(x) \implies du = \dfrac{dx}x[/tex]

[tex]du = \left(x^{2n+\frac13} - x^{2n-\frac13}\right) \, dx \implies u = \dfrac{x^{2n+\frac43}}{2n+\frac43} - \dfrac{x^{2n+\frac23}}{2n+\frac23}[/tex]

[tex]\implies \displaystyle \sum_{n=0}^\infty (-1)^{n+1} \int_0^1 \left(\dfrac{x^{2n+\frac43}}{2n+\frac43} - \dfrac{x^{2n+\frac13}}{2n-\frac13}\right) \, dx \\\\ = \sum_{n=0}^\infty (-1)^{n+1} \left(\frac1{\left(2n+\frac43\right)^2} - \frac1{\left(2n+\frac23\right)^2}\right) \\\\ = \frac94 \sum_{n=0}^\infty (-1)^{n+1} \left(\frac1{(3n+2)^2} - \frac1{(3n+1)^2}\right)[/tex]

Recall the Fourier series we used in an earlier question [27217075]; if [tex]f(x)=\left(x-\frac12\right)^2[/tex] where 0 ≤ x ≤ 1 is a periodic function, then

[tex]\displaystyle f(x) = \frac1{12} + \frac1{\pi^2} \sum_{n=1}^\infty \frac{\cos(2\pi n x)}{n^2}[/tex]

[tex]\implies \displaystyle f(x) = \frac1{12} + \frac1{\pi^2} \left(\sum_{n=0}^\infty \frac{\cos(2\pi(3n+1)x)}{(3n+1)^2} + \sum_{n=0}^\infty \frac{\cos(2\pi(3n+2)x)}{(3n+2)^2} + \sum_{n=1}^\infty \frac{\cos(2\pi(3n)x)}{(3n)^2}\right)[/tex]

[tex]\implies \displaystyle f(x) = \frac1{12} + \frac1{\pi^2} \left(\sum_{n=0}^\infty \frac{\cos(6\pi n x + 2\pi x)}{(3n+1)^2} + \sum_{n=0}^\infty \frac{\cos(6\pi n x + 4\pi x)}{(3n+2)^2} + \sum_{n=1}^\infty \frac{\cos(6\pi n x)}{(3n)^2}\right)[/tex]

Evaluate f and its Fourier expansion at x = 1/2 :

[tex]\displaystyle 0 = \frac1{12} + \frac1{\pi^2} \left(\sum_{n=0}^\infty \frac{(-1)^{n+1}}{(3n+1)^2} + \sum_{n=0}^\infty \frac{(-1)^n}{(3n+2)^2} + \sum_{n=1}^\infty \frac{(-1)^n}{(3n)^2}\right)[/tex]

[tex]\implies \displaystyle -\frac{\pi^2}{12} - \frac19 \underbrace{\sum_{n=1}^\infty \frac{(-1)^n}{n^2}}_{-\frac{\pi^2}{12}} = - \sum_{n=0}^\infty (-1)^{n+1} \left(\frac1{(3n+2)^2} - \frac1{(3n+1)^2}\right)[/tex]

[tex]\implies \displaystyle \sum_{n=0}^\infty (-1)^{n+1} \left(\frac1{(3n+2)^2} - \frac1{(3n+1)^2}\right) = \frac{2\pi^2}{27}[/tex]

So, we conclude that

[tex]\displaystyle \int_0^{\frac\pi2} \sqrt[3]{\tan(x)} \ln(\tan(x)) \, dx = \frac94 \times \frac{2\pi^2}{27} = \boxed{\frac{\pi^2}6}[/tex]