Help me again pleaseeeeeeeeee

Answer:

-2[tex]t^{3}[/tex] + 5t - 1

Step-by-step explanation:

(7[tex]t^{3}[/tex] + 3t - 1) + (-9[tex]t^{3}[/tex] + 2t)

7[tex]t^{3}[/tex] - 9[tex]t^{3}[/tex] + 3t + 2t - 1  Combine like terms

-2[tex]t^{3}[/tex] + 5t - 1

Like terms have to have the same variable and the same exponents to be like terms.

Answer:

8/5

Step-by-step explanation:

Slope of the line = (-1-4)/(2-0)= -5/2

Equation of the line :

=> y - y1 = m(x - x1)

=> y - 0 = (-5/2)(x - 4)

=> 2(y - 0) = - 5x + 20

=> 2y + 5x = 20

To make the RHS 16, divide both sides by 20 and multiply by 16:

=> (2y/20)*16 + (5x/20)*16 = (20/20)*16

=> 8y/5 + 4x = 16

compare the equation with ax + by = 16 for y, b = 8/5

Answer: B

Step-by-step explanation:

Answer:

A. 2 20x-8

B. 3 20y

====================================================

Explanation:

The change in value is 30-25 = 5, so the amount has dropped by 5

Divide this change over the original amount to get 5/30 = 0.1667 approximately. This converts to 16.67% roughly, and that rounds to 17%

----------------

Here's a way to do it using a formula

A = old value = 30

B = new value = 25

C = percent change

C = [ (B-A)/A ] * 100%

C = [ (25-30)/30 ] * 100%

C = -0.1667 * 100%

C = -16.67%

C = -17%

The negative percent change means we have a percent decrease. The class size went down by about 17%.

The value of the quantity after 96 months, to the nearest hundredth is 1146.66

The standard expression for an exponential equation is expressed as:

P(t) = P0e^rt

Given the following parameters

Po = 800

rate r = 4.5% = 0.045

time t = 8 years

Substitute

P(8) = 800e^0.045(8)
P(8) = 1146.66

Hence the value of the quantity after 96 months, to the nearest hundredth is 1146.66

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Answer:

[tex]tan\frac{56}{15}[/tex]

Step-by-step explanation:

We are given the trigonometrical equation of tan( 4/3 + 12/5) and are asked to find the answer.

To solve this, keep in mind that even though this has tan, the process of adding fractions is no different from the original format.

First, find the LCM of 3 and 5, this would be 15. Multiply the numbers to get to 15 (3 and 5) by both denominators and numerators.

[tex]\frac{4*5}{3*5} + \frac{12*3}{5*3}[/tex]

[tex]\frac{20}{15}+\frac{36}{15}[/tex]

[tex]\frac{56}{15}[/tex]

Our answer would be [tex]tan\frac{56}{15}[/tex]

Answer:

tan(56/15)

Step-by-step explanation:

tan( 4/3 + 12/5 ) =

tan( 20/15 + 36/15) =

tan( 56/15 )

Answer:

For a square of side length L, the perimeter is:

P = 4*L

Then if the perimeter of our square is 36 units, we have:

36 units = 4*L

(36 units)/4 = L = 9 units.

Now we know that one vertex of the square is located at (3, 5)

Then another vertex of the square can be at:

A distance of 9 units of this point (such that these vertices are connected by one side of the square)

Some examples can be:

(3 + 9, 5) = (12, 5)

or

(3, 5 + 9) = (3, 14)

These are the simpler options, there are a lot of other possible points that can be another vertes (we can have a circle of radius 9 units centered in the point (3, 5), all these points can be another vertex of the square).

We also can have a vertex that is connected by the diagonal, this point can be:

(3 + 9, 5 + 9) = (12, 14)

or

(3 - 9, 5 - 9) = (-6, -4)

Again, there are a lot of other possible points that can be this vertex (A circle of radius √2*9 units centered in the point (3, 5)).

Answer:

7x-5=72( vertically opposite angle are equal)

7x=72-5

x=67/7

x=9.57

hope it helps.

a. The table for the relation is given by the image shown at the end of the answer.

b. The domain and range of the relation are given as follows:

c. The relation is a function, as it value of the input is mapped to a single value of the output.

The ratio between the total cost and the number of vehicles is obtained as follows:

k = 3.75/5 = 3/4 = ... = 0.75/1 = 0.75.

Meaning that the situation is modeled by a proportional relationship with a constant of 0.75, and the function is given as follows:

y = 0.75x.

For which:

The domain and range are given as follows:

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Answer:

24,241 people

Step-by-step explanation:

To determine the attendance at the festival in the fifth year, we need to calculate the cumulative increase in attendance over five years.

1st year: 20,000

2nd year: 20,000 * 1.05 = 21,000 (5% increase from the first year)

3rd year: 21,000 * 1.05 = 22,050 (5% increase from the second year)

4th year: 22,050 * 1.05 = 23,127.50 (5% increase from the third year)

5th year: 23,127.50 * 1.05 = 24,241.38 (5% increase from the fourth year)

So, in the fifth year the festival will be attended by approximately 24,241 people.

Explanation:

The zeros in 0.00798516 are not considered significant because they are not between nonzero values.

If we had something like 1.207, then that zero would be considered significant.

The first three significant values we come across in 0.00798516 are 7, 9 and 8 in that order. The next digit 5 meets the criteria of "5 or larger", which means the 798 bumps up to 799. Erase everything to the right of that.

Therefore, 0.00798516 rounds to 0.00799 when rounding to 3 significant figures.

Answer: 0.00799

0.00798516 rounded off to three significant figures is 0.00799

hope that helps...

Note that solving an equation involves finding the value(s) of the variable(s) that make the equation true. For example, solving the equation 2x + 3 = 7 would give the solution x = 2.

On the other hand, solving an inequality involves finding the set of all values of the variable(s) that make the inequality true. For example, solving the inequality 2x + 3 > 7 would give the solution x > 1.

An inequality in mathematics is a relationship that makes a non-equal comparison between two integers or other mathematical expressions. It is most commonly used to compare the sizes of two numbers on a number line.

In its most basic form, an equation is a mathematical statement that indicates that two mathematical expressions are equal. 3x + 5 = 14, for example, is an equation in which 3x + 5 and 14 are two expressions separated by a 'equal' sign.

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Given:

The equation is:

[tex]\ln(3x^2-1)=\ln(191)[/tex]

To find:

The solution for the given equation.

Solution:

We have,

[tex]\ln(3x^2-1)=\ln(191)[/tex]

On comparing both sides, we get

[tex]3x^2-1=191[/tex]

[tex]3x^2=191+1[/tex]

[tex]3x^2=192[/tex]

Divide both sides by 3.

[tex]x^2=\dfrac{192}{3}[/tex]

[tex]x^2=64[/tex]

Taking square root on both sides, we get

[tex]x=\pm \sqrt{64}[/tex]

[tex]x=\pm 8[/tex]

Therefore, the solutions of the given equation are -8 and 8.

Answer:

3y ≥ 63

Step-by-step explanation:

Ill tell you how I did it hold on

Answer:

3y ≤ 63

Step-by-step explanation:

3y ≤ 63

y ≤ 21

this means that last year ('y') he caught, at most, 21 fish - this is 1/3 less than this year

Answer:

I DONT KNOW DO YOU?

[tex]8-2z+3(x+y)[/tex] when x is 4, y is 9, and z is 3

Substitute:

[tex]8-2(3)+3(4+9)[/tex]

[tex]8-6+39[/tex]

Solve:

[tex]8-6+39\\=\fbox{23}[/tex]

[tex]\huge\text{Hey there!}[/tex]

[tex]\mathsf{8 - 2z + 3(x + y)}[/tex]

[tex]\mathsf{= 8 - 2(3) + 3(4 + 9)}[/tex]

[tex]\mathsf{= 8 - 6 + 3(4) + 3(9)}[/tex]

[tex]\mathsf{= 8 - 6 + 12 + 27}[/tex]

[tex]\mathsf{= 2 + 12 + 27}[/tex]

[tex]\mathsf{= 14 + 27}[/tex]

[tex]\mathsf{= 41}[/tex]

[tex]\huge\text{Therefore, your answer should be:}[/tex]

[tex]\huge\boxed{\mathsf{41}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

Therefore , As a result 5, 10, and 15 make up the reasonable domain for the function 2 (l + w) = 64..

A connection between a group of sources and one output for each input is referred to as a function. A function is, to put it simply, a collection of equation  connected to a single, unique output. In mathematics, a function is a statement, rule, or law that describes the connection between two variables (the dependent variable). One input leads to one output when a rule of this type is used. by Alex Federspiel, the photographer. This statement gives an example of y=x2. There is just one output for y from any input for x. According to our definition, y is a function of x since x is the input value.

Here,

We have the following for the rectangle's perimeter:

2 ( l + w ) = 64

Here,

W = width, and L = length.

We must determine the length and breadth values necessary to make the rectangle's perimeter 64.

Now,

2 ( l + w ) = 64

l + w = 32

Thus, the sum of the length and breadth measurements must equal 32.

The possible widths are 5, 10, 15, 20, and 25.

Now,

l + 5 = 32

l = 27

l + 10 = 32

l = 22

l + 15 = 32

l = 17

l + 20 = 32

l = 12

l + 25 = 32

l = 7

We think about

The domain has widths of 5, 10, 15, 20, and 25.

The range for length is: 27, 22, 17, 12, and 7.

Values for width and length are used as the x- and y-axes, respectively.

Below is a graph of the data.

The following is the reasonable domain for the aforementioned situation:

5, 10, 15, 20, and 25

Below is a graph of the function 2 (l + w) = 64.

Therefore , As a result, 5, 10, and 15 make up the reasonable domain for the function 2 (l + w) = 64.

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Answer: C

Step-by-step explanation: It is C because X is greater than (>) 111, and 119 is greater than 111. Good luck on the test!  

1a) An equation that gives the width `y` of the book, if it has `x`-hundred pages printed on bond paper is; y = ¹/₂ + ¹/₄x

1b) Ledger paper has a thickness of 2/5 in. per `100` pages, the equation is; y = ¹/₂ + ²/₅x

2) The equation will be; y = ²/₃ +¹/₄x

1) We are told that the front cover and the back cover have a thickness of 1/4 inches and they also have a thickness of 1/4 inch. Thus;

The addition of both gives to the book thickness of;

1/4 + 1/4 = 1/2 inch, despite how many pages the book  has.

We are told that for every hundred pages, a thickness of 1/4 inch is added to the book, then the equation is:

y = ¹/₂ + ¹/₄x

where;

y is the width of the book in inches.

x is every hundred pages printed on bond paper.

1b) If ledger paper has a thickness of 2/5 in. per 100 pages, then the equation is now;

y = ¹/₂ + ²/₅x

2) If both front and back covers now, have a thickness of 1/3 inches instead of 1/4 inches each, then the equation will be;

y = 2(1/3) +¹/₄x

y = ²/₃ +¹/₄x

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The answer to the above question is B. Multiply the first equation by -2 and add the second equation.

A mathematical statement that establishes the equality of two mathematical expressions is the definition of an equation in algebra. Consider the equation 3x + 5 = 14, in which the terms 3x + 5 and 14 are separated by the word "equal."

Given,

[tex]2x - 2y = 24\\4x + 7y=-40\-4x +4y = -96\\4x+7y = -40\\11y = -136\\y = -136/11[/tex]

The answer to the above question is B. Multiply the first equation by -2 and add the second equation.

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Answer: A line segment is a part of a line having two endpoints.

Im not sure if you meant to put a picture there. So, a line segment is a piece or part of a line having two endpoints. Unlike a line, a line segment has a definite length.

Answer:

Step-by-step explanation:

First of all I'm going to presume it means an eight-grader chosen at random from the instrument players, if this is incorrect the question should have specified the total amount of students.

You have to add the amount of students of each of instrument to get the total:

5+9+10+9=33

then it says to not include the drum playing students so it goes from

[tex]\frac{33}{33}[/tex] to [tex]\frac{33-10}{33}[/tex] so its [tex]\frac{23}{33}[/tex] which we must now turn to a percentage.

so you divide the 23 by the 33:

23/33=0.6969....

then you multiply by 100 as it's a percentage:

0.6969...×100=69.6969...

and finally we round it do the nearest integer/whole number:

70 (we look at the tenths digit and it's a 6 so it's rounded up)

The equation to represent the height of a glass slab is y=11x+2.

The general equation of a straight line is y=mx+c, where m is the gradient, and y = c is the value where the line cuts the y-axis. This number c is called the intercept on the y-axis.

From the given table, we have (2, 24) and (4, 46).

Substitute (x₁, y₁)=(2, 24) and (x₂, y₂)=(4, 46) in m=(y₂-y₁)/(x₂-x₁)

= (46-24)/(4-2)

= 22/2

= 11

Substitute m=11 and (x, y)=(2, 24) in y=mx+c, we get

24=11(2)+c

c=2

Substitute m=11 and c=2 in y=mx+c, we get

y=11x+2

Therefore, the equation to represent the height of a glass slab is y=11x+2.

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Answer:

4/7

Step-by-step explanation:

8/14=4/7

Calculating the ratio between each pair of values in a table allows you to determine whether a proportional relationship is present. The table depicts a proportional relationship if all of those ratios are the same.

y = k x, where is the proportionality constant, is the equation that depicts a proportional relationship, or a line. Find k and create the equation by using k = y x from a table or graph. Tables, graphs, and equations can all be used to depict proportional relationships.

The equation y = kx represents a proportional relationship between two quantities y and x that have the same proportionality constant, k.

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The slope of the line through each pair of points (16,1), (17,7) is 6.

A line's slope serves as a gauge for its steepness. Between any two locations on the line, it is the ratio of the vertical change to the horizontal change.

The slope of a line can be positive, negative, zero, or undefined.

In algebraic equations, the letter "m" frequently stands in for slope. In slope-intercept form, a line's equation is written as y = mx + b, where m denotes the line's slope and b its y-intercept.

To find the slope of the line that passes through two points (x1, y1) and (x2, y2), you can use the following formula

m = (y2 - y1) ÷ (x2 - x1)

where m is the slope of the line and (x1, y1) and (x2, y2) are the coordinates of the two points.

In this case, the slope of the line through the points (16,1) and (17,7) is:

m = (7 - 1) ÷ (17 - 16) = 6 ÷ 1 = 6

So the slope of the line is 6.

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Answer:

she can edit 4 commericals in 144 minutes.

Step-by-step explanation:

144 divided by 36 is 4

Answer:

180

Step-by-step explanation:

you have to add 36/144 to get your answer our welcome.

Hello friend, (づ｡◕‿‿◕｡)づ I'm here to help you solve this

Answer:

IQR = 35.25

Step-by-step explanation:

First Quartile Q1 = 15.75

Second Quartile Q2 = 30.5

Third Quartile Q3 = 51

Interquartile Range IQR = 35.25

Median = Q2 x˜ = 30.5

Minimum Min = 11.5

Maximum Max = 61

Range R = 49.5

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