Answer:
D. f(x) divided by (x−1) has a remainder of 0.
C. (x−1) is a factor of f(x) .
Step-by-step explanation:
Just took a test with this question these are the answers!
The statements that are true about the polynomial function are;
(x−1) is a factor of f(x). f(x) divided by (x−1) has a remainder of 0.Given the polynomial function [tex]f(x)=x^3-x^2-4x+4[/tex]
If x = -1, hence;
[tex]f(-1)=(-1)^3-(-1)^2-4(-1)+4\\f(-1)=-1-1+4+4\\f(-1)=-2+8\\f(-1) =6[/tex]
This shows that f(x) ≠ 0 when x = −1 .
To check if x - 1 is a factor, we will substitute x = 1 into the function and check if the result is zero as shown:
[tex]f(1)=1^3-1^2-4(1)+4\\f(1)=1-1-4+4\\f(1) =0[/tex]
This shows that (x−1) is a factor of f(x).This also shows that if f(x) divided by (x−1) has a remainder of 0.
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some helps plssss i need help
Answer:
Yess
Step-by-step explanation:
If you multiply all the numbers together you get 39690000. And the square root of that number is 6300. So it is a perfect square. If you did 6300² = 39690000.
Question 9 of 10 What is the scale factor of ABC to DEF?
If a 25 kg car Accelerates at a speed of 100ms what will the force of the car be
Answer:
force = 100 m/s/25 s = 4 m/s^2
Simplify. 863x14y9−−−−−−√
Answer: 1
Step-by-step explanation: 863x14ysqrt9= 3 simplified is 1
multiply express your anwser in simplest form
Answer:
1/6
Step-by-step explanation:
9: 9,18,27,36,45,54,63,72,81,90
10: 10,20,30,40,50,60,70,80,90,100
Since, 90 is the LCM of 9 and 10 that turns into your denominater then your equation turns into this...
5/90 x 3/90
The denomineter stays the same so you get 90 then 5 x 3 equals 15 so you get 15 and in total that gives you 15/90. Divide the top and bottom by the greatest number that will divide both numbers exactly which gives you 1/6
HOPE THIS HELPED :D
The total sales tax in a certain city is 8.75%. The state sales tax rate is 7.25%, and the county adds an additional sales tax of 0.5%. How much in sales tax is added by the city?
a.) 0.1%
b.) 0.25%
c.) 1%
d.) 2.5%
Answer:
C.1%
Step-by-step explanation:
Which graph shows the line y = - 3x + 1
Answer:
i need a picture
Step-by-step explanation:
find the original price given the total amount and the tip rate if the total amount is $51.84 and the tip is 20%
Answer: $41.472 or $41.50
Step by step solving: First convert 20% to a decimal which is .20 now multiply that by $51.84 which equals 10.368 now subtract that number from 51.84 which equals 41.472
If you are allowed to round to the nearest hundreth then that would be $41.50 before the tip.
Why is near impossible to draw a rhombus on Geoboard and easy to draw a square?
Thank you in advance :)
Answer: Think about diagonal sides and horizontal bases.
Step-by-step explanation: "Think outside of the box." as they say.
See the screenshot attached.
9x6=9x(4+ )
=( X4)+(9x )
= +
=
idkStep-by-step explanation:
What is (8p - 2)(6p + 2)
answer:
48p² + 4p - 4
solution:
8p × 6p +8p × 2 - 2 × 6p - 2 × 2
48p² + 8p x 2 - 2 ×6p - 2 × 2
48p² + 16p - 12p - 4
48p² + 4p - 4
The required algebraic product is 48[tex]p^{2}[/tex] + 4p - 4.
Given the two binomial (8p - 2)(6p + 2).
To multiply two binomials, take the first term of the first binomial and multiply with the entire second binomial and positive or negative as per given in the first binomial ,take the second term of the first binomial and multiply with the entire second binomial.
Let a, b, c and d be any four variables. Consider (a - b)(c + d) gives
a(c + d) - (c + d).
That implies, (8p - 2)(6p + 2) = 8p(6p + 2) - 2(6p + 2)
Multiply by removing the brackets gives,
(8p - 2)(6p + 2) = 48[tex]p^{2}[/tex] + 16p - 12p - 4
Combining like terms and algebraic sum gives,
(8p - 2)(6p + 2) = 48[tex]p^{2}[/tex] + 4p - 4.
Hence, the required algebraic product is 48[tex]p^{2}[/tex] + 4p - 4.
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Suppose tan(b) = –2, and the terminal side of b is located in quadrant II. What is cot(b)?
Answer:
- 1/2
Step-by-step explanation:
Just took the test
The value of cot (b) using trigonometry is -1/2 when tan b = -2.
Since we are given that tan(b) = -2 and the terminal side of angle b is in quadrant II, determine the value of cot(b).
In quadrant II, the sine and cosine values are positive, while the tangent and cotangent values are negative.
Given:
tan(b) = -2
The cotangent (cot) of an angle is the reciprocal of the tangent:
cot(b) = 1 / tan(b)
Now, substituting the given value of tan(b):
cot(b) = 1 / (-2)
cot(b) = -1/2
So, the value of cot(b) is -1/2.
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A jar that contains quarters and dimes is worth $7.15. If there are a total of 40 coins,
how many of each type of coin is there?
Answer:
21 quarters and 19 dimes
Step-by-step explanation:
Create a system of equations where q is the number of quarters and d is the number of dimes.
0.25q + 0.1d = 7.15
q + d = 40
Solve by elimination by multiplying the bottom equation by -0.25
0.25q + 0.1d = 7.15
-0.25q - 0.25d = -10
Add them together and solve for d:
-0.15d = -2.85
d = 19
Then, plug in 19 as d into the second equation to solve for q:
q + d = 40
q + 19 = 40
q = 21
So, there are 21 quarters and 19 dimes
Answer:
21 Quarters, 19 Dimes.
Step-by-step explanation:
21 x .25 = 5.25
19 x .10 = 1.90
5.25 + 1.90 = 7.15
Supposed y varies directly as x and y =21 when x=3
4x + 10 + 3x = 40 - 3x
O A. x = 3
B. X=
x = 1
15
2
25
O C. X=
2
O D. x = 5
Answer:
a. 3
Step-by-step explanation:
Answer:
(A) X = 3
Step-by-step explanation:
-_-
Use the definition:
f'(x)=[tex]\lim_{h \to 0} \frac{f(x+h)-f(x)}{h}[/tex]
to find f'(x) for:
f(x)=[tex]\frac{1}{\sqrt{x}}[/tex]+x
I need the WORK, not the answer. Thanks!
Using the given definition, for [tex]f(x)=\frac1{\sqrt x}+x[/tex], we have
[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{\left(\frac1{\sqrt{x+h}}+x+h\right)-\left(\frac1{\sqrt x}+x\right)}h[/tex]
Right away, we see x and -x in the numerator, so we can drop those terms.
[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{\frac1{\sqrt{x+h}}+h-\frac1{\sqrt x}}h[/tex]
Remember that limits distribute over sums, i.e.
[tex]\displaystyle\lim_{x\to c}(f(x)+g(x))=\lim_{x\to c}f(x)+\lim_{x\to c}g(x)[/tex]
so we can separate the h from everything else in the numerator:
[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{\frac1{\sqrt{x+h}}-\frac1{\sqrt x}}h+\lim_{h\to0}\frac hh[/tex]
Since h ≠ 0, we have [tex]\frac hh=1[/tex], so the second limit is simply 1.
[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{\frac1{\sqrt{x+h}}-\frac1{\sqrt x}}h+1[/tex]
For the remaining limit, focus on the numerator for now. Combine the fractions in the numerator:
[tex]\dfrac1{\sqrt{x+h}}-\dfrac1{\sqrt x}=\dfrac{\sqrt x-\sqrt{x+h}}{\sqrt x\sqrt{x+h}}[/tex]
Recall the difference of squares identity,
[tex]a^2-b^2=(a-b)(a+b)[/tex]
Let [tex]a=\sqrt x[/tex] and [tex]b=\sqrt{x+h}[/tex]. Multiply the numerator and denominator by [tex](a+b)[/tex], so that the numerator can be condensed using the identity above.
[tex]\dfrac{\sqrt x-\sqrt{x+h}}{\sqrt x\sqrt{x+h}}\cdot\dfrac{\sqrt x+\sqrt{x+h}}{\sqrt x+\sqrt{x+h}}[/tex]
[tex]=\dfrac{(\sqrt x)^2-(\sqrt{x+h})^2}{\sqrt x\sqrt{x+h}(\sqrt x+\sqrt{x+h})}[/tex]
[tex]=\dfrac{x-(x+h)}{\sqrt x\sqrt{x+h}(\sqrt x+\sqrt{x+h})}[/tex]
[tex]=-\dfrac h{\sqrt x\sqrt{x+h}(\sqrt x+\sqrt{x+h})}[/tex]
Back to the limit: all this rewriting tells us that
[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{-\frac h{\sqrt x\sqrt{x+h}(\sqrt x+\sqrt{x+h})}}h+1[/tex]
Again, the h's cancel, and we can pull out the factor of -1 from the numerator and simplify the fraction:
[tex]f'(x)=\displaystyle-\lim_{h\to0}\frac1{\sqrt x\sqrt{x+h}(\sqrt x+\sqrt{x+h})}+1[/tex]
The remaining expression is continuous at h = 0, so we can evaluate the limit by substituting directly:
[tex]f'(x)=-\dfrac1{\sqrt x\sqrt{x+0}(\sqrt x+\sqrt{x+0})}+1[/tex]
[tex]f'(x)=-\dfrac1{2x\sqrt x}+1[/tex]
or, if we write [tex]\sqrt x=x^{1/2}[/tex], we get
[tex]f'(x)=-\dfrac12x^{-3/2}+1[/tex]
i need help on this stuck on it
Answer:
5=148 and 8=32
Step-by-step explanation:
For this equation we know since the lines are parelle that they will produce the same angle degrees.
so 2,4,6,and 8 are all 32
if we subtract 180 (the dregree of a stright line) from 32 we get 148
so 148 is for 1,3,5, and 7
What is the expanded form of (a + b)^2?
Answer:
[tex] {a}^{2} + 2ab + {b}^{2} [/tex]
Answer:
(a + b) × (a + b)
Step-by-step explanation:
(a + b)²
(a + b) × (a + b)
Joseph and Wendy were catching tadpoles. At first Wendy caught nine times three more than Joseph caught. Joseph was upset and released half of Wendy ’s tadpoles, and then six times as many as Joseph caught swam away. After all of this, Wendy only had three tadpoles left. How many tadpoles did Joseph catch?
Answer:
7
Step-by-step explanation:
Step 1: translate the given word problem into solvable algebraic equation.
Let "t" represent the number of tadpoles Joseph caught.
"Wendy caught nine times three more than Joseph caught" can be expressed as 9(t + 3)
Number of Wendy's tadpole = [tex] 9(t + 3) [/tex]
Given that half of Wendy's tadpole and also 6 times Joseph's tadpoles swarm away leaving Wendy with only 3, the following equation can be written:
[tex] \frac{9(t + 3)}{2} - 6t = 3 [/tex]
Step 2: solve for t using the equation created.
[tex] \frac{9(t + 3)}{2} - 6t = 3 [/tex]
Add 6t to both sides
[tex] \frac{9(t + 3)}{2} - 6t + 6t = 3 + 6t [/tex]
[tex] \frac{9(t + 3)}{2} = 3 + 6t [/tex]
Multiply both sides by 2
[tex] \frac{9(t + 3)}{2}*2 = (3 + 6t)*2 [/tex]
[tex] 9(t + 3) = 2(3 + 6t) [/tex]
[tex] 9t + 27 = 6 + 12t [/tex]
Collect like terms
[tex] 9t - 12t = 6 - 27 [/tex]
[tex] -3t = -21 [/tex]
Divide both sides by -3
[tex] t = 7 [/tex]
Joseph caught 7 tadpoles
12x ÷ 4y (if x = -8 and y = 3)
Answer:
- 8
Step-by-step explanation:
Step 1:
12x ÷ 4y Equation
Step 2:
12 ( - 8 ) ÷ 4 ( 3 ) Input x and y
Step 3:
- 96 ÷ 12 Multiply
Answer:
- 8 Divide
Hope This Helps :)
Use the zero product property to find the solutions to the equation x2 + x – 30 = 12.
Answer:
x= 6, -7
Step-by-step explanation:
At sunrise on monday the temperature in new haven, ct is -5f. By noon the temperature is 14 degrees warker and by sunset the temperature is 9 degrees colder than it was noon
Answer:
0 degrees faranhiet
Step-by-step explanation:
when you add 14 and -5 you get 9 then the question says 9 degrees cooler so that would translate to the problem 9 - 9 which you get zero.
Finding Decimal Products Which statements are true for the product of 0.2 and 0.2? Check all that apply. The product will be smaller than both the factors. ✓ There will be a zero in the tenths place, There will be a zero in the hundredths place. The answer is 0.4. ✓ The answer is 0.04.
Answer:
0 The product will be smaller than both the factors.
0 There will be a zero in the tenths place.
0 The answer is 0.04.
Please help me guys!!!
Which of the following is the value or PQ
Answer:
B. 61
Step-by-step explanation:
Given:
∆PQR ≅ ∆PQS
PQ = 2x + 41
QS = 7x - 24
QR = 3x + 16
Required:
Numerical value of PQ
SOLUTION:
First, create an equation to find the value of x as follows:
Since both triangles are congruent, therefore:
QS = QR
7x - 24 = 3x + 16 (Substitution)
Collect like terms
7x - 3x = 24 + 16
4x = 40
Divide both sides by 4
4x/4 = 40/4
x = 10
Find PQ by plugging x = 10 into PQ = 2x + 41
PQ = 2(10) + 41
PQ = 20 + 41
PQ = 61
Is this a function or not a function? (Picture)
Odd number between 3 and 19
Answer:
11, there both 8 away so its right in ze middle :D
Step-by-step explanation:
An expression is shown below if this expression is equivalent to 60, what must be the value of a? A.) 3 B.) 4 C.) 9 D.)16
Answer:
Option (A)
Step-by-step explanation:
Given expression is,
[tex]5\sqrt{48a}=60[/tex]
Squaring on both the sides of the equation,
[tex](5\sqrt{48a})^2=(60)^2[/tex]
25(48a) = 3600
1200a = 3600
By dividing the equation by 1200,
a = [tex]\frac{3600}{1200}[/tex]
a = 3
Therefore, Option (A) will be the answer.
The area of a rectangle is x²-4x-21
Write down an expression for the width and the length of
the rectangle.
Answer:
Step-by-step explanation:
Area of rectangle= Length x Width
and the given Area is a quadratic expression
A=[tex]x^{2} -4x-21[/tex]
We use the factorization method so,
we need 2 numbers that when multiplied we get -21 and when we add/subtract we get -4 so,
A=[tex]x^{2} -7x+3x-21[/tex]
now we simplify,
A=[tex]x(x-7)+3(x-7)[/tex]
A=[tex](x-7)(x+3)[/tex]
This looks familiar doesn't it, when we write the formula for the area of rectangle its
A= Length x Width and the equation here shows that
A= [tex](x-7)(x+3)[/tex]
So the expression for the length is x-7 and
the expression for the width is x+3 i think u have missed maybe some information on the question as such that the perimeter might be missing because length could be either x-7 or even x+3 same goes for width maybe someone can correct me if im wrong
HELP ASAP!!!! simplify 3^2-4/5
Answer:
9-4/5
5/5 = 1
Step-by-step explanation:
Answer:
1
9-4/5 is equal to 5/5 which is equal to 1