The Doppler method can be used to estimate the average orbital distance of a planet's orbit by measuring the time it takes for the star's line-of-sight velocity to cycle from peak to peak, and using Newton's version of Kepler's third law. Option c) is correct .
If a planet orbits a star, both of them revolve around their mutual center-of-mass. This center-of-mass is very close to the star's center since stars are much more massive than planets. As a result, if the star and planet orbit each other, they appear to move in small circles or ellipses around a fixed point.In the Doppler method, astronomers observe the motion of a star, which can reveal the presence of an exoplanet.
When a planet orbits a star, the star moves slightly as a result of the gravitational tug of the planet. This motion causes the star's spectrum to shift slightly towards longer wavelengths (redshift) and shorter wavelengths (blueshift) as the star moves away from and towards us respectively. The size of this shift depends on the mass of the planet and its orbital distance from the star.
By measuring the size of these shifts, astronomers can infer the presence of an exoplanet and estimate its mass and orbital distance. Hence option c) Is correct ,
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when you travel on a moving walkway or an elevator, the linear acceleration of your body is sensed by the
When you travel on a moving walkway or an elevator, the linear acceleration of your body is sensed by the inner ear. The inner ear is responsible for maintaining balance and detecting motion, so it senses the acceleration when the body is in motion on a moving walkway or an elevator.
Acceleration is the rate of change of velocity with respect to time. The change in velocity can be in the form of an increase or decrease in speed, a change in direction, or both. Acceleration is a vector quantity, which means it has both magnitude and direction. It is measured in meters per second squared (m/s²) in the International System of Units (SI).
The inner ear is a small, fluid-filled chamber located in the temporal bone of the skull. It is responsible for hearing and balance. The inner ear contains three semicircular canals and two other structures, the vestibule, and the cochlea. The semicircular canals are responsible for detecting rotational motion, while the vestibule detects linear motion and gravity. The cochlea is responsible for hearing.
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the fm radio band covers the frequency range 88-108 mhz .if the variable capacitor in an fm receiver ranges from 12.4 pf to 18.7 pf , what inductor should be used to make an lc circuit whose resonant frequency spans the fm band? express your answer in microhenries.
The inductor to be used to make an LC circuit whose resonant frequency spans the FM band is 6.30 µH.
An LC circuit comprises a capacitor and an inductor. The resonant frequency of an LC circuit is provided by the formula given below:
f = 1/(2π √LC)
Here, f denotes the resonant frequency, L denotes the inductance of the coil, and C denotes the capacitance of the capacitor.Given, the variable capacitor in an FM receiver ranges from 12.4 pF to 18.7 pF.The frequency range of the FM band covers from 88 MHz to 108 MHz. This means that the frequency range of the LC circuit should also fall within this range. We are to calculate the inductor to be used.To calculate the inductor to be used, we can use the resonant frequency formula and substitute the given values to find the value of the inductor:
88 MHz = 88 × 1[tex]0^{6}[/tex] Hz
108 MHz = 108 × 1[tex]0^{6}[/tex] Hz
Let's start by calculating the value of capacitance: Cmax = 18.7 pF Cmin = 12.4 pF
The resonant frequency can be found by the given formula:
f = 1/(2π √LC)
Let's solve for L using this formula:
f = 88 × 1[tex]0^{6}[/tex] HzC = CmaxL = ?88 × 1[tex]0^{6}[/tex] = 1/(2π √L × 18.7 × 1[tex]0^{-12}[/tex])
Solving for L: L = 6.30 µH
Now, the inductor that should be used to make an LC circuit whose resonant frequency spans the FM band is 6.30 µH.
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A thin uniform rod of mass M and length L is bent at its center so that the two segments are now perpendicular to each other.A) Find its moment of inertia about an axis perpendicular to its plane and passing through the point where the two segments meet.B) Find its moment of inertia about an axis perpendicular to its plane and passing through the midpoint of the line connecting its two ends.
A thin uniform rod of mass M and length L is bent at its center so that the two segments are now perpendicular to each other.
A) To find the moment of inertia about an axis perpendicular to its plane and passing through the point where the two segments meet, we can use the parallel axis theorem. The moment of inertia of a thin rod of length L and mass M can be found to be:
I = mL^2 /12
Now, we need to add the distance between the axis of rotation and the centre of mass. The distance between the two points is L/2. Thus, the moment of inertia is:
I = mL^2/12 + mL^2/4 = mL^2/3
B) To find the moment of inertia about an axis perpendicular to its plane and passing through the midpoint of the line connecting its two ends, we can use the perpendicular axis theorem. The moment of inertia of the rod can be found to be:
I = mL^2/3
Since the distance between the axis of rotation and the Centre of mass is 0, the moment of inertia remains the same.
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Which type of tide has the lowest tidal range?
Neap tides have the lowest tidal range.
During the neap tides, the gravitational forces of the sun and the moon are perpendicular to each other, resulting in the lowest tidal range. This occurs twice a month, during the first and third quarters of the moon. During these times, the high tides are not as high, and the low tides are not as low.
Neap tides occur because the gravitational forces of the sun and the moon partially cancel each other out, resulting in weaker tidal forces. In contrast, during the full and new moons, the gravitational forces of the sun and the moon are aligned, resulting in stronger tidal forces and higher tidal ranges, known as spring tides.
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a 2.00 kg mass is attached to a light cord that is wrapped around a pulley of radius 3.80 cm, which turns with negligible friction. the mass falls at a constant acceleration of 2.40 m/s2. find the moment of inertia of the pulley.
The moment of inertia of the pulley when a 2.00 kg mass is attached to a light cord that is wrapped around a pulley of radius 3.80 cm, which turns with negligible friction and the mass falls at a constant acceleration of 2.40 [tex]m/s^2[/tex] is 4.5472[tex]kgm^2[/tex].
The moment of inertia of a pulley can be calculated using the equation I = [tex]mr^2[/tex], where m is the mass of the pulley and r is its radius. In this example, the mass of the pulley is 2.00 kg and its radius is 3.80 cm. So, the moment of inertia is:
I = [tex](2.00 kg)(3.80 cm)^2[/tex]
= 4.5472 [tex]kgm^2[/tex]
To understand why this equation works, it helps to consider the concept of rotational inertia. Rotational inertia is the measure of an object's resistance to changes in its rotational velocity. When a mass is attached to a pulley and accelerates downwards, the pulley must resist the pull of the mass, resulting in an increased rotational velocity. The moment of inertia, then, is a measure of how well the pulley is able to resist changes in rotational velocity.
The equation for calculating the moment of inertia assumes that the mass of the pulley is evenly distributed around its circumference. When a pulley accelerates, it creates a centrifugal force, which increases with an increase in the pulley's rotational velocity. In other words, a pulley with a larger moment of inertia will be able to resist a greater centrifugal force.
In this example, the pulley accelerates downwards at a constant acceleration of [tex]2.40 m/s^2[/tex]. The equation for calculating the moment of inertia provides an accurate measurement of the pulley's rotational inertia in this situation, since it takes into account the mass and the radius of the pulley. By substituting the values for the mass and the radius into the equation, we can calculate the moment of inertia of the pulley to be [tex]4.5472 kgm^2[/tex].
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when a falling merteoiud is at a distance above the earth's surface of 3 times the earth's radius what is it acelartion due to earths gravitation
At a distance above the Earth's surface of 3 times the Earth's radius, the acceleration due to Earth's gravity is approximately 1.23 m/s².
Distance above the Earth's surface of 3 times the Earth's radius, the distance from the center of the Earth is:
d = 4 * R
where R is the radius of the Earth.
The acceleration due to gravity at this distance can be calculated using the formula:
a = G * M / d²
where G is the gravitational constant,
M is the mass of the Earth, and
d is the distance from the center of the Earth.
Substituting the values, we get:
a = G * M / (4*R)²
where G = 6.67 × 10⁻¹¹ Nm²/kg² and M = 5.97 × 10²⁴ kg.
Substituting these values, we get:
a = 1.23 m/s²
Therefore, the acceleration due to Earth's gravity at a distance above the Earth's surface of 3 times the Earth's radius is approximately 1.23 m/s².
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increasing the kilovoltage on the control panel, with all other exposure factors remaining the same, will result in a film that is: group of answer choices a. overexposed and darker b. underexposed and lighter c. normal exposure and diagnositc d. increasing the kvp does not affect the quality of the film
Increasing the kilovoltage on the control panel, with all other exposure factors remaining the same, will result in a film that is: "Underexposed and lighter." The correct option is b.
If we increase the kilovoltage on the control panel with all other exposure factors remaining the same, it will result in a film that is underexposed and lighter. The increase in kVp leads to the increase in the penetrating ability of the x-ray beam. It, therefore, increases the number of x-ray photons that reach the film and allows more of the scattered radiation to reach the film.
The underexposure leads to lightening of the image on the film. In addition to this, the increased kilovoltage reduces the contrast of the image. It is due to the fact that the overall density of the image is decreased due to underexposure.
In conclusion, an increase in kVp on the control panel leads to an increase in the number of x-ray photons that reach the film, thereby lightening the image on the film. Also, the image will be underexposed because an increased kilovoltage reduces the contrast of the image. Here, the correct option is b. underexposed and lighter.
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a 0.493 kg red puck, moving east with a speed of 2.79 m/s, has a head-on collision with a 0.963 kg blue puck initially at rest. assuming a perfectly elastic collision, what will be the speed of the red puck after the collision?
When two objects collide, their total momentum is conserved. In this case, the initial momentum of the system is the sum of the momentum of the red puck and the momentum of the blue puck, which is zero since the blue puck is at rest. Therefore, the initial momentum of the system is equal to the momentum of the red puck, which is 1.370 kg*m/s.
During the head-on collision, the momentum of the red puck is transferred to the blue puck, causing it to move east with a velocity of 2.79 m/s. However, the collision is perfectly elastic, so both the momentum and the kinetic energy of the system are conserved.
Since the blue puck was initially at rest and gains all the momentum of the system, the red puck rebounds with the same momentum as before the collision but in the opposite direction. This results in the conservation of total momentum.
Therefore, the speed of the red puck after the collision is 2.79 m/s in the opposite direction, which is the same as its initial speed. The blue puck, on the other hand, moves with a speed of 2.79 m/s in the same direction as the initial velocity of the red puck.
This type of collision is known as a perfectly elastic collision, where kinetic energy is conserved and there is no loss of energy due to deformation or other factors.
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write a statement (your hypothesis) about what you think will happen in the parallel circuit when you remove one resistor (led). support your answer with reasoning.
My hypothesis is that when one resistor (LED) is removed from a parallel circuit, the overall resistance of the circuit will decrease.
This is because parallel circuits have multiple paths for current to flow through, and removing one resistor (LED) reduces the number of paths and increases the current flow through the remaining resistors.
What happens when one resistor is removed from a parallel circuit?When you remove one resistor from a parallel circuit, the current through the other resistors will increase because there are fewer resistors for the current to flow through. This means that the overall resistance of the circuit decreases when you remove one resistor. This is because parallel circuits have multiple paths for current to flow through.
Removing one resistor reduces the number of paths and increases the current flow through the remaining resistors. A parallel circuit is a circuit in which the components are connected in such a way that the voltage is the same across each component.
In contrast, a series circuit is a circuit in which the components are connected in a series, so the same current flows through each component.
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a spaceship recedes from earth at 0.5 times the speed of light and shines a powerful searchlight onto earth. the photons from this searchlight will hit earth with a velocity of
When a spaceship recedes from Earth at 0.5 times the speed of light and shines a powerful searchlight onto Earth, the photons from this searchlight will hit Earth with a velocity of 1.5 times the speed of light.
According to Einstein's theory of special relativity, it is impossible for an object with mass to travel at the speed of light or faster. However, light always travels at the same speed, which is about 299,792,458 meters per second in a vacuum or 3.00 × 108 meters per second. It is the fundamental postulate of the theory of relativity. Let's say the spaceship is moving away from Earth at v = 0.5c. In this case, the velocity of the photons relative to the spaceship is c, the speed of light. Therefore, to find the velocity of the photons relative to Earth, we must add the velocities. That is:v = u + vw = 0.5c, u = c, v = ?v = u + wv = c + 0.5cv = 1.5c
Therefore, the photons from this searchlight will hit Earth with a velocity of 1.5 times the speed of light.
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a current of 6.09 a in a solenoid of length 14.8 cm creates a 0.203 t magnetic field at the center of the solenoid. how many turns does this solenoid contain?
The solenoid contains approximately 259 turns.
The magnetic field produced by a solenoid is directly proportional to the current passing through it and the number of turns in the solenoid. The formula for the magnetic field produced by a solenoid is given as B = μ₀nI, where B is the magnetic field, μ₀ is the permeability of free space, n is the number of turns per unit length, and I is the current passing through the solenoid.
We are given that the current passing through the solenoid is 6.09 A, the length of the solenoid is 14.8 cm, and the magnetic field produced at the center of the solenoid is 0.203 T. We can use these values to calculate the number of turns in the solenoid as follows:
B = μ₀nI
n = B/(μ₀I)
Substituting the given values, we get:
n = (0.203 T)/(4π×10⁻⁷ T·m/A × 6.09 A × 0.148 m)
n ≈ 259 turns
Therefore, the solenoid contains approximately 259 turns.
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a person who weighs 550 n empties her lungs as much as possible and is then completely immersed in water (of density 1000 kg/m3) while suspended from a harness. her apparent weight is now 21.2 n. what is her density?
The density of the person is 480.24 kg/m³.
Given,
Mass of the person = m = 550 N
Apparent weight =[tex]F_ a_p_p_a_r_e_n_t[/tex] = 21.2 N
Density of water = р = 1000 kg/m³
We need to find the density of the person.
The formula for the apparent weight of an object when it is immersed in a liquid is given as:
[tex]F_ apparent[/tex][tex]= (m[/tex]р[tex]V)_g[/tex]...…(1)
Where m is the mass of the object, ρ is the density of the liquid, V is the volume of the object and g is the acceleration due to gravity.
Let V be the volume of the person. Then, the weight of the person in air = mg And, the weight of the person in water = [tex]F_ a_p_p_a_r_e_n_t[/tex] = 21.2 N
We know that, Weight of the person in air - Weight of the person in water = Buoyant force = Weight of water displaced by the person[tex]mg - F_ a_p_p_a_r_e_n_t[/tex]
550 - 21.2 = р[tex]V_g[/tex]
528.8 = р[tex]V_g[/tex].......(2)
Dividing both sides of equation (1) and (2), we get:
[tex]F_ a_p_p_a_r_e_n_t[/tex][tex]/m - mg/m[/tex] = [tex](m -[/tex] р[tex]V)_g/m[/tex] = р[tex]V_g/m[/tex]
[tex]F_ a_p_p_a_r_e_n_t[/tex][tex]/m - g =[/tex] р/[tex]V_g[/tex][tex]/m - g[/tex]
[tex]F_ a_p_p_a_r_e_n_t[/tex][tex]m - g =[/tex] р/[tex]V_g[/tex][tex]/m[/tex]
21.2/550 - 9.81 = рVg/550 - 9.81Vg/550 = (21.2/550 - 9.81)/(р).........(3)
We know that, Density = mass/volume => р= m/V => V = m/р
Substituting V in equation (3), we get:
Vg/550 = (21.2/550 - 9.81)/m/рg
V = m/р = (21.2/550 - 9.81)/(1000*9.81)≈ 0.0113 m³
Substituting the value of V in equation (2), we get:528.8 = р(0.0113) (9.81)р = 480.24 kg/m³
Therefore, the density of the person is 480.24 kg/m³.
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the electric field just above one face of a copper penny is 2000 n/c. what is the surface charge density on this face of the penny?
The surface charge density on the face of the penny is [tex]5.02 * 10^{-6} C/m^2[/tex].
The electric field just above one face of the penny is given as 2000 N/C.
The electric field just above the surface of a conductor is given by the equation E = σ/ε₀, where σ is the surface charge density, and ε₀ is the electric constant.
Rearranging the equation to solve for σ, we get σ = ε₀ * E.
Plugging in the values, we get σ = [tex](8.85 * 10^{-12} C^2/N m^2) * 2000 N/C = 1.77 * 10^{-8} C/m^2.[/tex]
However, this value is for both the top and bottom faces of the penny, so we need to divide by 2 to get the surface charge density for only one face, which gives [tex]5.02 * 10^{-6} C/m^2[/tex]
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a talented musician can produce a number of overtones on this natural horn. what would be the frequency of the fourth overtone (5th harmonic) produce when the musician is playing a middle c fundamental?
The frequency of the fourth overtone produced when the musician is playing a middle C fundamental is 1280 Hz. Therefore, the correct option is D.
A natural horn (trumpet with no valves) is similar to a pipe open at both ends. A musician plans to create a fundamental frequency of 256 Hz (middle C) using the horn. A talented musician can produce a number of overtones on this natural horn.
To solve this question, you need to know that the frequency of the fundamental frequency in a pipe open at both ends is given by;
f = (n * v) / (2L)
where, f is the fundamental frequency, n is an integer, v is the speed of sound, and L is the length of the pipe.
Since the question has already given us the frequency, we can rearrange the above equation to obtain the length of the pipe. Therefore,
L = (n * v) / (2f).
Since we are dealing with the fourth overtone, we know that n = 5.
Therefore, the frequency of the fourth overtone is given by;
f4 = 5f = 5 * 256 Hz = 1280 Hz
Hence, the frequency of the fourth overtone produced when the musician is playing a middle C fundamental is 1280 Hz (option D).
Note: The question is incomplete. The complete question probably is: A natural horn (trumpet with no valves) is similar to a pipe open at both ends. A musician plans to create a fundamental frequency of 256 Hz (middle C) using the horn. A talented musician can produce a number of overtones on this natural horn. What would be the frequency of the fourth overtone produce when the musician is playing a middle C fundamental? A) 512 Hz B) 768 Hz C) 1024 Hz D) 1280 Hz E) 1536 Hz
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I
or
4.
Displacement/cm
-2-
-4
2-
0
45
0
2.
-21
4-
Displacement/cm
4
(a)
Figures A and B show two graphs which refer to the same transverse wave.
10
Figure A (Displacement at given time)
20
30
10
Figure B (Displacement at given distance from source)
40
X
50
12
60
14
Distance/m
70
(i) Mark clearly two points on figure A which are 2-5 wavelengths apart.
(ii) Mark clearly two points on figure B which are 90° out of phase.
(iii) Calculate the speed of the wave.
Time/s
UY
145
C
Num
Lock
9
Pg Up
6
3
Pg Dn
(iv) Draw another graph in figure A to represent a wave of the same frequency but double
the speed and half the amplitude.
131
Ente
Answer:
(i) On Figure A, two points that are 2.5 wavelengths apart can be marked at the points where the wave crosses the x-axis (i.e., where the displacement is zero) at approximately 12.5 cm and 32.5 cm.
(ii) On Figure B, two points that are 90° out of phase can be marked at any two points where the wave has the same displacement value but is moving in opposite directions. One such pair of points could be at approximately 45 m and 55 m, where the wave has a displacement of approximately 10 cm in opposite directions.
(iii) To calculate the speed of the wave, we can use the formula v = λf, where v is the speed, λ is the wavelength, and f is the frequency. From Figure A, we can see that the wavelength is approximately 20 cm, and from Figure B, we can see that the distance between two consecutive points where the wave has the same displacement value is also approximately 20 cm. Therefore, the wavelength is 20 cm, and the frequency can be calculated as f = 1/T, where T is the time period of the wave. From Figure A, we can see that the time period is approximately 0.16 s (the time it takes for the wave to complete one full cycle), so the frequency is f = 1/0.16 s = 6.25 Hz. Therefore, the speed of the wave is v = λf = 20 cm * 6.25 Hz = 125 cm/s.
(iv) To draw another graph in Figure A to represent a wave of the same frequency but double the speed and half the amplitude, we can simply shift the entire graph to the right so that the peaks and troughs line up with the points on the x-axis where the wave crosses zero, and then reduce the amplitude by a factor of 0.5. The resulting graph would have the same shape as Figure A but with a smaller amplitude and a shorter wavelength (since the speed is double).
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1. How does the speed of coastal erosion compare to other types of erosion?
a 0.24 kg blob of clay is thrown at a wall with an initial horizontal velocity of 16 m/s if the clay comes to a stop in what is the average horizontal force on the clay due to the wall?
The average horizontal force on the clay due to the wall, given that the clay is thrown at the wall with an initial horizontal velocity of 16 m/s is 42 N
How do i determine the average horizontal force?To obtain the average horizontal force, we shall begin by calculating the deceleration of the blob of clay. Details below:
Initial velocity (u) = 16 m/sFinal velocity (v) = 0 m/sTime (t) = 91 ms = 91×10⁻³ sDeceleration of blob of clay (a) =?a = (v - u) / t
a = (0 - 16) / 91×10⁻³
a = -16 / 91×10⁻³
a = -175.8 m/s²
Finally, we shall determine the average horizontal force on the clay due to the wall. This is illustrated below:
Mass of blob of clay (m) = 0.24 KgDeceleration of blob of clay (a) = -175.8 m/s²Average horizontal force (F) =?Force = mass × deceleration
Average horizontal force = 0.24 × -175.8
Average horizontal force = -42 N
Note: The negative sign indicates that the force is in opposite direction to the motion of the clay.
Thus, the average horizontal force is 42 N
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complete question
A 0.24 kg blob of clay is thrown at a wall with an initial velocity of 16 m/s. If the clay comes to a stop in 91 ms, what is the average force experienced by the clay?
if there were two telescopes with the same diameter, but one is a visible light telescope and the other a radio telescope, how would the resolution of the images from each telescope compare? the wavelength of visible light is several hundred nanometers (1 nanometer
The resolution of the images produced by the visible light telescope will be higher than that of the radio telescope, due to the difference in wavelength.
When there were two telescopes with the same diameter, but one is a visible light telescope and the other a radio telescope, the resolution of the images from each telescope would be different. The wavelength of visible light is several hundred nanometers (1 nanometer = 10−9 meters), while the wavelength of radio waves is much longer, typically on the order of meters or centimeters.
Hence, we can compare the resolution of visible light and radio telescopes. This means that the visible light telescope will be able to resolve more details, since it can detect smaller details due to its smaller wavelength.
Radio telescopes have a lower resolution compared to visible light telescopes because of their longer wavelength. The resolution of an optical telescope is limited by the size of its aperture. The smaller the aperture, the more diffracted the image. As the aperture size grows, the resolving power of the instrument improves.
The same is not true of radio telescopes because their wavelength is so much longer than visible light. The aperture size of a radio telescope would have to be several kilometers in diameter to achieve the same resolution as a visible light telescope of the same size. This is why radio telescopes are usually much larger than optical telescopes.
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a person is dragging a packing crate of mass 100 kg across a rough horizontal floor where the coefficient of kinetic friction is 0.400. he exerts a force f sufficient to accelerate the crate forward. at what angle above horizontal should his pulling force be directed in order to achieve the maximum acceleration?
The pulling force should be directed at an angle of 45 degrees above horizontal to achieve the maximum acceleration.
To find the angle above horizontal at which the maximum acceleration can be achieved, we can use the following equation: [tex]F - f_k = ma[/tex]
where F is the applied force,[tex]f_k[/tex] is the force of kinetic friction, m is the mass of the crate, and a is the acceleration of the crate.
The force of kinetic friction is given by: [tex]f_k =\mu_k N[/tex]
where μ_k is the coefficient of kinetic friction and N is the normal force.
The normal force is equal in magnitude to the weight of the crate, which is: N = mg
where g is the acceleration due to gravity.
Substituting the values given in the problem, we have:
[tex]f_k = 0.400 * 100 kg * 9.81 m/s^2 = 392.4 N[/tex]
[tex]N = 100 kg * 9.81 m/s^2 = 981 N[/tex]
[tex]f_k = \mu_k N = 0.400 * 981 N = 392.4 N[/tex]
Now we can rewrite the first equation as:
F - 392.4 N = ma
Solving for F, we have:
F = ma + 392.4 N
To achieve the maximum acceleration, the force should be applied at an angle that maximizes the horizontal component of the force. This occurs when the force is applied parallel to the surface of the floor, so the angle above horizontal is 0 degrees. Therefore, the pulling force should be directed horizontally to achieve maximum acceleration.
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If it takes 726 watts of power to move a mass 36 meters in 14 seconds, then what is the magnitude of the object’s mass?
A. 12. 1 kg
B. 20. 2 kg
C. 28. 8 kg
D. 282 kg
Answer: mass=28.8kg
Power , p =726 watt
displacement, d =36m
time ,t =14s
g=9.8m/s^2
p= (work)/t
p=(mg*d)/t
726=(m*9.8*36)/14
m= 28.8kg
Explanation: when a force causes displacement of the body , work is said to be done on the body. Power is the rate of doing work. Hence here power was applied on a body of certain mass which caused the given displacement of the body in given time.
which of the following force (s) conservative forces? (can be multiple answers) a) spring force b) gravitational force c) friction force d) an applied force
The conservative forces are spring force and gravitational force. The correct options are a) and b),
A conservative force is a force that depends only on the initial and final positions of an object and not on the path taken by the object between those positions. In other words, the work done by a conservative force in moving an object from one position to another is independent of the path taken by the object.
The spring force and the gravitational force are examples of conservative forces. The spring force is a restoring force that acts on an object that is displaced from its equilibrium position, and its magnitude depends only on the displacement of the object. The gravitational force is a force that attracts two masses to each other, and its magnitude depends only on the masses and the distance between them.
On the other hand, the friction force and an applied force are examples of non-conservative forces. The friction force depends on the path taken by the object, as it dissipates the energy of the object into heat and sound. The applied force is a force that is exerted on an object by another object, and its magnitude and direction can change as the object moves, making it path-dependent.
Therefore, the conservative forces are the spring force and the gravitational force. Which are options a) and b)
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7. How much time would it take a bowling ball dropped from a helicopter to reach a speed of 55 m/sec?
How far will the ball have fallen in that time?
Answer:
Approximately [tex]5.61\; {\rm s}[/tex].
Approximately [tex]154\; {\rm m}[/tex].
(Assuming that [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex], air resistance on the ball is negligible, and that the helicopter was initially stationary.)
Explanation:
Under the assumptions, acceleration of the ball during the fall would be constantly [tex]a = g = 9.81\; {\rm m\cdot s^{-2}}[/tex].
Let [tex]u[/tex] denote the initial velocity of the ball; [tex]u = 0\; {\rm m\cdot s^{-1}}[/tex] since it is assumed that the helicopter was initially stationary.Let [tex]v[/tex] denote the final velocity of the ball; [tex]v = 55\; {\rm m\cdot s^{-1}}[/tex].Apply the SUVAT equation [tex]t = (v - u) / a[/tex] to find the time it takes for the velocity of the ball to change from [tex]u = 0\; {\rm m\cdot s^{-1}}[/tex] to [tex]v = 55\; {\rm m\cdot s^{-1}}[/tex]:
[tex]\begin{aligned}t &= \frac{v - u}{a} \\ &= \frac{55 - 0}{9.81}\; {\rm s} \\ &\approx 5.61\; {\rm s}\end{aligned}[/tex].
Apply the SUVAT equation [tex]x = (v^{2} - u^{2}) / (2\, a)[/tex] to find the displacement [tex]x[/tex] of the ball as its velocity change from [tex]u = 0\; {\rm m\cdot s^{-1}}[/tex] to [tex]v = 55\; {\rm m\cdot s^{-1}}[/tex]:
[tex]\begin{aligned}x &= \frac{v^{2} - u^{2}}{2\, a} \\ &= \dfrac{55^{2} - 0^{2}}{2\, (9.81)}\; {\rm m} \\ &\approx 154\; {\rm m}\end{aligned}[/tex].
measurement of the speed of sound using the flash and report method
The flash and report method is a simple and common technique used to measure the speed of sound. In this method, an observer measures the time between seeing a flash, such as from a gunshot or a firecracker, and hearing the corresponding sound. The observer is usually at a known distance from the source of the flash and sound.
To perform the experiment, the observer stands at a fixed distance away from the source of the flash and sound. When the flash is seen, they start a stopwatch or use any other timing device. Once they hear the sound, they stop the timer and note the time difference between the flash and the sound. This time difference is the time it takes for the sound to travel from the source to the observer.
The speed of sound can then be calculated using the formula: speed of sound = distance / time taken. The distance between the observer and the source is divided by the time difference recorded to find the speed of sound in the medium (usually air).
It is essential to ensure that the distance between the source and the observer is accurate and that the observer's reaction time is considered when measuring the time difference. External factors such as temperature, humidity, and altitude also affect the speed of sound and should be taken into account.
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The probable question may be:
Discuss the measurement of the speed of sound using the flash and report method?
need help asap pleasee
Answer:
Hello! Our answer is C: it shows negative acceleration :)
Explanation:
Small tip: Always draw a car when you are working with these type of questions. Now imagine: A car is moving in the positive way, goes smae speed for a bit, and slows down. Then it stops at 30 mins. Then it starts moving in the opposite direction. So, our answer is c :)
Good luck!
define wavelength and amplitude. when considering color vision, how does our visual system interpret wavelength? amplitude? provide examples to illustrate your answer.
When we consider color vision, the visual system interprets wavelength and amplitude. The definition of wavelength and amplitude is given below.
Wavelength is the distance between two points, measured in the direction of propagation, that correspond to the same phase of the wave. Its symbol is λ. The distance traveled by one full cycle of the wave is its wavelength.
The human eye has a visual spectrum of wavelengths ranging from 400 to 700 nanometers. Amplitude is the extent of displacement or change in the oscillatory motion of a wave, particularly of a sound wave, electromagnetic wave, or other wave. Its symbol is A. The amplitude of a wave is the height of the wave's crest, measured from its resting position to its highest point.Color vision and how it interprets wavelength and amplitude Our visual system perceives color by interpreting light waves of different wavelengths. When light waves enter our eyes, they are broken down into different wavelengths, which our eyes interpret as color. When our eyes see light of different wavelengths, they appear to be different colors. The shorter the wavelength, the bluer the light appears, and the longer the wavelength, the redder it appears.
As a result, if we consider color vision, our visual system interprets wavelength and amplitude. The human eye sees different colors by interpreting different wavelengths of light. For example, when we see a rainbow, we can see all of the colors, such as red, orange, yellow, green, blue, indigo, and violet. The rainbow has a wavelength spectrum ranging from 400 to 700 nanometers.A rainbow is a natural phenomenon that occurs when light is refracted by water droplets, producing a spectrum of colors. Another instance of color vision is a sunset. The sky appears red and orange during a sunset because the longer wavelengths of light are refracted more than the shorter ones. When light waves travel through the atmosphere and bounce off the Earth's surface, this occurs.
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Wavelength
(meters)
Radio Microwave Infrared
10
102
10-5
About the size of...
Visible Ultraviolet
5x106
10
X-ray Gamma Ray
10-10
10 10-12
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tt
214 à & f &
Buildings Humans Honey Bee Pinpoint Protozoans Molecules Atoms Atomic Nuclei
A. visible light
C. gamma rays
According to this chart, which form of electromagnetic
radiation has the longest wavelength?
B. ultraviolet light
D. radio waves
Please help 30 points and will mark brain thing
The form of electromagnetic radiation with the longest wavelength according to the chart is radio waves, which have a wavelength of [tex]10^{5}[/tex]meters. So, the correct answer is D. radio waves.
What is Wavelength?
Wavelength is a physical quantity that measures the distance between two consecutive peaks or troughs of a wave. It is usually denoted by the Greek letter lambda (λ) and is measured in units of length, such as meters (m), centimeters (cm), or nanometers (nm). In other words, wavelength is the distance over which a wave repeats itself.
The question asks which form of electromagnetic radiation has the longest wavelength. Based on the chart, the answer is D. radio waves. Radio waves have wavelengths of about 10 meters to [tex]10^{5}[/tex] meters, which is much longer than the wavelengths of visible light, ultraviolet light, X-rays, and gamma rays. In fact, radio waves are about the same size as buildings, while gamma rays are about the same size as atomic nuclei.
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the b) part please...
Tyres have a tread pattern to improve traction and provide better handling on a variety of road surfaces, including wet and slippery conditions.
Why do tyres use a tread pattern ?The tread pattern on tyres is designed to provide a number of benefits for drivers. One of the main reasons for the tread pattern is to improve traction, particularly on wet or slippery surfaces.
The pattern provides channels or grooves that help to channel water away from the surface of the tyre, reducing the risk of hydroplaning and improving grip on wet roads. This can be particularly important in areas with frequent rainfall or snow. The tread pattern also helps to improve handling on a variety of road surfaces.
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from port a, a boat sails 26 miles on a bearing of 60°. then the boat changes course to a bearing of 270° until it reaches a point directly north of the port. determine the total distance the boat has sailed to the nearest tenth of a mile.
It states that the ratio of the length of a side of a triangle to the sine of the angle opposite that side is the same for all three sides of the triangle. Hence, the total distance the boat has sailed is 39 miles
From port A, a boat sails 26 miles on a bearing of 60°. Then the boat changes course to a bearing of 270° until it reaches a point directly north of the port. To find: The total distance the boat has sailed.Solution: Let A be the starting point of the boat, and C be the point where the boat reaches directly north of the port. Join AC and let BC be the second leg of the boat.
Join AB.AB = Distance traveled on the first leg = 26 miles
ΔABC,
∠ABC = 90°∠BAC = 60°
∴ ∠ACB = 30°
Using the sine rule in ΔABC,
sin A / AB = sin B / BC sin 60° / 26 = sin 30° / BCB = 26 sin 30° / sin 60°BC = 13 miles now,
the boat is moving northwards from point C.
So, BC is the distance traveled by boat in the direction of 270° angle. Total distance traveled = AB + BC= 26 + 13= 39 miles. Hence, the total distance the boat has sailed is 39 miles (the nearest tenth of a mile).Note: The sine rule is used to solve any triangle, i.e., finding the length of a side or the size of an angle when some or all the sides and angles are known.
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What will this wave look like when it reflects across a free boundary?
The amplitude of the reflected wave is opposite to the amplitude of the original wave.
When a wave reflects across a free boundary, it undergoes a change in direction and amplitude. The reflected wave looks like the original wave, but it's inverted. It means that the reflected wave's crest becomes a trough, and the trough becomes a crest.What is a wave?A wave is a disturbance that travels through space and time, carrying energy without carrying matter along with it. The movement of energy through a body of water, such as the ocean, is a typical example of a wave.A free boundary refers to a boundary that is not restricted. An example of a free boundary is a reflecting surface. When waves reflect off of a free boundary, they bounce back in the opposite direction. The angle of reflection equals the angle of incidence.The wave looks similar to the original wave, but it is inverted or flipped. The crest of the original wave becomes the trough of the reflected wave, and the trough becomes the crest.
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what would happen to shadows if you were to move the sun farther away from the earth and moon? and what would happen if you moved it closer?
If you were to move the sun farther away from the earth and moon, shadows would become sharper and more defined. This is because the light rays from the sun would be more parallel, resulting in less scattering and more direct illumination. The shadows would also be longer because the light source is farther away.
If you were to move the sun closer to the earth and moon, shadows would become less defined and more diffuse. This is because the light rays would be less parallel, resulting in more scattering and less direct illumination. The shadows would also be shorter because the light source is closer.
Answer:
If the sun were moved farther away from the Earth and Moon, the shadows would become sharper and darker because the Sun's light would be more direct and less scattered. This would result in more defined shadows with less ambient light to soften their edges.
On the other hand, if the Sun were moved closer to the Earth and Moon, the shadows would become less defined and lighter because the Sun's light would be less direct and more scattered. This would result in less defined shadows with more ambient light to soften their edges.
However, it's important to note that the position of the sun is not the only factor affecting shadows. Other factors include the size and shape of the object casting the shadow, the position of the observer, and the angle of incidence of the light source.