How do you write 9.6 × 103 in standard form?

Answer:

the number is even

Step-by-step explanation:

an even number plus an even number will aalways be even. adding 6 to an odd number will never be even. Therefore the number will be even

Answer:

24

Step-by-step explanation:

10^2+x^2=26^2

x^2=26^2-10^2

x^2=576

x=[tex]\sqrt{576}[/tex]=24

To move Point A(-5, -2) to Quadrant IV, we need to apply one or more transformations that result in a reflection about the x-axis and/or a rotation of 180 degrees. The following transformations would move Point A to Quadrant IV:

Reflection about the x-axis: This transformation would change the sign of the y-coordinate, making it positive. So, the image of A after this transformation would be (−5, 2).

Rotation of 180 degrees about the origin: This transformation would change the sign of both the x and y-coordinates, making them positive. So, the image of A after this transformation would be (5, 2).

Therefore, either a reflection about the x-axis or a rotation of 180 degrees would move Point A to Quadrant IV.

the solution to the original rational equation is: [tex]x = 4.678[/tex] (rounded to three decimal places)

A rational number is a number that can be expressed as a ratio of two integers, where the denominator is not zero. In other words, it is a number that can be written in the form of a/b, where a and b are integers and b is not equal to zero

There are two equal signs in the equation, which is incorrect. Assuming you meant to write:

[tex]2/(x-2) + 3/(x-4) = 1/(x^2 + 6x + 8)[/tex]

We can start by finding a common denominator for the left-hand side of the equation:

[tex]2/(x-2) + 3/(x-4) = 1/[(x+2)(x+4)][/tex]

Multiplying both sides of the equation by (x-2)(x-4)(x+2)(x+4), we get:

[tex]2(x-4)(x+2)(x+4) + 3(x-2)(x+2)(x+4) = (x-2)(x-4)[/tex]

Expanding and simplifying, we get:

[tex]5x^3 - 19x^2 - 39x + 56 = 0[/tex]

This polynomial equation does not factor nicely, so we can use the rational root theorem or numerical methods to find approximate solutions. Using a calculator or computer, we find that there is one real solution to the equation:

[tex]x \approx 4.678[/tex]

Therefore, the solution to the original rational equation is:

[tex]x = 4.678[/tex] (rounded to three decimal places)

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Answer:

Step-by-step explanation:

3 hours of babysitting = $27

if he needs $180 per week he needs to work at least 12 hours in landscaping.

12 hours of Landscaping = $156

156 + 27 = 183

It cuts down about an hour of work.

If I misunderstood something, please let me know. Have a good day :)

Answer:

18+5f

Step-by-step explanation:

6+9f+5+4+3-4f

=11+5f+7

=18+5f

Answer:

18 + 5f

Step-by-step explanation:

To simplify the expression 6 + 9f + 5 + 4 + 3 - 4f, we must combine like-terms.

6 + 5 + 4 + 3 = 18 (6,5,4, and 3 are like-terms because they are all normal integers)

18 + 9f - 4f (9f and 4f are like-terms because they have the same variable f)

18 + 5f

The consumers' surplus at a price level of $1 for the price-demand equation is -1072.5.

Given that price-demand equation p= D(x) = 20-0.1x, we need to find the consumers' surplus at a price level of $1.

So,

From the equation we have,

20-0.1x = 1

0.1x = 19

x = 190

Therefore, the equilibrium point = (190, 1) = (xe, Pe)

Now,

Cs = [tex]\int\limits^{x_e}_0 {D(x)} \ dx\, -Pexe[/tex]

[tex]\int\limits^{190}_0 {20-0.1x} \ dx\, -(190)[/tex]

= 20-0.1{9025}-190

= -1072.5

Hence the consumers' surplus at a price level of $1 for the price-demand equation is -1072.5

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The number of ways to pick 3 astronauts from 10 candidates can be found using the combination formula, which is:

nCk = n! / (k!(n-k)!)

where n is the total number of candidates, k is the number of candidates to be chosen, and "!" denotes the factorial function.

In this case, we want to choose 3 astronauts from a pool of 10 candidates, so we can plug these values into the formula:

10C3 = 10! / (3!(10-3)!)

= (10 x 9 x 8) / (3 x 2 x 1)

= 120

Therefore, there are 120 ways to pick 3 astronauts to go to the moon out of 10 candidates.

Answer:

120 or 220

Step-by-step explanation:

a. the standard deviation is approximately 25.01 and the variance is approximately 625.21.

b.the five-number summary for the data is: 30, 57, 71, 81, 98.

The standard deviation is a measurement of how widely apart a group of data points are from the mean (average) value. You can see how far each data point deviates from the mean value. When the standard deviation is minimal, the data points are densely packed around the mean; when it is great, the data points are more widely spaced from the mean. The standard deviation is a statistical concept that is frequently used to compare the degree of variability across various data sets as well as to infer and make conclusions about a population from a sample.

a. To find the standard deviation and variance for the given data, we can use the following formulas:

Variance: σ² = ∑(x - μ)² / n

Standard deviation: σ = sqrt(σ²)

where x is the data point, μ is the mean of the data, and n is the sample size.

First, we need to find the mean of the data:

μ = (30 + 35 + 43 + 44 + 47 + 48 + 54 + 55 + 56 + 57 + 59 + 62 + 63 + 65 + 66 + 68 + 69 + 69 + 71 + 72 + 72 + 73 + 74 + 76 + 77 + 77 + 78 + 79 + 80 + 81 + 81 + 82 + 83 + 85 + 89 + 92 + 93 + 94 + 97 + 98) / 40

μ = 69.3

Now, we can use the variance formula:

σ² = ∑(x - μ)² / n

σ² = [(30 - 69.3)² + (35 - 69.3)² + ... + (98 - 69.3)²] / 40

σ² = 625.21

Finally, we can find the standard deviation:

σ = sqrt(σ²)

σ = sqrt(625.21)

σ ≈ 25.01

Therefore, the standard deviation is approximately 25.01 and the variance is approximately 625.21.

b. To find the five-number summary, we need to find the minimum, maximum, median, and quartiles (Q1 and Q3) of the data:

Minimum: 30

Q1: 57

Median: 71

Q3: 81

Maximum: 98

Therefore, the five-number summary for the data is: 30, 57, 71, 81, 98.

c. To construct a boxplot for the given data, we can use the five-number summary:

Draw a number line and mark the minimum, Q1, median, Q3, and maximum.

Draw a box from Q1 to Q3.

Draw a vertical line inside the box at the median.

Draw whiskers from the ends of the box to the minimum and maximum, or to the nearest data point within 1.5 times the interquartile range (IQR).

Mark any outliers outside the whiskers.

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The area of the tabletop made by the students in the furniture - making class would be 26 ft ²

We can see that this tabletop made by students in the furniture - making class takes the form of a composite shape with two smaller rectangles and one large rectangle.

The area of the large rectangle is:

= 4 ft x ( 1 + 3 + 1 )

= 4 ft x 5 ft

= 20 ft ²

The area of the two smaller rectangles is:

= 2 x ( 3 ft x 1 ft )

= 2 x 3

= 6 ft ²

The total area of the tabletop is:

= 20 + 6

= 26 ft ²

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Answer:

The answer is **D. 30x+15y**.

```

5(6x + 3y) = 5*6x + 5*3y = 30x + 15y

```

Step-by-step explanation:

1. Distribute the 5:

```

5(6x + 3y) = (5 * 6x) + (5 * 3y)

```

2. Simplify:

```

5(6x + 3y) = 30x + 15y

```

Therefore, 5(6x + 3y) is equivalent to 30x + 15y.

the probability that the marble is not green is 0.9 or 90%. This means that if we were to randomly select a marble from the box, there is a 90% chance that it will not be green.

How to solve probability?

To calculate the probability that a marble is not green, we need to first determine the total number of marbles in the box, which is given by:

Total number of marbles = 8 + 6 + 2 + 4 = 20

Next, we need to determine the number of marbles that are not green. Since there are 2 green marbles, the number of marbles that are not green is given by:

Number of marbles that are not green = 20 - 2 = 18

Finally, we can calculate the probability of selecting a marble that is not green by dividing the number of marbles that are not green by the total number of marbles in the box, as follows:

Probability of selecting a marble that is not green = Number of marbles that are not green / Total number of marbles

= 18 / 20

= 0.9 or 90%

Therefore, the probability that the marble is not green is 0.9 or 90%. This means that if we were to randomly select a marble from the box, there is a 90% chance that it will not be green.

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Answer:

30 and 10

Step-by-step explanation:

Main concepts:

Concept 1.  Geometric Sequence

Concept 2. Common ratio

Concept 3. Finding the next terms

Concept 1.  Geometric Sequence

Geometric sequences are a specific type of sequence with a pattern where a specific number is multiplied to each term to get the next term.

For instance, a completely different geometric sequence 1,2,4,8,16,... is geometric because you multiply any term by 2 to get the next term.

Concept 2. Common ratio

In a geometric sequence, this number that you can multiply by to get the next term (in the "1,2,4,8,16,..." example, the number 2) is called the common ratio because taking the ratio of two sequential terms of the sequence (dividing two terms in a row) always gives the same answer:

This process of finding ratios will yield a common ratio only if the sequence is a Geometric Sequence.

Concept 3. Finding the next terms

Since we're told that the sequence we're given in the question is a Geometric sequence, it must have a common ratio (otherwise, it wouldn't be a geometric sequence).

Find the common ratio by dividing sequential terms:

270/810 = 1/3

90/270 = 1/3

So, for the sequence in the question, the common ratio is 1/3.  Each term is multiplied by 1/3 to get the next term in the sequence.  (This is equivalent to dividing each term by 3 to get the next term in the sequence, if you prefer division and/or to avoid fractions)

So, to get the next two terms in the sequence, multiply by the common ratio:

90 * 1/3 = 30

30 * 1/3 = 10

So, the next two terms of the sequence are 30 and 10

Answer:

A and D

Step-by-step explanation:

A- when multiplying -5 and -3 it should be positive 15.

D- when dividing 3 they just outta nowhere forgot about the negative, it should've been -5

An inequality to show the number of people  is  p ≥ 12

Let p be the number of people on the bus. We know that there are at least 12 people on the bus, so we can write:

p ≥ 12

This inequality means that the number of people on the bus, p, must be greater than or equal to 12.

To graph this inequality, we can draw a horizontal line at y = 12 on the y-axis, and shade the area above the line, since any value of p that is greater than or equal to 12 satisfies the inequality.

Here's a graph of the inequality attached

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Answer:

c + 3.6 + 3.4 + 4.1 + 2.3 = 18.6

c + 13.4 = 18.6

c = 5.2

$5.2 trillion was spent on consumption.

Answer:

A multi-step-word problem is like a puzzle with lots of pieces. Multi-step word problems are math problems that have more than one operation. An operation is addition, subtraction, multiplication, or division. Multi-step word problems can have any combination of these operations

Both equations give the correct terms, so we can conclude that the pattern rule is:  [tex]an^2 - 131n + 80[/tex] , where [tex]a=63[/tex]  .

To find the pattern rule for the given sequence 12, 59, 294, 1469, 7344, we need to observe the differences between consecutive terms. Let's find the differences between each pair of terms:

[tex]59 - 12 = 47[/tex]

[tex]294 - 59 = 235[/tex]

[tex]1469 - 294 = 1175[/tex]

[tex]7344 - 1469 = 5875[/tex]

The differences are not constant, so we need to find the differences between these differences:

[tex]235 - 47 = 188[/tex]

[tex]1175 - 235 = 940[/tex]

[tex]5875 - 1175 = 4700[/tex]

Now, the second differences are constant (equal to 940), which suggests that the pattern rule is a quadratic equation. Let's assume the pattern rule is of the form:

[tex]an^2 + bn + c[/tex]

where n is the term number (starting with n=1 for the first term).

To find the coefficients a, b, and c, we can use the first three terms of the sequence. Let's substitute n=1,2,3 into the equation and equate it to the corresponding terms:

[tex]a + b + c = 12 (for n=1)[/tex]

[tex]4a + 2b + c = 59 (for n=2)[/tex]

[tex]9a + 3b + c = 294 (for n=3)[/tex]

We can solve these equations simultaneously to get the values of a, b, and c:

[tex]a = 63[/tex]

[tex]b = -131[/tex]

[tex]c = 80[/tex]

Therefore, the pattern rule for the sequence is:

[tex]an^2 - 131n + 80[/tex]

where a=63.

To check if this pattern rule works for the other terms of the sequence, we can substitute n=4 and n=5:

[tex]a(4^2) - 131(4) + 80 = 1469[/tex]

[tex]a(5^2) - 131(5) + 80 = 7344[/tex]

Therefore, Both equations give the correct terms, so we can conclude that the pattern rule is:

[tex]an^2 - 131n + 80, where a=63.[/tex]

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Mine-craft Incorrect Responses is known to be a sort of game or challenge where members are inquired to reply to Mine-craft-related questions or explanations with intentioned inaccurate answers.

The thought is to utilize humor and creativity  to come up with reactions that are totally off-base but still somehow related to Mine-craft.

Mine-craft  Incorrect Responses is an amusing way of reacting to questions or statements related to the prevalent sandbox video diversion Mine-craft with intentioned off base answers. The objective is to be as imaginative and amusing as conceivable whereas intentionally giving off-base answers to Mine-craft-related questions or comments.

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Julieta's claim about the quadrilateral is false.

The statement is given as:

It is impossible to draw a quadrilateral that is not a trapezoid and not a parallelogram.

The condition for a shape to be a quadrilateral is that the shape must have four sides.

An irregular shape that has four sides is a quadrilateral, but neither a quadrilateral nor a parallelogram

Therefore, Julieta's claim is false

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In light of this, the 95% confidence interval for is (100.67, 111.33) as s is the sample standard deviation, n is the sample size.

A collection of information's values' standard deviation serves as a gauge for how much variance or dispersion there is. It is a statistical word used to describe the degree to which the individual data points depart as from mean or average value that is contained in the data set. By taking taking square root of the variance—the sum of the squared deviations amongst each point in the data and the mean—we can determine the standard deviation. While a high standard deviation suggests that the data points are widely dispersed, a modest standard deviation suggests that the statistics are close to the mean.

given

(a) When the sample size, n, is 16, we can apply the following formula to create a 95% confidence interval regarding the population mean, :

x ± tα/2 * (s/√n)

where t/2 is the crucial value from the t-distribution with n-1 degrees of freedom and a confidence level of 95%, and x is the sample mean, s is the sample standard deviation, n is the sample size.

We determine that t0.025,15 = 2.131 using a t-distribution table or calculator.

When we enter the values, we obtain:

106 ± 2.131 * (10/√16)

which is equivalent to:

106 ± 5.33

In light of this, the 95% confidence interval for is (100.67, 111.33) as s is the sample standard deviation, n is the sample size.

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Answer: The overall score obtained is 55.5, which is higher than the passing mark of 45. Therefore, the applicant will be accepted.

Step-by-step explanation:To determine if the applicant will be accepted, we need to calculate their overall score based on the percentage weights and passing mark given for each subject.

The overall score can be calculated as follows:

Overall score = (0.25 x English score) + (0.3 x Math score) + (0.25 x Computer score) + (0.2 x Accounting score)

Substituting the given scores, we get:

Overall score = (0.25 x 60) + (0.3 x 35) + (0.25 x 80) + (0.2 x 50)

= 15 + 10.5 + 20 + 10

= 55.5

a) If two similar solids have a scale factor of 2 : 5, the ratio of their volumes is 8:125, expressed in the lowest terms.

b) If cone with volume 2625 m³ is dilated by a scale factor of 15, the volume of the resulting cone is 10,640,625 m³.

(a) When two solids are similar, their corresponding linear dimensions are in the same ratio, which is known as the scale factor. For example, if two similar solids have a scale factor of 2:5, it means that the corresponding sides of the two solids are in the ratio 2:5.

The volume of a solid is proportional to the cube of its linear dimensions. Therefore, if the linear dimensions of two similar solids are in the ratio 2:5, the ratio of their volumes would be:

(2/5)³ = 8/125

(b) The volume of a cone is given by the formula:

V = (1/3)πr²h

where V is the volume, r is the radius, and h is the height of the cone.

When a cone is dilated by a scale factor of k, its linear dimensions increase by a factor of k, and its volume increases by a factor of k³. Therefore, if the volume of a cone is V and it is dilated by a scale factor of k, the volume of the resulting cone would be:

V' = k³V

In this case, the volume of the original cone is given as 2625 m³, and it is dilated by a scale factor of 15. Substituting these values in the formula, we get:

V' = 15³(2625)

V' = 15³(2625/1)

V' = 10640625

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The calculated value of the probability that the experiment results in exactly 1 success is 0.08719

From the question, we have the following parameters that can be used in our computation:

n = 7

x = 1

p = 0.45

The probability is then calculated as

P(x = x) = nCr * p^x * (1 - p)^(n - x)

Substitute the known values in the above equation, so, we have the following representation

P(x = 1) = 7C1 * (0.45)^1 * (1 - 0.45)^(7-1)

Evaluate the expression

So, we have

P(x = 1) = 0.08719

Hence, the probability is 0.08719

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The age of the 7th volunteer has to be 602 years so that the range of the all volunteer ages will be 557.

Given ages of 6 volunteers = (56, 81, 54, 47, 45, 94)

The range = maximum value - minimum value.

So, range of the given list = 94 - 45 = 49.

To increase, the range to 557, we have to add an age that is greater than 94, To obtain that age we have to solve 557 - 45 = 508. [here 557 is the maximum value]

Now, by adding the obtained range to the 94 we can get the required age of 7th volunteer. So 508 + 94 = 602.

From the above explanation, we can conclude that the age of the 7th volunteer has to be 602 years which is unrealistic so that the range becomes 557.

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a) The  piecewise function is 80p, if p > 100 b) For p > 100, the graph will be a straight line passing through the point (100, 100 × 80) with a slope of 8

a) We can define a piecewise function f(p) to represent the cost of catering service depending on the number of persons (pax).

f(p) =

120p, if p ≤ 30

105p, if 31 ≤ p ≤ 60

95p, if 61 ≤ p ≤ 100

80p, if p > 100

b) To graph the piecewise function, we can plot the points for each of the four parts of the function, and connect them with line segments. The graph will have four segments, each with a different slope.

For p ≤ 30, the graph will be a straight line passing through the origin with a slope of 120.

For 31 ≤ p ≤ 60, the graph will be a straight line passing through the point (31, 31 × 105) with a slope of 105.

For 61 ≤ p ≤ 100, the graph will be a straight line passing through the point (61, 61 × 95) with a slope of 95.

For p > 100, the graph will be a straight line passing through the point (100, 100 × 80) with a slope of 80.

c) To find how many persons they invite to their wedding, we can use the inverse function of f(p) and plug in the given cost of RM9025.

Let C = RM9025, then

120p, if p ≤ 30

105p, if 31 ≤ p ≤ 60

95p, if 61 ≤ p ≤ 100

80p, if p > 100

Case 1: p ≤ 30

120p = C

p = C/120 = 9025/120 = 75.2083

Since p must be an integer, we round up to the nearest integer. Therefore, if they invite 76 persons, the cost of catering service will be more than RM9025.

Case 2: 31 ≤ p ≤ 60

Let x = p - 30, then

105x + 120 × 30 = C

105x = C - 3600

x = (C - 3600)/105 = (9025 - 3600)/105 = 54.5238

Therefore, if they invite 31 + 54 = 85 persons, the cost of catering service will be RM9025.

Case 3: 61 ≤ p ≤ 100

Let x = p - 60, then

95x + 120 × 30 + 105 × 30 = C

95x = C - 9750

x = (C - 9750)/95 = (9025 - 9750)/95 = 0.7632

Therefore, if they invite 60 + 0.7632 × 100 = 137 persons, the cost of catering service will be RM9025.

Case 4: p > 100

Let x = p - 100, then

80x + 120 × 30 + 105 × 30 + 95 × 40 = C

80x = C - 17700

x = (C - 17700)/80 = (9025 - 17700)/80 = -109.375

Since p must be a positive integer, this case is not possible.

Therefore, Mohammed and Mira should invite 85 persons to their wedding to pay RM9025 for the catering service.

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