How long does it take light from a camera to travel to the face of someone standing 7 meters away?

Answers

Answer 1

The time taken for the light to travel from the camera to someone standing 7 m away is 2.33×10¯⁸ s

Speed is simply defined as the distance travelled per unit time. Mathematically, it is expressed as:

Speed = distance / time

With the above formula, we can obtain the time taken for the light to travel from the camera to someone standing 7 m away. This can be obtained as follow:

Distance = 7 m

Speed of light = 3×10⁸ m/s

Time =?

Time = Distance / speed

Time = 7 / 3×10⁸

Time = 2.33×10¯⁸ s

Therefore, the time taken for the light to travel from the camera to someone standing 7 m away is 2.33×10¯⁸ s

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Related Questions

Which of the following statements about electromagnetic radiation it true? A.electromagnetic waves with long wavelength are more energetic then electromagnetic waves with short wavelength. B.all electromagnetic radiation carries the same amount of energy. C.electromagnetic radiation in a vacuum can change frequently to become more or less energetic. D.electromagnetic waves with high frequency are more energetic then electromagnetic waves with low frequency

Answers

Given what we know, we can confirm that option D,  Electromagnetic waves with high frequency are more energetic than electromagnetic waves with low frequency is true.

Why are high-frequency waves more energetic?

High-frequency waves are synonymous with short wavelengths. This means that the waves are oscillating much quicker and therefore carry more kinetic energy within them. This is transformed and released as electromagnetic radiation, which is the reason why high-frequency waves are more energetic than low-frequency electromagnetic waves.

Therefore, we can confirm that the statement "Electromagnetic waves with high frequency are more energetic than electromagnetic waves with low frequency" is true.

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Suppose that scientists observe violent gas eruptions on a planet with an acceleration due to gravity of 3.8 m/s2. The jets throw sand and dust about 75 m above the surface.

What is the speed i of the material just as it leaves the surface?
Scientists estimate that the jets originate as high‑pressure gas speeds through vents just below ground at about 160 km/h. How much energy per kilogram of material does the jet lose to non conservative forces as the high‑speed matter forces its way to the surface and into the air?

Answers

Answer:

linarkuoouonpnpjjñihy

Explanation:

SEND HELP :<<

A meteor falls from the sky to the Earth. The meteor already had an initial velocity downward when it was spotted. If it hit the Earth at 335 m/s after being seen for 30 seconds, then what was the initial velocity of the meteor?

Answers

Answer:

335 - 30 g

Explanation:

V = Vo + g*T = 335

Vo + 9.8*30 = 335

Vo =

If you traveled 50m/s for 60 seconds, how far did you travel? Remember speed=distance/time


Question options:


300 m/s



500 m/s



3,000 m/s



300 km/h

Answers

Answer:

3,000 m

Explanation:

speed = distance/time

distance = speed * time

= 50 * 60

= 3000 m

Starting from rest, a student pulls a (25.0 A) kg box a distance of (4.50 B) m across the floor using a (134 C) N force applied at 35.0 degrees above horizontal. The coefficient of kinetic friction is 0.220 between the floor and the box. Find the work done by the pulling force. Give your answer in joules (J) and with 2 significant figures.

Answers

A 25.0 kg box is moved 4.50 m by a force of 134 N applied at 35.0° above horizontal. The work done by the pulling force is 4.9 × 10² J.

Starting from rest, a student pulls a 25.0 kg box a distance of 4.50 m across the floor using a 134 N force applied at 35.0 degrees above horizontal.

We can calculate the work  (W) done by the pulling force using the following expression.

[tex]W = F \times d \times cos\theta = 134 N \times 4.50 m \times cos35.0\° = 4.9 \times 10^{2} J[/tex]

where,

F: puling forced: displacementθ: angle between F and d

The friction between the floor and the box. does not influence the work done by the pulling force.

A 25.0 kg box is moved 4.50 m by a force of 134 N applied at 35.0° above horizontal. The work done by the pulling force is 4.9 × 10² J.

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What happens to the size of an Object when it is heated ?​

Answers

Answer:

the object melts so the size get smaller

what is 4 differences between saturated unsaturated and supersaturated solutions

Answers

Answer:

Unsaturated Solution: Less amount of salt in water, clear solution, no precipitation. Saturated Solution: The maximum amount of salt is dissolved in water, Colour of the solution slightly changes, but no precipitation. Supersaturated Solution: More salt is dissolved in water, Cloudy solution, precipitation is visible.

1.protozoo ore ?
A. multicellular organisms B. one - Celled animals
C. amembers of the group Protocista
D. unicellulor Plants​

Answers

Answer:

c

Explanation:

amembers of the group protocista

A boy 11.0 m above the ground in a tree throws a ball for his dog, who is standing right below the tree and starts running the instant the ball is thrown. If the boy throws the ball upward at 50.0 ∘ above the horizontal, at 8.00 m/s .
How fast must the dog run to catch the ball just as it reaches the ground?
How far from the tree will the dog catch the ball?

Answers

12414253

Explanation:

Light of 650 nm wavelength illuminates two slits that are 0.20 mm
apart. (Figure 1) shows the intensity pattern seen on a screen behind the slits.
What is the distance to the screen?

PLEAsE URGENT. thank you

Answers

We have that for the Question "Light of 650 nm wavelength illuminates two slits that are 0.20 mm  apart. (Figure 1) shows the intensity pattern seen on a screen behind the slits.

What is the distance to the screen?" it can be said that  the distance to the screen

d=1.168m

From the question we are told

Light of 650 nm wavelength illuminates two slits that are 0.20 mm

apart. (Figure 1) shows the intensity pattern seen on a screen behind the slits.

What is the distance to the screen?

Generally the equation for the distance  is mathematically given as

[tex]d=\frac{0.33*10^{-2}*0.23*10^{-3}}{650*10^{-9}}\\\\d=1.160m[/tex]

d=1.168m

Therefore

The distance to the screen

d=1.168m

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In these images taken a few days apart, the light part of the Moon appeared to get smaller
over time. Why did this happen? (1)

a) The Moon moved farther away from the sun so less sunlight reached the Moon's
surface.

b) Earth moved so its shadow was blocking more of the Moon so the student astronomer
was able to see less of it.

c) The Moon rotated so that less of the light-colored rock on the Moon's surface faced
Earth

d) The Moon moved so that the student astronomer was able to see less of the half that
facer the sun

Answers

Answer:

Explanation:

d) The Moon moved so that the student astronomer was able to see less of the half that faced the sun.

A trouble-making youth is standing on a bridge, and wants to drop a water balloon on an unsuspecting passerby. A man is jogging on a path below the bridge with a constant speed of 4.2 m/s. The bridge is 11.6 m above the ground. If the balloon is to land right at the jogger's feet, at what horizontal distance x from the bridge should he be when the youth drops the balloon?

Answers

Answer:

Explanation:

Time needed for a balloon to drop from vertical rest a distance of 11.6 m

t = √(2h/g) = √(2(11.6)/9.8) = 1.538618

d = vt = 4.2(1.538618) = 6.462197...

d = 6.5 m

Horizontal distance x = 6.5 m from the bridge he should be when the youth drops the balloon with velocity 4.2 m/s.

What is velocity?

When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time.

Uniform motion an object is said to have uniform motion when object cover equal distance in equal interval of time within exact fixed direction. For a body in uniform motion, the magnitude of its velocity remains constant over time.

Given in the question time needed for a balloon to drop from vertical rest a distance of 11.6 m

t = √(2h/g) = √(2(11.6)/9.8) = 1.538618

d = vt = 4.2(1.538618) = 6.462197...

d = 6.5 m

Horizontal distance x = 6.5 m from the bridge he should  be when the youth drops the balloon with velocity 4.2 m/s.

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2. A 6.0 kg mass is pulled along a horizontal surface where the coefficient of friction is 0.20.
a) What is the friction force acting on the mass?
b) What force is needed to accelerate it at 0.68 m/s^(2)?

Answers

Answer:

Below

Explanation:

a) To find the force of friction acting on the mass we can use this formula :

     friction = coefficientoffriction x normal force

First we need to find the normal force of this object :

     Fn = mg

          = (6.0)(9.8)

          = 58.8 N

Now we can find the force of friction acting on the object :

     friction = (0.20)(58.8N)

                 = 11.76 N

                 = 12 N (we round this to 2 sig figs)

b) To find the force needed to accelerate this object at 0.68 m/s^2 use this :

     F = ma

     0.68 = x - 11.76 / 6

     x = 15.84

     x = 16 N

Hope this helps! Best of luck <3

Incisors (front teeth) act as wedges in the human body. Which change would increase the mechanical advantage of incisors?
1 a decrease in the distance of the teeth from the fulcrum,
2 an increase in the distance of the teeth from the fulcrum,
3 an increase in the thickness at the widest part of the teeth and no change in the length of the teeth,
4 an increase in the length of the teeth and no change in the thickness at the widest part of the teeth

Answers

To increase the mechanical advantage of incisors (front teeth) so that they act as wedges in the human body is through 2. an increase in the distance of the teeth from the fulcrum.

 

The decrease in the distance will decrease the mechanical advantage of incisors. The increase in the thickness at the widest part of the teeth will not necessarily support the incisors to become more effective wedges.  

 

Thus, incisors will acquire some mechanical advantage by increasing the force that it exerts. This advantage can be achieved by increasing the distance of incisors from the fulcrum.

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Answer:

4 aka D

Explanation:

What shape is the graph produced by a force vs acceleration graph?

A. Linear
B. Quadratic
C. Circular
D. Triangular

Answers

The answer to the question What shape is the graph produced by a force vs acceleration graph is A. Linear

Since Force, F = ma where m = mass and a = acceleration. For constant mass, F ∝ a. That is, F is directly proportional to acceleration, a.

Since this is a linear relationship, the graph of force vs acceleration will be linear.

The answer to the question What shape is the graph produced by a force vs acceleration graph is A. Linear

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The term that is used to quantity the amount of heat in the evaporator is

Answers

Answer:

Enthalpy

The quantity of heat contained in a material as measured from a particular base or point.

can anyone heelp me pls pls

Answers

Answer:

Explanation:

Answer in the pic.. hope it helps

A string is wrapped around a solid cylinder with mass M and radius R. The free end of the string is held in place, allowing the cylinder to fall. Recall that the moment of inertia of a solid cylinder rotated about its center is given by MR2/2. All answers to this problem should be symbolic, purely in terms of the variables M, R, and g. (a) Find the linear acceleration (in m/s2) of the cylinder and the tension in the string (in Newtons) as the cylinder falls. (b) Now suppose the cylinder is hollow instead of solid. The moment of inertia of a hollow cylinder rotated about its center is given by MR2. What is the acceleration and tension in this case?

Answers

Answer:

I will use (a / R) for alpha the angular acceleration

T R = I a / R     torque equals angular acceleration for cylinder

M g - T = M a    linear acceleration of center of mass

T = M (g - a) = I a / R^2 from first equation

If I = 1/2 M R^2 then M ( g - a) = M a / 2    from above

or g = 3 a / 2  and a = 2 g / 3

Also we have T = M (g - a) = M (g - 2 g / 3) = g / 3

Substitute I = M R^2 for the hollow cylinder

Looks like a = g/2 for hollow cylinder

Heat rash is caused by chemical exposure Truth or false

Answers

Answer:

This is false.

Explanation:

Heat rash develops when some of your sweat ducts clog. Instead of evaporating, perspiration gets trapped beneath the skin, causing inflammation and rash. Heat rash is usually self-limited, meaning it resolves on its own without treatment. Over-the-counter treatments such as calamine, hydrocortisone cream, itch preparations (such as Benadryl spray), or sunburn lotions can be used as skincare to treat the itching and burning symptoms. Heat rash usually goes away on its own within three or four days so long as you don't irritate the site further. Heat rash happens when the sweat glands get blocked. The trapped sweat irritates the skin and leads to small bumps.

Answer:

FALSE

Explanation:

Heat rash develops when blocked pores or sweat ducts trap perspiration under your skin. Symptoms range from superficial blisters to deep, red lumps. Some forms of heat rash feel tingly  or intensely itchy.

The seat on a carnival ride is fixed on the end of an 12.60-m-long beam, pivoted at the other end. If the beam sweeps through an angle of 141°, what is the distance through which the rider moves?

Answers

The distance through which the rider at the end of the beam moves is;

L = 15.5 m

We are told that the beam on which the carnival ride is fixed is 12.6m in length.

Since the seat is at the end of the beam with the other end pivoted and the beam sweeps through an angle of 141°, then we can say that the radius of this arc formed by the swing is;

Radius; r = 12.6 m

Also, θ = 141°

The distance through which the driver moves will be the length of the arc formed by the beam at angle of 141°.

Formula for length of arc is given as;

L = 2πr(θ/360)

Plugging in the relevant values gives;

L = 2π × 12.6 × 141/360

L = 15.5 m

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Which is the largest number? O A. 9.9 x 106 O B. 4.5 x 107 O c. 5.5 x 105 O D. 5.8 x 108​

Answers

Answer:

107

Explanation:

It's the biggest number

The box is pushed to the left with 30 N of force, but does not move. What is the Friction Force?​

Answers

However here coefficient of friction is not given so unable to calculate.

You can calculate it by below formula.

The formula given by

[tex]\\ \sf\longmapsto F_f=\mu N[/tex]

Or

[tex]\\ \sf\longmapsto F_f=\mu mg[/tex]

u is coefficient of friction

N is normal reaction.

Here..

box doesn't move means the force if limiting friction is greater than applied force.

Which phrase describes an irregular galaxy O has a round shape O does not have a specific shape O has arms that extend from the center O is larger than other types of galaxies​

Answers

Answer:

I think it does not have a specific shape

Explanation:

Irregular galaxies have no definite shape, which means that the second option is correct. They are definitely not round.

The "spiral galaxy" is the type of galaxy that has arms that extend from the center. These arms look "spiral," which influenced its name.  

They are actually smaller than the other types of galaxies. This makes them prone to collisions.  

The phrase that describes the irregular galaxy is that it does not have a specific shape. The correct option is B.

What is irregular galaxy?

A galaxy with an undefined shape is an irregular galaxy with a large number of young stars and a large amount of gas and dust that is typically found near larger galaxies.

An irregular galaxy is a catch-all term for any galaxy that does not neatly fit into one of the Hubble classification schemes.

They have no discernible shape or structure and could have formed as a result of collisions, close encounters with other galaxies, or violent internal activity.

They lack beautiful spiral arms, but they do have dark patches of gas and dust. Some irregular galaxies appear to be the result of two galaxies colliding.

Thus, the correct option is B.

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HELP
A 3000-kg truck moving with a velocity of 10 m/s hits a 1000-kg parked car. The impact causes the 1000-kg car to be set in motion at 15 m/s . Assuming that momentum is conserved during the collision, determine the velocity of the truck immediately after the collision.

Answers

Answer:

Hey I go to GOC send me your number

Explanation:

Ex 3) A tennis player lobs the tennis ball up in the air during a serve at a rate 3 m/s.
How long will it take the tennis ball to reach its maximum height?

Answers

Explanation:

s=(v^2-u^2)/2g

=(0-3^2)/2*10

= 0.45m

How can I create a whirlpool of water?​

Answers

Answer:

To make a small scale whirlpool of water, take a cup and fill it with water and stir. It will create a vortex that pulls particles down.

Or you could see this when draining a tub of water.

Water which contains large amounts of calcium dissolved within it results from
a) factory sewage outfalls.
b) water dissolving materials in the ground.
c) volcanic activity.
d) increase in number of wells in area.

Answers

Answer: B

Explanation:

The other options have nothing to do with the water apart from transporting it.

A closed, uninsulated system fitted with movable piston, so no matter is exchanged with the surroundings, was assembled. Introduction of 430 J of heat caused the system to expand, doing 238 J of work against a constant pressure of 101 kPa. What is the value of for this process

Answers

Answer: You do not specify what is being asked for. ∆E? ∆H?

∆E = (430 - 238) J = 192 J

∆H = 430 J

Explanation:

If asked for the value of ∆H the answer is simply the change in heat, and in the question, it states introduction of 430 J of heat is causing the system to expand.

Therefore ∆H = 430 J

If asked for ∆E, we know that ∆E = ±q (heat) + work (-P∆V) = ±q + w

The question states that 238 J of work are done AND the system expanded

(work is negative because expansion means work is done BY the system, releasing energy/heat... Conversely, if the system were compressed, work is done ON the system, absorbing heat/energy)

Therefore, ∆E = (430 - 238) J = 192 J

Please show your workmkmmkekdmnesnndndndndn

Answers

Answer:

Explanation:

Remark

The question really is how long does the projectile stay in the air if it was just dropped from a height of 46 meters.

Givens

vi = 0

a = 9.81 m/s^2

h = 46 m

t = ?

Solution

d = vi*t + 1/2 a t^2

46 = 0 + 1/2 * 9.81 * t^2       multiply both sides by 2

92 = 9.81 * t^2                     divide by 9.81

t^2 = 9.38                            Take the square root of both sides

sqrt(t^2) = sqrt(9.38)

t = 3.06 seconds.

In 3.06 seconds the object will hit the ground, thus stopping it. How far horizontally does it go in that time.

d = r * t

d=?

r = 102 m/s

t = 3.06 seconds

d = 102 * 3.06

d = 312.4  meters.

The figure shows a jet engine suspended beneath the wing of an airplane. The weight of the engine is 14900 N and acts as shown in the figure. In flight the engine produces a thrust of 61500 N that is parallel to the ground. The rotational axis in the figure is perpendicular to the plane of the paper. With respect to this axis, find the magnitude of the torque due to (a) the weight and (b) the thrust.

Answers

We have that for the Question, it can be said that With respect to this axis, the magnitude of the torque due to the weight and ,the thrust is

TW=19740N-mTT=130387.39N-m

From the question we are told

The figure shows a jet engine suspended beneath the wing of an airplane. The weight of the engine is 14900 N and acts as shown in the figure. In flight the engine produces a thrust of 61500 N that is parallel to the ground. The rotational axis in the figure is perpendicular to the plane of the paper. With respect to this axis, find the magnitude of the torque due to (a) the weight and (b) the thrust.

a)

Generally the equation for the Torque due to weight  is mathematically given as

[tex]TW=Engine weight*2.50*sin32\\\\TW=14900*2.50*sin32[/tex]

TW=19740N-m

b)

Generally the equation for the Torque due to thrust  is mathematically given as

[tex]TT=Engine thrust*2.50*cos32\\\\TT=61500*2.50*cos32\\\\[/tex]

TT=130387.39N-m

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