There are approximately 223.2 grams of oxygen in 615 grams of N2O.
To find the number of grams of O in 615g of N2O, we first need to understand the chemical formula of N2O. N2O is a compound made up of two nitrogen atoms (N) and one oxygen atom (O). Therefore, the molecular weight of N2O would be:
(2 x atomic weight of N) + (1 x atomic weight of O)
= (2 x 14.01 g/mol) + (1 x 16.00 g/mol)
= 44.01 g/mol
Now, to calculate the number of grams of O in 615g of N2O, we need to know the proportion of O in the compound. Since there is only one oxygen atom in each molecule of N2O, we can find the proportion of O by dividing the atomic weight of O by the molecular weight of N2O:
Atomic weight of O / Molecular weight of N2O
= 16.00 g/mol / 44.01 g/mol
= 0.363
This means that oxygen makes up 36.3% of the total weight of N2O. To find the number of grams of O in 615g of N2O, we can multiply the total weight by the proportion of O:
615g x 0.363
= 223.2g
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Chemistry..... Reaction Rate
W → U + S Chemistry Reaction Rate use the table to find reaction rate
See reaction Rate Table Picture
The reaction rates for trial 1 is 8.22 x 10⁻² M⁻² s⁻¹ and 1.10 M⁻² s⁻¹ for trail 2 and 3
How to find reaction rate?Keep the concentration of W constant while varying the concentrations of U and S while measuring the reaction rate in order to determine the reaction rate with regard to U and S.
Select trial 1 as the reference trial and calculate the reaction's rate constant (k) with respect to U and S, assuming that the concentration of W is constant throughout all three trials.
For trial 1:
[W] = 0.13 M
Rate = 4.72 x 10⁻⁴ M/s
For trial 2:
[W] = 0.13 M
Rate = 1.18 x 10⁻² M/s
From the equation rate = k[U][S], set up the following ratio of rates:
Rate2/Rate1 = (k[U]2[S]2)/(k[U]1[S]1)
Simplifying:
k = (Rate2/Rate1) x (1/[U]2) x (1/[S]2) x ([U]1) x ([S]1)
Substituting the values from trials 1 and 2:
k = (1.18 x 10⁻² M/s) / (4.72 x 10⁻⁴ M/s) x (1/0.65 M) x (1/1 M) x (0.13 M) x (1 M)
k = 8.22 x 10⁻²M⁻² s⁻¹
Similarly, for trial 3:
[W] = 0.13 M
Rate = 2.95 x 10⁻¹ M/s
Again, using trial 1 as the reference trial, figure out the reaction's rate constant (k) in relation to U and S:
k = (Rate3/Rate1) x (1/[U]3) x (1/[S]3) x ([U]1) x ([S]1)
k = (2.95 x 10⁻¹ M/s) / (4.72 x 10⁻⁴ M/s) x (1/3.25 M) x (1/1 M) x (0.13 M) x (1 M)
k = 1.10 M⁻² s⁻¹
Therefore, the equation states the reaction rate in relation to U and S is k = 8.22 x 10⁻² M⁻² s⁻¹ and 1.10 M⁻² s⁻¹ for trials 2 and 3, respectively.
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The Environmental Protection Agency was assigned which task? A. setting standards and governing the cleanliness of water used by Americans B. setting standards and governing the highways and interstates in the United States C. setting standards and governing the use of national parks and monuments in the United States. D. setting standards and governing the civil and commercial air transportation throughout America
Answer:
A. setting standards and governing the cleanliness of water used by Americans
Explanation:
The responsibilities of the Environmental Protection Agency (EPA) is to make sure that:
People in America should have clean air, water, and good quality soil so that land is fertile.Using Scientific information to come up with efforts on a national level and reduce risks to the environment.A fair and effective administration of federal laws centered around the protection of human health and our environment.Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl(aq)
, as described by the chemical equation
MnO2(s)+4HCl(aq)⟶MnCl2(aq)+2H2O(l)+Cl2(g)
How much MnO2(s)
should be added to excess HCl(aq)
to obtain 105 mL Cl2(g)
at 25 °C and 765 Torr
?
What two statements are true about a system?A) systems are a group of objects analyzed as one unit? B) energy that moves across a system boundaries is covered? C) only one way to define the boundary of a system? D) systems are made by humans?
The two true statements about a system are:
A) Systems are a group of objects analyzed as one unit.
B) Energy that moves across system boundaries is covered.
In general, a system can be defined as a group of objects or components that are connected or related to one another in some way, and that can be analyzed as a single unit. The components within a system can interact with each other, and with the environment outside of the system, in various ways. One of the key characteristics of a system is that it has a boundary or interface that separates it from the surrounding environment.
Energy, matter, or other quantities may flow across this boundary, and the interactions between the system and its environment can affect the behavior and properties of the system as a whole.
Overall, systems are a fundamental concept in many fields of science and engineering, and they can be used to model and analyze a wide range of phenomena, from physical systems like engines and circuits, to social and ecological systems like cities and ecosystems.
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Can someone help me ?
The problem requires the calculation of the volume of carbon dioxide produced at STP when 587 mol of octane combusts; ,therefore, the volume of CO₂ produced at 36.0 °C and 0.995 atm is approximately 124,700 L.
The ideal gas law is given by:
PV = nRT
P is the pressure in atm, V is the volume in L, n is the number of moles, R is the gas constant (0.0821 L·atm/mol·K), and T is the temperature in K.
587 mol octane × (16 mol CO₂/2 mol octane) = 4696 mol CO2
Next, one can use the ideal gas law to calculate the volume of CO₂ produced at 36.0 °C and 0.995 atm. Then one needs to convert the temperature to kelvin by adding 273.15:
T = 36.0 °C + 273.15 = 309.15 K
Substituting the values into the ideal gas law:
PV = nRT
V = nRT/P
V = (4696 mol)(0.0821 L·atm/mol·K)(309.15 K)/(0.995 atm)
V ≈ 124,700 L
Therefore, the volume of CO2 produced at 36.0 °C and 0.995 atm is approximately 124,700 L.
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The volume of a sample of air in a cylinder with
a movable piston is 2.0 L at a pressure P1 , as
shown in the diagram above. The volume is
increased to 5.0 L as the temperature is held
constant. The pressure of the air in the cylinder is
now P2 . What effect do the volume and pressure
changes have on the average kinetic energy of the
molecules in the sample?
(A) The average kinetic energy increases.
(B) The average kinetic energy decreases.
(C) The average kinetic energy stays the same.
(D) It cannot be determined how the kinetic
energy is affected without knowing P1
and P2 .
Answer:
I used Chat GPT to answer the question here is the answer
Assuming the gas behaves ideally, the answer is (C) The average kinetic energy stays the same.
According to the ideal gas law, PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the ideal gas constant, and T is temperature. If the temperature is held constant, then nR is also constant. Therefore, for a given amount of gas, if V increases, P must decrease (and vice versa) to maintain the same value of PV.
The average kinetic energy of gas molecules is proportional to temperature, so if the temperature is held constant, the average kinetic energy of the gas molecules stays the same. The changes in volume and pressure only affect the density and distribution of the gas molecules, but not their average kinetic energy.
At some constant temperature, the equilibrium constant for the reaction below is Kc = .76. An empty 1.00L flask is charged with 2.00 mol carbon tetrachloride and then allowed to reach equilibrium.
CCl4(g) ⇌ C (s) + 2 Cl2(g)
a. What fraction of the reactant remains at equilibrium?
b. What is the molarity of chlorine gas at equilibrium?
At some constant temperature, the equilibrium constant for the reaction below is Kc = .76. An empty 1.00L flask is charged with 2.00 mol carbon tetrachloride and then allowed to reach equilibrium. CCl4(g) ⇌ C (s) + 2 Cl2(g)
a. To find the fraction of the reactant (CCl4) remaining at equilibrium, we can start by determining the initial concentration of CCl4:
Initial concentration of CCl4 = moles/volume = 2.00 mol / 1.00 L = 2.00 M
Let x be the change in concentration of CCl4 at equilibrium. Then, the equilibrium concentrations are:
[CCl4] = 2.00 - x
[Cl2] = 2x
The equilibrium constant expression is given by:
Kc = [Cl2]^2 / [CCl4]
Plugging in the given Kc value (0.76) and the equilibrium concentrations:
0.76 = (2x)^2 / (2.00 - x)
Now, you can solve for x. The fraction of the reactant remaining at equilibrium is (2.00 - x) / 2.00.
b. To find the molarity of chlorine gas (Cl2) at equilibrium, you can use the value of x obtained in part (a). The molarity of Cl2 is equal to 2x.
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Help!!!!!!!!!!!!!!!!!!!!!!!
All of the equation-related claims are not entirely true. The appropriate chemical formula should be:
Fe(OH)3 + 3NH4Cl = FeCl3 + 3NH4OH
Because the total mass of the reactants and products are equal, as well as the number of each type of atom in each of the reactants and products, mass is conserved in this balanced equation. Depending on the stoichiometric coefficients in the balanced equation, there may or may not be an equal amount of molecules in the reactants and products.
Iron(III) hydroxide (Fe(OH)3) and ammonium chloride (NH4Cl) are the products of the chemical reaction between iron(III) chloride (FeCl3) and ammonium hydroxide (NH4OH).
The coefficients (the numbers in front of the chemical formulae) must be changed to make sure that the number of each type of atom is the same on both sides of the equation in order to ensure that the equation is balanced. The coefficients in this instance are:
Fe(OH)3 + 3NH4Cl = FeCl3 + 3NH4OH
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Why does the air feel "sticky" on warm summer days? What is in the air that caausses this
Jeremiah is conducting an investigation about the water cycle. He is given the following materials:
a lamp
a glass jar that contains water
plastic wrap
Describe how Jeremiah can arrange these materials to create a model that shows the processes by which water is cycled from a lake into the atmosphere and back to the lake. Be sure to identify what each material represents in the model.
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Jeremiah can arrange the materials in the following way to create a model that shows the processes by which water is cycled from a lake into the atmosphere and back to the lake
What is the water cycle?The following can be a representation of the water cycle;
Fill the glass jar with water to resemble the lake.
Put the lamp next to the jar to symbolize the sun.
Wrap the jar in plastic sheet to imitate the atmosphere.
Turn on the bulb to represent the sun warming the water.
When the water in the jar warms up and evaporates into water vapor, moisture will condense on the plastic wrap.
The water vapor will ascend and collect on the plastic wrap to represent the water vapor rising into the atmosphere.
Water vapor cools as it rises and condenses back into liquid form, as shown by the water droplets gathering on the plastic wrap.
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What mass (grams) of oxygen will be released when 268.9 grams of Potassium Chlorate is thermally decomposed?
KClO3 --> KCl + O2
The centripetal acceleration experienced by the object can be calculated using the formula a = v^2/r, where v is the speed of the object and r is the radius of the circle. Substituting the given values, we get:
a = (50 cm/s)^2 / (250 cm)
a = 10 cm/s^2
Therefore, the centripetal acceleration experienced by the object is 10 cm/s^2.
To calculate the centripetal acceleration experienced by the object, you can use the formula:
Centripetal acceleration (a_c) = (velocity^2) / radius
Here, the velocity (v) is 50 cm/s and the radius (r) is 250 cm. Plugging in these values, we get:
a_c = (50^2) / 250 = 2500 / 250 = 10 cm/s²
So, the centripetal acceleration experienced by the object is 10 cm/s².
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How many hydrogen molecules (h2) are needed to convert the triacylglycerol shown to saturated fat
The triacylglycerol depicted may be converted to a saturated fat by adding two hydrogen atoms (H2) to each carbon-carbon double bond. Six hydrogen atoms (H2) are required to convert the three carbon-carbon double bonds in triacylglycerol into saturated fat.
This is so that the triacylglycerol may be converted to a saturated fat by using hydrogen molecules (H2) to saturate the double bonds.
Triacylglycerol's physical characteristics, such as its melting point, will similarly be altered by the addition of hydrogen molecules (H2), making it more solid at normal temperature.
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A sample of air occupies 0.75 L at standard conditions. What is the pressure in atm if the volume is 100.0 mL at 25oC?
P1 = 760 mmHg P2 = ?
V1 = 0.750 L V2 = 100.0 mL
T1 = 273 K T2 = 25oC
According to the ideal gas law, a gas's pressure is inversely related to its volume and directly proportionate to its temperature. So, if a gas sample's volume is reduced, the gas sample's pressure must also increase.
As a result, in order to determine the pressure of the gas sample under the specified circumstances, we must first determine the ratio of the two volumes before multiplying the starting pressure of the sample by that ratio.
We may get the ratio of the two volumes using the ideal gas law as follows: V2/V1 = (100.0 mL/0.75 L) x (273 K/25oC) = 8.02 As a result, the gas sample's pressure at 25 oC with a volume of 100.0 mL is 8.02 times higher than the sample's original pressure.
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Water can dissolve many substances because-
-
it has a partial charge on each side of its molecules
it has a linear molecular shape
it has a nonpolar molecular structure
it has the molecular formula H₂O
Answer:
Water can dissolve many substances because it has a partial charge on each side of its molecules.
Explanation:
Water is a polar molecule, meaning that it has an uneven distribution of electrons between its hydrogen and oxygen atoms. This creates a partial negative charge on the oxygen side of the molecule and a partial positive charge on the hydrogen side. These partial charges allow water molecules to attract and surround other charged or polar molecules, such as ions and polar compounds, and separate them from each other. This process of surrounding and separating other substances in a solution is known as hydration or dissolution, and it is what allows water to dissolve many substances. Therefore, the correct option is: "it has a partial charge on each side of its molecules."
A 50.0-g sample of water at 25.0°C is mixed with 29.0 g of water at 65.0°C. The final temperature of the water is ________°C.
Answer:
39.7
Explanation:
Therefore, the final temperature of the water is 39.7°C.
You perform a reaction in a coffee cup calorimeter. The calorimeter has 100 mL of water in it, and the temperature of the water increases by 9.3°C. The calorimeter has a heat capacity of 50.2 J/°C. How much heat was produced by the reaction (specific heat capacity of water is 4.184 J/g-°C)?
We can use the equation:
q = m * c * ΔT
where q is the heat absorbed or released by the water, m is the mass of water, c is the specific heat capacity of water, and ΔT is the change in temperature of the water.
Since we know that the calorimeter contains 100 mL (or 100 g, since 1 mL of water has a mass of 1 g) of water and that the temperature of the water increased by 9.3°C, we can plug in these values:
q = (100 g) * (4.184 J/g-°C) * (9.3°C)
q = 3896.68 J
However, this is not the total amount of heat produced by the reaction. We need to take into account the heat absorbed by the calorimeter itself, which has a heat capacity of 50.2 J/°C. If we assume that the temperature of the calorimeter did not change during the reaction (i.e., it remained constant), we can calculate the heat absorbed by the calorimeter:
q_calorimeter = (50.2 J/°C) * (9.3°C)
q_calorimeter = 466.86 J
The total heat produced by the reaction is then:
q_reaction = q_water + q_calorimeter
q_reaction = 3896.68 J + 466.86 J
q_reaction = 4363.54 J
Therefore, the heat produced by the reaction is 4363.54 J.
What is the net ionic charge of an oxygen ion ?
A 2.550×10−2 M glycerol solution (C3H8O3) in water is at 20.0 ∘C . The sample was created by dissolving a sample of C3H8O3 in water and then bringing the volume up to 1.000 L. It was determined that the volume of water needed to do this was 998.9 mL. The density of water at 20.0 ∘C is 0.9982 g/mL
a.) Calculate the molality of the glycerol solution
b.) Calculate the mole fraction of glycerol in this solution
c.) Calculate the concentration of the glycerol solution in percent by mass
d.) Calculate the concentration of the glycerol solution in parts per million by mass
The molality of the solution is 0.0256 m.
The mole fraction of glycerol is 0.00046
The percent by mass concentration of glycerol is 0.23%
The ppm concentration is 2300 ppm
What is the molality?Molality is a measure of the concentration of a solute in a solution. It is defined as the number of moles of solute per kilogram of solvent.
The formula for molality is:
molality = moles of solute / mass of solvent in kilograms
1) Density of water = mass/volume
Mass of water = Density * volume of water
Mass =[tex]0.9982 g/mL * 998.9 mL[/tex]
Mass =0.997 Kg of water
Number of moles of the glycerol = [tex]2.550* 10^-2 M * 1 L[/tex]
= [tex]2.550*10^-2[/tex] moles
Molality of the solution = [tex]2.550*10^-2[/tex] moles/0.997 Kg
= 0.0256 m
Number of moles of water = 998.9/18 g/mol
= 55.5 mole
Mole fraction of glycerol = [tex]2.550*10^-2[/tex] /[tex]2.550*10^-2[/tex] + 55.5
= 0.00046
By percent by mass;
2.3/1001.2 * 100/1
= 0.23%
Mass of glycerol = 2.3 g
Volume of solution = 1 L
Thus we have concentration in ppm as;
[tex]2.3 * 10^3[/tex] mg/ 1 L =2300 ppm
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5. The head of matches contains an oxidizing agent such as potassium chlorate, KCIO3, together with tetraphosphorus trisulfide, P4S3.
glass, and binder. When struck either by an obect or on the side of a box of matches, the phosphorus sulfide compound is easily
ignited, causing the potassium chlorate to decompose into potassium chloride and oxygen. The oxygen in turn causes the
phosphorus sulfide to burn more vigorously.
Determine the oxidation number of chlorine in potassium chlorate.
The oxidation number of the unknown chlorine in the compound is + 5
What is oxidation number?The oxidation number of an element in a compound is determined by a set of rules based on its position in the periodic table, as well as the charges of other atoms in the compound
We know that the oxidation number of the chlorine which we want to obtain would be designated as x and the total of the oxidation numbers of the elements in the compound is zero.
Thus we have that;
1 + x + 3(-2) = 0
1 + x - 6 = 0
-5 + x = 0
x = 5
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What is the difference between collecting and analysing data
Answer:
Data collection is the act of obtaining information from diverse sources, and data analytics is the process of processing that information to derive practical insights.
Explanation:
How many mL of a 0.75 N KOH solution
should be added to a 500 mL flask to make
500 mL of a 0.300 M KOH solution?
The amount of volume of KOH solution that should be added to make 500mL of a 0.300M solution is 200mL.
How to calculate volume?The volume of a solution given the concentration can be calculated using the following expression;
CaVa = CbVb
Where;
Ca = initial concentrationVa = initial volumeCb = final concentrationVb = final volumeAccording to this question, we are to calculate how many mL of a 0.75 M OH solution that should be added to a 500 mL flask to make 500 mL of a 0.300 M KOH solution.
0.75 × Va = 500 × 0.3
0.75Va = 150
Va = 150/0.75
Va = 200mL
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Pleas help anyone!!!!!!!!!!!!!!!
The correct number of molecules of ammonium acetate used, given that the student uses 0.100 mole of ammonium acetate in the reaction is 6.022×10²² molecules
How do i determine the number of molecules of ammonium acetate?The following data were obtained from the reaction:
Number of mole ammonium acetate used = 0.100 moleNumber of molecules of ammonium acetate used =?The correct number of molecules of ammonium acetate used can be obtained as shown below:
From Avogadro's hypothesis,
1 mole of ammonium acetate = 6.022×10²³ molecules
Therefore,
0.1 mole of ammonium acetate = 0.1 × 6.022×10²³
0.1 mole of ammonium acetate = 6.022×10²² molecules
Thus, the number of molecules of ammonium acetate used is 6.022×10²² molecules
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Ocean water contains 3.3 % NaCl by mass.
How much salt can be obtained from 234g of seawater?
Answer:
Ans: 8.9 NaCl
Explanation:
Ocean water contains 3.5 nacl by mass how much salt can be obtained from 254 g of seawater
Question: Ocean water contains 3.5% NaCl by mass. How much salt can be obtained from 254g of seawater?
If 3.24 mol
of an ideal gas has a pressure of 2.19 atm
and a volume of 76.67 L,
what is the temperature of the sample in degrees Celsius?
The temperature of the sample in degrees Celsius is 358.14°C.
How to calculate temperature?The temperature of a substance can be calculated by using the following ideal gas law expression;
PV = nRT
Where;
P = pressureV = volume n = no of molesR = gas law constantT = temperatureAccording to this question, 3.24 mol of an ideal gas has a pressure of 2.19 atm and a volume of 76.67 L. The temperature can be calculated as follows;
2.19 × 76.67 = 3.24 × 0.0821 × T
167.9073 = 0.266004T
T = 167.9073/0.266004
T = 631.14K
T {°C} = 631.14 - 273 = 358.14°C
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The characteristics of two different types of reactions are shown below:
Reaction A: An atom loses electrons during the reaction.
Reaction B: An atom loses protons and neutrons during the reaction.
Which statement is true about the two reactions?
Both reactions retain the identity of the elements.
Both reactions change the identity of the elements.
Reaction A produces more energy than Reaction B.
Reaction B produces more energy than Reaction A.
The statement that is true about the reactions is
Both reactions retain the identity of the elements.How to identify the true statementIn Reactions A and B, the participating atoms preserve their elemental identity despite losing electrons (in Reaction A) or protons and neutrons (in Reaction B). This can give rise to distinct isotopes or ions of the same element while preserving its fundamental attributes.
The statements concerning energy production aren't necessarily accurate or linked with the reaction's traits. Energy output depends on many variables, such as specific reactants involved and their conditions during reactions.
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A flexible container at an initial volume of 5.12 L
contains 8.51 mol
of gas. More gas is then added to the container until it reaches a final volume of 13.3 L.
Assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.
Step-by-step Explanation:
8.51 moles is to 5.12 L as 'x' moles is to (13.3-5.12) L
8.51 moles / 5.12 L = x / ( 13.3-5.12)
x = 13.6 moles
Balance:
2. K₂O + H₂O → KOH
3.F₂ +NaBr-NaF + Br₂
4.Ba(CIO3) → BaCl2 + O2
*
5.SrBr₂ + (NH4)2CO3 → SrCO3 + NH4Br
6. C8H18 + O₂ → CO₂ + H₂O
What is the reactions to these?
the balanced equation and there reactions are as follow:
K₂O + H₂O → 2KOH
The reaction between potassium oxide and water produces potassium hydroxide (KOH).
F₂ + 2NaBr → 2NaF + Br₂
The reaction between fluorine gas and sodium bromide produces sodium fluoride and bromine.
2Ba(CIO3)₂ → 2BaCl₂ + 3O₂
The decomposition of barium chlorate produces barium chloride and oxygen gas.
SrBr₂ + (NH₄)₂CO₃ → SrCO₃ + 2NH₄Br
The reaction between strontium bromide and ammonium carbonate produces strontium carbonate and ammonium bromide.
C₈H₁₈ + 12O₂ → 8CO₂ + 9H₂O
The combustion of octane with oxygen produces carbon dioxide and water.
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Acetic acid has a molar mass of 60.05 g/mol. If 16.84 grams of acetic acid are present, how many moles of acetic acid does that correspond to?
Answer:
3.566 mol
Explanation:
Since 60.05 is grams divided by mol to cancel out the grams to get only mols it must be divided by 16.84 g
[tex]\frac{60.05 g}{mol} *\frac{1 }{16.84g} =3.566[/tex] mols acetic acid
Summarize the main challenges and constraints that engineers must overcome in the design of a low-cost, portable water purification system.
The primary difficulties in creating a low-cost, portable water purification system include assuring efficient pollution removal, compact design, durability etc.
In order to create a low-cost, portable water purification system, engineers must overcome several main obstacles and challenges, including: ensuring the removal of contaminants effectively; designing a compact and lightweight system; guaranteeing durability and reliability in harsh environments; providing an affordable, sustainable power source; and addressing cultural and social factors that may affect user acceptance and adoption.
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( + 0₂ (0₂ 1 Is the molecular mas of carbon is 12 and that of oxygen is 32, Calculate the mass of carbon dioxide formed when 24kg of carbon is burnt completely in oxygen and determine the heat thereby released in MJ if the complete combustion of 1kg of carbon releases 33.8MJ of heat
The mass of carbon dioxide formed when 24 kg of carbon is burnt completely in oxygen is 88 kg, and the heat released is 811.2 MJ.
What is Molar Mass?
Molar mass is the mass of one mole of a substance and is expressed in grams per mole (g/mol). It is calculated by adding up the atomic masses of all the atoms in a molecule or formula unit of a compound. The molar mass is used in stoichiometry calculations to convert between mass and moles of a substance.
The balanced equation for the combustion of carbon is:
C + O₂ → CO₂
From the equation, we can see that one mole of carbon reacts with one mole of oxygen to produce one mole of carbon dioxide. The molar mass of carbon dioxide is 12 + (2 × 16) = 44 g/mol.
First, let's find the number of moles of carbon in 24 kg:
n(C) = m/M = 24000 g / 12 g/mol = 2000 mol
Therefore, 2000 mol of CO₂ will be produced.
The mass of CO₂ produced can be calculated as:
m(CO₂) = n(CO₂) × M(CO₂) = 2000 mol × 44 g/mol = 88,000 g = 88 kg
Now, let's calculate the heat released during combustion:
Heat released = 33.8 MJ/kg × 24 kg = 811.2 MJ
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