How much force is needed to accelerate a 70kg table at a rate of 4 m/s

Answers

Answer 1

Answer:

F = 280 N

Explanation:

To determine the force needed to accelerate a 70 kg table at a rate of 4 m/s², we can use Newton's second law of motion, which states that force (F) is equal to mass (m) times acceleration (a).

So, we can calculate the force (F) required using the following formula:

F = m x a

where F is the force in Newtons (N), m is the mass in kilograms (kg), and a is the acceleration in meters per second squared (m/s²).

Plugging in the given values, we get:

F = 70 kg x 4 m/s²F = 280 NTherefore, the force needed to accelerate a 70 kg table at a rate of 4 m/s² is 280 Newtons.

Related Questions

A sled rider having a combined mass of 125 kg travels down the slope as shown in the
figure. A friction force of 2 N acts between the slope and the sled. If he starts at rest
on the top of the slope, calculate the speed (in m/s) of the sled rider when he reaches
the bottom of the slope. [Enter the number up to one decimal place]
[Hint: Use conservation of total energy, use trigonometry to find the length of the
slope, s and use it in Wother]

Answers

The conservation of energy principle, which states that a system's total mechanical energy is conserved in the absence of external forces, will be used to solve this issue. The Earth and the sled rider make up the system in this instance.

In the absence of outside influences, does the overall quantity of mechanical energy in a closed system remain constant?

The mechanical energy will be constant in a closed system, one in which there are no external dissipative forces at work. In other words, nothing will alter (become more or less). The Law of Conservation of Mechanical Energy is what we refer to as this.

What is the circumstance in which mechanical energy is conserved according to the concept of conservation of energy?

The lone circumstance in which mechanical energys conserved is that all the forces acting on it should be conservative forces.ie no friction or heat loss should be there!!.

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A cart travels with a constant nonzero acceleration along a straight line. Which graph best represents the relationship between the acceleration the cart travels and time of travel?

Answers

Answer:

Option 3

Explanation:

A cart travels with constant nonzero acceleration along a straight line. the relationship between the distance the cart travels and the time of travel is represented in the graph which has a curved in an upward direction.

A boat is heading due east at speed v when passengers onboard
spot a dolphin swimming due north away from them, relative
to their moving boat. Which of the following must be true of
the dolphin’s motion relative to a stationary observer floating
in the water (choose one)? The dolphin is (a) heading south
of east at a speed greater than v, (b) heading south of west at a
speed less than v, (c) heading north of east at a speed greater
than v, or (d) heading north of west at a speed less than v.

Answers

boat is heading due east at speed v when passengers onboard

spot a dolphin swimming due north away from them, relative

to their moving boat (c) heading north of east at a speed greater than v

The motion of the dolphin relative to a stationary observer floating in the water depends on the velocity of the boat and the velocity of the dolphin relative to the water.

Since the boat is heading due east and the dolphin is swimming due north relative to the moving boat, the dolphin's velocity relative to the boat is due north. Let's call the magnitude of this velocity "d".

The boat's velocity relative to the water is also due east and has a magnitude of "v".

Using the Pythagorean theorem, the magnitude of the dolphin's velocity relative to the stationary observer is:

sqrt([tex]d^2 + v^2)[/tex]

The direction of the dolphin's velocity relative to the stationary observer can be found using trigonometry. The angle between the dolphin's velocity relative to the boat and the boat's velocity relative to the water is 90 degrees, so the tangent of the angle between the dolphin's velocity and the velocity of the boat is d/v.

If we draw a right triangle with sides d, v, and sqrt([tex]d^2 + v^2[/tex]), the angle between the dolphin's velocity and the velocity of the boat is the angle opposite the side d. Using trigonometry, we find that this angle is:

[tex]tan^-1(d/v)[/tex]

The direction of the dolphin's velocity relative to the stationary observer is then 90 degrees plus this angle, since the dolphin's velocity is heading north relative to the boat.

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Marina was immunized against chicken pox when she was young. Which of the following statements is true?

Since she was immunized, it is impossible for Marina to contract chicken pox.
Marina was exposed to a weak form of chicken pox antigen.
The immunization provided Marina with passive immunity.
Marina needs to be immunized again because antibodies do not last long in the body.

Answers

Answer:

see below

Explanation:

In chickenpox vaccine , weakened/killed pathogens are introduced into the body to generate immune response. The first response is slow and is called primary response while the subsequent exposure with the same pathogen generates a highly intensified immune response which is known as secondary response .

This type of immunity which generates antibody against the virus particles by introducing them into the body is called active immunity . It lasts forever in the body as the immune system has the memory of first exposure with the pathogen and after coming in contact with the same pathogen it recognises it and generates immune response.

So the correct option would be,

Marina was exposed to a weak form of chicken pox antigen.

[tex]\rule{200}2[/tex]

Related information:-

Passive immunity:-

It is the type of immunity when performed antibodies are introduced in the body . Like in case of smallpox. This doesn't last long in the body and requires repeated infusions in the body after coming in contact with the same pathogen again.

Also , it is helpful when quick reponse is required against the antigen and we don't have time to wait for generating immune response like in case of snake bites .

Write a synthetic route for the conversion of cyclopropane to cyclopropanecarboxylic acid via Grignard reagent.​

Answers

Here is a synthesis method for using the Grignard reagent to change cyclopropane into cyclopropanecarboxylic acid: Make cyclopropane into cyclopropanone using ozonolysis or another appropriate process.

What is a cyclopropanation example?

Dichlorocarbene is one illustration. The formation of cyclopropanes from these halogenated carbenes is similar to that of methylene, with the intriguing addition of two halogen atoms in lieu of the hydrogen atoms. Although they do not strictly qualify as carbenes, carbeneoids are substances that combine to form cyclopropanes.

What is alkene cyclopropanation?

Since the addition of carbene and carbenoids to alkenes is a type of cheletropic reaction and occurs in a syn way, cyclopropanation also exhibits stereospecificity.

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5. Determine the friction a car that has a mass of 320kg would experience traveling 20 m/s going around a curve if
the radius of the curve is 200m.

Answers

The frictional force acting on the car is equal to the centripetal force, therefore the frictional force = 3200 N.

What is frictional force?

The force produced when two surfaces slide against and touch each other is called frictional force.

To determine the friction that a car would experience, we need to use the formula for centripetal force:

F = m * (v² / r)

where F is the force required to keep the car moving in a circular path, m is the mass of the car, v is the velocity of the car, and r is the radius of the curve.

In this case, we can substitute the given values to find the required force:

F = 320 kg * (20 m/s)² / 200 m

F = 3200 N

This force is the centripetal force required to keep the car moving in a circular path around the curve. This force is provided by the friction between the car's tires and the road surface. Therefore, the frictional force acting on the car is equal to the centripetal force:

Frictional force = 3200 N

Note that this calculation assumes that the car is traveling at a constant speed around the curve. If the car is accelerating or decelerating, additional forces (such as the force due to braking or acceleration) would need to be considered in the calculation of the frictional force.

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For the simple harmonic oscillation where k = 19.6
N/m, A = 0.100 m, x = -(0.100 m) cos 8.08t, and v =
(0.808 m/s) sin 8.08t, determine (a) the total energy, (b)
the kinetic and potential energies as a function of time,
(c) the velocity when the mass is 0.050 m from
equilibrium, (d) the kinetic and potential energies at
half amplitude (x = A/2).

Answers

a. Total energy is 0.098 J

b. Potential and Kinetic Energies is 0.032 sin^2(8.08t) J

c. Velocity at x is -0.808 sin(8.08t) m/s

d. Potential and Kinetic Energies at x is 0.016 sin^2(8.08t) J

Step by step explanation

We can use the following formulas for the energy, velocity, and potential and kinetic energies of a simple harmonic oscillator:

Total Energy: E = 1/2 k A^2Velocity: v = -ωA sin(ωt)Potential Energy: U = 1/2 k x^2Kinetic Energy: K = 1/2 m v^2

where ω = √(k/m) is the angular frequency.

Given that k = 19.6 N/m, A = 0.100 m, x = -(0.100 m) cos 8.08t, and v = (0.808 m/s) sin 8.08t, we can find the values of E, U, and K as follows:

(a) Total Energy:

E = 1/2 k A^2 = 1/2 * 19.6 * 0.1^2 = 0.098 J

(b) Potential and Kinetic Energies:

U = 1/2 k x^2 = 1/2 * 19.6 * (-0.1 cos(8.08t))^2 = 0.098 cos^2(8.08t) J

K = 1/2 m v^2 = 1/2 * (0.1) * (0.808 sin(8.08t))^2 = 0.032 sin^2(8.08t) J

(c) Velocity at x = 0.050 m:

When x = 0.050 m, cos(8.08t) = -0.5, so we have:

v = -ωA sin(ωt) = -ω(0.1) sin(8.08t) = -0.808 sin(8.08t) m/s

(d) Potential and Kinetic Energies at x = A/2:

When x = A/2 = 0.050 m, cos(8.08t) = -0.5, so we have:

U = 1/2 k x^2 = 1/2 * 19.6 * (0.050)^2 = 0.0245 J

K = 1/2 m v^2 = 1/2 * (0.1) * (0.808 sin(8.08t))^2 = 0.016 sin^2(8.08t) J

Note that the sum of potential and kinetic energies at any point in time is equal to the total energy, which is constant.

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How high would a 8 kg mass need to be lifted to have a potential energy of 400 J?

Answers

Explanation:

Potential Energy = m g h

400 J   =  8 kg  * 9.81 m/s^2  * h

400 / (8 *9.81) = h = 5.1 m

A force of 35.0 N is applied to a 15kg block at rest. If the block travels 125m in the first 5.00 seconds the force is applied, what is the average force of friction acting on the block?

Answers

The average force of friction acting on the block over the distance of 125 m is 0.294 N/m

How to find the average force of friction acting on the block?

We can use the equation of motion to calculate the acceleration of the block as follows:

d = 1/2 * a * t^2

Where

d is the distance traveled t is the time taken a is the acceleration

Substituting the given values, we get:

125 m = 1/2 * a * (5 s)^2

Solving for a, we get:

a = 10 m/s^2

The net force acting on the block is equal to the product of its mass and acceleration, i.e.:

F_net = m * a = 15 kg * 10 m/s^2 = 150 N

Since the block is at rest initially, the force of static friction must balance the applied force of 35.0 N, i.e.:

friction = 35.0 N

Once the block starts moving, the force of kinetic friction opposes the motion and has a constant magnitude given by:

friction = μ * N

Where

μ is the coefficient of kinetic friction N is the normal force

The normal force is equal to the weight of the block, i.e.:

N = m * g = 15 kg * 9.81 m/s^2 = 147.15 N

Substituting the given coefficient of friction μ = 0.25, we get:

friction = 0.25 * 147.15 N = 36.79 N

Therefore, the average force of friction acting on the block over the distance of 125 m is:

average friction = friction / distance = 36.79 N / 125 m = 0.294 N/m

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A travel trailer has four running lights that draw 0.5A each and two taillights that draw 1.2A each. What is the current supplied to the trailer when the taillights and running lights are on?​

Answers

The total current supplied to the trailer when the taillights and running lights are on is the sum of the current drawn by the running lights and the current drawn by the taillights.

The current drawn by the running lights is:

I1 = 4 * 0.5 A = 2 A

The current drawn by the taillights is:

I2 = 2 * 1.2 A = 2.4 A

Therefore, the total current supplied to the trailer when the taillights and running lights are on is:

I = I1 + I2 = 2 A + 2.4 A = 4.4 A

Therefore, the current supplied to the trailer when the taillights and running lights are on is 4.4 A.

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An object is weight with spring balance in air and then totally with water, the reading on the balance are 0.98N and 0.88N repectively. Calculate the desity of the object.

Answers

Answer:

Weight of object = .98 N

Buoyant force equals weight of water displaced = .10 N

Weight of object - weight of water displaced = .98 - .10 = .88 N

Density = Weight of object / Weight of equivalent weight of water

ρ = .98 / .10 = 9.8         specific gravity of object

Since the density of water = 1 g / cm^3

the density of the object is 9.8 g / cm^3      (9800 kg/m^3)

A bungee jumping company wants to set up a bungee
jumping location on the top of a bridge that is 300 m above
the ground. For safety reasons, the company wants to
select a bungee cord spring constant such that a jumper
with a mass of 115 kg will reach his lowest point that is,
the point when the change in gravitational potential energy
equals the amount of energy stored in the bungee cord at
the bottom of the jump - at 50 m above the ground. What
is the approximate spring constant the company should
choose, assuming that air resistance, friction, and the
weight of the cord can be ignored and that the cord
immediately begins to stretch as soon as the jumper
begins to fall? (Recall that g = 9.8 m/s²)
cord mg
A. 23 N/m
B. 9 N/m
C. 4 N/m
D. 15 N/m

Answers

Answer:

Approximately [tex]9\; {\rm N \cdot m^{-1}}[/tex].

Explanation:

Change in the gravitational potential energy (GPE) of the system:

[tex](\text{change in GPE}) = m\, g\, \Delta h[/tex], where:

[tex]m = 115\; {\rm kg}[/tex] is the mass of the jumper.[tex]g = 9.8\; {\rm m\cdot s^{-2}} = 9.8\; {\rm N\cdot kg^{-1}}[/tex] is the gravitational field strength.[tex]\Delta h = (300 - 50)\; {\rm m} = 250\; {\rm m}[/tex] is the absolute value of the change in height.

Change in the elastic potential energy (EPE) of the system:

[tex]\text{(change in EPE)} = (1/2)\, k\, x^{2}[/tex], where:

[tex]k[/tex] is the spring constant and needs to be found.[tex]x = (250 - 0)\; {\rm m} = 250\; {\rm m}[/tex] is the change in the length of the cord. Note that since the cord started stretching immediately, that initial length of the cord would be [tex]0\; {\rm m}[/tex] .

Set [tex]\text{(change in GPE)} = \text{(change in EPE)}[/tex] and solve for the spring constant [tex]k[/tex]:

[tex]\displaystyle m\, g\, \Delta h = \frac{1}{2}\, k\, x^{2}[/tex].

[tex]\begin{aligned}k &= \frac{m\, g\, \Delta h}{(1/2)\, x^{2}} \\ &= \frac{(115)\, (9.8)\, (250)}{(1/2)\, (250)^{2}}\; {\rm N\cdot m^{-1}} \\ &\approx 9\; {\rm N\cdot m^{-1}}\end{aligned}[/tex].

2. This diagram shows an electric bell ringing in a sealed glass chamber containing air. to vacuum pump 5655 bell A student hears the bell ringing. The air is then removed from the chamber. State and explain any change in the sound heard by the student.​

Answers

When the air is removed from the chamber using a vacuum pump, the sound heard by the student will become quieter.

What is Vacuum?

Vacuum is typically created by removing gases and other matter from a closed container, using methods such as mechanical pumps, diffusion pumps, or cryopumps. In the absence of matter, there is no medium for sound waves to propagate, which is why sound cannot travel through a vacuum.

This is because sound waves require a medium to travel through, such as air. When the air is present in the chamber, the sound waves from the vibrating bell can travel through the air and reach the student's ear. However, when the air is removed, there is no medium for the sound waves to travel through, so they cannot reach the student's ear as effectively.

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The rocket fuel container says it possesses an impulse of 250,000 N•s. It burns through its fuel in a time period of 0.25s, and the rocket gets pushed a distance of 1046 m. How much work was done on the stolen rocket?.

Must everything that is given

Answers

Answer:

the work done on the stolen rocket is approximately 1,046,000,000 joules.


Step-by-step explanation:


Yes, we need all the given information to calculate the work done on the rocket.

We can use the formula for impulse to find the force exerted on the rocket:

impulse = force x time

We can rearrange this formula to solve for force:

force = impulse / time

Substituting the given values, we get:

force = 250,000 N•s / 0.25 s = 1,000,000 N

Now we can use the formula for work done by a constant force:

work = force x distance

Substituting the values we get:

work = 1,000,000 N x 1046 m = 1,046,000,000 J

A frog is riding on the top of a cylindrical piece of wood floating in still water. Half of the wood, with a diameter of 4 cm and length 20 cm, is immersed in water. The density of water is 1 gm/cc. a) What is the mass of the wood along with the frog? b) After the frog slowly goes into the water only one third of the wood remains immersed in water. Calculate the mass of the frog. c) Calculate x, the distance between the water level and the center of the circular end of the wooden piece. d) Briefly describe the motion of the wood after the instance the frog moves into the water. Give a rough sketch of x as a function of time.​

Answers

The total mass of the wood along with the frog is 120π gm.

The mass of the frog is (160/3)π gm.

How to calculate the Mass

The volume of the wood that is immersed in water is given by the volume of a cylinder with a radius of 2 cm and a height of 10 cm, which is V1 = π(2cm)²(10cm) = 40π cm³. The mass of the water displaced by this volume of wood is m1 = V1ρ = 40π gm. The mass of the remaining part of the wood above water is m2 = ρV2 = ρ(π(2cm)²(10cm)) = 80π gm.

mTherefore, the total mass of the wood along with the frog is m1 + m2 = 120π gm.

b) After the frog goes into the water, the volume of the wood that is immersed decreases to V3 = (1/3)π(2cm)^2(20cm) = (80/3)π cm^3. The mass of the water displaced by this volume of wood is m3 = V3ρ = (80/3)π gm. Therefore, the mass of the frog is (m1 + m2) - m3 = (120π - (80/3)π) gm = (240/3)π - (80/3)π = (160/3)π gm.

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Assume that an average student in your physics class can load into a van forty 12.7 kg boxes of copy paper in 5.0 min . The van has a loading height of 0.70 m . Assume also that the magnitude of the work done on each bag by the student equals the magnitude of the work done on the bag by gravity when the box is lifted into the van.

What is the average power output of the student in watts?
Express your answer in watts.

Answers

The average power output of the student in watts, given that the student can load into a van forty 12.7 kg boxes of copy paper in 5.0 mins is 11.62 Watts

How do i determine the average power output?

First, we shall obtain the work done by the student in loading the  forty 12.7 kg boxes of copy paper. Details below:

Total mass of box (m) = 40 × 12.7 = 508 KgHeight (h) = 0.7 mAcceleration due to gravity (g) = 9.8 m/s² Work done (Wd) = ?

Wd = mgh

Wd = 508 × 9.8 × 0.7

Wd = 3484.88 J

Now, we shall determine the average power output of the student. Details below:

Time (t) = 5.0 mins = 5 × 60 = 300 secondsWork done (Wd) = 3484.88 JAverage power output (P) = ?

P = Wd / t

P = 3484.88 / 300

P = 11.62 Watts

Thus, the average power output is 11.62 Watts

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A ray diagram shows that an object is placed in front of a plane mirror. What are the characteristics of the image produced by the object?

inverted, larger than object, real
upright, smaller than object, virtual(this is not the answer)
inverted, same size as object, real
upright, same size as object, virtual

Answers

The image created when an object is placed in front of a plane mirror is virtual, hence it cannot be projected onto a screen. The right response is: virtual, upright, and of the same size as the object.

Does an object's image emerge when it is placed in front of a flat mirror?

A virtual picture is created when an object is placed in front of a plane mirror. The distance between the image and the mirror is equal to the distance between the item and the mirror, and the size of the image is the same as the size of the object.

When the object is flipped over in relation to the mirror's planar image?

The left side of an object appears to be the right side of its image when it is placed in front of a plane mirror, and the opposite is true for the right side of the object. Lateral inversion is the term for this phenomena.

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The skin keeps __________ and ________ out of the body

Answers

Answer:

stable bone

save from sun rays

John and Mary are skating at an ice rink. John skates at a constant speed of 6.5 m/s, with respect to the ice surface, directly south. Mary skates at a constant speed of 10.5 m/s in a direction of 27° west of south, with respect to the ice. What are the magnitude and direction of Mary's velocity with respect to John? Give the magnitude in m/s, and give the direction as measured relative to due south.

Answers

Mary's velocity with respect to John has a magnitude of approximately 5.459 m/s and a direction of approximately 120.7° relative to due south.

What is  velocity?

A vector quantity that describes the rate of change of any object's position with respect to the time is called velocity.

Component of Mary's velocity vector in the south direction is given by:

[tex]\rm v_{south[/tex] = 10.5 cos(27°) = 9.373 m/s

Component of Mary's velocity vector in the west direction is: [tex]\rm v_{west[/tex] = 10.5 sin(27°) = 4.642 m/s

Mary's velocity vector with respect to the ice can be written as: [tex]\rm v_M/Ice[/tex] = -9.373 m/s (in the south direction) - 4.642 m/s (in the west direction)

[tex]\rm v_J/Ice[/tex] = -6.5 m/s (in the south direction)

[tex]\rm v_M/J[/tex] = [tex]\rm v_M/Ice - v_J/Ice[/tex]

[tex]\rm v_M/J[/tex] = (-9.373 m/s) (in south direction) - (-6.5 m/s) (in south direction) - 4.642 m/s (in west direction)

[tex]\rm v_M/J[/tex] = -2.873 m/s (in the south direction) - 4.642 m/s (in the west direction)

|[tex]\rm v_M/J[/tex]| = √((-2.873 m/s)² + (-4.642 m/s)²) = 5.459 m/s

θ = 59.3°

θ = 180° - 59.3° = 120.7°

Therefore, Mary's velocity with respect to John has a magnitude of approximately 5.459 m/s and a direction of approximately 120.7° relative to due south.

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Janice turns on a speaker in her house that is powered by the nearby dam. Below is the list of steps describing how the energy is transformed several times to get to her speaker.
Match the step of the energy transformation with the type of energy that describes it.
1. Water sits at top of dam (not moving)
2. Water flows down towards the bottom of the dam.
3. Water moves the turbine and coil as it passes through the dam.
4. The water causes electrons inside the coil to move.
[ Choose ]
Choose 1
Sound energy
Heat energy
Potential energy
Kinetic energy
Electrical energy
Elastic potential energy
Light energy
Nuclear energy
[ Choose ]
5. Electrons move from the coil across the power lines to Janice's house.
[ Choose
6. Sound comes out of the speaker that is plugged into the wall
Choose

Answers

possible energy, Motional energy. Mech. energ. Sound energy, electrical energy Conversion of gravitational potential energy into electrical energy. Hydroelectric Power Plant: ​Hydroelectric power is produced by the gravity of falling water.

When you switch on a speaker, what kind of energy happens?

The right response is acoustic energy from electric energy. Electrical energy is transformed into sound energy by the loudspeaker. It creates a sound wave that follows the original voice or music signal's pattern. A loudspeaker's diaphragm vibrates as a result of electrical energy, which in turn causes the nearby air to vibrate.

What happens to energy when it is transformed in a hydroelectric power plant?

A turbine is turned by the water's kinetic energy as it passes through the dam. The generator turns the mechanical energy from the turbine into electricity.

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Suppose that two equally charged spheres attract each other with a force of -0.492 N ("-" means attractive) when placed a distance of 29.1 cm from each other. Determine the charge of the spheres.

Answers

Each sphere has a charge of 2.00 x 10^-7 C.

The electric force between two charged objects is given by Coulomb's law:

F = k(q1q2/r^2),

where F is the force, k is Coulomb's constant (9.0 x 10^9 N m^2/C^2), q1 and q2 are the charges of the two objects, and r is the distance between them.

In this case, we know that the force is -0.492 N (attractive), the distance is 29.1 cm (0.291 m), and the two spheres have the same charge, so q1 = q2 = q

Substituting these values into Coulomb's law, we get:

-0.492 N = k(q^2 / (0.291 m)^2)

Solving for q, we get:

q = sqrt((-0.492 N * (0.291 m)^2) / k)

q = sqrt((-0.492 N * (0.291 m)^2) / (9.0 x 10^9 N m^2/C^2))

q = 2.00 x 10^-7 C

Therefore, each sphere has a charge of 2.00 x 10^-7 C.

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What do non count? As apples and oranges

Answers

Non-count nouns, such as substances or concepts, are often things that are difficult to count or quantify. Like with count nouns like apples or oranges, you cannot count them in discrete units.

Which nouns are countable and uncountable?

Nouns may or may not be countable. One apple, two apples, three apples, etc. are all examples of countable nouns. Uncountable nouns, such as air, rice, water, etc., cannot be tallied. When learning a new word, it is important to determine if it is countable or uncountable and to take note of its placement in a sentence.

How does fruit not have a count?

It is okay to say "I love fruit" instead of "I love fruits" because "fruit" is generally considered to be an uncountable noun. But, if you refer to a specific kind of fruit, then this word becomes countable: for instance, This region is suitable for citrus fruit cultivation.

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A car traveling 45.0 m/s starts to accelerate at 4.00 m/s2. How far does this car travel after 3.00 seconds?

141 m
147 m
153 m
204 m

Answers

Answer:

153 m

Explanation:

Given:

A = 4m/s^2

V₁ = 45m/s

V = V₀ + at = ( 45 + 4 × 3 m/s) = 57 m/s

2ax = v^2 - v₀^2

∴ x = v^2-v₀^2/2a

=57^2-45^2/2*4

153 m

The distance traveled by the car after 3 seconds is 135 meters. Therefore, option C is correct.

Given:

Initial velocity = 45.0 m/s

Acceleration = 4.00 m/s²

Time = 3.00 s

To calculate the distance traveled by a car after 3.00 seconds, the kinematic equation can be used: [tex]s = ut + \frac{1}{2} at^2[/tex]

Where:

s = distance traveled

u = initial velocity

t = time

a = acceleration

Substituting the values in the formula:

[tex]s = 45\times 3 + \frac{1}{2} \times 4 \times 3^2\\[/tex]

s = 135 + 2 × 9

s = 135 + 18

s = 153 meters

Therefore, this car having an initial velocity of 45m/s and acceleration of 4 m/s² will travel 153 meters in three seconds.

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Discussion of the experiments with the dynamics track: Newton’s laws

Answers

Experiments with the dynamics track provide a practical and visual way to demonstrate the laws of motion proposed by Newton, which are still fundamental to our understanding of physics today.

What is Newton's First Law?

Newton's first law of motion states that an object at rest will remain at rest, and an object in motion will continue to move at a constant velocity in a straight line, unless acted upon by an unbalanced force. To demonstrate this, a cart or ball can be placed on the track and allowed to roll with no additional forces acting on it. The object will continue to move at a constant velocity until it is stopped by friction or another force.

Experiments with a dynamics track can provide insights into the fundamental laws of motion proposed by Sir Isaac Newton. The dynamics track consists of a track with a level, smooth surface, which allows objects to slide or roll along it with minimal friction. The experiments usually involve a cart or a ball, and various additional objects such as weights, springs, and pulleys, to test the laws of motion.

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1. Describe how the word ‘scientist’ came to be.
2. Who were the four men that met at Cambridge in 1812 and what were some of their accomplishments? What did they do and discuss at their meetings? Explain and describe.
3. What was the inductive scientific method? Explain. What was the debate surrounding this scientific method? Describe.
4. How did women first get a foot in the door of science? By whom? Explain.
5. What is the heroic part of the Philosophical Breakfast Clubs story? What is the flip side of this story? Explain the details of the ‘flip side.’
6. Snyder ends her talk by saying, “Darwin knew what we seem to have forgotten, that science is not only for scientists.” What do you think that is meant by this? Do you consider yourself to have a basic scientific literacy? Explain and discuss your thoughts.
7. Do you think it’s important that forensics is categorized as a science? Why or why not?

Answers

The word 'scientist' was first coined by William Whewell in the early 19th century. He proposed the term as a replacement for the previous term 'natural philosopher.

What is the word scientist about?

The four men who met at Cambridge in 1812 were Charles Babbage, John Herschel, George Peacock, and Richard Jones. They were all highly accomplished scientists and mathematicians, and they formed a close friendship and intellectual partnership. They discussed a wide range of scientific and philosophical topics, including the nature of knowledge, the role of mathematics in science, and the principles of inductive reasoning. Their meetings laid the foundation for the development of the modern scientific method and helped to establish the field of mathematics as a central component of scientific inquiry.

The inductive scientific method involves making observations and collecting data in order to draw general conclusions or make predictions about a particular phenomenon. It is based on the idea that knowledge can be built up gradually through the accumulation of empirical evidence. The debate surrounding this scientific method focused on the question of whether it was truly objective and reliable, or whether it was inherently biased by the particular observations and assumptions of the scientist conducting the research.

Women first began to make significant contributions to science in the 19th century, largely through the efforts of pioneers such as Mary Somerville and Caroline Herschel. These women often had to overcome significant social and institutional barriers in order to pursue scientific research, but their accomplishments helped to pave the way for future generations of female scientists.

The heroic part of the Philosophical Breakfast Clubs story is the way in which these four men collaborated and supported each other in pursuit of scientific knowledge. They were willing to challenge established ideas and take risks in order to advance their field. However, the flip side of this story is that their exclusive, male-dominated intellectual circle reinforced existing power structures and excluded women and other marginalized groups from participating in the scientific enterprise.

Darwin's statement that "science is not only for scientists" emphasizes the idea that scientific knowledge should be accessible and understandable to everyone, not just those who have specialized training or expertise. In order to fully participate in a democratic society, it is important for individuals to have at least a basic understanding of scientific concepts and methods. Whether or not one considers oneself to have a basic scientific literacy depends on individual experiences and education.

Therefore, It is important that forensics is categorized as a science because it involves the application of scientific principles and methods to the investigation of crimes and other legal matters. By using evidence-based techniques, forensic scientists can provide accurate and reliable information that can be used to make informed decisions in legal proceedings.

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The required tension in cable AB is 1200 N. Determine (a) the vertical force P that must be applied to the pedal, (b) the corresponding reaction at C. The surface of the inclined plane shown is frictionless. If F = 30 N, what is the magnitude of the force exerted on the 3.0-kg block by the 2.0-kg block?

Answers

The vertical force P that need to be applied to the pedal is 500 N.The corresponding reaction at C is 1300N. The magnitude of the pressure exerted on the three.zero-kg block via the two.0-kg block is eighteen N.

1. a) Taking Moments about C & equating to Zero.

+ ∑M_c = 0 ⇒

P x300 = 1200 x 125 =0

So, P = 500 N.

b) Applying the vertical of equilibrium along horizontal & vertical directions.

+Σ F_x = 0⇒ Cx - 1200 0

                     so,  Cx = 1200 N

+ΣFy = 0 ⇒ Cy - P = 0

                    so, Cy = P = 500N

So, Reaction at C.

[tex]R_c=\sqrt{C_x^2+C_y^2}\\= \sqrt{(1200)^2+(500)^2}[/tex]

= 1300 N.

2. The net force on the two blocks is calculated by applying Newton's second law of motion as shown below;

[tex]\sum F_x = ma\\\\F+m_2gcos\theta - F_{3n} = Fnet\\\\F+m_2gcos\theta - m_{3g} = F_{net}\\\\(30) + (2 * 9.8 * cos 30) - (3 * 9.8) = F_{net}\\\\17.6 N = F_{net}\\\\F_{net} = 18 N[/tex]

Magnitude refers to the size or degree of something, often used in the context of scientific measurements or observations. In physics, magnitude typically refers to the strength or intensity of a physical quantity, such as the magnitude of a force or the magnitude of an electric field. In astronomy, magnitude is used to describe the brightness of celestial objects, such as stars, with a larger magnitude indicating a fainter object.

Magnitude can refer to the size of a number or vector, which is often represented by its absolute value. Magnitude is also a concept in geometry, where it refers to the size or length of a geometric object, such as a line segment or a vector. Magnitude is a useful concept in various fields of study, helping to quantify and compare the size, strength, or intensity of different phenomena.

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Complete Question: -

1. The required tension in cable AB is 1200 N. Determine (a) the vertical force P that must be applied to the pedal, (b) the corresponding reaction at C.

2. The surface of the inclined plane shown is frictionless. If F = 30 N, what is the magnitude of the force exerted on the 3.0-kg block by the 2.0-kg block?

3.A Physics professor sets up an experiment to determine the height of a building in his experiment he found that a putty ball, A, released from the top of a building, X, Covers the last 2 min the air in 0,125 s. ignore the effects of air resistance Putty Ball PA 2,0 m Ground Z 3.1 State the value of the "change in velocity per second" for the putty ball 3.2 The experiment is repeated using a putty ball B of TWICE the mass of putty ball A will the acceleration of balt B be GREATER THAN, EQUAL TO or LESS THAN the acceleration of ball A? Give a reason for the answer 4.What can be done to ensure the reliability of results? (0) (1)​

Answers

3,1 The value of the "change in velocity per second" for the putty ball is 256 m/s².

3.2 The putty ball's mass has no effect on its acceleration, but it does have an effect on its weight and momentum.

4 The experiment can be repeated several times to ensure the reliability of the results.

How to calculate change in velocity?

3.1 The "change in velocity per second" for the putty ball can be calculated using the formula:

change in velocity = (final velocity - initial velocity) / time

In this case, the putty ball A is released from rest, so its initial velocity is zero. Its final velocity can be calculated using the equation of motion:

distance = 0.5 x acceleration x time²

where distance is the height of the building, and time is the time it takes for the ball to fall to the ground. We are given that the distance is h and the time is 2 minutes or 120 seconds. Using these values, we can solve for the acceleration:

h = 0.5 × a × t²

a = 2h / t²

Substituting h = XZ = 2.0 m and t = 0.125 s:

a = 2 x 2.0 / (0.125)² = 256 m/s²

Now, calculate the change in velocity per second:

change in velocity = (final velocity - initial velocity) / time

= (acceleration x time) / time

= acceleration

= 256 m/s²

Therefore, the value of the "change in velocity per second" for the putty ball is 256 m/s².

3.2 The acceleration of putty ball B will be equal to the acceleration of putty ball A. This is because the acceleration of an object is determined only by the force acting on it and its mass, according to Newton's second law of motion (F = ma). In this case, both putty balls are subject to the same gravitational force and experience the same air resistance (which is negligible), so their acceleration will be the same. The mass of the putty ball does not affect its acceleration, but it does affect its weight and momentum.

4 To ensure the reliability of the results, the experiment can be repeated multiple times, and the results can be compared and analyzed for consistency. The experiment can also be performed under controlled conditions, such as in a vacuum, to eliminate the effects of air resistance. The equipment used in the experiment should be calibrated and properly maintained to ensure accurate measurements. The experimenter should also take care to minimize sources of error, such as parallax error when reading the height of the building, and record all measurements and observations accurately.

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Part b from question 5 says briefly explain how an expirement would be different from the observational study you have used as an example

Answers

An experiment is a research design in which the researcher manipulates one or more variables to observe the effect on another variable, while an observational study involves observing and measuring variables without any manipulation.

How is an experiment different from the observational study?

In an experiment, the researcher has control over the variables being studied and can isolate the effect of the independent variable on the dependent variable, whereas in an observational study, the researcher cannot control or manipulate variables, and thus cannot establish a cause-and-effect relationship between variables.

Also, in an experiment, participants are usually randomly assigned to different conditions, while in an observational study, participants are typically observed in their natural setting without any manipulation. This allows for more control and precision in an experiment, but also means that the results may not be as applicable to real-world situations as those from an observational study.

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With what speed should a projectile be launched if it’s to cover a maximum range of 82.5m and g =9.8m/s2

Answers

R = (v2/g) * sin(2) is a formula for calculating the range of a projectile propelled at an angle of with an initial speed of v. G is the acceleration caused by gravity.

How can I determine the widest horizontal range?

R = 2 v () () g, s I n c o s can be used to compute the horizontal range, R, of a projectile thrown from the same initial and final vertical displacement. where v is the projectile's initial speed, is its launch angle (measured above horizontal), and g is gravity's constant.

What is the projectile motion's maximum horizontal distance formula?

As t=0 denotes the initial time and we know that the bullet travels a finite horizontal distance sx, the right answer would be t=2using.

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When an object speeds up, it has a? 7._______

Answers

When an object speeds up, it has a positive acceleration

What is Positive acceleration?

Positive acceleration is the rate at which an object's speed increases over time. It is measured in distance units per time squared (m/s2) and is the result of a net force being applied to an object.

Positive acceleration indicates that an object is accelerating in the same direction as the applied force. When a net force is applied to an object, it changes the velocity of the object in the same direction as the force. The object's velocity will continue to increase until the net force is equal to zero.

At this point, the object is said to be moving at a constant velocity. Positive acceleration occurs when the net force acting on an object is greater than zero, resulting in an increase in the object's speed. This increase in speed is known as a positive acceleration.

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