A. The number of moles of water that were absorbed is 0.094 mole
B. The percentage of water in the hydrate is 25.4%
1. How do i determine the mole of water?The number of mole water absorbed can be obtain as follow:
Mass increase = 1.70 grams Mass of water = Mass increase = 1.70 grams Molar mass of water = 18 g/mol Mole of water =?Mole = mass / molar mass
Mole of water = 1.70 / 18
Mole of water = 0.094 mole
B. How do i determine the percentage of water?We can obtain the percentage of water as follow:
Mass of water = 1.70Mass of anhydrous = 5.00 gramsMass of hydrate = 11.7 + 5 = 6.7 gramsPercentage of water =?Percentage of water = (mass of of water / mass of hydrate) × 100
Percentage of water = (1.7 / 6.7) × 100
Percentage of water = 25.4%
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What is the purpose of sulfuric acid in a Fischer esterification reaction?
Sulfuric acid is added to Fischer's esterification reaction as an acid catalyst to increase the pace of the reaction while also going about as a drying-out specialist.
The Fischer esterification is an acid-catalyzed harmony reaction. The reaction proceeds slowly and adding sulfuric acid increases the pace of the reaction. Concentrated sulfuric acid is used to give the greatest yield to the item.
Fischer esterification or Fischer-Speier esterification is a special sort of esterification by refluxing a carboxylic acid and a liquor in the presence of an acid catalyst. The reaction was first described by Emil Fischer and Arthur Speier in 1895. Fischer esterification is a natural reaction used to change a carboxylic acid and a liquor over completely to an ester using a strong acid catalyst. It is also known as Fischer-Speier Esterification.
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what is the mass of 6.02×1022 6.02 × 10 22 atoms of argon?
Answer:
3.6 g
Explanation:
No. of moles = No. of atoms / Avogadro's No.
= 6.02 × 10^22 / 6.02 × 10^23
= 0.1 moles of argon
No. of moles = mass/ molar mass
molar mass of argon = 36 g/mol
Therefore, mass of argon = No. of moles × molar mass
= 0.1 × 36
= 3.6 g of argon
why must some solid remain in contact with a solution of a sparingly soluble salt in order to ensure equilibrium?
An ester is mixed with LiNHCH3 in order to perform a SNAc mechanism. What is the LUMO in this reaction?A. N p orbitalB. C-N σ bondC. C-O σ* bondD. C-O π* bond
Correct option is option C, C-O σ* bond.
Let's discuss it further below.
SNAc is an acronym for substitution nucleophilic acyl cyclic mechanism. The SNAc mechanism describes a nucleophilic substitution reaction in which an acyl group is transferred between two molecules, forming a cyclic intermediate.
In this reaction, the LUMO (lowest unoccupied molecular orbital) is the antibonding molecular orbital of the C-O σ bond, represented as C-O σ*.
This is because the LUMO is the orbital that accepts electrons during the nucleophilic attack, and the C-O σ* bond is the antibonding orbital involved in the breaking of the bond between the carbonyl carbon and the oxygen of the ester. Therefore, the correct answer is option C, C-O σ* bond.
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a polystyrene molecule has a molar mass of 18,000 g/mol. calculate the number of monomer units (the degree of polymerization) for this molecule.
This polystyrene molecule is roughly 173 percent polymerized.
What is the polymerization formula?Multiply the molecular weight of the monomer by the polymer's molecular mass. Tetrafluoroethylene, for instance, has a molecular mass of 1,20,000; its degree of polymerization is computed as 1,20,000 / 100 = 1,200. Hence, 1,200 is the degree of polymerization.
A polymer called polystyrene is created by repeating units of styrene monomers. By dividing the molar mass of the styrene monomer by the quantity of monomer units (degree of polymerization) present in the polymer, one may get the molar mass of polystyrene, which is 18,000 g/mol.
Let's call the styrene monomer's molar mass M. Then, we may create the following equation:
18,000 g/mol = M × n
where n is the degree of polymerization (the number of monomer units).
Rearranging the equation, we can solve for n:
n = 18,000 g/mol ÷ M
The periodic chart shows the molar mass of styrene as the total of the atomic masses of its component elements as follows:
M(styrene) = 104.15 g/mol (28.05 g/mol for carbon x 8 + 1.01 g/mol for hydrogen x 8)
When we enter this number into the equation, we obtain:
n = 18,000 g/mol ÷ 104.15 g/mol ≈ 173
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A compound is composed of 79.4% carbon, 8.9% hydrogen, and 11.7% oxygen by weight. If it has a molar mass of 272 g/mol, what is its molecular formula?
what is the mass percent of chlorine in iron(ii) chloride?
The mass percent of chlorine in Iron(II) chloride is 55.93%.
Iron(II) chloride is a chemical compound that has the formula FeCl₂. It is also known as ferrous chloride. Iron(II) chloride is an ionic compound. It is made up of positively charged iron ions (Fe2+) and negatively charged chloride ions (Cl−).The formula mass of FeCl₂ can be calculated as follows:
Formula mass of FeCl₂ = Atomic mass of Fe + (Atomic mass of Cl × 2)
Formula mass of FeCl₂ = 55.85 + (35.45 × 2) = 126.75.
The mass percent of chlorine in Iron(II) chloride can be calculated using the following formula:
Mass percent of chlorine = (Mass of Cl in FeCl₂ ÷ Formula mass of FeCl₂) × 100%
The mass of chlorine in one mole of FeCl₂ is equal to the product of the number of chlorine atoms in one mole of FeCl₂ and the atomic mass of chlorine.The number of chlorine atoms in one mole of FeCl₂ is 2, and the atomic mass of chlorine is 35.45.
Mass of Cl in FeCl₂ = Number of Cl atoms × Atomic mass of Cl
Mass of Cl in FeCl₂ = 2 × 35.45 = 70.9
Now, let's substitute the mass of chlorine and the formula mass of FeCl₂ into the formula to calculate the mass percent of chlorine. Mass percent of chlorine = (Mass of Cl in FeCl₂ ÷ Formula mass of FeCl₂) × 100%
Mass percent of chlorine = (70.9 ÷ 126.75) × 100% = 0.5593 × 100% = 55.93%.
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g part d: trans-1,2-dibromocyclopentane - construct a model of trans-1,2-dibromocyclopentane and its mirror image (use the models from part c). 1. how many carbons in this compound are chiral, bonded to four different groups? 2. are the molecules superimposable? 3. does a plane of symmetry exist in the molecule? 4. can this compound exist as a pair of enantiomers?
1) The structure of the compound shows that two carbons are bonded and chiral,
2) they are not superimposable and
3) no plane of symmetry exists between them.
4) Yes, trans-1,2-dibromocyclopentane can exist as a pair of enantiomers.
To construct a model of trans-1,2-dibromo cyclopentane and its mirror image, the structure of the compound is need to be known. Here's the structural formula of trans-1,2-dibromocyclopentane:
Br H
| |
Br H
\ /
C=C
| |
C-C
| |
C-C
| |
C-C
| |
H H
There are two carbons in trans-1,2-dibromocyclopentane that are chiral, bonded to four different groups. They are the two carbons in the cyclopentane ring that are not part of the double bond.
No, the molecules are not superimposable. If we try to align the two molecules, we'll find that the bromine atoms on one molecule will not align with the hydrogen atoms on the other molecule.
No, there is no plane of symmetry in the molecule. If we try to draw a plane that would divide the molecule into two equal halves, we'll find that it is not possible without cutting through at least one of the chiral carbons.
Yes, trans-1,2-dibromocyclopentane can exist as a pair of enantiomers. Since there are two chiral carbons in the molecule, there are four possible stereoisomers. However, since the molecule has a plane of symmetry, two of these stereoisomers are identical to their mirror image, and therefore achiral. The remaining two stereoisomers are enantiomers, meaning they are mirror images of each other and cannot be superimposed.
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A 5.0 l vessel holds 3.0 mol n2, 2.0 mol f2, and 1.0 mol h2 at 273 k. what is the partial pressure of fluorine? a. 453 kpa b. 907 kpa c. 1,361 kpa d. 2,722 kpa
The correct option is a. 453 kPa
To find the partial pressure of fluorine in the given mixture of gases, we need to use the ideal gas law, which relates the pressure (P), volume (V), number of moles (n), and temperature (T) of a gas.
PV = nRT
where R is the gas constant.
First, we need to calculate the total number of moles of gas in the vessel:
[tex]n_t_o_t_a_l[/tex] = [tex]n_N[/tex]₂ + [tex]n_F[/tex]₂ + [tex]n_H[/tex]₂
[tex]n_t_o_t_a_l[/tex] = 3.0 mol + 2.0 mol + 1.0 mol
[tex]n_t_o_t_a_l[/tex] = 6.0 mol
Next, we need to calculate the total pressure of the gas mixture using the ideal gas law:
[tex]P_t_o_t_a_l[/tex]= ([tex]n_t_o_t_a_l[/tex] * R * T) / V
where T = 273 K and V = 5.0 L. The gas constant R has a value of 8.31 J/mol K.
[tex]P_t_o_t_a_l[/tex]= (6.0 mol * 8.31 J/mol K * 273 K) / 5.0 L
[tex]P_t_o_t_a_l[/tex] = 269.9 kPa
Now, we can use Dalton's law of partial pressures, which states that the total pressure of a mixture of gases is equal to the sum of the partial pressures of the individual gases:
[tex]P_t_o_t_a_l[/tex]= [tex]P_N[/tex]₂ + [tex]P_F[/tex]₂ + [tex]P_H[/tex]₂
We are given the number of moles of each gas, so we can calculate the mole fraction of fluorine:
[tex]X_F[/tex]₂ = n_F₂ / n_total
[tex]X_F[/tex]₂ = 2.0 mol / 6.0 mol
[tex]X_F[/tex]₂ = 0.333
The mole fraction of fluorine is 0.333, so we can use it to calculate the partial pressure of fluorine:
[tex]P_F[/tex]₂ = [tex]X_F[/tex]₂* [tex]P_t_o_t_a_l[/tex]
[tex]P_F[/tex]₂ = 0.333 * 269.9 kPa
[tex]P_F[/tex]₂= 90.0 kPa
Therefore, the partial pressure of fluorine in the mixture of gases is 90.0 kPa or 0.90 atm.
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calcium reacts with sulfur (s8) forming calcium sulfide. what is the theoretical yield (g) of cas(s) that could be prepared from 1.94 g of ca(s) and 3.40 g of sulfur(s)?
The theoretical yield (g) of `CaS` that could be prepared from `1.94 g` of `Ca(s)` and `3.40 g` of `S8` is `0.958 g`.
Mass of calcium (Ca) = 1.94 g
Mass of sulfur (S) = 3.40 g
The reaction is,
`Ca(s) + S8 -> CaS(s)`
Molar mass of Ca = 40 g/mol
Molar mass of S8 = 8 × 32.06 g/mol = 256.48 g/mol
As per the reaction 1 mol of Ca reacts with 1 mol of S8 to yield 1 mol of CaS. So, from 1 mol of Ca, we get 1 mol of CaS. Hence, from `40 g` of Ca, we get `CaS of 80 g`.
Now, calculating the number of moles of Ca, we have
`(1.94 g)/(40 g/mol)`= `0.0484 mol`
Calculating the number of moles of S, we have
`(3.40 g)/(256.48 g/mol)`= `0.01326 mol`
From the balanced equation, it is seen that 1 mole of Ca reacts with 1 mole of S to form 1 mole of CaS. Since S is the limiting reactant, 0.01326 moles of CaS can be obtained from 0.01326 moles of S. 1 mole of CaS weighs
40 + 32.06 = 72.06 g.
So, `0.01326 mol` of CaS weighs `0.958 g`. Hence, the theoretical yield of `CaS` is `0.958 g`.
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When a diprotic acid is titrated with a strong base, and the Ka1 and Ka2 are significantly different, then the pH vs. volume plot of the titration will have
A. one equivalence point.
B. a pH of 7 at the equivalence point.
C. two distinct equivalence points
D. two equivalence points below 7.
E. no equivalence point
When a diprotic acid is titrated with a strong base, and the Ka1 and Ka2 are significantly different, then the pH vs. volume plot of the titration will have: two distinct equivalence points. The answer is C.
There are two distinct steps in the titration curve, the first equivalence point is the point at which the base has reacted with all of the H+ ions from the first acidic hydrogen, while the second equivalence point is the point at which the base has reacted with all of the H+ ions from the second acidic hydrogen.
The pH at the first equivalence point will be less than 7, and the pH at the second equivalence point will be greater than 7, indicating that the solution is acidic for the first equivalence point and basis for the second equivalence point.
The Ka1 and Ka2 values for diprotic acids are typically different because the first hydrogen ion is more strongly bound to the molecule than the second hydrogen ion, resulting in different dissociation constants for each hydrogen ion.
Therefore, the pH vs. volume plot of the titration of a diprotic acid with a strong base will have two distinct equivalence points if Ka1 and Ka2 are significantly different.
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Hydrogen peroxide is a compound made from two elements: hydrogen and oxygen. Water is also a compound made from hydrogen and oxygen. What makes these two compounds different?
Pls help!!
Answer:
Explanation:
Hydrogen peroxide (H2O2) and water (H2O) are both compounds made up of hydrogen and oxygen, but they have different chemical structures and properties.
Water is a simple compound made up of two hydrogen atoms and one oxygen atom that are covalently bonded together. Water is a polar molecule, which means that it has a partial positive charge on the hydrogen atoms and a partial negative charge on the oxygen atom. This polarity allows water molecules to interact with each other and other polar substances, making it an excellent solvent for many substances.
Hydrogen peroxide, on the other hand, is a compound made up of two hydrogen atoms and two oxygen atoms that are covalently bonded together. The two oxygen atoms are bonded together in a single covalent bond, while the other oxygen atom is bonded to one of the hydrogen atoms. Hydrogen peroxide is a highly reactive and unstable compound that readily decomposes into water and oxygen gas. It is often used as a disinfectant or bleaching agent due to its strong oxidizing properties.
In summary, the main differences between hydrogen peroxide and water are their chemical structures and properties. Water is a simple, stable, and polar molecule, while hydrogen peroxide is a more complex and reactive compound with oxidizing properties.
you need a 60% alcohol solution. on hand, you have a 375 ml of a 40% alcohol mixture. you also have 85% alcohol mixture. how much of the 85% mixture will you need to add to obtain the desired solution?
We need to add 300 mL of the 85% alcohol mixture to the 375 mL of the 40% alcohol mixture to obtain 675 mL of a 60% alcohol solution.
Let x be the volume (in mL) of the 85% alcohol mixture that we need to add.
To obtain a 60% alcohol solution, we need to use the following equation, which states that the amount of pure alcohol in the final mixture is equal to the sum of the amounts of pure alcohol in each of the initial mixtures:
0.40(375) + 0.85x = 0.60(375 + x)
Simplifying and solving for x, we get:
150 + 0.85x = 225 + 0.60x
0.25x = 75
x = 300
Therefore, we need to add 300 mL of the 85% alcohol mixture to the 375 mL of the 40% alcohol mixture to obtain 675 mL of a 60% alcohol solution.
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if the resulting solution has a volume of 1.7 l , what is the minimum mass of caso4(s) needed to achieve equilibrium?
The minimum mass of [tex]CaSO_{4}[/tex](s) needed to achieve equilibrium in a 1.7 L solution is approximately 4.08 grams.
How to determine the minimum mass required to achieve equilibrium?Step 1: Find the solubility of [tex]CaSO_{4}[/tex] in water at the given temperature.
The solubility of [tex]CaSO_{4}[/tex] in water at room temperature is approximately 2.4 grams per liter (g/L).
Step 2: Calculate the amount of [tex]CaSO_{4}[/tex] that will dissolve in 1.7 L of water.
Use the solubility value from Step 1:
Amount of [tex]CaSO_{4}[/tex] = Solubility × Volume
Amount of [tex]CaSO_{4}[/tex] = 2.4 g/L × 1.7 L
Amount of [tex]CaSO_{4}[/tex]4 ≈ 4.08 grams
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introduction: the polarity of molecules give rise to the forces that act between them. these intermolecular forces, or imfs, affect many physical properties including boiling point, solubility, viscosity, and surface tension. question: how does polarity affect the forces between molecules? observe: select the show polar molecules inset checkbox. what do you notice?
When the "show polar molecules" inset checkbox is selected, polar molecules are highlighted in a different color from nonpolar molecules. This allows us to observe the effect of polarity on intermolecular forces between molecules.
Polar molecules have a permanent dipole moment due to the electronegativity difference between the atoms in the molecule. This means that there is an uneven distribution of electrons, with one end of the molecule being more negative (due to the presence of a lone pair of electrons or a more electronegative atom) and the other end being more positive.
The presence of these dipoles results in the formation of dipole-dipole interactions, which are stronger than the London dispersion forces that nonpolar molecules experience. The greater the polarity of a molecule, the stronger the dipole-dipole interactions will be.
Therefore, when observing the polar molecules inset, we can see that polar molecules tend to be clustered together, forming stronger intermolecular forces than nonpolar molecules. This clustering can lead to higher boiling points, increased solubility in polar solvents, higher viscosity, and higher surface tension due to the stronger intermolecular forces between molecules.
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How many grams of oxygen are there in a 50L gas cylinder at 21 degrees Celsius and a pressure of 15. 7atm
Answer:
It's 1.0407 Kilograms of oxygen (O2) in that container
Explanation:
according to ideal gas law:
[tex]PV = nRT[/tex]
P: pressure, V: volume, n: moles, R: gas constant = 0.0821, T: temperature in Kelvin
Temperature in Kelvin = Temperature in Celsius + 273
Gas constant (R) is changed by changing pressure units (while using atm, R = 0.0821 atm•L/mol•K )
by substituting with given data:
[tex]15.7 * 50 = n*0.0821*(21+273)[/tex]
[tex]n = \frac{50*15.7}{0.0821 * 294} = 32.522 mol[/tex]
So, O2 mass (Molar mass of O2 = 32 g/mol) = 32.522 * 32 = 1040.709 grams = 1.0407 kilograms
How many signals would be present in the 'HNMR? O=O 6 ,4 ,5, none of the above
The given compound O=O does not have any hydrogen atoms, so it will not produce any signals in an HNMR spectrum. Therefore, the correct answer is "none of the above".
In NMR spectroscopy, signals appear as peaks in a spectrum that correspond to the resonant frequency of the hydrogen atoms in a molecule. The number of signals produced in an HNMR spectrum is determined by the number of unique sets of chemically equivalent hydrogen atoms in a molecule.
Hence, the absence of hydrogen atoms in the O=O compound means that there will be no signals produced in an HNMR spectrum.
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When treated with base, the following compound undergoes an intramolecular aldol reaction to give a product containing a ring. Propose a structure for this product. base C11H180 + H20 . . • Consider EIZ stereochemistry of alkenes. • Do not show stereochemistry in other cases. • If there is more than one major product possible, draw all of them. Draw organic products only • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. •
Separate multiple products using the + sign from the drop-down menu.
The product obtained after the intramolecular aldol reaction of 2-pentanone (C5H10O) with a strong base is a six-membered cyclic ring with a double bond and an alcohol group.
When treated with a base, the compound C11H18O undergoes an intramolecular aldol reaction to give a product containing a ring. To propose a structure for this product, follow these steps:
Identify the carbonyl group (C=O) in the compound, which will act as the electrophile in the reaction.Identify the alpha-hydrogen adjacent to the carbonyl group, which will act as the nucleophile upon deprotonation by the base.Deprotonate the alpha-hydrogen using the base to form an enolate ion.Perform a nucleophilic attack by the enolate ion on the carbonyl group within the same molecule, resulting in the formation of a new C-C bond.Tautomerize the product, if necessary, to give the final aldol product with an alkene group (considering E/Z stereochemistry of alkenes).If there is more than one major product possible, draw all of them.The product structure is shown below: Thus, the product obtained after the intramolecular aldol reaction of 2-pentanone (C5H10O) with a strong base is a six-membered cyclic ring with a double bond and an alcohol group.
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coitünsup Isolmer
4. Sulfur dioxide (SO₂) is a compound used to preserve grapes. How many moles
are in a 23.8 g sample of sulfur dioxide? The molar mass of SO₂ is 64 g/mol. Use
dimensional analysis, show all work to receive full credit. (4 pts)
a. 0.37 mol SO₂
b. 1.2 mol SO₂
c. 0.5 mol SO₂
d. 44 mol SO₂
Answer:
a. 0.37 mol SO₂
Explanation:
The number of moles in a sample can be calculated by dividing the mass of the sample by its molar mass. In this case, the number of moles of SO₂ in a 23.8 g sample would be:
23.8 g SO₂ × (1 mol SO₂ / 64 g SO₂) = 0.37 mol SO₂
So the correct answer is (a) 0.37 mol SO₂.
write a balanced net ionic equation for the neutralization of equimolar amounts of hno2 and koh. indicate whether the ph after neutralization is greater than, equal to, or less than 7. values of ka and kb are listed in appendix c.
The concentration of OH- after neutralization is greater than the concentration of HNO₂, and therefore the pH of the solution is greater than 7.
The balanced net ionic equation for the neutralization of equimolar amounts of HNO₂ and KOH is:
HNO₂ (aq) + OH- (aq) → NO₂⁻ (aq) + H₂O (l)
After the neutralization, the resulting solution contains the NO₂⁻ ion, which is the conjugate base of HNO₂. Since HNO₂ is a weak acid (with a pKa of 3.15, according to appendix c), the NO₂⁻ ion is a weak base. The reaction of NO₂⁻- with water is:
NO₂⁻ (aq) + H₂O (l) ⇌ HNO₂ (aq) + OH⁻- (aq)
The equilibrium constant for this reaction is Kb = [HNO₂][OH-] / [NO₂⁻].
Since NO₂⁻ is a weak base, the concentration of OH- after neutralization is greater than the concentration of HNO₂, and therefore the pH of the solution is greater than 7.
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what are the reduced mass and moment of inertia of 23 na35 cl? the equilibrium internuclear distance re is 236 pm. whatarethevaluesofe forthestateswithj 1andj 2?
The reduced mass of NaCl= 14.45 amu.
moment of inertia= [tex]= 0.809 \times 10^{-43} kg m^2[/tex]
E value For J=1 is E(1) = 0.360 [tex]cm^{-1}[/tex] and for J=2 is E(2) = 0.720[tex]cm^{-1}[/tex]
To find the reduced mass and moment of inertia of a diatomic molecule like NaCl, we need to know the masses of the two atoms (Na and Cl) and the equilibrium internuclear distance.
The mass of Na is approximately 23 atomic mass units (amu), while the mass of Cl is approximately 35 amu.
The reduced mass of the system can be calculated using the following formula:
μ [tex]= m_1m_2 / (m_1 + m_2)[/tex]
where [tex]m_1[/tex] and [tex]m_2[/tex] are the masses of the two atoms.
μ = (23 amu x 35 amu) / (23 amu + 35 amu)
= 14.45 amu
The moment of inertia of a diatomic molecule is given by the formula:
[tex]I = \mu r^2[/tex]
where μ is the reduced mass of the system and r is the internuclear distance.
[tex]I = 14.45 amu \times (236 pm)^2[/tex]
[tex]= 0.809 \times 10^{-43} kg m^2[/tex]
To find the values of E for the states with J=1 and J=2, we need to know the rotational constant (B) of the molecule. The rotational constant is related to the moment of inertia by the formula:
[tex]B = h / (8\pi^2cI)[/tex]
where h is Planck's constant, c is the speed of light, and I is the moment of inertia.
[tex]B = (6.626\times 10^{-34} J s) / (8\pi^2\times 3\times 10^8 m/s \times0.809\times 10^{-43} kg m^2)[/tex]
[tex]= 0.180 cm^{-1}[/tex]
The energy of a rotational state with quantum number J is given by the formula:
E(J) = B J(J+1)
For J=1, E(1) = 0.360 [tex]cm^{-1}[/tex]
For J=2, E(2) = 0.720[tex]cm^{-1}[/tex]
Note: The values of E are very small because they correspond to rotational transitions, which typically have lower energies than electronic transitions.
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a buffer solution contains 0.11 mol of acetic acid and 0.14 mol of sodium acetate in 1.00 l. the ka of acetic acid is 1.8 x 10-5. part a: what is the ph of this buffer? round your answer to two places past the decimal.
The buffer solution has a pH of 4.85.
To determine the pH of the buffer solution, we first need to calculate the concentration of both the conjugate acid (acetic acid) and conjugate base (sodium acetate) in the solution. Using the given information, we can calculate the concentrations as follows:
[acetic acid] = 0.11 mol/1.00 L = 0.11 M
[sodium acetate] = 0.14 mol/1.00 L = 0.14 M
Next, we need to determine the pKa of acetic acid, which is given as 1.8 x 10⁻⁵. We can use the Henderson-Hasselbalch equation to calculate the pH of the buffer solution:
pH = pKa + log([A⁻]/[HA])
where [A-] is the concentration of the conjugate base and [HA] is the concentration of the conjugate acid.
Substituting the values into the equation, we get:
pH = 4.74 + log(0.14/0.11) = 4.85
Therefore, the pH of the buffer solution is 4.85.
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1 mole of Powdered Aluminum Hydroxide Al(OH)3, reacts with 3 moles of aqueous hydrochloric Acid (HCl)to produce 1 mole aqueous Aluminum Chloride (AlCl3) and 3 moles of water.
the reaction would result in 1 mole of aluminium chloride and 3 moles of water from a starting mole of 1 mole of powdered aluminium hydroxide, which would require 3 moles of hydrochloric acid to thoroughly react with it.
What is the balanced chemical equation?The balanced chemical equation for the reaction between powdered aluminum hydroxide (Al(OH)3) and hydrochloric acid (HCl) is:
[tex]2 Al(OH)3 + 6 HCl \rightarrow 2 AlCl3 + 6 H2O[/tex]
This equation shows that 2 moles of aluminum hydroxide react with 6 moles of hydrochloric acid to produce [tex]2[/tex] moles of aluminum chloride and [tex]6[/tex] moles of water.
The mole ratio between aluminum hydroxide and hydrochloric acid is 1:3, and the mole ratio between aluminum chloride and water is also 1:3, as per the stoichiometry of the balanced equation.
Therefore, if you start with 1 mole of powdered aluminum hydroxide, you would need 3 moles of hydrochloric acid to completely react with it, and the resulting reaction would produce 1 mole of aluminum chloride and 3 moles of water.
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hexaneandair enterthe combustionchamberof a well-insulatedgasturbine engineat 25oc. whatamount of excessair willberequired if the temperature ofthe productsis to belimited to 825oc?
We need 32.63% less air than the stoichiometric amount to limit the temperature of the products to 825°C.
To solve this problem, we need to use the stoichiometry of the combustion reaction of hexane with air. The balanced equation for the combustion of hexane is:
2 C6H14 + 19 O2 → 12 CO2 + 14 H2O
This equation tells us that for every 2 moles of hexane (C6H14) that react, we need 19 moles of oxygen (O2) to react completely. However, the problem asks for the amount of excess air, which means we need to add more than the stoichiometric amount of oxygen to ensure complete combustion and limit the temperature of the products.
To find the amount of excess air, we can use the air-fuel ratio (AFR), which is the ratio of the mass of air to the mass of fuel (in this case, hexane) required for complete combustion. The AFR for hexane is:
AFR = (mass of air) / (mass of hexane)
Using the molecular weights of hexane and air, we can convert the AFR to a molar ratio:
AFR = (moles of air) / (moles of hexane)
We can then use this molar ratio to calculate the amount of excess air required. Let's start by calculating the AFR:
Mass of hexane = 1 mole x 86.18 g/mol = 86.18 g
Mass of air = 19 moles x 28.96 g/mol = 550.24 g
AFR = 550.24 g / 86.18 g = 6.39
This tells us that we need 6.39 moles of air for every mole of hexane to ensure complete combustion. To limit the temperature of the products to 825°C, we need to add excess air. The amount of excess air can be expressed as a percentage of the theoretical amount of air required:
Excess air = ((actual moles of air) - (stoichiometric moles of air)) / (stoichiometric moles of air) x 100%
We can calculate the actual moles of air required by multiplying the AFR by the moles of hexane:
Actual moles of air = 6.39 x 1 mole = 6.39 moles
To calculate the stoichiometric moles of air required, we use the balanced equation:
2 C6H14 + 19 O2 → 12 CO2 + 14 H2O
For 1 mole of hexane, we need 19/2 moles of oxygen, or 9.5 moles of air:
Stoichiometric moles of air = 9.5 moles
Plugging in the values, we get:
Excess air = ((6.39 moles) - (9.5 moles)) / (9.5 moles) x 100% = -32.63%
This means that we actually need 32.63% less air than the stoichiometric amount to limit the temperature of the products to 825°C. However, this result is negative, which means it doesn't make physical sense. It's likely that there is an error in the problem statement or that some additional information is needed to solve the problem correctly.
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The Ostwald Process is used to make Nitric Acid in a one step process where ammonia is burnt in 900 degrees Celsius at 10 atm in the presence of platinum/rhodium catalyst. Explain:
(a) Why a temperature of 900 degrees Celsius is used.
(b) Why is a pressure of 10 atm used?
(c) Economic consideration.
Nitric acid is created by the Ostwald process. Platinum is utilised as a catalyst. Nowadays, catalysts consisting of 90% platinum and 10% rhodium are in use. The temperature is 800 °C.
What key byproduct is produced during the ammonia oxidation steps of the Ostwald nitric acid manufacturing process?The first phase in Ostwald's method for producing nitric acid includes oxidising ammonia gas with oxygen gas to produce nitric oxide gas and steam.
How does the Ostwald process produce nitric acid? What conditions are necessary to obtain the Optimum product?Significant steps in the Ostwald process: A catalytic chamber is filled from the top with a 1:10 combination of ammonia and clean, filtered air.
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True/false....
The effective nuclear charge acting on an electron is larger than the actual nuclear charge.
Effective nuclear charge is always lesser than the actual nuclear charge because of the inner core electrons shielding outer core electrons. so, the statement given is false.
The effective nuclear charge is said to be the the actual amount of positive charge experienced by an electron in a multi-electron atom. It is defined as the net positive charge pulling these electrons towards the nucleus. The stronger the pull on the outermost electrons that is valence electrons towards the nucleus, the higher the effective nuclear charge.
It is the magnitude of positive charge in an atom from the pull on the valence electrons towards the positively charged nucleus. An increase in atomic number associated with a decrease in atomic radius will result in a higher effective nuclear charge of an electron. It increases with increasing atom number and with decreasing atomic radius as you go across a period.
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Xenon forms several compounds with oxygen and fluorine. It is the most reactive non-radioactive noble gas because a. Its large radius allows oxygen and fluorine to bond without being crowded. B. It has the highest electronegativity of these noble gases. C. It has the highest electron affinity of these noble gases. D. Its effective nuclear charge is lower than the other noble gases. E. It has the lowest ionization energy of these noble gases
Xenon is the most reactive non-radioactive noble gas because it has the lowest ionization energy among the noble gases.
This means that it requires the least amount of energy to remove an electron from a xenon atom, making it more likely to form chemical bonds with other elements, such as oxygen and fluorine.
Xenon also has a relatively large atomic radius, which allows oxygen and fluorine atoms to bond with it without being too crowded. This is important because the noble gases typically do not form chemical bonds with other elements due to their stable electron configurations and small atomic radii.
Additionally, xenon has a higher electronegativity and electron affinity compared to other noble gases, which also contributes to its reactivity. Electronegativity refers to an atom's ability to attract electrons, while electron affinity refers to an atom's tendency to accept electrons. Both of these properties can make an atom more likely to form chemical bonds with other elements.
Overall, the combination of xenon's low ionization energy, large atomic radius, high electronegativity, and electron affinity make it a relatively reactive noble gas, capable of forming compounds with oxygen and fluorine.
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write a set of possible quantum numbers (n, l , m l, m s) for an electron in a 7d {x^2-y^2} orbital.
The set of quantum numbers for an electron in a 7d {x²-y²} orbital would be:
n = 7, l = 2, m_l = ±2, m_s = ±1/2
The principal quantum number, n, describes the energy level of the electron, which in this case is 7 since the electron is in the seventh energy level. The angular momentum quantum number, l, describes the shape of the orbital, which for a d orbital can range from 0 to 2. The magnetic quantum number, m_l, describes the orientation of the orbital in space, which for a d orbital can range from -l to +l. Since the orbital in question is {x²-y²}, it has two lobes that lie along the x- and y-axes and two lobes that lie along the z-axis, which corresponds to m_l = ±2. Finally, the spin quantum number, m_s, describes the direction of the electron's spin, which can be either +1/2 or -1/2.
It's worth noting that electrons in the same orbital must have different spin quantum numbers, according to the Pauli exclusion principle. Therefore, the two electrons in the 7d {x²-y²} orbital would have opposite spin quantum numbers, i.e. one would have m_s = +1/2 and the other would have m_s = -1/2.
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a 9.5 l container at 1.7 atm has 0.50 mol c3h6, a van der waals gas with . what is the temperature (k)?
A 9.5 l container at 1.7 atm has 0.50 mol C₃H₆ , a vander waal gas, the temperature will be 393.65 K.
The formula of ideal gas equation is
PV= nRT
where P is the pressure of the gas, V is the volume of the gas, n is the no of moles of gas, R is gas constant and T is the temperature.
Here,
P=1.7 atm
V= 9.5 l
n= 0.50 mol
Converting 1.7 atm into Kpa
P= 1.7 atm × 101.325 Kpa/1 atm
P=172.2525 KPa
Putting these values in the equation PV=nRT
172.2525 KPa × 9.5 l = 0.5 mol×8.314 l.KPa/mol.K.T
⇒1636.39875 l. KPa= 4.157 l.KPa/ K.T
⇒T= 393.6489
⇒T= 393.65 approx
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