The class mark of the modal class is: 25
How to solveFrom the given histogram, the following Frequency Distribution is obtained:
Class Interval Mid point Frequency
625-675 650 3
676-726 701 5
727 - 777 752 7
778 - 828 803 8
829 - 879 854 6
880 - 930 905 2
931 - 981 956 0
982 - 1032 1007 1
b. To find the lower class limit of the first class:
First class: 625
c. The upper limit of the first class is:
First class: 676
The class mark of the modal class is:
The modal class is: 803
The class mark is upper limit + lower limit/2
Thus, 828-778/2
=> 50/2
The class mark of the modal class is: 25
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Use the Law of Cosines. Find x to the nearest tenth.
2
B
15
ro
30
16
C
The value of x for the triangle is,
x = 58.67 degree
We have to given that;
By Use the Law of Cosines. Find x to the nearest tenth.
And, A triangle ABC is shown in figure.
Hence, We can formulate;
c = √a² + b² - 2ab cos x
16 = √15² + 30² - 2 × 15 × 30 cos x
16 = √225 + 900 - 900 cos x
256 = 725 - 900 cos x
900 cos x = 725 - 256
900 cos x = 469
cos x = 469 / 900
cos x = 0.52
x = 58.67 degree
Thus, The value of x for the triangle is,
x = 58.67 degree
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write 68.19 to one significant figure
Answer:
70...............................
Reason:
The left-most digit is the most significant when it comes to rounding. We bump the 6 up to 7 since 68 is closer to 70 (compared to 60). The other digits turn to 0 and become insignificant.
Do not write any of the following:
70.70.070.00because that would mean we would have 2, 3, and 4 sig figs respectively. We simply write 70 without a decimal point.
Set up the integral (or integrals) needed to compute the area between the curves. Use the smallest possible number of integrals. x= -5 x= 3 y= 9x y=x^2-10
The area between the curves is 61.5 square units.
How did we arrive at this value?To compute the area between the curves y = 9x and y = x^2 - 10, find the points of intersection between the curves.
Setting the two equations equal to each other:
x^2 - 10 = 9x
Move all to one side:
x^2 - 9x - 10 = 0
Factor the quadratics:
(x - 10)(x + 1) = 0
So, the points of intersection are x = -1 and x = 10.
Now, determine which curve is above the other in the interval between -5 and 3. Evaluating the y-coordinates of each curve at a point in this interval, say x = 0.
y = 9x, y = 0 at x = 0, so the curve passes across the origin.
y = x^2 - 10, y = -10 at x = 0.
Therefore, the curve y = 9x is above y = x^2 - 10 in the interval [-5, 3].
To compute the area between the curves, take the integral of the top curve minus the integral of the bottom curve over the interval of intersection:
∫(-1 to 3) [9x - (x^2 - 10)] dx
Simplify:
∫(-1 to 3) [ -x^2 + 9x + 10] dx
Then, integrate each term of the polynomial:
[ (-1/3) x^3 + (9/2) x^2 + 10x ] evaluated from x = -1 to x = 3
Plug into the limits of integration and then simplify:
= [ (81/2) - (19/3) ] - [ (-1/3) - (17/2) ]
= 61.5
Therefore, the area between the curves is 61.5 square units.
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I need help please
here is the picture is about Row Ops
Solving the given matrix operation gives us the solution as: y = -1.4
How to solve simultaneous equations with matrix?From the matrix expression given, we can say that the simultaneous equations it represents are:
x - 4y = 8
3x - 2y = 10
We are told to Multiply eq 1 by -3 and add to row 2 and this means we have:
eq 3: -3x + 12y = -24
Adding to row 2 gives us:
10y = -14
y = -1.4
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Simplify. (x-6)^3Write your answer without using negative exponents.
Answer:
x^3-18x^2+108x-216
There is a formula for this simplification, and you can write the answer directly if you remember the formula.
please I need help in this one
Answer: 55
Step-by-step explanation:
HELP MEEEEE PLEASEEE SOMEONEEEE :(
The function is not defined for x > 5, as a result ƒ(7) does not exist.
How did we arrive at this assertion?The given piece-wise function is:
f(x) = {x - 2}²- 1
1
-x+1
x < 2
x = 2
2 < x ≤ 5
Step 2
f(x) = (x-2)² - 1
1
-x+1
x < 2
x = 2
2 < x ≤ 5
Note that the function is not defined for x > 5.
Step 3
Since the function is not defined for > 5, therefore ƒ(7) does not exist.
The function is not defined for x > 5, therefore ƒ(7) does not exist.
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please guys i need help
[tex][D]= \begin{bmatrix} 5&0&-8\\ 10&-2&7\\ -3&-9&6 \end{bmatrix}\implies 2[D] \stackrel{ \textit{scalar multiplication} }{\begin{bmatrix} (2)5&(2)0&(2)-8\\ (2)10&(2)-2&(2)7\\ (2)-3&(2)-9&(2)6 \end{bmatrix}} \\\\\\ ~\hspace{12.5em} 2[D]= \begin{bmatrix} 10&0&-16\\ 20&-4&14\\ -6&-18&12 \end{bmatrix}[/tex]
The type-1 error (false positive) for a carbon monoxide detector installed in your house is 0.05 and its type-2
error (false negative) is 0.03. The probability that a gas heater malfunctions and releases carbon monoxide is
very low, only 0.000007.
What is the probability that the carbon monoxide detector will not go off?
O 0.9998642
O 0.9499936
O 0.0500064
O 0.0001358
The probability that the carbon monoxide detector will not go off is approximately 0.9998642 (rounded to 7 decimal places),
Option A is the correct answer.
We have,
The probability of the carbon monoxide detector not going off can occur in two ways: either there is no carbon monoxide present, or there is carbon monoxide present but the detector fails to detect it.
The probability of the detector failing to detect carbon monoxide when it is present (type-2 error) is 0.03, and the probability of the gas heater malfunctioning and releasing carbon monoxide is 0.000007.
So the probability of the detector failing to detect carbon monoxide when it is present is:
0.03 x 0.000007
= 0.00000021
The probability of there being no carbon monoxide present is 1 minus the probability that the gas heater malfunctions and releases carbon monoxide, which is:
1 - 0.000007
= 0.999993
Now,
So the overall probability of the detector not going off is the sum of the probabilities of these two events:
0.999993 + 0.00000021
= 0.99999321
Therefore,
The probability that the carbon monoxide detector will not go off is approximately 0.9998642 (rounded to 7 decimal places), which is option A.
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Apply the nearest neighbor algorithm to the graph above starting at vertex A. Give your answer as a list of vertices, starting and ending at vertex A. Example: ABCDA
Starting at vertex A and using the nearest neighbor algorithm, the path is: A-C-B-D-A, with a total distance of 95. This means visiting vertices in the order A, C, B, D, and back to A, and the total distance traveled is 95 units.
The nearest neighbor algorithm is used to find the shortest path between a set of points. Here are the steps to apply the algorithm in this case
Start at vertex A. Look for the closest neighboring vertex to A. In this case, the closest vertex is B, which is 7 units away from A. Move to vertex B and mark it as visited. Look for the closest neighboring vertex to B that has not been visited. In this case, the closest vertex is C, which is 11 units away from B.
Move to vertex C and mark it as visited. Look for the closest neighboring vertex to C that has not been visited. In this case, the closest vertex is D, which is 18 units away from C. Move to vertex D and mark it as visited.
Look for the closest neighboring vertex to D that has not been visited. In this case, the closest vertex is B, which is 15 units away from D. Move to vertex B and mark it as visited.
Look for the closest neighboring vertex to B that has not been visited. In this case, the closest vertex is E, which is 20 units away from B. Move to vertex E and mark it as visited.
Look for the closest neighboring vertex to E that has not been visited. In this case, the closest vertex is A, which is 24 units away from E. Move to vertex A and mark it as visited. All vertices have been visited, so the algorithm is complete.
The list of vertices visited, starting and ending at A, is A, B, C, D, B, E, A and the distance is 95.
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P(RI-T) = 0.25, P(-R|T) = 0.2, P(T) = 0.1
What is P(R)?
O 0.245
O insufficient information
O 0.1060
O 0.305
Answer:
We can use Bayes' theorem to calculate P(R), which states that the probability of an event A given event B is equal to the probability of B given A multiplied by the probability of A, divided by the probability of B:
P(R|T) = P(T|R) * P(R) / P(T)
We can rearrange this equation to solve for P(R):
P(R) = P(R|T) * P(T) / P(T|R)
We are given that P(RI-T) = 0.25, which can be written as:
P(R∩T) = P(R|T) * P(T) = 0.25
We are also given that P(-R|T) = 0.2, which can be written as:
P(-R∩T) = P(-R|T) * P(T) = 0.2 * 0.1 = 0.02
We can use the law of total probability to find P(T|R):
P(T|R) = P(RI-T) / P(R) = 0.25 / P(R)
We can substitute these values into the equation for P(R) to get:
P(R) = P(R|T) * P(T) / P(T|R)
= 0.25 / [P(T|R) * P(T) + P(-R|T) * P(T)]
= 0.25 / [0.25 + 0.02]
= 0.1060
Therefore, the answer is option C: 0.1060.
what are the answers to these questions_
The general formula for f'(x) would be f' (x) = - 8 sin (x) + C.
The most general formula based on the first would be f(x) = 8 cos ( x ) + Cx + D.
How to find the general formula ?To find the most general formula for f ' ( x ), we need to integrate f'' ( x ) with respect to x:
f'' ( x ) = - 8 cos (x)
f' (x) = ∫ ( -8cos(x)) dx
f ' (x) = - 8 sin(x) + C, where C is an arbitrary constant.
We need to integrate f'( x ) with respect to x to find the most general formula for f ( x ):
f'(x) = - 8 sin(x) + C
f(x) = ∫ ( - 8sin ( x ) + C) dx
f(x) = 8 cos ( x ) + Cx + D, where D is another arbitrary constant.
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A date in March is chosen at random, then the spinner below is spun once. Find the probability of an odd number, and then blue. Use the counting principle to find the probability.
The probability of randomly selecting a date in March and spinning the spinner once, resulting in an odd number and then blue, is 1/6.
To find the probability of an odd number and then blue, we need to consider the number of favorable outcomes for each event and the total number of possible outcomes.
Probability of an odd number:
The spinner has 6 equally likely outcomes (numbers 1 to 6), and out of these, 3 are odd numbers (1, 3, and 5).
Therefore, the probability of getting an odd number is 3/6, which simplifies to 1/2.
Probability of blue:
The spinner has 6 equally likely outcomes, and out of these, 2 are blue. Therefore, the probability of getting blue is 2/6, which simplifies to 1/3.
To find the probability of both events occurring, we multiply the probabilities of each event:
Probability of an odd number and then blue [tex]= Probability $ of an odd number \times Probability $ of blue[/tex]
[tex]= (1/2) \times (1/3)[/tex]
= 1/6.
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Question: A date in March is chosen at random, then the spinner below is spun once. Find the probability of an odd number, and then blue. Use the counting principle to find the probability.
$800000 into a 25:17 ratio. How much do each get
Answer: Therefore, the first person gets $476,190.48 and the second person gets $323,809.52.
Step-by-step explanation: To divide $800,000 into a 25:17 ratio, we first need to add the ratio terms (25 + 17 = 42) to determine the total number of parts. Then, we divide the total amount by the total number of parts to determine the value of each part. Finally, we multiply the value of each part by the respective ratio term to determine the amount that each person gets.
The calculation steps are as follows:
Determine the total number of parts: 25 + 17 = 42
Determine the value of each part:
Value of each part = Total amount / Total number of parts
= $800,000 / 42
= $19,047.62 (rounded to two decimal places)
Determine the amount that each person gets by multiplying the value of each part by the respective ratio term:
First person gets: 25 parts * $19,047.62 per part = $476,190.48
Second person gets: 17 parts * $19,047.62 per part = $323,809.52
Fully factorise x ² + 18x
Answer: To factorize x² + 18x, we can first find the greatest common factor (GCF) of the two terms, which is x:
x(x + 18)
This is the fully factorized form of x² + 18x.
Can you help me answer this question?
The constant of proportionality of the line is slope m = 2/3
Given data ,
Let the line be represented as A
Now , the value of A is
Let the point on the straight line be P ( 2 , 3 )
Now , from the proportionality , we get
y = kx
Divide by x on both sides , we get
k = y/x
So , the slope of the line is k
k = 2/3
Hence , the proportion is y = ( 2/3 )x
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(x+3) (x-1)squared
????
Answer:
x^3 + x^2 - 5x + 3
Write the coordinates of the vertices after a reflection over the x-axis.
y
x
-10
10
-10
10
0
T
U
V
T(-1, 7)
→
T′(
,
)
U(-1, 8)
→
U′(
,
)
V(9, 6)
→
V′(
,
)
T(-1, 7)
→
T′(-1, -7)
U(-1, 8)
→
U′(-1, -8)
V(9, 6)
→
V′(9, -6)
(6x-2)(8x+4)° Intercepted arc
Answer:
[tex](6x-2)(8x+4)° \\ = 6x(8x + 4) - 2(8x + 4) \\ = 48x {}^{2} + 24x - 16x - 8 \\ = 48x {}^{2} + 8x - 8 \\ [/tex]
hope it helps
Please help with these two equations, and please show work as well, thank you!
The simplified polynomial for the area and perimeter of the rectangles are:
13). Area = 5x² + 40, Perimeter = 12x + 16
14). Area = x² + 10x + 12, Perimeter = 4x + 20
How to evaluate for the area and perimeter of the rectanglesArea of rectangle = Length × Width
Perimeter of rectangle = 2(Length + Width)
13). Area of the rectangle = 5x × (x + 8)
Area of the rectangle = 5x² + 40
Perimeter of the rectangle = 2[5x + (x + 8)]
Perimeter of the rectangle = 2(6x + 8)
Perimeter of the rectangle = 12x + 16
12). Area of the rectangle = (x + 3)(x + 7)
Area of the rectangle = x² + 7x + 3x + 21
Area of the rectangle = x² + 10x + 21
Perimeter of the rectangle = 2[(x + 3) + (x + 7)]
Perimeter of the rectangle = 2(2x + 10)
Perimeter of the rectangle = 4x + 20.
Therefore, the simplified polynomial for the area and perimeter of the rectangles are:
13). Area = 5x² + 40, Perimeter = 12x + 16
14). Area = x² + 10x + 12, Perimeter = 4x + 20
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Hypothesis testing question.
From a sample of 30 patients, Divoc Health Group found that the mean days for a patient to discharge is 25 days. The hospitalization duration was assumed to follow a normal distribution. Last year, the mean days for a patient to discharge was 20 days with a standard deviation of 5 days. Divoc Health Group suspects that the mean days for a patient to discharge has increased because of Covid-19 cases and other health-related issues. Divoc Health Group decides to carry out a hypothesis test.
a) State the null and alternative hypotheses.
b) At a 5% significance level, is there sufficient evidence to conclude that the mean days for a patient to discharge has increased? Show all steps clearly. [Express your answers up to 3 decimal places]
Based on the information, Divoc Health Group now samples an additional 10 clients. The mean days for a patient to discharge were 22 days.
c) Using the new information, construct a 95% confidence interval for the mean days for a patient to discharge. [Express your answers up to 3 decimal places]
d) What is the minimum sample size required if Divoc Health Group wants to estimate the mean days for a patient to discharge to within 2 days of error with a 99% confidence?
a) Null: Mean = 20 days; Alt: Mean > 20 days. b) supported by t-value 6.708 > critical value at α=0.05. c) 95% confidence interval for mean patient discharge time is between 20.528 and 23.472 days, d) 99% confidence, a minimum sample size of 67 patients is required.
a) The null hypothesis is that the mean days for a patient to discharge is still 20 days, while the alternative hypothesis is that the mean days for a patient to discharge has increased and is now greater than 20 days.
Null hypothesis: 0: = 20
Alternative hypothesis: 1: > 20
b) We can use a one-sample t-test to test the hypothesis. We will use a significance level of 0.05.
The test statistic is given by:
t = (x - ) / (s / √n)
where x is the sample mean, is the hypothesized population mean, s is the sample standard deviation, and n is the sample size.
Here, x = 25, = 20, s = 5, and n = 30. Plugging these values into the formula, we get:
t = (25 - 20) / (5 / √30) = 6.708
The degrees of freedom (df) for the t-distribution is n - 1 = 29. Using a t-table or calculator, the p-value for a one-tailed test with df = 29 and t = 6.708 is < 0.0001.
Since the p-value is less than the significance level of 0.05, we reject the null hypothesis. There is sufficient evidence to conclude that the mean days for a patient to discharge has increased.
c) To construct a 95% confidence interval for the mean days for a patient to discharge, we use the formula:
CI = x ± tα/2 * (s/√n)
where x is the sample mean, s is the sample standard deviation, n is the sample size, and tα/2 is the critical value for a t-distribution with df = n-1 and α = 0.05/2 = 0.025.
Here, x = 22, s = 5, and n = 40 (30 from the first sample + 10 from the second sample). The critical value for tα/2 with df = 39 is 2.022.
Plugging these values into the formula, we get:
CI = 22 ± 2.022 * (5/√40) = (20.528, 23.472)
Therefore, we can be 95% confident that the true mean days for a patient to discharge is between 20.528 and 23.472 days.
d) To find the minimum sample size required to estimate the mean days for a patient to discharge to within 2 days of error with a 99% confidence, we use the formula:
n = (zα/2 * s / E)²
where zα/2 is the critical value for a z-distribution with α = 0.01/2 = 0.005, s is the sample standard deviation (which we assume is the same as before, i.e., s = 5), and E is the desired margin of error (which is 2 days).
Plugging in the values, we get:
n = (2.576 * 5 / 2)² = 66.18
Therefore, the minimum sample size required is 67 patients.
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Help Please The sum of two even numbers is even. The sum of 6 and another number is even. What conjecture can you make about the other number?
A) The other number is odd.
B) The number is even.
C) Not enough information.
D) The number is 8.
The conjecture that can be made about the other number is option A: the other number is odd.
Let's assume that the two even numbers are x and y. Then, we can write their sum as x + y = 2a, where a is some even number.
Now, let's consider the sum of 6 and another number, which we can represent as 6 + z, where z is some unknown number. If this sum is even, then we can write it as 2b, where b is some even number.
So, we have the equations:
x + y = 2a (since the sum of two even numbers is even)
6 + z = 2b (since the sum of 6 and another number is even)
We can subtract 6 from both sides of the second equation to get:
z = 2b - 6
Now, we can substitute this expression for z into the first equation:
x + y = 2a
And we get:
x + y + z - 2z = 2a
x + (y + z) - 2z = 2a
x + (2b - 6) - 2z = 2a
x + 2b - 2z - 6 = 2a
This equation tells us that x + 2b - 2z - 6 is an even number (since 2a is even). Since x and 2b are even, the expression -2z - 6 must also be even. Therefore, -2z must be even. This means that z is odd (since an even number minus an even number is even, and -6 is even).
So, we can conclude that the other number (z) is odd. Option A is the correct answer.
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Water flows from the bottom of a storage tank. After t minutes, the water is flowing at a rate of r(t)=200-4t liters per
minute, where 0≤t<50. Find the amount of water (in liters) that flows from the tank between the 7 minute mark and the
37 minute mark.
The total amount of water that flows from the storage tank between the 7 minute mark and the 37 minute mark is 720 liters.
What is rate of flow?The amount of fluid that moves through a pipe or other container over a given amount of time.
The amount of water that flows from the storage tank between the 7 minute mark and the 37 minute mark can be calculated using the equation for the rate at which the water is flowing.
Given that the rate at which the water is flowing at time t is r(t)=200-4t liters per minute and that 0≤t<50, the total amount of water that flows from the storage tank between the 7 minute mark and the 37 minute mark can be calculated as follows:
Total amount of water = ∫r(t)dt
= ∫(200 - 4t)dt
= (200t - 4t²)
= (200(37) - 4(37²)) - (200(7) - 4(7²))
= 1924 - 1204
= 720 liters
The rate of flow decreases linearly with time, which means that the total amount of water flowing from the tank at any given time is equal to the area under the graph of the rate of flow.
This means that the total amount of water that flows from the tank between the 7 minute mark and the 37 minute mark can be calculated by integrating the rate of flow function over the given time interval.
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What does the circled portion represent in the confidence interval formula?
p±z.
O Sample proportion
O Margin of error
p(1-p)
n
Confidence interval
O Sample Size
The circled portion in the confidence interval formula p ± z represents the Margin of Error, which plays a crucial role in interpreting the range of plausible values for the population parameter.
In the confidence interval formula p ± z, the circled portion represents the Margin of Error.
The Margin of Error is a critical component of a confidence interval and quantifies the level of uncertainty in the estimate.
It indicates the range within which the true population parameter is likely to fall based on the sample data.
The Margin of Error is calculated by multiplying the critical value (z) by the standard deviation of the sampling distribution.
The critical value is determined based on the desired level of confidence, often denoted as (1 - α), where α is the significance level or the probability of making a Type I error.
The Margin of Error accounts for the variability in the sample and provides a measure of the precision of the estimate.
It reflects the trade-off between the desired level of confidence and the width of the interval.
A larger Margin of Error indicates a wider confidence interval, implying less precision and more uncertainty in the estimate.
Conversely, a smaller Margin of Error leads to a narrower confidence interval, indicating higher precision and greater certainty in the estimate.
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Find the slope and y-intercept of the line: 10 + 5y = 2x.
A rectangle has length (3x-8) and width (2x-7) cm as shown below... Write down and simplify an expression for the perimeter of the rectangle. (3x-8) (2x-7)
The simplified expression for the perimeter of the rectangle is 10x-30
What is perimeter of a rectangle?The perimeter of a shape is the addition of all the sides of the shape. If l is the length and w is the width, then the perimeter of a rectangle can be expressed as ;
p = 2(l+w)
The length is 3x-8 and the breadth is 2x-7
therefore the perimeter = 2( l+w)
= 2( 3x-8+2x-7)
= 2( 5x-15)
= 10x-30
therefore, the simplified expression for the perimeter of the rectangle is 10x-30
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Use the unit circle to find the exact value of the trig function
Cos(45°)
Answer: √2/2
Step-by-step explanation: Starting from the positive x-axis (angle 0), we rotate the ray counterclockwise by 45 degrees, or π/4 radians. Since the point on the unit circle corresponding to 45 degrees lies on the line y = x, its coordinates are (cos(45), sin(45)) = (√2/2, √2/2).
PLS HELP THIS IS DUE TOMORROW
Answer: y = -|x + 1| + 1
Step-by-step explanation:
Since this is a "V" shaped graph, we know it uses the absolute value function. This is the parent function:
y = |x|
This represents the transformations:
➜ a is amplitude
➜ h is horizontal shift
➜ k is vertical shift
f(x) = a | x - h | + k
Next, we see it is shifted one unit upwards.
y = |x| + 1
Then, we see it is also shifted one unit left.
➜ Note that this shift is -h units, so we will use positive for moving left.
y = |x + 1| + 1
Lastly, we see this graph is flipped and has a negative slope, or amplitude.
y = -|x + 1| + 1
Identify the null and alternative hypotheses
Statistics!
The null and the alternate hypothesis are:
H₀: p ≤ 0.5H₁: p > 0.5How to write the hypothesisIn hypothesis testing, we take the null hypothesis (H₀) and the alternative hypothesis (H₁). The null hypothesis is the opposite of the claim , while the alternative hypothesis states the claim.
In this case, the null hypothesis is that a majority of adults would not erase their personal information online if they could (i.e., 50% or less of them would do so). The alternative hypothesis is that a majority of adults would erase their personal information online if they could (i.e., more than 50% of them would do so). In symbolic form:
H₀: p ≤ 0.5
H₁: p > 0.5
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Ashley bought 2 CDs that were each the same price. Including sales tax, she paid a total of $31.40 . Each CD had a tax of $0.80. What was the price of each CD before tax?
Answer:
Each CD cost $14.90 before tax.
Step-by-step explanation:
Let's call the price of each CD before tax "x".
We know that Ashley bought 2 CDs, so the total cost before tax would be 2x.
We also know that the sales tax on each CD was $0.80, so the total sales tax for both CDs would be 2(0.80) = $1.60.
So the total cost including tax would be:
2x + 1.60 = 31.40
To solve for x, we can start by subtracting 1.60 from both sides:
2x = 29.80
Then, we can divide both sides by 2 to solve for x:
x = 14.90