Answer:
Explanation:
During a physical temperature change, one substance, such as water will be heated. Because one compound is mixed in with another. Therefore, these reactants produce a product. When the reactants are mixed, the temperature change caused by the reaction is an indicator of a chemical change.
Find the volume in milliliters of 2.00 mol of an ideal gas at 36°C and a pressure of 1120 torr.
Use the ideal gas law and the appropriate Rvalue:
R=0.0821 atmL/mol. K
R= 8.31 kPa • L/mol •K
R= 62.4 torr • L/mol · K
mL
Answer:
V = 34430 mL
Explanation:
Given data:
Volume in mL = ?
Number of moles of gas = 2.00 mol
Temperature = 36°C (36+273= 309K)
Pressure of gas = 1120 torr
Solution:
Formula:
PV = nRT
V = nRT/P
V = 2.00 mol ×62.4 torr • L/mol · K × 309K / 1120 torr
V = 38563.2 torr • L / 1120 torr
V = 34.43 L
L to mL
34.43 L ×1000 mL / 1 L
34430 mL
chemistry question worth 40 points!!
If an M&M weighs 0.88 grams, how much would a mole of M&Ms
weigh?
Answer:
5.30x10²³g
Explanation:
A mole can be understood as an amount of something.
One mole of eggs are 6.022x10²³ eggs
One mole of atoms are 6.022x10²³ atoms
One mole of molecules are 6.022x10²³ molecules
And 1 mole of M&M are 6.022x10²³ M&M. As 1 M&M weighs 0.88g, 1 mole will weigh:
0.88g*6.022x10²³ =
5.30x10²³gOne mole of M&Ms will weigh 5.3 x 10²³ grams.
The given parameters
Weight of an M&M = 0.88 gramsOne mole of every substance contains 6.022x10²³ atoms of the substance.
Weight of an M&M, implies an atom of M&M.
1 atom --------- 0.88 grams
6.022x10²³ atoms = ?
= 0.88 g x 6.022x10²³
= 5.3 x 10²³ grams.
Thus, one mole of M&Ms will weigh 5.3 x 10²³ grams.
Learn more about number of atoms in a substance here: https://brainly.com/question/15193101