If an order is for 500mg from a dosage strength of 250 mg/mL, is to be administered in 20 cc D5 1/2NS, how many mL of drug is used and how many mL of D5 1/2NS is used?

[tex]y= g(x) = \log_4 (x^3 +2)\\\\\text{Replace x with y and solve for y:}\\\\~~~~x=\log_4 (y^3 +2)\\\\\implies y^3 +2 = 4^x\\\\\implies y^3 =4^x-2\\ \\\implies y = \sqrt[3]{4^x -2}\\\\\implies f^{-1} (x) = \sqrt[3]{4^x -2}[/tex]

Answer:

-cos^4(x)

Step-by-step explanation:

Step 1: Use the Pythagorean identity : 1=cos^2(x) + sin^2(x)

1-sin^2(x) = cos^2(x)

-1+sin^2(x) = -cos^2(x)

cos^2(x) (-cos^2(x))

Step 2: Factor out common terms cos^2(x)

cos^2(x) (sin^2(x)-1)

Ans: -cos^4(x)

I'll help you!

Answer:

EXACT: 2.7√1.71 + 4.05 units²

APPROX: 3.5307 + 4.05 = 7.58 units²

Step-by-step explanation:

See the attached help image

Total A = 2 triangles + 1 trapezoid

Triangles

Find missing side:

2.7² + b² = 3²

b² = 3² - 2.7²

b = √1.71

Find area of triangles:

A = bh/2

A = b(2.7)/2

A = √1.71(2.7)/2
A = 1.35√1.71 units²

Trapezoid

A = (a + b)(h)/2

A = ((3-√1.71) + √1.71)(2.7)/2

A = (3)(2.7)/2

A = 4.05 units²

Total

2(1.35√1.71) + 1(4.05)

EXACT: 2.7√1.71 + 4.05 units²

APPROX: 3.5307 + 4.05 = 7.58 units²

Answer: Fred needs 4/3 a cup of sugar, which can be simplified into 1 1/3.

Step-by-step explanation:

If you do 2/3 times 2/1 (because double means twice the amount) you will get 4/3, which again, can be simplified into 1 1/3.

Answer:

144

Step-by-step explanation:

im right:D have  a good day or night

Answer:

1

Step-by-step explanation:

[tex]my \: dear \: \\ to \: find \: the \: slope \: of \: a \: line \: use \: the \: formular \\ slope = \frac{y2 - y1}{x2 - x1} \\ from \: the \: question \: x1 = 5 \: \: y1 = 1\: \: x2 = - 5 \: \: y2 =- 9 \\ slope = \frac{ - 9 - 1}{ - 5 - 5} = \frac{ - 10}{ - 10} = 1 \\ therefore \: slope = 1 \\ hope \: this \: helps \\ stay \: focused \: with \: your \: studies[/tex]

Answer:

sorry I tried But Don't Know The Answer

Answer:

25 fl oz

Step-by-step explanation:

1 pint is equivalent to 16 fl oz, so we're left with 25 fl oz and 16 fl oz. As you can see, 25 is greater than 16, making 25 fl oz the correct answer.

The ratio of the large cans to small cans shows the distribution of both cans

The new ratio of large cans of soup to small cans of soup in the grocery store is (b) 5 : 3 and (e) 35: 21

The given parameters are:

Ratio = 12 : 7

Rewrite as:

Large : Small= 12 : 7

The number of cans is given as:

Can = 114

So, the distribution of the cans are:

Large = 12/(12 + 7) * 114

Large = 72

Small = 7/(12 + 7) * 114

Small = 42

When 2 large cans are purchased, the remaining number of cans are:

Small = 42

Large = 70

Express as ratio

Large : Small = 70 : 42

Simplify

Large : Small = 35 : 21

Large : Small = 5 : 3

Hence, the new ratio  is (b) 5 : 3 and (e) 35: 21

Read more about ratio at:

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Step-by-step explanation:

For example: Subtract 4x - 10y + 15z from 5x + 8y - 20z.

Step 1: Arrange the polynomials in standard form. In this example, it is already arranged.

Step 2: Place them horizontally.

(4x - 10y + 15z) - (5x + 8y - 20z)

Step 3: Change the sign of the second polynomial through the parentheses.

4x - 10y + 15z - 5x - 8y + 20z

Step 4: Arrange the like terms together.

4x - 5x - 10y - 8y + 15z + 20z

Step 5: Solve the equation

-x - 18y + 35z

Therefore, when we subtract 4x - 10y + 15z from 5x + 8y - 20z = -x - 18y + 35z.

Answer:

10 to the power of 4

Step-by-step explanation:

Answer:

$100

Step-by-step explanation:

What we know,

Let us assume that Ronald has $25, so Howard must have $75,

Now Howard gives $50 to Ronald, Now Ronald has $75,

Therefore our assumption is correct,

Therefore Ronald and Howard together will have $100.

We can find the distance between two points by using distance formula,

[tex] \qquad \: D = \sf \red{\sqrt{ {(x_2 -x_1)}^{2} + {(y_2 -y_1)}^{2} }}[/tex]

Here,

x₁ = -3

x₂ = 5

y₁ = -2

y₂ = 2

Therefore,

[tex] : \implies \: D = \sf \red{\sqrt{ {(x_2 -x_1)}^{2} + {(y_2 -y_1)}^{2} }} \\ \\ : \implies \: D = \sf \sqrt{ {(5-( - 3))}^{2} + {(2 -( - 2))}^{2} }

\\ \\ : \implies \: D = \sf \sqrt{ {8}^{2} + {4}^{2} } \\ \\ : \implies \: D = \sqrt{64 + 16}

\\ \\ : \implies \: D = \sqrt{80} [/tex]

Hence the √80 = 8.94 approx is the distance between the two points (-3,-2) and (5,2).

The distance between 2 points

Here we have been provided 2 points

(-3, -2) and (5, 2)

[tex] (x_1,y_1) = (-3,-2) \\ (x_2,y_2) = (5,2) [/tex]

Formula to find distance is

[tex] = \sqrt{ {(x_2 - x_1)}^{2} + {(y_2 - y_1)}^{2} } [/tex]

[tex] = \sqrt{ {(5 - ( - 3))}^{2} + {(2 - ( - 2))}^{2} } \\ = \sqrt{ {(8)}^{2} + {(4)}^{2} } \\ = \sqrt{64 + 16} \\ = \sqrt{80} \\ = 4 \sqrt{5} [/tex]

The distance between 2 points is 4√5.

[tex] \mathcal {BE \: \: BRAINLY} [/tex]

Answer:

1. 4[tex]x^{3}[/tex] + 26x² + 4x - 48

2. 2[tex]x^{3}[/tex] - 23x² + 60x - 32

3. [tex]x^{5}[/tex] + 7[tex]x^{3}[/tex] - 4x + 2[tex]x^{4}[/tex] + 14x² - 8

4. 2[tex]x^{7}[/tex] + [tex]x^{6}[/tex] - 28[tex]x^{5}[/tex] + 3x + 12

Step-by-step explanation:

To multiply polynomials, simply distribute whatever's outside the largest set of parenthesis, then combine like terms.

1) Distribute the parenthesis (x + 6):

x(4x² + 2x - 8)  +  6(4x² + 2x - 8)

4[tex]x^{3}[/tex] + 2x² -8x  +  6(4x² + 2x -8)

4[tex]x^{3}[/tex] + 2x² -8x + 24x² + 12x - 48

Combine like terms:

4[tex]x^{3}[/tex] + 26x² + 4x - 48

2) Distribute the parenthesis (x - 8):

x(2x² - 7x + 4)  +  (-8)(2x² - 7x + 4)

2[tex]x^{3}[/tex] - 7x² + 4x  +  (-8)(2x² - 7x + 4)

2[tex]x^{3}[/tex] - 7x² + 4x  +  -16x² + 56x - 32

Combine like terms:

2[tex]x^{3}[/tex] - 23x² + 60x - 32

3) Distribute the parenthesis (x + 2):

x([tex]x^{4}[/tex] + 7x² - 4)  +  2([tex]x^{4}[/tex] + 7x² - 4)

[tex]x^{5}[/tex] + 7[tex]x^{3}[/tex] - 4x  +  2([tex]x^{4}[/tex] + 7x² - 4)

[tex]x^{5}[/tex] + 7[tex]x^{3}[/tex] - 4x + 2[tex]x^{4}[/tex] + 14x² - 8

No like terms to combine, so:

[tex]x^{5}[/tex] + 7[tex]x^{3}[/tex] - 4x + 2[tex]x^{4}[/tex] + 14x² - 8

4) Distribute the parenthesis (x + 4):

x(2[tex]x^{6}[/tex] - 7[tex]x^{5}[/tex] + 3)  +  4(2[tex]x^{6}[/tex] - 7[tex]x^{5}[/tex] + 3)

2[tex]x^{7}[/tex] - 7[tex]x^{6}[/tex] + 3x  +  4(2[tex]x^{6}[/tex] - 7[tex]x^{5}[/tex] + 3)

2[tex]x^{7}[/tex] - 7[tex]x^{6}[/tex] + 3x + 8  [tex]x^{6}[/tex] - 28[tex]x^{5}[/tex] + 12

Combine like terms:

2[tex]x^{7}[/tex] + [tex]x^{6}[/tex] - 28[tex]x^{5}[/tex] + 3x + 12

hope this helps!

Answer: D: Square Root Of 5

Step-by-step explanation: 30/6 is 5, now fill in the sqrt symbol. Hope this helped. (This problem was one of the simpler, friendlier numbers.)

Answer:

Center: (9,-4)

Radius: 5

Step-by-step explanation:

Equation for a circle:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

h=9

k=-4

r=5

center is (h,k)

to find the radius, get square root of 25

Answer:

Center is (9,-4)

Radius: 5

Step-by-step explanation:

h=9

k=-4

r=5

Answer:

< –13, 4, 4 >

Step-by-step explanation:

Vector u = < –5, 6, 3 >

Vector t = < –8, –2, 1 >

  -5   6   3

+ -8  -2   1

 -13   4   4

Vector u + t = < –13, 4, 4 >

Answer:

B. <14,-3>

Step-by-step explanation:

Answer:

10

Step-by-step explanation:

153+17=170
180-170=10

Let a be the first term in the sequence, and d the common difference between consecutive terms. If aₙ denotes the n-th term in the sequence, then

a₁ = a

a₂ = a₁ + d = a + d

a₃ = a₂ + d = a + 2d

a₄ = a₃ + d = a + 3d

and so on, up to the n-th term

aₙ = a + (n - 1) d

The sum of the first 10 terms is 100, and so

[tex]\displaystyle \sum_{n=1}^{10} a_n = 100 \\ \sum_{n=1}^{10} (a + (n-1)d) = 100 \\ (a-d) \sum_{n=1}^{10} 1 + d \sum_{n=1}^{10} n = 100 \\ 10a+45d = 100[/tex]

where we use the well-known sum formulas,

[tex]\displaystyle \sum_{n=1}^N 1 = 1 + 1 + 1 + \cdots + 1 = N[/tex]

[tex]\displaystyle \sum_{n=1}^N n = 1 + 2 + 3 + \cdots + N = \frac{N(N+1)}2[/tex]

The sum of the next 10 terms is 300, so

[tex]\displaystyle \sum_{n=11}^{20} a_n = 300 \\ (a-d) \sum_{n=11}^{20} 1 + d \sum_{n=11}^{20} n = 300 \\ (a-d) \left(\sum_{n=1}^{20} 1 - \sum_{n=1}^{10} 1\right) 1 + d \left(\sum_{n=1}^{20} n - \sum_{n=1}^{10} n\right) = 300 \\ 10a+145d = 300[/tex]

Solve for a and d. Eliminating a gives

(10a + 145d) - (10a + 45d) = 300 - 100

100d = 200

d = 2

and solving for a gives

10a + 145×2 = 300

10a = 10

a = 1

So, the given sequence is simply the sequence of positive odd integers,

{1, 3, 5, 7, 9, …}

given recursively by the relation

[tex]\begin{cases}a_1 = 1 \\ a_n = a_{n-1} + 2 & \text{for }n>1\end{cases}[/tex]

and explicitly by

[tex]a_n = 1 + 2(n-1) = 2n - 1[/tex]

for n ≥ 1.

Answer: y = one-half x minus 4

Step-by-step explanation:

y = 1/2 x + b

-3 = 1/2 (2) + b

-3 = 1 + b

-3 - 1 = b

-4 = b

Answer:

x = 52, c = 87

Step-by-step explanation:

Set up and then solve this system of equations:

3c + 5x = 521--->3c + 5x = 521

c + x = 139 --->3c + 3x = 417

-------------------

2x = 104

x = 52, c = 87

Answer: the answer is 139-c

Answer:

A=0.50

B=0.477

C=0.423<p<0.531

Step-by-step explanation:

sample size N :333

number of success X: 159

sample part of success x/n = 159/333

x=0.477 B

0.50 A Half a chance to flip a tail or head

part C:

[tex]0.477 plusminus 1.96 * \sqrt{ \frac{0.477 (1 - 0.477)}{333} } [/tex]

simplify

[tex]0.477 plusminus 1.96 * 0.0536[/tex]

expand

[tex]0.477 + 1.96 * 0.0536[/tex]

[tex]0.531[/tex]

expand minus

[tex]0.477 - 1.96 * 0.0536[/tex]

[tex]0.423[/tex]

finally answer part c

[tex]0.423 < p < 0.531[/tex]

Answer:

Not a proper question. But I think it's a 5

[tex] \huge \pink{ \underline{ \overline{ \: 5 \: i \: think}}}[/tex]

Answer:

Yes

Step-by-step explanation:

5,000 cm = 50m

[tex]\frac{1m}{100cm} =5000cm[/tex]

[tex]\frac{1m(5000)}{100}[/tex]

[tex]\frac{5000m}{100}[/tex]

= 50 m

hope this helps :)

Answer:

divide what is on the right hand side of the equal sign by what is next to x or y

Step-by-step explanation:

e.g.

2x=3

x=3/2

fraction:3/2

decimal: 1.5

Answer:

divide what is on the right hand side of the equal sign by what is next to x or y

Step-by-step explanation:

Answer:

G(x) = (x-4)⁴

Step-by-step explanation:

The equation of the graph of f(x) which is formed by shifting 4 units to the right of g(x) is f(x) = (x - 4)⁴

Translation of functions is defined as the when each point in the original graph is moved by a fixed units in the same direction.

There are horizontal translation and vertical translation of functions.

Given a function G(x).

G(x) = x⁴

A function F(x) is formed by shifting the graph of G(x) to the right by 4 units.

A function h(x) when shifted to the right by k units becomes h(x - c).

So the graph of G(x) when shifted to the right by 4 units becomes G(x - 4).

G(x - 4) = (x - 4)⁴

So, F(x) = (x - 4)⁴

Hence the function is F(x) = (x - 4)⁴.

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