if i forward an email to another email account and delete it will it delete from the original account?

Answers

Answer 1

Yes, if you forward an email to another email account and delete it from the original account, it will be deleted.

Here is a step-by-step explanation:
1. Log in to the original email account.
2. Find the email you want to forward and delete.
3. Click on the email and open it.
4. At the top of the email there should be an option to 'forward'.
5. Enter the email address of the recipient you wish to forward the email.
6. Click 'send'.
7. After you have sent the email, click on the trash or delete button on the original email to delete it.
8. Confirm that you would like to delete the email from the original account.

By following these steps, you will be able to forward an email to another account and delete it from the original account.

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Related Questions

to avoid confusion, each component in the wbs needs to have a unique name and a unique number. group of answer choices false true

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The statement "to avoid confusion, each component in the WBS needs to have a unique name and a unique number" is TRUE.

WBS stands for Work Breakdown Structure. It is a useful project management tool that helps to break down the project's work into smaller, more manageable components, making it easier to manage, monitor, and control. In WBS, each component must have a unique name and number to avoid confusion. Because it specifies the project's complete scope, a WBS aids in defining project objectives and establishing the project's critical path. A WBS also facilitates the project manager's communication with the project team and stakeholders, ensuring that everyone is aware of the project's progress.

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what significant cloud coverage is reported by this pilot report? kmob ua/ov 15nw mob 1340z/sk ovc-top025 / ovc045-top090

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According to the pilot report, the significant cloud coverage is overcast, with cloud tops at 2500 feet and 4500 feet.

The pilot report is written in a specific format that provides information about weather conditions and other factors relevant to aviation. In this report, the cloud coverage is described using the abbreviations "ovc-top025" and "ovc045-top090," which indicate that the clouds are overcast and that their tops are at 2500 feet and 4500 feet, respectively.

Overcast conditions mean that the sky is completely covered by clouds, and the sun is not visible.

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how many bits are required to address a 1m x 8 main memory if a) main memory is byte-addressable? b) main memory is word-addressable?

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a) If the main memory is byte-addressable, each byte needs an address, thus the number of addresses required is equal to the size of the main memory.

Therefore, for a 1M x 8 main memory, the number of bytes is 1M, which equals 220 bytes. Each byte requires an address, so the number of bits required to address the memory is equal to the log base 2 of 220, which is 20 bits.
b) If the main memory is word-addressable, then each word in the memory will need an address, and the size of a word will depend on the machine.

For instance, if the word size is 16 bits, then the memory size would be 512K x 16 bits. Then the number of words will be 512K, which is equal to 219. Since each word requires an address, the number of bits required to address the memory is equal to the log base 2 of 219, which is 19 bits.

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aside from color names and hex color codes, what is another way to encode a css color value? give an example.

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Aside from color names and hex color codes, another way to encode a CSS color value is by using RGB values. An example of CSS color value in RGB format is as follows: RGB (255, 0, 0), which represents the color red.

RGB values CSS (Cascading Style Sheets) can be used to style web pages. It is used to change the appearance of text, backgrounds, borders, and many more. CSS supports three different ways to describe colors on a web page, which include color names, RGB values, and Hexadecimal color codes.

RGB values are specified as a set of three numbers that represent the red, green, and blue values. They have the following syntax: RGB (red, green, blue), where each color value is a number between 0 and 255. For example, the RGB value for red is RGB (255, 0, 0). The RGB color model is based on the colors of light, and its main advantage is its ability to create millions of color combinations.

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Kendra has a very limited budget, but has three critical servers that she needs to secure against data breaches within her company's infrastructure. She knows that she won't be able to protect the entire network, but she has started searching for a solution to secure the most critical assets. Which of the following options would she most likely choose?
a. UTM appliance
b. NIPS
c. Proxy server
d. HIPS

Answers

Given Kendra's limited budget and the need to secure the most critical assets, the most likely option she would choose is a Host-based Intrusion Prevention System (HIPS) option D. which provides protection to the individual servers by monitoring and analyzing their behavior to detect and prevent intrusions.

While Unified Threat Management (UTM) appliances, Network-based Intrusion Prevention Systems (NIPS), and Proxy servers all provide security benefits, they are more appropriate for protecting larger networks with multiple endpoints rather than a small set of critical servers.

UTM appliances are typically used to provide comprehensive security services to an entire network, including firewalls, intrusion detection/prevention, antivirus, and content filtering.

NIPS is designed to monitor network traffic for signs of malicious activity and prevent attacks in real-time. However, they are more suited to larger networks with multiple endpoints rather than a small set of critical servers.

Proxy servers can provide an additional layer of security by filtering incoming traffic and blocking potentially harmful requests. However, they are more suited to larger networks where there is a higher volume of traffic.

Therefore, in Kendra's scenario, a HIPS would be the most appropriate choice for securing her critical servers within her limited budget.

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what tool in ehr go provides increased visibility to an allergy entered using the tab you selected as your answer for question 6?

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The tool in EHR Go that provides increased visibility to an allergy entered using the tab you selected as your answer for question 6 is the "Allergies" tab. This tab allows users to easily track and manage allergies and other medical information.

The Allergies tab is broken down into two sections: the Allergies & Reactions section, which displays all allergies entered, and the Current Allergies section, which shows only active allergies. By clicking on an allergy, users can view the source, severity, onset date, reaction, and other important information.

The Allergies tab also allows users to easily add and remove allergies, as well as adjust their severity levels. The "Add Allergy" button lets users enter a new allergy or edit an existing one. To remove an allergy, simply click the red "Remove Allergy" button.

Additionally, the Allergies tab provides an easy way to set up alerts for any new allergies or changes to existing allergies. This feature helps to ensure that medical staff is alerted of any new allergies or changes in severity.

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you have the proper client installed on your laptop. what needs to be installed on the remote linux machine

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In order to remotely access a Linux machine from your laptop, you would need to have a remote access client installed on your laptop and the necessary server software installed on the remote Linux machine.

The specific server software needed on the remote Linux machine may depend on the type of remote access you want to use. For example, if you want to use SSH (secure shell) to access the command line interface of the remote machine, then you would need to ensure that the SSH server software is installed and running on the remote machine. The specific software needed on the remote Linux machine will depend on the type of remote access you want to use and the specific configuration of the remote machine.

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which one of these connection types has the longest delay? group of answer choices cellular wired infrared wireless

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The delay is greatest on cellular. Among all connection methods, wired networks can offer the fastest data transmission rates.

How do wireless access points and routers differ?

A local area network is created by the router, which also controls all of the connected devices and communication. On the other hand, an access point is a sub-device of the local area network that enables more devices to be connected to the network and offers another location for devices to connect from.

What does a router do in a network?

One or more packet-switched networks or subnetworks can be connected using a router. It manages traffic between these networks by forwarding data packets to their intended IP addresses and permits communication between these networks.

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which access list statement will permit all http sessions to network 192.168.144.0/24 containing web servers?

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To permit all HTTP sessions to network 192.168.144.0/24 containing web servers, the following access list statement can be used:

access-list 101 permit tcp any 192.168.144.0 0.0.0.255 eq www

This access list statement allows any source IP address (denoted by any) to access any web server within the network 192.168.144.0/24 (denoted by 192.168.144.0 0.0.0.255) on port 80 (denoted by eq www). Port 80 is the default port used for HTTP traffic.

Note that this access list statement should be applied to the appropriate interface or interfaces on the router using the ip access-group command. The access list number (in this case, 101) can be modified to match the access list number being used on the router.

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what address shoudl you ping if you want to test local ipv6 operation but dont want to actually send any packets on the network?

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To test local IPv6 operation but don't want to send any packets on the network, you should ping the localhost or loopback address, which is ::1. This is also known as the IPv6 loopback address.

In IPv6, the loopback address is a single address that serves the same purpose as the IPv4 loopback address (127.0.0.1). The loopback address for IPv6 is ::1/128. This address can only be used to transmit traffic within a device, and any traffic sent to it will never leave the computer.

The loopback interface is a virtual network interface that is created in the kernel of an operating system, allowing traffic to flow without using any external network interface or physical hardware. Since this address is only used to send traffic inside the computer, it is a good method to test that the computer's IPv6 protocol stack is working correctly. For example, by sending an ICMPv6 echo request message to the loopback address, you can check whether the computer's IPv6 protocol stack is operational. By doing this, you may confirm that the TCP/IP network stack is working properly.

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genie is worried that her binary response model will not perform as well with data outside of the estimation sample. what technique should she use to assess the predictive power of her model?

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To assess the predictive power of a binary response model and evaluate its performance on data outside the estimation sample, Genie can use techniques such as cross-validation or out-of-sample testing.

What happens in cross-validation?

In cross-validation, the data is randomly divided into training and testing subsets, and the model is trained on the training set and then tested on the testing set. This process is repeated multiple times with different subsets, and the average performance across all tests is used to assess the model's predictive power.

In out-of-sample testing, the model is tested on a separate dataset that was not used in the model's estimation. This allows Genie to evaluate how well the model generalizes to new data.

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private ipv4 address 172.331.255.255 is an example of a full class a address, as defined by request for comment 1918. true false

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The aforementioned private IP addresses, 172.331.255.255 ipv4 isn't present. Thus, the given statement is false.

Internet Protocol version 4, also known as IPv4, is a protocol used to send and receive data on the internet. IPv4 is a connectionless protocol that operates at the network layer of the OSI model, providing internet addressing to devices.

Internet Protocol Version 4 (IPv4) addresses are made up of 32 bits and are displayed in dotted-decimal notation. Routers on the internet use these addresses to direct traffic to and from networks. Request for Comment (RFC) 1918RFC 1918 is a request for comments (RFC) that specifies addresses that can be used in private networks. It is used to limit IP address fragmentation when several organizations with private IP networks need to interconnect with one another. The addresses that are defined in RFC 1918 are private IP addresses. These addresses can only be used on private networks, and not on the public internet. Because of the range of private IP addresses available, there is no need to assign globally unique IP addresses to every device on a private network. Private IPv4 addresses 172.16.0.0 to 172.31.255.255 (16.7 million addresses) 192.168.0.0 to 192.168.255.255 (65,536 addresses) 10.0.0.0 to 10.255.255.255 (16.8 million addresses). From the aforementioned private IP addresses, 172.331.255.255 isn't present. Thus, the given statement is false.

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when a data set is tabulated into bins, we lose information about the location of the x values within bins but gain clarity of presentation because grouped data can be displayed more compactly than raw data. true false question. true false

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The given statement, when a data set is tabulated into bins, we lose information about the location of the x values within bins but gain clarity of presentation because grouped data can be displayed more compactly than raw data, is true.

However, this loss of information is outweighed by the clarity of presentation gained by grouping data into bins, as this makes the data more compact and easier to visualize.

One major advantage of grouped data is that it can be displayed more compactly than raw data. This creates a clearer and more concise picture of the data, which can be useful when presenting data to others. Additionally, it can be easier to identify patterns and trends in grouped data, as it reduces the amount of noise in the data.

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Rachel works for a large graphic design firm. She is making a poster to notify people about an upcoming graphic design seminar. Which type of poster is she making?

Rachel is creating an _______ poster to notify people about the upcoming graphic design seminar.

Answers

Answer:

a eye- catching poster

Explanation:

sorry if its wrong

explain how email usage has changed over the past 20 years. describe how an anticipatory system might work. explain how advances in hardware and software might change the types of jobs you take in the future.

Answers

Email usage has changed significantly over the past 20 years. In the early 2000s, email was largely used for personal communication, but with the advent of social media, it is now a key component of business communication. An anticipatory system is one that can proactively respond to emails in a timely manner, anticipating the needs of the recipient. Advances in hardware and software have changed the way we use email and the types of jobs available.

Hardware has allowed for greater speeds in sending and receiving emails, as well as increased storage capacity. The software has also enabled more efficient management of emails, with the ability to organize emails into folders and categories. These advances have resulted in new roles such as email marketers and email system administrators, as well as increased demand for certain skill sets such as HTML coding. In the future, email usage is likely to increase further as the use of AI in email becomes more widespread.

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you are configuring the acl for the network perimeter firewall. you have just finished adding all the proper allow and deny rules. what should you place at the end of your acl rules?

Answers

At the end of your Access Control List (ACL) rules, you should always include a “deny all” rule.

This rule explicitly denies all traffic that is not explicitly allowed by the previous rules, ensuring that all traffic that does not match the criteria specified in the other rules is blocked from entering the network.

In the context of a firewall, an ACL is a set of rules that determine whether or not a packet of data is allowed to pass through the firewall. The ACL defines which traffic is allowed to pass through the firewall, and which traffic is denied. By setting a “deny all” rule at the end of the ACL, all traffic that does not match the criteria specified in the other rules is blocked from entering the network.

The “deny all” rule should be the last rule in the list of ACL rules. This rule is also known as an “implicit deny” rule, as it is implied that anything that does not match the other rules should be denied. This rule is also known as the “default deny” rule, as the default action is to deny access.

The “deny all” rule helps to ensure that your firewall is secure, as any traffic that is not explicitly allowed is blocked from entering the network. It is important to remember to include this rule at the end of the list of ACL rules, as it provides a final layer of protection against unauthorized traffic.

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To the ADT stack given in this chapter, add a void method remove(n) that removes and discards the topmost n entries from a stack. Write a link-based implementation for this method.

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To the ADT stack given in this chapter, add a void method remove(n) that removes and discards the topmost n entries from a stack. Write a link-based implementation for this method.

Here is the given ADT stack, as follows:public interface StackADT {// adds the item to the top of the stackpublic void push(T item); // removes and returns the item from the top of the stackpublic T pop(); // returns the item from the top of the stack without removing it

public T peek(); // returns true if the stack is emptypublic boolean isEmpty(); // returns the number of items on the stackpublic int size();}The below-mentioned is the link-based implementation for the given method. It is as follows:public void remove(int n) { Node currentNode = top; for (int i = 1; i <= n; i++) { if (currentNode == null) { throw new RuntimeException("Cannot remove more elements than the stack has"); } currentNode = currentNode.

next; } if (currentNode == null) { top = null; return; } top = currentNode; } Note: The remove method will remove the first n elements from the top of the stack. If the stack has less than n elements, then it throws an exception. The top of the stack is set to null if n is greater than or equal to the stack's size.

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complete the getaverage() method in the arrayaverage class using a for-each loop. create an arrayaverage object and print the result. your output should be:

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Your output should be:```Average: 4.0```

Here is the code that can be used to solve this problem:

public class ArrayAverage {

   public static void main(String[] args) {

       int[] arr = {2, 4, 6};

       ArrayAverage avg = new ArrayAverage();

       System.out.println("Average: " + avg.getAverage(arr));

   }

   

   public double getAverage(int[] arr) {

       double sum = 0.0;

       for (int i = 0; i < arr.length; i++) {

           sum += arr[i];

       }

       return sum / arr.length;

   }

}

Here is the completed code for the `getAverage()` method in the `ArrayAverage` class:`

public class ArrayAverage {

   public static void main(String[] args) {

       int[] arr = {2, 4, 6};

       ArrayAverage avg = new ArrayAverage();

       System.out.println("Average: " + avg.getAverage(arr));

   }

   

   public double getAverage(int[] arr) {

       int sum = 0;

       for (int num : arr) {

           sum += num;

       }

       return (double) sum / arr.length;

   }

}

```Output:```Average: 4.0```

Note: the output will depend on the values in the array.

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which protocol provides up to 16 instances of rstp, combines many vlans with the same physical and logical topology into a common rstp instance, and provides support for portfast, bpdu guard, bpdu filter, root guard, and loop guard?

Answers

This protocol integrates numerous VLANs with the same physical and logical topology into a single RSTP instance, supports PortFast, and offers up to 16 instances of RSTP (Rapid Spanning Tree Protocol).

Which protocol allows for up to 16 RSVP instances?

Explanation: MSTP, an IEEE standard protocol that offers up to 16 instances of RSTP and merges numerous VLANs with the same physical and logical topology into a single RSTP instance, is implemented by Cisco as STP-Rapid PVST+-PVST+-MSTE.

What is the purpose of BPDU guard?

Although the port can broadcast STP BPDUs, the BPDU Guard feature prevents the port from receiving STP BPDUs. A BPDU Guard enabled port is shut down and changes its state to ErrDis when a STP BPDU is received on it.

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Under which of the following circumstances might you be most likely yo contact a professional to repair your computer or mobile device?a. screen is brokenb. computer cannot synchronize with bluetooth accessoriesc. computer or device is too hotd. printer will not print

Answers

The circumstance where you would be most likely to contact a professional to repair your computer or mobile device is when your A: screen is broken.

If the screen of a computer or mobile device is broken, it is a hardware issue that requires specialized repair. Attempting to fix it without proper training and tools can cause further damage. Therefore, contacting a professional repair service is the best course of action.

In the case of other issues like synchronization, heating, or printing, there are often troubleshooting steps that a user can take before considering professional repair. However, a broken screen is a physical issue that needs to be addressed by someone with the right expertise and resources.

Thus correct answer is: A. Screen is broken.

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different computing systems could have conflicting optimization goals. describe how the following pairs of scheduling criteria could have conflicting goals. (6 pts) cpu utilization and response time average turnaround time and maximum waiting time i/o device utilization and cpu utilization.

Answers

CPU utilization and response time can have conflicting goals because high CPU utilization implies keeping the CPU busy with processes, while low response time implies quick turnaround for processes, which can lead to processes being starved of CPU resources.

Various computer systems may have competing optimization objectives. The following pairs of scheduling criteria may have competing objectives:

1. CPU usage and reaction time:

When a CPU is heavily used, reaction time tends to increase. It might be difficult to strike a balance between high CPU use and low reaction time since high CPU utilization implies a speedy response and low CPU utilization implies a lengthy response. As a result, the CPU usage optimization target may clash with the reaction time optimization goal.

2. Both average turnaround time and maximum waiting time relate to the amount of time it takes for a process in a computer system to finish. The average turnaround time seeks to reduce the time it takes the system to perform all operations, whereas the maximum waiting time seeks to ensure that no process must wait for a lengthy amount of time.

These two criteria contradict each other since reducing average turnaround time may require a few processes to wait for an extended period, increasing in maximum waiting time.

3. I/O device usage and CPU utilization: There is a conflict between these two optimization goals since the CPU and I/O devices compete for processing resources in general. Increased I/O device use, for example, by processing more I/O requests, might result in lower CPU utilization since the CPU must wait for the I/O requests to be processed.

As a result, there is a trade-off between increasing I/O device utilization and reducing CPU utilization.

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which of these statements is incorrect? group of answer choices interfaces can be instantiated abstract classes may or may not have abstract methods. interfaces cannot have constructors. abstrac classes can have constructors.

Answers

The incorrect statement from the given options is "abstract classes can have constructors."

In Java, an abstract class is a class that is declared abstract. The class cannot be instantiated, but it may be extended by subclassing. It can contain both concrete and abstract methods. It is useful for defining a standard template for concrete classes and defining common methods to be used by multiple subclasses. The abstract keyword is used to indicate that a class is abstract.

An interface is a collection of abstract methods. It is not a class and cannot be instantiated. It can be implemented by a class, which provides concrete implementations of all of its abstract methods. It is used to define a contract that a class implementing the interface must follow. The interface keyword is used to indicate that a class is an interface.

Abstract classes can have constructors. The purpose of an abstract class constructor is to initialize the instance variables that will be used by the subclass. A subclass must call the constructor of its superclass using the super keyword. An abstract class constructor can be either public or protected, but it cannot be private.Interfaces and ConstructorsInterfaces cannot have constructors. Thus the correct answer is abstract classes can have constructors.

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which of the following statements are valid? a constructor can return a integer a constructor can return a char a constructor cannot return anything a constructor can return a void

Answers

Out of the given statements, the following statements are valid for a constructor: a constructor cannot return anything and a constructor can return a void.

Know what is a constructor! A constructor is a method that has the same name as the class in which it is located. When an object is created, the constructor is called, which initializes the object's values.

Constructors are used to provide initial values for the object's state (the values of instance variables) and to allocate memory for the object. A constructor does not have a return type because it returns an instance of the class it belongs to. Therefore, statement (c) "a constructor cannot return anything" is valid. A return type may be defined for a method in Java, which specifies the data type that the method will return after execution. Constructors, on the other hand, never specify a return type because they always return a reference to an instance of the class. Furthermore, it is not necessary to explicitly declare constructors because Java automatically creates a default constructor if one is not specified. Since the default constructor does not have any parameters, it initializes all variables to their default values, making it possible to construct objects without having to specify any values, making statement (d) "a constructor can return a void" valid.

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you notice that your computer is running slow and decide to reboot the computer to see if that will fix the problem. during the reboot, you notice that the amount of ram shown during the ram count is not the same as it was the day before. what might cause this problem?

Answers

There are a few possibilities that could cause the amount of RAM shown during the RAM count to change after a reboot. They are :

HardwareBIOS SettingsSoftware Issue.

What is RAM?

RAM (Random Access Memory) is a type of computer memory that is used to temporarily store data that the computer is actively using.

The possibilities that could cause the amount of RAM shown during the RAM count to change after a reboot are:

Hardware issue: There could be a problem with the RAM module or slot, causing it to malfunction or become partially dislodged. This could cause the system to recognize less RAM than it should.

Software issue: There could be an issue with the operating system or other software that is causing the system to allocate less RAM to the system.

BIOS settings: The amount of RAM recognized by the system can also be affected by the BIOS settings. It's possible that a change was made to the settings that caused the system to recognize less RAM than before.

In any case, if the amount of RAM recognized by the system has changed.

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you conducted a security scan and found that port 389 is being used when connecting to ldap for user authentication instead of port 636. the security scanning software recommends that you remediate this by changing user authentication to port to 636 wherever possible. what should you do?

Answers

In order to remediate the issue with port 389 being used when connecting to LDAP for user authentication, you should change the authentication port to 636 wherever possible. To do this, you will need to identify the applications and services which are currently using port 389, and modify their configurations to use port 636 instead. Depending on the system, this may require changing the server configuration, client configuration, or both.

The Lightweight Directory Access Protocol (LDAP) is an open, vendor-neutral, directory service protocol that is used to manage and access distributed directory information over an IP network. It was developed by the Internet Engineering Task Force (IETF) as an evolution of the earlier X.500 Directory Access Protocol. LDAP provides a way to access and modify directory services that store information about users, groups, systems, networks, and other resources in a structured way. It allows clients to search, add, delete, and modify entries in a directory service, and supports authentication and authorization mechanisms to control access to the directory data.

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write a c program to convert the change given in quarters, dimes, nickels, and pennies into dollars and cents.sr2jr

Answers

This is a relatively simple program to write in C. Here's a template you can use:

#include <stdio.h>
int main(){
   // Declare variables for quarters, dimes, nickels, and pennies
   int quarters, dimes, nickels, pennies;
   // Calculate the number of dollars and cents
   int dollars = (quarters * 25 + dimes * 10 + nickels * 5 + pennies) / 100;
   int cents = (quarters * 25 + dimes * 10 + nickels * 5 + pennies) % 100;
   // Print the result
   printf("%d dollars and %d cents\n", dollars, cents);
   return 0;
}

The program starts with including the standard input-output library. Then, the main function is defined in the program. The variables quarters, dimes, nickels, pennies, total_cents, and dollars are declared in the program.Next, the user is prompted to enter the number of quarters, dimes, nickels, and pennies. Then, the total amount in cents is calculated and stored in the variable total_cents.The value of total_cents is divided by 100 to get the value in dollars. Finally, the value of dollars is displayed on the console with two decimal places.

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if another end device such as a scanner is added to the topology beside the leftmost printer, what type of cable would be used to connect the scanner to the switch?

Answers

The type of cable that would be used to connect the scanner to the switch would depend on the type of interface supported by the scanner and the switch.

What happens if both devices support Ethernet connectivity?

If both devices support Ethernet connectivity, then an Ethernet cable would be used. The most common type of Ethernet cable used for this purpose is a twisted pair cable with an RJ-45 connector on each end.

However, if the scanner uses a different interface, such as USB, then a USB cable would be required instead. It is important to ensure that the cable used is compatible with both devices to ensure proper communication.

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vremus is an art student who wants to start creating digital artwork on his computer. he wants to be able to create images that retain their quality in all sizes. which type of app should he use?

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Student of art Remus wants to begin producing digital artwork on his computer. He hopes to be able to produce photos that are high-quality at all scales. He should use a drawing app as his app type.

What is digital artwork?Any creative endeavour or artistic practise that incorporates digital technology into the production or presentation process is referred to as digital art. It also applies to computational art that interacts with and utilises digital media. The term "digital art" describes works of art that incorporate digital technology into their production or display. Although various media, including video art, photography, and digital printing, are technically included in the definition, using computer programmes is most frequently linked to it.Digital art can be defined as anything created or produced using digital media, such as animations, pictures, drawings, movies, paintings, and other things.

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a) draw the runtime stack after each line executes under static scoping. what value assigned to z in line 12? b) draw the runtime stack after each line executes under dynamic scoping. what value assigned to z in line 12?

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Runtime stack for Static Scoping, the value of the z variable at line 12 is 20, and the Runtime stack for Dynamic Scoping, the value of the z variable at line 12 is 10.

As per the given question, we need to create a runtime stack for both Static and Dynamic Scoping, respectively. And the value of the z variable on line 12 needs to be evaluated. Now, let's proceed with the solution:

Static Scoping: In Static scoping, the variable declared in the outer block retains the same value for all the inner blocks. That means, the variable is not changed by the inner block. Hence, z = 20, will remain the same throughout the program.

Here's the value of the z variable at line 12: 20

Dynamic Scoping: In Dynamic scoping, the variable declared in the inner block, overwrites the variable declared in the outer block. Hence the value of the z variable at line 12 will be 10.

Here's the value of the z variable at line 12: 10

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for binary data, define a glm using the log link. show that effects refer to the relative risk. why do you think this link is not often used

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A Generalized Linear Model (GLM) using the log link is a type of GLM that uses the natural logarithm to link the predicted probability of an outcome to the explanatory variables. The log link is not often used because the interpretation of the relative risk can be more difficult to interpret than the interpretation of a GLM with another link function.

Binary data is a type of data in which each observation can only have two possible outcomes (usually 0 or 1). It is often used to measure the relative risk associated with a particular explanatory variable, as it allows for the effects of the explanatory variable to be expressed in terms of the odds ratio (i.e., the ratio of the probability of one outcome to the probability of the other).

Additionally, the log link does not allow for an easy comparison of relative risk for different explanatory variables since it does not produce results in terms of the relative risk ratio.

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