No, the sound wouldn't be twice as loud as that of either flutist playing alone at that intensity. The increase in sound intensity would be less than twice as loud.
This is because when two sound waves coincide, the amplitude of the resulting sound wave is the sum of the amplitudes of the individual sound waves. That is, when two identical sound waves come together, they create a new sound wave that is slightly louder than the original sound wave, but not twice as loud.
Furthermore, sound intensity is affected by the distance from the sound source, and when two flutists are playing together, the sound waves produced have to travel further before they reach the listener, thus reducing the intensity of the sound.
Know more about flutist here
https://brainly.com/question/2386102#
#SPJ11
is it possible for an observer to travel fast enough so that in his system the earthquake happens also exactly now?
Yes, it is theoretically possible for an observer to travel fast enough so that in his system the earthquake happens also exactly now. This is due to the fact that time slows down as an object approaches the speed of light, a phenomenon known as time dilation.
The equation for time dilation states that the elapsed time T observed in the frame of reference of an observer travelling at velocity v is given by
[tex]T = T0 / \sqrt{(1 - v^2/c^2)}[/tex] ,
where ,T0 is the elapsed time as observed from the reference frame of an observer at rest relative to the travelling object, c is the speed of light, and v is the velocity of the travelling object. Therefore, the greater the velocity of the travelling object, the slower the elapsed time in its reference frame.
For an observer to travel fast enough so that in his system the earthquake happens also exactly now, he would need to travel at a velocity equal to or greater than the speed of light. This is impossible according to Einstein's theory of relativity, since nothing can travel faster than the speed of light in a vacuum.
for such more question on earthquake
https://brainly.com/question/20409140
#SPJ11
if the sun is located at one focus of earth's elliptical orbit, the earth is at the other focus. question 20 options: true false
calculate the work done on the block by the spring during the motion of the block from its initial position to where the spring has returned to its uncompressed length.
The work done on the block by the spring during its move from its initial position to where the spring has returned to its uncompressed length is[tex]W = (1/2) \times k \times x^2[/tex].
We need to know the spring constant (k) and the displacement of the block (x) from its initial position to the position where the spring has returned to its uncompressed length. We can use the formula:
W = (1/2) * k * x^2
where W is the work done on the block, k is the spring constant, and x is the displacement of the block.
This formula is derived from the potential energy stored in the spring, which is given by:
U = (1/2) * k * x^2
where U is the potential energy stored in the spring.
When the block is initially at rest, the spring is compressed, and it has potential energy given by U = - (1/2) * k * x^2, where x is the initial compression of the spring.
Note that the negative sign indicates that the work done by the spring is negative, which means that the spring is doing work on the block in the opposite direction to the displacement of the block. This is because the spring force is always directed opposite to the displacement of the block.
As the block is released, the spring begins to push it back to its uncompressed length, and the block begins to move.
The work done on the block by the spring is equal to the change in potential energy of the spring, which is given by:
W = U_final - U_initial
Since the final position of the block is where the spring has returned to its uncompressed length, the final potential energy of the spring is zero. Therefore, the work done on the block by the spring is:
W = U_initial
Substituting the initial potential energy of the spring into this equation, we get:
W = (1/2) * k * x^2
Therefore, the work done on the block by the spring during its move from its initial position to where the spring has returned to its uncompressed length is given by the formula:
W = (1/2) * k * x^2
Learn more about spring:
https://brainly.com/question/14670501
#SPJ11
Air at atmospheric pressure of inside a of Hg is trapped availaible 760mm. container piston. The piston is so that the volume 100 km² to 150 dm³. the with a moveable pulled out slowly is increased from temperature remaining constant. What will be presture of the air?answer of this numerical?????
If the piston is positioned so that the volume is between 100 km² and 150 dm³, the air pressure within the container is 506.67 mm Hg. the from a moveable drawn out slowly while the temperature stays the same.
How do you determine air pressure?We can rewrite the equation as P = nRT/V using the ideal gas law, where PV = nRT, where P is pressure, V is volume, n is number of moles of gas, R is ideal gas constant, and T is temperature.
We can assume that n, R, and T are constants because the temperature doesn't change. Hence, we can write:
P1V1 = P2V2
P1(100) = P2 x (150)
Upon solving for P2, we obtain:
P2 = (P1 x V1) / V2
P2 = 506.67 mmHg
To learn more about pressure visit:
brainly.com/question/15265703
#SPJ9
true or false: energy is the capacity to do work and work is anything that involves moving matter against an opposing force.
The given statement "Energy is the capacity to do work and work is anything that involves moving matter against an opposing force" is TRUE. Energy is the capacity to do work, which is defined as any action that requires the application of a force to move matter. This includes tasks such as lifting a book, pushing a door open, or running.
Energy refers to the capacity of a physical system to perform work. Energy is generally used to complete tasks, such as moving an object from one location to another, heating up or cooling down a material, or lighting up a room. Work is defined as the transfer of energy to an object via a force applied to the object over a given distance, as per the statement. Work is usually identified as the displacement of an object through a force applied to it in the direction of its displacement against an opposing force.Energy and work are two distinct but interrelated concepts in physics. Energy is the capacity to perform work, and work is the transfer of energy from one object to another through a force acting over a distance. Energy and work are both expressed in joules (J), the unit of energy in the International System of Units (SI).
For more details on energy, click on below link:
https://brainly.com/question/17290830
#SPJ11
What is the magnitude of the applied electric field inside an aluminum wire of radius 1. 0 mm
that carries a 4. 0- A
current? [
σaluminum
= 3. 6 ×
10 7
A/(V⋅m)
]
The following formula may be used to determine how large the electric field is within the aluminium wire:
E = J/σ
E, J, and are the electric field, the current density, and the conductivity of aluminium, respectively.
where A is the wire's cross-sectional area and I is the current.
The following formula may be used to get the cross-sectional area of the wire:
A = πr^2
where r is the wire's radius.
We obtain the following by substituting the aluminum's electrical conductivity value from the problem:
E = J/σ
learn more about aluminium wire here:
https://brainly.com/question/30899929
#SPJ4
every atom (other than hydrogen and helium) that you see around us, making up everything including the earth, is literally group of answer choices from the big bang star stuff, from stars
Every atom other than hydrogen and helium that we see around us is actually the result of nucleosynthesis, a process of nuclear fusion in stars that creates heavier elements.
During nucleosynthesis, two hydrogen atoms collide and form helium, which is then subjected to intense pressures and temperatures that allow the helium to fuse into heavier elements such as,
oxygen, nitrogen, and carbon. This process repeats until the heavier elements that form the core of stars, like iron and nickel, are created.
The process of fusion is ongoing and eventually the star runs out of fuel and explodes in a supernova, releasing the material that was created within it.
This material is then scattered across the universe, eventually forming clouds of gas and dust that coalesce to create planets, moons, and other bodies, including Earth.
All of the atoms that make up our planet, from oxygen to iron, are the direct result of this process, which began in the big bang and continues to the present day.
to know more about atom refer here:
https://brainly.com/question/30898688#
#SPJ11
how much work is done lifting a 15 pound object from the ground to the top of a 30 foot building if the cable used weighs 2 pounds per foot
The amount of work required to lift a 15 pound object from the ground to the top of a 30 foot building if the cable used weighs 2 pounds per foot is 1050 foot-pounds.
In order to solve the problem, we can use the formula W = Fd. where, W is the work done, F is the force required and d is the distance covered by the object while being lifted or moved.
So, we have to first calculate the force required to lift the object. Let us assume the force required is F, then
F = weight of object + weight of cable
F = 15 + 2 * 30
F = 75 pounds
Therefore, the force required to lift the object is 75 pounds. Now, we can calculate the work done as follows:
W= Fd
W = 75 * 14
W = 1050 foot-pounds
Therefore, the amount of work required to lift a 15 pound object from the ground to the top of a 30 foot building if the cable used weighs 2 pounds per foot is 1050 foot-pounds.
Learn more about work of move at https://brainly.com/question/28356414
#SPJ11
an electron microscope is designed to resolve objects as small as 0.49 nm. what energy electrons must be used in this instrument?
An electron microscope is designed to resolve objects as small as 0.49 nm by using electrons as a source of illumination.
This requires electrons of high energy, typically in the range of 50 to 300 keV (kilo electronvolts). To put this into perspective, 50 keV is equivalent to 8.25 x 10^-17 Joules of energy.
Read more about the topic microscope:
https://brainly.in/question/3297453
#SPJ11
a sample of paramagnetic material is located very close to a bar magnet, in a region in which the field of the magnet appears almost uniform over small distances. if the magnet is kept in the same location but rotated in a counter-clockwise direction so that the sample is no longer in the quasi-uniform region of the magnetic field, how will the sample respond?
When a sample of paramagnetic material is moved out of the quasi-uniform region of a magnetic field, it will experience a torque and tend to align with the magnetic field, but the magnetization may be weaker and less stable due to the non-uniform field.
The paramagnetic materials are also affected by :
When a paramagnetic material is placed close to a bar magnet in a region where the magnetic field appears almost uniform, the material aligns itself with the direction of the magnetic field lines. This happens because the material is weakly attracted to the magnetic field due to its paramagnetic properties.However, if the magnet is rotated in a counter-clockwise direction, the magnetic field lines near the paramagnetic material will no longer be uniform. As a result, the material will no longer be able to align itself with the magnetic field lines and will experience a torque instead. The torque will cause the material to rotate until it aligns itself with the new direction of the magnetic field lines.This phenomenon is similar to how a compass needle behaves when it is placed near a magnet. When the magnet is rotated, the compass needle will also rotate until it aligns itself with the new direction of the magnetic field lines.The paramagnetic material will align itself with the magnetic field lines when the field is uniform, but when the field is no longer uniform due to the rotation of the magnet, the material will rotate until it aligns itself with the new direction of the magnetic field lines.
To learn more about the 'magnetic field':
https://brainly.com/question/7802337
#SPJ11
imagine you have a sensitive radio telescope and you would like to look at the sun. is it reasonable to expect that you would see it?
Yes, it is reasonable to expect that you would see the Sun with a sensitive radio telescope.
Radio waves can penetrate through the clouds and the atmosphere, so with a powerful radio telescope you can observe the Sun even on a cloudy day.
Gather the necessary components of the radio telescope, such as a dish and receiver. Point the radio telescope towards the Sun. Tune the receiver to the proper frequency. Take a look at the results from the telescope and observe the Sun.
Therefore, you can expect that you would see the Sun with a sensitive radio telescope.
To know more about radio telescope click here:
https://brainly.com/question/3964280
#SPJ11
b) what happens to the reaction rate when the concentration (absorbance) of the reactants is quadrupled? determine the reaction order by solving the following equations. show a sample computation in your lab notebook.
Rate 4/ Rate 2 = [CV 4]’/[CV 2]’ <-> X = ________ Rate 5/ Rate 3 = [CV 5]’/[CV 3]’ <-> X = ________
When the concentration of the reactants is quadrupled, the reaction rate depends on the reaction order. To determine the reaction order, we can solve the given equations:
1.[tex]Rate 4 / Rate 2 = [CV 4]'^x / [CV 2]'^x[/tex]
2.[tex]Rate 5 / Rate 3 = [CV 5]'^x / [CV 3]'^x[/tex]
To find the reaction order (x), we first need to know the values of the rates (Rate 4, Rate 2, Rate 5, Rate 3) and the concentrations (CV 4, CV 2, CV 5, CV 3). Once you have these values, you can plug them into the equations and solve for x.
For example, let's say the given values are:
Rate 4 = 8, Rate 2 = 2, Rate 5 = 10, Rate 3 = 1
CV 4 = 4, CV 2 = 1, CV 5 = 5, CV 3 = 2
Now plug these values into the equations:
1.[tex]8 / 2 = (4^x) / (1^x)[/tex]
2. [tex]10 / 1 = (5^x) / (2^x)[/tex]
Solve for x:
1. [tex]4 = 4^x[/tex]
2. [tex]10 = (5^x) / (2^x)[/tex]
From equation 1, we can deduce that x = 1 (since 4^1 = 4). Thus, the reaction order is 1, which means the reaction rate is directly proportional to the concentration of the reactants. Therefore, when the concentration of the reactants is quadrupled, the reaction rate will also be quadrupled.
To learn more about reaction order https://brainly.com/question/28179168
#SPJ11
A Frisbee gets stuck in a tree. You want to get it out by throwing a 1.0-kg rock straight up at the Frisbee. If the rock’s speed as it reaches the Frisbee is 4.0 m/s, what was its speed as it left your hand 2.8 m below the Frisbee? Specify the system and the initial and final states.
Answer: The rock's speed as it left your hand was 8.8 m/s.
Explanation: The system is the rock and the Earth. The initial state is the rock at rest in your hand 2.8 m below the Frisbee. The final state is the rock hitting the Frisbee at a speed of 4.0 m/s.
Using conservation of energy, we know that the initial potential energy of the rock-Earth system is transformed into both kinetic energy and potential energy at its maximum height. Therefore, we can use the conservation of energy equation:
potential energy (initial) = kinetic energy (final) + potential energy (final)
mgh = 1/2mv^2 + mgh
where m is the mass of the rock, g is the acceleration due to gravity, h is the height that the rock has been raised, and v is the velocity of the rock.
We can solve for the initial velocity by rearranging the equation:
v = sqrt(2gh + v^2)
Plugging in the values, we get:
v = sqrt(2 * 9.81 * 2.8 + 4^2)
v ≈ 8.8 m/s
Therefore, the rock's speed as it left your hand was 8.8 m/s.
65. a 150-w lightbulb emits 5% of its energy as electromagnetic radiation. what is the radiation pressure on an absorbing sphere of radius 10 m that surrounds the bulb?
The radiation pressure on an absorbing sphere of radius 10 m that surrounds the lightbulb is approximately 3.98 x 10^-13 Pa.
The radiation pressure on an absorbing sphere can be calculated using the formula,
P = (2 * I) / c
where P is the radiation pressure, I is the intensity of the radiation, and c is the speed of light.
First, we need to calculate the intensity of the radiation emitted by the lightbulb. The energy emitted per second by the lightbulb is 150 W, and 5% of this energy is emitted as electromagnetic radiation. Therefore, the energy emitted as radiation is,
E = 150 W * 0.05 = 7.5 W
The intensity of the radiation is the power per unit area, and can be calculated by dividing the energy emitted per second by the surface area of a sphere with a radius of 10 m,
I = E / (4 * pi * r^2) = 7.5 W / (4 * pi * 10^2 m^2) = 5.98 x 10^-5 W/m^2
Now we can calculate the radiation pressure, P = (2 * I) / c = (2 * 5.98 x 10^-5 W/m^2) / 3 x 10^8 m/s = 3.98 x 10^-13 Pa
To know more about radiation pressure, here
brainly.com/question/23972862
#SPJ4
what is the purpose of wires in a circuit? why do we use wires to connect power supplies to resistors or other objects on a circuit board? why can't we just use power supplies and resistors?
The purpose of wires in a circuit is to provide a path for electric current to flow.
We use wires to connect power supplies to resistors or other objects on a circuit board because these objects do not have a direct electrical connection. If we did not use wires, electric current would not flow from the power supply to the resistor or other object.
Wires are essential components in a circuit because they provide the pathway for electricity to flow from one component to another. Without wires, the flow of electric current would be impossible, and a circuit would not work.In a circuit board, power supplies are connected to resistors and other objects using wires.
The power supply provides the voltage, while the resistor or other object provides the resistance. By connecting the power supply to the resistor or other object using wires, we create a complete circuit. Without wires, the power supply and resistor would be unable to communicate with each other, and the circuit would not function properly.
In conclusion, wires are an essential component of a circuit. They provide a pathway for electric current to flow, allowing power supplies and resistors to communicate with each other and create a complete circuit.
To know more about electric current click on below link:
https://brainly.com/question/2264542#
#SPJ11
Compared to a landscape that develops in a cool, dry climate, a landscape that develops in a warm, rainy climate will most likely weather and erode a. Slower, so the landforms are more angular b. Slower, so the landforms are more rounded c. Faster, so the landforms are more angular d. Faster, so the landforms are more rounded
A landscape that develops in a warm, rainy climate will most likely weather and erode faster, so the landforms are more rounded.
This is because in a warm, rainy climate, there is more water available to weather and erode the landforms. The water can penetrate cracks and crevices in the rocks, dissolve minerals, and carry away sediments. Over time, this can lead to the rounding of edges and the smoothing of surfaces, resulting in more rounded landforms.
In contrast, in a cool, dry climate, there is less water available to weather and erode the landforms. This can result in slower rates of erosion and less rounding of the landforms.
Learn more about A landscape
https://brainly.com/question/840314
#SPJ4
first you walk 5.38 m in a direction 35.0 degrees north of east. then you walk 8.50 m in a direction 60.0 degrees south of east. what is your total displacement for this trip, both magnitude and direction?
The total displacement for this trip is 10.50 m in a direction 25.0 degrees south of east.
The total displacement for this trip can be calculated by first breaking the trip into its two components and then combining the two.
First, you walked 5.38 m in a direction 35.0 degrees north of east. This can be written in vector form as <5.38, 35.0>.
Second, you walked 8.50 m in a direction 60.0 degrees south of east. This can be written in vector form as <8.50, -60.0>.
To find the total displacement, we can add the two vectors together: <5.38, 35.0> + <8.50, -60.0> = <13.88, -25.0>. This means that the total displacement is 13.88 m in a direction 25.0 degrees south of east.
We can also calculate the magnitude of the displacement by using the Pythagorean theorem: d = √(5.38² + 8.50²) = 10.50 m. This means that the total magnitude of the displacement is 10.50 m.
In summary, the total displacement for this trip is 10.50 m in a direction 25.0 degrees south of east.
For more such questions on Displacement.
https://brainly.com/question/6516113#
#SPJ11
Which label identifies a rarefaction?
O A
Ов
O C
OD
In the longitudinal wave ,B represents the phenomenon of rarefaction. Rarefaction refers to the region of a sound wave where the pressure of the medium is lower than its normal value.
What is rarefaction?Rarefaction is a term used to describe a decrease in the density or pressure of a substance, such as a gas or liquid. In the context of sound waves, rarefaction refers to the region of a sound wave where the pressure of the medium is lower than its normal value, causing the particles of the medium to be spread further apart than usual.
Sound waves are composed of regions of compression and rarefaction that alternate in a regular pattern as the wave travels through a medium. In a compressional (longitudinal) sound wave, the particles of the medium are pushed together in regions of compression, while they are spread apart in regions of rarefaction. These changes in pressure and density cause the wave to propagate through the medium.
In general, rarefaction can occur in any medium, not just in sound waves. For example, in a gas, rarefaction can be caused by a decrease in pressure, temperature or density. In a liquid, rarefaction can be caused by a decrease in pressure or density. Rarefaction waves can be observed in many natural phenomena, such as atmospheric pressure waves, seismic waves, and waves on the surface of water.
To know more about rarefaction, visit:
https://brainly.com/question/8401754
#SPJ1
What velocity of a body will you obtain from the position vs.
time graph for the following data: position from origin is 0 m, 10
m, 20 m, 30 m and 40 m at instants 0 s, 1 s, 2 s, 3 s, 4 s?
Answer:10 m/s
Explanation:
the acceleration of a super-vehicle is proportional to the difference between 240 km/h and the velocity of this sports car. if it can accelerate from rest to 120 km/h in one second, what speed can it reach from rest in three seconds?
The speed that the car can reach from rest in three seconds is 79.73 km/hr.
The acceleration of a super-vehicle is proportional to the difference between 240 km/h and the velocity of this sports car.
Initial speed u = 0 km/hr,
Final speed v = ? t
Time t = 3 s,
Velocity at a particular time = v,
Acceleration = proportional to the difference between 240 km/h and the velocity of this sports car Given acceleration is proportional to the difference between 240 km/h and the velocity of this sports car
So, a ∝ (240 - v)To find constant of proportionality k, Let's assume acceleration when velocity is 0 is 100m/s² when t=1sWhen v=0, a=k(240 - 0) = 240k ⇒ 100=k(240 - 0) = 240k ⇒ 100=k
Therefore acceleration is a=100(240-v)When t=3 seconds, u=0km/hr, v=? and a=100(240-v)Using the formula, v=u+atWe get, v = u + at=0+(100(240 - v)) * 3v = 24000 - 300v⇒ 301v = 24000⇒ v = 79.73 km/hr
Therefore, the speed that the car can reach from rest in three seconds is 79.73 km/hr.
Note: While solving these types of questions, we should try to find out the constant of proportionality and then substitute the values to get the result.
Learn more about Velocity
brainly.com/question/17127206
#SPJ11
a student exerts a horizontal force of 40.0 n with her hand and pushes a 10.0 kg box a distance of 2.0 m across a frictionless floor. calculate the magnitude of the work done by the student. group of answer choices 40.0 j 60.0 j 80.0 j 100.0 j
The magnitude of the work done by the student is 80.0 J. Option c is correct.
The work done by the student can be calculated using the formula,
W = Fd cos(theta)
where W is the work done, F is the force exerted, d is the distance moved, and theta is the angle between the force vector and the displacement vector.
In this problem, the force exerted by the student is a horizontal force of 40.0 N, and the box is moved a distance of 2.0 m across a frictionless floor. Since the force and displacement vectors are in the same direction (horizontal), the angle between them is 0 degrees, so cos(theta) = 1. Therefore, we can calculate the work done as,
W = (40.0 N)(2.0 m) cos(0) = 80.0 J
Hence, option c is correct choice.
To know more about work, here
brainly.com/question/29342548
#SPJ4