If you want to increase the mechanical advantage of a machine, what do you also have to increase?
Group of answer choices

The distance the force is applied over while using the machine

The amount of force applied while using the machine

The amount of energy put into the machine while using it

The amount of time the force is applied while using the machine

The basketball has a slugs density of 0.0228 per gallon (m/V = 0.0427 slugs/1.8697 gallons) (approximately).

Based on normal gravity, the international foot, and the avoirdupois pound, one slug weighs 32.1740 lb (14.59390 kg). An item with a mass of 1 slug would weigh around 32.2 lbf, or 143 N, at the Earth's surface.

We need to apply the following conversion factor to convert grammes to slugs:

1 slug = 14.5939 kg

1 kg = 1000 g

Therefore:

1 slug = 14.5939 kg = 14.5939 x 1000 g = 14593.9 g

So, the mass of the basketball in slugs is:

m = 624 g / 14593.9 g/slug = 0.0427 slugs

To convert from cubic feet to gallons, we need to use the following conversion factor:

1 gallon = 0.133681 ft^3

Therefore:

0.25 ft⁻³ = 0.25 / 0.133681 = 1.8697 gallons

So, the volume of the basketball in gallons is:

V = 1.8697 gallons

The density of the basketball in slug/gal is:

ρ = m / V = 0.0427 slugs / 1.8697 gallons = 0.0228 slug/gal (approximately)

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Change in kinetic energy is 6.4 Joules when a block of wood is pushed against a relaxed spring to compressed it 0.080m.

The spring constant is the force necessary to stretch or compress a spring divided by the spring's length. It is used to determine the stability or instability of a spring and, by extension, the system for which it is designed. The symbol k stands for the "spring constant," a value that indicates how "stiff" a spring is. If k is large, it signifies that stretching it a specific length requires more force than stretching a less stiff spring the same length.

Use formula

change in kinetic energy = [tex]\frac{1}{2}[/tex] × k × [tex]x^{2}[/tex]

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When an object slows down, it has a negative acceleration, also known as deceleration.

Deceleration is a vector quantity, meaning it has both magnitude (the amount of change in velocity per unit time) and direction (opposite to the direction of motion).

Thus, the rate of deceleration is often measured in terms of the object's acceleration, which is expressed in meters per second squared (m/s^2) or other appropriate units. When an object slows down, its acceleration is negative, meaning it is directed opposite to its initial motion. The greater the negative acceleration, the faster the object slows down.

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Answer:

hi, I am an IGCSE student and i know pretty well about physics, may I help you with any question?

Explanation:

When a 0.80 Kg block is used in place of a 0.25 Kg block, the length of the string is increased by 19.6 cm.

The formula used by the Hooke's Law Calculator is Fs = -kx, where F is the spring's restoring force, k is the spring constant, and x is the displacement, or the length by which the spring is being stretched

We'll start by determining the spring's string constant. Specifics below:

Extension (e) = 6.0 cm

Mass (m) = 0.25 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Force (F) = mg = 0.25 × 9.8 = 2.45 N

Spring constant (K) =?

F = Ke

2.45 = K × 6

Divide both sides by 6

K = 2.45 / 6

K = 0.40 N/cm

The extension will be calculated after the 0.25 kg block is replaced with the 0.80 kg block. As demonstrated below:

Mass (m) = 0.80 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Force (F) = mg = 0.80 × 9.8 = 7.84 N

Spring constant (K) = 0.40 N/cm

Extension (e) = ?

F = Ke

7.84 = 0.40 × e

Divide both sides by 0.40

e = 7.84 / 0.40

e = 19.6 cm

We may thus deduce from the preceding computation that the spring will lengthen by 19.6 cm.

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Using the principle of the echo, we can see that the first echo can be heard after  0.2 s.

In acoustics, an echo refers to the reflection of sound waves off a surface and back to the listener. When sound waves encounter a hard surface, such as a wall or mountain, some of the energy is reflected back towards the source.

To find the time interval for the first echo;

v = 2x/t

t = 2x/v

t = 2(33)/330

t = 0.2 s

Echoes are often heard in large open spaces such as auditoriums, canyons, or empty rooms. They can also be artificially created using electronic sound processing equipment, such as reverb effects in music production or sound systems in large events.

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Answer:

Circadian rhythm refers to the natural cycle of physical, mental, and behavior changes that the body goes through in a 24-hour cycle.

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When light is travelling through ice, its wavelength is 4.50 10⁻⁷ metres.

Since glass has a higher index of refraction than air, light travels more slowly through glass than through air (n=c/v). Although the wavelength does not change, the frequency does because the speed does.

The following equation describes the relationship between the wavelengths of light in two different media:

n1 * λ1 = n2 * λ2

We may rewrite this equation to get the wavelength of the light in the second medium while assuming that the light's frequency stays constant: λ2 = (n1 / n2) * λ1

For water, the refractive index is about 1.333, and for ice, it is about 1.31. Therefore, we have:

λ2 = (1.333 / 1.31) * 4.42×10⁻⁷ m

λ2 = 4.50×10⁻⁷ m

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Scientists typically collect ozone samples from the stratosphere, which is the atmospheric layer located between about 10 and 50 kilometers (6 to 30 miles) above the Earth's surface.

The stratosphere is the layer of the Earth's atmosphere located above the troposphere and below the mesosphere. It extends from about 10 kilometers (6 miles) to about 50 kilometers (30 miles) above the Earth's surface.

The stratosphere is characterized by a gradual increase in temperature with altitude, due to the absorption of ultraviolet radiation by ozone in the stratosphere.

This is where most of the Earth's ozone is found and where the ozone layer is located. The ozone layer absorbs harmful ultraviolet (UV) radiation from the sun, protecting life on Earth from its harmful effects. Scientists collect air samples from this layer using airplanes or weather balloons equipped with specialized instruments.

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(a) The weight of the sled is given by the product of its mass and the acceleration due to gravity:

w = m*g = 47.0 kg * 9.81 m/s^2 = 461.07 N

(b) The force needed to start the sled moving is the maximum force of static friction, which is given by:

f_s = μ_s * w = 0.30 * 461.07 N = 138.32 N

(c) Once the sled is moving at a constant velocity, the force needed to keep it moving is equal to the force of kinetic friction, which is given by:

f_k = μ_k * w = 0.10 * 461.07 N = 46.11 N

(d) The total force needed to accelerate the sled at 3.3 m/s^2 is the sum of the force of kinetic friction and the force required to produce the desired acceleration:

F = f_k + m*a = 46.11 N + 47.0 kg * 3.3 m/s^2 = 200.97 N

The image is reversed if the image height has a negative sign. The image is inverted and has a height of -6.45 cm.

The lens equation describes how a convex lens's object distance (d o), image distance (d i), and focal length (f) relate to one another:

1/f = 1/d_o + 1/d_i

1/d_i = 1/15.0 cm - 1/35.0 cm 1/d_i = 1/f - 1/d o

1/d_i = 0.0667 cm -1

d_i = 15.0 cm

The image's magnification (M) is determined by:

M = - d_i / d_o

M = -15.0 cm / 35.0 cm

M = -0.43

M = h_i / h_o

h_i = M x h_o

The value for h_o is 15.0 cm. With M = -0.43, we obtain:

h_i = -0.43 * 15.0 cm

h_i = -6.45 cm

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Answer: C6H5CH3 (toluene) + Br2 + Mg + CO2 + oxidizing agent → C6H5CH2COOH (2-phenylethanoic acid)

Explanation:

2-Phenylethanoic acid, also known as phenylacetic acid, can be prepared from toluene through the following steps:

Bromination: Toluene is brominated using Br2 and FeBr3 as a catalyst to form 2-bromotoluene.

Grignard reaction: The 2-bromotoluene is reacted with magnesium (Mg) in dry ether to form phenylmagnesium bromide (C6H5MgBr).

Acidification: The phenylmagnesium bromide is then reacted with carbon dioxide (CO2) to form 2-phenylpropanoic acid (also known as phenylpropionic acid). This reaction is carried out by bubbling CO2 gas through the solution of phenylmagnesium bromide in dry ether.

Oxidation: The 2-phenylpropanoic acid is then oxidized using a strong oxidizing agent, such as potassium permanganate (KMnO4) or chromic acid (H2CrO4), to form 2-phenylethanoic acid.

The overall reaction can be represented as follows:

C6H5CH3 (toluene) + Br2 + Mg + CO2 + oxidizing agent → C6H5CH2COOH (2-phenylethanoic acid)

Note: This is a complex reaction sequence and should only be attempted by experienced chemists in a well-equipped laboratory with appropriate safety measures.

C. The period of a planet (time it takes to go around the sun) is not related to its mass.

The first law states that the planets follow elliptical orbits with the sun at one of its foci, the second law states that an imaginary line drawn from the sun to a planet sweeps out equal areas in equal times, and the third law states that the square of the period of a planet is directly proportional to the cube of its average distance from the sun. Since the period of a planet is not related to its mass, answer C is not one of Kepler's laws of planetary motion.

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The effort required to compress an ideal gas is therefore given by W = -1/2 nRT ln(V2/V1) during an isothermal process.

When an ideal gas is subjected to isothermal expansion (T = 0) in a vacuum, the work done is equal to zero as pex=zero. Joule established q = 0 empirically; hence, U = 0. Equation 1 can be written as: for both reversible and irreversible isothermal changes. Reversible isothermal change q = -w = pex (Vf-Vi)

nRT = ln(V2/V1) - W

If we solve for W, we obtain:

W = ln(V1/V2)nRT (v) If we condense this phrase, we get:

W=-nRT ln(V2/V1).

W=-RT ln(V2/V1).

W=-1/2nRT ln(V2/V1)

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n = 1.50. In this case, the index of refraction is 1.50, which demonstrates that the lens is able to refract light in order to form an image.

Let us calculate the focal length of the lens:

F = 1/[(1/r1)+(1/r2)]

F = 1/[(1/3.00 cm)+(1/3.00 cm)]

F = 1.50 cm

Calculate the index of refraction:

n = 1/(1/f - 1/d)

n = 1/(1/1.50 cm - 1/1.98 cm)

n = 1.50

Both of these surfaces cause light rays to bend and converge at a focal point on the other side of the lens. The index of refraction of the lens can be calculated by using the equation n = 1/(1/f - 1/d), where f is the focal length and d is the distance of the image.

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(a)

Potential Energy  = 4.95 J

Kinetic Energy =0.132 J

b.) the total mechanical energy of the ball before Hanif spikes it is 5.08 J.

Potential energy (PE) = mgh

Kinetic energy (KE) = (1/2)mv^2

m = 0.226 kg

h = 2.29 m

v = 1.06 m/s

g = 9.81 m/s^2 (acceleration due to gravity)

PE = mgh = (0.226 kg)(9.81 m/s^2)(2.29 m) = 4.95 J

KE = (1/2)mv^2 = (1/2)(0.226 kg)(1.06 m/s)^2 = 0.132 J

(b) The total mechanical energy of the ball before Hanif spikes it is the sum of its potential and kinetic energy:

Total mechanical energy = PE + KE = 4.95 J + 0.132 J = 5.08 J

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We can use the conservation of momentum to solve both problems:

Conservation of momentum:

0 = m1(v1') + m2(v2')

where m1 = 50 kg, v2' = 3 m/s, and m2 = 80 kg. We can solve for v1' to get:

v1' = -(m2/m1) v2'

v1' = -(80 kg/50 kg) (3 m/s) = -4.8 m/s

Therefore, the 50 kg swimmer moves away from the raft with a velocity of -4.8 m/s.

Conservation of momentum:

m1(v1) + m2(v2) = m1(v1') + m2(v2')

where m1 = 90 kg, v1 = 6 m/s, m2 = 60 kg, and v1' = 4 m/s. We can solve for v2 to get:

v2 = (m1v1 + m2v2 - m1v1') / m2

v2 = (90 kg)(6 m/s) + (60 kg)(2 m/s) - (90 kg)(4 m/s) / 60 kg

v2 = -1 m/s

Therefore, the velocity of the 60 kg player after the collision is -1 m/s, which means they are moving in the opposite direction to the 90 kg player.

We must define a function that accepts an input parameter x and returns the associated height y in order to use the golden-section search. By entering the specified numbers for yo, vo, 0o, g, and x into the formula.

The golden-section search algorithm can now be used to identify the value of x that maximises y. We begin by setting the error tolerance to 10% and starting with the basic hypotheses .

Calculate the values of x2 and x3 using the golden ratio:Evaluate the function at x2 and x3:If y2 > y3, the maximum is between x1 and x3, so we set x4 = x3 and repeat from step 1. Otherwise, the maximum is between x2 and x4, so we set x1 = x2 and repeat from step.

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Answer: if the predator sees the light bugs easier than the dark bugs then the bright bug will most likely go extinct

Explanation:

The nearest mountain is 4,550 m away. see the calculation procedures

Given data

Let us multiply the velocity of sound (325 m/s) by the time it takes for the echo to return (14 seconds).

325 m/s x 14 seconds = 4,550 m.

Therefore, the nearest mountain is 4,550 m away.

The velocity of sound is a measure of how quickly sound travels through a medium. In this example, the velocity of sound is 325 m/s and it takes 14 seconds for an echo to return from the nearest mountain.

This means the mountain is 4,550 m away. Yodeling in the mountains is a great way to appreciate the power of sound and its ability to move through space.

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Answer:

Explanation:

a) The potential energy gained by the froghopper at the maximum height of 293 mm can be calculated using the formula:

ΔPE = mgh

where ΔPE is the change in potential energy, m is the mass, g is the acceleration due to gravity, and h is the maximum height.

Substituting the given values, we get:

ΔPE = (12.8 × 10^-6 kg) × (9.81 m/s^2) × (0.293 m) = 3.69 × 10^-6 J

The kinetic energy of the froghopper at takeoff can be calculated using the formula:

KE = 0.5mv^2

where KE is the kinetic energy and v is the takeoff speed.

Substituting the given values, we get:

KE = 0.5 × (12.8 × 10^-6 kg) × (2.71 m/s)^2 = 4.75 × 10^-5 J

Therefore, the total energy generated by the froghopper for the jump is the sum of the potential and kinetic energy, which is:

Total energy = ΔPE + KE = 3.69 × 10^-6 J + 4.75 × 10^-5 J = 5.12 × 10^-5 J

Expressing the answer in microjoules, we get:

Total energy = 5.12 × 10^-5 J = 51.2 µJ

b) The energy per unit body mass required for the jump can be calculated by dividing the total energy generated by the froghopper by its body mass.

Substituting the given values, we get:

Energy per unit body mass = (5.12 × 10^-5 J) ÷ (12.8 × 10^-6 kg) = 4 J/kg

Therefore, the energy per unit body mass required for the jump is 4 J/kg.

When particle A is infinitely far from particle B, option 1, it moves at its top speed.

Initial velocity of the first particle was u₁ = 4×10 ⁴m/s Initial velocity of the second particle was u₂ = 6×10⁴ m/s Initial velocity of the third particle was v = Final velocity of both particles after collision was v =

Use the idea of linear momentum conservation;

k e = 9 ₓ 10⁹ N  m² / C² and e = 1.6 ₓ 10⁻¹⁹ C.)

m2, v2 represent the mass and speed of a 10 kilogram item (before collision)

M1, V1 stand for mass and speed.

v(m₁+ m₂) = m₁u₁ - m₂u₂.

11 x 2 - 11 x 2 = v( 11 + 11)

22 - 22 = v(22) (22)

0 = 22v = 0/22  = 0

As a result, both particles are at rest.

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Here is a free body diagram of the block on the incline:

         /|

        / |

       /  |

      /   |

     /    |

    /     |

   /θ    |

  /       |

 /         |

/           |

/____________|

        N

        |

        |

        |

        |<----f_kinetic

        |_______  <----f_gravity

Static force:

f_static is less than the maximum force of static friction, the block will not slide and will remain at rest.

In this diagram, θ represents the angle of the incline, N represents the normal force exerted on the block by the incline, f_gravity represents the force of gravity pulling the block down the incline, and f_kinetic represents the force of kinetic friction opposing the motion of the block. Since the block is at rest, the net force must be zero.

We can calculate the force of gravity using the formula:

f_gravity = mgcosθ

where m is the mass of the block, g is the acceleration due to gravity (9.81 m/s^2), and θ is the angle of the incline. Substituting the given values, we get:

f_gravity = (5.0 kg)*(9.81 m/s²)*cos(30°) = 42.7 N

The normal force, N, is perpendicular to the incline and equal in magnitude to the component of the force of gravity perpendicular to the incline. We can calculate it using the formula:

N = f_gravity*sinθ

Substituting the given values, we get:

N = (5.0 kg)*(9.81 m/s²)*sin(30°) = 24.5 N

The force of static friction, f_static, can be found using the formula:

f_static = μ_static*N

where μ_static is the coefficient of static friction. Substituting the given value, we get:

f_static = (0.5)*(24.5 N) = 12.3 N

Since the block is at rest, the force of static friction must be equal in magnitude to the component of the force of gravity parallel to the incline:

f_static = f_gravitysinθ = (5.0 kg)(9.81 m/s²)*sin(30°) = 24.5 N

Since f_static is less than the maximum force of static friction, the block will not slide and will remain at rest.

We don't need to determine the force of kinetic friction since the block is not sliding.

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We can find the time for which the glider is in contact with the spring by using the impulse-momentum theorem:

Impulse = Change in momentum

The impulse of the force exerted by the spring is given by the area under the force-time graph, which is a triangle:

Impulse = (1/2) * (1 N) * (0.02 s) = 0.01 Ns

The initial momentum of the glider is:

p1 = m * v1 = (0.5 kg) * (0.3 m/s) = 0.15 kg m/s

The final momentum of the glider is zero, since it comes to rest:

p2 = 0 kg m/s

Therefore, the change in momentum is:

Δp = p2 - p1 = -0.15 kg m/s

Setting the impulse equal to the change in momentum and solving for the time gives:

Impulse = Change in momentum

0.01 Ns = Δp = p2 - p1

0.01 Ns = 0 - 0.15 kg m/s

0.01 Ns = -0.15 kg m/s

t = Δp / Impulse = (-0.15 kg m/s) / (0.01 Ns) ≈ -15 s

The negative value for time doesn't make sense physically, so we need to check our work. Looking at the force-time graph, we see that the force is actually zero for most of the time, and only becomes non-zero when the glider is in contact with the spring. Therefore, we need to find the time for which the force is non-zero.

The force is non-zero for a duration of 0.01 s, so this is the contact time:

t = 0.01 s

Therefore, the glider is in contact with the spring for 0.01 seconds.

here's the answer. I'm not too sure about it, but good luck

The time for which the glider is in contact with the spring is approximately 0.17 s.

Momentum is a physical quantity that describes the motion of an object. It is defined as the product of an object's mass and velocity. Mathematically, momentum can be expressed as:

p = mv

where p is momentum, m is the mass of the object, and v is the velocity of the object.

Impulse is the change in momentum of an object that results from the application of a force over a certain period of time. Impulse is equal to the product of force and the time interval over which the force acts. Mathematically, impulse can be expressed as:

J = FΔt

where J is the impulse, F is the force applied to the object, and Δt is the time interval over which the force acts.

The relationship between impulse and momentum is given by the impulse-momentum theorem, which states that the impulse applied to an object is equal to the change in momentum of the object. Mathematically, the impulse-momentum theorem can be expressed as:

J = Δp

where J is the impulse, and Δp is the change in momentum of the object. This theorem is useful in analyzing collisions and other situations where forces act on objects for a finite period of time.

Here in the Question,

To find the time for which the glider is in contact with the spring, we need to use the impulse-momentum theorem, which relates the impulse (change in momentum) of an object to the force applied to it and the time over which the force is applied:

impulse = force x time = change in momentum

The momentum of the glider before it collides with the spring is:

p1 = m1v1 = (0.500 kg)(0.750 m/s) = 0.375 kg·m/s

The momentum of the glider after it rebounds from the spring is:

p2 = m2v2

We can find v2 from the velocity-time graph in Figure 1. At the moment of maximum compression, the velocity of the glider is zero, so we need to find the time at which this occurs. From the graph, we can see that this occurs at about t = 0.02 s. Therefore, the velocity of the glider after rebounding from the spring is:

v2 = -0.750 m/s

(Note that the negative sign indicates that the glider is moving in the opposite direction after rebounding.)

The change in momentum of the glider is:

Δp = p2 - p1 = m2v2 - m1v1 = (0.500 kg)(-0.750 m/s) - (0.500 kg)(0.750 m/s) = -0.750 kg·m/s

The impulse applied to the glider by the spring is equal in magnitude to the change in momentum:

impulse = Δp = -0.750 kg·m/s

We can find the time for which the force is applied by rearranging the impulse-momentum theorem:

time = impulse/force

We can find the force from the force-time graph in Figure 2. The force at the maximum compression is approximately 4.5 N. Therefore, the time for which the glider is in contact with the spring is:

time = impulse / force = (-0.750 kg·m/s) / (4.5 N) ≈ 0.167 s ≈0.17 s

Therefore, Rounding to two significant figures and including the appropriate units, the time for which the glider is in contact with the spring is approximately 0.17 s.

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Answer: I'm not entirely sure this is what you meant, but...

Velocity refers to an object's speed and acceleration.

The decay constant (λ) of a radioactive element can be calculated using the formula:

λ = ln(2) / T1/2

where ln(2) is the natural logarithm of 2 and T1/2 is the half-life of the element.

Substituting the given values, we get:

λ = ln(2) / (4 x 10^8)

λ = 1.73 x 10^-9 per year

Therefore, the decay constant of the radioactive element is 1.73 x 10^-9 per year.

The mean life (τ) of a radioactive element can be calculated using the formula:

τ = 1 / λ

Substituting the calculated value of λ, we get:

τ = 1 / (1.73 x 10^-9)

τ = 5.78 x 10^8 years

Therefore, the mean life of the radioactive element is 5.78 x 10^8 years.

The magnitude of the force due to the electric field on the charged glass ball is 2.4 x [tex]10^{-5}[/tex] N, and the Earth's magnetic field is not relevant in this scenario.

What is Magnetic Field?

A magnetic field is a field created by a magnet, moving electric charge, or changing electric field. A magnetic field can also be created by a loop of electric current. A magnetic field is a vector field, meaning it has both magnitude and direction.

The Earth's magnetic field is not relevant for the interaction between the charged glass ball and the Earth's gravitational field. Instead, we need to calculate the force due to the electric field generated by the charge on the ball.

We can use the formula for the electric force on a charged particle:

F = qE

where F is the force on the charge q, and E is the electric field at the location of the charge.

In this case, the charge on the ball is q = 1.0 x 10^-8 C, and the velocity of the ball is directed to the west, so the direction of the force should be to the north or south.

Assuming the electric field due to the charge on the ball is uniform and perpendicular to the velocity of the ball, we can use the formula for the electric field due to a point charge:

E = k*q / [tex]r^{2}[/tex]

where k is Coulomb's constant (9 x 10^9 N·[tex]m^{2}[/tex]/[tex]C^{2}[/tex]), q is the charge on the ball, and r is the distance from the charge to the point where we want to calculate the electric field.

If we assume that the ball is moving at a constant height above the Earth's surface, then the distance r is constant and we can use the above equation to find the electric field E.

E = k*q / [tex]r^{2}[/tex] = (9 x 10^9 N·[tex]m^{2}[/tex] /[tex]C^{2}[/tex]) * (1.0 x 10^-8 C) /[tex]r^{2}[/tex]

We don't know the distance r, but we do know that the electric force on the ball due to this field must be equal to the force required to cause the ball to move in a circular path, as it is in this case. The force required to maintain a circular motion of radius r with speed v is

where m is the mass of the ball. This force must be equal to the electric force on the ball:

F = qE

We can equate these two expressions to solve for the distance r

Plugging in the given values, we get:

r = 1.78 x [tex]10^{-3}[/tex] m

So the ball is moving in a circular path with radius r = 1.78 x [tex]10^{-3}[/tex]m, and the electric field at the location of the ball is:

E = 2.4 x [tex]10^{3}[/tex] N/C

Finally, we can calculate the force on the charged ball due to this electric field:

F = qE = (1.0 x [tex]10^{8}[/tex] C) * (2.4 x [tex]10^{3}[/tex] N/C)

F = 2.4 x [tex]10^{-5}[/tex]N

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Explanation:

a. To calculate the total distance traveled, we need to find the distance traveled during the first 30 minutes and the distance traveled during the next 20 minutes, and then add them up.

During the first 30 minutes:

distance = speed × time

distance = 916.66 m/min × 30 min

distance = 27,499.8 meters

During the next 20 minutes:

distance = speed × time

distance = 900 m/min × 20 min

distance = 18,000 meters

Total distance traveled:

distance = 27,499.8 meters + 18,000 meters

distance = 45,499.8 meters

Therefore, the total distance traveled is 45,499.8 meters.

b. To calculate the average speed, we need to divide the total distance traveled by the total time taken.

Total time taken:

time = 30 min + 20 min

time = 50 min

Average speed:

speed = distance ÷ time

speed = 45,499.8 meters ÷ 50 min

speed = 909.996 m/min

Therefore, the average speed is 909.996 m/min.

The velocity of the truck after the collision, given that a 1450 kg car having a speed of 25.2 m/s collides with the 7.5 kg truck is 1992 m/s

The following data were obtained from the question given above:

The velocity of the truck after the collision can be obtained by using the law of conservation of linear momentum as follow:

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(1450 × 25.2) + (7.5 × 20) = (1450 × 15) + (7.5 × v₂)

36540 + 150 = 21750 + (7.5 × v₂)

36690 = 21750 + 7.5v₂

Collect like terms

7.5v₂ = 36690 - 21750

7.5v₂ = 14940

Divide both sides by 7.5

v₂ = 14940 / 7.5

v₂ = 1992 m/s

Thus, the velocity of the truck after collision is 1992 m/s

Learn more about velocity after collison:

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