In a particular crash test, an automobile of mass 1245 kg collides with a wall and bounces back off the wall. The x components of the initial and final speeds of the automobile are 18 m/s and 2.9 m/s, respectively. If the collision lasts for 0.11 s, find the magnitude of the impulse due to the collision. Answer in units of kg · m/s. Answer in units of kg · m/s.

Answers

Answer 1

Answer:

Δp=-18799.5kg*m/s

Explanation:

Δv=Vf-Vi

Δv=2.9m/s-18m/s

Δv=-15.1m/s

m*Δv=Δp

1245kg*(-15.1m/s)=Δp

Δp=-18799.5kg*m/s

Extra:

Deriving mΔv=Δp

Δp=Pf-Pi

Δp=m*Vf-m*Vi

Δp=m(Vf-Vi)

Vf-Vi=Δv

Δp=m(Δv) or Δp=mΔv


Related Questions

Gravity on earth is 9.8
Jaydens mass is 50 kilograms his weight is

Answers

The weight of an object is a measure of the force of gravity on that object. It is calculated using the formula weight = mass * acceleration due to gravity.

In this case, the mass of the object is 50 kilograms and the acceleration due to gravity on Earth is 9.8 m/s^2. Plugging these values into the formula, we get:

weight = 50 kg * 9.8 m/s^2
= 490 N

Therefore, the weight of Jayden, who has a mass of 50 kilograms, is 490 Newtons.

3. An electron moves along the trajectory from i to f as shown.
a) Does the electric potential energy increase, decrease or stay the same? Explain.
b) Is the electron's speed at f greater than, less than or equal to its speed at i? Explain.

Answers

Answer:

decrease

Explanation:

this is for part a

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