In a quadratic equation a^2+ bx + c = 0, why is it that the value of a cannot be equal to zero?

Answer:

That would be B Collinear

Answer:

B: Collinear

Step-by-step explanation:

Let's look at the answer choices, shall we?

-Coplanar is two lines or points on the same plane.

-Supplementary is where two angles measure to 180 degrees

- Parallel lines are where two lines have the same slope and will never intersect

The only other option is collinear, which happens to have the definition of two points on the same line.

Answer:

−5x+13y=84

Step-by-step explanation:

I hope this is good :)

Answer:

in you question there is the ans hibben

Step-by-step explanation:

x^2+3x+5=0 =a+ bi

Answer:

Step-by-step explanation:

x=6

y=4

5x-y^2 :2

5×6 - 4 ^2 :2

30 - 16 :2

30 - 8

22 (the wright answer)

Circle the mistake :x =6 and y =4 it's not x=4 and y=6

Explain the mistake :when you calculed with x=4 and y=6 the final answer is wrong.

Answer:

133.18522

Step-by-step explanation:

g=55.3188

r=77.86642

77.86642+55.3188

133.18522

Answer:

x = 9

Step-by-step explanation:

6x + 7 = -x + 70

~Subtract 7 to both sides

6x = -x + 63

~Add x to both sides

7x = 63

~Divide 7 to both sides

x = 9

Best of Luck!

Answer:

3x-3(6) = 3x-18

Step-by-step explanation:

Answer:

$15

Step-by-step explanation:

30 - (12+15)

30-27=3

18-3=15

Hope this helps ;)

Answer:

(a) 0.6579

(b) 0.2961

(c) 0.3108

(d) 240

Step-by-step explanation:

The random variable X can be defined as the number of particles in a suspension.

The concentration of particles in a suspension is 50 per ml.

Then in 5 mL volume of the suspension the number of particles will be,

5 × 50 = 250.

The random variable X thus follows a Poisson distribution with parameter, λ = 250.

The Poisson distribution with parameter λ, can be approximated by the Normal distribution, when λ is large say λ > 10.  

The mean of the approximated distribution of X is:

μ = λ  = 250

The standard deviation of the approximated distribution of X is:

σ = √λ  = √250 = 15.8114

Thus, [tex]X\sim N(250, 250)[/tex]

(a)

Compute the probability that the number of particles withdrawn will be between 235 and 265 as follows:

[tex]P(235<X<265)=P(\frac{235-250}{15.8114}<\frac{X-\mu}{\sigma}<\frac{265-250}{15.8114})[/tex]

                             [tex]=P(-0.95<Z<0.95)\\=P(Z<0.95)-P(Z<-0.95)\\=P(Z<0.95)-[1-P(Z<0.95)]\\=2P(Z<0.95)-1\\=(2\times 0.82894)-1\\=0.65788\\\approx 0.6579[/tex]

Thus, the value of P (235 < X < 265) = 0.6579.

(b)

Compute the probability that the average number of particles per mL in the withdrawn sample is between 48 and 52 as follows:

[tex]P(48<\bar X<52)=P(\frac{48-50}{15.8114/\sqrt{5}}<\frac{\bar X-\mu}{\sigma/\sqrt{n}}<\frac{52-50}{15.8114/\sqrt{5}})[/tex]

                             [tex]=P(-0.28<Z<0.28)\\=P(Z<0.28)-P(Z<-0.28)\\=P(Z<0.28)-[1-P(Z<0.28)]\\=2P(Z<0.28)-1\\=(2\times 0.64803)-1\\=0.29606\\\approx 0.2961[/tex]

Thus, the value of [tex]P(48<\bar X<52)=0.2961[/tex].

(c)

A 10 mL sample is withdrawn.

Compute the probability that the average number of particles per mL in the withdrawn sample is between 48 and 52 as follows:

[tex]P(48<\bar X<52)=P(\frac{48-50}{15.8114/\sqrt{10}}<\frac{\bar X-\mu}{\sigma/\sqrt{n}}<\frac{52-50}{15.8114/\sqrt{10}})[/tex]

                             [tex]=P(-0.40<Z<0.40)\\=P(Z<0.40)-P(Z<-0.40)\\=P(Z<0.40)-[1-P(Z<0.40)]\\=2P(Z<0.40)-1\\=(2\times 0.65542)-1\\=0.31084\\\approx 0.3108[/tex]

Thus, the value of [tex]P(48<\bar X<52)=0.3108[/tex].

(d)

Let the sample size be n.

[tex]P(48<\bar X<52)=P(\frac{48-50}{15.8114/\sqrt{n}}<\frac{\bar X-\mu}{\sigma/\sqrt{n}}<\frac{52-50}{15.8114/\sqrt{n}})[/tex]

                             [tex]0.95=P(-z<Z<z)\\0.95=P(Z<z)-P(Z<-z)\\0.95=P(Z<z)-[1-P(Z<z)]\\0.95=2P(Z<z)-1\\P(Z<z)=\frac{1.95}{2}\\\\P(Z<z)=0.975[/tex]

The value of z for this probability is,

z = 1.96

Compute the value of n as follows:

[tex]z=\frac{\bar X-\mu}{\sigma/\sqrt{n}}\\\\1.96=\frac{48-50}{15.8114/\sqrt{n}}\\\\n=[\frac{1.96\times 15.8114}{48-50}]^{2}\\\\n=240.1004\\\\n\approx 241[/tex]

Thus, the sample selected must be of size 240.

You may be asked to "determine algebraically" whether a function is even or odd. To do this, you take the function and plug –x in for x, and then simplify. If you end up with the exact same function that you started with (that is, if f (–x) = f (x), so all of the signs are the same), then the function is even. If you end up with the exact opposite of what you started with (that is, if f (–x) = –f (x), so all of the signs are switched), then the function is odd.

In all other cases, the function is "neither even nor odd".

Let's see what this looks like in action:

Determine algebraically whether f (x) = –3x2 + 4 is even, odd, or neither.

If I graph this, I will see that this is "symmetric about the y-axis"; in other words, whatever the graph is doing on one side of the y-axis is mirrored on the other side:

graph of y = –3x^2 + 4

This mirroring about the y-axis is a hallmark of even functions.

Also, I note that the exponents on all of the terms are even — the exponent on the constant term being zero: 4x0 = 4 × 1 = 4. These are helpful clues that strongly suggest to me that I've got an even function here.

But the question asks me to make the determination algebraically, which means that I need to do the algebra.

So I'll plug –x in for x, and simplify:

f (–x) = –3(–x)2 + 4

= –3(x2) + 4

= –3x2 + 4

I can see, by comparing the original function with my final result above, that I've got a match, which means that:

f (x) is even

Answer:

125+15c=t

Step-by-step explanation:

Every cartridge is worth $15, so that would be 15c aka 15 x however many cartridges you purchase. Then the printer is $125, and its not changing so there will be no variable. Put those two amounts together and you'll get the total cost. (Hopefully I explained this well enough.)

whole numbers, plus their counterparts less than zero, and zero

Negative integers(less than 0) being: –1, –2, –3 exc.

Positive integers(more than 0) being: 1, 2, 3 exc.

Answer:

Integers are whole numbers like -3, -2, -1, 1, 2, 3, 4. They can't be fractions or decimals though

x = 3

y = 1

Hi !

6x - 5y = 13

9y - 15 + 2x = 0

6x - 5y = 13

2x + 9y = 15 | ×(-3)

6x - 5y = 13

- 6x - 27y = - 45

add

6x - 6x - 5y - 27y = 13 - 45

- 32y = - 32 | ×(-)

32y = 32

y = 1

replace y = 1

6x - 5(1) = 13

6x - 5 = 13

6x = 13 + 5

6x = 18

x = 3

Good luck !

The equation that can be used to find the cost of each ticket is 4x = 52.

An equation is a mathematical statement that is made up of two expressions connected by an equal sign.

Example:

2x + 3 = 6 is an equation.

We have,

Number of people who bought the tickets = 4

The total cost of tickets = $52

Now,

The cost of each ticket.

= 52 ÷ 4

= 13

Now,

Cost of one ticket = x

4x = 52

x = 52/4 = 13

Thus.

The cost of each ticket is $13.

Learn more about equations here:

https://brainly.com/question/17194269

#SPJ2

Answer:

Not sure, not good with lines, but I think I did it correctly. EM = Neither TC= Perpendicular.

Answer:

40,000,000 or 40 million

Step-by-step explanation:

Answer:

given

2x-1-x+3=0

x+2=0

x= -2

hope it helps you mate

please mark me as brainliast...

Answer:

2x-1-x+3=5

subtract 3 both sides

add 1 both sides

after that now its

2x-x=3

2x-x= x

x=3 thats the answer

Answer:

8 for $1.00

step by step explanation:

Answer: (8)(-4.5)

Step-by-step explanation:

If you were to multiply-4.5 • -8 that would equal a positive number but if you were to divide (8)(-4.5) it would equal a negative number

Answer:

(8)(-4.5)

Step-by-step explanation:

please mark brainliest

Answer: Kavitha is 18 and Lizzy is 27

Step-by-step explanation: 8 years ago, Kavitha was 10 and Lizzy was 19.

10 × 2 = 20

20 - 1 = 19

Kavitha is 9 years younger than Lizzy because 27 - 9 = 18

9514 1404 393

Answer:

  Kavitha is 19 and Lizzy is 28

Step-by-step explanation:

Let k and l represent the current ages of Kavitha and Lizzy.

  k = l -9 . . . . . Kavitha is 9 years younger

  l -8 = 2(k -8 -1) . . . . 8 years ago, Lizzy was 2 times as old as Kavitha was 9 years ago

  l -8 = 2(l -9 -9) . . . . substitute for k

  l -8 = 2l -36 . . . . . . eliminate parentheses

  28 = l . . . . . . . . . . . add 36 - l

  k = 28 -9 = 19

Kavitha is 19; Lizzy is 28.

Answer:

-5

Step-by-step explanation:

[tex] \frac{3 - 8}{3 - 2} [/tex]

[tex] \frac{ - 5}{1} [/tex]

[tex] - 5[/tex]

Answer:

Explained below.

Step-by-step explanation:

A Binomial experiment has the following properties:

If a random variable X is used in an experiment and the experiment has all the above mentioned properties, then the random variable X is known as a binomial random variable.

The number of employees selected is, n = 20.

Every employees response is independent of the others.

Each employees response is either: Yes or No.

The probability of an employee responding as "yes" is, p = 0.31.

Thus, the experiment being performed is a binomial experiment.

So, the probability distribution for the number of employees believing their company president has low ethical standards can be modelled by a binomial probability distribution.

But the number of years of experience cannot be modelled by a binomial probability distribution. Because every employee will have different answer for this question.

Answer:

U = 5x^3

V = 3

(5x^3 - 3)^2

Step-by-step explanation:

(1) The value of U and V are U = 5x³ and V = 3.

(2) The factored form of 25x⁶ - 30x³ + 9 is (5x³3 - 3)²

A basic quadratic equation, or a second-order polynomial equation with a single variable, is represented by the equation x : ax² + bx + c = 0, where a≠0 for the variable x. As it is a second-order polynomial equation, which is ensured by the algebraic fundamental theorem, it must have at least one solution.

We can factor the expression 25x⁶ - 30x³ + 9 by first noticing that each term is a perfect square:

25x⁶ = (5x³)²

30x³ = 2(15x³)

9 = 3²

Now we can write the expression as the difference of two squares:

25x⁶ - 30x³ + 9 = (5x³)² - 2(5x³)(3) + 3²

Let U = 5x³ and V = 3. Then we have:

(5x³3 - 3)²

Therefore, the factored form of 25x⁶ - 30x³ + 9 is (5x³3 - 3)².

To learn more about the quadratic equation;

https://brainly.com/question/17177510

#SPJ2