In the diagram below, quadrilateral HIJK is inscribed in circle L. Solve for x and y. ​

Answer:

[tex] \: \frac{11}{1620} \: \pi^{2} [/tex]

Step-by-step explanation:

I think this is it. But if you find a mistake somewhere let me know? I'm confused because the answer seems a little weird. Like 11/1620 pi² really?

Also at the bottom I wrote "area of sector =" but the area got cut off

-5 and 7

Step-by-step explanation

lets try putting -5 and 7

-5 +7=2

and the difference is 8

i am not smart sorry

Answer:

x-intercepts (4,0) (2,0)

y-intercepts (0,8)

Step-by-step explanation:

have a good day :)

Unfortunately, I cannot provide an answer to this question as it is incomplete. The given information ∫f(t)dt is not enough to determine the value of f(log e 5). More information about the function f would be needed, such as its explicit form or additional properties. Please provide more context or information to help me answer your question accurately.
Given that f is a function f:R → R that satisfies ∫f(t)dt, we need to find the value of f(log e 5).

By definition, log e 5 is the natural logarithm of 5, which can be written as ln(5). Therefore, we want to find the value of f(ln(5)).

However, without further information on the function f or the integral bounds, it's not possible to determine the exact value of f(ln(5)). Please provide more details about the function or the integral to get a specific answer.

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(34) the sum of the series is 170. (33) The sum of the series is 341. (35) the sum of the series is 21844

To evaluate a geometric series, we use the formula:

Sn = a(1 - r^n) / (1 - r)

where:

Sn = the sum of the first n terms of the series
a = the first term of the series
r = the common ratio between consecutive terms
n = the number of terms we want to sum

Let's use this formula to evaluate the given geometric series:

34) a1 = -2, a8 = 256, r = -2

To find the sum of this series, we need to know the value of n. We can find it using the formula:

an = a1 * r^(n-1)

a8 = -2 * (-2)^(8-1) = -2 * (-2)^7 = -2 * (-128) = 256

Now we can solve for n:

an = a1 * r^(n-1)
256 = -2 * (-2)^(n-1)
-128 = (-2)^(n-1)
2^7 = 2^(1-n+1)
7 = n-1
n = 8

So this series has 8 terms. Now we can use the formula to find the sum:

Sn = a(1 - r^n) / (1 - r)
S8 = (-2)(1 - (-2)^8) / (1 - (-2))
S8 = (-2)(1 - 256) / 3
S8 = 510 / 3
S8 = 170

Therefore, the sum of the series is 170.

33) a1 = -1, a9 = 512, r = -2

We can use the same method as before to find n:

an = a1 * r^(n-1)
512 = -1 * (-2)^(9-1) = -1 * (-2)^8
512 = 256
This is a contradiction, so there must be an error in the problem statement. Perhaps a9 is meant to be a5, in which case we can find n as:

an = a1 * r^(n-1)
a5 = -1 * (-2)^(5-1) = -1 * (-2)^4
a5 = 16
512 = -1 * (-2)^(n-1)
-512 = (-2)^(n-1)
2^9 = 2^(1-n+1)
9 = n-1
n = 10

So this series has 10 terms. Now we can use the formula to find the sum:

Sn = a(1 - r^n) / (1 - r)
S10 = (-1)(1 - (-2)^10) / (1 - (-2))
S10 = (-1)(1 - 1024) / 3
S10 = 1023 / 3
S10 = 341

Therefore, the sum of the series is 341.

35) a1 = 4, a14 = 16384, r = 4

Again, we can find n using the formula:

an = a1 * r^(n-1)
16384 = 4 * 4^(14-1) = 4 * 4^13 = 4 * 8192 = 32768
This is a contradiction, so there must be an error in the problem statement. Perhaps a14 is meant to be a7, in which case we can find n as:

an = a1 * r^(n-1)
a7 = 4 * 4^(7-1) = 4 * 4^6 = 4 * 4096 = 16384
16384 = 4 * 4^(n-1)
4096 = 4^(n-1)
2^12 = 2^(2n-2)
12 = 2n-2
n = 7

So this series has 7 terms. Now we can use the formula to find the sum:

Sn = a(1 - r^n) / (1 - r)
S7 = (4)(1 - 4^7) / (1 - 4)
S7 = (4)(1 - 16384) / (-3)
S7 = 65532 / 3
S7 = 21844

Therefore, the sum of the series is 21844.

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Answer:

Step-by-step explanation:

60 x 3 = 180

180 miles

If Clare's average number of strokes per hole is 3, it means that the total number of strokes she took in the round divided by the number of holes she played is equal to 3.

Let's say Clare played n holes in total and took a total of s strokes in the round. Then we can write:

s/n = 3

Multiplying both sides by n, we get:

s = 3n

This means that Clare took 3 strokes per hole on average, and a total of 3n strokes in the round. If she were to redistribute the strokes on different greens, the total number of strokes would still be 3n, and her average number of strokes per hole would remain 3.

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Answer:

Step-by-step explanation:

An obtuse angle has a measure between 90 and 180 degrees. Looks like S and Q have obtuse angles, Its impossible to be sure unless you measure them with a protractor.

the sum of the convergent series is 8.

To find the sum of the convergent series ∑(24/n(n+2)) where n starts at 1, we can re-write the given expression as a partial fraction decomposition:

24/n(n+2) = A/n + B/(n+2)

Solving for A and B, we find that A = 12 and B = -12. So the expression becomes:

12/n - 12/(n+2)

Now, we can compute the sum for the given series:

∑[12/n - 12/(n+2)] from n = 1 to infinity

As this is a telescoping series, most of the terms will cancel out. We are left with:

12/1 - 12/3 + 12/2 - 12/4 + ... + 12/∞ - 12/(∞+2)

The sum converges to:

12 - 12/3 = 12 * (1 - 1/3) = 12 * 2/3 = 8

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The pole is approximately 3.86 feet tall.

Let's denote the height of the pole as "x" (in feet). From the problem, we know that the pole makes a 75° angle with the road surface, which means that the angle between the pole and the vertical is 90° - 75° = 15°.

Now, we can use the tangent function to find the height of the pole:

tan(15°) = x/15

Multiplying both sides by 15, we get:

x = 15 tan(15°) ≈ 3.86 feet

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The area of triangle ABC is 13.95 square inches.

We can start by finding the length of AB, which is equal to the diameter of the circle. Since the radius is 3 inches, the diameter is 2 times the radius, or 6 inches.

Next, we can use the fact that AC is tangent to the circle to conclude that angle CAB is a right angle. Therefore, triangle ABC is a right triangle.

Let's use the information about the arcs CD and CE to find the measure of angle BAC. The measure of an inscribed angle is half the measure of the arc that it intercepts, so angle CAD is 80 degrees and angle CAE is 50 degrees. Since angles CAD and CAE are opposite each other and AC is a tangent, we have angle BAC is 180 - 80 - 50 = 50 degrees.

Now we know that triangle ABC is a right triangle with a 90-degree angle at B and a 50-degree angle at A. To find the area of the triangle, we need to know the length of BC.

Using trigonometry, we can find that BC = AB * sin(50) ≈ 4.65 inches.

Therefore, the area of triangle ABC is (1/2) * AB * BC = (1/2) * 6 * 4.65 = 13.95 square inches. Rounded to the nearest hundredth, the area of triangle ABC is 13.95 square inches.

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The probability of choosing a king or queen from a standard 52-card deck is 2/13 or approximately 15.4%.

The probability of choosing a king or a queen from a standard 52-card deck can be calculated by first determining the number of kings and queens in the deck. There are four kings (hearts, diamonds, clubs, and spades) and four queens (hearts, diamonds, clubs, and spades) in the deck, for a total of eight cards.

To find the probability of choosing a king or a queen, you need to divide the number of desired outcomes (eight) by the total number of possible outcomes (52).

Probability = Number of desired outcomes / Total number of possible outcomes

Probability = 8 / 52

This simplifies to:

Probability = 2 / 13

Therefore, the probability of choosing a king or a queen from a standard 52-card deck is approximately 0.154 or 15.4%.

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Mary's average monthly expense for housing is $2,129.93.

We need to add up all her annual housing expenses and divide the total by 12 (the number of months in a year):

Total annual housing expenses = mortgage payments + real estate taxes + annual insurance premium + maintenance + utilities

Total annual housing expenses = $14,169.20 + $3,960.00 + $840.00 + $1,410.00 + $5,180.00

Total annual housing expenses = $25,559.20

Average monthly expense = Total annual housing expenses ÷ 12

Average monthly expense = $25,559.20 ÷ 12

Average monthly expense = $2,129.93

Therefore, Mary's average monthly expense for housing is $2,129.93.

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Answer:

16 peaches

Step-by-step explanation:

Let's break this down:

Total: 144 peaches

Number of boxes she has to fill evenly: 9

Question: How many peaches are able to fit into each box evenly?

144 peaches/9 boxes = 16 peaches

So, Ariana should pack 16 peaches into each box

Hope this helps :)

The first order partial derivatives of f(x, y) =  ex cos y and the second order partial derivatives are ex sin y = ex cos y.

The given function is f(x, y) = ex sin y. We need to find the first and second order partial derivatives of this function with respect to x and y.
First order partial derivatives:
To find the partial derivative of f(x, y) with respect to x, we treat y as a constant and differentiate ex with respect to x. This gives:
∂f/∂x = ex sin y
To find the partial derivative of f(x, y) with respect to y, we treat x as a constant and differentiate sin y with respect to y. This gives:
∂f/∂y = ex cos y
Second order partial derivatives:
To find the second order partial derivatives, we differentiate the first order partial derivatives we found above. That is, we differentiate ∂f/∂x and ∂f/∂y with respect to x and y, respectively.
∂/∂x (ex sin y) = ex sin y
∂/∂y (ex cos y) = -ex sin y
To find the mixed partial derivatives, we differentiate one of the first order partial derivatives with respect to the other variable. That is,
∂/∂y (ex sin y) = ex cos y
We can also find the mixed partial derivative  by differentiating ∂f/∂y with respect to x, which gives the same result:
∂/∂x (ex cos y) = ex cos y
The first order partial derivatives of f(x, y) = ex sin y are ∂f/∂x = ex sin y and ∂f/∂y = ex cos y and the second order partial derivatives are ex sin y, ∂f/∂[tex]y^2[/tex] = -ex sin y, and ∂f/∂x∂y = ∂f/∂y∂x = ex cos y.

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The values of a and b that satisfy the equation of the line and pass through points A(2,5) and B(3,7) are a = 3 and b = 2.

To find the values of a and b, we need to use the coordinates of points A and B and the equation of the line ax+by=16.

First, we substitute point A(2,5) into the equation to get:

a(2) + b(5) = 16

Next, we substitute point B(3,7) into the equation to get:

a(3) + b(7) = 16

We now have two equations with two unknowns, which we can solve simultaneously.

Multiplying the first equation by 3 and the second equation by -2, we get:

6a + 15b = 48

-6a - 14b = -32

Adding the two equations, we eliminate the a variable and get:

b = 2

Substituting b = 2 into one of the original equations, we get:

2a + 10 = 16

Solving for a, we get:

a = 3

Therefore, the values of a and b that satisfy the equation of the line and pass through points A(2,5) and B(3,7) are a = 3 and b = 2.

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f(0.5) represents the volume of the smaller box when its' side length is 0.5 cm less than the larger cube

The formula to find the Volume of a cube is:

V = x³

where:

x is the side length of the cube

The cube has a volume of 27 cm³. Thus:

Side length of cube = ∛27 = 3 cm

Since the side length of the smaller cube is x cm less than side length of the larger cube, then we can say that the function to find the volume of the smaller cube is:

V_small: f(x) = (3 - x)³

Thus, f(0.5) is the volume of the smaller box when its' side length is 0.5 cm less than the larger cube

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To solve the triangle, we have;

Angle Q = [tex]112^{o}[/tex]

QR = 30.0

PR = 40.2

A sine rule is a trigonometric function that can be applied to determined the unknown side, or angle of a none right triangle.

From the information given in the question, to solve the triangle;

P + R + Q = 180

42 + 26 + Q = 180

Q = 180 - 68

   = 112

Q = [tex]112^{o}[/tex]

Applying the sine rule,

QR/Sin P = PR/Sin Q = PQ/Sin R

PR/Sin Q = PQ/Sin R

PR/Sin 112 = 19/ Sin 26

PRSin 26 = 19*Sin 112

             = 17.6165

PR = 17.6165/ 0.4384

  = 40.1836

PR = 40.2

Also,

QR/Sin P = PQ/Sin R

QR/Sin 42 = 19/ Sin 26

QRSin 26 = 19*Sin 42

                = 12.7135

QR = 12.7135/ 0.4384

     = 28.9998

QR = 30

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For the sample size of 200 and sample data 96 there is no sufficient evidence to conclude that proportion of palay harvested is different from 0.50.

Sample size 'n' = 200

The proportion of palay harvested is different from 0.50

Use a hypothesis test.

Let us assume the null hypothesis H₀ is that the proportion of palay harvested is equal to 0.50,

and the alternative hypothesis Hₐ is that the proportion of palay harvested is different from 0.50.

H₀: p = 0.50 proportion of palay harvested is equal to 50%

Hₐ: p ≠ 0.50 proportion of palay harvested is not equal to 50%

where p is the population proportion of palay harvested.

To test this hypothesis, use the sample data of 96 out of 200 one-hectare farm lands that harvested palay.

The sample proportion of palay harvested is,

p₁= 96/200

  = 0.48

To determine if this sample proportion is significantly different from the hypothesized proportion of 0.50,

Use a two-tailed z-test with a significance level of α = 0.05.

The test statistic is calculated as,

z = (p₁ - p) / √(p(1-p)/n)

where n is the sample size.

Substituting the values, we get,

z = (0.48 - 0.50) / √(0.50(1-0.50)/200)

⇒ z = -0.5658

Using a z-table,

The probability of getting a z-value of -0.5658 or lower in the left tail of the distribution is approximately 0.7123.

Since this is a two-tailed test,

Probability of getting a z-value of 0.5658 or higher in the right tail of the distribution is also approximately 0.7123

p-value for this test is 0.7123+ 0.7123 = 1.4246

Since the p-value is greater than the significance level of α = 0.05,

Fail to reject the null hypothesis.

Therefore,  do not have sufficient evidence to conclude that the proportion of palay harvested is different from 0.50.

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For the expression (3m⁴n)³(2m²n⁵p)/6m⁴n⁹p⁸, the simplified-value is 9m¹⁰n⁻¹p⁻⁷.

To simplify the expression (3m⁴n)³(2m²n⁵p)/6m⁴n⁹p⁸, we first use the exponent-rule that states (qᵃ)ᵇ = qᵃᵇ to simplify the first part of the expression:

⇒ (3m⁴n)³ = 3³(m⁴)³n³ = 27m¹²n³;

Next, we can simplify the denominator by using the rules of exponents to combine the like terms:

⇒ 6m⁴n⁹p⁸ = 2×3m⁴n⁹p⁸;

Substituting the values,

We get;

⇒ (27m¹²n³)×(2m²n⁵p)/(2*3m⁴n⁹p⁸);

Simplifying the expression by cancelling out the common factors, we get:

⇒ 9m¹⁰n⁻¹p⁻⁷;

Therefore, the simplified-value is : 9m¹⁰n⁻¹p⁻⁷.

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The given question is incomplete, the complete question is

What is the simplified form of the expression below (3m⁴n)³(2m²n⁵p)/6m⁴n⁹p⁸;

1. The probability that the point chosen is in the triangle is 0.1 (nearest tenth)

2. The probability that the point is in the square is 0.2( nearest tenth)

A probability is a number that reflects the chance or likelihood that a particular event will occur. The certainty for an event is 1 which is equivalent to 100%.

Probability = sample space / total outcome

total outcome is the area of rectangle , which is

A = l× w

= 12 × 8

= 96

area of the rectangle = 1/2 bh

= 1/2 × 4 × 5

= 2 × 5

= 10

Area of the square = 4×4

= 16

1. Probability the the point will be in the triangle= 10/96 = 5/48

= 0.1( nearest tenth)

2. probability the the point will be in the square =

16/96 = 1/6

= 0.2 ( nearest tenth)

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The likelihood of at least 12% of the sample being left-handed is approximately 0.007 or 0.7%.

Let X be the number of left-handed people in a sample of 800 individuals. Since the probability of a person being left-handed is 0.1, the probability of a person being right-handed is 0.9. Then, X follows a binomial distribution with n = 800 and p = 0.1.

P(X ≥ 0.12*800) = P(X ≥ 96)

where 96 is the smallest integer greater than or equal to 0.12*800.

[tex]P(X > =96)-P(X < 96)=1-[K=0 to 95](800 CHOOSE )(0.1^{k} (0.9)^{2} (800-k)[/tex]

This is the complement of the probability of getting less than 96 left-handed people in the sample. Using a calculator or statistical software, we can find that:

P(X ≥ 96) ≈ 0.007

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we see that the greatest rate of participation was in Grade 8, and the least rate of participation was in Grade 6.

To compare the rates of participation in sports among the three grades, we can convert each percentage or fraction to a decimal and then compare the values.

Grade 6: 0.872

Grade 7: 0.87 (87% converted to decimal)

Grade 8: 0.875 (7/8 converted to decimal)

Therefore, we see that the greatest rate of participation was in Grade 8, and the least rate of participation was in Grade 6.

Answer:

Grade 8 had the greatest rate of participation.

Grade 6 had the least rate of participation.

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the equivalent integral with the order of integration reversed is: ∫0^1 ∫1^2 log(x) 9(y) dydx = (9/2) (2log(2) - 1)

To write an equivalent integral with the order of integration reversed, we need to integrate first with respect to y and then with respect to x. So, we have:

∫a^b ∫f(y)g(x) F(x,y) dxdy

Reversing the order of integration, we get:

∫f(y)g(x) ∫a^b F(x,y) dydx

Now, substituting the given values for f(y), g(x), and F(x,y), we get:

∫0^1 ∫1^2 log(x) 9(y) dydx

= ∫0^1 [9(y)∫1^2 log(x) dx] dy

= ∫0^1 [9(y) (xlog(x) - x) from x=1 to x=2] dy

= ∫0^1 [9(y) (2log(2) - 2 - log(1) + 1)] dy

= ∫0^1 [9(y) (2log(2) - 1)] dy

= (9/2) [(2log(2) - 1) y] from y=0 to y=1

= (9/2) (2log(2) - 1)

Therefore, the equivalent integral with the order of integration reversed is:

∫0^1 ∫1^2 log(x) 9(y) dydx = (9/2) (2log(2) - 1)

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The probability of a randomly selected family from the United States having at least 2 children is 0.2734. The probability that if 40 families from the United States are randomly selected, the mean number of children per family is at least 2 children is 0.1884. Analyst 1 plans to use a sample size of 1 and analyst 2 plans to use a sample size of 40.

Analyst 1 wants to calculate the probability that a randomly selected family from the United States has at least 2 children. Since the number of children under age 18 per family is skewed right with a mean of 1.9 children and a standard deviation of 1.1 children, we can use the normal distribution to solve this problem.

To calculate the probability of a randomly selected family having at least 2 children, we need to find the area under the normal curve to the right of 2.

Using a standard normal distribution table or calculator, we can find that the area to the right of 2 is approximately 0.2734. Therefore, the probability of a randomly selected family from the United States having at least 2 children is 0.2734.

Analyst 2 wants to calculate the probability that if 40 families from the United States are randomly selected, the mean number of children per family is at least 2 children. Since we know that the mean number of children per family in the population is 1.9 children and the standard deviation is 1.1 children, we can use the central limit theorem to approximate the sampling distribution of the sample means.

The central limit theorem tells us that the sampling distribution of the sample means will be approximately normal with a mean of 1.9 children and a standard error of the mean equal to the population standard deviation divided by the square root of the sample size.

We want to find the probability that the mean number of children per family is at least 2, so we need to standardize the sample mean using the formula:

z = (sample mean - population mean) / (standard error of the mean)

Plugging in the values, we get:

z = (2 - 1.9) / (1.1 / sqrt(40)) = 0.889

Using a standard normal distribution table or calculator, we can find that the area to the right of 0.889 is approximately 0.1884. Therefore, the probability that if 40 families from the United States are randomly selected, the mean number of children per family is at least 2 children is 0.1884.

So, analyst 1 plans to use a sample size of 1 and analyst 2 plans to use a sample size of 40.

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The mean is 48.47 kg, median is 49.55 kg, mode is not available, variance is 34.1 kg², standard deviation is 5.84 kg, coefficient of variation is 12.03% and IQR is 8.35 kg.

The given data shows the weight (in kg) of 24 women in a study. To analyze the data, we need to calculate various statistical measures:

I. Statistical Measures:
a) Mean = (Sum of all weights) / (Number of observations) = (1163.4) / (24) = 48.47 kg
b) Median = Middle value of the sorted data set = 49.55 kg
c) Mode = The most frequent value in the data set = No mode as there are no repeating values.
d) Variance = (Sum of squares of deviations of each value from mean) / (Number of observations) = 34.1 kg²
e) Standard deviation = Square root of variance = 5.84 kg
f) Coefficient of variation = (Standard deviation / Mean) x 100 = 12.03%
g) IQR (Interquartile range) = Q3 - Q1 = 53.025 - 44.675 = 8.35 kg

II. Box and Whisker Plot:
The box and whisker plot displays the distribution of the data. The lower and upper quartiles are represented by the bottom and top of the box respectively, and the median is represented by the line in the middle. The whiskers represent the minimum and maximum values.

III. Distribution:
The data set appears to be skewed to the right as the median is less than the mean. There are no outliers in the data, and the IQR is relatively small, indicating that the data is not too spread out. The coefficient of variation is moderate, indicating that the data has a moderate degree of variation. Overall, the data set seems to be fairly normal, with a few outliers on the right side.

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The margin of error at the 99% confidence interval is 0.018 or 1.8%.

Interpretation: This means that if we were to repeat the survey many times, about 99% of the intervals calculated from the samples would contain the true proportion of viewers under 30 in the population, and the margin of error for each interval would be no more than 1.8%.

The margin of error is the amount by which the sample statistic (in this case, the proportion of viewers under 30) may differ from the true population parameter.

Using the given formula for margin of error:

Margin of error = z* * sqrt(p*(1-p)/n)

Where:

- z* is the z-score corresponding to the confidence level (99% in this case), which is 2.576

- p is the proportion of viewers under 30, which is 0.3

- n is the sample size, which is 5000

Substituting these values, we get:

Margin of error = 2.576 * sqrt(0.3*(1-0.3)/5000) = 0.018

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(i) A Venn-diagram of this information is shown below.

(ii) The number of students who like picnic = 34

(iii) The number of students who like hiking only = 51

(iv) The percentage of students who like picnic only. = 45.33%

Let us assume that A represents the set of students who like picnic.

B represents the set of students who like the hiking.

The total number of students in a  class are: n(A U B) = 75

Out of 75 students, 10 like both the activities.

n(A ∩ B) = 10

The ratio of the number of students who like picnic to those who like hiking is 2 : 3

Let number of students like tea n(A) = 2x

and the number of students like coffee n(B) = 3x

n(A U B) = n(A) + n(B) - n(A ∩ B)

75 = 2x + 3x - 10

75 + 10 = 5x

85/5= x

x = 17

The number of students like picnic = 2x

                                                          = 2 × 17

                                                          = 34

The number of students like hiking = 3x

                                                           = 3 × 17

                                                           = 51

This informtaion in Venn diagram is shown below.

The percentage of students who like picnic only would be,

(34/75) × 100 = 45.33%

Learn more about the Venn diagram here:

https://brainly.com/question/30248978

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