Insert a monomial so that the trinomial may be represented by the square of a
binomial.
0.0152 +.... +100c2

Jhon bought a rectangular door mat that was 1/2 meter long and 3/10 meter wide. The area of the rectangular door mat is 3/20 square meters.

Find the area of John's rectangular door mat that is 1/2 meter long and 3/10 meter wide, you'll need to multiply the length by the width.
Identify the length and width.
Length = 1/2 meter
Width = 3/10 meter
Multiply the length and width to find the area.
Area = Length × Width
Area = (1/2) × (3/10)
Calculate the multiplication.
Area = 3/20 square meters
The area of the rectangular door mat is 3/20 square meters.

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The distance between the airplane and the tower is approximately 1864.5 meters.

To solve this problem, we can use trigonometry. Let's draw a diagram to help us visualize the situation:

```
   T
  /|
 / |
/  | 500m
/a  |
--------
  x
```

In this diagram, "T" represents the control tower, "a" represents the airplane, and "x" represents the distance between them. We know that the height of the airplane is 500m, and the angle of depression from the tower to the airplane is 15 degrees. This means that the angle between the horizontal ground and the line from the tower to the airplane is also 15 degrees.

Using trigonometry, we can set up the following equation:

```
tan 15 = 500 / x
```

We can solve for "x" by multiplying both sides by "x" and then dividing by tan 15:

```
x = 500 / tan 15
```

Using a calculator, we can find that tan 15 is approximately 0.2679. Therefore:

```
x = 500 / 0.2679
x ≈ 1864.5m
```

So the distance between the airplane and the tower is approximately 1864.5 meters.

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The length of segment SR is 90x - 4s, which can be determined by analyzing the given expression for units RT and QT: 2x + 88x - 4s.

Step 1: Identify the segment
In this problem, we need to find the length of segment SR.

Step 2: Understand the given information
We are given the lengths of two segments, RT and QT, as follows:
- RT = 2x
- QT = 88x - 4s

Step 3: Analyze the relationship between segments
Since SR is the segment that includes both RT and QT, we can express the length of segment SR as the sum of the lengths of RT and QT.

Step 4: Add the lengths of RT and QT
To find the length of segment SR, add the lengths of RT and QT:
SR = RT + QT
SR = (2x) + (88x - 4s)

Step 5: Simplify the expression
Combine like terms in the expression:
SR = 90x - 4s

The length of segment SR is 90x - 4s.

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The detail that adds tension to the rising action of the story is when Mother Wolf tells Mowgli that some day he will have to kill Shere Khan.

This statement introduces a sense of conflict and foreshadows a significant challenge that Mowgli must face in the future. The idea of Mowgli, a young boy raised by wolves, confronting and defeating the powerful and dangerous Shere Khan adds suspense to the story, as readers anticipate the eventual showdown between these two characters.

Other details, such as Mowgli growing stronger and learning life lessons, or Mowgli forgetting his mother's advice, are relevant to his character development, but do not contribute as directly to the story's tension. Similarly, Mowgli considering himself a wolf and lacking the ability to speak like a human reflects his unique upbringing, but does not add tension in the same way as the impending confrontation with Shere Khan.

In conclusion, Mother Wolf's warning about Mowgli's future encounter with Shere Khan adds tension to the rising action of the story, as it sets up an exciting and challenging conflict for the protagonist to face, capturing the reader's interest and anticipation.

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The probability that a student chosen randomly from the class passed the test or completed the homework is 20/27.

The probability that a student chosen randomly from the class passed the test or completed the homework is calculated as follows:

Let the probability that a student completed the homework be P(B).

Also, let the probability that a student passed the test be P(A)

P(A or B) = P(A) + P(B) - P(A * B)

From the data table:

The number of students who passed the test = 18

The number of students who completed the homework = 17

The number of students who both passed the test and completed the homework = 15.

Total number of students = 27

P(A) = 18/27

P(B) = 17/27

P(A*B) = 15/27

Therefore,

P(A or B) = 18/27 + 17/27 - 15/27

P(A or B) = 20/27

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The solution to the system is x = 94/9 and y = 22/9.

There is a unique solution, we classify the system as consistent and independent.

Part 1: Solve the system using linear combination or substitution. Show all work. (4 points)
System: 3x - 12y = 2, y = x - 8
Part 2: Classify the system as consistent independent, inconsistent, or coincident. (2 points)

Part 1: Let's solve the system using substitution:
Since y = x - 8, we can substitute this expression for y in the first equation:
3x - 12(x - 8) = 2

Now, we'll solve for x:
3x - 12x + 96 = 2
-9x + 96 = 2
-9x = -94
x = 94/9

Now that we have the value of x, we can substitute it back into y = x - 8 to find the value of y:
y = (94/9) - 8
y = (94 - 72)/9
y = 22/9

So, the solution to the system is x = 94/9 and y = 22/9.

Part 2: Since there is a unique solution, we classify the system as consistent and independent.

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The expression 6\cdot6\cdot6\cdot6\cdot66\cdot6\cdot6\cdot6\cdot66 is equivalent to 60534416.

The given expression is:

6\cdot6\cdot6\cdot6\cdot66\cdot6\cdot6\cdot6\cdot66

To simplify this expression we can first simplify the factors that are multiples of 6:

6\cdot6\cdot6\cdot6\cdot6\cdot6\cdot6\cdot6\cdot11\cdot11

Next, we can use the commutative property of multiplication to group the factors of 6 together:

(6\cdot6\cdot6\cdot6\cdot6\cdot6)\cdot(6\cdot6\cdot6\cdot6)

Simplifying each of these groups of factors separately, we get:

46656\cdot1296

Multiplying these two numbers together, we get the final result:

60534416

Let's break down the given expression and simplify it step by step.

The expression is:

6\cdot6\cdot6\cdot6\cdot66\cdot6\cdot6\cdot6\cdot66

We can start by simplifying the factors that are multiples of 6:

6\cdot6\cdot6\cdot6\cdot6\cdot6\cdot6\cdot6\cdot11\cdot11

Next, we can use the commutative property of multiplication to group the factors of 6 together:

(6\cdot6\cdot6\cdot6\cdot6\cdot6)\cdot(6\cdot6\cdot6\cdot6)

Simplifying each of these groups of factors separately, we get:

6\cdot6\cdot6\cdot6\cdot6\cdot6 = 46656

6\cdot6\cdot6\cdot6 = 1296

Now we can substitute these values back into the expression:

46656\cdot1296

We can multiply these two numbers together to get the final result:

60534416

The given expression is:

6\cdot6\cdot6\cdot6\cdot66\cdot6\cdot6\cdot6\cdot66

To simplify this expression, we can first simplify the factors that are multiples of 6:

6\cdot6\cdot6\cdot6\cdot6\cdot6\cdot6\cdot6\cdot11\cdot11

Next, we can use the commutative property of multiplication to group the factors of 6 together:

(6\cdot6\cdot6\cdot6\cdot6\cdot6)\cdot(6\cdot6\cdot6\cdot6)

Simplifying each of these groups of factors separately, we get:

46656\cdot1296

Multiplying these two numbers together, we get the final result:

60534416

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let's recall that two tangent lines to the same circle meeting outside it, will have the same length, so all those pair of tangent lines are equal in length.

Check the picture below.

The marked point under (x, y) are (-4,-6), (-3,-5), (-2,-4), (-1,-3), (0,-2), (1,-3), (2,-4), (3,-5) and (4,-6), under the condition that (A) y=x-2, (B) y=-x-2, (C) y=|x|-2.
Point A
where y=x-2.
This projects that for every x value, y will be 2 less than that x value. So if we place in x=0, we get y=-2. If we plug in x=1, we get y=-1 and so on. So we could plot these points on the coordinate plane as (0,-2), (1,-1), (2,0), (3,1) .

Then, similarly point B
where y=-x-2.
This projects that for every x value, y should be 2 less than the negative of that x value. So if we place in x=0, we get y=-2. If we place in x=1, we get y=-3 and .
Then, we can place these points on the coordinate plane as (0,-2), (1,-3), (-1,-1), (2,-4) .

Finally let's proceed on to point C where y=|x|-2. This projects that for every positive x value, y will be 2 less than that x value and for every negative x value, y will be 2 less than the negative of that x value. So if we plug in x=0, we get y=-2. If we plug in x=1, we get y=-1 and so on.
So we can place these points on the coordinate plane as (0,-2), (1,-1), (-1,-1), (2,0), (-2,0) and so on.

So all the evaluated points are (-4,-6), (-3,-5), (-2,-4), (-1,-3), (0,-2), (1,-3), (2,-4), (3,-5) and (4,-6).

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Check the picture below.

The radius of ⊙P is also 12, so ⊙Q and ⊙P have the same size. Therefore, they are similar circles.

1. To construct a circle circumscribed about triangle △DEF, we need to find its circumcenter, which is the point where the perpendicular bisectors of the sides of the triangle intersect.

To do this, we first draw the three perpendicular bisectors of the sides of the triangle. The point where these three bisectors intersect is the circumcenter, which we label as C. We then draw a circle with center C and radius equal to the distance between C and any of the vertices of the triangle, such as D.

2. To show that ⊙O and ⊙P are similar, we can use a similarity transformation such as a dilation. We can start by translating ⊙O and ⊙P so that their centers are both at the origin. We can then scale ⊙O by a factor of 12/5 to get a new circle ⊙Q with the same center as ⊙O and a radius of 12.

The radius of ⊙P is also 12, so ⊙Q and ⊙P have the same size. Therefore, they are similar circles. We can then translate ⊙Q back to its original position centered at (−2, 7) to show that ⊙O and ⊙P are similar circles with similarity center at (−2, 7).

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An equivalent function of the form G'(t) = abt for the given function G(t) = 15(4)+3 is: G'(t) = 63 * 1.

An equivalent function refers to a mathematical function that has the same output values or behavior as another function but may have a different mathematical expression or representation. In other words, two functions are considered equivalent if they produce the same results for the same inputs, even though they may be expressed differently in terms of mathematical notation, variables, or parameters.

According to the given information:

To write an equivalent function of the form G'(t) = abt, we need to rearrange the given function G(t) = 15(4)+3 into a format that matches the form G'(t) = abt.

The given function G(t) = 15(4)+3 can be simplified as follows:

G(t) = 60 + 3

G(t) = 63

Now, we can see that G(t) is a constant function with a constant value of 63. To express it in the form G'(t) = abt, we can rewrite it as:

G'(t) = 63 * 1

So, an equivalent function of the form G'(t) = abt for the given function G(t) = 15(4)+3 is:

G'(t) = 63 * 1

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The function 1/[tex]r^2[/tex] can be expressed in terms of the spherical Bessel functions of the first kind, which are a family of solutions to the spherical Bessel differential equation.

The expansion involves a combination of the delta function and the first two spherical Bessel functions, j_0(r) and j_1(r). Specifically, the expansion can be written as (1/2)*[pi * delta(r) + (1/r)*d/d(r)(r * j_0(r)) + (1/[tex]r^2[/tex])*d/d(r)[[tex]r^2[/tex] * j_1(r)]]. This expansion is valid for all values of r except for r=0, where the first term dominates. The spherical Bessel functions are commonly used in physics, particularly in the context of scattering problems and wave propagation.

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The function is increasing for all real values of x where x < –4.

The statement that is true about the function is: "The function is decreasing for all real values of x where x < -4."

In order to determine the behavior of the function, we look at the given options. Among the options, the only statement that aligns with the function being decreasing is the one that states the function is decreasing for all real values of x where x < -4.

If a function is decreasing, it means that as the value of x decreases, the value of the function also decreases. In this case, it indicates that as x becomes more negative, the function's values decrease.

Therefore, the statement that correctly describes the behavior of the function is that it is decreasing for all real values of x where x < -4.

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Answer: a) To find the speed of Train A, we need to divide the distance traveled by the time taken:

Speed = Distance / Time

Speed = 520.4 km / 4.8 h

Speed ≈ 108.42 km/h

Rounding to the nearest whole number, we get:

Train A is traveling at 108 km/h (approximately).

b) To find the speed of Train B, we need to divide the distance traveled by the time taken:

Speed = Distance / Time

Speed = 72.1 km / 0.8 h

Speed ≈ 90.13 km/h

Rounding to the nearest whole number, we get:

Train B is traveling at 90 km/h (approximately).

Step-by-step explanation:

The workers would have traveled a total of 32 km while erecting the fence over 40 days.

To determine the total distance the workers traveled while erecting the fence, we can use the following terms: daily distance, number of days, and total distance.

Step 1: Determine the daily distance traveled.
The workers erect 0.8 km of new fence each day.

Step 2: Determine the number of days it takes to erect the fence.
It takes 40 days to erect the fence.

Step 3: Calculate the total distance traveled.
To find the total distance, multiply the daily distance (0.8 km) by the number of days (40).

Total distance = Daily distance × Number of days
Total distance = 0.8 km × 40

Total distance = 32 km

So, the workers would have traveled a total of 32 km while erecting the fence over 40 days.

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The area of the surface generated by revolving the curve y=4x+2 on [0,4] about the x-axis is S =4π/3 (3√17 + 2) .

To find the surface area generated by revolving the curve y=4x+2 about the x-axis on [0,4], we need to use the formula:

S = 2π∫[a,b] y ds

where ds = \sqrt(1 + (dy/dx)²) dx is the arc length element.

First, we find dy/dx: dy/dx = 4

Then, we can find the arc length element: ds = \sqrt(1 + (dy/dx)²) dx = \sqrt(1 + 16) dx = \sqrt(17) dx

The integral for surface area becomes: S = 2π∫[0,4] y ds = 2π∫[0,4] (4x+2)√17 dx

Evaluating this integral, we get:

S = 2π(2/3)√17 [ (4x+2)^(3/2) ]_0^4

S = 4π/3 (3√17 + 2)

Therefore, the area of the surface generated is 4π/3 (3√17 + 2) square units.

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The absolute maximum value of the function f(x) is 222.

To find the absolute minimum value of the function f(x), we need to first find the critical points within the given interval -6 ≤ x ≤ 5. To do this, we take the derivative of f(x) and set it equal to zero:

f'(x) = 6x² + 12x - 144
0 = 6(x² + 2x - 24)
0 = 6(x+6)(x-4)

The critical points are x=-6, x=-4, and x=4. To determine which of these points correspond to a minimum value, we evaluate f(x) at each of these points and at the endpoints of the interval:

f(-6) = -880, f(-4) = -184, f(4) = -136, f(-6) = -880, f(5) = 222

Therefore, the absolute minimum value of the function f(x) is -880.

To find the absolute maximum value of the function f(x), we follow the same process. The critical points are still x=-6, x=-4, and x=4, but now we need to evaluate f(x) at each of these points and at the endpoints of the interval to determine which corresponds to a maximum value:

f(-6) = -880, f(-4) = -184, f(4) = -136, f(-6) = -880, f(5) = 222

Therefore, the absolute maximum value of the function f(x) is 222.

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Answer:

Sure, I can help you with that.

To find the area of the gazebo floor, we can think of the decagon as being composed of ten congruent triangles. Each triangle has a base of 10 feet and a height of 192 feet. The area of a triangle is equal to (1/2)bh, so the area of each triangle is (1/2)(10)(192) = 960 square feet. The area of the decagon is equal to 10 times the area of each triangle, or 960*10 = 9600 square feet.

Therefore, the area of the gazebo floor is 9600 square feet.

Here is a diagram of the decagon, with the ten congruent triangles labeled:

[Image of a decagon with ten congruent triangles labeled]

I hope this helps! Let me know if you have any other questions.

Step-by-step explanation:

I'm so grateful for your help. I would be honored if you would give me a Brainlyness award."

"IF THERE BASES ARE SAME POWER WILL BE ADD"

4^6+2=4^8 THAT IS AN ERROR

If lea wants to divide the canvas into sections that contain an area of 3 then Lea can create 81 sections on the canvas.

To find the number of sections Lea can create on the painting canvas, given the length is 3^5 mm, the width is 3^7 mm, and each section has an area of 3^8 mm^2 we should follow the steps given below:

Step 1: Calculate the total area of the canvas by multiplying the length and the width.
[tex]Total area = (3^5 mm) * (3^7 mm)[/tex]

Step 2: Use the property of exponents that states a^m * a^n = a^(m+n) to simplify the total area.
Total area = 3^(5+7) mm^2
Total area = 3^12 mm^2

Step 3: Divide the total area of the canvas by the area of each section to find the number of sections.
Number of sections = (3^12 mm^2) / (3^8 mm^2)

Step 4: Use the property of exponents that states a^m / a^n = a^(m-n) to simplify the number of sections.
Number of sections = 3^(12-8)
Number of sections = 3^4

Step 5: Calculate the numerical value of 3^4.
Number of sections = 81

Lea can create 81 sections on the canvas.

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Answer:

The order from smallest to largest price per package is: December, April, February.

Step-by-step explanation:

For the sale in February:

- Price per package = $4.49 ÷ 3 = $1.50 per package

For the sale in April:

- Price per package = $7.39 ÷ 5 = $1.48 per package

For the sale in December:

- Price per package = $5.88 ÷ 4 = $1.47 per package

To evaluate the integral ∫√5+x/5-x dx, we first need to simplify the integrand. We can do this by multiplying the numerator and denominator of the fraction by the conjugate of the denominator, which is 5+x. This gives us:

∫√(5+x)(5+x)/(5-x)(5+x) dx

Simplifying further, we get:

∫(5+x)/(√(5-x)(5+x)) dx

We can now make a substitution by letting u = 5-x. This gives us du = -dx, and we can substitute these values into the integral to get:

-∫(4-u)/(√u(9-u)) du

To simplify this expression, we can use partial fraction decomposition to break it up into simpler integrals. We can write:

(4-u)/(√u(9-u)) = A/√u + B/√(9-u)

Multiplying both sides by √u(9-u), we get:

4-u = A√(9-u) + B√u

Squaring both sides and simplifying, we get:

16 - 8u + u^2 = 9A^2 - 18AB + 9B^2

From this equation, we can solve for A and B to get:

A = -B/3
B = 2√2/3

Substituting these values back into the partial fraction decomposition, we get:

(4-u)/(√u(9-u)) = -√(9-u)/3√u + 2√2/3√(9-u)

We can now substitute this expression back into the integral to get:

-∫(-√(9-x)/3√x + 2√2/3√(9-x)) dx

This integral can be evaluated using standard integral formulas, and we get:

(2/3)√(5+x)(9-x) - (2/9)√(5+x)^3 + C

where C is the constant of integration.

In summary, to evaluate the integral ∫√5+x/5-x dx, we simplified the integrand by multiplying the numerator and denominator by the conjugate of the denominator, made a substitution to simplify the expression further, used partial fraction decomposition to break it up into simpler integrals, and evaluated the integral using standard integral formulas. The final answer is (2/3)√(5+x)(9-x) - (2/9)√(5+x)^3 + C.

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Approximate APR = (205 ÷ 24)(12)(987) = 0.1025 or 10.3%. Rounding to the nearest tenth, the answer is 10.4%.

To calculate Wally's approximate APR, we'll use the provided formula and given information:

Approximate APR = (Finance Charge ÷ #Months) * (12) ÷ Amount Financed

Plugging in the given values:

Approximate APR = ($205 ÷ 24) * (12) ÷ $987

Approximate APR = (8.5417) * (12) ÷ $987

Approximate APR = 102.5 ÷ $987

Approximate APR ≈ 0.1038

To express the result as a percentage and round to the nearest tenth, we'll multiply by 100:

Approximate APR ≈ 0.1038 * 100 = 10.38%

Rounded to the nearest tenth, Wally's approximate APR is 10.4%.

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Answer:

68in

Step-by-step explanation:

square: 3x3=9

9+9= 18

trapezoid (centre area) : 7x3x5=25

25x2=50

50+18=68

not entirely sure abt this

The possible values of x that satisfy the equation |x+5| = c are x = c - 5 and x = -c - 5.

what is algebra?

Algebra is a branch of mathematics that deals with mathematical operations and symbols used to represent numbers and quantities in equations and formulas.

Assuming you meant to write |x+5|= some value, I can give you a general method to solve equations involving absolute values.

If |a| = b, then either a = b or a = -b. Thus, to solve the equation |x+5| = c, where c is some given value, we can split it into two cases:

Case 1: x+5 = c

Solving for x, we get x = c - 5.

Case 2: -(x+5) = c

Solving for x, we get x = -c - 5.

So, the possible values of x that satisfy the equation |x+5| = c are x = c - 5 and x = -c - 5.

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The value of k = 2

Substituting into the integral:

k ∫₀^(π/2k) sec²(u) du

= k [tan(u)]₀^(π/2k)

= k [tan(π/2k) - tan(0)]

= k [∞ - 0]

= ∞

This means that the integral diverges unless k = 0.

∫₀^(π/2k) sec²(x/k) dx

= ∫₀^(π/2k) (1 + tan²(x/k)) dx

= [x + k tan(x/k)]₀^(π/2k)

= π/2

So we have:

π/2 = [π/2k + k tan(π/2k)] - [0 + k tan(0)]

= π/2k + k tan(π/2k)

Multiplying through by k:

π/2 = π/2 + k² tan(π/2k)

Subtracting π/2 from both sides:

0 = k² tan(π/2k)

The only way for this equation to hold for k > 0 is if tan(π/2k) = 0. This occurs when π/2k is an integer multiple of π/2, i.e., when k is an even integer.

Therefore, the value of k that satisfies the original integral is k = 2.

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Answer: x² - 2x - 3

Step-by-step explanation:

      What is FOIL? The FOIL method is used to multiply two binomials.

F ➜ First
O ➜ Outer
I ➜ Inner
L ➜ Last

      Let us break it down into each piece by multiplying, following the pattern.

F ➜ x * x ➜ x²
O ➜ x * 1 ➜ x
I ➜ x * -3 ➜ -3x
L ➜ -3 * 1 ➜ -3

      Lastly, we add these pieces together.

x² + x - 3x - 3 = x² - 2x - 3

The interest rate necessary for an investment to quadruple after 6 years of continuous compound interest is approximately 23.105%.

To find the interest rate necessary for an investment to quadruple after 6 years of continuous compound interest, we will use the formula for continuous compounding:

A = P * e^(rt)

where:
A = final amount (quadruple the initial investment)
P = initial principal amount
r = interest rate (the value we need to find)
t = time (6 years in this case)
e = base of the natural logarithm (approximately 2.718)

Since the investment needs to quadruple, we have A = 4P. Now, we can substitute the values into the formula:

4P = P * e^(r * 6)

Divide both sides by P:

4 = e^(6r)

To solve for r, take the natural logarithm (ln) of both sides:

ln(4) = ln(e^(6r))

Using the property of logarithms, we can rewrite this as:

ln(4) = 6r

Now, divide by 6 to isolate r:

r = ln(4) / 6

Using a calculator, we find:

r ≈ 0.231049 (or 23.105% when expressed as a percentage)

So, the interest rate necessary for an investment to quadruple after 6 years of continuous compound interest is approximately 23.105%.

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