The above prompt is related to Interplanetary Science or Astronomy.
1) The diagram that best represents the appearance of the Moon at position P 'When viewed from the Earth is Option A.
2) The factor that most likely caused the difference in the apparent size of the Moon in photographs A and B is: "The distance from the Earth to the Moon changed." (Option D).
What is Interplanetary Science?The study of planets and other objects in our solar system is known as interplanetary science. Telescopes, satellites, and other technologies are used by scientists to understand more about these objects and how they developed and evolved through time.
It also entails researching the possibility of life on other planets and moons, as well as learning about the solar system's past and future.
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A spring with a cart at its end vibrates at frequency 5.0Hz\;Hz .
A. Determine the period of vibration.
B. Determine the frequency if the cart's mass is doubled while the spring constant remains unchanged.
C. Determine the frequency if the spring constant doubles while the cart's mass remains the same.
A. The period of vibration is the time it takes for one complete oscillation to occur. It is the reciprocal of the frequency. The period of vibration can be calculated using the formula:
Period = 1/Frequency
Given that the frequency of vibration is 5.0Hz, the period of vibration is:
Period = 1/5.0 s
Period = 0.2 s
B. If the cart's mass is doubled while the spring constant remains unchanged, the frequency of vibration will not change. This is because frequency is dependent on the spring constant and the mass of the cart and not on the amplitude of the oscillation.
C. If the spring constant doubles while the cart's mass remains the same, the frequency of vibration will also double. This is because frequency is directly proportional to the square root of the spring constant. Therefore, doubling the spring constant would lead to an increase in the frequency of vibration by a factor of square root of 2.
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A brain-imaging method using radio waves and magnetic fields of the body to produce detailed images of the brain is called __________.
Magnetic Resonance Imaging is a technique for producing precise pictures of the brain that uses radio waves and the magnetic fields of the body.
What imaging processes make use of magnetic fields and radio waves?A magnetic field and radio waves produced by a computer are used in the medical imaging procedure known as magnetic resonance imaging (MRI), which produces precise pictures of your body's organs and tissues.
Describe an MRI picture.The noninvasive medical imaging procedure known as magnetic resonance imaging, or MRI, creates precise pictures of virtually every internal bodily structure, including the organs, bones, muscles, and blood arteries. A sizable magnet and radio waves are used in MRI scanners to produce pictures of the human body.
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An engine with a power output of 110 hp has a thermal efficiency of 28%. Determine the rate of fuel consumption (in kg/hr) if heating valve of the fuel is 44,200kj/kg
The rate of fuel consumption is 6.69 kg/hr.
Solution:
To determine the rate of fuel consumption, we need to calculate the amount of energy required by the engine and divide that by the thermal efficiency.
From the question:
W = 110 hp
η = 28%.
r = ?
First, we can convert the power output from horsepower to watts:
1hp = 746 W
power output = 110 hp x 746 W/hp
= 82016 W
Then, we can calculate the energy required by the engine by multiplying the power output by the time the engine is running:
Energy = Power x time
Without knowing the time the engine runs, we cannot calculate the energy required.
We can calculate the fuel consumption by using the heating value of the fuel and the thermal efficiency.
Fuel consumption = ( Power )
(heating value * thermal efficiency))
So in this case:
Fuel consumption = (82016)
(44200*0.28)
= (82016)
12276
Fuel consumption = 6.69 kg/hr
Hence, the rate of fuel consumption is 6.69 kg/hr.
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PLEASE PLEASE PLEASE HELP ME ASAP I NEED IN FIVE MINUTES!!!!!! I WILL MARK BRAINLYEST AND WILL GIVE 10 EXTRA POINTS!!!!!
How does knowing how the Earth is structured help you decide where you would like to live in terms of temperature?
Answer:
Much of our understanding of the basic structure and composition of Earth and the other planets in our solar system is not strenuously debated. We can infer a surprising amount of information from the size, mass and moment of inertia of the planets, all of which can be determined from routine astronomical observations. Measurements of surface chemical composition, either by direct sampling (as has been done on Earth, the moon, and Mars) or through spectroscopic observations, can be used to estimate elemental abundances and the degree of chemical differentiation that occurred as the planets condensed from the solar nebula. Remote observations of the gravitational field can be used to understand how a planet's mass is distributed, whereas the strength and shape of the magnetic field provides some constraint on the structure of a metallic core. The specifics of structure and composition, however, are much more debatable. And it is these details that tell us a much more extensive and ultimately more interesting story about the internal dynamics of the planets and their evolution. As a result, trying to determine them is frontier research in almost all fields of earth and planetary science.
Even on Earth, many of these details have to be inferred from remote observations. Because we cannot sample the deep Earth, we must deduce its composition either by looking at the clues hidden in igneous and metamorphic rocks, or by examining proxies for composition and structure such as the three-dimensional variation of the velocity of seismic waves produced by earthquakes and sampled by networks of seismometers on the surface. The late Francis Birch, the eminent Harvard geophysicist, and his colleagues and students worked out the basic methodology that brings these distinct observations together. Birch showed how the stiffness of rocks changes under the extreme conditions of pressure and temperature deep within planets, as well as with chemical composition. Because the speed of seismic waves depends on the stiffness of the medium through which they propagate, it is possible to calculate temperature and composition from maps of seismic velocity. Most current research is based on Birch's work and it has even been extended to the most extreme temperature and pressure conditions of Earth's core. For example, much of our understanding of the large- and small-scale convection patterns driving plate tectonics has come about by using Birch-type proxies for temperature and composition.
Explanation:
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Which of the following bodies are at thermal equilibrium when being put into contact? (1) A glass of water of internal energy E at 20 °C (2) Alcohol with unknown internal energy at 20 °C (3) A jar of water of internal energy E at 25 °C A(1) and (2) only B(1) and (3) only C(2) and (3) only D(1), (2) and (3)
When two bodies at equal temperature are brought in contact with each other then no heat flows between them and they are said to be in thermal equilibrium.
When bodies in contact are in thermal equilibrium then they have the same?When the engine temperature eventually reaches the same level as the ambient temperature, thermal equilibrium has taken place. After being placed on the table and waiting a short while, a cup of hot tea cools to the same temperature as its surroundings.
This is where thermal equilibrium occurs. the set temperature at which all of a solid's mass melts. When the solid turns into a liquid, both the solid and the liquid coexist in the thermal equilibrium.
The individual drove himself to his location. The engine temperature was excessively high during that time, but it eventually dropped to the air temperature outside. When the engine temperature eventually reaches air temperature, thermal equilibrium has occurred.
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A(1) and (2) only of the following bodies are at thermal equilibrium when being put into contact. i.e. (1) A glass of water of internal energy E at 20 °C (2) Alcohol with unknown internal energy at 20 °C .
What is thermal equilibrium?When two physical systems are linked by a channel permeable to heat, they are said to be in thermal equilibrium if there is no net transfer of thermal energy between them. The zeroth law of thermodynamics is observed during thermal equilibrium.As internal energy is measured in terms of the body temperature, when two bodies are in thermal equilibrium, their internal energies will also be equal.
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A boy with a mask of 20 is running at 3 m/s what is his kinetic energy
Important Formulas:
[tex]KE=.5mv^2[/tex]
Kinetic energy(measured in joules) = .5 * mass(measured in kg) * velocity(measured in m/s)^2
__________________________________________________________
Given:
[tex]m=20kg[/tex]
[tex]v=3m/s[/tex]
[tex]KE=?[/tex]
__________________________________________________________
Finding kinetic energy:
[tex]KE=.5mv^2[/tex]
[tex]KE=.5(20)(3)^2[/tex]
__________________________________________________________
[tex]\fbox{KE = 90 Joules}[/tex]
at what distance from a -5.35*10^-6 C charge will the electric potential be -500 v?
Answer:
Different values of Q will make different values of electric potential V (shown in the image). The electric potential arising from a point charge Q, at a distance r from the charge is observed to be where ε0 is the permittivity of vacuum. VE is known as the Coulomb potential .Explanation:
The distance from the -5.35 × 10⁻⁶ C charge where the electric potential is -500 V is approximately 0.0935 meters or 9.35 cm.
To determine the distance from a charge where the electric potential is -500 V, we can use the formula for electric potential due to a point charge:
V = k × (Q / r)
Where:
V is the electric potential (in volts),
k is the Coulomb's constant (approximately 8.99 × 10⁹ Nm²/C²),
Q is the charge (in coulombs), and
r is distance from the charge (in meters).
Rearranging the formula, we solve for the distance:
r = k × (Q / V)
Substituting the given values into the equation
k = 8.99 × 10⁹ Nm²/C²,
Q = -5.35 ×10⁻⁶ C, and
V = -500 V,
r = (8.99 × 10⁹ Nm²/C²) × (-5.35 × 10⁻⁶ C / -500 V)
Calculating this expression:
r ≈ 0.0935 meters or 9.35 cm
Therefore, the distance from the -5.35 × 10⁻⁶ C charge where the electric potential is -500 V is approximately 0.0935 meters or 9.35 cm.
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at what distance from a -5.35*10^-6 C charge will the electric potential be -500 v? Please I really need help!
Answer:
What is c and v
Explanation:
Answer:
96.2
Explanation:
I got it right on Acellus
A convex lens has a focal length of 25.5 cm. If an object is placed 72.5 cm from the lens, the image's distance from the lens will be
Question 14 options:
33.5 cm
39.3 cm
none of the above.
31.7 cm
Answer:
The answer is 39.3
Explanation:
5
What 2D shape can be created by slicing a cone horizontally?
circle
A
B) rectangle
C triangle
D
square
Answer:
I believe the answer is triangle
Hope it helps!
The amplitude of pulse A is 20 cm and that of pulse B is 10 Cm what is the minimum amplitude of the resultant pulse
The minimum amplitude of the resultant pulse is 10 cm.
What is amplitude of a pulse?The amplitude of a pulse is the maximum height of the waveform measured from the baseline, also known as the peak-to-peak amplitude. In the case of two pulses, A and B, the minimum amplitude of the resultant pulse is determined by the vector sum of the individual amplitudes of the two pulses.
When two pulses are in phase, the resultant pulse amplitude is the sum of the individual amplitudes, which in this case is 20 cm + 10 cm = 30 cm.
However, if the two pulses are out of phase, the minimum amplitude of the resultant pulse is determined by the difference between the amplitudes of the two pulses. In this case, the minimum amplitude of the resultant pulse would be |20 cm - 10 cm| = 10 cm.
So, the minimum amplitude of the resultant pulse is 10 cm.
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hello please help i’ll give brainliest
Answer:
Oceanic crust moves easly. Continental crust does not move
how much percent of the earth's water is drinkable?
A theme park is planning out a new free-fall ride. The drop is almost perfectly frictionless, with a distance of 190 meters. Assuming that the initial velocity was zero, what would be the speed at the bottom of the drop?
a-53 m/s
b-61 m/s
c-67 m/s
d-72 m/s
Answer:
Approximately [tex](-61)\; {\rm m\cdot s^{-2}}[/tex], assuming that [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex].
Explanation:
Under the assumptions, the vehicle would be in a free fall. Acceleration would be constant: [tex]a = (-g) = (-9.81)\; {\rm m\cdot s^{-2}}[/tex].
Let [tex]u[/tex] denote the initial velocity of the vehicle. Let [tex]v[/tex] denote the velocity of the vehicle at the bottom of the drop. Let [tex]x[/tex] denote the displacement of the vehicle during the drop.
It is given that the initial velocity is [tex]u = 0\; {\rm m\cdot s^{-1}}[/tex]. During the drop, displacement would be [tex]x = (-190)\; {\rm m}[/tex] (negative since the vehicle is below where it started.) The value of final velocity [tex]v[/tex] needs to be found.
It is known that the vehicle is moving downwards at the end of the fall. Therefore, the value of [tex]v\![/tex] would be negative. Apply the SUVAT equation [tex]v^{2} - u^{2} = 2\, a\, x[/tex] to find [tex]v[/tex] from [tex]u[/tex], [tex]a[/tex], and [tex]x[/tex].
[tex]\begin{aligned}v^{2} &= u^{2} + 2\, a\, x\end{aligned}[/tex].
[tex]\begin{aligned}v &= -\sqrt{u^{2} + 2\, a\, x} \\ &= -\sqrt{(0\; {\rm m\cdot s^{-1}})^{2} + 2\, (-9.81\; {\rm m\cdot s^{-2}})\, (-190\; {\rm m})} \\ &\approx (-61)\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].
(Note that [tex]v[/tex] is negative.)
In other words, the velocity of the vehicle would be approximately [tex](-61)\; {\rm m\cdot s^{-1}}[/tex] at the end of the drop.
A 2.0-kg block of wood is on a level surface where and A 13.7-N force is being applied to the block parallel to the surface. (a) If the block was originally at rest, then (A) it will remain at rest, and the force of friction will be about 15.7 N. (B) it will remain at rest, and the force of friction will be about 13.7 N. (C) it will remain at rest, and the force of friction will be 11.8 N. (D) it will begin to slide with a net force of about 1.9 N acting on the block.
When 13.7-N force is being applied to the block parallel to the surface it will remain at rest, and the force of friction will be about 13.7 N. Hence option B is correct.
How do you determine the frictional force?The resistive force of friction (Fr), which pushes the items together, is divided by the normal or perpendicular force (N), which pushes them apart, to produce the coefficient of friction (fr), which is a numerical value. The following formula represents it: fr = Fr/N.
What does physics mean by a frictional force?Force which prevents one solid object from rolling or slipping over another. Although frictional forces can be advantageous, such as the traction required to walk without slipping, they also provide a significant amount of resistance to motion.
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In 1935, a french destroyer , La Terrible , started from rest and accelerates to attain a speed of 83km/h. Suppose it took 2 minutes for the ship to speed up. Find the ships average acceleration.
According to the given statement The ships average acceleration is 2790 km/hr².
What is an explain acceleration?A measure of how quickly motion's speed and direction change over time. When a point or object advances or decelerates, it is moving straight forward. Motion on a circle increases despite the same speed because the direction is always changing.
Calculation:We know that from newton's equation,
v² + u² = 2as
S = ut + 0.5 at²
Where, v = final speed
u = initial speed
a = acceleration
S = distance covered
t = time taken
Given, u = 0
So the equations becomes:
v² = 2as
S = 0.5 at²
Using these equations we get:
v² = 2a(0.5)at²
v² = a²t²
v = at
v/t = a
Given, v = 93 km/hr
t = 2 min = 2/60 hr
Putting these values in above equation we get, a = 2790 km/hr²
So, the ships average acceleration is 2790 km/hr²
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What are the 7 basic forms of hazardous energy in the industrial plants?
Machines and equipment use a variety of energy sources, including electrical, mechanical, hydraulic, pneumatic, chemical, thermal, and others.
What are the forms of hazardous energy?Equipment and machinery that draw power from electrical, mechanical, hydraulic, pneumatic, chemical, thermal, or other sources may put workers at risk.
hazards to safety
biological threats
bodily dangers
hazards of ergonomics
chemistry risks
threats to organisations during work.
environment-related risks.
Potential energy, or stored energy in an object, poses a risk to employees if it is suddenly released.
Lockout is only one aspect of hazardous energy control. It includes measures like machine guarding, alternative guarding arrangements that stop exposure to hazardous energy, lockouts, and other ways to protect workers from coming into touch with such energy. Anything that could be harmful, hurt someone, or have negative health impacts on something or someone is said to be in a hazardous condition.
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A person weighing 6:0 102 newtons rides an elevator upward at an average speed of 3.0 meters per second for 5.0 seconds. How much does this person's gravitational potential energy increase as a result of this ride
This ride increases this person's gravity potential energy by 9000 Joules.
What is gravitational force ?The force of attraction between any two bodies is directly proportional to the product of their masses and is inversely proportional to the square of their distance, according to Newton's universal law of gravitation.
What is energy ?The definition of energy is "the ability to do work, which is the capability to apply a force causing the displacement of an object." Despite this vague description, energy simply refers to the power that propels motion.
Weight of the person, W = 6 x 102 N = 600 N
Avg. Speed of elevator, v = 3 m/s
Time of ride, t = 5 sec.
Therefore,
Mass of the person, m = W/g = 600/9.8 = 61.2244 kg
Height of the elevator after 5 sec, h = v x t = 3 x 5 = 15 m
Potential energy increase , PE = mgh = 61.2244 x 9.8 x 15
PE = 9000 Joule
Therefore, 9000 Joule does this person's gravitational potential energy increase as a result of this ride.
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What environmental factor can influence natural selection and decrease genetic diversity?
The genetic and chemical variety of plant populations is influenced by environmental factors such as soil nutrients, temperature, water availability, and light intensity.
How may the environment impact genetic diversity?Sometimes a gene's DNA sequence or degree of activity is altered by the environment. Both of these effects have the capacity to change the proteins that a gene generates, which then affects traits. Some harmful environmental factors can change the nucleotide sequence of a gene. UV rays, for example, can harm DNA strands.
How is natural selection impacted by environmental factors?Successful competitors have a higher chance of surviving. Individual creatures with specific qualities are more likely to survive under specific environmental conditions than those without these traits.
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Write a summary discussing this experiment and the results. Use the following questions and topics to help guide the content of your paragraph. Submit with your observations and summary in the essay box below.
Was your hypothesis supported? Summarize the conclusions that you can draw from this experiment. Use the questions above to guide your ideas. (Be sure to refer to your data when answering this question.)
Give at least one example from real life where the principles demonstrated in this lab are evident.
350 words
Answer:
A hypothesis. In science, a hypothesis is an idea or explanation that you then test through study and experimentation. Outside science, a theory or guess can also be called a hypothesis. A hypothesis is something more than a wild guess but less than a well-established theory. My hypothesis was right because although it was n educated guess it was still correct
The viscosity value decreased with the increase of temperature. The effect caused by temperature in the range studied was more important in the low range of temperature, whereas at high temperature, the viscosity showed less variation.The studies carried out in the present work indicated that the effect of temperature upon the viscosity of Galician honeys was prominent, and it is necessary to take into account this variable when the operation temperature is under 25°C, since below this value a small variation in temperature produces high changes in the viscosity value. On the other hand, different models to fit experimental values of viscosity/temperature have been proved. The glass transition temperature was determined necessarily since several models include this parameter in the equation, because it provides important information related to the viscosity value. All the models show a good behaviour but the best results were obtained using the Arrhenius one.
Based on the information provided, it is unclear what hypothesis was being tested in this experiment. however, I can explain about hypothesis, and The experiment demonstrates a decomposition reaction in which heating a mixture of sugar and baking soda produces carbon, and the principles of this reaction can be observed in real-life scenarios such as burning wood and digestion.
What is a hypothesis?A hypothesis is a proposed explanation or prediction for a phenomenon or observed data that is based on prior knowledge, assumptions, and logical reasoning. It is an educated guess that can be tested through scientific investigation and experimentation. A hypothesis is usually formulated as a statement or a question that predicts the outcome of an experiment or study. The validity of a hypothesis is evaluated through empirical evidence, which may either support or refute the proposed explanation or prediction.
Hypotheses are an essential component of the scientific method, which involves formulating a hypothesis, testing it through experiments or observations, analyzing the data, and drawing conclusions based on the evidence. A hypothesis can be modified or revised based on the results of the experiments, and further investigations can be conducted to refine and validate the proposed explanation or prediction.
Here in the experiment,
The experiment involved mixing 9 sugar cubes and 2 teaspoons of baking soda, then heating it to make a long black tube of carbon. The sugar cubes had a mass of 2 grams each, and the teaspoon could hold 3 grams of baking soda. The total mass of the reactants used in the experiment was found to be 24 grams.
From this experiment, we can conclude that the reaction between sugar and baking soda can result in the formation of carbon. Heating the mixture causes a chemical reaction, which breaks down the sugar and baking soda into carbon, water vapor, and other byproducts. This reaction is an example of a decomposition reaction, in which a single compound breaks down into two or more simpler substances.
The principles demonstrated in this experiment are evident in many real-life scenarios. For example, the process of burning wood can be seen as a type of decomposition reaction. When wood is burned, it reacts with oxygen in the air to produce carbon dioxide, water vapor, and other byproducts. Similarly, the process of digestion in the human body involves the breakdown of complex food molecules into simpler substances that can be absorbed by the body.
Therefore, this experiment demonstrates the principles of a decomposition reaction and shows how sugar and baking soda can be transformed into carbon through heating. By understanding the underlying chemistry of such reactions, we can gain insights into many real-life processes and phenomena.
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1. What are the criteria for accepting a theory as a physical law?
A theory must meet certain requirements in order to be accepted as a physical law , 1. It must explain the available data 2. It need to offer hypotheses that can be verified by science.
A physical law outlines the broad relationships between and, when necessary, changes in the physical quantities that define the states of a physical system. Typically, this is described mathematically. These laws are also known as natural laws or are associated with them in the physical realm. A physical law applies with a very high probability when it falls within its scope of applicability. Physical experiments and observations that are specifically focused are used to test this validity range. The law is established if the outcomes match the predictions.
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Una onda cuya frecuencia es igual a 550 Hz, se propaga en el aire. ¿ cual es su longitud de onda y su periodo?
Answer:
The wavelength of the wave is [tex]5.45\times 10^5\ m[/tex] and time period is 0.0018 s.
Explanation:
The given question is, "A wave whose frequency is equal to 550 Hz, propagates in the air. What is its wavelength and its period?"
Given that,
The frequency of a wave, f = 550 Hz
The time period of a wave,
[tex]T=\dfrac{1}{f}\\\\T=\dfrac{1}{550}\\\\T=0.0018\ s[/tex]
Wavelength,
[tex]\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{550}\\\\\lambda=5.45\times 10^5\ m[/tex]
So, wavelength of the wave is [tex]5.45\times 10^5\ m[/tex] and time period is 0.0018 s.
What theorem is presented based on the structure of the baseball field?
Pythagorean Theorem to determine the gap between second base and home plate.
Explain the pythagorean theorem.The Pythagorean theorem and the coordinates of the two locations are used in the distance formula to determine the distance between them. The formula below can be used to determine the length of AB if A and B make up the hypotenuse of a right triangle: Leg2 plus Leg2 equals Hypotenuse 2.
measured from the middle of the backstop to the apex of home plate. Place second base in centre by drawing a line from the backstop's centre point over the pitcher's mound, through the apex. The distance that needs to be measured is between the centre of second base and the top of home plate.
The square root of (a,c)2 + (b,d)2 is used to calculate the distance between the points (a,b) and (c,d). The distance between points (a, b, c) and (d, e, f) in three dimensions is equal to the square root of (a, d), (b, e), and (c, f).
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CANT DO IT
i neeeed herlp For numbers 14a-14d, tell which expressions require you to rename mixed numbers before you can subtract.
14a. LaTeX: 5\frac{2}{5}-2\frac{1}{4}5 2 5 − 2 1 4
[ Select ]
14b. LaTeX: 5\:-\:2\frac{7}{8}5 − 2 7 8
[ Select ]
14c. LaTeX: 7\frac{2}{3}\:\:-\:6\frac{1}{8}7 2 3 − 6 1 8
[ Select ]
14d. LaTeX: 9\frac{1}{6}-5\frac{2}{3}9 1 6 − 5 2 3
[ Select ]
14 a, 14 b, 14 c, and 14 d are the Expressions that require renaming mixed numbers before we can subtract.
Actually, there are a few steps to convert normal fractions into a mixed fractions. The steps are as follows:
firstly, we have to find the whole number to do this we divide the numerator by the denominator. secondly, Get the new numerator: To get a new number we should calculate in step one and multiply it by the original denominator. The result of that multiplication is then subtracted from the original numerator.After that Our mixed fraction, we need to put the whole number together with our new numerator and original denominator.finally, Simplifying our fraction.Solving one by one with the help of the given options:
1) 14a
[tex]5\frac{2}{5}-2\frac{1}{4} \\\\\frac{17}{5} -\frac{9}{4} \\\\\frac{68-45}{20}\\\\ \frac{23}{20} =1\frac{3}{20}[/tex]
2)14b
[tex]5-2\frac{7}{8} \\\\\frac{5}{1} -\frac{7}{8} \\\\\\\frac{40-23}{8}\\\\ \frac{17}{8} =2\frac{1}{8}[/tex]
3)14c
[tex]7\frac{2}{3} -6\frac{1}{8} \\\\\frac{23}{3} -\frac{49}{8} \\\\\frac{184-147}{8} \\\\\frac{37}{24} =1\frac{13}{24}[/tex]
4)14d
[tex]9\frac{1}{6} -5\frac{2}{3}\\\\ \frac{55}{6}-\frac{17}{3}\\\\ \frac{165-102}{18} \\\\\frac{63}{18}=3\frac{9}{18}[/tex]
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01) When operating a simple machine an effort of 60N is used to lift the load of 240 N. Find the mechanical advantage.
02) When operating the same machine the effort arm moves 4m while load moves 1m. Find velocity ratio
03) In the same machine find work input.
04) In the same machine find work output.
05) Find the efficiency of this simple machine.
Useless answers will be reported!
Answer:
1 MA= load/effort
MA= 240/60
MA=4
2.VR=Distance moved by effort/ Distance moved by Load
VR=4/1
= 4
5. Efficiency= MA/VR
4/4*100/1
=100%
Like the Kelvin scale, the Rankine scale is an absolute temperature scale: Absolute zero is zero degrees Rankine (0∘R). However, the units of this scale are the same size as those on the Fahrenheit scale (∘F) rather than the Celsius scale (∘C).
A) Given that water at standard pressure freezes at 0∘C, which corresponds to 32∘F, and that it boils at 100∘C, which corresponds to 212∘F, calculate the temperature difference ΔT in degrees Fahrenheit that corresponds to a temperature difference of 1 K on the Kelvin scale.
B) What is the numerical value of the triple-point temperature Ttriple of water on the Rankine scale?
The temperature difference of 1 K on the Kelvin scale is equivalent to the temperature difference of (5/9)°F on the Fahrenheit scale. Triple-point temperature of water is approximately 491 degrees Rankine.
The unit of scales on the Rankine scale is the same as those on the Fahrenheit scale. Hence, from the freezing point of water (0⁰C) to the boiling point of water(100⁰C) , Rankine scale is divided into 180 scales.
The absolute zero is zero degrees Rankine. In Celsius scale, absolute zero is −273 °C.
A). A unit scale on the Kelvin scale is the same size as a unit scale in the Celsius scale. Hence,
ΔT 1 K = ΔT 1°C
The ratio of Celsius and Fahrenheit scale is 5/9, therefore:
K/F = C/F = 5/9
Hence,
ΔT 1 K = ΔT (5/9)°F
B) Triple-point temperature of water is approximately 0 °C. Since zero degrees Rankine is equivalent to −273 °C, hence:
0 °C = 0 - (9/5)(-273) = 491 degrees Rankine.
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Hydrogen bonding is a weak attractive force.
O A. True
O B. False
Answer:
The Answer is gonna be True
Explanation : A hydrogen bond is a weak type of force that forms a special type of dipole-dipole intermolecular attraction when a hydrogen atom is bonded directly to one of the most electronegative elements like nitrogen (N), oxygen (O) or fluorine (F). This causes the hydrogen to acquire a significant amount of positive charge.
Or
Hydrogen bond is an attractive force between a partially positive charged hydrogen and a partially negative charged atom (oxygen and nitrogen). This is a very weak bond and strength of hydrogen bond (5-10 Kcal per bond) is much less than the strength of covalent bond. Hydrogen bonds are usually showed as dotted lines between two atoms.
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Answer: The attraction of opposite charges between hydrogen and oxygen does not form a weak bond because oxygen-hydrogen makes hydrogen bonding. Hydrogen bonding is a very attraction force
An object is experiencing an acceleration of 12 m/s2 while traveling in a circle of radius 5. 0 m. What is its velocity?
The velocity of the object is 7.74m/s
Though it may sound sophisticated, velocity is simply the rate at which an object's location changes with regard to a frame of reference and time. Since it is a vector quantity, the definition of velocity requires both magnitude (speed) and direction.
We are given that,
Acceleration = 12m/s²
Radius = r = 5.0m
Velocity = v = ?
The velocity of the object can be calculated by the formula ,
a = v²/r
v = √ar
v = √12m/s²× 5m
v = √60m²/s²
v= 7.74m/s
Thus , the velocity of the object would be 7.74m/s.
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A bicyclist maintains a constant velocity of
4. 0 m/s for a distance of 480 m. How long does it take the bicyclist to travel this distance?
A8s
B 120s C 476s D 1920s
The bicyclist will need to ride for a total time of 120 seconds in order to cover 480 meters of distance at a constant velocity of 4.0 meters per second.
In this scenario, we are provided with:
The distance of the ride is 480 meters.
The velocity is four meters per second
In order to calculate the time, we can use the following formula:
Time = Distance : Velocity
= 480 meters : 4.0 meters per second
= 120 seconds
Therefore, the amount of time a cyclist needs to travel would be 120 seconds.
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Solve these 5 items in your notebook and take a clear and readable photo. PS. You need to balance the equation before u identify the type of chemical reaction.
Answer:
that is not physics pls dont do that again
Explanation: